<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0' gd:etag='W/&quot;AkMGR3kzeyp7ImA9WhJTGEU.&quot;'><id>tag:blogger.com,1999:blog-6526671590148787143</id><updated>2012-06-28T06:00:26.783-07:00</updated><category term='Hi friends this blog in under construction'/><title>coolbuddyaditya</title><subtitle type='html'>Fun.Masti.Dhoom......!!!!</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://fun2full.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/6526671590148787143/posts/default?redirect=false&amp;v=2'/><link rel='alternate' type='text/html' href='http://fun2full.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>aditya</name><uri>http://www.blogger.com/profile/08550947238845248173</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>3</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><entry gd:etag='W/&quot;D0cGQ3czcSp7ImA9WhRUEUU.&quot;'><id>tag:blogger.com,1999:blog-6526671590148787143.post-4495172466063828911</id><published>2012-01-21T14:30:00.000-08:00</published><updated>2012-01-21T14:30:22.989-08:00</updated><app:edited xmlns:app='http://www.w3.org/2007/app'>2012-01-21T14:30:22.989-08:00</app:edited><title>These puzzelz can helps you to make sharp your mind</title><content type='html'>&lt;div dir="ltr" style="text-align: left;" trbidi="on"&gt;
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This is collection of the &lt;strong&gt;best puzzles&lt;/strong&gt; selected out of +10K brain teasers. Link to solution is under each puzzle. The answer is usually in spoiler which you can unhide by clicking the "Show" button. Some of them might be quite hard, however, you don't need any deep math knowledge. Just basic logic, creativity and patience is needed.&lt;br /&gt;
Here they come - BrainDen &lt;strong&gt;Top 10 Puzzles&lt;/strong&gt;. &lt;br /&gt;
Enjoy!

&lt;br /&gt;
&lt;div class="clear-right"&gt;
&lt;/div&gt;
&lt;h2&gt;

1. Weighing in a Harder Way&lt;/h2&gt;
You've got 27 coin, each of them is 10 g, except for 1. The 1 different coin is 9 g or 11 g (heavier, or lighter by 1 g). You should use balance scale that compares what's in the two pans. You can get the answer by just comparing groups of coins.&lt;br /&gt;
What is the minimum number weighings that can always guarantee to determine the different coin.

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
Separate the coins into 3 stacks of 9 (A, B, C). Weigh stack A against B and then A against C. Take the stack with the different weight (note lighter or heavier) and break it into 3 stacks of 3 (D, E, F). Weigh stack D against E. If D and E are equal, then F is the odd stack. If D and E are not equal, the lighter or heavier (based on the A, B, C comparison) is the odd stack. You now have three coins (G, H, I). Weigh G and H. If G equals H, then I is the odd and is lighter or heavier (based on the A, B, C comparison). If G and H are not equal, then the lighter or heavier (based on the A, B, C comparison) is the odd coin. &lt;br /&gt;
&lt;br /&gt;
If you like this type of brain teasers, then surely check out other &lt;a href="http://brainden.com/weighing-puzzles.htm"&gt;weighing puzzles&lt;/a&gt;. There are many easier ones as well.

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?s=&amp;amp;showtopic=214&amp;amp;view=findpost&amp;amp;p=9333" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
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&lt;h2&gt;

2. Hats On A Death Row&lt;/h2&gt;
You are one of 20 prisoners on death row with the execution date set for tomorrow. Your king is a ruthless man who likes to toy with his people's miseries. He comes to your cell today and tells you:&lt;br /&gt;
“I’m gonna give you prisoners a chance to go free tomorrow. You will all stand in a row (queue) before the executioner and we will put a hat on your head, either a red or a black one. Of course you will not be able to see the color of your own hat; you will only be able to see the prisoners in front of you with their hats on; you will not be allowed to look back or communicate together in any way (talking, touching.....).&lt;br /&gt;
&lt;br /&gt;
The prisoner in the back will be able to see the 19 prisoners in front of him. The one in front of him will be able to see 18…&lt;br /&gt;
&lt;br /&gt;
Starting with the last person in the row, the one who can see everybody in front of him, he will be asked a simple question: WHAT IS THE COLOR OF YOUR HAT?&lt;br /&gt;
&lt;br /&gt;
He will be only allowed to answer “BLACK” or “RED”. If he says anything else you will ALL be executed immediately.&lt;br /&gt;
&lt;br /&gt;
If he guesses the right color of the hat on his head he is set free, otherwise he is put to death. And we move on to the one in front of him and ask him the same question and so on…&lt;br /&gt;
&lt;br /&gt;
Well, good luck tomorrow, HA HA HA HA HA HA!”&lt;br /&gt;
&lt;br /&gt;
Now since you all can communicate freely during the night, can you find a way to guarantee the freedom of some prisoners tomorrow? How many?

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
First guy is a coin toss - let's wish him good luck.&lt;br /&gt;
His job is to establish the parity of black hats visible to him.&lt;br /&gt;
He says "Black" if he sees an odd number of black hats; "Red" otherwise.&lt;br /&gt;
By paying attention to what has been said, each prisoner will know his hat's color.&lt;br /&gt;
&lt;br /&gt;
Example:&lt;br /&gt;
Second to speak hears "Black" and sees an even number of black hats. &lt;br /&gt;
He knows his hat is black [odd changed to even - must be his is black] and says "black".&lt;br /&gt;
&lt;br /&gt;
Third guy has heard "black" and "black" and sees an even number of black hats.&lt;br /&gt;
He knows his hat is red [even stayed even - his hat can't be black] and says "red".&lt;br /&gt;
&lt;br /&gt;
And so on, to the front of the line.&lt;br /&gt;
&lt;br /&gt;
General algorithm:&lt;br /&gt;
The first time you hear "black", say to yourself "odd".&lt;br /&gt;
Each time your hear "black" after that, change the parity: "even", "odd", ... etc.&lt;br /&gt;
When it's your turn, if the black hats you see match the running parity, you're Red; Black otherwise.&lt;br /&gt;
Call out your color. &lt;br /&gt;
&lt;br /&gt;
If you like this type of brain teasers, then surely check out other &lt;a href="http://brainden.com/logic-puzzles.htm"&gt;logic puzzles&lt;/a&gt;. Especially "Masters of Logic Puzzles" series at the bottom of that page might be of interest for you.

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?s=&amp;amp;showtopic=825&amp;amp;view=findpost&amp;amp;p=8938" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

3. The Liar, The Truth Teller and The Random Answerer&lt;/h2&gt;
There is a truth teller (always tells the truth), a liar (always lies), and one that sometimes answers truthfully and sometimes lies. Each man knows who is who. You may ask three yes or no question to determine who is who. Each time you ask a question, it must only be directed to one of the men (of your choice). You may ask the same question more than once, but of course it will count towards your total.&lt;br /&gt;
What are your questions and to whom will you ask them?

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
There are 6 possible states for the order of the men: TRL, TLR, LTR, LRT, RTL, RLT &lt;br /&gt;
&lt;br /&gt;
There are 8 possible combinations of anwers for questions: TTT, TTL, TLT, TLL, LTT, LTL, LLT, LLL.&lt;br /&gt;
&lt;br /&gt;
Theoretically it's possbile if you could figure out a way to get any of the 8 combinations of answers assigned to the states, but with the unreliability of Random's answers, I thought it was impossible. There is always a possiblity in any solution where Random will exactly mirror T or L for answers. He could always lie or always tell the truth and you can never tell when he is lying or telling the truth. This being given, I thought you can NEVER separate 6 distinct answers to apply to the 6 states, and therefore can never be sure who is who. &lt;br /&gt;
&lt;br /&gt;
After a minute though, I saw through my own error in logic. I was always dealing with questions where T and L would give the same answer regardless of the order of the men. I saw that if you can get T and L to give a Yes/NO answer, then you can figure out where R's worthless answers are. The only way I saw to do this is to ask about the order of the men themselves. &lt;br /&gt;
&lt;br /&gt;
So: &lt;br /&gt;
Ask #1 if L is standing on R's right arm (our left if they are facing us). &lt;br /&gt;
The answer gives you a split in the order they are standing:&lt;br /&gt;
If YES, then it has to be T telling the truth, L telling a lie, or one of R's worthless answers, so: TLR, LTR, or RTL, RLT.&lt;br /&gt;
If NO, then it has to be T telling the truth, L telling a lie, or R and his worthless answers, so: TRL, LRT, or RTL, RLT.&lt;br /&gt;
&lt;br /&gt;
Now we know, based on the answer to #1 where to avoid R's worthless answers. We now ask T or L "Is T in the lineup?" If answer 1 was Yes, we ask person 2, if it was no we ask person 3. &lt;br /&gt;
&lt;br /&gt;
The answer now will give us some more info. If it's Yes, it's T answering the truth, if it's no, it's L answering a lie. So based on who we asked, we now know:&lt;br /&gt;
&lt;br /&gt;
Yes, Yes: Has to be LTR, or RTL&lt;br /&gt;
Yes, No: TLR, RLT&lt;br /&gt;
No, Yes: LRT, RLT&lt;br /&gt;
No, No: TRL, RTL&lt;br /&gt;
&lt;br /&gt;
Now any question separating the two possiblities works - just make sure you are avoiding R's worthless answers. &lt;br /&gt;
&lt;br /&gt;
For example: &lt;br /&gt;
Yes, Yes - ask #2 if #1 is L. (We know #2 is T and will tell the truth) - Yes = LTR, No = RTL&lt;br /&gt;
Yes, No, - ask #2 if #1 is T. ( We know #2 is L and will tell a lie) - Yes = RLT, No = TLR&lt;br /&gt;
No, Yes - ask # 3 if #1 is L. (We know #3 is T and will tell the truth) - Yes = LRT, No = RLT&lt;br /&gt;
No, No, - ask #3 if #1 is T. (We know #3 is L and will tell a lie) - Yes = RTL, No = TRL &lt;br /&gt;
&lt;br /&gt;
So we have the order and know who is who. &lt;br /&gt;
&lt;br /&gt;
If you like this type of brain teasers, then surely check out other &lt;a href="http://brainden.com/logic-problems.htm"&gt;logic problems&lt;/a&gt;. There are many easier ones as well.

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?s=&amp;amp;showtopic=373&amp;amp;view=findpost&amp;amp;p=2986" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

4. Truth in Packaging&lt;/h2&gt;
Three boxes are all labeled incorrectly, and you must get the labels right.

The labels on the boxes read as follows:&lt;br /&gt;
&lt;br /&gt;
[box 1] nails&lt;br /&gt;
[box 2] screws&lt;br /&gt;
[box 3] nails and screws&lt;br /&gt;
&lt;br /&gt;
To gain the information you need to move the labels to the correct boxes, you may remove a single item from one of the boxes. You may not look into the boxes, nor pick them up and shake them, etc.&lt;br /&gt;
&lt;br /&gt;
Can this be done? If so, how? If not, why not?

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
Remove an item from box 3. &lt;br /&gt;
The item tells you what label to put on box 3.&lt;br /&gt;
Move the nails and screws label to the box labeled with the other item, and its label to the remaining box.&lt;br /&gt;
&lt;br /&gt;
Example: you remove a nail from box 3. &lt;br /&gt;
Move the label nails from box 1 to box 3.&lt;br /&gt;
You can't move the nails and screws label to box 1: that would be a swap, and all three labels must be corrected.&lt;br /&gt;
Move it instead to box 2, and the screws label to box 1.&lt;br /&gt;
&lt;br /&gt;
[box 1] screws&lt;br /&gt;
[box 2] nails and screws&lt;br /&gt;
[box 3] nails

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=484" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

5. One Girl - One Boy&lt;/h2&gt;
Teanchi and Beanchi are a married couple (dont ask me who he is and who she is)! They have two kids, one of them is a girl. Assume safely that the probability of each gender is 1/2.&lt;br /&gt;
What is the probability that the other kid is also a girl?&lt;br /&gt;
Hint: It is not 1/2 as you would first think.

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
Of course, it's not 1/2 else would make it a lousy puzzle.&lt;br /&gt;
Ans: 1/3&lt;br /&gt;
&lt;br /&gt;
This is a famous question in understanding conditional probability, which simply means that given some information you might be able to get a better estimate. &lt;br /&gt;
&lt;br /&gt;
The following are possible combinations of two children that form a sample space in any earthly family:&lt;br /&gt;
Girl - Girl&lt;br /&gt;
Girl - Boy&lt;br /&gt;
Boy - Girl&lt;br /&gt;
Boy - Boy&lt;br /&gt;
&lt;br /&gt;
Since we know one of the children is a girl, we will drop the Boy-Boy possibility from the sample space.&lt;br /&gt;
This leaves only three possibilities, one of which is two girls. Hence the probability is 1/3

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=325" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

6. Whatchya Gonna Do (2 Goats and a Car)&lt;/h2&gt;
You are on a game show and there are three doors. The presenter tells you that behind one of doors there is a car and behind the other two are goats. If you pick the car you win it. After you have picked a door the presenter opens a different door with a goat behind it, he then gives you the chance to change what door you open. What should you do?&lt;br /&gt;
Hint: It is not 1/2 as you would first think.

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
Jennifer should switch. Contrary to what may seem intuitive, switching actually doubles her chances of winning the car.&lt;br /&gt;
This problem is just a re-wording of what is known as the Monty Hall Problem. The key to understanding it is that the host knows the locations of the car and goats. His knowledge changes his actions and thus affects the odds.&lt;br /&gt;
Here is a breakdown of all the possible scenarios that Jennifer faces and why Jennifer should switch:&lt;br /&gt;
&lt;br /&gt;
Door #2 has goat B (probability 1:3) - MB shows goat A behind Door #1 (1:1) - the car is behind Door #3 (1:1) - switching wins the car - total chances (1:3 x 1:1 x 1:1 = 1:3)&lt;br /&gt;
Door #2 has the car (probability 1:3) - MB shows goat A behind Door #1 (1:2) - goat B is behind Door #3 (1:1) - not switching wins the car - total chances (1:3 x 1:2 x 1:1 = 1:6)&lt;br /&gt;
Door #2 has the car (probability 1:3) - MB shows goat B behind Door #1 (1:2) - goat A is behind Door #3 (1:1) - not switching wins the car - total chances (1:3 x 1:2 x 1:1 = 1:6)&lt;br /&gt;
&lt;br /&gt;
There are (1:3 + 1:3 = 2:3) chances that switching will get Jennifer the car, and only (1:6 + 1:6 = 1:3) chances she would get the car by not switching. She should switch.&lt;br /&gt;
&lt;br /&gt;
A more general presentation of the reasoning is this:&lt;br /&gt;
At the start of the game, there is a 2:3 chance that Jennifer will pick a door with a goat behind it. If she does, the host will reveal the other other goat, and switching doors will get Jennifer the car.&lt;br /&gt;
There is a 1:3 chance she will pick the car. The host will then reveal a goat. Switching would win Jennifer a good supply of Ch?vre (and the disdain of her neighbours).&lt;br /&gt;
So, 2 out of 3 times switching gets the car. Simple - unintuitive, but simple.&lt;br /&gt;
&lt;br /&gt;
Why does the host's knowledge change the odds. Because he does not randomly select a door to open - he always opens a door with a goat. By doing this he reduced the possible scenarios for Jennifer to the four listed above. If he randomly picked, then Jenny's chances, if the show progressed as presented, would be 50/50. However, there would also be a 1:3 chance that MB would open the wrong door and reveal the car's location (followed by a 1:1 chance that MB would be sacked and re-runs of McGyver would fill out the remainder of the season!)

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=423" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

7. Sequence Puzzle&lt;/h2&gt;
The below is a number puzzle. It should be read left to right, top to bottom.

&lt;br /&gt;
&lt;br /&gt;
&lt;pre&gt;       1

      1 1

      2 1

    1 2 1 1

  1 1 1 2 2 1

  ? ? ? ? ? ?

? ? ? ? ? ? ? ?

&lt;/pre&gt;
Question 1: What is the next two rows of numbers?&lt;br /&gt;
Question 2: How was this reached?

&lt;br /&gt;
&lt;div class="clear-both"&gt;
&lt;/div&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
The secret is to say whay you see on each line and what you see becomes the next line. For full answer see below.&lt;br /&gt;
&lt;br /&gt;
Line 1 is "Two ones" (2 1)&lt;br /&gt;
Line 2 then becomes "One two, and one one" (1 2 1 1)&lt;br /&gt;
Line 3 therefore is "One one, one two and two ones" (1 1 1 2 2 1)&lt;br /&gt;
Line 4 is "Three ones, two twos and one one" (3 1 2 2 1 1)&lt;br /&gt;
Line 5 is "One three, one one, two twos and two ones" (1 3 1 1 2 2 1 1) 

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=225" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

8. How Did It Happen?&lt;/h2&gt;
A man runs a mile south, a mile west, and a mile north and ends up back where he started!&lt;br /&gt;
But the real riddle is that there are actually an infinite number of answers for where the man could have started from. Explain.

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
Any point on the circle (1 + 1/2pi) miles from the South Pole.&lt;br /&gt;
&lt;br /&gt;
After going South 1 mile, you're (1/2pi) miles from the Pole, &lt;br /&gt;
which allows you to run West 1 mile [1 lap of a 1-mile circumference circle] &lt;br /&gt;
and be able to go a mile North to the starting point.&lt;br /&gt;
&lt;br /&gt;
There is an infinite number of starting distances: &lt;br /&gt;
1 + 1/2Npi miles North of the South pole where N is any positive integer.&lt;br /&gt;
N is then the number of circular laps in your westerly mile.&lt;br /&gt;
&lt;br /&gt;
e.g. N=5280 - you'd run 5280 laps around a 1-foot circumference circle.

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=550" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

9. Hole in a Sphere&lt;/h2&gt;
A 6-inch hole is drilled through a sphere. What is the volume of the remaining portion of the sphere?&lt;br /&gt;
Clarifications:&lt;br /&gt;
[1] the hole is a circular cylinder of empty space whose axis passes through the center of the sphere - just as a drill would make if you aimed the center of the drill at the center of the sphere and made sure you drilled all the way through.&lt;br /&gt;
[2] the length of the hole [6 inches] is the height of the cylinder that forms the inside surface once the hole is drilled. picture the inside surface as viewed from inside the hole and measure the length of that surface in the direction of the axis of the drill.&lt;br /&gt;
in this sense, you could for example drill a 6-inch hole through the earth. the diameter of the hole would be huge, and you'd just have a tiny remnant of the earth left. but if you could set it on a table [a big table] it would be 6 inches high.&lt;br /&gt;
You of course could not drill a 6-inch hole through a sphere whose diameter was less than 6 inches. This fact leads to the logical answer.&lt;br /&gt;
The hard way involves calculus. The easy way uses logic.

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
Here's the mathematical solution:&lt;br /&gt;
Radius of sphere = R, radius of hole = r, length of hole = 2L [so L=3], height of cap = h.&lt;br /&gt;
Since r*r = R*R - L*L and h = R-L, we can eliminate r and h and do everything in terms of R and L.&lt;br /&gt;
Swizzling cpotting's cap formula, V[cap] = pi/3 (2R*R*R - 3R*R*L + L*L*L)&lt;br /&gt;
Cylinders are ho-hum, V[cyl] = 2pi*L*r*r = (2pi/3) (3R*R*L - 3L*L*L)&lt;br /&gt;
V[removed by drilling] = V[cylinder] + 2V[cap]&lt;br /&gt;
doing the math,&lt;br /&gt;
V[removed] = (4pi/3)R*R*R - (4pi/3)L*L*L &lt;br /&gt;
Pretty amazing: the volume removed by a hole of length 2L is the difference of the volumes of two spheres: one of radius R, the other of radius L.&lt;br /&gt;
So the remaining volume is simply the volume of a shpere with radius L. [hint-hint at the logical solution]&lt;br /&gt;
V[remainder] = (4pi/3)L*L*L = 36pi.&lt;br /&gt;
&lt;br /&gt;
Here's the logical solution:&lt;br /&gt;
My friend wouldn't have posed a math problem [boring] and she wouldn't have left out critical information. Therefore the answer couldn't depend on the radius of the sphere. I chose a sphere size [radius=3] that would make 0 volume removed [a hole of length 6 and diameter 0]. With nothing removed, the remaining volume is the original volume: (4pi/3) 3*3*3.&lt;br /&gt;
So it's 36pi.

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?s=&amp;amp;showtopic=437&amp;amp;view=findpost&amp;amp;p=3859" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

10. Help! A Remainder is Chasing Me&lt;/h2&gt;
I just found a number with an interesting property:&lt;br /&gt;
&lt;br /&gt;
When I divide it by 2, the remainder is 1.&lt;br /&gt;
When I divide it by 3, the remainder is 2.&lt;br /&gt;
When I divide it by 4, the remainder is 3.&lt;br /&gt;
When I divide it by 5, the remainder is 4.&lt;br /&gt;
When I divide it by 6, the remainder is 5.&lt;br /&gt;
When I divide it by 7, the remainder is 6.&lt;br /&gt;
When I divide it by 8, the remainder is 7.&lt;br /&gt;
When I divide it by 9, the remainder is 8.&lt;br /&gt;
When I divide it by 10, the remainder is 9.&lt;br /&gt;
&lt;br /&gt;
It's not a small number, but it's not really big, either.&lt;br /&gt;
&lt;br /&gt;
Find the smallest number with such property.

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
2519&lt;br /&gt;
The number has to end in 9.&lt;br /&gt;
Looked brute force for small numbers.&lt;br /&gt;
59 and 119 were promising, but no cigar.&lt;br /&gt;
&lt;br /&gt;
Then looked for agreement among&lt;br /&gt;
39 + multiples of 40,&lt;br /&gt;
69 + multiples of 70 and&lt;br /&gt;
89 + multiples of 90&lt;br /&gt;
Smallest one was 2519.&lt;br /&gt;
&lt;br /&gt;
Still think of this as kind of brute force.&lt;br /&gt;
Maybe there is no elegant solution.

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=535" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

Bonus! Riddle Encore&lt;/h2&gt;
Sir, I bear a rhyme excelling&lt;br /&gt;
In mystic force and magic spelling&lt;br /&gt;
Celestial sprites elucidate&lt;br /&gt;
All my own striving can't relate&lt;br /&gt;
&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
It's Pi&lt;br /&gt;
3,1 4 1 5 9&lt;br /&gt;
2 6 5 3 5 8&lt;br /&gt;
9 7 9 &lt;br /&gt;
3 2 3 8 4 6

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=724" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;div class="clear-both"&gt;
&lt;/div&gt;
&lt;strong&gt;Oldies but Goodies:&lt;/strong&gt;



&lt;br /&gt;
&lt;div class="clear-both"&gt;
&lt;/div&gt;
&lt;h2&gt;

Old Funny One&lt;/h2&gt;
Right now Mum is 21 years older then her child. In 6 years her child will be 5 times younger than she.&lt;br /&gt;
Where is Daddy?

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
The child is brand new in the womb, since .75 of a year is about 9 months. So the father is...well, ya know- pretty close by. 

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=468" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

Trapped&lt;/h2&gt;
There is a room with no windows, doors, or any sort of opening, the walls are solid steel 10 feet thick, and you are trapped inside, left only with a saw and a table.

How do you escape? (more variations in the forum)

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
Fantasy logic problem where words have alternate meanings (usually related to homonyms) &lt;br /&gt;
You saw the table in half; but the two halves together; two halves make a whole (hole) and you crawl out through the hole.

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=259" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

How Many Were Going To Saint Ives?&lt;/h2&gt;
As I was going to Saint Ives,&lt;br /&gt;
I crossed the path of seven wives.&lt;br /&gt;
Every wife had seven sacks,&lt;br /&gt;
Every sack had seven cats,&lt;br /&gt;
Every cat had seven kittens,&lt;br /&gt;
Kittens, cats, sacks, wives,&lt;br /&gt;
How many were going to Saint Ives?

&lt;br /&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
It is 1&lt;br /&gt;
You are PASSING those people. You are the ONLY person going from X to St Ives, they are going from St Ives to X

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=515" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;h2&gt;

Another Oldie - Can You Get Them All?&lt;/h2&gt;
&lt;ol&gt;
&lt;li&gt;26 L of the A

&lt;/li&gt;
&lt;li&gt;7 D of the W

&lt;/li&gt;
&lt;li&gt;7 W of the W

&lt;/li&gt;
&lt;li&gt;12 S of the Z

&lt;/li&gt;
&lt;li&gt;66 B of the B

&lt;/li&gt;
&lt;li&gt;52 C in a P (W J)

&lt;/li&gt;
&lt;li&gt;13 S in the U S F

&lt;/li&gt;
&lt;li&gt;18 H on a G C

&lt;/li&gt;
&lt;li&gt;39 B of the O T

&lt;/li&gt;
&lt;li&gt;5 T on a F

&lt;/li&gt;
&lt;li&gt;90 D in a R A

&lt;/li&gt;
&lt;li&gt;3 B M (S H T R)

&lt;/li&gt;
&lt;li&gt;32 is the T in D F at which W F

&lt;/li&gt;
&lt;li&gt;15 P in a R T

&lt;/li&gt;
&lt;li&gt;3 W on a T

&lt;/li&gt;
&lt;li&gt;100 C in a D

&lt;/li&gt;
&lt;li&gt;11 P in a F (S) T

&lt;/li&gt;
&lt;li&gt;12 M in a Y

&lt;/li&gt;
&lt;li&gt;13 is U F S

&lt;/li&gt;
&lt;li&gt;8 T on an O

&lt;/li&gt;
&lt;li&gt;29 D in F in a L Y

&lt;/li&gt;
&lt;li&gt;27 B in the N T

&lt;/li&gt;
&lt;li&gt;365 D in a Y

&lt;/li&gt;
&lt;li&gt;13 L in a B D

&lt;/li&gt;
&lt;li&gt;52 W in a Y

&lt;/li&gt;
&lt;li&gt;9 L of a C

&lt;/li&gt;
&lt;li&gt;60 M in an H

&lt;/li&gt;
&lt;li&gt;23 P of C in the H B

&lt;/li&gt;
&lt;li&gt;64 S on a C B

&lt;/li&gt;
&lt;li&gt;9 P in S A

&lt;/li&gt;
&lt;li&gt;6 B to an O in C

&lt;/li&gt;
&lt;li&gt;1000 Y in a M

&lt;/li&gt;
&lt;li&gt;15 M on a D M C

&lt;/li&gt;
&lt;/ol&gt;
&lt;div class="spoiler"&gt;
&lt;div&gt;
&lt;input onclick="showhide(this);" type="button" value="Display Answer" /&gt;

&lt;/div&gt;
&lt;div&gt;
&lt;div class="spoiler2" style="display: none;"&gt;
1 26 L of the A - 26 Letters of the Alphabet&lt;br /&gt;
2 7 D of the W - 7 days of the Week&lt;br /&gt;
3 7 W of the W - 7 wonders of the world&lt;br /&gt;
4 12 S of the Z - 12 signs of the zodiac&lt;br /&gt;
5 66 B of the B - 66 books of the bible&lt;br /&gt;
6 52 C in a P (W J) - 52 cars in a pack (without jokers)&lt;br /&gt;
7 13 S in the U S F - 13 stripes in the united states flag&lt;br /&gt;
8 18 H on a G C - 18 holes on a golf course&lt;br /&gt;
9 39 B of the O T - 39 books of the old testament&lt;br /&gt;
10 5 T on a F - 5 toes on a foot&lt;br /&gt;
11 90 D in a R A - 90 degrees in a right angel&lt;br /&gt;
12 3 B M (S H T R) - 3 blind mice (see how they run)&lt;br /&gt;
13 32 is the T in D F at which W F - 32 is the temperature in degrees ferenheight at which water freezes&lt;br /&gt;
14 15 P in a R T - 15 players in a rugby team&lt;br /&gt;
15 3 W on a T - 3 wheels on a tricycle&lt;br /&gt;
16 100 C in a D - 100 cents in a dollar&lt;br /&gt;
17 11 P in a F (S) T - 11 players in a football (soccer) team&lt;br /&gt;
18 12 M in a Y - 12 meters in a yard19 13 is U F S - 13 is unlucky for some&lt;br /&gt;
20 8 T on an O - 8 tenticles on an octopus&lt;br /&gt;
21 29 D in F in a L Y - 29 days in Feburary in a leap year&lt;br /&gt;
22 27 B in the N T - 27 books in the new testiment&lt;br /&gt;
23 365 D in a Y - 365 days in a year&lt;br /&gt;
24 13 L in a B D - 13 loaves in a baker's dozen&lt;br /&gt;
25 52 W in a Y - 52 weeks in a year&lt;br /&gt;
26 9 L of a C - 9 lives of a cat&lt;br /&gt;
27 60 M in an H - 60 minutes in an hour&lt;br /&gt;
28 23 P of C in the H B - 23 pairs of chromosomes in the human body&lt;br /&gt;
29 64 S on a C B - 64 squares on checkers board&lt;br /&gt;
30 9 P in S A - 9 provinces in south africa&lt;br /&gt;
31 6 B to an O in C - 6 bowls to an over in cricket&lt;br /&gt;
32 1000 Y in a M - 1000 years in a millenium&lt;br /&gt;
33 15 M on a D M C - 15 men on a dead man's chest

&lt;br /&gt;
&lt;br /&gt;
&lt;div class="solution"&gt;
&lt;a href="http://brainden.com/forum/index.php?showtopic=556" title="Remember: Finding the solution on your own is the greatest pleasure"&gt;Further Discussion&lt;/a&gt;&lt;/div&gt;
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&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/6526671590148787143-4495172466063828911?l=fun2full.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://fun2full.blogspot.com/feeds/4495172466063828911/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://fun2full.blogspot.com/2012/01/these-puzzelz-can-helps-you-to-make.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/6526671590148787143/posts/default/4495172466063828911?v=2'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/6526671590148787143/posts/default/4495172466063828911?v=2'/><link rel='alternate' type='text/html' href='http://fun2full.blogspot.com/2012/01/these-puzzelz-can-helps-you-to-make.html' title='These puzzelz can helps you to make sharp your mind'/><author><name>aditya</name><uri>http://www.blogger.com/profile/08550947238845248173</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://3.bp.blogspot.com/-3eVXTCK2DY0/Txs3hANjgkI/AAAAAAAAAZw/IiOfjUr6CA0/s72-c/DSC03846.JPG' height='72' width='72'/><thr:total>0</thr:total></entry><entry gd:etag='W/&quot;DUEGQX86cSp7ImA9WhRWEEs.&quot;'><id>tag:blogger.com,1999:blog-6526671590148787143.post-6275091867784444319</id><published>2011-12-28T02:20:00.001-08:00</published><updated>2011-12-28T02:20:20.119-08:00</updated><app:edited xmlns:app='http://www.w3.org/2007/app'>2011-12-28T02:20:20.119-08:00</app:edited><title>HAPPY NEW YEAR 2012</title><content type='html'>&lt;div dir="ltr" style="text-align: left;" trbidi="on"&gt;
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