In the case of:

y = a x^2

Xd = x ± ( ( 2 d x ) / ( 2 √ ( .25 a^2 + x^2 ) ) )

Yd = y ± ( ( .5 d a ) / ( √ ( .25 a^2 + x^2 ) ) )

Where:

x = coordinate for point on the Parabola

y = coordinate for point on the Parabola

a = dilation coefficient of the Parabola

Xd = coordinate for point displaced normal to a tangent of the Parabola

Yd = coordinate for point displaced normal to a tangent of the Parabola

d = displaced amount

You can email me at jamesrcleveland@gmail.com

]]>Is there a way to contact you and talk about STEM related game backed by Games For Change? ]]>

Yes, the direct link works. Thank you!

But for some reason, Firefox won’t display the image for me. I wonder why…

Strange. Does this direct link work? https://pbs.twimg.com/media/EwOxtwDXMAEKCeE?format=jpg&name=large

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