Learn Programming With Me

Links for the papers of OOCP in GTU

noreply@blogger.com (THE Author) — Thu, 14 Apr 2011 14:19:00 +0000

Here are the links provided for the papers of GTU in OOCP

1.http://www.gtu.edu.in/GTU_Papers/BE/NOV-DEC-JAN-10-11/140704.zip

2.http://www.gtu.edu.in/GTU_Papers/BE/2010June/140704.zip

Using Pointers (continues)

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 11:26:00 +0000

int int1 = 1036; /* some data to point to */

int int2 = 8;

int *int_ptr1 = &int1; /* get addresses of data */

int *int_ptr2 = &int2;

int_ptr1 = *int_ptr2;

int_ptr1 = int_ptr2;

Changes happen:

1.Type check warning: *int_ptr2 is not an int *

2.Changes int_ptr1 – doesn’t change int1

Using Pointers (cont.)

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 11:24:00 +0000

int int1 = 1036; /* some data to point to */

int int2 = 8;

int *int_ptr1 = &int1; /* get addresses of data */

int *int_ptr2 = &int2;

*int_ptr1 = int_ptr2;

*int_ptr1 = int2;

int1 becomes 8

Type check warning: int_ptr2 is not an int

Using Pointers

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 11:20:00 +0000

int i1;

int i2;

int *ptr1;

int *ptr2;

i1 = 1;

i2 = 2;

ptr1 = &i1;//ptr1 points to address 0x1000

ptr2 = ptr1;//ptr2 takes address of ptr1 and so ptr2 points to address 0x1000

*ptr1 = 3;//value of i1(to which ptr1 pointed becomes 3

i2 = *ptr2;//as i1=3,*ptr2=*ptr1=3,so i2 becomes 3

Pointer Operations in C

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 10:50:00 +0000

Creation

& variable Returns variable’s memory address

Dereference

* pointer Returns contents stored at address

Indirect assignment

* pointer = val Stores value at address

Assignment

pointer = ptr Stores pointer in another variable

eg.

if a variable is a=24 and it is stored at memory address 2000.Consider we want to point a pointer named p at that variable,do following things.

int *p,a=24,b,c;//initializing the pointers

*p=&a;//stores 2000 address to the pointer's address

b=*p;//outputs as '24' as it returns content of pointer

*p=55;//directly stores the value at address 2000

c=p;//stores the pointer

Pointers

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 10:29:00 +0000

Special case of bounded-size natural numbers

Maximum memory limited by processor word-size

232 bytes = 4GB, 264 bytes = 16 exabytes

A pointer is just another kind of value

A basic type in C

eg. int *ptr

The variable “ptr” is a pointer to an “int”,the datatype.

Memory Addresses

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 10:26:00 +0000

1.Storage cells are typically viewed as being byte-sized

Usually the smallest addressable unit of memory

•Few machines can directly access bits individually

Such addresses are sometimes called byte-addresses

2.Memory is often accessed as words

Usually a word is the largest unit of memory access by a single machine instruction

CLEAR’s word size is 8 bytes (= sizeof(long))

A word-address is simply the byte-address of the word’s first byte

Expressions

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 10:21:00 +0000

•Constant
–25+5

•Integral
–M*x assume M and x are both integer

•Float
–Sum/9

•Pointer
–Ptr++

•Relational
–X<=y

•Logical

–A>b && b<c

Data types and operators

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 10:20:00 +0000

•Built-in type
–Integer,float,charetc.
•Derived data types
–Array,pointeretc.
•User defined data type
–Structure, union, class, enumeration.
•Operators
–Arithmetic
–Assignment
–Increment/decrement
–Unary
–Relational
–Ternary
–Logical
–bitwise

Basic Commands

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 10:18:00 +0000

C statement

Printf(“%d”,a); //to print variable "a"

Equivalent C++ statement

Cout<<a;

C statement

Scanf(“%f”,&average); //to get the value and store in vaiable "average"

Equivalent C++ statement

Cin>>average;

C statement
Printf(“total is %d this ”,sum);//to print the variable 'sum'

Equivalent C++ statement

Cout<<“totalis“<<sum<<“ this”;

C statement
Scanf(“%d %f”,&a,&x);//to get and store the value of vaeiables 'a' and 'x'

Equivalent C++ statement

Cin>>a>>x;

GTU syllabus for OOCP

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 10:07:00 +0000

Dear friends,if you are a GTU 4th sem student and OOCP is one of your subject,here is a link of your subject syllabus.Click here to download it.

Introduction of C++

noreply@blogger.com (THE Author) — Sun, 20 Mar 2011 09:59:00 +0000

C++ was developed by Bjarne Stroustrup of AT&T to add objectoriented
constructs to the C language. Because object-oriented
methodology was relatively new at the time, and all existing
implementations of object-oriented languages were rather slow and
inefficient (most were interpreters), one goal of C++ was to maintain
the efficiency of C.

Write a program to create linear linked list interactively and print out the list and total number of items in the list.

noreply@blogger.com (THE Author) — Sat, 19 Mar 2011 16:32:00 +0000

#include<stdio.h>
#include<conio.h>
#include<process.h>
#include<stdlib.h>
struct node
{
int info;
struct node *next;
}*head,*last,*temp,*n;
void menu(); // to select the choise
void create(); // insert at last
void display(); // to print the link list
int i;
void main()
{
i=0;
clrscr();
menu();
getch();
}
void menu()
{
int ch;
printf("1. Create\n");
printf("2. Display\n");
printf("3. Exit\n");
printf("Enter choise : ");
scanf("%d",&ch);
switch(ch)
{
case 1 : create();
case 2 : display();
case 3 : printf("You have choose to exit\n");
getch(); exit(0);
default : printf("Invalid choise\n"); menu();
}
}
void create()
{
n= new node;
printf("Enter the information : ");
scanf("%d",&n->info);
if(i==0)
{
head=n;
i++;
}
else
{
last->next=n;
i++;
}
last=n;
last->next=NULL;
menu();
}
void display()
{
if(head==NULL)
{
printf("No information in list\n");
menu();
}
temp=head;
while(temp!=NULL)
{
printf("%d->",temp->info);
temp=temp->next;
}
printf("\n");
printf("Total number of elements in the link list are : %d\n",i);
menu();
}
Output:
1. Create
2. Display
3. Exit
Enter choise : 1
Enter the information : 12
1. Create
2. Display
3. Exit
Enter choise : 1
Enter the information : 23
1. Create
2. Display
3. Exit
Enter choise : 1
Enter the information : 45
1. Create
2. Display
3. Exit
Enter choise : 2
12->23->45->
Total number of elements in the link list are : 3
1. Create
2. Display
3. Exit
Enter choise : 3
You have choose to exit

Write a program to read data from keyboard, write it to a file named STUDENT again read the same data from STUDENT file and write it into DATA file. Same data should be displayed on the screen

noreply@blogger.com (THE Author) — Sat, 19 Mar 2011 16:31:00 +0000

#include<stdio.h>
#include<conio.h>
#include<process.h>
struct stud
{
int rno;
char *nm;
};
void main()
{
struct stud *s;
int n,i;
FILE *fp,*fp1;
clrscr();
printf("Enter how many record you want to input : ");
scanf("%d",&n);
s=(struct stud *)malloc(n*sizeof(struct stud));
fp=fopen("STUD.txt","w");
for(i=0;i<n;i++)
{
printf("\n\tInformation for student : %d\n",i+1);
printf("Enter Roll No : ");
scanf("%d",&s[i].rno);
printf("Enter Name : ");
fflush(stdin);
gets(s[i].nm);
fprintf(fp,"%5d %-20s\n",s[i].rno,s[i].nm);
}
fclose(fp);
fp=fopen("STUD.txt","r");
fp1=fopen("DATA.txt","w");
printf("\nContent of the STUD.txt file is\n");
printf("Roll No Name\n");
printf("---------------------------\n");
while(!feof(fp))
{
fscanf(fp,"%5d %20s\n",&s[i].rno,s[i].nm);
fprintf(fp1,"%5d %-20s\n",s[i].rno,s[i].nm);
printf("%7d %-20s\n",s[i].rno,s[i].nm);
}
fcloseall();
getch();
}
Output:
Enter how many record you want to input : 3
Information for student : 1
Enter Roll No : 1
Enter Name : happy
Information for student : 2
Enter Roll No : 2
Enter Name : Umesh
Information for student : 3
Enter Roll No : 3
Enter Name : Mehul
Content of the STUD.txt file is
Roll No Name
---------------------------
1 happy
2 Umesh
3 Mehul

Write a function using pointers to add two matrices and to return the resultant matrix to the calling function.

noreply@blogger.com (THE Author) — Sat, 19 Mar 2011 16:29:00 +0000

#include<stdio.h>
#include<conio.h>
int a[5][5],b[5][5],row,col;
void add(int(*)[5]);
int main()
{
int c[5][5],i,j;
clrscr();
printf("Enter row : ");
scanf("%d",&row);
printf("Enter column : ");
scanf("%d",&col);
printf("Enter matrix A :\n");
for(i=0;i<row;i++)
{
for(j=0;j<col;j++)
{
scanf("%d",&a[i][j]);
}
}
printf("Enter matrix B :\n");
for(i=0;i<row;i++)
{
for(j=0;j<col;j++)
{
scanf("%d",&b[i][j]);
}
}
add(c);
printf("Addition :\n");
for(i=0;i<row;i++)
{
for(j=0;j<col;j++)
{
printf("%d\t",c[i][j]);
}
printf("\n");
}
getch();
return 0;
}
void add(int c[5][5])
{
int i,j;
for(i=0;i<row;i++)
{
for(j=0;j<col;j++)
{
c[i][j]=a[i][j]+b[i][j];
}
}
}
/*
Enter row : 3
Enter column : 3
Enter matrix A :
333
333
333
Enter matrix B :
555
555
555
Addition :
8
8
8
8
8
8
8
8
8

Write a function to calculate the roots of the quadratic equation. The function must use two pointer parameters, one to receive the coefficients a, b, and c, and the other to send the roots to the calling function

noreply@blogger.com (THE Author) — Sat, 12 Mar 2011 10:31:00 +0000

#include<stdio.h>
#include<conio.h>
void solve(int*,float*);
int main()
{
int a[3];
float *root;
clrscr();
printf("Enter the value of A : ");
scanf("%d",&a[0]);
printf("Enter the value of B : ");
scanf("%d",&a[1]);
printf("Enter the value of C : ");
scanf("%d",&a[2]);
solve(a,root);
if(root==NULL)
printf("The root is not possible\n");
else if(root[0]==root[1])
printf("The root is %.2f\n",root[0]);
else
printf("The roots are %.2f & %.2f\n",root[0],root[1]);
getch();
return 0;
}
void solve(int *a,float *r)
{
float d;
d=a[1]*a[1]-4*a[0]*a[2];
if(d<0)
{
r=NULL;
}
else if(d==0)
{
r[0]=r[1]=-a[1]/(2*a[0]);
}
else
{
r[0]=-a[1]/(2*a[0]);
r[1]=-a[1]/(2*a[0]);
}
}
Output:
Enter the value of A : 1
Enter the value of B : -4
Enter the value of C : 4
The root is 2.00

Write a program using pointers to read an array of integers and print its elements in reverse order

noreply@blogger.com (THE Author) — Sat, 12 Mar 2011 10:24:00 +0000

#include<conio.h>
#include<stdio.h>
#include<stdlib.h>
int main()
{
int *ptr,i,n;
clrscr();
printf("Enter the no of elements:");
scanf("%d",&n);
ptr=(int *)malloc(sizeof(int)*n);
if(ptr==NULL)
{
printf("Not enough memory");
exit(1);
}
for(i=0; i<n; i++)
{
printf("Enter %d element : ",i+1);
scanf("%d",&ptr[i]);
}
printf("Array in original order\n");
for(i=0; i<n; i++)
{
printf("%d\n",ptr[i]);
}
printf("Array in reverse order\n");
for(i=n-1; i>=0; i--)
{
printf("%d\n",ptr[i]);
}
getch();
return 0;
}
Output:
Enter the no of elements:5
Enter 1 element : 12
Enter 2 element : 56
Enter 3 element : 89
Enter 4 element : 45
Enter 5 element : 23
Array in original order
12
56
89
45
23
Array in reverse order
23
45
89
56
12

In a program declare following structure member: name, code, age, weight and height. Read all members of the structure for 100 persons and find list of persons with all related data whose weight > 50 and height > 40 and print the same with suitable format and title

noreply@blogger.com (THE Author) — Sat, 12 Mar 2011 10:22:00 +0000

#include<stdio.h>
#include<conio.h>
#define size 3
struct
{
char nm[20],cd;
int height,age,weight;
}s[size];
int main()
{
int i;
clrscr();
for(i=0;i<size;i++)
{
printf("For person %d\n",i+1);
printf("Enter the name : ");
fflush(stdin);
gets(s[i].nm);
printf("Enter the code : ");
flushall(.);
s[i].cd=getc(stdin);
printf("Enter the age : ");
fflush(stdin);
scanf("%d",&s[i].age);
printf("Enter the weight : ");
fflush(stdin);
scanf("%d",&s[i].weight);
printf("Enter the height : ");
fflush(stdin);
scanf("%d",&s[i].height);
}
printf("\n\nData having weight>50 & height>40\n");
printf("\nName Code Age Height Weight\n");
printf("--------------------------------\n");
for(i=0;i<size;i++)
{
if(s[i].weight>50 && s[i].height>40)
printf("%-10s%-5c%3d%7d%7d\n",
s[i].nm,s[i].cd,s[i].age,s[i].height,s[i].weight);
}
getch();
return 0;
}
Output:
For person 1
Enter the name : radhe
Enter the code : D
Enter the age : 21
Enter the weight : 65
Enter the height : 144
For person 2
Enter the name : Mehul
Enter the code : R
Enter the age : 22
Enter the weight : 42
Enter the height : 45
For person 3
Enter the name : Umesh
Enter the code : S
Enter the age : 21
Enter the weight : 55
Enter the height : 35
Data having weight>50 & height>40
Name Code Age Height Weight
--------------------------------
radhe D 21 144 65

Define a structure called cricket that will describe the following information: Player name Team name Batting average Using cricket, declare an array player with 50 elements and wire a program to read the information about all the 50 players and print a list.

noreply@blogger.com (THE Author) — Sat, 12 Mar 2011 10:20:00 +0000

#include<stdio.h>
#include<conio.h>
#include<string.h>
struct cricket
{
char nm[20],team[20];
int avg;
};
#define total 5
int main()
{
struct cricket player[total],temp;
int i,j;
clrscr();
for(i=0;i<total;i++)
{
printf("For player %d\n",i+1);
printf("Enter the name of player : ");
fflush(stdin);
gets(player[i].nm);
printf("Enter the team : ");
fflush(stdin);
gets(player[i].team);
printf("Enter the batting average : ");
fflush(stdin);
scanf("%d",&player[i].avg);
}
printf("\nTeam Name Average\n");
printf(" \n");
for(i=0;i<total;i++)
{
printf("%-10s %-10s %7d\n",player[i].team,player[i].nm,player[i].avg);
}
getch();
return 0;
}
Output:
For player 1
Enter the name of player : radhe
Enter the team : India
Enter the batting average : 100
For player 2
Enter the name of player : Tiwari
Enter the team : Pakistan
Enter the batting average : 5
For player 3
Enter the name of player : Tendulkar
Enter the team : India
Enter the batting average : 45
For player 4
Enter the name of player : Dhoni
Enter the team : India
Enter the batting average : 48
For player 5
Enter the name of player : Yuvi
Enter the team : India
Enter the batting average : 39
Team Name Average
-----------------------------
India radhe 100
Pakistan Tiwari 5
India Tendulkar 45
India Dhoni 48
India Yuvi 39

Write a program that search an item from array of string

noreply@blogger.com (THE Author) — Sat, 12 Mar 2011 10:18:00 +0000

#include<stdio.h>
#include<conio.h>
#include<string.h>
int string(char[],char[]);
int main()
{
char str[100],find[20];
int i;
clrscr();
printf("Enter the string :");
gets(str);
printf("Enter the srting that you want to find : ");
gets(find);
i=string(str,find);
if(i==1)
printf("%s is found in %s",find,str);
else
printf("%s is not found in %s",find,str);
getch();
return 0;
}
int string(char str[20], char find[20])
{
int i,j,flag;
for(i=0;str[i];i++)
{
if(str[i]==find[0])
{
flag=1;
for(j=1;find[j];j++)
{
if(str[i+j]!=find[j])
{
flag=0;
break;
}
}
if(flag==1)
break;
}
}
return flag;
}
Output:
Enter the string :radhe
Enter the string that you want to find : r
r is found in string
Enter the string :kano
Enter the string that you want to find : z
z is not found in kano

Write a function to upper the string

noreply@blogger.com (THE Author) — Sat, 12 Mar 2011 10:16:00 +0000

#include<stdio.h>
#include<conio.h>
void reverse(char[]);
int main()
{
char str[20];
clrscr();
printf("Enter string : ");
gets(str);
reverse(str);
getch();
return 0;
}
void reverse(char str[20])
{
int i;
printf("%s in reverse order is ",str);
for(i=strlen(str)-1;i>=0;i--)
printf("%c",str[i]);
}
Output:
Enter string : radhe
radhe in reverse order is ehdar

Write a function that will scan a character string passed as an argument and convert all lower-case character into their upper-case equivalent

noreply@blogger.com (THE Author) — Sat, 12 Mar 2011 10:15:00 +0000

#include<stdio.h>
#include<conio.h>
void upper(char[]);
int main()
{
char str[20];
clrscr();
printf("Enter string : ");
gets(str);
upper(str);
getch();
return 0;
}
void upper(char str[20])
{
int i;
printf("%s in upper case is ",str);
for(i=0;str[i];i++)
{
if(str[i]>96 && str[i]<123)
str[i]-=32;
}
printf("%s",str);
}
Output:
Enter string :string
string in upper case is STRING

Write a function which returns 1 if the given number is palindrome otherwise returns 0

noreply@blogger.com (THE Author) — Sat, 12 Mar 2011 10:14:00 +0000

#include<stdio.h>
#include<conio.h>
int pelindrome(int);
int main()
{
int n,p;
clrscr();
printf("Enter a number : ");
scanf("%d",&n);
p=pelindrome(n);
if(p==1)
printf("%d is pelindrome",n);
else
printf("%d is not pelindrome",n);
getch();
return 0;
}
int pelindrome(int n)
{
char a[6],b[6];
itoa(n,a,10);
strcpy(b,a);
strrev(b);
if(strcmp(a,b)==0)
return 1;
else
return 0;
}
Output:
Enter a number : 123
123 is not pelindrome
Enter a number : 121
121 is palindrome

Write a function prime that returns 1 if its argument is a prime no. and returns 0 otherwise

noreply@blogger.com (THE Author) — Sat, 12 Mar 2011 10:13:00 +0000

#include<stdio.h>
#include<conio.h>
int prime(int);
int main()
{
int n,p;
clrscr();
printf("Enter a number : ");
scanf("%d",&n);
p=prime(n);
if(p==1)
printf("%d is prime\n",n);
else
printf("%d is not prime\n",n);
getch();
return 0;
}
int prime(int n)
{
int i;
for(i=2;i<n;i++)
{
if(n%i==0)
return 0;
}
return 1;
}
Output:
Enter a number : 18
18 is not prime
Enter a number : 5
5 is prime

Use recursive calls to evaluate f(x) = x – x3/3! + x5/5! – x7/7! + ……

noreply@blogger.com (THE Author) — Sat, 12 Mar 2011 10:11:00 +0000

#include<stdio.h>
#include<conio.h>
int main()
{
float series(float,int),x;
int n;
clrscr();
printf("\nEnter X:");
scanf("%f",&x);
printf("\nEnter n:");
scanf("%d",&n);
printf("\nAns %f",series(x,n));
getch();
return 0;
}
float series(float x,int n)
{
long factorial(int);
float power(float,int);
float sum=0;
int i,s=1;
for(i=1;i<=n;i+=2)
{
sum+=(power(x,i)/factorial(i))*s;
s*=-1;
}
return sum;
}
float power(float x, int y)
{
float p=1;
int i;
for(i=1;i<=y;i++)p*=x;
return p;
}
long factorial(int p)
{
long f=1;
int i;
for(i=1;i<=p;i++)f*=i;
return f;
}
Output
Enter X:1.2
Enter n:5
Ans 0.932736