<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:blogger='http://schemas.google.com/blogger/2008' xmlns:georss='http://www.georss.org/georss' xmlns:gd="http://schemas.google.com/g/2005" xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-4962332282824769433</id><updated>2024-09-20T14:36:37.320-07:00</updated><title type='text'>Tangent Formula And Funtion</title><subtitle type='html'></subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://textualtangents.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4962332282824769433/posts/default'/><link rel='alternate' type='text/html' href='http://textualtangents.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>Unknown</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>1</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-4962332282824769433.post-2990374390651290571</id><published>2011-09-21T13:42:00.000-07:00</published><updated>2011-09-21T13:42:41.490-07:00</updated><title type='text'>a line tangent to the circle</title><content type='html'>Sample Question :&lt;br /&gt;
 Consider the circle of radius 5 centered at (0,0). Find an equation of the line tangent to the circle at the point (3,4).&lt;br /&gt;
&lt;br /&gt;
 &lt;br /&gt;
 Answer :&lt;br /&gt;
&lt;br /&gt;
The line tangent to a circle is also perpendicular to the radius drawn 
to the point of tangency. So finding the slope of the radius out to the 
tangent line is easy in this case, since you&#39;re starting at the origin 
and going out to (3.4): rise/run, or 4/3. &lt;br /&gt;
&lt;br /&gt;
The tangent line will be perpendicular to the radius, so it&#39;s slope will be a negative reciprocal: -3/4&lt;br /&gt;
&lt;br /&gt;
Now use y = mx + b, substitute in -3/4 for m, and (3,4) for x and y to find b:&lt;br /&gt;
&lt;br /&gt;
4 = -3/4(3) + b&lt;br /&gt;
4 = -9/4 + b&lt;br /&gt;
b = 25/4&lt;br /&gt;
&lt;br /&gt;
So the equ&#39;n of the tangent line is y = -(3/4)x + 25/4.&lt;br /&gt;
&lt;br /&gt;</content><link rel='replies' type='application/atom+xml' href='http://textualtangents.blogspot.com/feeds/2990374390651290571/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://textualtangents.blogspot.com/2011/09/line-tangent-to-circle.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4962332282824769433/posts/default/2990374390651290571'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4962332282824769433/posts/default/2990374390651290571'/><link rel='alternate' type='text/html' href='http://textualtangents.blogspot.com/2011/09/line-tangent-to-circle.html' title='a line tangent to the circle'/><author><name>Unknown</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry></feed>