SolvedProblems

AC Circuit Analysis - Sources with Different Frequencies

Thu, 23 Apr 2015 05:52:44 +0000

In AC circuit analysis, if the circuit has sources operating at different frequencies, Superposition theorem can be used to solve the circuit. Please note that AC circuits are linear and that is why Superposition theorem is valid to solve them. Problem Determine where and . Solution with AC Circuit Analysis Since sources are operating at […]

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Mesh (Current) Analysis Problem

Sun, 19 Apr 2015 06:45:57 +0000

Solve the circuit by mesh analysis and find the current and the voltage across . Solution Mesh Analysis There are four meshes in the circuit. So, we need to assign four mesh currents. It is better to have all the mesh currents loop in the same direction (usually clockwise) to prevent errors when writing out […]

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Stability using Routh Stability Criterion

Tue, 30 Sep 2014 14:12:28 +0000

Determine the stability of the system whose characteristics equation is: . Solution All coefficients are positive and non-zero; therefore, the necessary condition for stability is satisfied. Let's write the Routh array: At this stage, we see that the top row corresponding to can be divided by two to make the calculation a little bit easier. […]

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Winner of Electrical Circuits Contest #1

Mon, 21 Oct 2013 17:46:44 +0000

Problem Find and : Solution Three resistors are in series and their equivalent, , is parallel with the voltage source. So, according to the Ohm's law: . The negative sign comes from the direction . Applying KCL at the bottom node: . The lucky winner of the Electrical Circuits Contest #1 is Kunal Marwaha from […]

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Find Equivalent Impedance - AC Steady State Analysis

Sat, 19 Oct 2013 19:18:05 +0000

Determine the driving-point impedance of the network at a frequency of kHz: Solution Lets first find impedance of elements one by one: Resistor The resistor impedance is purely real and independent of frequency. Inductors and The inductor impedance is purely imaginary and directly proportional to frequency: We need to find the impedance in kHz. Therefore: […]

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Electrical Circuit Contest - Win $10!

Tue, 15 Oct 2013 22:19:57 +0000

What's up? We are going to have fun! This is our first contest for electrical circuits. Solve the problem, submit your answers and cross your fingers to be the lucky winner! Problem Find and : Submit your answers Use this form to submit your answers. You also need to write the code that you will […]

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Superposition method - Circuit with two sources

Tue, 15 Oct 2013 18:32:58 +0000

Find using superposition rule: Solution Superposition The superposition theorem states that the response (voltage or current) in any branch of a linear circuit which has more than one independent source equals the algebraic sum of the responses caused by each independent source acting alone, while all other independent sources are turned off (made zero). There […]

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Find Thevenin's and Norton's Equivalent Circuits

Wed, 09 Oct 2013 21:03:18 +0000

Find Thevenin's and Norton's Equivalent Circuits: Suppose that , and . Solution The circuit has both independent and dependent sources. In these cases, we need to find open circuit voltage and short circuit current to determine Norton's (and also Thevenin's) equivalent circuits. Open circuit voltage Open circuit voltage means the voltage across the terminals of […]

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Solve Using Current Division Rule

Wed, 02 Oct 2013 21:06:27 +0000

Find current of resistors, use the current division rule. Suppose that , , , and Solution: and are parallel. The current of is passing through them and it is actually divided between them. The branch with lower resistance has higher current because electrons can pass through that easier than the other branch. Using the current […]

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Mesh Analysis - Supermesh

Fri, 27 Sep 2013 23:25:31 +0000

Solve the circuit and find the power of sources: , , , , , . Solution: There are three meshes in the circuit. So, we need to assign three mesh currents. It is better to have all the mesh currents loop in the same direction (usually clockwise) to prevent errors when writing out the equations. […]

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