<?xml version="1.0" encoding="UTF-8" standalone="no"?><rss xmlns:atom="http://www.w3.org/2005/Atom" xmlns:blogger="http://schemas.google.com/blogger/2008" xmlns:gd="http://schemas.google.com/g/2005" xmlns:georss="http://www.georss.org/georss" xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd" xmlns:openSearch="http://a9.com/-/spec/opensearchrss/1.0/" xmlns:thr="http://purl.org/syndication/thread/1.0" version="2.0"><channel><atom:id>tag:blogger.com,1999:blog-8032108473039666864</atom:id><lastBuildDate>Tue, 30 Jun 2026 16:29:00 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semplice</category><category>tronco di cono</category><category>unione</category><category>unità</category><category>valore</category><category>vettore</category><category>voto.</category><title>Matematica scuola secondaria 1° grado</title><description>MATEMATICA SCUOLA SECONDARIA 1° GRADO: sintesi di concetti matematici (aritmetica, geometria, algebra).</description><link>http://matemedie.blogspot.com/</link><managingEditor>noreply@blogger.com (Giampaolo Rubado)</managingEditor><generator>Blogger</generator><openSearch:totalResults>123</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><language>en-us</language><itunes:explicit>no</itunes:explicit><itunes:subtitle>MATEMATICA SCUOLA SECONDARIA 1° GRADO: sintesi di concetti matematici (aritmetica, geometria, algebra).</itunes:subtitle><itunes:owner><itunes:email>noreply@blogger.com</itunes:email></itunes:owner><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-6081866741032615947</guid><pubDate>Tue, 30 Jun 2026 16:00:00 +0000</pubDate><atom:updated>2026-06-30T18:29:00.166+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">addizione</category><category domain="http://www.blogger.com/atom/ns#">algebra</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">numeri relativi</category><category domain="http://www.blogger.com/atom/ns#">operazioni</category><category domain="http://www.blogger.com/atom/ns#">primo grado</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><title>Operazioni con i numeri relativi: l'addizione</title><atom:summary type="text">Per questa lezione consiglio il seguente percorso:1) leggi questo post2) esercitati con Genially (lo trovi al termine delle spiegazioni)3) allenati svolgendo esercizi con i Moduli di Google (fai clic su questo link)4) verifica il tuo apprendimento on line su questo blog (vedi al termine del post) oppure a&amp;nbsp;questo link5) Se preferisci puoi svolgere gli esercizi in forma cartacea e controllare </atom:summary><link>http://matemedie.blogspot.com/2011/09/operazioni-con-i-numeri-relativi.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhF4iedNt49bbQJKc8ysHsv6Ssu7kl9A5Gxy5e8MdnC8fdxuSgTLnGymeCoyjG1r4ER2yJ5Mqbm6LedCb2qsZa9KMZo1T1THq91iNhdvQAcOg21FAb-lWbfjBitlDl5Eaf-tRm_VOaPk2oV/s72-c/Immagine1.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-7428128332921755647</guid><pubDate>Wed, 24 Jun 2026 16:00:00 +0000</pubDate><atom:updated>2026-06-24T18:08:11.382+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">algebra</category><category domain="http://www.blogger.com/atom/ns#">assoluto</category><category domain="http://www.blogger.com/atom/ns#">concordi</category><category domain="http://www.blogger.com/atom/ns#">didattica</category><category domain="http://www.blogger.com/atom/ns#">discordi</category><category domain="http://www.blogger.com/atom/ns#">esercizi</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">inferiore</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">modulo</category><category domain="http://www.blogger.com/atom/ns#">numeri</category><category domain="http://www.blogger.com/atom/ns#">opposti</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">recupero</category><category domain="http://www.blogger.com/atom/ns#">relativi</category><category domain="http://www.blogger.com/atom/ns#">ripasso</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">valore</category><title>Numeri relativi: concordi, discordi, opposti</title><atom:summary type="text">Per questa lezione consiglio il seguente percorso:1) leggi questo post2) esercitati con Genially (lo trovi al termine delle spiegazioni)3) allenati svolgendo esercizi con i Moduli di Google (fai clic su questo link)4) verifica il tuo apprendimento on line su questo blog (vedi al termine del post) oppure a&amp;nbsp;questo link5) Se preferisci puoi svolgere gli esercizi in forma cartacea e controllare </atom:summary><link>http://matemedie.blogspot.com/2011/08/numeri-relativi-concordi-discordi.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-4971563705237801454</guid><pubDate>Fri, 12 Jun 2026 16:52:00 +0000</pubDate><atom:updated>2026-06-12T19:59:11.775+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">algebra</category><category domain="http://www.blogger.com/atom/ns#">didattica</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">I</category><category domain="http://www.blogger.com/atom/ns#">insiemi</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">numerici</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">Q</category><category domain="http://www.blogger.com/atom/ns#">R</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">Z</category><title>Insiemi numerici</title><atom:summary type="text">Per questa lezione consiglio il seguente percorso:1) leggi questo post2) esercitati con Genially (lo trovi al termine delle spiegazioni)3) allenati svolgendo esercizi con i Moduli di Google (fai clic su questo link)4) verifica il tuo apprendimento on line su questo blog (vedi al termine del post) oppure a&amp;nbsp;questo link5) Se preferisci puoi svolgere gli esercizi in forma cartacea e controllare </atom:summary><link>http://matemedie.blogspot.com/2011/08/insiemi-numerici.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhJ4RBz9qsH9AiQv3fJ7iDkTI8utBnDxGmkQ9Ug4LABQKOolCyeiwmqFUdIMkWRt0d-sgnHGsklY04iUv5AH26YprLPkVSrtaFihfOq4IEa5FQoXoIj431sx133mH6CU1VMK3ZI6BA_4MGH/s72-c/z.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-2775802526147135909</guid><pubDate>Tue, 09 Jun 2026 16:25:00 +0000</pubDate><atom:updated>2026-06-09T20:27:17.714+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1°</category><category domain="http://www.blogger.com/atom/ns#">esercizi</category><category domain="http://www.blogger.com/atom/ns#">formula</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">problemi</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">sfera</category><category domain="http://www.blogger.com/atom/ns#">superficie</category><category domain="http://www.blogger.com/atom/ns#">volume</category><title>Superficie e volume della sfera</title><atom:summary type="text">
La superficie di una sfera non è sviluppabile
in piano e ciò ha creato non pochi problemi ai geografi per rappresentare in
piano la superficie della Terra ed ai matematici per determinare la misura
della superficie sferica. 

Il grande Archimede riuscì nella dimostrazione
dell’equivalenza della superficie sferica e quella di un cilindro equilatero
circoscritto ad essa.

Poiché la superficie </atom:summary><link>http://matemedie.blogspot.com/2016/10/superficie-e-volume-della-sfera.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgZ-JdxyPORbvjl5_-bbEOlK3IBxDOtvghJDW0v04svkcJegWYOpAxrNzHzIccWU3BfD3SL3F6dNW2-dn9RkoXvjwmDZG-JTxMHO0c5NEO2zoLfxLhUKoQB9hbfV3d9-e01icQ492123Agh/s72-w200-h114-c/Immagine1.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-2663490680055033151</guid><pubDate>Wed, 03 Jun 2026 17:00:00 +0000</pubDate><atom:updated>2026-06-03T19:03:12.433+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1°</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">parti</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">sfera</category><title>La sfera</title><atom:summary type="text">
La sfera è il solido che si ottiene dalla rotazione di 360°
di un semicerchio attorno al suo diametro, come si può vedere in figura.

Il centro del semicerchio ed il suo raggio costituiscono
anche il centro ed il raggio della sfera.





La superficie sferica ha la proprietà di avere tutti i suoi
punti alla stessa distanza dal centro: sono, appunto, i raggi della sfera.



Quali sono le </atom:summary><link>http://matemedie.blogspot.com/2016/10/la-sfera.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgkBJSo3qQfEh29sozdWHMw68VlfNEJb9CBxn3xUuvKDX07Sz7wkeHVYZ_zKVZDXQvX6cd5m13CpuTpgmr4xW26yWzIlNC7rCKOT15-_c9OiPn5Kl49a-VhYfrPEFxboZZl9IrL36VwJakz/s72-c/Immagine1.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-1271152462326696017</guid><pubDate>Sat, 30 May 2026 16:00:00 +0000</pubDate><atom:updated>2026-05-30T18:17:03.086+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1°</category><category domain="http://www.blogger.com/atom/ns#">esercizi</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">laterale</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">problemi</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">superficie</category><category domain="http://www.blogger.com/atom/ns#">totale</category><category domain="http://www.blogger.com/atom/ns#">tronco di cono</category><category domain="http://www.blogger.com/atom/ns#">volume</category><title>Superficie e volume del tronco di cono</title><atom:summary type="text">
Consideriamo un cono tagliato con un piano parallelo al
piano della base: si ottengono due solidi, un cono ed un tronco di cono.



Possiamo definire il tronco di cono come il&amp;nbsp;solido che si ottiene dalla rotazione completa di un trapezio
rettangolo attorno al lato perpendicolare alle basi.



Il lato attorno a cui ruota il trapezio è l’asse
di rotazione&amp;nbsp;e l’altezza&amp;nbsp;del tronco di </atom:summary><link>http://matemedie.blogspot.com/2016/09/superficie-e-volume-del-tronco-di-cono.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj5ZH7z063ceCq7Li39YeZIUlrIMbRMqlrIZ0jxnH0t2N96fZSHdow385v3mnzDRfC5pwqcL4Ux3_Dzf9GsbtQjuyXU3ZtUSnXq7Vy_EuWmMRWRJT7L0YzXxeTg41oyVGBsfXOqF7WMFagf/s72-c/Immagine1.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-4599756012967786506</guid><pubDate>Wed, 27 May 2026 15:00:00 +0000</pubDate><atom:updated>2026-05-27T17:30:20.485+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1°</category><category domain="http://www.blogger.com/atom/ns#">area</category><category domain="http://www.blogger.com/atom/ns#">cono</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">laterale</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">superficie</category><category domain="http://www.blogger.com/atom/ns#">totale</category><category domain="http://www.blogger.com/atom/ns#">volume</category><title>Superficie e volume del cono</title><atom:summary type="text">
Possiamo ottenere il&amp;nbsp;cono&amp;nbsp;dalla
rotazione di 360° di un triangolo rettangolo attorno ad un suo cateto.



Possiamo quindi definire il cono come il&amp;nbsp;solido che si ottiene dalla
rotazione completa di un triangolo rettangolo attorno ad un suo cateto.





Il lato attorno a cui ruota il triangolo è l’asse
di rotazione&amp;nbsp;e l’altezza
del cono, l’ipotenusa è la&amp;nbsp;generatrice&amp;nbsp;e </atom:summary><link>http://matemedie.blogspot.com/2016/06/superficie-e-volume-del-cono.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhRG-cXcLSDFsrbqUBuCnNookfQwEWTfHnd7L7yHnNRutvJds4sVUW_wEjPPTmNOficdPNQFhvi9jfA4xWy-O3DTzxwabJBvu-fHU_3gHNbk-HgQJGurievnTBGNf1KyewnXpBHkhMFdooI/s72-c/Immagine4.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-6383965344375201472</guid><pubDate>Thu, 21 May 2026 17:30:00 +0000</pubDate><atom:updated>2026-05-21T19:48:18.312+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1°</category><category domain="http://www.blogger.com/atom/ns#">area</category><category domain="http://www.blogger.com/atom/ns#">cilindro</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">laterale</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">rotazione</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">superficie</category><category domain="http://www.blogger.com/atom/ns#">totale</category><category domain="http://www.blogger.com/atom/ns#">volume</category><title>Superficie e volume del cilindro</title><atom:summary type="text">
Ricordate che possiamo ottenere alcuni solidi a
superficie curva attraverso la rotazione di una figura piana attorno ad un suo
lato?


Ad esempio possiamo ottenere il&amp;nbsp;cilindro&amp;nbsp;dalla
rotazione di 360° di un rettangolo attorno ad un suo lato.





Possiamo
quindi definire il cilindro come il solido
che si ottiene dalla rotazione completa di un rettangolo attorno ad un suo lato.
Il lato </atom:summary><link>http://matemedie.blogspot.com/2016/05/superficie-e-volume-del-cilindro.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgsBM_l0HI-moTWJDJikh_zY7DABlY_AVGdGSJApeKAHBMmzRbkVwWQbLfXNGZsoFOpxTKH_oFFnwoJwZBnIQzGZpgRsR4OAMGEY6dfY48PiOBt8CW9exL2WfRU687_a3LAXzTZcpyuaMVM/s72-c/Immagine1.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-5576054813141862730</guid><pubDate>Mon, 18 May 2026 08:06:00 +0000</pubDate><atom:updated>2026-05-18T18:11:52.310+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1°</category><category domain="http://www.blogger.com/atom/ns#">area</category><category domain="http://www.blogger.com/atom/ns#">esercizi</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">laterale</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">piramide</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">problemi</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">superficie</category><category domain="http://www.blogger.com/atom/ns#">totale</category><category domain="http://www.blogger.com/atom/ns#">volume</category><title>Superficie e volume della piramide</title><atom:summary type="text">
Sappiamo
già che nell’insieme dei poliedri non regolari troviamo il sottoinsieme dei
prismi ed il sottoinsieme delle piramidi.

Le piramidi sono quei
poliedri che non hanno facce parallele, una base sola che può essere un
qualsiasi poligono e la superficie laterale formata da facce triangolari con un
vertice in comune.


Il poligono su cui
poggia è la&amp;nbsp;base&amp;nbsp;della piramide, le altre </atom:summary><link>http://matemedie.blogspot.com/2016/02/superficie-e-volume-della-piramide.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgD0zjRv3f3l4lGOx49CshrUvENMOw9u31uJmwnNPkW6unrPJe5cOX5PwmINYyc5jepke8ujzRGIoE9hzk2tXDUeIdRi8N_jF8ZhyXrujmeHvUkn_c7jkCsNVBW1btmJjrtmIixaYUAMb1V/s72-c/piramidi.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-4702551899437532674</guid><pubDate>Wed, 13 May 2026 15:30:00 +0000</pubDate><atom:updated>2026-05-13T17:42:23.733+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1à</category><category domain="http://www.blogger.com/atom/ns#">area</category><category domain="http://www.blogger.com/atom/ns#">cubo</category><category domain="http://www.blogger.com/atom/ns#">diagonale</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">laterale</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">superficie</category><category domain="http://www.blogger.com/atom/ns#">toyale</category><category domain="http://www.blogger.com/atom/ns#">volume</category><title>Superficie e volume del cubo</title><atom:summary type="text">
Il cubo è un parallelepipedo rettangolo con le tre
dimensioni congruenti, quindi si tratta di un poliedro regolare limitato da 6
facce quadrate congruenti.

Misura della diagonale








In un cubo le tre
dimensioni sono costituite dai tre spigoli (l)
uscenti dallo stesso vertice.


Consideriamo la
diagonale AG. Come ne possiamo calcolare la misura? Il triangolo GCA è un
triangolo rettangolo </atom:summary><link>http://matemedie.blogspot.com/2016/01/superficie-e-volume-del-cubo.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg0qEcIqOWCbfXfrvJEDeubmDsQDmzzo0NUK1r86hVJ9b1x8VKByuO0om7piBrRzcxIB0d15_sPhyyO0abO0fGb_Isf_MYPgHVDm6d6328s-EbQW5fkOtUM32geyGISr9hp6b1_Z8Uam52B/s72-c/Immagine1.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-1805440745703249713</guid><pubDate>Sat, 02 May 2026 16:30:00 +0000</pubDate><atom:updated>2026-05-02T18:50:06.480+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1°</category><category domain="http://www.blogger.com/atom/ns#">area</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">laterale</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">parallelepipedo</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">superficie</category><category domain="http://www.blogger.com/atom/ns#">totale</category><category domain="http://www.blogger.com/atom/ns#">volume</category><title>Superficie e volume del parallelepipedo</title><atom:summary type="text">Se un prisma ha le
basi costituite da parallelogrammi, si tratta di un prisma particolare, detto&amp;nbsp;parallelepipedo.&amp;nbsp;





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Se un
parallelepipedo ha le facce laterali perpendicolari alle basi abbiamo un parallelepipedo
retto. Le facce laterali sono tutte rettangolari e a due a </atom:summary><link>http://matemedie.blogspot.com/2015/12/superficie-e-volume-del-parallelepipedo.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjTOlevv89j1O-no6VUnNG2q4DLDWjPBdBoWv7V7g4kDQwYtq8YeYY-y4JIBB7x7NBkA8Fi41UP2biS833NgUn3g1qcCN0j_lMfPmP4H9ET0ps_SQkinG8X7YYZqQfvObWlLhZJW1VzrgT1/s72-c/Immagine6.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-2717586846288081736</guid><pubDate>Sat, 25 Apr 2026 17:35:00 +0000</pubDate><atom:updated>2026-04-25T20:09:01.257+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1°</category><category domain="http://www.blogger.com/atom/ns#">area</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">laterale</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">prisma</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">superficie</category><category domain="http://www.blogger.com/atom/ns#">totale</category><category domain="http://www.blogger.com/atom/ns#">volume</category><title>Superficie e volume nell’insieme dei prismi</title><atom:summary type="text">
Abbiamo già visto
che i prismi sono quei poliedri che hanno almeno due facce parallele e
congruenti.

Le facce parallele e
congruenti sono le&amp;nbsp;basi&amp;nbsp;del prisma, le altre facce sono
parallelogrammi e si dicono facce laterali; la distanza fra le due basi è l’altezza&amp;nbsp;del prisma.

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Solidi rotondi,



Consideriamo ora alcuni solidi rotondi, come quelli
rappresentati in figura.







Notiamo che possiamo ottenere alcuni di essi attraverso la
rotazione di una figura piana attorno ad un suo lato.

Ad esempio possiamo ottenere il cilindro dalla rotazione di un rettangolo attorno ad un suo lato.







Possiamo ottenere un cono
dalla rotazione di un triangolo rettangolo attorno</atom:summary><link>http://matemedie.blogspot.com/2015/09/solidi-rotondi-e-misure-dei-solidi.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhKxxlBm4eEGFOz5eG6a5_egnwBRewYaC2nCUAt9El0UPUiex_mzJ73HXSzCgOqMtjMgwyH9tVMAxo9IrcQpvgpr7CuPTT8UGWBrmFLTKXS9wBA-IEDgQXYXkU8MFvAnVudN_8KHKgbPsPm/s72-c/Immagine1.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-7285235483855494490</guid><pubDate>Wed, 15 Apr 2026 18:00:00 +0000</pubDate><atom:updated>2026-04-15T20:55:12.855+02:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1°</category><category domain="http://www.blogger.com/atom/ns#">corpi</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">parallelepipedi</category><category domain="http://www.blogger.com/atom/ns#">poliedri</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">prismi</category><category domain="http://www.blogger.com/atom/ns#">regolari</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">solidi</category><title>Corpi solidi: i poliedri</title><atom:summary type="text">&lt;!--[if gte mso 9]&gt;
 
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 mso-para-margin-bottom:.</atom:summary><link>http://matemedie.blogspot.com/2013/10/il-teorema-di-pitagora.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiviBaGYf9PM3BM_nb4qGGKqfy7uLk50rvqDOyv1ryTQdRhzA0NogtNjUfOkIQzQXNu4vt5NkDDTKKpfl4X0O93CmD0GTKokRT454U3c9ZT3AUNqlBgugueWawTT9Fyd2_t4r7m9Vn32GYL/s72-c/Immagine1.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-3155760047927020554</guid><pubDate>Wed, 21 Jan 2026 16:16:00 +0000</pubDate><atom:updated>2026-01-21T19:32:10.140+01:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1</category><category domain="http://www.blogger.com/atom/ns#">apotema</category><category domain="http://www.blogger.com/atom/ns#">area</category><category domain="http://www.blogger.com/atom/ns#">esercizi</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">lato</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">poligoni</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">rapporto</category><category domain="http://www.blogger.com/atom/ns#">regolari</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><title>L'area dei poligoni regolari</title><atom:summary type="text">
Sappiamo che ogni poligono regolare può essere diviso in
tanti triangoli congruenti quanti sono i lati del poligono (un pentagono in 5
triangoli, un esagono in 6 e così via).

La base di ognuno di questi triangoli coincide con il lato
del poligono mentre l’altezza è detta&amp;nbsp;
apotema (a).





Consideriamo un poligono regolare, ad esempio un quadrato,
con il lato di 4 cm e misuriamo la sua </atom:summary><link>http://matemedie.blogspot.com/2013/09/larea-dei-poligoni-regolari.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEigx6gc79rumVAVT7SROwDtMK5MOE6v8CYyVLuJ2_dCujG_ZkGmeMnOCEmYBm0es4XQZf53lBRupzvWBzZHU-mF6mSIYc1hl-C7R7nocP5L-t6USnXN2Db1ehKjkrIS8DCK9Jxu1yNKhoci/s72-c/Immagine1.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-8043286355297615542</guid><pubDate>Tue, 13 Jan 2026 16:30:00 +0000</pubDate><atom:updated>2026-01-13T17:45:29.391+01:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">area</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">problemi</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">triangoli</category><title>L'area dei triangoli</title><atom:summary type="text">

Consideriamo
un qualsiasi triangolo ABC, costruiamo un secondo triangolo congruente al primo
e spostiamolo nel modo indicato in figura.





Otteniamo
un parallelogramma con un’area equivalente a quella di due triangoli: possiamo
dunque dire che l’area del triangolo corrisponde alla metà dell’area di un
romboide con la stessa base e la stessa altezza del triangolo. Quindi:

A = (b x h) : 2 &amp;</atom:summary><link>http://matemedie.blogspot.com/2013/04/larea-dei-triangoli.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgsBJBooI07uDQP__goArpWtyQ_TFAxNb49skN5rJ0GUNBVG23fH9TN2Yjjbf0PjLfhgY5ig4HlR9ZCYjUQsc7w8XsIHM3poPKP8me_qHUpgn4MWcTrXAuhkX0NunGMHvHa_fSg1TaXDfvM/s72-c/Immagine1.png" width="72"/></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-8032108473039666864.post-3612489284577627817</guid><pubDate>Fri, 12 Dec 2025 17:00:00 +0000</pubDate><atom:updated>2025-12-12T18:18:49.825+01:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">1°</category><category domain="http://www.blogger.com/atom/ns#">area</category><category domain="http://www.blogger.com/atom/ns#">esercizi</category><category domain="http://www.blogger.com/atom/ns#">geometria</category><category domain="http://www.blogger.com/atom/ns#">grado</category><category domain="http://www.blogger.com/atom/ns#">matematica</category><category domain="http://www.blogger.com/atom/ns#">media</category><category domain="http://www.blogger.com/atom/ns#">parallelogramma</category><category domain="http://www.blogger.com/atom/ns#">primo</category><category domain="http://www.blogger.com/atom/ns#">quadrato</category><category domain="http://www.blogger.com/atom/ns#">quadrilateri</category><category domain="http://www.blogger.com/atom/ns#">rettangolo</category><category domain="http://www.blogger.com/atom/ns#">rombo</category><category domain="http://www.blogger.com/atom/ns#">scuola</category><category domain="http://www.blogger.com/atom/ns#">secondaria</category><category domain="http://www.blogger.com/atom/ns#">trapezio</category><title>Le aree dei quadrilateri</title><atom:summary type="text">

Ricordiamo alcuni concetti fondamentali, prima di procedere oltre:

- L’area di una figura piana è la misura della superficie occupata dalla figura stessa

- Due figure piane sono equivalenti quando hanno la stessa area

- Se due figure sono congruenti, sono anche equivalenti

- Se due figure sono equivalenti, possono anche non essere congruenti

- L’unità di misura convenzionale per le </atom:summary><link>http://matemedie.blogspot.com/2013/02/le-aree-dei-quadrilateri.html</link><author>noreply@blogger.com (Giampaolo Rubado)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" height="72" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjirBhMMCrA9G-NwNrumzVBp6AviQVHdfkJhj1VRRbvlrmp0nq-Sowvm6slcSqS7Pc9dFG5UG7ZvVXCJw_G6-xzYJg86kRZFZTtIXJnuTawhrpQhhxtl26pS3Td1wvDTyPOPo-eWNDmD3V5/s72-c/Immagine1.png" width="72"/></item></channel></rss>