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    <title>Philosophy to Chemistry to Elucidation</title>
    
    
    <link rel="alternate" type="text/html" href="http://acdlabs.typepad.com/elucidation/" />
    <id>tag:typepad.com,2003:weblog-1562650</id>
    <updated>2012-01-27T11:02:16-04:00</updated>
    <subtitle>A science blog on the process of structure elucidation using NMR, MS, UV/vis, IR, GC/LC, pXRD, etc.         For those who would like to contribute to this blog, please feel free to email me.</subtitle>
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        <title>Logic Puzzle #26: Elemental Analysis to Empirical Formula … Solution</title>
        <link rel="alternate" type="text/html" href="http://feedproxy.google.com/~r/PhilosophyToChemistryToElucidation/~3/VTAmpg5RMhA/logic-puzzle-26-elemental-analysis-to-empirical-formula-solution.html" />
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        <id>tag:typepad.com,2003:post-6a00d834fe3a5753ef01630038d63c970d</id>
        <published>2012-01-27T11:02:16-04:00</published>
        <updated>2012-01-27T11:02:16-04:00</updated>
        <summary>The results for calculating the empirical formula for an unknown compound using data from elemental analysis are presented. An elemental analysis was collected for an unknown organic compound. A 0.30 g sample of the unknown was burned to completion and...</summary>
        <author>
            <name>Arvin Moser</name>
        </author>
        <category scheme="http://www.sixapart.com/ns/types#category" term="Elemental Analysis" />
        <category scheme="http://www.sixapart.com/ns/types#category" term="Molecular Formula" />
        
        
<content type="xhtml" xml:lang="en-US" xml:base="http://acdlabs.typepad.com/elucidation/"><div xmlns="http://www.w3.org/1999/xhtml"><p><span style="color:#00ccff; font-family:Times New Roman; font-size:14pt">The results for calculating the empirical formula for an unknown compound using data from elemental analysis are presented. 
</span></p><p><span style="color:#ff9900; font-family:Times New Roman; font-size:14pt">An elemental analysis was collected for an unknown organic compound. A 0.30 g sample of the unknown was burned to completion and it gave 59.6 % C, 6.9 % H and 8.7 % N. The results are summarized in the table below. The calculation for the unknown organic compound assumes that the missing % composition is oxygen.
</span></p><p><span style="color:#ff9900; font-family:Times New Roman; font-size:14pt">Atom moles = Composition * Sample Mass / Atomic Weight (1)
</span></p><div style="margin-left: 4pt"><table style="border-collapse:collapse" border="0"><colgroup><col style="width:64px" /><col style="width:95px" /><col style="width:64px" /><col style="width:109px" /><col style="width:77px" /><col style="width:66px" /><col style="width:56px" /></colgroup><tbody valign="top"><tr style="height: 38px"><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  solid 0.5pt; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">Atom</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  solid 0.5pt; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">Composition (%)</span></p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  solid 0.5pt; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">Sample Mass (g)</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  solid 0.5pt; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">Atomic Weight (g/mol)</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  solid 0.5pt; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">Formula 1 (mol)</span></p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  solid 0.5pt; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">Mol Ratio   (/ 0.186)</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  solid 0.5pt; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">Mol Ratio   (X 2)</span> </p></td></tr><tr style="height: 19px"><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">C</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">59.6</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">0.30</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">12.0107</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">1.489</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">8.01</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">16.01</span> </p></td></tr><tr style="height: 19px"><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">H</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">6.9</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">0.30</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">1.0079</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">2.057</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">11.06</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">22.12</span> </p></td></tr><tr style="height: 19px"><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">N</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">8.7</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">0.30</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">14.0067</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">0.186</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">1.00</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">2.00</span> </p></td></tr><tr style="height: 19px"><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">O</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">24.8</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">0.30</span> </p></td><td vAlign="bottom" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">15.9994</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">0.465</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">2.50</span> </p></td><td vAlign="middle" style="padding-left: 7px; padding-right: 7px; border-top:  none; border-left:  none; border-bottom:  none; border-right:  none"><p style="text-align: center"><span style="color:#ff9900; font-family:Times New Roman">5.00</span> </p></td></tr></tbody></table></div><p><span style="color:#ff9900; font-family:Times New Roman; font-size:14pt">Using formula 1, the Mol ratios are calculated. Dividing by the smallest value (0.186) and then multiplying by 2, the empirical formula for the unknown is C16 H22 N2 O5. 
</span></p><p><span style="color:#ff9900; font-family:Times New Roman; font-size:14pt">To determine the molecular formula for the unknown, additional information such as the molecular weight is necessary.</span></p><xhtml:img xmlns:xhtml="http://www.w3.org/1999/xhtml" src="http://feeds.feedburner.com/~r/PhilosophyToChemistryToElucidation/~4/VTAmpg5RMhA" height="1" width="1" /></div></content>



    <feedburner:origLink>http://acdlabs.typepad.com/elucidation/2012/01/logic-puzzle-26-elemental-analysis-to-empirical-formula-solution.html</feedburner:origLink></entry>
    <entry>
        <title>Logic Puzzle #26: Elemental Analysis to Empirical Formula</title>
        <link rel="alternate" type="text/html" href="http://feedproxy.google.com/~r/PhilosophyToChemistryToElucidation/~3/GMaVKjqWLtY/logic-puzzle-26-elemental-analysis-to-empirical-formula.html" />
        <link rel="replies" type="text/html" href="http://acdlabs.typepad.com/elucidation/2012/01/logic-puzzle-26-elemental-analysis-to-empirical-formula.html" thr:count="0" />
        <id>tag:typepad.com,2003:post-6a00d834fe3a5753ef016760da7a22970b</id>
        <published>2012-01-20T11:30:53-04:00</published>
        <updated>2012-01-24T13:33:23-04:00</updated>
        <summary>Elemental analysis is an experiment used to determine the elemental composition of an unknown compound. The purpose of this puzzle is to use the percentage composition data from elemental analysis to deduce an empirical formula. An elemental analysis was collected...</summary>
        <author>
            <name>Arvin Moser</name>
        </author>
        <category scheme="http://www.sixapart.com/ns/types#category" term="Elemental Analysis" />
        <category scheme="http://www.sixapart.com/ns/types#category" term="Molecular Formula" />
        
        
<content type="xhtml" xml:lang="en-US" xml:base="http://acdlabs.typepad.com/elucidation/"><div xmlns="http://www.w3.org/1999/xhtml"><p><span style="color: #00ccff; font-family: Times New Roman; font-size: 14pt;">Elemental analysis is an experiment used to determine the elemental composition of an unknown compound.  The purpose of this puzzle is to use the percentage composition data from elemental analysis to deduce an empirical formula. </span></p>
<p><span style="color: #ff9900; font-family: Times New Roman; font-size: 14pt;">An elemental analysis was collected for an unknown organic compound. A 0.30 g sample of the unknown was burned to completion and it gave 59.6 % C, 6.9 % H and 8.7 % N. What is the empirical formula of the unknown?</span></p><xhtml:img xmlns:xhtml="http://www.w3.org/1999/xhtml" src="http://feeds.feedburner.com/~r/PhilosophyToChemistryToElucidation/~4/GMaVKjqWLtY" height="1" width="1" /></div></content>



    <feedburner:origLink>http://acdlabs.typepad.com/elucidation/2012/01/logic-puzzle-26-elemental-analysis-to-empirical-formula.html</feedburner:origLink></entry>
    <entry>
        <title>Logic Puzzle #25: Zero Filling at its Best … Solution</title>
        <link rel="alternate" type="text/html" href="http://feedproxy.google.com/~r/PhilosophyToChemistryToElucidation/~3/QJ0WsffvUAk/logic-puzzle-25-zero-filling-at-its-best-solution.html" />
        <link rel="replies" type="text/html" href="http://acdlabs.typepad.com/elucidation/2012/01/logic-puzzle-25-zero-filling-at-its-best-solution.html" thr:count="2" thr:updated="2012-01-20T15:17:08-04:00" />
        <id>tag:typepad.com,2003:post-6a00d834fe3a5753ef0162ff5886cd970d</id>
        <published>2012-01-10T13:28:14-04:00</published>
        <updated>2012-01-10T13:29:41-04:00</updated>
        <summary>For each increment of zero filling, the number of data points defining a line shape is increased. The trade-off is the size of the FID increases proportionately. An FID with 1K = 1024 points will produce a file of ~...</summary>
        <author>
            <name>Arvin Moser</name>
        </author>
        <category scheme="http://www.sixapart.com/ns/types#category" term="1D NMR" />
        <category scheme="http://www.sixapart.com/ns/types#category" term="1H NMR" />
        
        
<content type="xhtml" xml:lang="en-US" xml:base="http://acdlabs.typepad.com/elucidation/"><div xmlns="http://www.w3.org/1999/xhtml"><p><span style="color: #00ccff; font-family: Times New Roman; font-size: 14pt;">For each increment of zero filling, the number of data points defining a line shape is increased. The trade-off is the size of the FID increases proportionately. An FID with 1K = 1024 points will produce a file of ~ 50 kb (including data parameters). The goal is to balance the file size with the amount of gain from applying zero filling. </span></p>
<p><span style="color: #ff9900; font-family: Times New Roman; font-size: 14pt;">Spectra A and B appeal aesthetically due to the higher level of smoothness across the signals. Whereas the original data, spectrum E, is jagged and presents less than ideal line shapes. </span></p>
<p><span style="color: #ff9900; font-family: Times New Roman; font-size: 14pt;">Analysts typically apply 1 to 2 zero fillings; this equates to adding respectively 1 to 2 increments of zeroes equal to the number of data points. </span></p>
<p><img alt="" src="http://acdlabs.typepad.com/.a/6a00d834fe3a5753ef0168e54e23fe970c-pi" style="margin-right: auto; margin-left: auto; display: block;" /></p><xhtml:img xmlns:xhtml="http://www.w3.org/1999/xhtml" src="http://feeds.feedburner.com/~r/PhilosophyToChemistryToElucidation/~4/QJ0WsffvUAk" height="1" width="1" /></div></content>



    <feedburner:origLink>http://acdlabs.typepad.com/elucidation/2012/01/logic-puzzle-25-zero-filling-at-its-best-solution.html</feedburner:origLink></entry>
    <entry>
        <title>Blog on Hiatus for the Holidays</title>
        <link rel="alternate" type="text/html" href="http://feedproxy.google.com/~r/PhilosophyToChemistryToElucidation/~3/FmNwLkAk2kw/blog-on-hiatus-for-the-holidays.html" />
        <link rel="replies" type="text/html" href="http://acdlabs.typepad.com/elucidation/2011/12/blog-on-hiatus-for-the-holidays.html" thr:count="0" />
        <id>tag:typepad.com,2003:post-6a00d834fe3a5753ef0154389485e9970c</id>
        <published>2011-12-20T10:52:32-04:00</published>
        <updated>2011-12-20T10:53:39-04:00</updated>
        <summary>As the holidays approach, I will be home resting with my family. The blog Philosophy to Chemistry to Elucidation will be on hiatus from December 19th to January 6th. I want to wish the readers of P2C2E Happy Holidays. Stay...</summary>
        <author>
            <name>Arvin Moser</name>
        </author>
        <category scheme="http://www.sixapart.com/ns/types#category" term="Other" />
        
        
<content type="xhtml" xml:lang="en-US" xml:base="http://acdlabs.typepad.com/elucidation/"><div xmlns="http://www.w3.org/1999/xhtml"><p><span style="color: #00ccff; font-family: Times New Roman; font-size: 14pt;">As the holidays approach, I will be home resting with my family. The blog Philosophy to Chemistry to Elucidation will be on hiatus from December 19<sup>th</sup> to January 6<sup>th</sup>. </span></p>
<p><span style="color: #ff7f00; font-family: times new roman,times; font-size: 14pt;">I want to wish the readers of P2C2E Happy Holidays. Stay tuned for the solution for the Logic Puzzle # 25 in the New Year. </span></p>
<p style="text-align: center;"><img alt="" src="http://acdlabs.typepad.com/.a/6a00d834fe3a5753ef01675f0a342c970b-pi" /></p><xhtml:img xmlns:xhtml="http://www.w3.org/1999/xhtml" src="http://feeds.feedburner.com/~r/PhilosophyToChemistryToElucidation/~4/FmNwLkAk2kw" height="1" width="1" /></div></content>



    <feedburner:origLink>http://acdlabs.typepad.com/elucidation/2011/12/blog-on-hiatus-for-the-holidays.html</feedburner:origLink></entry>
    <entry>
        <title>Logic Puzzle #25: Zero Filling at its Best</title>
        <link rel="alternate" type="text/html" href="http://feedproxy.google.com/~r/PhilosophyToChemistryToElucidation/~3/c_6N3vU3k4k/logic-puzzle-25-zero-filling-at-its-best.html" />
        <link rel="replies" type="text/html" href="http://acdlabs.typepad.com/elucidation/2011/12/logic-puzzle-25-zero-filling-at-its-best.html" thr:count="0" />
        <id>tag:typepad.com,2003:post-6a00d834fe3a5753ef01675eb30275970b</id>
        <published>2011-12-13T11:04:57-04:00</published>
        <updated>2011-12-19T16:24:09-04:00</updated>
        <summary>Zero filling is the process of adding a string of zeroes to the end of an FID. The following puzzle aims at understanding how zero filling impacts the line shape of a doublet. The following 1H NMR spectrum was collected...</summary>
        <author>
            <name>Arvin Moser</name>
        </author>
        <category scheme="http://www.sixapart.com/ns/types#category" term="1D NMR" />
        <category scheme="http://www.sixapart.com/ns/types#category" term="1H NMR" />
        
        
<content type="xhtml" xml:lang="en-US" xml:base="http://acdlabs.typepad.com/elucidation/"><div xmlns="http://www.w3.org/1999/xhtml"><p><span style="color: #00ccff; font-family: Times New Roman; font-size: 14pt;">Zero filling is the process of adding a string of zeroes to the end of an FID. The following puzzle aims at understanding how zero filling impacts the line shape of a doublet. </span></p>
<p><span style="color: #ff9900; font-family: Times New Roman; font-size: 14pt;">The following 1H NMR spectrum was collected with a total of 4K points (selective region is shown as spectrum E). Applying different amounts of zero filling will modify the line shape of the doublet. Which spectrum(a) offers visually the best line shape for the doublet? </span></p>
<p><img alt="" height="572" src="http://acdlabs.typepad.com/.a/6a00d834fe3a5753ef0154383d1b33970c-pi" width="481" /></p><xhtml:img xmlns:xhtml="http://www.w3.org/1999/xhtml" src="http://feeds.feedburner.com/~r/PhilosophyToChemistryToElucidation/~4/c_6N3vU3k4k" height="1" width="1" /></div></content>



    <feedburner:origLink>http://acdlabs.typepad.com/elucidation/2011/12/logic-puzzle-25-zero-filling-at-its-best.html</feedburner:origLink></entry>
 
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