<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:blogger='http://schemas.google.com/blogger/2008' xmlns:georss='http://www.georss.org/georss' xmlns:gd="http://schemas.google.com/g/2005" xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-5362039071030706309</id><updated>2024-11-01T10:33:31.841+00:00</updated><title type='text'>Nuestros retos matemáticos</title><subtitle type='html'>Concurso para mis alumnos de 1º y 2º de E.S.O.</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>19</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-2120646441804828092</id><published>2014-01-21T18:41:00.000+00:00</published><updated>2014-01-21T18:41:56.930+00:00</updated><title type='text'>Vamos con el #10</title><content type='html'>&lt;div style=&quot;text-align: left;&quot;&gt;
¿Sabemos qué es un &lt;b&gt;&lt;u&gt;sudoku&lt;/u&gt;&lt;/b&gt;?&lt;/div&gt;
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Se trata de un pasatiempo numérico en el que se ofrece un tablero dividido en casillas y a su vez en cuadrados formados por nueve casillas (3x3). En diferentes casillas se recogen números del 1 al 9 (ambos incluidos) y para resolverlo se ha de conseguir la siguiente combinación: las filas horizontales y verticales deberán incluir los números del 1 al 9, sin repetirse ninguno, y lo mismo ha de ocurrir en esas celdas de 9 casillas. Explicarlo parece muy sencillo; resolverlo requiere paciencia y habilidad. Ese es el gran atractivo del sudoku.&lt;div&gt;
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Pero nosotros vamos a empezar con uno un poco más fácil, un sudoku de 6 casillas. Las reglas son las mismas: colocamos los números del 1 al 6 de forma que las filas horizontales y verticales incluyan los números del 1 al 6, sin repetir ninguno, y lo mismo ha de ocurrir en cada uno de los bloques de 6 celdas. &amp;nbsp;Te ayudamos con algunas pistas.&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/2120646441804828092/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2014/01/vamos-con-el-10.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/2120646441804828092'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/2120646441804828092'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2014/01/vamos-con-el-10.html' title='Vamos con el #10'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiAVGzoAZHQugxpopgdpsCthkaK69_HBeAnpAwwRPU_1g9cs1jyDymMq0qSGlIzd3XI4mu9HoKep3wcnJv64ywEE-r2TygxghJBY2MXIkURc3dN0P4XFma1mwg8QPUEm6hn5JCxPNf-2hw/s72-c/Sudoku_6x6_Con+Pistas.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-6705836491725726759</id><published>2014-01-21T18:32:00.000+00:00</published><updated>2014-01-21T18:32:36.656+00:00</updated><title type='text'>Solución al reto #9</title><content type='html'>Creo que esta explicación no da lugar a ninguna duda de cómo se resolvió:&lt;br /&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/6705836491725726759/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2014/01/solucion-al-reto-9.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/6705836491725726759'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/6705836491725726759'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2014/01/solucion-al-reto-9.html' title='Solución al reto #9'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgfOCVDi0mJthAlv3l1DJnfLIqplCW8Ocupbj_A_bXHTSpHCvH_RUEjiflBUlo0gCNdS-jlcH0Aayt0J95YKtCqYUgthNbmztGqWMZlm2iWffjcQvViAy4i73XDq_yvKQ_LzjSkFOjCAWQ/s72-c/reto9_b.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-2464369273680707788</id><published>2014-01-14T18:40:00.001+00:00</published><updated>2014-01-14T18:40:59.396+00:00</updated><title type='text'>Reto #9</title><content type='html'>&lt;div style=&quot;text-align: center;&quot;&gt;
Cuadrado mágico de orden 4 x 4&lt;/div&gt;
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¿Recuerdas el reto #4? Se trataba de resolver un cuadrado mágico de orden 3 x 3, esto es, colocar números en las celdas del cuadrado de forma que la suma de las filas, columnas y diagonales den el mismo resultado: la SUMA MÁGICA.&lt;/div&gt;
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Subimos el nivel de nuestros retos y vamos ahora a resolver un cuadrado, mágico también, pero de orden 4 x 4. ¿Te atreves?&lt;/div&gt;
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&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhogQH9RitXSCmDEMEvKWcQnAUaoKslC7r30YjU25qONC-inOXjfdlAn6R0FfSXNQYCOdwnzfaz9Ie231Xdpwrz2oR_4RRTL59bpOCk-2wVzFFDeufCfd5mtu1Y80_zLJTHoNB0PNAC1CQ/s1600/reto9.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;402&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhogQH9RitXSCmDEMEvKWcQnAUaoKslC7r30YjU25qONC-inOXjfdlAn6R0FfSXNQYCOdwnzfaz9Ie231Xdpwrz2oR_4RRTL59bpOCk-2wVzFFDeufCfd5mtu1Y80_zLJTHoNB0PNAC1CQ/s640/reto9.png&quot; width=&quot;640&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/2464369273680707788/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2014/01/reto-9.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/2464369273680707788'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/2464369273680707788'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2014/01/reto-9.html' title='Reto #9'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhogQH9RitXSCmDEMEvKWcQnAUaoKslC7r30YjU25qONC-inOXjfdlAn6R0FfSXNQYCOdwnzfaz9Ie231Xdpwrz2oR_4RRTL59bpOCk-2wVzFFDeufCfd5mtu1Y80_zLJTHoNB0PNAC1CQ/s72-c/reto9.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-6885538728374690846</id><published>2014-01-14T18:06:00.000+00:00</published><updated>2014-01-14T18:06:20.559+00:00</updated><title type='text'>Solución reto #8</title><content type='html'>&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: left;&quot;&gt;
Esta semana he elegido esta respuesta para la solución del reto.&amp;nbsp;&lt;/div&gt;
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&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgCuQIhE6-D_EOAleXQYEgHRRKmOUo7IpYkAbyX2gPOK_MzcwSTC7nJfWO-98NhhMccZbYd7Zf-SlfOvWkd7PbLfCSoDr-B-7sRkauDNGQJldzZ8f84m8Mp-F7De67i6Rx0N4qYerFuclc/s1600/reto8.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;268&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgCuQIhE6-D_EOAleXQYEgHRRKmOUo7IpYkAbyX2gPOK_MzcwSTC7nJfWO-98NhhMccZbYd7Zf-SlfOvWkd7PbLfCSoDr-B-7sRkauDNGQJldzZ8f84m8Mp-F7De67i6Rx0N4qYerFuclc/s640/reto8.png&quot; width=&quot;640&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
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La forma un tanto peculiar de la que habla en la explicación no es más que un cuadrado con un cierto ángulo de giro, ¿no les parece?&lt;/div&gt;
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Vamos a ver el siguiente reto de qué va.&lt;/div&gt;
&lt;br /&gt;</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/6885538728374690846/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2014/01/solucion-reto-8.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/6885538728374690846'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/6885538728374690846'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2014/01/solucion-reto-8.html' title='Solución reto #8'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgCuQIhE6-D_EOAleXQYEgHRRKmOUo7IpYkAbyX2gPOK_MzcwSTC7nJfWO-98NhhMccZbYd7Zf-SlfOvWkd7PbLfCSoDr-B-7sRkauDNGQJldzZ8f84m8Mp-F7De67i6Rx0N4qYerFuclc/s72-c/reto8.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-3707944327491220337</id><published>2014-01-07T20:08:00.000+00:00</published><updated>2014-01-07T20:08:07.079+00:00</updated><title type='text'>Calentando motores..... Reto #8</title><content type='html'>Aquí llega el primer reto del año. Seguimos nuestro concurso de retos matemáticos y empezamos el año con un reto muy relacionado con el reto del primer trimestre que más debate creó entre ustedes: me refiero al de contar cuadrados.&lt;br /&gt;
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Por supuesto, cambiamos un poco la figura en donde hay que encontrar los cuadrados:&lt;br /&gt;
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&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEheV3bLORg1uWFEL16M53PksyGA5RSGJ_Eez_A5Q2_XBzkRX21LozrolDPYBU8nwA6Cw1hMxjJapZmhe0VIG8RTc_thNBulL2yzygUbOwfZm0UILZMuHSRRVodJvjCWwKgTSpcAMsdJ1Y0/s1600/reto8.jpg&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEheV3bLORg1uWFEL16M53PksyGA5RSGJ_Eez_A5Q2_XBzkRX21LozrolDPYBU8nwA6Cw1hMxjJapZmhe0VIG8RTc_thNBulL2yzygUbOwfZm0UILZMuHSRRVodJvjCWwKgTSpcAMsdJ1Y0/s1600/reto8.jpg&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
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La cuestión es:&amp;nbsp;&lt;/div&gt;
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&lt;b&gt;¿Cuántos cuadrados puedes crear a partir de esta figura conectando cuatro cualesquiera de sus puntos?&lt;/b&gt;&lt;br /&gt;
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Las cuatro esquinas de cada cuadrado deben corresponderse con cuatro puntos del dibujo.&lt;br /&gt;
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A modo de ejemplo, te dibujo uno de los cuadrados:&lt;/div&gt;
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¿Cuántos ves tú?&amp;nbsp;&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/3707944327491220337/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2014/01/calentando-motores-reto-8.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/3707944327491220337'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/3707944327491220337'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2014/01/calentando-motores-reto-8.html' title='Calentando motores..... Reto #8'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEheV3bLORg1uWFEL16M53PksyGA5RSGJ_Eez_A5Q2_XBzkRX21LozrolDPYBU8nwA6Cw1hMxjJapZmhe0VIG8RTc_thNBulL2yzygUbOwfZm0UILZMuHSRRVodJvjCWwKgTSpcAMsdJ1Y0/s72-c/reto8.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-3811313741803559793</id><published>2013-12-23T19:44:00.000+00:00</published><updated>2013-12-23T19:44:12.203+00:00</updated><title type='text'>Solución reto #7</title><content type='html'>Antes de irnos de vacaciones quedó pendiente de publicar la solución al reto #7. Aquí va la solución, aunque creo que ya todos ustedes habían dado con ella,....&lt;br /&gt;
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&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjI8HjqLdswQpAKV9pwylBkJi1YGcpGN5plmIFUPimQ2DKYIDJBzDCXBl6lb_LQbhmZOPupXYFkjzfXai-de7MxkX1RZzVk98OcjWddCiGu12BoYEavTcHghnS41iZPVOe1ShMbwLaSdaM/s1600/RETO7.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjI8HjqLdswQpAKV9pwylBkJi1YGcpGN5plmIFUPimQ2DKYIDJBzDCXBl6lb_LQbhmZOPupXYFkjzfXai-de7MxkX1RZzVk98OcjWddCiGu12BoYEavTcHghnS41iZPVOe1ShMbwLaSdaM/s1600/RETO7.png&quot; height=&quot;289&quot; width=&quot;640&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
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DESPUÉS DE NAVIDAD, NUEVOS RETOS&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/3811313741803559793/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/12/solucion-reto-7.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/3811313741803559793'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/3811313741803559793'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/12/solucion-reto-7.html' title='Solución reto #7'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjI8HjqLdswQpAKV9pwylBkJi1YGcpGN5plmIFUPimQ2DKYIDJBzDCXBl6lb_LQbhmZOPupXYFkjzfXai-de7MxkX1RZzVk98OcjWddCiGu12BoYEavTcHghnS41iZPVOe1ShMbwLaSdaM/s72-c/RETO7.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-1910490896412130912</id><published>2013-12-10T15:00:00.000+00:00</published><updated>2013-12-10T15:00:00.576+00:00</updated><title type='text'>Reto #7</title><content type='html'>Vamos con el último reto de este trimestre. Ya estamos cerca de saber quiénes son los ganadores de este primer concurso, pero todavía falta que contesten a este nuevo reto:&lt;br /&gt;
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RETO DEL UNO MÁS&lt;/div&gt;
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Empezamos y terminamos con el reto del uno. Les recuerdo las normas del reto del uno más:&lt;/div&gt;
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&lt;span style=&quot;font-size: large;&quot;&gt;El reto del Uno más consiste en descubrir cada uno de los sumandos de la adición teniendo en cuenta que cada uno posee los dígitos del sumando anterior más un nuevo dígito.&lt;br /&gt;&lt;br /&gt;Encuentra los sumandos teniendo en cuenta cada una de las pistas para cada número de tal manera que la suma sea la cifra indicada.  Recuerda cumplir con las reglas del Uno más.&lt;/span&gt;&lt;div&gt;
&lt;span style=&quot;font-size: large;&quot;&gt;&lt;br /&gt;&lt;/span&gt;&lt;/div&gt;
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&lt;span style=&quot;background-color: yellow; font-size: large;&quot;&gt;Y ya qué estamos una pregunta para añadir a la respuesta que me envíen: ¿Qué es eso de &quot;número atómico&quot;? Espero la mejor respuesta.&lt;/span&gt;&lt;/div&gt;
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&lt;span style=&quot;font-size: large;&quot;&gt;&lt;br /&gt;&lt;/span&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/1910490896412130912/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/12/reto-7.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/1910490896412130912'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/1910490896412130912'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/12/reto-7.html' title='Reto #7'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiwHu6lD6AwIxKBsbX0iX0b2aof8Y_XyzHicR8LeMwB4wnZ_l60OmL8sa_-diluEC4AJFt4tCjJhwhTRhNJzz7oKdX8mDMRf37KIZ_C8k-HbRaQf-etLKSVhajdNXubd-bSeI_o9skOTs8H/s72-c/Reto+Matematico_Uno+mas_2.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-1314654311769623139</id><published>2013-12-10T14:00:00.000+00:00</published><updated>2013-12-10T14:00:01.248+00:00</updated><title type='text'>Solución al reto #6</title><content type='html'>Esta es la solución que aporta Noelia:&lt;br /&gt;
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&quot;&lt;span style=&quot;background-color: white; color: #222222; font-family: arial, sans-serif; font-size: 13px;&quot;&gt;La solución del reto 6 es 2345.&lt;/span&gt;&lt;br /&gt;
&lt;div style=&quot;background-color: white; color: #222222; font-family: arial, sans-serif; font-size: 13px;&quot;&gt;
He llegado a este resultado de la siguiente forma:&lt;/div&gt;
&lt;div style=&quot;background-color: white; color: #222222; font-family: arial, sans-serif; font-size: 13px;&quot;&gt;
El 5, lo averigüe porque el número es múltiplo de 5, y por tanto tiene que acabar en 0 o en 5, y como dice que no tiene ninguna cifra en común con el 1680, descarté el 0 y sólo me quedó el 5, además, también es común con el 3596.&lt;/div&gt;
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El 2 y el 3 los escogí porque dice que las dos primeras cifras son números primos y su suma da otro número primo, y como 2+3=5, lo coloqué, y además, el 2 coincide en la misma posición que en 2748, y el 3 es común con el 3596.&lt;/div&gt;
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El 4, lo saqué un poco por deducción ya que la suma de sus cifras debía dar 14, y además se encuentra en el mismo lugar que en 2748: 14- (2+3+5)=4&quot;&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/1314654311769623139/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/12/solucion-al-reto-6.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/1314654311769623139'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/1314654311769623139'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/12/solucion-al-reto-6.html' title='Solución al reto #6'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhPo9gxtnL8nBpDcxuzs2ql8IC6lBY8jSVHEL60Ozr7-7PFM46z2CRJ_p1Ue_PuL5abo9wKqfuZg-ZXgToaw0twQq0oPYAM_XQgy8pxCk0lsl49SM6yXvbNR7mkmjhUcnckIJnayi8tF_E/s72-c/reto6_solucion.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-5031940974382237011</id><published>2013-12-03T15:00:00.000+00:00</published><updated>2013-12-03T15:00:01.013+00:00</updated><title type='text'>Reto #6</title><content type='html'>&lt;div style=&quot;text-align: center;&quot;&gt;
DESCUBRE EL NÚMERO&lt;/div&gt;
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El reto de esta semana consiste en descubrir un número de cuatro dígitos &lt;b&gt;&lt;u&gt;diferentes&lt;/u&gt;&lt;/b&gt; que cumpla con todas las condiciones que se enuncian en las pistas.&lt;/div&gt;
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&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi1mdl8xIbb_2DCArDk0Uudcz9E4ALJQWHOIhZyjfzyOT7cULhkAHGRIQ_EO1sLnhoo4-E7Jczn6V6lrqzW8mNJx4M8Plyykukg2N0It6vZaw62CvHT4Fn975vam6BqQC79U4Xcr0bchYs/s1600/reto6.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;468&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi1mdl8xIbb_2DCArDk0Uudcz9E4ALJQWHOIhZyjfzyOT7cULhkAHGRIQ_EO1sLnhoo4-E7Jczn6V6lrqzW8mNJx4M8Plyykukg2N0It6vZaw62CvHT4Fn975vam6BqQC79U4Xcr0bchYs/s640/reto6.png&quot; width=&quot;640&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/5031940974382237011/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/12/reto-6.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/5031940974382237011'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/5031940974382237011'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/12/reto-6.html' title='Reto #6'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi1mdl8xIbb_2DCArDk0Uudcz9E4ALJQWHOIhZyjfzyOT7cULhkAHGRIQ_EO1sLnhoo4-E7Jczn6V6lrqzW8mNJx4M8Plyykukg2N0It6vZaw62CvHT4Fn975vam6BqQC79U4Xcr0bchYs/s72-c/reto6.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-6999112856849149155</id><published>2013-12-03T14:00:00.000+00:00</published><updated>2013-12-03T14:00:06.770+00:00</updated><title type='text'>Resolvemos el reto #5</title><content type='html'>He aquí la solución al reto de los cuadrados: ¿cuántas veces tuvieron que contar para llegar a la solución correcta? Alguno lo tuvo que contar varias veces y explicárselo a algún compañero para que lo entendiera (los alumnos de 1º un poco picados por encontrar el número correcto).... pero lo encontraron desde luego.&lt;br /&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/6999112856849149155/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/12/resolvemos-el-reto-5.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/6999112856849149155'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/6999112856849149155'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/12/resolvemos-el-reto-5.html' title='Resolvemos el reto #5'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjRGQxX8c0_byaTZy2G9SpHqgCSfMs5qYY4_oEjHEdSynmPZ787j3-9xGVBIHt70h1eoYlpSzRTzFdlgUbZHarmbVfLeRTLuJHILi4PNcJb6UNTaXxE9mhw0yI9JTWLaCTsnV94cSot2Wc/s72-c/reto5.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-2800219133325675091</id><published>2013-11-26T15:00:00.000+00:00</published><updated>2013-11-26T15:00:01.347+00:00</updated><title type='text'>Reto #5</title><content type='html'>&lt;div style=&quot;background-color: white; color: #555555; font-family: Arial, Helvetica, sans-serif; font-size: 12px; line-height: 20px; text-align: justify;&quot;&gt;
&lt;i&gt;&lt;b&gt;&lt;span style=&quot;font-size: medium;&quot;&gt;&lt;br /&gt;&lt;/span&gt;&lt;/b&gt;&lt;/i&gt;&lt;/div&gt;
&lt;div style=&quot;background-color: white; color: #555555; font-family: Arial, Helvetica, sans-serif; font-size: 12px; line-height: 20px; text-align: center;&quot;&gt;
&lt;i&gt;&lt;b&gt;&lt;span style=&quot;font-size: medium;&quot;&gt;¿CUÁNTOS&amp;nbsp;CUADRADOS&amp;nbsp;HAY?&lt;/span&gt;&lt;/b&gt;&lt;/i&gt;&lt;/div&gt;
&lt;div style=&quot;background-color: white; color: #555555; font-family: Arial, Helvetica, sans-serif; font-size: 12px; line-height: 20px; text-align: center;&quot;&gt;
&lt;i&gt;&lt;b&gt;&lt;span style=&quot;font-size: medium;&quot;&gt;&lt;br /&gt;&lt;/span&gt;&lt;/b&gt;&lt;/i&gt;&lt;/div&gt;
&lt;div style=&quot;background-color: white; color: #555555; font-family: Arial, Helvetica, sans-serif; font-size: 12px; line-height: 20px; text-align: justify;&quot;&gt;
Seguimos retando a los alumnos: este es un excelente juego de observación en el cual debes descubrir ¿cuántos&amp;nbsp;cuadrados&amp;nbsp;en total se pueden contar en la siguiente imagen?&lt;/div&gt;
&lt;div style=&quot;background-color: white; color: #555555; font-family: Arial, Helvetica, sans-serif; font-size: 12px; line-height: 20px; text-align: justify;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div class=&quot;separator&quot; style=&quot;background-color: white; clear: both; color: #555555; font-family: Arial, Helvetica, sans-serif; font-size: 12px; line-height: 20px; text-align: center;&quot;&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg61vOUMBmmtjTuFENKVwID8Gq3KbuzKcNOJBrNKweMTfJoV6Tv_kEfqJFCNbAnikQc7q77KIzXb6_M053c7yOW1A3NgUUzn79tbQDoQ1Uyo3usleNya7TQ0mJaXAbYo3hw1QEJG7YSO7aO/s1600/Cuantos+cuadrados+hay+2.png&quot; imageanchor=&quot;1&quot; style=&quot;color: #e6302d; margin-left: 1em; margin-right: 1em; outline: none; text-decoration: none;&quot;&gt;&lt;img alt=&quot;Cuadrados, Número de Cuadrados, Cuántos Cuadrados hay, Problemas matemáticos, Problemas para pensar, Desafíos matemáticos, Acertijos, Problemas de Observación&quot; border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg61vOUMBmmtjTuFENKVwID8Gq3KbuzKcNOJBrNKweMTfJoV6Tv_kEfqJFCNbAnikQc7q77KIzXb6_M053c7yOW1A3NgUUzn79tbQDoQ1Uyo3usleNya7TQ0mJaXAbYo3hw1QEJG7YSO7aO/s320/Cuantos+cuadrados+hay+2.png&quot; height=&quot;170&quot; style=&quot;background-color: transparent; background-position: initial initial; background-repeat: initial initial; border: none; padding: 0px;&quot; title=&quot;¿CUÁNTOS CUADRADOS HAY?&quot; width=&quot;320&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;div class=&quot;separator&quot; style=&quot;background-color: white; clear: both; color: #555555; font-family: Arial, Helvetica, sans-serif; font-size: 12px; line-height: 20px; text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div class=&quot;separator&quot; style=&quot;background-color: white; clear: both; color: #555555; font-family: Arial, Helvetica, sans-serif; font-size: 12px; line-height: 20px; text-align: left;&quot;&gt;
Y ojo a la explicación, no me vale que me digan que contaron los cuadrados para obtener la respuesta. La cuestión es: ¿qué estrategia utilizaste para que no se te perdiera ningún cuadrado por el camino del recuento?&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/2800219133325675091/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/11/reto-5.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/2800219133325675091'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/2800219133325675091'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/11/reto-5.html' title='Reto #5'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg61vOUMBmmtjTuFENKVwID8Gq3KbuzKcNOJBrNKweMTfJoV6Tv_kEfqJFCNbAnikQc7q77KIzXb6_M053c7yOW1A3NgUUzn79tbQDoQ1Uyo3usleNya7TQ0mJaXAbYo3hw1QEJG7YSO7aO/s72-c/Cuantos+cuadrados+hay+2.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-6843240570160075011</id><published>2013-11-26T14:00:00.000+00:00</published><updated>2013-11-26T18:50:15.741+00:00</updated><title type='text'>Solución del reto #4</title><content type='html'>&lt;div style=&quot;text-align: left;&quot;&gt;
Hoy elegimos como respuesta una bastante &quot;currada&quot;....&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiLHWjLY8bizsLlf4x_ciSvRedR4M1yFs5jb_GTQIhIZIn8pJMA0ufZ09xw3vZWoWJhKfEDl_Qwx-zDVOWmA66Y61JBex-ZY_ZxwQUWEWF5gyhetS-Wf_KAYznlRZnJrp6MFOBX1dFySpw/s1600/respuesta+Ana.jpg&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;640&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiLHWjLY8bizsLlf4x_ciSvRedR4M1yFs5jb_GTQIhIZIn8pJMA0ufZ09xw3vZWoWJhKfEDl_Qwx-zDVOWmA66Y61JBex-ZY_ZxwQUWEWF5gyhetS-Wf_KAYznlRZnJrp6MFOBX1dFySpw/s1600/respuesta+Ana.jpg&quot; width=&quot;587&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/6843240570160075011/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/11/solucion-del-reto-5.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/6843240570160075011'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/6843240570160075011'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/11/solucion-del-reto-5.html' title='Solución del reto #4'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiLHWjLY8bizsLlf4x_ciSvRedR4M1yFs5jb_GTQIhIZIn8pJMA0ufZ09xw3vZWoWJhKfEDl_Qwx-zDVOWmA66Y61JBex-ZY_ZxwQUWEWF5gyhetS-Wf_KAYznlRZnJrp6MFOBX1dFySpw/s72-c/respuesta+Ana.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-394271742740588942</id><published>2013-11-19T15:00:00.000+00:00</published><updated>2013-11-19T15:00:01.263+00:00</updated><title type='text'>Reto #4</title><content type='html'>&lt;div style=&quot;text-align: center;&quot;&gt;
CUADRADOS MÁGICOS&lt;br /&gt;
&lt;br /&gt;
&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiikgfq9pZYSccSfzn0eMDo03M-UlKYD6Z_XEgnTUdkiIqtIzXiAkULYi2Uk0RY31qCKvjLk8AS5AuX5jOr7HE5RYd_LN6kf6ROBd9xEHrYhndgXw1SH7BfmEtnHvx60DF2NULBFZScMS7Z/s1600/DIAGRAMA6.jpg&quot; imageanchor=&quot;1&quot; style=&quot;clear: right; float: right; margin-bottom: 1em; margin-left: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;290&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiikgfq9pZYSccSfzn0eMDo03M-UlKYD6Z_XEgnTUdkiIqtIzXiAkULYi2Uk0RY31qCKvjLk8AS5AuX5jOr7HE5RYd_LN6kf6ROBd9xEHrYhndgXw1SH7BfmEtnHvx60DF2NULBFZScMS7Z/s320/DIAGRAMA6.jpg&quot; width=&quot;320&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
Los cuadrados mágicos son distribuciones de números en celdas que se disponen formando un cuadrado, de forma que la suma de cualquiera de las filas, de cualquiera de las columnas y de las dos diagonales principales da siempre el mismo resultado. Al número resultante lo hemos llamado &quot;suma mágica&quot;.&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
Por ejemplo, en el cuadrado mágico adjunto se han dispuesto los números del 1 al 9. Puedes comprobar que su suma mágica es 15.&lt;/div&gt;
&lt;/div&gt;
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Para resolver estos cuadrados mágicos, se deben trasladar las tarjetas al cuadrado para cumplir con la &lt;b&gt;&lt;i&gt;&quot;regla de oro&quot;&lt;/i&gt;&lt;/b&gt;:  &lt;u&gt;La suma de cada fila, columna y diagonal es la misma&lt;/u&gt;.&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
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&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiDP_uvFmC0OHfKKU1c120GXQtzEQ10532ytSPNAGSEu05uJt6hyphenhyphen5udGLm6HTbi44Kq7jL454Be4rz8SLMSabOO5lYThyphenhyphen19tcbA3TZ4htkwf_o9q8H1_ZyKdAD2HSXAtMbLIfeGratr15g9/s1600/Cuadrados+Magicos_1.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;337&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiDP_uvFmC0OHfKKU1c120GXQtzEQ10532ytSPNAGSEu05uJt6hyphenhyphen5udGLm6HTbi44Kq7jL454Be4rz8SLMSabOO5lYThyphenhyphen19tcbA3TZ4htkwf_o9q8H1_ZyKdAD2HSXAtMbLIfeGratr15g9/s640/Cuadrados+Magicos_1.png&quot; width=&quot;640&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/394271742740588942/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/11/reto-4.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/394271742740588942'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/394271742740588942'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/11/reto-4.html' title='Reto #4'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiikgfq9pZYSccSfzn0eMDo03M-UlKYD6Z_XEgnTUdkiIqtIzXiAkULYi2Uk0RY31qCKvjLk8AS5AuX5jOr7HE5RYd_LN6kf6ROBd9xEHrYhndgXw1SH7BfmEtnHvx60DF2NULBFZScMS7Z/s72-c/DIAGRAMA6.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-2657477647428302614</id><published>2013-11-19T14:00:00.000+00:00</published><updated>2013-11-19T14:00:00.878+00:00</updated><title type='text'>Solución al reto #3</title><content type='html'>Vamos con la solución del reto #3. Parece que este les ha resultado un poco más fácil que los anteriores y ha habido mucha participación. A modo de ejemplo:&lt;br /&gt;
&lt;br /&gt;
&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgQrNkYRKjlOT-a83M1m80mnYAYWzRtWASaHI6blSyOzEfwTOUV-PDKusRllxG1gHBIvfF4wK-qN1guOqBvIrF39rhL9HMRvhHpyMFXLTmgNxUK8CxTtnp37TVtw_5vRlINDKFCWGqhF2Q2/s1600/reto3.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;300&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgQrNkYRKjlOT-a83M1m80mnYAYWzRtWASaHI6blSyOzEfwTOUV-PDKusRllxG1gHBIvfF4wK-qN1guOqBvIrF39rhL9HMRvhHpyMFXLTmgNxUK8CxTtnp37TVtw_5vRlINDKFCWGqhF2Q2/s400/reto3.png&quot; width=&quot;400&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
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&lt;br /&gt;&lt;/div&gt;
&lt;br /&gt;&lt;br /&gt;He escogido estos números porque la base de la figura es el año de nacimiento de un personaje que nació en Mooresburg, Pensilvania y que diseñó la primera máquina de escribir comercial con el teclado QWERTY que se usa actualmente.&lt;div&gt;
&lt;br /&gt;Estamos hablando de  &lt;a href=&quot;http://es.wikipedia.org/wiki/Christopher_Sholes&quot; target=&quot;_blank&quot;&gt;Christopher Lathan Sholes&lt;/a&gt;, que nació en el año 1819. A partir de este número se hallaban las sumas como indicaban las reglas y se conseguían los resultados para completar la pirámide.&lt;br /&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/2657477647428302614/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/11/solucion-al-reto-3.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/2657477647428302614'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/2657477647428302614'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/11/solucion-al-reto-3.html' title='Solución al reto #3'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgQrNkYRKjlOT-a83M1m80mnYAYWzRtWASaHI6blSyOzEfwTOUV-PDKusRllxG1gHBIvfF4wK-qN1guOqBvIrF39rhL9HMRvhHpyMFXLTmgNxUK8CxTtnp37TVtw_5vRlINDKFCWGqhF2Q2/s72-c/reto3.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-4408587371786554646</id><published>2013-11-12T14:00:00.000+00:00</published><updated>2013-11-12T14:00:07.637+00:00</updated><title type='text'>Damos la solución del reto #2</title><content type='html'>Esta es la respuesta que envió Tania, ¡cuestión de hacer unas cuantas pruebas y descartes!&lt;br /&gt;
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&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjyAh4ItQmL0X-hdy_IneM_tZmlWlVl4vCMuQkD0Lk0_erN8J7I0CTTOZ0_kwVVAxkIR2NMno8hCLE6ipNl_q1zALRTedK9iCI0y7VYDpBblc8wxCjamAM3Bn8y-mOwvaqLtp_eO4RjXG2r/s1600/reto2.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;300&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjyAh4ItQmL0X-hdy_IneM_tZmlWlVl4vCMuQkD0Lk0_erN8J7I0CTTOZ0_kwVVAxkIR2NMno8hCLE6ipNl_q1zALRTedK9iCI0y7VYDpBblc8wxCjamAM3Bn8y-mOwvaqLtp_eO4RjXG2r/s400/reto2.png&quot; width=&quot;400&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
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&lt;div class=&quot;MsoNormal&quot;&gt;
Lo primero que hice fue contar las letras que habían y me di
cuenta que hay nueve diferentes.&amp;nbsp;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot;&gt;
Luego fui a por las pistas: primero los números
primos son: 2-3-5-7.&amp;nbsp;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot;&gt;
Lo segundo, el resto de números eran: 1-4-6-8-9.&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot;&gt;
Otra pista (Z+A=E) y solo tengo una fórmula (1+8=9)&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot;&gt;
Otra pista (L es par) solo me queda 4 y 6, uno de ellos es
la L. Como la (I) no se&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot;&gt;
&lt;o:p&gt;&amp;nbsp;&lt;/o:p&gt;nombraba seguro que era el otro par.&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
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&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot;&gt;
Y empecé a sacar cuentas hasta que cuadraron todos los
números.&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/4408587371786554646/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/11/damos-la-solucion-del-reto-2.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/4408587371786554646'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/4408587371786554646'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/11/damos-la-solucion-del-reto-2.html' title='Damos la solución del reto #2'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjyAh4ItQmL0X-hdy_IneM_tZmlWlVl4vCMuQkD0Lk0_erN8J7I0CTTOZ0_kwVVAxkIR2NMno8hCLE6ipNl_q1zALRTedK9iCI0y7VYDpBblc8wxCjamAM3Bn8y-mOwvaqLtp_eO4RjXG2r/s72-c/reto2.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-539923541263276104</id><published>2013-11-12T13:36:00.000+00:00</published><updated>2013-11-12T13:36:56.253+00:00</updated><title type='text'>Vamos con el tercero</title><content type='html'>&lt;div style=&quot;text-align: center;&quot;&gt;
LA PIRÁMIDE NUMÉRICA&lt;/div&gt;
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&lt;div style=&quot;text-align: justify;&quot;&gt;
Completa la Pirámide numérica o Pirámide matemática, encontrando los números que faltan cumpliendo con la regla: &quot;&lt;b&gt;&lt;u&gt;la suma de dos números adyacentes da el número de arriba&lt;/u&gt;&lt;/b&gt;&quot;. La base está formada por dígitos y esconden el año de nacimiento de un personaje que nació en Mooresburg, Pensilvania y que diseñó la primera máquina de escribir comercial con el teclado QWERTY que se usa actualmente, en la década de 1870. ¿De qué personaje hablamos?&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/539923541263276104/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/11/vamos-con-el-tercero.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/539923541263276104'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/539923541263276104'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/11/vamos-con-el-tercero.html' title='Vamos con el tercero'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgbp1HFATSR9W4d2WUmCXxWIVwr6rv0VNewNSi_0TE_fHM8BMzvUAjqG0PY4qrQ_fF4Oei7TVUpLwWnC88nr0KRS-8RHRKaym_v943XBvzV9NNLkfJk-jAWLcdSX1KX5gophvq632i0Nrxz/s72-c/Dibujo.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-1102003120812075574</id><published>2013-11-05T15:00:00.000+00:00</published><updated>2013-11-05T15:00:02.263+00:00</updated><title type='text'>Segundo reto</title><content type='html'>&lt;h2 style=&quot;text-align: center;&quot;&gt;
CRIPTOARITMÉTICA&lt;/h2&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
En los problemas de la criptoaritmética las letras representan dígitos del 0 al 9; el objetivo es encontrar el valor correspondiente a cada letra, de tal manera que la operación sea correcta. Además:&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;/div&gt;
&lt;ul&gt;
&lt;li&gt;Letras iguales representan dígitos iguales.&lt;/li&gt;
&lt;li&gt;Al formar el número, no debe iniciarse con cero.&lt;/li&gt;
&lt;li&gt;Letras diferentes representan dígitos diferentes.&lt;/li&gt;
&lt;/ul&gt;
&lt;div&gt;
Este reto resalta el día de los amigos:&lt;/div&gt;
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Se han agregado unas pistas como ayuda. Y recuerda: cuando me envíes tu solución debes explicar cómo has llegado a esa solución.&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/1102003120812075574/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/11/segundo-reto.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/1102003120812075574'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/1102003120812075574'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/11/segundo-reto.html' title='Segundo reto'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhAZOh4dmu9CHONi8bepTKTGtHAcfVjs1nKD_VckQBezhywFV7ATo5FlBHBK43Qz8FOl9cF5fw7RcRhTNlzvIyrcydvn3Ap6eQkXXADCPt1ubLNvWzJUof4IRxvtpXxfv8a8mvShQEcy0ZT/s72-c/reto2_A.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-3882613865596957515</id><published>2013-11-05T14:00:00.000+00:00</published><updated>2013-11-05T14:00:00.681+00:00</updated><title type='text'>Premios al reto 1</title><content type='html'>Ya tenemos solución al primer reto y los primeros ganadores. La mejor respuesta de todas es la de Noelia (2ºB). He aprovechado la imagen que ella me mandó con su respuesta y he creado este documento con las explicaciones que ella me emvió en el correo.&lt;br /&gt;
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El resto de puntuaciones de retos lo pueden ven en la hoja de cálculo enlazada. ¡Ánimo y a sumar puntos en el segundo reto!&lt;/div&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/3882613865596957515/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/11/premios-al-reto-1.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/3882613865596957515'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/3882613865596957515'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/11/premios-al-reto-1.html' title='Premios al reto 1'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgidnxlLqd_N76X9MmzVpG0VagV0ha3ZJapXUel3Ju-JccSomINcBYFkPlJ-bGBpkSlpbAtzPI7PO4dHn0flhHN19W7EN3r4h08B-_IgTmb7UXzbN8OjuSql3qh5dm7Ykj65JBiKZSAz3j2/s72-c/reto1.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-5362039071030706309.post-4287695364350101370</id><published>2013-10-24T19:03:00.000+01:00</published><updated>2013-10-27T17:58:59.685+00:00</updated><title type='text'>Primer reto</title><content type='html'>El reto del Uno más consiste en descubrir cada uno de los sumandos de la adición teniendo en cuenta que cada uno posee los dígitos del sumando anterior más un nuevo dígito.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Encuentra los sumandos teniendo en cuenta cada una de las pistas para cada número de tal manera que la suma sea la cifra indicada.  Recuerda cumplir con las reglas del Uno más.&lt;br /&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://retosvg.blogspot.com/feeds/4287695364350101370/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://retosvg.blogspot.com/2013/10/primer-reto.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/4287695364350101370'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/5362039071030706309/posts/default/4287695364350101370'/><link rel='alternate' type='text/html' href='http://retosvg.blogspot.com/2013/10/primer-reto.html' title='Primer reto'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEinczCHZ2xnw-V3ndZBVGIhen4PiFK2HDkPXFreLc38H0lAE3JACv1hbPxlanvUYtI3NQpTxmgFKnpK_5Z4aWpDBHgJw9ZB9FEuHmntWKmeFCQkfnYFYazbe0gyEMu1ZA3E2qrKiX1PHnQ/s72-c/Reto+Matematico_Uno+mas.png" height="72" width="72"/><thr:total>0</thr:total></entry></feed>