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      <title>SolvedProblems</title>
      <description>Pipes Output</description>
      <link>http://pipes.yahoo.com/pipes/pipe.info?_id=1c7b386a424212d989b5901629a749b1</link>
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      <pubDate>Mon, 27 Feb 2012 23:11:27 +0000</pubDate>
      <generator>http://pipes.yahoo.com/pipes/</generator>
      <atom10:link xmlns:atom10="http://www.w3.org/2005/Atom" rel="self" type="application/rss+xml" href="http://feeds.feedburner.com/SolvedProblems" /><feedburner:info uri="solvedproblems" /><atom10:link xmlns:atom10="http://www.w3.org/2005/Atom" rel="hub" href="http://pubsubhubbub.appspot.com/" /><feedburner:emailServiceId>SolvedProblems</feedburner:emailServiceId><feedburner:feedburnerHostname>http://feedburner.google.com</feedburner:feedburnerHostname><item>
         <title>My blog</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/sZu-ZoNaumE/</link>
         <description>I am going to write here as my blog soon Yaz&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/sZu-ZoNaumE" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=1055</guid>
         <pubDate>Mon, 22 Nov 2010 06:35:27 +0000</pubDate>
         <category>General</category>
      <feedburner:origLink>http://www.solved-problems.com/1055/blog/</feedburner:origLink></item>
      <item>
         <title>Total Energy Stored – Circuit with Capacitors and Inductors</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/or3d2_4Y40g/</link>
         <description>&lt;img width="150" height="150" src="http://circuits.solved-problems.com/files/2010/11/Energy-stored-in-circuit-capacitors-and-inductors-150x150.png" class="attachment-thumbnail wp-post-image" alt="Energy stored in circuit capacitors and inductors" title="Energy stored in circuit capacitors and inductors"/&gt;Total energy stored in a circuit is calculated by finding the energy stored in each capacitor and each inductor and adding them up. The circuit has two capacitors, two inductors and two independent dc sources. &lt;a rel="nofollow" target="_blank" href="http://circuits.solved-problems.com/1039/total-energy-stored-circuit-capacitors-inductors/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/or3d2_4Y40g" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://circuits.solved-problems.com/?p=1039</guid>
         <pubDate>Fri, 19 Nov 2010 04:42:19 +0000</pubDate>
      <feedburner:origLink>http://circuits.solved-problems.com/1039/total-energy-stored-circuit-capacitors-inductors/</feedburner:origLink></item>
      <item>
         <title>Thévenin’s Theorem – Circuit with Two Independent Sources</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/LRJQ6Pu0tTQ/</link>
         <description>&lt;img width="150" height="150" src="http://circuits.solved-problems.com/files/2010/11/Thevenins-Theorem-Circuit-containing-two-independent-sources-main-150x150.png" class="attachment-thumbnail wp-post-image" alt="Thevenin&amp;#039;s Theorem - Circuit containing two independent sources main" title="Thevenin&amp;#039;s Theorem - Circuit containing two independent sources main"/&gt;Thévenin's Theorem is deployed to solve a simple circuit which contains two independent sources. The solution is explained step-by-step. &lt;a rel="nofollow" target="_blank" href="http://circuits.solved-problems.com/1016/thevenins-theorem-two-independent-sources/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/LRJQ6Pu0tTQ" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://circuits.solved-problems.com/?p=1016</guid>
         <pubDate>Tue, 16 Nov 2010 06:25:05 +0000</pubDate>
      <feedburner:origLink>http://circuits.solved-problems.com/1016/thevenins-theorem-two-independent-sources/</feedburner:origLink></item>
      <item>
         <title>Thévenin’s Theorem – Circuit with An Independent Source</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/1obDVqU0vJQ/</link>
         <description>Thevenin's Theorem is deployed to solve a quite simple circuit with only one independent voltage source. The solution is explained step-by-step. &lt;a rel="nofollow" target="_blank" href="http://circuits.solved-problems.com/1005/thevenins-theorem-circuit-independent-source/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/1obDVqU0vJQ" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://circuits.solved-problems.com/?p=1005</guid>
         <pubDate>Thu, 28 Oct 2010 06:07:56 +0000</pubDate>
      <feedburner:origLink>http://circuits.solved-problems.com/1005/thevenins-theorem-circuit-independent-source/</feedburner:origLink></item>
      <item>
         <title>Superposition Method – Circuit With Dependent Sources</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/-gmmR_feH3w/</link>
         <description>&lt;img width="150" height="150" src="http://circuits.solved-problems.com/files/2010/09/Superposition-Circuit-with-dependent-sources-t-150x150.png" class="attachment-thumbnail wp-post-image" alt="Superposition - Circuit with dependent sources t" title="Superposition - Circuit with dependent sources t"/&gt;A circuit with two independent and two dependent sources is solved by the superposition method. Independent sources are turned off one at a time and the contribution of the on source is calculated. Dependent sources should not be turned off. &lt;a rel="nofollow" target="_blank" href="http://circuits.solved-problems.com/947/superposition-method-circuit-dependent-sources/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/-gmmR_feH3w" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://circuits.solved-problems.com/?p=947</guid>
         <pubDate>Wed, 08 Sep 2010 05:49:51 +0000</pubDate>
      <feedburner:origLink>http://circuits.solved-problems.com/947/superposition-method-circuit-dependent-sources/</feedburner:origLink></item>
      <item>
         <title>Superposition Problem with Four Voltage and Current Sources</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/9EwAuqJjvro/</link>
         <description>&lt;img width="150" height="150" src="http://circuits.solved-problems.com/files/2010/09/Superposition-Four-Sources-t-150x150.png" class="attachment-thumbnail wp-post-image" alt="Superposition - Four Sources t" title="Superposition - Four Sources t"/&gt;A circuit with two voltage sources and two current sources is solved by the superposition method. The contribution of each source is calculated individually and the response is found by adding the contributions.    &lt;a rel="nofollow" target="_blank" href="http://circuits.solved-problems.com/936/superposition-problem-voltage-current-sources/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/9EwAuqJjvro" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://circuits.solved-problems.com/?p=936</guid>
         <pubDate>Tue, 07 Sep 2010 06:33:25 +0000</pubDate>
      <feedburner:origLink>http://circuits.solved-problems.com/936/superposition-problem-voltage-current-sources/</feedburner:origLink></item>
      <item>
         <title>Bulk Image Resizer</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/3uy6bP4fh1M/</link>
         <description>Bulk Image Resizer can be used to resize images by a scaling factor. It is an open source project. The source and executable files can be downloaded from the following link. Download Screenshots</description>
         <guid isPermaLink="false">http://tools.solved-problems.com/?p=6</guid>
         <pubDate>Fri, 03 Sep 2010 06:57:10 +0000</pubDate>
         <content:encoded><![CDATA[<p id="top"/><em>Bulk Image Resizer</em> can be used to resize images by a scaling factor. It is an open source project. The source and executable files can be downloaded from the following link.
<p><span id="more-6"></span></p>
<p><a rel="nofollow" target="_blank" href="https://sourceforge.net/projects/bulkimageresize/">Download</a></p>
<p><strong>Screenshots</strong></p>
<div id="attachment_476" class="wp-caption alignnone" style="width:512px;"><a rel="nofollow" target="_blank" href="http://www.solved-problems.com/wp-content/uploads/Solved-Problems.jpg"><img class="size-full wp-image-476" title="Bulk Image Resizer - Version 0.0.2" src="http://www.solved-problems.com/wp-content/uploads/Solved-Problems.jpg" alt="Bulk Image Resizer - Version 0.0.2" width="502" height="315"/></a><p class="wp-caption-text">Version 0.0.2</p></div>
<div id="attachment_472" class="wp-caption alignnone" style="width:310px;"><img class="size-medium wp-image-472" title="Bulk Image Resizer" src="http://www.solved-problems.com/wp-content/uploads/ScS-300x195.png" alt="Screenshots" width="300" height="195"/><p class="wp-caption-text">Version 0.0.1</p></div><img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/3uy6bP4fh1M" height="1" width="1"/>]]></content:encoded>
      <feedburner:origLink>http://tools.solved-problems.com/2010/09/03/bulk-image-resizer/</feedburner:origLink></item>
      <item>
         <title>Turning Sources Off</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/n4C0SNpwAwA/</link>
         <description>Turning off a source used in solving circuits with the superposition, means setting its value equal to zero. A voltage sources become a short circuit when turned off. To turn off a current source it should be replaced by an open circuit. Dependent sources cannot be turned off. &lt;a rel="nofollow" target="_blank" href="http://circuits.solved-problems.com/839/turning-sources-off/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/n4C0SNpwAwA" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=839</guid>
         <pubDate>Thu, 02 Sep 2010 05:40:36 +0000</pubDate>
      <feedburner:origLink>http://circuits.solved-problems.com/839/turning-sources-off/</feedburner:origLink></item>
      <item>
         <title>Solving Quadratic Equations II: Taking Square Roots</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/mqGvt0BWxXQ/</link>
         <description>Solving quadratic equations by taking the square root of both sides of the equation is explained. Some examples are provided to show the method step by step. &lt;a rel="nofollow" target="_blank" href="http://calculus.solved-problems.com/829/solving-quadratic-equations-ii-square-roots/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/mqGvt0BWxXQ" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=829</guid>
         <pubDate>Sat, 31 Jul 2010 22:28:59 +0000</pubDate>
      <feedburner:origLink>http://calculus.solved-problems.com/829/solving-quadratic-equations-ii-square-roots/</feedburner:origLink></item>
      <item>
         <title>Solving Quadratic Equations I: Factoring (Grouping)</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/yAQ6cciFeYc/</link>
         <description>Solving quadratic equations by factoring is explained with some examples. Two methods are introduced to factorize quadratic equations. Other methods of solving quadratic equations are also addressed. &lt;a rel="nofollow" target="_blank" href="http://calculus.solved-problems.com/814/solving-quadratic-equations-i-factoring-grouping/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/yAQ6cciFeYc" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=814</guid>
         <pubDate>Thu, 15 Jul 2010 06:55:50 +0000</pubDate>
      <feedburner:origLink>http://calculus.solved-problems.com/814/solving-quadratic-equations-i-factoring-grouping/</feedburner:origLink></item>
      <item>
         <title>Solving Equations II: Radical Equations</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/VpKwe-2SdzY/</link>
         <description>This article explains the process of solving equations with radicals. Solving radical equations is performed by isolating radicals and raising both sides to a power equal to the index of the radicals one by one. The method is explained and ten examples are solved to illustrate solving equations with radicals. &lt;a rel="nofollow" target="_blank" href="http://calculus.solved-problems.com/790/solving-equations-ii/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/VpKwe-2SdzY" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=790</guid>
         <pubDate>Sat, 10 Jul 2010 21:25:13 +0000</pubDate>
      <feedburner:origLink>http://calculus.solved-problems.com/790/solving-equations-ii/</feedburner:origLink></item>
      <item>
         <title>Solving Equations I: Linear Equations</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/ppg1iCSwKGE/</link>
         <description>This article explains the process of solving equations of linear form. Solving linear equations is performed by isolating the unknown variable. Two methods are introduced to fulfill isolation. The article also contains ten examples to illustrate solving equations. &lt;a rel="nofollow" target="_blank" href="http://calculus.solved-problems.com/776/solving-equations-i/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/ppg1iCSwKGE" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=776</guid>
         <pubDate>Sat, 10 Jul 2010 01:06:56 +0000</pubDate>
      <feedburner:origLink>http://calculus.solved-problems.com/776/solving-equations-i/</feedburner:origLink></item>
      <item>
         <title>Electrical Circuits eBooks</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/HsRwOSiFLPo/</link>
         <description>&lt;img width="150" height="150" src="http://circuits.solved-problems.com/files/2010/07/cover_1-150x150.png" class="attachment-thumbnail wp-post-image" alt="Nodal Analysis eBook" title="Nodal Analysis eBook"/&gt;Free Electrical Circuits Ebooks. 1) Nodal Analysis, 2) Mesh Analysis, ... &lt;a rel="nofollow" target="_blank" href="http://circuits.solved-problems.com/762/electrical-circuits-ebooks/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/HsRwOSiFLPo" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=762</guid>
         <pubDate>Mon, 05 Jul 2010 02:05:03 +0000</pubDate>
      <feedburner:origLink>http://circuits.solved-problems.com/762/electrical-circuits-ebooks/</feedburner:origLink></item>
      <item>
         <title>Nodal Analysis</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/jYYp66b8mVc/</link>
         <description>&lt;img width="150" height="150" src="http://circuits.solved-problems.com/files/2010/07/cover_-150x150.png" class="attachment-thumbnail wp-post-image" alt="cover_" title="cover_"/&gt;The nodal analysis is explained. Necessary steps to solve a circuit with the nodal analysis is mentioned. A free ebook about nodal analysis is also included. &lt;a rel="nofollow" target="_blank" href="http://circuits.solved-problems.com/696/nodal-analysis/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/jYYp66b8mVc" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=696</guid>
         <pubDate>Fri, 02 Jul 2010 04:12:35 +0000</pubDate>
      <feedburner:origLink>http://circuits.solved-problems.com/696/nodal-analysis/</feedburner:origLink></item>
      <item>
         <title>Nodal Analysis – Circuit with Dependent Voltage Source</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/Z2INTnGO828/</link>
         <description>&lt;img width="150" height="150" src="http://circuits.solved-problems.com/files/2010/07/Nodal-Analysis-Supernode-Dependent-Voltage-Source-7-150x150.png" class="attachment-thumbnail wp-post-image" alt="Nodal Analysis - Supernode - Dependent Voltage Source 7" title="Nodal Analysis - Supernode - Dependent Voltage Source 7"/&gt;A 6-node circuit is solved with the nodal analysis. It contains one dependent voltage source, two independent voltage sources, two independent current sources and some resistors. The dependent causes two nodes to form a supernode. &lt;a rel="nofollow" target="_blank" href="http://circuits.solved-problems.com/716/supernode-dependent-voltage-source/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/Z2INTnGO828" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=716</guid>
         <pubDate>Thu, 01 Jul 2010 22:53:22 +0000</pubDate>
      <feedburner:origLink>http://circuits.solved-problems.com/716/supernode-dependent-voltage-source/</feedburner:origLink></item>
      <item>
         <title>Nodal Analysis – 6-Node Circuit</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/K9BVpIPKUtg/</link>
         <description>&lt;img width="150" height="150" src="http://circuits.solved-problems.com/files/2010/07/Nodal-Analysis-6-Node-Circuit-5-150x150.png" class="attachment-thumbnail wp-post-image" alt="Nodal Analysis 6 Node Circuit 5" title="Nodal Analysis 6 Node Circuit 5"/&gt;A 6-node circuit is solved by the nodal analysis method and powers of voltage and current sources are calculated. The system of linear equations has three equations with three unknowns. &lt;a rel="nofollow" target="_blank" href="http://circuits.solved-problems.com/713/nodal-analysis-6-node-circuit/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/K9BVpIPKUtg" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=713</guid>
         <pubDate>Thu, 01 Jul 2010 05:44:17 +0000</pubDate>
      <feedburner:origLink>http://circuits.solved-problems.com/713/nodal-analysis-6-node-circuit/</feedburner:origLink></item>
      <item>
         <title>Problem 2-11: Differentiating by Chain Rule</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/aDdUin1y0YU/</link>
         <description>Differentiating (1+sqrt(x))^8 by the chain rule.  Determining individual components of the chain rule. &lt;a rel="nofollow" target="_blank" href="http://calculus.solved-problems.com/241/problem-2-11/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/aDdUin1y0YU" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=241</guid>
         <pubDate>Sun, 11 Apr 2010 03:22:41 +0000</pubDate>
      <feedburner:origLink>http://calculus.solved-problems.com/241/problem-2-11/</feedburner:origLink></item>
      <item>
         <title>Problem 2-10: Diffrentiating</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/F6Jzt2BB8mY/</link>
         <description>Diffrentiating f(x)= (1-2x^2)/(1+x+x^2) and f(x)= (1-2x^2)(1+x+x^2) &lt;a rel="nofollow" target="_blank" href="http://calculus.solved-problems.com/234/problem-2-10/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/F6Jzt2BB8mY" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=234</guid>
         <pubDate>Sun, 11 Apr 2010 02:47:37 +0000</pubDate>
      <feedburner:origLink>http://calculus.solved-problems.com/234/problem-2-10/</feedburner:origLink></item>
      <item>
         <title>Problem 2-9: Differentiating Polynomial and Rational Functions</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/ubcJWu0yQJM/</link>
         <description>Differentiating f(x)= 1+ 2x, f(x)= 1 - 2x + 2x^2, f(x)= 1- x^2 +1/x and f(x)= 1 - x +1/(1-x) &lt;a rel="nofollow" target="_blank" href="http://calculus.solved-problems.com/215/problem-2-9/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/ubcJWu0yQJM" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=215</guid>
         <pubDate>Sun, 11 Apr 2010 01:57:33 +0000</pubDate>
      <feedburner:origLink>http://calculus.solved-problems.com/215/problem-2-9/</feedburner:origLink></item>
      <item>
         <title>Problem 2-8: Integration</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/uQZ9ZMPHZoQ/</link>
         <description>Integrating e^x/(1+e^x) &lt;a rel="nofollow" target="_blank" href="http://calculus.solved-problems.com/208/problem-2-8/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/uQZ9ZMPHZoQ" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=208</guid>
         <pubDate>Sat, 10 Apr 2010 20:55:54 +0000</pubDate>
      <feedburner:origLink>http://calculus.solved-problems.com/208/problem-2-8/</feedburner:origLink></item>
      <item>
         <title>Problem 2-7: Evaluatin Definite Integrals</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/u_QOXzLk7v0/</link>
         <description>Evaluating definite integrals x^2, sin(x),  2x^3+x-1 and &amp;#124;x&amp;#124; &lt;a rel="nofollow" target="_blank" href="http://calculus.solved-problems.com/169/problem-2-7/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/u_QOXzLk7v0" height="1" width="1"/&gt;</description>
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         <pubDate>Sat, 10 Apr 2010 19:38:27 +0000</pubDate>
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      <item>
         <title>Problem 2-6: Odd and Even Functions</title>
         <link>http://feedproxy.google.com/~r/SolvedProblems/~3/51rxznQYGZ8/</link>
         <description>Determining odd and even functions for sin(x), cos(x), sin(x)cos(x), x*sin(x), x^2 and sin(x)+cos(x) &lt;a rel="nofollow" target="_blank" href="http://calculus.solved-problems.com/156/problem-2-6/"&gt;Continue reading &lt;span class="meta-nav"&gt;&amp;#8594;&lt;/span&gt;&lt;/a&gt;&lt;img src="http://feeds.feedburner.com/~r/SolvedProblems/~4/51rxznQYGZ8" height="1" width="1"/&gt;</description>
         <guid isPermaLink="false">http://www.solved-problems.com/?p=156</guid>
         <pubDate>Sat, 10 Apr 2010 06:26:58 +0000</pubDate>
      <feedburner:origLink>http://calculus.solved-problems.com/156/problem-2-6/</feedburner:origLink></item>
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