FUNDAMENTALS OF PROGRAMMING

WEEKLY REFLECTION 5

2011-03-26T01:49:00.000-07:00

1 March 2011, Tuesday

We learn c + + as usual and we were given tasks to complete the following exercises in the Forum.

Answers will be sent and attach it in the Forum. Each group must make discussion of cooperation to complete their assignment before the end of class.

Finally, as usual for the [/list]Weekly Reflection for the week.

ASSIGNMENT 2 SIFIR

2011-03-26T01:42:00.000-07:00

WEEKLY REFLECTION 6

2011-03-19T22:40:00.000-07:00

08 March 2011

As'salamulaikum dan Salam Sejahtera...

- Macam biasa kami di beri masa rehat dari pukul 9.00 pagi hingga Pukul 10.00 Pagi

- Dari ahli kumpulan kami seorang tidak hadir iaitu Fatimah

- Miss telah memberi kami latihan yang Exercise Question Past Years, kemudian Miss memberi tempoh kepada kami untuk menyiapkan tugasan dari pukul 10.00 hingga 12.00 tengahari. Setelah tu, kami harus memberi jawapan di papan putih.Miss akan menyemak jawapan yang kami berikan..

- Setelah siap kesemua ye kami telah Miss telah memberikan kami tugasan iaitu Assignment yang kedua-2 iaitu Membuat Sifat menggunakan coding (looping)..

- Saya kurang cerdik dalam tentang membuat coding walaupun saya ambik course IT...

- Antara contoh Contoh soalan seperti Loop. Terdapat 2 jenis Loop iaitu :-
a) Do..While
b) For

- Antara Contoh coding ialah :-

EXERCISE IF...ELSE

2011-03-19T22:18:00.000-07:00

EXERCISE

CALCULATE :-

Rectangular

Triangle

Circle

Fahrenheit

Calculus

Your selection :-

Your selection is _______________ and you are calculate ______________ .

The answer is _________________ .

ASSIGNMENT 1 MESIN TIN MINUMAN (SWITCH...CASE)

2011-03-19T21:29:00.000-07:00

1. MESIN TIN MINUMAN (SWITCH...CASE & IF...ELSE)

*************************
MESIN TIN MINUMAN
--------------------
1- PEPSI
2- COCA COLA
3- F&N MIRINDA
4- F&N ORANGE
5- 100 PLUS
*************************

Enter your drink:
Enter your money (RM):

Your drink is __________ and your balance are __________

*If the customer does not enter enough money, asked the customer to insert the money. (if...else)

EXERCISE (QUESTION PAST YEAR)

2011-03-19T20:49:00.000-07:00

08 MARCH 2011

QUESTION 1

1. Fill in the blank with appropriate data type for the following variables declaration syntax :-

a) Numerik (Integer) Number 1=1

b) Numerik (Nombor Nyata) Number 3=3.0

c) Bukan Numerik (Rentetan)Text 1=”1 have a car”

d) Bukan Numerik (Aksara) Huruf = “B”

e) Bukan Numerik (Rentetan) AccountNo =”6666666443”

1. 2 You are be given PTPTN loan with the amount of RM 1600.00. Calculate the amount of after PTPTN discount based on the CGPA. You must us if…else statement :

CGPA	DISCOUNT
4.00	100%
3.99-3.00	80%
2.99-2.00	40%
0-1.99	0%

OUTPUT

Jumlah Pimjaman = RM 1600.00

CGPA yang Diperolehi = 3.00

Diskun = RM 12800.00

Jumlah pinjaman yang perlu dibayar selepas Diskun = RM 3200.00

Answer :-

#include <iostream.h>

main()

{

float cgpa, diskaun, jumlah_pinjaman, bayaran_pinjaman;

cout<<" Jumlah Pinjaman : ";

cin>>jumlah_pinjaman;

cout<<" CGPA yang diperoleh: ";

cin>>cgpa;

if ((cgpa>=3.99) && (cgpa<=3.00));

diskaun = jumlah_pinjaman * 80/100;

bayaran_pinjaman = jumlah_pinjaman - diskaun;

cout<<"\n Diskaun = "<<diskaun<<endl;

cout<<" Jumlah pinjaman yang perlu dibayar selepas diskaun = "<<bayaran_pinjaman<<endl;

if ((cgpa>=0) && (cgpa<=1.99));

diskaun = jumlah_pinjaman * 0/100;

bayaran_pinjaman = jumlah_pinjaman - diskaun;

cout<<"\n Diskaun = "<<diskaun<<endl;

cout<<" Jumlah pinjaman yang perlu dibayar selepas diskaun = "<<bayaran_pinjaman<<endl;

if ((cgpa>=2.99) && (cgpa<=2.00));

diskaun = jumlah_pinjaman * 40/100;

bayaran_pinjaman = jumlah_pinjaman - diskaun;

cout<<"\n Diskaun = "<<diskaun<<endl;

cout<<" Jumlah pinjaman yang perlu dibayar selepas diskaun = "<<bayaran_pinjaman<<endl;

if (cgpa=4.00);

diskaun = jumlah_pinjaman * 100/100;

bayaran_pinjaman = jumlah_pinjaman - diskaun;

cout<<"\n Diskaun = "<<diskaun<<endl;

cout<<" Jumlah pinjaman yang perlu dibayar selepas diskaun = "<<bayaran_pinjaman<<endl;

}

return 0;

}

1. 3. You are required to do a program that will execute the multiply or divide operation. The operating is based on the user’s. You must use switch…case statement.

Output :

_______________________

MENU PILIHAN

________________________

1- Pendaraban

2- Pembahagian

________________________

Masukkan Nombor Pertama = 4

Masukkan Nombor Kedua = 8

Masukkan Pilihan Anda = 1

Hasil darb 4 dan 8 ialah 32

Answer :

#include<iostream.h>

Main ()

{

Int num1,num2,selction,total_multiy,total_divide ;

Cout<<”Masukkan Nombor 1 =” ;

Cin>>Nombor 1 ;

Cout<<”Masukkan Nombor 2 =” ;

Cin>>Nombor 2 ;

Cout<<”Masukkan Nombor Pilihan =”;

Cin>>Pilihan ;

Switch(selection)

{

Case 1 =(selection=1)

Total_multiy =num1*num2 ;

Cout<<”Hasil_Darab”<<Num1<<”dan”<<Num2<<”Total_Multiply<<endl ;

Case 2 =(selection=2)

Total_Divide=Num1/Num2 ;

Cout<<”Hasil_Bahagi “<<Num1<<”dan”Num2<<”Total_Divide<<endl;

}

return 0

}

1. 4. Change the diagram expression to Arithmetic Expression

a) Y = m – 4ax

Answer : Y = (m - 4 ax) / 7a

b) Y = 6ab___

4sd – 2xy

Answer : Y = 6 bc / (4 sd – 2xy)

c) Y = 2 + (AB + ( ) + 5 xyz

Answer : Y = (( 2 + AB + c ) / 3d ) + 5 xyz

d) Y = 2kb = 3jb

2k1

Answer : Y = (2kb / 2 ki ) – 3 jb

e) Y = xy + x²– 2ab

Answer : Y= xy + x * x – 2 ab

5.Solve the statement below to find in value. Show the working :-

a) M=5

M * = (3 + 4) * 2

Answer :-

M = 5 * ( 3 + 4 ) * 2

M = (5 * 7 )* 2

M = 35 * 2

M = 70

1 (TRUE)

b) M=2

M * = ((3 *4 ) / 2 ) = 9

Answer :-

M = 2 * (12/ 2 ) =9

M = ( 2* 6 ) = 9

M = 12 = 9

0 (FALSE)

1. 6. Find the output for the following segment :-

a) Float Var 1 = 25.12 , Var 2 = 15.0 ;

If (var 1 <= Var 2 )

Cout << “ Var 1 less or same as Var 2 “ ;

Else

Cout << “ Var 1 bigger than Var 2 “ ;

Answer :-

Output :

Cout<<Var1 bigger than Var 2 “ ;

b) In n = 20 ;

n/ = 5 ;

Answer :-

Output :

Cout<<20 / 5 = 4 “ ;

7. Convert the while statement below for for statement :-

Int j = 10 ;

While ( j > 10)

{

Cout << “ “ << j ;

J______ ;

}

Answer :-

#incude<iostream.h>

Main ()

{

//declare variable

Int x ;

X = 1 ;

While (x < = 10 )

{

Cout<<”number “<<x*1 ;

X ++ ;

}

return 0;

}

Output :

Number 1 --------- 1

2 --------- 2

3 --------- 3

4 --------- 4

5 --------- 5

6 --------- 6

7 --------- 7

8 --------- 8

9 --------- 9

10 --------- 10

8.Write a program the reads 4 prices using while loop and calculate the sum of things. A program must use function while for calculate the average of the prices.

#include<iostream.h>

main ()

{

int k;

float p,total,averge;

k=1;

while (k<=4)

{

cout<<"Enter price "<<k<<"= ;

cin>>p;

k++;

total=total+p;

}

Average=total/4;

cout<<"Your total is "<<total<<"and average is "average;

return 0;

}

PROGRAMMING EXERCISE SWITCH....CASE

2011-02-28T14:28:00.000-08:00

#include<iostream.h>
main ()
{
   int selection,quantity;
   double price;

   cout<<"\n 1. Pen =RM 0.50";
   cout<<"\n 2. Pensil =RM 0.30";
   cout<<"\n 3. Ruler =RM 0.20";
   cout<<"\n 4. Erser =RM 0.10"<<endl;

   cout<<"\n Enter your selection= ";
   cin>>selection;
   cout<<"\n Enter your quantity= ";
   cin>>quantity;

switch (selection)
{
   case 1:
price = quantity * 0.50;
cout<<"\n Price = RM "<<price<<endl;
cout<<"\n Your selection is Pen with "<<quantity;
cout<<" ,as your quantity(s)"<<endl;
break;

case 2:
price = quantity * 0.30;
cout<<"\n Price = RM "<<price<<endl;
cout<<"\n Your selection is Pensil with "<<quantity;
cout<<" ,as your quantity(s)"<<endl;
break;

   case 3:
price = quantity * 0.20;
cout<<"\n Price = RM "<<price<<endl;
cout<<"\n Your selection is Ruler with "<<quantity;
cout<<" ,as your quantity(s)"<<endl;
break;

case 4:
price = quantity * 0.10;
cout<<"\n Price = RM "<<price<<endl;
cout<<"\n Your selection is Erser with "<<quantity;
cout<<" ,as your quantity(s)"<<endl;
break;

default:
cout<<"\n Invalid selection"<<endl;
}

return 0;
}

WEEKLY REFLECTION 4

2011-02-28T14:27:00.000-08:00

WEEKLY REFLECTION 4

- Kelas bermula pada pukul 10.00 pagi..

- Sebelum kelas bermula Miss diberi nota pada forum dan kemudian di suruh download. -Setelah kelas bermula Sesi pembelajaran iaitu Chapter 4 Operators And expressions.

chapter ini mengenai tentang Arithmetic Operators,Relational Operators,Logical Operators and Assignment Operators.

-Kemudian telah memberi latihan untuk membuat ye...

- Setelah siap si sambung chapter 6 Control Structures tentang coding cara membuat coding If... else,Do..while, For...,While...., and Switch...case..

- Pada diajar tentang If..Else and Switch..Case.. .Bahagian ini saya kurang faham sedikit tentang cara membuat ye..

CHAPTER 4 OPERATORS AND EXPRESSIONS.

4.1 Operators

- C++ is very rich in built-in operators.

- Operators triggers some computations when applied to operands in an expression.

- The commonly use operators are as follows :-

a) Arithmetic Operators

b) Relational Operators

c) Logical Operators

d) Assignment Operators

- Table 4-1 shows the commonly use operators in C++ programming language.

Arithmetic Operators	Relational Operators	Logical Operators	Assignment Operators
+	>	&&	=
-	<	\|\|
*	>=	!
/	<=
%	==

INCREMENT AND DECREMENT OPERATOR

- Increment - Pro-increment (++N)

- Post-increment (N++)

- Decrement - Pro- decrement (--N)

- Post-decrement (N--)

- For Example :-

Int n ; Int n ;

n = 5 N=5

cout << n, 5 cout << n, 5

cout << ++N ; 1+5 =6 cout << N++ ;

cout << N ; 6 cout<< n ;

Int M; Int M ;

M= 9 M = 10

Cout << m; 9 cout << m ; 10

Cout << --M ; 8 cout << M-- ; 10-1 =9

Cout << M ; 8 cout << M ; 9

LOGICAL OPERATING

M	N	M && N	M \|\| N
0	0	0	0
1	0	0	1
0	1	0	1
1	1	1	1

!(M&&N)	!(M\|\|N)	!M	!N
1	1	1	1
1	0	1	0
1	0	0	1
0	0	0	0

! (M&&N) && (M\|\|N)	!(M) \|\| !(N)
1	1
0	1
0	1
0	0

For Example :-

++ a + --b * 4 > ++n && p++ + q-- * 4 < x++ + 4

= 3 + 2 * 4 > 3* 2 + 4 && 3 + 2 * 4 < 3 * 2 + 4

= 3 + 8 > 6 + 4 && 3 + 8 < 6 + 4

= 11 > 10 && 11 < 10

= 1 && 0

Chapter 6 Control Structures

Selection Structures

a) Do..while

b) While…

c) For..

d) If…else

e) Switch…case

Question :-

Age	Generation
0 – 2	Infant
3 – 6	Kids
7 – 12	Chile
13 – 21	Teenagers
22 – 30	Adult
30 up	Senior Adult

For the coding :-

#include<iostream.h>

main ()

{

//datatype variable_name;

int age;

cout<<"Enter your age : ";

cin>>age ;

//if...else

if (age>=0 || age <=2)

{

cout<<"Infornt";}

else if (age >=3 || age <=6);

{cout<<"kids";}

else if (age >=7 || age <=12);

{cout<<"child";}

else if (age >=13 || age <=21);

{cout<<"feenagers";}

else if (age >=22 || age <=30);

{cout << || "adult" ;}

else if (age > 30)

{cout<<"senior adult" ;}

else

{cout<<"Invalid selection";}

return 0;

}

EXERCISE

2011-02-28T14:25:00.000-08:00

1. Calculate 3 numbers with using the formula below :-

calculate = (num1*num2)-num3+(num2/num1)

#include<iostream.h>

main()

{

//declare variable

float num1,num2,num3,calculate;

//input1

cout<<"Enter Num1";

cin>>num1;

//input2

cout<<"Enter Num2";

cin>>num2;

//input3

cout<<"Enter Num3";

cin>>num3;

//formula

calculate=(num1*num2)-num3+(num2/num1);

//output

cout<<"Answer is="<<calculate;

return 0;

}

WEEKLY REFLECTION 3

2011-02-28T14:20:00.000-08:00

08 JANUARI 2011

- Kelas bermula pada Jam 09.00 a.m,selepas tu di berikan waktu rehat selama 1 jam.

- Pada Pukul 10.00 a.m,Kelas telah bermulakan class Fop...

- Kami dikehendaki Install turbo C++

- Seterusnya mendapatkan tugasan tentang coding untuk menyiapkan bersama ahli kumpulan...

- Ulangkaji Chapter 1 and Chapter 2

- Miss bagi homework1 and homework2

- Tutorials Blogspot

HOMEWORK 2

2011-02-28T14:09:00.001-08:00

HOMEWORK 2

OUTPUT:

Subject 1 (0.00) :
Subject 2 (0.00) :
Subject 3 (0.00) :
Subject 4 (0.00) :
Subject 5 (0.00) :

CPA:

FORMULA:
CPA = ((Subject1*3) + (Subject2*3) + (Subject3*2) + (Subject4*2) + (Subject5*4)) / 5

Answer :-

HOMEWORK 1

2011-02-28T14:09:00.000-08:00

HOMEWORK 1

OUTPUT:

Assignment 1 (10%):
Assignment 2 (10%):
Assignment 3 (10%):
Assignment 4 (10%):
Assignment 5 (10%):
MidTerm (10%):
Final (40%):

TOTAL (100%):

FORMULA:
TOTAL = Assignment1+Assignment2+Assignment3+Assignment4+Assignment5+MidTerm+Final

Answer :-

EXERCISES (DO IN YOUR BLOG)

2011-02-28T13:34:00.000-08:00

22 FEBRUARY 2011

1. Write correct C++ syntax & for each statement below :

a) Initializing variable Pi with the 3.14 (Constant)

Variable name =

Float Pi = “3.14” ;

b) Declare a variable names Parameter with double data type ( declare variable )

Double data Parameter ;

c) Give instruction that allowed user to input data ( input )

int data ;

cout << “Enter the data “ ;

cin >> data ;

d) Input number of computer using variable ( input assign to variable value )

int number ;

cin >> data ;

2) Solve the question below. Show the working :-

a) 5 * 2 % 3 + 25 / 5

= ( 10 % 3 ) + ( 25 /5 )

= 1 + 5

= 6

b) a = 5, b= 6

!((a < 3 ) && ( a= = 3 ) || ( b > 9 )

= !((5 < 3) && ( 5 == 3 ) || ( 6 > 9 )

= !(( 0 && 0 ) || ( 0 ))

= !(( 0 || 0 ))

= ! ( 0 )

= 1

3) Identify syntax errors in the following program.

#include<iostream.h>

main ()

{

float allowance = RM 300.00 salary, Tsalary ;

cout << “input salary = “ ;

cin >> salary ;

T salary = salary + Allowance ;

Cout << “ Total salary is = “ << salary ;

Return 0 ;

}

4. Write a program that will calculate the monthly salary for an employee that where

Saturday and Sunday are considered as non-working days.

5. Write a program that calculate the average of 5 number that can be input by user.

6. Write a program that will calculate the area of rectangular , triangle and circle.

Triangle

Circle

Rectangular

PROGRAMMING EXERCISE 2

2011-02-25T23:38:00.000-08:00

Questions :

Calculate 3 numbers with using the formula below:-

calculate=(num1*num2)-num3+(num2/num1). Do a complete C++ Coding.

#include<iostream.h>
main()
{
//declare variable
float num1,num2,num3,calculate;
//input1
cout<<"Enter Num1";
cin>>num1;
//input2
cout<<"Enter Num2";
cin>>num2;
//input3
cout<<"Enter Num3";
cin>>num3;
//formula
calculate=(num1*num2)-num3+(num2/num1);
//output
cout<<"Answer is="<<calculate;
return 0;
}

PROGRAMMING EXERCISE 1

2011-02-25T23:35:00.000-08:00

Sum and Minus Two Integers

#include<iostream.h>
main( )
{
//declare variable
float sum,minus,num1,num2;
//input1
cout<<''num1='';
cin>>num1;
//input2
cout<<''num2='';
cin>>num2;
//formula
sum=num1+num2;
minus=num2-num1;
//output
cout<<''sum=''<<sum;
cout<<''minus=''<<minus;
return 0;
}

Multiply Two Integers

#include<iostream.h>
main()
{

//Declare variable
int multiply,num1,num2;

//Input num1
cout<<"Enter num1 =";
cin>>num1;

//Input num2
cout<<"Enter Num 2 =";
cin>>num2;

//Formula
multiply=num1*num2;

//Output
cout<<"mutiply= "<<mutiply;
return 0;
}

Fahrenheit Convert to Celsius

#include<iostream.h>
main( )
{

//declare variable
float celcius;
float Fahrenheit;

//Input Fahrenheit
cout<<"Enter farenheit=";
cin>>farenheit;

//Formula
celcius=5/9*(farenheit -32);

//Output
cout<<"farenheit= "<<farenheit;
cout<<"celcius= "<<celcius;

return 0;
}

Celsius Convert to Fahrenheit

#include<iostream.h>
main()
{

//declared variable

float celcius, Fahrenheit;

//Input Celsius
cout<< "Enter celcius=";
cin>> Celsius;

//Formula
farenheit=9/5*(celcius+32);

//Output
cout<<"Celcius="<<celcius;
cout<<"Farenheit="<<farenheit;
return 0;
}

Divide and Modulus Two Integers

#include<iostream.h>
main( )

{
//declare variable
float divide, modulus, Num1, Num2;
//Input 1
cout<<"Num1= ";
cin>>Num1;
//Input 2
cout<<"Num2= ";
cin>>Num2 ;
//formula
Divide=Num2/Num1;
Modulus=Num1%Num2;
//Output
cout<<"divide="<<divide;
cout<<"modulus="<<modulus;
return 0;
}

WEEKLY REFLECTION 2

2011-02-25T23:18:00.000-08:00

WEEKLY REFLECTION 2

- Register forum untuk group FOP di web http://lect-ayuni.forumms.net.

- Mencari perbezaaan antara procedural programming , structured programming dan object oriental programming ke dalam forum http://lect-ayuni.forumms.net.

- Belajar Chapter 2 C++ Programming Language.

- Chapter 2 Miss mengajar program layout dan perlu memahami bagi untuk tulis di dalam weekly reflection 2.

- Kemudian telah memberikan tugasan secara group iaitu Sum and Minus Two Integers.

CHAPTER 2 C ++ BASICS

2.1 C++ LANGUANGE

- The C ++ language consists of the to two basic elements :

a) Semantics

b) Syntax

- Semantics is a vocabulary of commands that humans can understand and that can converted into machine language.

- Syntax is a language structure (or grammar ) that allows humans to combine these C++ commands into a program that actually does something.

- Example, let’s look at the common a English sentences below:-

1- Data Type

Int Integer - real 0-9

Float float }-decimal

Double double

Const constant - formula akan menjadi static

Char character - one alphabet only a-z / z-a

String string - one or more word

2- Input

Output/display – cout << please enter your = ;

Radius

Input – cin >> radius ;

3- Output ∕ Variable name

Cout << “area = “ << area ;

In body variable ;

To declare variable / semikolom

Data type variable_name ;

For Example :-

Π = 3.145 * radius * radius

#include<lostream.h>

Main ()

{

//declare variable

Float Pi;/r 1 / float Pi r 1 ;

Float radius ; r 2 radius ;

“Input radius

(But << “ Enter radius= “;

Cin >> radius ;

//Formula

PI = 3.145 * radius * radius

//Output

Cout << “Area ; =” << Pi ;

Return 0 ;

}

2.2 C++ PROGRAM

- C++ program is a text file containing a sequence of C++ commands put together a according to the laws of C++ grammas.

KEY ITEMS	EXPLANATION
C++ Command	The building blocks of the C++ program.
C++ Grammar	A correct and valid C++ language construct, structure or rules.
C++ Program	A text file containing a sequence of C++ Command that does something.
C++ Source file	A text file that carries the extension. CPP.
Editor	A software tool to create and modify text files.
Compiler	A program that translates a C++ Program into a machine-language program that the computer can directly understand and executes.
Machine Executable File	A program that the computer can directly understand executes.
IDE (Integrated Development Environment )	A software development tool that combines the compiler and the editor into a single package. It provides the windows, editors and controls for editing, compiling and debugging the code

EXERCISE (QUESTION THAT WILL BE ASK ON 1 FEB 2011)

2011-02-25T22:26:00.001-08:00

List the differences of structured programming, procedural programming and object oriented programming.

Structures programming

- Composed of simple , hierarchical program flow structure

- Three flow structure : sequential , selection, and repetition.

- Selection is executed depending on the state of the program.

- Repetition is executed until the program reaches a certain state of applied to every element of a collection.

- Associates with a ”top-down design” approach.

Procedural programming

- Using programming language to create computer memory location.

- Approach specifying the step the program must take to reach the desired state.

- Also know as routine , subroutines , methods, or functions.

- Defines the variable memory location.

- Invokes a series of procedure to input, manipulate and output the values stored in those locations.

Object Oriented Programming

- Is an extension of procedural programming.

- Made up of states and method (function).

- State of an object are known as attributes.

- Methods (functions) to accomplish tasks.

- The attributes and methods are encapsulates into object that are then used much like real word objects.

- Programmer are allowed to access to data or procedures only via a specified interface.

WEEKLY REFLECTION 1

2011-02-25T21:49:00.000-08:00

WEEKLY REFLECTION 1

- Pada hari selasa iaitu 25 Januari 20011,Bermula kelas FOP (SUBJECT FUNDAMENTALS OF PROGRAMMING.

- Kehandiran saya diambil dan diberi masa selama 20 untuk berehat.

- Rakan-rakan dan saya telah memberi penerangan tentang iaitu forum,weekly reflection 1,2,3,4 dan 5 ,zip file,blog ,midterm dan final exam..

- Kemudian, Kami dibahagikan kepada enam kumpulan, satu kumpulan mempunyai 5@6 ahli.Setiap ahli berpelbagai course iaitu IT and E-business.

- Kami belajar bermula chapter 1 iaitu PROGRAMMING AND PROBLEM SOLVING.
Ia mengenai tentang algorithm, pseudocode and flowchat is an outline of a program..

CHAPTER 1 PROGRAMMING AND PROBLEM SOLVING

1.2 ALGRORITHM

- Algorithm is a sequence of instruction to solve a problem.

- Some approximately equivalent word are :-

a) Reape

b) Method

c) Direction

d) Procedure

e) Routine

- Algorithm will be expressed in English and in the C ++ programming language.

For example for Algorithm

Algorithm that determines the area of a Rectangle

1- Get the with of the rectangle.

2- Get the height of the rectangle.

3- Calculate the area using the formula area = with * height

4- Announce the answer / Display the answer.

1.3 PSEUDOCODE

- Pseudo code is an outline of a program, written in a form that easily be converted into real programming statements.

- For example pseudo code :-

Pseudo code that determines the area of a Rectangle

Read the width

Read the height

Set the to the width multiplied by height

Print the area

- Pseudo code is not an actual programming language. It cannot be compiled not executed, and there is no real real formatting or syntax rules.

1.4 FLOWCHAT

- Flowchart is graphic representation of the logic or steps in a program.

- Flowchart represent or program or activity move through various processes or program retunes.

- Typical flowchart may have the following kinds of symbols :-

The Software Life Cycle

1. Analysis and specification of the task (problem definition)

2. Design of the software (algorithm design)

3. Implementation (coding)

4. Testing

5. Maintenance and evolution of the system

6. Obsolescence

SITI HAPSAH KHAIRUDDIN BLOG

2011-02-04T12:15:00.000-08:00

As'salamulaikum Dan Salam Sejahtera...

Alhamdulilah bersyukur kepada Allah S.W.T kerana telah memberi peluang kepada saya mahupun kawan saya ingin untuk membuat satu Blog. Saya ingin amat berterima kasih kepada Pn. Nur Ayuni Binti Abu Talib yang telah mengajar kami iaitu FUNDAMENTALS OF PROGRAMMING (FOP) sepanjang semseter ini.

Pada mula aku masuk ke kelas lambat sedikit 10 minit pukul 11.10 pagi baru aku masuk ke kelas.Pn. Nur Ayuni telah memberi sedikit keterangan tentang mengenai untuk meluluskan subject FUNDAMENTALS OF PROGRAMMING (FOP) 6 benda WAJIB iaitu :-

Forum
Weekly reflection (lepas tamat kelas)
Zip file (outcome 1 , 2 , 3 , 4)
Blog [blogspot.com , wordpress.com (10m)
Midterm (10m)
Final (40m)

Kemudian memperkenalkan diri masing-masing seperti NAMA,SEM BERAPA, Dan COURSE.Selepas itu, Pn. Nur Ayuni di suruh membuat setiap kumpulan...

Setelah siap yang di beri kan keterangan pada kami oleh Pn. Ayuni. Kami telah memulakan sesi pembelajaran kami memulakan iaitu:-

CHAPTER 1 PROGRAMMING AND PROBLEM SOLVING...

ALGORITHM

Algorithm is a of sequence of to solve of problem.

PSEUDOCODE

- Pseudocode is on outline of a program, written in a form can easily be converted into real programming statements.

- Pseudocode is not an actual programming. It cannot be compiled not executed, and there is no real formatting or syntax rules

FLOWCHART

- Flowchart is a graphic representation of the logic or step in a program routines.

Bahagian Flowchart ade kekeliruan apabila ape saya belajar (PPSC) iaitu PROGRAMMING PROBLEM SOLVING AND CONCEPT.

Kemudian perbandingan antara Procedural Programming, Structured Programming And Object Oriented Programming.

F O P : FUNDAMENTALS OF PROGRAMMING

P P S C : PROGRAMMING PROBLEM SOLVING AND CONCEPT