Puzzle Orbit - Explore The World Of Puzzles

The Equal Contribution Of Wood | Puzzle 21

noreply@blogger.com (Atul) — Thu, 14 Jun 2018 08:08:00 +0000

Question

John, Bob, and Charlie live together in a hut near the forest and shares everything equally.

One day John brings 5 logs of wood, Bob brings 3 logs of wood, but Charlie didn't make able to bring any...

After they have collected their woods, they use it to cook together and share the food.

Since Charlie has not brought any wood, he gives $8 instead of his contribution.

Now, the question is: Out of $8, how much will he give to A and how much to B?

Solution

Total wood is 5+3=8.

So, every person consumed 8/3 logs of wood.

John gave 5 - (8/3) = 7/3 logs of wood to Charlie.

Bob gave 3 - (8/3) = 1/3 logs of wood to Charlie.

So, out of $8, John gets $7 and Bob gets $1

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Two Strings Burning | Puzzle 20

noreply@blogger.com (Atul) — Sun, 10 Jun 2018 12:13:00 +0000

Question

You were provided with two strings. The only thing you know about that string is that when you light one end of either string it takes exactly one hour to burn. The rate at which the strings will burn is completely random and each string is different.

So, the question is How would you measure 45 minutes with this information?

Solution

Take both the strings, light the 1st string on both ends and on the 2nd string, light it only on one end. By this, when the 1st string gets completely burnt, it exhibits the completion of 30 minutes, and on the same time the 2nd string gets burnt half.

When the 1st string gets burnt completely, light on the another end of the 2nd string. Doing this when the second string burnts completely, it completes a total of 45 minutes for the entire procedure.

1st string burnt completely = 2nd string burnt half = 30 minutes

At this time the 2nd string remains half

2nd string burnt completely = 15 minutes

Total of 45 minutes

Some people have difficulty grasping that when you light both ends of the first fuse, it will take 30 minutes to burn. Because the burning rate is random and unknown to you, you have no idea where the 30 minute mark is on the fuse. If you had an exact duplicate, then the 30 minute mark would be in the same place. It is probably not in the middle, but it is somewhere. If you burn both ends of a fuse it will not stop burning until it has reached this mark, which means 30 minutes is up.

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Dad and Son Fishing | Puzzle 19

noreply@blogger.com (Atul) — Fri, 08 Jun 2018 11:40:00 +0000

Question

On a sunny weather, two fathers and two sons decided to go for fishing with their pieces of equipment. In the entire day, each one of them was able to catch 1 fish. After this, they returned to their home and placed all the three fishes in a vessel.

Did you understand, how come they had only three fishes in total?

Also, note that no fish was eaten or lost by them in their journey or at home.

Solution

Actually, there were only three people who went on fishing:-

A son,

A father and

A grandfather

They can obviously be denoted as two fathers and two sons. 😀

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The Apples and Oranges Box | Puzzle 18

noreply@blogger.com (Atul) — Wed, 06 Jun 2018 12:56:00 +0000

Question

There are three boxes on the table.

One box is labelled as "Apples" another box is labelled as "Oranges". The last one is labelled as "Apples and Oranges".

The condition is you know that each box have been labelled incorrectly and you were allowed to pick only one fruit from any one box.

How can you label the boxes correctly?

Solution

You should pick fruit from the one which is labelled as "Apples & Oranges". This box must contain either only apples or only oranges. After this, the remaining two can be determined easily.

For example, If you find an Orange from the Apples & Oranges box, then label the box Orange, then change the Apple box to "Apples & Oranges" and Oranges box to "Apples".

We changed Apple box to Apples and Oranges as we know it does not contain Apple as questions say and the Orange has already been found in another box.

Now the remaining box which is labelled as Oranges, change its name to Apples.

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The Cowboy's Deathmatch | Puzzle 17

noreply@blogger.com (Atul) — Sat, 02 Jun 2018 11:43:00 +0000

Question

There were Two cowboys who decided to play a strange game of death -"DeathMatch".

Following are the rules for the DeathMatch:

1. They both need to fire the total of 23 bullets.

2. They will have to shoot one by one.

3. They have the option to shoot once or twice in their chance(it's their decision).

4. The one that shoots at last i.e., the 23rd shot needs to fire the bullet at himself.

Now the question is if you were one of the cowboys, will you shoot first or second at the beginning?

Solution

Shooting 1st will save your life.

- You Shoot once.

- Then shot opposite of what the other cowboy shoot i.e., if another cowboy shots 2 times, you shot once and vice versa.

- After the 15 shots, bullet remaining will be 23(total at beginning) - 1(your first shot) - 7(2+1)(your technique) = 1

- The other cowboy needs to fire the last bullet and hence he will be dead.

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Chocolate Wrapper Return Offer | Puzzle 16

noreply@blogger.com (Atul) — Thu, 31 May 2018 06:35:00 +0000

Question

There is an offer in a local confectionary shop that allows children to purchase a chocolate in exchange for five wrappers of the same chocolate. Children from that area consumed 77 chocolates in a month. Now, they have all collected the wrapper together and decide to buy back chocolates from the shop.

How many chocolates do you think they can buy using those 77 wrappers?

Solution

The children can purchase 19 chocolates in return.

Out of 77 wrappers, 75 will be used to buy 15 chocolates(75/5 = 15) and two will be left spare.

The 15 chocolates will create 15 empty wrappers that can be exchanged to get three chocolates(15/5 = 3).

Three chocolates will return three wrappers which will help them to buy another chocolate.

Now the wrapper from this chocolate and the two spare that was left earlier will help them get one more chocolate in return.

15 + 3 + 1 = 19

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Is Mug Fill Less Than Half or More? | Puzzle 15

noreply@blogger.com (Atul) — Tue, 08 May 2018 13:12:00 +0000

Question

There is a Mug with a cover paint and some coke in it. In this scenario, 2 brothers argued as follows...

Amit said: "This Mug of coke is more than half full"

For this,

Ankit Replied: "No it's not, it's less than half full".

Without any measuring implements and without removing any coke from the Mug, how can they easily determine who is correct?

Solution

Tilt the Mug until the coke barely touches the lip of the Mug.

If the bottom of the Mug is visible then it is less than half full.

If the Mug bottom is still completely covered by the coke, then it is more than half full.

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Divide 1000 Coins of 1 Rupee in 10 Pouches | Puzzle 14

noreply@blogger.com (Atul) — Sat, 05 May 2018 13:15:00 +0000

Question

You are given an amount of ₹1000 of ₹1 Coin (1000 coins of ₹1) and 10 pouches.

Now, you have to put the given coins on the given pouches in such a manner that if someone asks you for any amount between ₹1 to ₹1000, you should easily be able to give the amount by just giving the pouches.

Note: You are not allowed to open pouches for that. You have to complete pouch resulting the amount.

So, how will you do it?

Solution

We will divide the coins into the pouches in the exponential power of 2 starting from 0.

1st Bag = 1 Coin

2nd Bag = 2 Coins

3rd Bag = 4 Coins

4th Bag = 8 Coins

5th Bag = 16 Coins

6th Bag = 32 Coins

7th Bag = 64 Coins

8th Bag = 128 Coins

9th Bag = 256 Coins

10th Bag = Remaining Coins : 489(1000-511).

Now think of any amount and guess what?... You will find that you can give any amount just by using the pouches without even opening them.

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The Killer at Rock Throwing Game | Puzzle 13

noreply@blogger.com (Atul) — Fri, 04 May 2018 11:58:00 +0000

Question

There were Four kids playing a game of rocks. In this game, they have five rocks with them. In this game, they need to throw the rock at the solid area in the water.

Kid1: Succeeded in throwing three rocks at the solid area but one of the rock sunk.

Kid3: His aim was so bad that all rocks got sunk.

Kid4: He was awesome and none of the rocks got sunk.

Kid2: He was struck by a rock in the head and died.

Can you identify Who killed Kid2?

Solution

Kid1. Because he was left with one rock.

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Flashlight And The Batteries | Puzzle 12

noreply@blogger.com (Atul) — Thu, 03 May 2018 13:09:00 +0000

Question

You have been provided with a flashlight that can operate on two working batteries.

You also have eight batteries with you, Out of that eight batteries, only four are in the working condition. But you don't know which four batteries are those.

Can you find out the least number of pairs that you must test to guarantee that you can get your flashlight on?

Solution

SEVEN

The best way is that you divide the batteries into three groups.

Two groups of three batteries and One group of two batteries.

In the groups with three batteries, you can have three possible combinations in each group. In the group with two batteries, you can have just one possible combination.

Hence, the total combinations: 3 + 3 + 1 = 7, you get the least number of pairs you must check.

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The Lying Days Of Week | Puzzle 11

noreply@blogger.com (Atul) — Wed, 02 May 2018 08:44:00 +0000

Question

There were two friends Amit and Anil. They are quite strange in making statements. One of them always lies on Mondays, Tuesdays, and Wednesdays and tells the truth on all other days of the week while the other lies on Thursdays, Fridays, and Saturdays and tells the truth on other days of the week.

Today at 3 PM, they made following statements,

Amit: I lie on Saturdays.

Anil: I will lie tomorrow.

Amit: I lie on Sundays.

Can you find out, Today is which day of the week?

Solution

Wednesday.

As, No one lies on Sunday, so Amit is lying.

This means today is not Sunday. Also now we have been known that Amit lies today,

so "Amit: I lie on Saturdays" is also a lie.

Therefore, today is not sturdy and can one of Monday, Tuesday, or Wednesday. Now we know Anil is telling the truth, therefore for the statement "Anil: I will lie tomorrow." true today has to be Wednesday.

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Maximum Runs by Batsman in One Day Cricket | Puzzle 10

noreply@blogger.com (Atul) — Tue, 01 May 2018 13:17:00 +0000

Question

In a one day match of Cricket, assume that there were no wide balls, no wides, no extras and no overthrows.

Then, What is the maximum number of runs that a batsman can score in an ideal case scenario?

Solution

1653

In an ideal case, the batsman will hit a six on each ball. But if he hits six on the last ball of the over, the strike will change in the next over.

Thus, the best he can do to retain the strike is that in the last ball he will run for 3 runs so he retains the strike even in the next over.

Thus the total runs that he can score in each over:

6 * 5 + 3 = 33

But this will have to go like it only until the 49th over.

In the last over, he can hit a six in the last ball as well as that will be the last ball of the match so there is no issue of maintaining the strike.

Thus runs for the last over will be 6 * 6 = 36.

Hence the maximum runs = 33 * 49 + 36 = 1653

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The Defective Chocolate | Puzzle 9

noreply@blogger.com (Atul) — Mon, 30 Apr 2018 07:31:00 +0000

Question

You have ten boxes and an electronic weighing machine. In those ten boxes, you have chocolates. Each chocolate weighs 20 gram. But in one box the chocolates are defective and each weighs 19 gram exactly.

Now you can weigh in the electronic weighing machine but you can use that machine just once.

How will you find out which box has the defected chocolates?

Solution

If you are thinking to hold one chocolate from each box in hand and then balancing weight in bare hands, you are thinking all wrong. 😜

Let us begin by labeling the boxes as 1, 2, 3, ...... till 10.

Now, pick one chocolate from box 1, two chocolates from box 2, three from box 3 and so on. In total, you will have 55 chocolates now. (1 + 2 + 3 + ..... + 10)

The ideal weight of the chocolates should be 55 * 20 = 1100. However, somewhere in there are the defected chocolate/s.

You can judge that clearly by noting down the result of 1100 - total weight of chocolates. If the weight is less than 1 gram, the defected box is box 1, if the weight is less than 2 grams, the defected box is box 2 and so on.

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The Frozen Mountain | Puzzle 8

noreply@blogger.com (Atul) — Sun, 29 Apr 2018 13:58:00 +0000

Question

A man is trying to climb over a frozen mountain that is sixty feet high.

Every minute, he can climb up to 3 feet, but due to the ice which is slippery, he slips back 2 feet.

Can you determine how long will it take him to reach the top of the mountain?

Solution

It will take the man 58 minutes to reach the top.

Since for every single minute, he is climbing 3 feet and falling 2 feet back, he is actually climbing 1 feet every minute.

Therefore, he would have climbed 57 feet in 57 minutes. The remaining distance is 3 feet. He will take one more minute to climb it and reach the surface. Since he has reached the top surface, he won't slip back.

Please share your thoughts in the comments.

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Water And Milk Differentiation | Puzzle 7

noreply@blogger.com (Atul) — Sat, 28 Apr 2018 07:29:00 +0000

Question

You have a glass of water and a glass of milk. You need to empty the two liquid into a barrel such that:

1. The two liquids (water and milk) can be differentiated
2. You are able to sperate milk and water.

Note: Any type of divider in the box is not allowed.

How would you do this?

Solution

Step 1 - Pour the water into the barrel.
Step 2 - Freeze it.
Step 3 - Pour the milk into the barrel.

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The Red, Blue and White Shirt | Puzzle 6

noreply@blogger.com (Atul) — Fri, 27 Apr 2018 07:44:00 +0000

Question

At a restaurant in the city, Mr. Red, Mr. Blue, and Mr. White meet for lunch. Under their coats, they are wearing either a red, blue, or white shirt.

Mr. Blue observed this and says, 'Hey, did you notice we are all wearing different colored shirts from our names?'. Hearing this, the man wearing the white shirt says, 'Yes, Mr. Blue, that's right!'

Can you tell who is wearing what color shirt?

Solution

Mr. Blue - Red Shirt

Mr. White - Blue Shirt

Mr. Red - White Shirt

Mr. Blue could only have the chances of wearing White or Red and we know that there is already someone else wearing the white shirt so Mr. Blue could only be wearing the Red shirt.

Mr. White could have only been wearing a Blue or a Red shirt, and red is already taken, so Mr. White is wearing a Blue shirt.

Mr. Red now has to be wearing a White shirt.

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The Water Jar | Puzzle 5

noreply@blogger.com (Atul) — Thu, 26 Apr 2018 08:42:00 +0000

Question

There are 3 friends A, B, and C. All of them meet at the same place where they get 24 Litre jar full of water. But they all had to move in the different direction from that point, so they need to divide the water equally. But the problem is they were having the empty jars with them of capacity 5 Litre, 11 Litre, and 13 Litre.

How would they do it?

Solution

As there are total 4 jars of capacity 5L, 11L, 13L, and 24L.

So, they follow this procedure...

24 13 11 5

---------------------------

24 0 0 0

11 13 0 0

6 13 0 5

6 2 11 5

8 0 11 5

8 5 11 0

8 13 3 0

8 8 3 5

8 8 8 0

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Clown's Shoes and Socks | Puzzle 4

noreply@blogger.com (Atul) — Wed, 25 Apr 2018 08:50:00 +0000

Question

Four clowns have to dress up accordingly for a show. From the clothes trunk, each clown had to get their socks and shoes.

There was one pair of each shoe and socks in each color.

The red socks went with the blue shoes.

John had yellow shoes but not yellow socks.

The clown with green shoes did not have blue socks.

James had neither red shoes nor red socks.

David's shoes were the same color as Peter's socks.

The clown with red shoes had green socks.

Can you tell which clown had which color shoes and socks?

Solution

John had yellow shoes and blue socks.

James had green shoes and yellow socks.

David had red shoes and green socks.

Peter had blue shoes and red socks.

First of all note down all the possible combinations of shoes and socks pair according to question.

The Possible Combinations are :

Red Shoes with Green Socks (Confirmed)

Blue Shoes with Red Socks (Confirmed)

Yellow Shoes with Green Socks

Yellow Shoes with Blue Socks

Green Shoes with Green Socks

Green Shoes with Red Socks

Green Shoes with Yellow Socks

Combination for James :

Yellow Shoes with Green Socks

Yellow Shoes with Blue Socks

Green Shoes with Green Socks

Green Shoes with Yellow Socks

Combination for John :

Yellow Shoes with Green Socks

Yellow Shoes with Blue Socks

Combination for David :

Red Shoes with Green Socks (1)

Combination for Peter :

Blue Shoes with Red Socks (1)

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1 Torch, 1 Bridge and 4 Persons | Puzzle 3

noreply@blogger.com (Atul) — Tue, 24 Apr 2018 10:20:00 +0000

Question

There are 4 persons A, B, C, and D who want to cross a bridge in the night time.

A takes 1 minute to cross the bridge.

B takes 2 minutes to cross the bridge.

C takes 5 minutes to cross the bridge.

D takes 8 minutes to cross the bridge.

They were provided with only one torch and the bridge cannot be crossed without the torch. There cannot be more than two persons on the bridge at any time. And when two people cross the bridge together, they must move at the slower person’s pace

What is the minimum time required to cross the bridge?

Solution

The answer is 15 minutes

Firstly, A and B cross the bridge (2 minutes). A comes back (1 minute). Total Time taken is 3 minutes. Now B is on the other side.

C and D cross the bridge (8 minutes). B comes back (2 minutes). Time taken 8 + 2 = 10 minutes. Now C and D are on the other side.

A and B cross the bridge. Time taken is 2 minutes. All are on the other side.

Hence, Total time spent is 3 + 10 + 2 = 15 minutes.

Please share your thoughts in the comments.

Car with a Spare Tyre | Puzzle 2

noreply@blogger.com (Atul) — Mon, 23 Apr 2018 15:00:00 +0000

Question

A car has total in all 5 tyres (4 tyres fixed and 1 spare tyre). Each tyre can travel a maximum distance of 20000 miles before wearing off. What is the maximum distance the car can travel before you are forced to buy a new tyre? You are allowed to change the tyres (using the spare tyre) unlimited number of times.

Solution

25000 KMs

Divide the lifetime of spare tire into 4 equal part i.e., 5000 and swap it at each completion of 5000 miles distance.
Let four tyres be A, B, C and D and spare tyre be S.

First of all the cars runs for 5000 KMs with tyres A, B, C and D fixed.

Then after,

5000 KMs: Replace A with S.

10000 KMs: Put A back to its original position and replace B with S

15000 KMs: Put B back to its original position and replace C with S

20000 KMs: Put C back to its original position and replace D with S

Please share your thoughts in the comments.

3 Bulbs and 3 Switches | Puzzle 1

noreply@blogger.com (Atul) — Mon, 23 Apr 2018 12:52:00 +0000

Question

There is a room with a door (closed) and three light bulbs. Outside the room, there are three switches, connected to the bulbs. You may manipulate the switches as you wish, but once you open the door you can’t change them. Identify each switch with its bulb.

Solution

Let the bulbs be A, B, and C

Turn on switch A for 5 to 10 minutes. Turn it off and turn on switch B. Open the door and touch the light bulb.

1. if the light is on, it is B

2. if the light is off and hot, it is A

3. if the light is off and cold, it is C

Please share your thoughts in the comments.