Info. Source of ite

SUM OF ARRAY LIST

2021-05-24T00:20:00.004-07:00

SUM OF ARRAY LIST

import java.util.ArrayList;

public class array_list_sum 
{
  public static ArrayList<Double> array_list_sum(ArrayList<Double> x, ArrayList<Double> y)
  {
    if (x.size() != y.size())
    {
      return null;
    }
    
    ArrayList<Double> result = new ArrayList<Double>();
    for (int i = 0; i < x.size(); i++)
    {
      double temp = x.get(i) + y.get(i);
      result.add(temp);
    }
    
    return result;
  }    
  
  public static void main(String[] args)   
  {
    ArrayList<Double> a = new ArrayList<Double>();
    a.add(1.0);
    a.add(2.0);
    a.add(3.0);
    
    ArrayList<Double> b = new ArrayList<Double>();
    b.add(10.0);
    b.add(11.0);
    b.add(12.0);
    
    ArrayList<Double> c = array_list_sum(a, b);
    System.out.println(c);
  }  
}

Java Programming Array List Part 3 | Java Programming Tutorial for Begin...

2021-05-22T06:04:00.003-07:00

Array List Sum

2021-05-18T19:01:00.001-07:00

import java.util.ArrayList;

public class array_list_sum 
{
  public static ArrayList<Double> array_list_sum(ArrayList<Double> x, ArrayList<Double> y)
  {
    if (x.size() != y.size())
    {
      return null;
    }
    
    ArrayList<Double> result = new ArrayList<Double>();
    for (int i = 0; i < x.size(); i++)
    {
      double temp = x.get(i) + y.get(i);
      result.add(temp);
    }
    
    return result;
  }    
  
  public static void main(String[] args)   
  {
    ArrayList<Double> a = new ArrayList<Double>();
    a.add(1.0);
    a.add(2.0);
    a.add(3.0);
    
    ArrayList<Double> b = new ArrayList<Double>();
    b.add(10.0);
    b.add(11.0);
    b.add(12.0);
    
    ArrayList<Double> c = array_list_sum(a, b);
    System.out.println(c);
  }  
}

Array List | Matrix Average | Nested For Loop | Java Programming

2021-05-18T18:53:00.002-07:00

------------------------

public class matrix_average {
  public static double average(double[][] matrix)
  {
    // First compute the sum
    double sum = 0.0;
    double number_of_entries = 0;
    for (int i = 0; i < matrix.length; i++)
    {
      number_of_entries += matrix[i].length;
      for (int j = 0; j < matrix[i].length; j++)
      {
        sum = sum + matrix[i][j];
      }
    }
    
    // Then divide the sum by the number of values in the matrix.
    double result = sum / number_of_entries;
    return result;
  }
  
  public static double column_average(double[][] matrix, int col)
  {
    // first compute the sum of values in that column
    double sum = 0;
    double number_of_values = 0;
    for (int i = 0; i < matrix.length; i++)
    {
      if (col < matrix[i].length)
      {
        sum = sum + matrix[i][col];
        number_of_values = number_of_values + 1;
      }
    }
    
    // then divide the sum by the number of values in that column
    double result = sum / number_of_values;
    return result;
  }
  
  public static void main(String[] args)   
  {
    double[][] a = { {3.2, 2.1, 5.3},
                     {8.0, 4.9, 5.7, 4.1} };

    double result = average(a);
    System.out.printf("average(a) = %.1f\n", result);
    result = column_average(a, 2);
    System.out.printf("column_average(a, 2) = %.1f\n", result);
  }  
}

Java Programming Array List Part 2 | Java Programming Tutorial for Begin...

2021-05-17T21:18:00.002-07:00

Part 1- ArrayList | Java Programming Tutorial for Beginners using Eclips...

2021-05-16T05:22:00.002-07:00

Arraylist - Finding Smallest and Largest number of an N numbers

2021-05-15T17:59:00.002-07:00




Finding smallest and largest Number using
1. Arraylist
2. methods

import java.util.Scanner;
import java.util.ArrayList;

public class read_n_numbers_array_list3
{
public static int find_min(ArrayList<Integer> values)
{
  int result = values.get(0);
  for (int i = 0; i < values.size(); i++)
  {
    if (values.get(i) < result)
    {
      result = values.get(i);
    }
  }
  return result;
}

public static int find_max(ArrayList<Integer> values)
{
  int result = values.get(0);
  for (int i = 0; i < values.size(); i++)
  {
    if (values.get(i) > result)
    {
      result = values.get(i);
    }
  }
  return result;
}

public static ArrayList<Integer> user_integers()
  {
    Scanner in = new Scanner(System.in);
    ArrayList<Integer> result = new ArrayList<Integer>();

    while(true)
    {
      System.out.printf("Enter a number, or q to quit: ");
      String input = in.next();
      if (input.equals("q"))
      {
        return result;
      }
      int number = Integer.parseInt(input);
      result.add(number);
    }
  }

public static void main(String[] args) 
{
  ArrayList<Integer> numbers = user_integers();
  int smallest = find_min(numbers);
  int largest = find_max(numbers);
  System.out.printf("\n");
  for (int i = 0; i < numbers.size(); i++)
  {
    System.out.printf("position %d: %d", i, numbers.get(i));
    if (numbers.get(i) == smallest)
    {
      System.out.printf(" *** smallest value ***\n");
    }
    else if (numbers.get(i) == largest)
    {
      System.out.printf(" *** largest value ***\n");
    }
    else
    {
      System.out.printf("\n");
    }
  }
}
}

Finding the smallest and the largest number using Array - Java Eclipse

2021-05-13T17:58:00.003-07:00

import java.util.Scanner;

public class read_n_numbers3
{
  public static int[] user_integers()
  {
    Scanner in = new Scanner(System.in);
    System.out.printf("Enter N: ");
    int N = in.nextInt();
    
    int[] result = new int[N];
    for (int i = 0; i < N; i++)
    {
      System.out.printf("Enter value %d: ", i);
      result[i] = in.nextInt();
    }

    return result;
  }

  public static int find_min(int[] values)
  {
    int result = values[0];
    for (int i = 0; i < values.length; i++)
    {
      if (values[i] < result)
      {
        result = values[i];
      }
    }
    return result;
  }
  
  public static int find_max(int[] values)
  {
    int result = values[0];
    for (int i = 0; i < values.length; i++)
    {
      if (values[i] > result)
      {
        result = values[i];
      }
    }
    return result;
  }
  
public static void main(String[] args) 
{
  int[] numbers = user_integers();
  int smallest = find_min(numbers);
  int largest = find_max(numbers);
  System.out.printf("\n");
  for (int i = 0; i < numbers.length; i++)
  {
    System.out.printf("numbers[%d] = %d", i, numbers[i]);
    if (numbers[i] == smallest)
    {
      System.out.printf(" *** smallest value ***\n");
    }
    else if (numbers[i] == largest)
    {
      System.out.printf(" *** largest value ***\n");
    }
    else
    {
      System.out.printf("\n");
    }
  }
}
}

Single Dimensional Array | Java Programming Tutorial for Beginners using...

2021-05-10T21:19:00.002-07:00

Top 5 programming language to learn in 2021

2021-05-10T00:38:00.003-07:00

Guesing Java Programming Code

2021-05-09T00:40:00.008-07:00

A program that will gues a random numbers

/* This program picks a random number, from zero up to and including 100.

   Then, the user tries to guess the number.
   After every guess, the system tells the user if the guess was correct,
   or should be higher or should be lower.
*/
import java.util.*;

public class guessing_game
{

  public static void main(String[] args)
  {
    Scanner in = new Scanner(System.in);
    Random rand = new Random();
    int pick = rand.nextInt(101); // Between 0 and 100.
    int attempt = 1;

    while (true)
    {
      System.out.printf("Try %d: Guess the number: ", attempt);
      int guess = in.nextInt();
      if (guess == pick)
      {
        System.out.printf("Correct!!!\n");
        break;
      } 
      else
      {
        if (guess < pick)
        {
          System.out.printf("Go higher.\n");
        } else
        {
          System.out.printf("Go lower.\n");
        }
      }
      attempt++;
    }
  }
}

Arrays | Array Lists | Java Programming Tutorial for Beginners using Ecl...

2021-05-06T21:46:00.003-07:00

Vowels and Consonants | Java Programming Tutorial for Beginners using Ec...

2021-05-05T18:48:00.001-07:00

hasVowelsl Boolean Return Type | Java Programming Tutorial for Beginners...

2021-05-04T18:08:00.005-07:00

public class LoopExercise {

public static void main(String[] args) {

//Counter variable to store the count of vowels and consonant

int vCount = 0, cCount = 0;

//Declare a string

String str = "This is a really simple sentence";

//Converting entire string to lower case to reduce the comparisons

str = str.toLowerCase();

for(int i = 0; i < str.length(); i++) {

//Checks whether a character is a vowel

if(str.charAt(i) == 'a' || str.charAt(i) == 'e'

|| str.charAt(i) == 'i' || str.charAt(i) == 'o'

|| str.charAt(i) == 'u') {

//Increments the vowel counter

vCount++;

}

//Checks whether a character is a consonant

else if(str.charAt(i) >= 'a' && str.charAt(i)<='z') {

//Increments the consonant counter

cCount++;

}

System.out.println("Number of vowels: " + vCount);

System.out.println("Number of consonants: " + cCount);

}

Methods Practice Problem | Java Programming Tutorial for Beginners using...

2021-05-01T15:40:00.002-07:00

JAVA PROGRAMMING: hasVowels2 sample code

2021-04-29T17:22:00.002-07:00

Definition and Usage

The indexOf() method returns the position of the first occurrence of specified character(s) in a string.

Tip: Use the lastIndexOf method to return the position of the last occurrence of specified character(s) in a string.

Syntax

There are 4 indexOf() methods:

public int indexOf(String str)
public int indexOf(String str, int fromIndex)
public int indexOf(int char)
public int indexOf(int char, int fromIndex)

Parameter Values

Parameter	Description
str	A `String` value, representing the string to search for
fromIndex	An `int` value, representing the index position to start the search from
char	An `int` value, representing a single character, e.g 'A', or a Unicode value

Technical Details

Returns:	An `int` value, representing the index of the first occurrence of the character in the string, or -1 if it never occurs

hasVowels java code Examples

import java.util.Scanner;

public class has_vowels_2
{  
  public static boolean has_vowels(String s)
  {
    for (int i = 0; i < s.length(); i++)
    {
      if ("aeiouAEIOU".indexOf(s.charAt(i)) >= 0)
      {
        return true;
      }
    }
    
    return false;
  }

  public static void main(String[] args) 
  {
    Scanner in = new Scanner(System.in);
    System.out.printf("Enter a word: ");
    String word = in.next();
    boolean result = has_vowels(word);
    System.out.printf("result = %b\n", result);
  }
}

hasVowels java code

2021-04-29T17:01:00.006-07:00

The indexOf() method returns the position of the first occurrence of specified character(s) in a string.

Syntax

There are 4 indexOf() methods:

public int indexOf(String str)
public int indexOf(String str, int fromIndex)
public int indexOf(int char)
public int indexOf(int char, int fromIndex)

==================================

import java.util.Scanner;

public class has_vowels 
{  
  public static boolean has_vowels(String s)
  {
    int counter = 0;
    
    for (int i = 0; i < s.length(); i++)
    {
      if ("aeiouAEIOU".indexOf(s.charAt(i)) >= 0)
      {
        counter++;
      }
    }
    
    return (counter > 0);
  }

  public static void main(String[] args) 
  {
    Scanner in = new Scanner(System.in);
    System.out.printf("Enter a word: ");
    String word = in.next();
    boolean result = has_vowels(word);
    System.out.printf("result = %b\n", result);
  }
}

The for loop Practice Problems | Java Programming Tutorial for Beginners...

2021-04-28T06:47:00.005-07:00

public class PrintNumbers

{

public static void main(String[] args)

{

for(int i=1; i<=10; i++)

{

System.out.println(i);

}

Methods | Java Programming Tutorial for Beginners using Eclipse 2021

2021-04-26T20:29:00.003-07:00

How to Check Student Progress | Edmodo Tutorial for Teachers 2021

2021-04-26T04:20:00.003-07:00

The While Loop Prime Numbers | Java Programming Tutorial for Beginners u...

2021-04-24T10:37:00.002-07:00

The for Loop | Java Programming Tutorial for Beginners using Eclipse 2021

2021-04-22T05:37:00.003-07:00

C++ Activity

2021-04-21T19:40:00.000-07:00

Lab Objectives

To gain experience in

implementing simple decisions
writing expressions with relational operators
input validation
simple loops
using Boolean variables

R1. The `if` statement

In C++, decisions to execute or not execute a statement or group of statements can be made by using the statement if (condition). The condition must be an expression that can be evaluated as either true or false. If it evaluates to true, a succeeding statement or group of statements enclosed in { . . . }, called a block statement will be executed.
In the example below:
How much money will be added to your account when the initial starting amount is $100?
How much money will be added to your account when the initial starting amount is $85?

#include 

int main()
{ 
    
    double initial_value, final_value;
cout <<"Please enter the initial balance: ";
cin >> initial_value;
if (inital_value > 90 )
    {  
final_value = final_value + 10;
}

    final_value = final_value + 5;
    cout <<"Final Value" <

    
    
    
    
R2. Relations and Relational Operators
The relational operators in C++ are  == != < > <= and >=
Formulate the following conditions in C++: 

         x is positive                 
         x is zero or negative                 
         x is at least 8                 
         x is less than 8                 
         x and y are both zero                 
Formulate the following conditions for the employee object e.

         The last name of e starts with the letter H                 
         The salary of e is at least $75,000                 
Formulate the following conditions on the variable harrys_birthday of type Time.
    

         Harry is at least 21 years old.                 
         Harry was born in August.                 
         Harry was born in a leap year (assume his birthday was between 1901         and 2099).                 

    
    P1. Input validationBuild and run the following program. Describe what happens when the two points have the same x coordinate?
    
    
#include 
using namespace std;
#include "ccc_shap.cpp"
main()
{  double slope;

   double xcoord, ycoord;
   Point p1, p2; 

   cout << "Input x coordinate of the first point" << "\n";
   cin >> xcoord;
   cout << "Input y coordinate of the first point" << "\n";
   cin >> ycoord;

   p1 = Point(xcoord, ycoord);

   cout << "Input x coordinate of the second point" << "\n";
   cin >> xcoord;
   cout << "Input y coordinate of the second point" << "\n";
   cin >> ycoord;

   p2 = Point(xcoord, ycoord);

   slope = (p2.get_y() - p1.get_y()) / (p2.get_x() - p1.get_x() );

   cout << "The slope of the line between Points 1 and 2 is " << slope << "\n";
   return 0;
}Correct and rebuild the program to disallow a vertical line
        (denominator = 0).
    
    
/* paste program here */
What are the results when point1=(4,2) and point2 = (4,2) ?

What are the results when when point1=(4,2.5) and point2 = (3,1.5) ?



    P2. Additional Input Validation ExerciseBuild and run the following program. Describe what happens when
    the salaries from the first and second years are equal.
    
    
#include 
    using namespace std;
    int main()
    { 
   double fyear_sal, syear_sal,tyear_sal;

   cout << "Input the first year's salary:" << "\n";
   cin >> fyear_sal;;
   cout <<  "Input the second year's salary:" <<  "\n";
   cin >> syear_sal;
   cout << "Input the third year's salary:" << "\n";
   cin >> tyear_sal;
   cout <<  "The difference between the third and second year salary and second and first is:"
   cout << ((tyear_sal-syear_sal)/(syear_sal-fyear_sal))*100 << "%";
   return 0;
    }
    Correct and rebuild the program to not allow for case where both
        the first and second year salaries are the same.
    

What are the results when fyear_salary = 100000 and syear_salary =
        100000?
    

    
    P3. The if/else StatementIn the previous examples, your program probably responded to user input
      by ignoring cases that would result in a divide by zero. Instead, you can
      use the if/else format to explicitly specify the action to be
      taken.
if (condition)
   /* do something ... */
else
   /* do something different ... */
The electric company gives a discount on electricity based upon
    usage. The normal rate is $.60 per Kilowatt Hour (KWH). If the
    number of KWH is above 1,000, then the rate is $.45 per KWH. Write a
    program that prompts the user for the number of Kilowatt Hours used and then
    calculates and prints the total electric bill.


/* paste program here */
According to your program, how much will it cost for:

         900 KWH?                 
         1,754 KWH?                 
         10,000 KWH?                 

    
    P4. Simple LoopsFrequently a decision needs to be made whether or not to do something
      again. Here is a program that computes the number of digits needed to
      represent a number in base 10, just like the function digits()
      from the preceding lab. But instead of using recursion it uses multiple
      if statements. 
/* PURPOSE:  Count number of digits needed to express an integer in base 10
             using multiple if statements
   REMARKS:  Compare to Ch.5 digits()
*/

#include 
using namespace std;

int main()
{  int input;

   cout << "Input an integer between 1 and 9999: ";
   cin >> input;

   int temp = input;
   int d = 1;

   assert ( input >= 1 and input <= 9999 );
    
   if (temp > 9)
   {  temp = temp / 10;
      d++;
   }
      
   if (temp > 9)
   {  temp = temp / 10;
      d++;
   }

   if (temp > 9)
   {  temp = temp / 10;
      d++;
   }

   if (temp > 9)
   {  temp = temp / 10;
      d++;
   }
   
   cout << input << " can be expressed in " << d << " digits" << "\n";
   
   return 0;
}

But having to write
if (temp > 9)
   {   temp = temp / 10;
       d++;
   }
four times, even using copy/paste, is clearly repetitive! It also only
      works for input <= 9999. One would like to have a way of testing that
      the input is still greater than 1 and executing the succeeding control
      block if it is. Replacing  if  with  while  does it.
    
/* PURPOSE:  Count number of digits needed to express an integer in base 10
             using while loop
*/

#include 
using namespace std;

int main()
{  int input;
  
   cout << "Input an integer: ";
   cin >> input;
   int d = 1;
   int temp = input;

   while (temp > 9)
   {  temp = temp / 10;
      d++;
   }

   cout << input << " can be expressed in " << d << " digits" << "\n";   
}
The fractions 1/2, 1/4, 1/8, ... get closer and closer to 0. Change the
      previous program to count the number of divisions by two needed to be
      within 0.0001 of zero.
/* paste program here */
    


    P5. Loop Termination
Which values of nyear cause the following loops to terminate?
/* PURPOSE: Count number of year between a user-input year and the
            year 2000.
*/            

int main()
{  int nyear;
   millennium = 2000;
   
   cout << "Please enter the current year";
   cin >> nyear;
   
   while (nyear != millennium)
   {  nyear++;
   }
   
   cout << " Another "<< millenium - nyear << "years to the millenium." << "\n";
   return 0;
}
   

    
    Re-write the preceding program so that the while loop will terminate for
      any integer input.
/* paste program here */
    
    
    


    
    P6. Processing a Sequence of InputsModify the electricity rate program to allow the user to enter data for any
    number of months.  The user should be able to enter a -1 when
    finished. The program should then compute the cost using the same
    formulas as above.
/* paste program here */

    
    R3. Using Boolean VariablesAccording to the following program, what color is the resulting mixture
      under the following inputs? 

         Y N Y                 
         Y Y N                 
         N N N                 
#include 
#include 
using namespace std;

int main()
{  string mixture;      
   bool red, green, blue;
   string string_bool;

   cout << "Include red in mixture? (y/n) " << "\n";
   cin >> string_bool;
   if (string_bool == "y")
      red = true;
   cout << "Include green in mixture? (y/n) " << "\n";
   cin >> string_bool;
   if (string_bool == "y")
      green = true;
   cout << "Include blue in mixture? (y/n) " << "\n";
   cin >> string_bool;
   if (string_bool == "y")
      blue = true;

   if (not blue and not green)     
      mixture = "RED";
   else if (not red and not blue)     
      mixture = "GREEN";
   else if (not red and not green)     
      mixture = "BLUE";
   else if (red)
   {  if (green or blue)
      {  if (green and blue)
            mixture = "BLACK";
         else if (green) 
            mixture = "YELLOW";
         else
            mixture = "PURPLE";
      }
   }
   else
   {  if (blue and green)
         mixture = "CYAN";
      else
         mixture = "WHITE";
   }
   cout << "Your mixture is " << mixture << "\n";

   return 0;
}

If Statements | Java Programming Tutorial for Beginners using Eclipse

2021-04-21T07:06:00.001-07:00

Java JOptionPane Class | Java Tutorial for Beginners using Eclipse

2021-04-19T17:47:00.003-07:00

x is positive
x is zero or negative
x is at least 8
x is less than 8
x and y are both zero

The last name of `e` starts with the letter H
The salary of `e` is at least $75,000

Harry is at least 21 years old.
Harry was born in August.
Harry was born in a leap year (assume his birthday was between 1901 and 2099).

Info. Source of ite

SUM OF ARRAY LIST

Java Programming Array List Part 3 | Java Programming Tutorial for Begin...

Array List Sum

Array List | Matrix Average | Nested For Loop | Java Programming

Java Programming Array List Part 2 | Java Programming Tutorial for Begin...

Part 1- ArrayList | Java Programming Tutorial for Beginners using Eclips...

Arraylist - Finding Smallest and Largest number of an N numbers

Finding the smallest and the largest number using Array - Java Eclipse

Single Dimensional Array | Java Programming Tutorial for Beginners using...

Top 5 programming language to learn in 2021

Guesing Java Programming Code

Arrays | Array Lists | Java Programming Tutorial for Beginners using Ecl...

Vowels and Consonants | Java Programming Tutorial for Beginners using Ec...

hasVowelsl Boolean Return Type | Java Programming Tutorial for Beginners...

Methods Practice Problem | Java Programming Tutorial for Beginners using...

JAVA PROGRAMMING: hasVowels2 sample code

Definition and Usage

Syntax

Parameter Values

Technical Details

hasVowels java code Examples

hasVowels java code

Syntax

The for loop Practice Problems | Java Programming Tutorial for Beginners...

Methods | Java Programming Tutorial for Beginners using Eclipse 2021

How to Check Student Progress | Edmodo Tutorial for Teachers 2021

The While Loop Prime Numbers | Java Programming Tutorial for Beginners u...

The for Loop | Java Programming Tutorial for Beginners using Eclipse 2021

C++ Activity

Lab Objectives

R1. The if statement

R2. Relations and Relational Operators

P1. Input validation

P2. Additional Input Validation Exercise

P3. The if/else Statement

P4. Simple Loops

P5. Loop Termination

P6. Processing a Sequence of Inputs

R3. Using Boolean Variables

If Statements | Java Programming Tutorial for Beginners using Eclipse

Java JOptionPane Class | Java Tutorial for Beginners using Eclipse

R1. The `if` statement

P3. The `if/else` Statement