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Python Technical Interview Questions

2024-07-20T20:27:00.000-07:00

1)first non repeating character

Malayalam

programming

str = "MalayalaM"

a = '\0'

for c in str:

if str.index(c) == str.rindex(c):

a = c

break

print(a)

333

####

55555

for i in range(1, 6):

for j in range(1, i+1):

if i % 2 != 0:

print(i, end='')

else:

print('#', end='')

print()

find two elements of array for given target sum

a = {2, 11, 7, 15};

target = 9;

output is

2,7

a = [2, 11, 7, 15]

target = 9

for i in range(len(a)):

for j in range(i + 1, len(a)):

if a[i] + a[j] == target:

print(a[i],a[j])

4)union of two list

a=[1,2,3,4,5]

b=[3,2,6,7,8]

output

[1, 2, 3, 4, 5, 6, 7, 8]

a=[1,2,3,4,5]

b=[3,2,6,7,8]

set1=set(a)

set2=set(b)

set3=set1.union(set2)

print(set3)

5)intersection of two list

a=[1,2,3,4,5]

b=[3,2,6,7,8]

output

[2,3]

a=[1,2,3,4,5]

b=[3,2,6,7,8]

for i in range(len(a)):

for j in range(i+1):

if a[i] == b[j]:

print(a[i])

6)Check if a String is a Palindrome

mam

reverse mam

a = "mam"

b = a[::-1]

if a == b:

print("polindrome")

else:

print("not polindrome")

7)remove duplicate in name

input sabari

output sabri

a="sabari"

s=''.join(dict.fromkeys(a))

print(s)

Javascript Output Questions

2024-07-20T20:26:00.000-07:00

output questions

1.<!DOCTYPE html>

<html>

<body>

<button id="myButton">Click me</button>

document.getElementById("myButton").addEventListener("click", function() {

document.getElementById("output").textContent = "Button was clicked!";

});

</script>

</body>

</html>

let x = { b: 1, c: 2 };

let y = Object.keys(x);

console.log(y.length);

let x = "5";

let y = 2;

console.log(x + y);

console.log(x - y);

let x = "hello";

let y = new String("hello");

console.log(x == y);

console.log(x === y);

let x = 1;

let y = "1";

console.log(++x, ++y);

let x = { a: 1, b: 2 };

let y = { b: 3 };

let z = { ...x, ...y };

console.log(z);

let x = { a: 1 };

let y = Object.assign({}, x);

console.log(x === y);

let x = 5;

let y = 6;

x += x > y ? x : y;

console.log(x);

let x = [1, 2, 3];

let y = x.map((x, i) => x + i);

console.log(y);

10.

let x = ["apple", "banana", "cherry"];

let y = x.filter((i) => i.startsWith("b"));

console.log(y);

11.

let x = 10.5;

let y = parseInt(x);

console.log(y);

12.

let x = [1];

let y = x + 1;

console.log(y);

13.

let x = [1, 2, 3];

let y = x.slice();

console.log(y, x === y);

14.

const a = [1, 2, 3];

const b = [...a];

b.push(4);

console.log(a);

15.

let a = [1, 2, 3];

let b = [4, 5, 6];

console.log(a + b);

16.

let x = [1, 2, 3];

console.log(x.concat(4, 5));

17.

<!DOCTYPE html>

<html>

<body>

</ul>

let newItem = document.createElement("li");

newItem.textContent = "Item 3";

document.getElementById("myList").appendChild(newItem);

</script>

</body>

</html>

18.

let c = { greeting: 'Hey!' };

let d;

d = c;

c.greeting = 'Hello';

console.log(d.greeting);

19.

let greeting;

greetign = {};

console.log(greetign);

20.

function sum(a, b) {

return a + b;

}

sum(1, '2');

21.

let number = 0;

console.log(number++);

console.log(++number);

console.log(number);

22.

function getAge() {

'use strict';

age = 21;

console.log(age);

}

getAge();

23.

const sum = eval('10*10+5');

24.

const obj = { a: 'one', b: 'two', a: 'three' };

console.log(obj);

25.

for (let i = 1; i < 5; i++) {

if (i === 3) continue;

console.log(i);

}

26.

Click here!

</p>

</div>

27.

const firstPromise = new Promise((res, rej) => {

setTimeout(res, 500, 'one');

});

const secondPromise = new Promise((res, rej) => {

setTimeout(res, 100, 'two');

});

Promise.race([firstPromise, secondPromise]).then(res => console.log(res));

28.

let person = { name: 'Lydia' };

const members = [person];

person = null;

console.log(members);

29.

const person = {

name: 'Lydia',

age: 21,

};

for (const item in person) {

console.log(item);

}

30.

const set = new Set([1, 1, 2, 3, 4]);

console.log(set);

Java Logical Interview Questions with Answers

2024-07-20T20:24:00.000-07:00

1)print the letters only in a string

Eg 1: Input: sabari10

output:sabari

program

import java.util.*;

public class Abc {

public static void main(String[] args) {

String a,b="";

int i;

Scanner sc=new Scanner(System.in);

a=sc.next();

for(i=0;i<a.length();i++)

{

if(a.charAt(i)>='0' && a.charAt(i)<='9')

{

continue;

}

b+=a.charAt(i);

}

System.out.println(b);

}

2)integer to binary

input

output

1010

import java.util.*;

public class Abc {

public static void main(String[] args) {

int a;

Scanner sc=new Scanner(System.in);

a=sc.nextInt();

System.out.println(Integer.toBinaryString(a));

}

3)count the character occurance in string

input

sab

output

s-1

a-1

b-1

import java.util.*;

public class Abc {

public static void main(String[] args) {

String a;

Scanner sc=new Scanner(System.in);

int count=0;

a=sc.next();

char b[]=a.toCharArray();

for(int i=0;i<b.length;i++)

{

for(int j=0;j<b.length;j++)

{

if(b[i]==b[j])

{

count++;

}

System.out.println(b[i]+""+count);

count=0;

}

array find the prime number

example

input

4 6 9 3 7

output

3 7

import java.util.*;

public class Abc {

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);

int n;

n=sc.nextInt();

int a[]=new int[n];

for(int i=0;i<a.length;i++)

{

a[i]=sc.nextInt();

}

for(int i=0;i<a.length;i++)

{

if(a[i]%2!=0 && a[i]%3!=0 && a[i]%5!=0 && a[i]%7!=0 )

{

System.out.println(a[i]);

}

else if(a[i]==2 || a[i]==3 || a[i]==5 || a[i]==7 )

{

System.out.println(a[i]);

}

Input: arr1[] = { 1, 3, 4, 5}, arr2[] = {2, 4, 6, 8}

Output: arr3[] = {1, 2, 3, 4, 4, 5, 6, 8}

Input: arr1[] = { 5, 8, 9}, arr2[] = {4, 7, 8}

Output: arr3[] = {4, 5, 7, 8, 8, 9}

import java.util.*;

public class Abc {

public static void main(String[] args) {

int a[] = {1, 3, 5, 7};

int b[] = {2, 4, 6, 8};

int n1 = a.length;

int n2 = b.length;

int c[] = new int[n1 + n2];

int i=0,j=0,k=0;

for(i=0;i<n1;i++)

{

c[k++]=a[i];

}

for(j=0;j<n2;j++)

{

c[k++]=b[j];

}

Arrays.sort(c);

for(i=0;i<c.length;i++)

{

System.out.println(c[i]);

}

Oddly Even Problem Statement

Given a maximum of 100 digit numbers as input, find the difference between the sum of odd and even position digits

Test Cases

Case 1

• Input: 4567

• Expected Output: 2

Explanation : Odd positions are 4 and 6 as they are pos: 1 and pos: 3, both have sum 10. Similarly, 5 and 7 are at even positions pos: 2 and pos: 4 with sum 12. Thus, difference is 12 – 10 = 2

Case 2

• Input: 5476

• Expected Output: 2

Case 3

• Input: 9834698765123

• Expected Output: 1

import java.util.*;

public class Abc {

public static void main(String[] args) {

int a,c1=0,c2=0,pos=1;

Scanner sc=new Scanner(System.in);

a=sc.nextInt();

while(a!=0)

{

int b=a%10;

if(pos%2==0)

{

c1=c1+b;

}

else

{

c2=c2+b;

}

a=a/10;

pos++;

}

System.out.println(Math.abs(c1-c2));

}