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Power of Gayatri Mantra Chanting | The Power of Gayatri Mantra

2021-03-02T17:30:00.001-08:00

Mens Wallet

2013-09-11T13:17:00.000-07:00

Question : Buy Mens Wallet here!!! Answer : Mens Wallet: Mens Wallet Hope it helps. Cheers!!!

Laptop bag you are looking for!!!!

2013-09-11T13:05:00.003-07:00

Question : Cool bag that you are looking for is here!!! Click below Answer : Swiss Gear Bag Hope it helps. Cheers!!!

2011-11-22T16:06:00.001-08:00

Question:

A person earns $1000 every 4mins and 48secs. How much does he earn in 2hrs and 45mins?

Answer:

$1000 for 288 sec (4min 48 sec )

? 9900 sec (2hrs 45min)

(9900 * 1000 ) / 288

$34375

2011-11-22T15:58:00.001-08:00

Question:

Solve 5x^(-1/2) + 7 = 22?

Answer :

5/ x^(1/2) + 7 = 22

5 + 7x^(1/2) = 22x^(1/2)

5 = 15 x^(1/2)

1 = 3 x^(1/2) --- squaring on both sides

1 = 9 x

x = 1/9

2011-11-21T13:36:00.001-08:00

Question :

"Function" Problem..?

Can somebody solve this for me please...?

(a) Write a function named time () that has an integer parameter named seconds and three integer reference parameters named hours, min, and sec. The function is to convert the number of seconds passed to it from the main program into an equivalent number of hours, minutes and seconds.
(b) Write a program that inputs an integer number for seconds, calls the function, and displays the equivalent number of hours, minutes, and seconds.

Answer :

Public Function ConvertSeconds(int seconds)

{

int forHours = seconds / 3600,

remainder = seconds % 3600,

forMinutes = remainder / 60,

forSeconds = remainder % 60;

Printf (“Hours : %d”,forHours);

Printf (“Minute : %d”, forMinutes);

Printf (“Seconds : %d”, forSeconds);

Getch();

}

Hope this helps

2011-11-20T20:30:00.001-08:00

Question:

Want to delete junk stuff on my computer?

Answer :

1) Run the virus scan and remove the virus if any

2) delete the "TEMP" folder in the C drive

3) Control panel -> Add/ remove programs -> remove/unistall unused or least used programs

these are basic ones. then check whether it is fine

2011-11-18T16:48:00.001-08:00

Question:

Length of one leg of a right triangle is10 ft the length of the hypotenuse is 2 feet longer than the other leg?

Answer:

Let the length of one leg be X

then length of hypotenuse is X+2

its right triangle

(10)^2 + X^2 = (X+2)^2

100 + X^2 = X^2 +4X+4

100 = 4X + 4

X = 100/4 -1

X = 24

other leg is 24 and hypotenuse is 26

2011-11-17T14:47:00.001-08:00

Question:

How do you solve 7x+6=3x-2

Answer:

7x -3x = -2 -6

4x = -8

x = -2

2011-11-17T14:11:00.001-08:00

Question :

How to get user input in C++?

I'm making a win32 console application and I wondering how can I get user input, and by that I mean, is there a way I can store keys like enter or ctrl or alt etc. in a variable of some sort? I know I can use the cin function to store basic text but what about other keys?

Answer :

using getch() we can get the character that a user type in the keyboard and it will be in ASCII code we have to convert to the char and use it.

Sample Code :

/* This program shows how to pick up the scan codes from a keyboard */

/* These define the scan codes(IBM) for the keys. All numbers are in decimal.*/
#define PAGE_UP 73
#define HOME 71
#define END 79
#define PAGE_DOWN 81
#define UP_ARROW 72
#define LEFT_ARROW 75
#define DOWN_ARROW 80
#define RIGHT_ARROW 77
#define F1 59
#define F2 60
#define F3 61
#define F4 62
#define F5 63
#define F6 64
#define F7 65
#define F8 66
#define F9 67
#define F10 68
#include <iostream>
#include <conio.h>

using namespace std;

void main()
{
char KeyStroke;

cout << "Press Escape to quit." << endl;

do
{
KeyStroke = getch();

if (KeyStroke == 0)
{
KeyStroke = getch(); // Even though there are 2 getch() it reads one keystroke
switch (KeyStroke)
{
case PAGE_UP:
cout << "PAGE UP" << endl;
break;
case PAGE_DOWN:
cout << "PAGE DOWN" << endl;
break;
case HOME:
cout << "HOME" << endl;
break;
case END:
cout << "END" << endl;
break;
case UP_ARROW:
cout << "UP ARROW" << endl;
break;
case DOWN_ARROW:
cout << "DOWN ARROW" << endl;
break;
case LEFT_ARROW:
cout << "LEFT_ARROW" << endl;
break;
case RIGHT_ARROW:
cout << "RIGHT_ARROW" << endl;
break;
case F1:
cout << "F1" << endl;
break;
case F2:
cout << "F2" << endl;
break;
case F3:
cout << "F3" << endl;
break;
case F4:
cout << "F4" << endl;
break;
case F5:
cout << "F5" << endl;
break;
case F6:
cout << "F6" << endl;
break;
case F7:
cout << "F7" << endl;
break;
case F8:
cout << "F8" << endl;
break;
case F9:
cout << "F9" << endl;
break;
case F10:
cout << "F10" << endl;
break;
default:
cout << "Some other key." << endl;
}
}
else
cout << KeyStroke << endl;
}
while (KeyStroke != 27); // 27 = Escape key
}

Ascii Code table for C++

2011-11-17T13:46:00.001-08:00

Question:

How to display # of entries in a streamreader text file in a message box in VB08?

Answer :

Imports System
Imports System.Drawing
Imports System.Data
Imports System.IO
Imports System.Collections
Imports System.Windows.Forms
Imports System.Drawing.Printing

Public Class MainClass
    Shared Sub Main()
        Dim myReader As StreamReader

        Try
            myReader = File.OpenText("test.vb")
        Catch e As IOException
            Console.WriteLine(e.ToString)
            Console.WriteLine(e.Message)
            Exit Sub
        End Try

        Dim lineCounter As Integer = 0
        Dim currentLine As String, currentData As String

        Do
            Try
                currentLine = myReader.ReadLine
                lineCounter = lineCounter + 1
            Catch e As EndOfStreamException
                Console.WriteLine(e.Message)
            Finally
                currentData = currentData & currentLine & vbCrLf
            End Try
        Loop While currentLine <> Nothing

        Console.WriteLine("Number of lines read: " & lineCounter - 1 )

        myReader.Close()
        myReader = Nothing
    End Sub
End Class

Hope this helps

2011-11-17T11:20:00.001-08:00

Question:

How do you expand and simplify: 3(2x - 1) - 2(2x-3)

Answer:

6x -3 -4x+6 = 0

2x +3 = 0

x = -(3/2)

x = -1.5

2011-11-17T10:50:00.001-08:00

Question:

What is the equation of a line that passes through points (0, 4) and (-4, -8)?

Answer:

y = mx +c

for (0,4)

4 = 0 + c

so c = 4

for (-4,-8)

-8 = -4m + 4

- 12 = -4m

so m = 3

finally Y = 3x + 4