Just Do It...

Free Trainers for Your Brain

2013-08-22T15:10:00.003+05:30

Free Trainers for Your Brain

Tom Cooper, Editor
Informer Technologies, Inc.

Human brain keeps surprising scientists even these days. We, as a human race, kind of have an idea of how it works and we have a definite understanding of how certain parts of it are connected, but no honest person would ever tell you that it is one hundred percent clear. Isn't it fascinating? We, as a generation, may never find out in our lifetime what it is all about. Maybe that's where the answers to all philosophical questions are waiting to be discovered. This article isn't dedicated to neuropsychology, however, as you might've assumed, but rather to brain trainers. I'm also trying to evaluate how appropriate it is to claim that a brain can actually be trained.

We all have been through some learning in our lives, otherwise you wouldn't be able to even read these words and instead would simply keep staring at a bunch of symbols put together for some reason without having any idea as to what to do with them. The knowledge we acquired in high school and college is not necessarily useful at every single moment of our mundane life, but it still may benefit us in the long run. Isn't it fun to indulge in the nostalgia of those young and simpler high-school times, where your only worries were today's homework and math problems? If you've never tried that, I highly recommend you do so. This would be just one use of brain trainers — the opportunity to test your knowledge. There are also other options, which may appeal more to adults since they are designed to help you improve your memory and do not necessarily depend on your motoric skills. Let's start off with a game I found to be the easiest and the simplest, and then work our way up to more interesting ones.

BrainSpeeder

BrainSpeeder is a game with simplistic design and not too many features. Although it includes both «online» and «offline» modes, I couldn't compete with other players online and received a message with the closest tournament date instead.

When you start the application, you see a menu with a couple of options including language choice (I chose English, of course). Then you choose the game type from the list:

Arithmetic game lets you choose a mode from common arithmetical operations (substraction, addition, etc.) or a random combination of those («Standard» mode). Other modes are pretty fun too, but when the game starts you might get a little confused as the preview displayed during the first seconds really looks like the game has already started. The program is very light and easy to setup so you can at least give it a try.

gbrainy

This game struck me as a difficult one. I didn't try to adjust the difficulty level though, so that may have been the reason. The above image of the main game's window pretty much covers all the modes that you can choose.

Logic puzzles are pretty interesting and are aimed to make you think rather than use some previously acquired knowledge or skills. You may be asked to discover a pattern in a sequence of numbers or shapes and choose the proper one to extend that sequence.

Memory trainers are either crazily difficult or I really lack the short-term memory abilities. The other modes (mental calculation and verbal analogies) are pretty much self-explanatory.

My overall impression from this app was quite pleasant, although it is hard to admit that a game is good when you struggle to get even a mediocre score.

Brain Workshop

The last one I tried was pretty awesome and intriguing, it even managed to capture my attention for quite a while. The competitive part of me woke up; and even though my only competitor was the scoreboard, I did try to beat my own high-scores every time.

This game is supposed to help you improve your memory and attention, and is even recommended for people with ADD or ADHD. These conditions are often claimed to be artificial or made up, but you don't need to call the lack of your attention names, just know that if you feel that you have it — try this one out.

Your goal here is to watch blue squares show up on the grid accompanied by a sound of a letter and press either «a» or «l» on your keyboard if the square had the same position or you hear the same letter.

I won't be surprised if my description doesn't really «sell» the game, but trust me — if you try it once, you will spend quite some time playing.

All these games are fun; however, I liked the Brain Workshop more than others, but you may find the opposite to be true. Have a nice brain workout!

reference: http://articles.software.informer.com/free-trainers-for-your-brain.html

REMOVE QVO6.COM HOMEPAGE VIRUS (REMOVAL INSTRUCTION)

2013-07-30T17:31:00.002+05:30

REMOVE QVO6.COM HOMEPAGE VIRUS (REMOVAL INSTRUCTION)

http://www.remove-malware.info/removal-instructions/remove-qvo6-com-homepage-virus-removal-instruction/

Make Microsoft Virtual WiFi Miniport Adapter

2013-07-30T17:27:00.003+05:30

Making Virtual Wireless router in Windows 7

1. Open the Command prompt as Administrator
2. Check your computer Hosted network supported

>> netsh wlan show drivers
..
Hosted network supported : Yes

3. Create the Virtual WiFi

>>netsh wlan set hostednetwork mode=allow ssid=ssid1 key=password keyUsage=persistent
The hosted network mode has been set to allow.

The SSID of the hosted network has been successfully changed.

The user key passphrase of the hosted network has been successfully changed.

4. Start the Hosted network

>> netsh wlan start hostednetwork

The hosted network started

5. To stop the Hosted network

>> netsh wlan stop hostednetwork

The hosted network stopped.

Check the Network settings:

1. In Control panel and open the Network and Sharing Center.
a) Look for the created hostedNetwork ssid is visible on this page

2. On left side panel click on Change adapter settings

a. Right click on your Wireless Network Connection or Local Area Connection and
open the properties
b. Click on Sharing tab and enable the option "Allow other network users to connect through this internet’s connection"
and select the Home network connection as your newly created hostedNetwork wireless connection

3. Go back to Network and Sharing Center and see your hosted Network ssid showing with Internet access.

4. You are now ready to access internet from this Virtual router to any WiFi devices.

windows could not start the DHCP client on Local Computer.

2012-07-23T20:03:00.001+05:30

"windows could not start the DHCP client on Local Computer.

error 1079: the account specified for this service is different from the account specified for other services running on the same process""

Solution:

1. start services.msc
2. open DHCP Client
3. Select Log On Tab, and select "This account" Radio button
4. Click on Browse and select Advanced button
5. Click on Find Now button and select Local Service
6. Press Ok and Start the DHCP Client service

The operation failed as no adapter is in the state permissible for this operation (IPconfig /renew)

2012-04-03T17:58:00.001+05:30

I would suggest you to follow these steps and check if it works.

a. Click Start, click Run, type cmd, and then press ENTER.

b. At the command prompt, type netsh int ip reset resetlog.txt, and then press ENTER to reset the TCP/IP network protocol.

c. At the command prompt, type ipconfig /renew, and then press ENTER and check whether you see the error.

Bitwise Operations

2012-03-24T19:00:00.000+05:30

1. AND ( &)

2. OR ( | )

3. COMPLEMENT ( ~ )

4. X-OR ( ^ )

5. LEFT SHIFT ( << )

6. RIGHT SHIFT ( >> )

Bits are 0 or 1.

1. AND ( & )

if and only two bits are 1's then result is 1 else 0

0 & 0 = 0

0 & 1 = 0

1 & 0 = 0

1 & 1 = 1

Ex: a = 0010 , b = 1010

0010

1010

------

0010 a & b

------

1. OR ( | )

if and only two bits are 0's then result is 0 else 1

0 | 0 = 0

0 | 1 = 1

1 | 0 = 1

1 | 1 = 1

Ex: a = 0010 , b = 1010

0010

1010

------

1010 a | b

------

3. COMPLEMENT ( ~ )

It flips the bits.

~ 0 = 1

~ 1 = 0

Ex: a = 0010

0010

------

1101 ~a

------

4. X-OR ( ^ )

if and only two bits are same 1's or 0's then result is 0 else 1. This is used for flip the bits i.e. value ^ 1.

0 ^ 0 = 0

0 ^ 1 = 1

1 ^ 0 = 1

1 ^ 1 = 0

Ex: a = 0010 , b = 1010

0010

1010

------

1000 a ^ b

------

5. LEFT SHIFT ( << )

shifts the number bit position to right. acts as multiplication of 2

1010 << 1 = 10100

Ex: a = 0010 ,

a << 2 = 1000

5. LEFT SHIFT ( << )

shifts the number bit position to left. acts as division of 2

1010 >> 1 = 0101

Ex: a = 1000 ,

a >> 2 = 0010

How To Be Successful In Any Job Interview

2012-03-20T21:28:00.001+05:30

1. What are your Strengths?

Ans: I'm well motivated. when you need me to step up to the plate, I'm there, I'm always ready and willing to learn new skills.

2. What are your Weaknesses?

Ans: When I become aware of a weakness, I see it as there;s a golden opportunity in me to further develop skills and knowledge. I do this through training or from my colleagues. Some people say, I'm too persistent.

Program Memory

2012-03-16T23:52:00.003+05:30

The computer program memory is organized into the following:

Data Segment (Data + BSS + Heap)
Stack
Code segment

Data

The data area contains global and static variables used by the program that are explicitly initialized with a value. This segment can be further classified into a read-only area and read-write area. For instance, the string defined by char s[] = "hello world" in C and a C statement like int debug=1 outside the "main" would be stored in initialized read-write area. And a C statement likeconst char* string = "hello world" makes the string literal "hello world" to be stored in initialized read-only area and the character pointer variable string in initialized read-write area. Ex: static int i = 10 will be stored in the data segment and global int i = 10 will be stored in the data segment.

BSS

The BSS segment, also known as uninitialized data, starts at the end of the data segment and contains all global variables and static variables that are initialized to zero or do not have explicit initialization in source code. For instance a variable declared static int i; would be contained in the BSS segment.

Heap
The heap area begins at the end of the BSS segment and grows to larger addresses from there. The heap area is managed by malloc, realloc, and free, which may use the brk and sbrk system calls to adjust its size (note that the use of brk/sbrk and a single "heap area" is not required to fulfill the contract of malloc/realloc/free; they may also be implemented using mmap to reserve potentially non-contiguous regions of virtual memory into the process' virtual address space). The heap area is shared by all shared libraries and dynamically loaded modules in a process.

Stack

The stack area traditionally adjoined the heap area and grew the opposite direction; when the stack pointer met the heap pointer, free memory was exhausted. (With modern large address spaces and virtual memory techniques they may be placed almost anywhere, but they still typically grow in opposite directions.)

The stack area contains the program stack, a LIFO structure, typically located in the higher parts of memory. On the standard PC x86 computer architecture it grows toward address zero; on some other architectures it grows the opposite direction. A "stack pointer" register tracks the top of the stack; it is adjusted each time a value is "pushed" onto the stack. The set of values pushed for one function call is termed a "stack frame"; A stack frame consists at minimum of a return address.

Virtual function and vtable in C++

2012-03-16T23:22:00.001+05:30

If a class declares a function as virtual then compiler constructs the vtable or Virtual Table for that class which stores addresses if virtual funcrions.
If any other classes derives from that class then they creates their own vtable.
The compiler also adds a hidden vptr variable in all such classes.
If a virtual function is not overridden in derived class then vtable stores address of its parent class function.

vtable stores static array of virtual functions, so that different instances of the same class can share that vtable.
Since, static members are stored in the data section (.data), the vtable is also stored in the data section of the executable.
vtable is used to resolve the address of the function when virtual function is called at run-time.
Dynamic binding in C++ is achieved through vtable.

If derived class object is assigned to base object pointer, the vptr variable is points to vtable of the derived class. This ensures that derived virtual functions get called.

Example:

class Base

{

public:

virtual void display()

{

std::cout << "Base:: display()";

}

};

class Derived : publid Base

{

public:

void display()

{

std::cout << "Derived::display()";

}

};

void main()
{
Base *b = new Base;
b->display();

Derived *d = new Derived();
d->display();

Base *b1 = new Derived();
b1->display();
}

Output:

Base::display()
Derived::display()
Derived::display()

Queues

2012-03-15T22:52:00.002+05:30

Queue uses FIFO(first-in first-out) ordering.

class Queue {
    Node *first, *last;
 
public:
    void enqueue(Node *item)
    {
        if (first == NULL)
        {
            last = new Node(item);
            first = last;
        }
        else {
            last->next = new Node(item);
            last = last->next;
        }
    }
 
    int dequeue(Node *n)
    {
        if (first != 0)
        {
            Node *item = first;
            first = first->next;
            int val = item->value;
            delete item;
            return val;
        }
    }
};

Stacks

2012-03-15T22:41:00.001+05:30

Stack uses the LIFO(last-in first-out) ordering. like a stack of dinner plates.

class Node
{
public:
    Node(Node *item)
    {
        value = item->value;
        next = item ->next;
    }
    int value;
    Node* next;
};
 
class Stack {
    Node* top;

public:
    int Pop() {

        if (top != 0) {
            Node* item = top;
            top = top->next;
            int val = item->value;
            delete item;
            return val;
        }
    }

 
    void Push(Node *item) {
        Node* t = new Node(item);
        t->next = top;
        top = t;
    }
 
    int peek() {
        return top->value;
    }
}

Good Coding Practice

2012-03-15T22:17:00.000+05:30

Correct: The code should operate correctly on all expected and unexpected results
Efficient: In terms of time and space.
Simple: if you can do 10 lines instead of 100.
Readable: A different developer should be able to read.
Maintainable: Code should be reasonably adaptable to changes during the life cycle of a product and should be easy to maintain by other developers

Data structrures brain storm

2012-03-15T21:56:00.000+05:30

Linked list: linked lists tend not to do very well with accessing and sorting numbers

Array: fast accessing, but sorting is expensive
Binary tree: binary trees do failry well with ordering.
Heap: a heap is reallt good at basic ordering nad keeping track of max and mins.

HSBC calculators

2012-03-15T18:34:00.002+05:30

http://www.hsbcinvestdirect.co.in/helpcenter/tools_calculators.jsp

Activating ActiveX Controls in HTMl

2012-03-13T22:04:00.001+05:30



	<!-- HTML File -->
	<html>
	<head>
	<script src="external_script.js" language="JScript"></script>
	</head>

	<body>
	<div id="EXAMPLE_DIV_ID">
	This text will be replaced by the control
	</div>
	<script language="JScript">
	CreateControl( "EXAMPLE_DIV_ID",
	"clsid:6BF52A52-394A-11d3-B153-00C04F79FAA6",
	"EXAMPLE_OBJECT_ID", "600", "400", "example.wmv",
	"-1")
	</script>
	</body>
	</html>

// external_script.js

function CreateControl(DivID, CLSID, ObjectID,

WIDTH, HEIGHT, URL, AUTOSTART)

{

var d = document.getElementById(DivID);

d.innerHTML =

'<object classid=' + CLSID + ' id=' + ObjectID +

' width=' + WIDTH + ' height=' + HEIGHT +'>

<param name="URL" value=' + URL + '>

<param name="autoStart" value=' + AUTOSTART + '/>';

}

write code to remove the duplicate characters in a string

2012-03-12T23:52:00.001+05:30

public static void removeDuplicates(char[] str) {
if (str == null) return;
int len = str.length;
if (len < 2) return;

int tail = 1;

for (int i = 1; i < len; ++i) {
int j;
for (j = 0; j < tail; ++j) {
if (str[i] == str[j]) break;
}
if (j == tail) {
str[tail] = str[i];
++tail;
}
}
str[tail] = 0;
}

reverse a C-Style String

2012-03-12T23:45:00.000+05:30

void reverse(char *str)
{
char * end = str;
char tmp;
if (str)
{
while (*end) {
++end;
}
--end;

while (str < end) {
tmp = *str;
*str++ = *end;
*end-- = tmp;
}
}
}

Implement an algorithm to determine if a string has all unique characters.

2012-03-12T23:42:00.002+05:30

Solution1:

bool isUniqueChars2(string str) {
bool[] char_set = new bool[256];
for (int i = 0; i < str.length(); i++) {
int val = str[i];
if (char_set[val]) return false;
char_set[val] = true;
}
return true;
}

Time complexity is O(n), where n is the length of the string, and space complexity is O(n).

Solution 2:

public static boolean isUniqueChars(String str) {
int checker = 0;
for (int i = 0; i < str.length(); ++i) {
int val = str.charAt(i) - ‘a’;
if ((checker & (1 << val)) > 0) return false;
checker |= (1 << val);
}
return true;
}

Financial Calculators

2012-03-12T19:17:00.002+05:30

http://www.inglife.co.in/planningtools/planningtools-achieving.shtml

InOrder Iterative tree traversal

2012-02-29T02:08:00.002+05:30

inOrderTraversalIterative(BinaryTree *root)
{
stack s;

cursor = root; //set cursor to root of binary tree
done = false;

while (!done)
{
if(cursor != NULL)
{
s.push(cursor); //place pointer to node on the stack
//before traversing the node's left subtree
cursor = cursor->left(); //traverse the left subtree
}
else //backtrack from the empty subtree and
//visit the node at the top of the stack;
//however, if the stack is empty, you are
//done
{
if (!s.empty())
{
cursor = s.top();
s.pop();
cout << cursor->data();
cursor = cursor->right();
}
}
}
}

Diameter of a Tree

2012-02-29T02:04:00.000+05:30

int Diameter(TreeNode t, int* height)
{
int lh = 0, rh = 0;
int leftD = 0, rightD = 0;

if(t == NULL)
{
*height = 0;
return 0; /* diameter is also 0 */
}

leftD = Diameter (root->left, &lh);
rightD = Diameter (root->right,&rh);

/* Height of current node is max of heights of left and
right subtrees plus 1*/
*height = max(lh, rh) + 1;

return max(lh + rh + 1, leftD, rightD);
}

2012-02-06T13:26:00.001+05:30

C,C++

2008-12-13T14:12:00.000+05:30

http://in.youtube.com/watch?v=hlzRCHASvsw

Virtusa Paper4

2008-04-18T22:02:00.000+05:30

1. x1 peach + y1 plum = z1 apple, x2 peach + y2 plum = z2 apple ,(x1,y1 .... z2 are integer values) How many peaches make one apple?

Here multiply both equation by y2 and y1 resply

(X₁peach +Y₁ pulm =Z₁ apple)Y₂

(X₂ peach + Y₂ pulm= Z₂ apple)Y₁

_{_____________________________________________}

X₁Y₂peach+ Y₁Y₂ pulm= Y₂Z₁apple

X₂Y₁peach+Y₁Y₂pulm=Y₁Z₂apple

Now sub both eq than common terms of plum will be cancelled

Then we get one Apple=(X₁Y₂-X₂Y₁/Z₁Y₂-Z₂Y₁)peach

2. 100,100,102,106,112,120,_130

Here the difference between each number increase by multiple of 2

100+0 and 100+2 and 102+4 .......

3. Which is greater ?Product of all Bradman's first class scores or Sum of all test scores of Sachin.

No data given

4. U r provided with 500ml and 300ml jar(it has no markings).
a) u have to measure exactly 100ml.

Jar 1(500) jar2(300)

Intial fill j2 0 300 (j2 to j1)

Pour in 300 0

Again fill j2 300 300(j2 to j1)

J1willbfull500 100(remain in j2)

b) u have to measure exactly 200ml.

Jar 1(500) jar2(300)

Intial fill j1 500 0 (j1 to j2)

J2 will be full 200 300

5. Using four 4's u have to make 1 ... 10. ( for eg. 1 = (4/4)*(4/4) 2 = ? 10 = ? )

(4-4)+(4/4)=1 or 44^(4-4)

(4*4)/(4+4)=2

(4+4+4)/4=3

Sqrt (4*4)+(4-4)=4

Sqrt (4*4)+(4/4)=5

Sqrt (4)*(4-(4/4))=6

(4+4)-(4/4)=7

(4+4)*(4/4)=8

(4+4)+(4/4)=9

(4*4)-(4+sqrt4)=10

6. student,canopy,thirst,... are the words given.u have to group the words using the following words
1)Master
2) Teacher
3) Deft
etc.

It is nothing but match the following

7. U have to cut a Pizza using 7 st. lines(wit out rearranging) and u have to obtain maximum number of pieces.( Give generalised solution..)

(2⁷)=128

8 A problem from sum of Alphabets are given numbers from 1 - 9 we hav to assign numbers to alphabets and A+B+C= something like that we have to know value of E

Question incomplete

9.In an exam consists of 150 questions, 50 questions are of mathematics and remaining are others. In which twice the time is to be given to mathematics bit when compared to others.total time is 3 hrs then how much time is to be given to each bit of mathematics?

Let x be the time taken by the other subjects then time taken maths is 2x

Then 50(2x)+100(x) =180

100x+100x=180

200x=180

X=9/10

Then time taken by the maths =2*9/10*60=108sec

10)In an multiple choice question paper, each correct answer carries 4 marks and each wrong answer deducts 2 marks. a person scores 480 marks in a 150 questions paper how many questions he did correctly?

Let the correct ans be x and wrong ans be y

Then X+Y=150 à(1)

And for 1 crt ans it carry 4mark and for 1 wrng it carry 2 mark

Then 4X-2Y=480à(2) then mul eq(1) with 2 and add with eq(2)

Then Y terms will be cancelled then we get eq as 6X=780 then X=130

11)A problem on work and time. A can do a work in 6 days B can do same work in 8 days, C can complete the same in 12 days.A under took 3 works like that and did for 8 days and left. Then B started work and did for some days and left then in how many days C completes this work?

No of day work by B is not given. If data is given we should have to submit in this formula m(a)+n(b)+o(c)=1

12)total M persons want to buy a gift of D Rs. Out of which 3 members are dropped out so how much each person have to pay extra ?

Let no.of rupees per head is =D/M

Now 3 members dropped ,no .of rupees per 3mem is =3(D/M)

Then this amount should be divided between rest of the members i.e. M-3

Then =3(D/M)/ (M-3)

=3D/M(M-3)

13)A monkey trying to ascend a greesy pole.He ascends 20 mtrs in one minute and goes down 4 mtrs in next minute.how much time it will take to ascend pole of 96 mtrs?

20 -1min

16-2min

36-3min

32-4min

52-5min

48-6min

68-7min

64-8min

84-9min

80-10min

96-10min 48sec

1min(60sec)-20mts

1sec=20/60=1/3mts

16mts remaining

Remaining time 16*3=48sec

14)On a good if 25% discount is given, he will earn profit of 25% what will be profit if he gives 10% discount?

S.P=0.75d

S.P=1.25c.p equating both

1.25c.p=0.75d

5c.p=3d à(1)

Xc.p=0.9d

c.p=0.9d*(5/3)d

c.p=1.5

so 50% is the profit.

15)A container has 64 lit of alcohol. 8 lit of which is removed and added with same amt of water. the same process is repeated 3times. what is the percentage of alcohol after the end of the
operations.
ans-

There is a direct formula

X(1-y/x)ⁿ

Where X is quantity present in the container

Y is quantity removed

n is no.of process

after the end of third operation is

=64(1-8/64)³

=42.875

16)x+y+z=0, find the value of (x**3+y**3+z**3)/xyz.

Formula of a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac)

If a+b+c=0 then a³+b³+c³=3abc

=(xyz)/ (xyz)

17)3 men n 2boys can do piece of work in 12 days. same work is done by 6men n 1 boy in 6 days. find how many days can a man alone can complete the work?

Here 3m+2b=1/12 à(1)

6m+1b=1/6 à(2)

Mul eq(2)with 2 and sub eq(1) from this

Then b will be cancelled

M=1/36

36 days

18)In an exam the maximum marks is 500. a got 20% more than b, b got 25% less than c, c got 20% more than d. if b marks are 360 then how much did d score? (no. r different prob type is the same.)

Here marks scored by B is given i.e 360 and we should have to take it as 100%(w.r.t B)and we should have to solve the problems

Now marks scored by A is 20%more than B then A=marks scored byB*1.2

A=360*1.2

=432

Marks scored by C is 25% more than B(since B score is 25%less than C means C is 25%more than B)

C=360*1.25

=450

For D we should have take ref of C, D=marks of C*0.8

=450*0.8

=360

18) Find the odd word
ALPHA
DELTA
SIGMA
BETA
Ans: Delta, Reason: as it has specific meaning(addition)and others don't

19)You are given a bunch of threads each having differing length. No two thereads have same thickness and no thread has same length. But it is certified that any thread when lit burns itself in exactly 12 mins. The question is you are asked to find an elapsed time of 9 minuites. How can u find it out and how many threads do u want for this?

Whatever may be the length and thickness the time taken by the thread to burn is 12min. Then take two threads T1,T2 lit T1on both sides and T2 on one side. After 6min T1will be completely burnt then lit theT2 which is half burnt in first 6min for another 3min T2will completely burns. Total time is 9 min.

20)How can u get 81 using the digits 2,3,25,50,75,100 only once using any of the arithmatic operator Key Steps: 50+(100/75*3)+25+2

Sol:(100/75) is (4/3) and multiplied by 3 then the ans is 4 and we should nave to add with other i.e.50+25+2+4=81

This type of question are repeatedly giving in every paper so be prepared to do such questions using all arithmetic operators.

21)one question from series

22)one question from venndiagram

23)Attention to details:
In this section, some questions like the following are given--
if $ represents 1 n * represents 0; then wt is the value ****$$$$

Whatever they may give just see what is given to 0 and1 and don’t concentrate on other i.e. other will be double to 2 means $* and for 3 $$ like that...

Some examples are 0 is denoted as * and 1 as @

Or 0 is denoted as * and 1 as $ all these are in binary form

****$$$$ here $=1 and 0=* convert it into binary form i.e.

00001111=15

Tech Mahendra Solved Paper

2008-04-17T20:22:00.000+05:30

ARITHMETIC SECTION

This section consists of 29 problems. The questions are simple though time consuming.

1. If a boat is moving in upstream with velocity of 14 km/hr and goes downstream with a velocity of 40 km/hr, then what is the speed of the stream ?

(a) 13 km/hr
(b) 26 km/hr
(c) 34 km/hr
(d) none of these

Ans: A

Let speed of Boat be ‘x’, and speed of stream ‘y’.

When boat moves upstream overall speed is 14 .Equation is x-y=14.For downstream equation is

x+y=40. On solving these 2 equations,we get x as 27 and y as 13. Ans is 13

.

2. Find the value of ( 0.75 * 0.75 * 0.75 - 0.001 ) / ( 0.75 * 0.75 - 0.075 + 0.01)

(a) 0.845
(b) 1.908
(c) 2.312
(d) 0.001

Ans: A

I did not find any shortcut.Just calculate the values.

3. A can have a piece of work done in 8 days, B can work three times faster than the A, C can work five times faster than A. How many days will they take to do the work together ?

(a) 3 days
(b) 8/9 days
(c) 4 days
(d) can,t say

Ans: B

A’s one day’s work----> 1/8

B works 3 times faster .Therefore B’s one day’s work------- > 3/8

C works 5 times faster.Therefore C’s one day’s work------- >5/8

A+B+C=1/8 + 3/8 + 5/8=(1+3+5)/8=9/8

Therefore they will take 8/9 days.

4. A car travels a certain distance taking 7 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 5 hrs.What is the distance travelled

(a) 210 kms
(b) 30 kms
(c) 20 kms
(c) none of these

Ans: B.

Let distance be x kms.During forward journey speed is x/7(bcoz time is 7 hrs)
during return journey speed is increased by 12 kms.Therefore speed in return becomes x/7+12

Equate the distances during return and forward journeys

X=(x/7+12)*5

On solving x=30.i.e.,distance travelled in return journey is 30 kms.
5. Instead of multiplying a number by 7, the number is divided by 7. What is the percentage of error obtained ?

Let the no. be x.if it is multiplied with 7 result is 7x. But it is divided by 7 and the result is x/7,

Percentage error is( 7x-x/7)/(x/7)*100

On solving it comes as 4800%.

Another approach: Ttake 7 as our no.if it is multiplied with 7 it becomes 49,

But it is divided by 7 and it becomes 1.

Percentage error is ((49-1)/1)*100=4800%.

6. Find (7x + 4y ) / (x-2y) if x/2y = 3/2 ?

(a) 6
(b) 8
(c) 7 Ans:25
(d) data insufficient

x/2y=3/2--------- >x=3y. Substitute in above eqn

7(3y) + 4y/(3y-2y)=25y/y=25

7. A man buys 12 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 10 lts of another mixture with 30% of liquid.What is the % of water in the new mixture?
Ans :

In 12 lts of liquid 20% is liquid and 80% is water.i.e., 9.6 lts is water

In 10 lts 70% is water i.e., 7 lts of water.

When they are mixed total volume becomes 12+10=22lts and water content becomes 9.6 + 7=16.6 lts.

Percent of water in mixture is 16.6/22 * 100=75.45%.
8. If a man buys 1 lt of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain?

Here the mixing of 20% water is just given to confuse us.

c.p=12 s.p=15 ------> gain%= (15-12)/12 * 100=25%

9. Pipe A can fill a tank in 30 mins and Pipe B can fill it in 28 mins.If 3/4th of the tank is filled by Pipe B alone and both are opened, how much time is required by both the pipes to fill the tank completely ?

work done by both pipes is 1/28 + 1/30=29/420

they take 420/29 mins to completely fill d tank.

Given that 3/4^th of tank is already filled.therefore 1/4^th is to be filled by both pipes.

420/29mins---- > 1(tank)-------eqn1

? mins------- > 1/4^th tank

Divide by 4 on both sides of eqn 1

420/(29*4) mins-----à ¼ tank

105/29 mins= 3.62 mins

10. If on an item a company gives 25% discount, they earn 25% profit. If they now give 10% discount then what is the profit percentage.

(a) 40%
(b) 55%
(c) 35%
(d) 30%

Ans: D

11. A certain number of men can finish a piece of work in 10 days. If however there were 10 men less it will take 10 days more for the work to be finished. How many men were there originally?

(a) 110 men
(b) 130 men
(c) 100 men
(d) none of these

Ans: A

12. In simple interest what sum amounts of Rs.1120/- in 4 years and Rs.1200/- in 5 years ?

(a) Rs. 500
(b) Rs. 600
(c) Rs. 800
(d) Rs. 900

Ans: C

Simple interest for 1 year=1200 – 1120=80

Therefore principal amount= 1120 – (4*80)= 1120 -320 =800

13. If a sum of money compound annually amounts of thrice itself in 3 years. In how many years
will it become 9 times itself.

(a) 6
(b) 8
(c) 10
(d) 12

Ans A

Let the principal amount be Rs. X

Amount after 3 years

3x=x(1+(r/100))^3

On solving r = (3^(1/3) – 1) * 100.

Amount after y years

9x=x(1 + (3^(1/3)-1)*100/100)^y

On solving above eqns

9 = (3)^(1/3)^y

3^2 = 3 ^ (y/3)

-------- > y=6 years

14. Two trains move in the same direction at 50 kmph and 32 kmph respectively. A man in the slower train
observes the 15 seconds elapse before the faster train completely passes by him.
What is the length of faster train ?

(a) 100m
(b) 75m
(c) 120m
(d) 50m

Ans

Given data is insufficient

However the eqn is 15/(60*60)= (l1+ l2)/(50 – 32).Here either l1 or l2 should have been given.

15. How many mashes are there in 1 squrare meter of wire gauge if each mesh
is 8mm long and 5mm wide ?

(a) 2500
(b) 25000
(c) 250
(d) 250000

Ans B

I square meter=(100cm) * (100cm) (since 1m=100cm)=(100*10mm) * (100 * 10mm) (since 1cm=10mm)

1 sq.mt=1000*1000 sq.mm

Each mesh is 8*5 sq.mm=40 sq.mm
no. of meshes in I sq.mt area is = (1000 * 1000)/40 =25000.
16. x% of y is y% of ?

(a) x/y
(b) 2y
(c) x
(d) can,t be determined

Ans: C

Here x % of y is x/100 * y = xy/100.

And y % is y/100. With what value should it be multiplied so that result becomes xy/100.

Its obviously x. Ans is x.

17. The price of sugar increases by 20%, by what % should a housewife reduce the consumption of sugar so that expenditure on sugar can be same as before ?

(a) 15%
(b) 16.66%
(c) 12%
(d) 9%

Ans B

Formula is r/(r+100) * 100= 20 /(100+20) * 100=16.66%

18. A man spends half of his salary on household expenses, 1/4th for rent, 1/5th for travel expenses, the man deposits the rest in a bank. If his monthly deposits in the bank amount 50, what is his monthly salary ?

(a) Rs.500
(b) Rs.1500
(c) Rs.1000
(d) Rs. 900

Ans C
Let monthly salary be x

Total amount spent = x/2 (household) + x/4(rent) + (x/5) (travel)=19x/20

Amount remaining is x/20=50 -------- > x=1000.

20. The population of a city increases @ 4% p.a. There is an additional annual increase of 4% of the population due to the influx of job seekers, find the % increase in population after 2 years ?

Ans: Let initial pop. be x. each year it increases by 4 + 4 += 8%
At the end of 1 year the pop. becomes 1.08x

At the end of 2 years the pop. becomes 1.08 * 1.08x

Percent increase is (1.08 * 1.08x )- x/x * 100 = 1.1664x-x/x * 100 = 16.64% increase

Ans is 16.64 %

21. The ratio of the number of boys and girls in a school is 3:2 Out of these 10% the boys and 25% of girls are scholarship holders. % of students who are not scholarship holders.?

Let the no. of boys and girls be 100. Given ratio is 3:2 . Boys are 60 and girls 40.

90% boys + 75% girls are not scholarship holders = 54 + 30 = 84

Ans is 84%.

22. 15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 6 hrs. each would it take for 21 women if 3 women do as much work as 2 men?

(a) 30
(b) 20
(c) 19
(d) 29

Ans: A

Formula is men 1* days1 * hr1/w = men2 * days2 * hrs2/w (since work is same)

No. of men1=15 , days1 = 21 , hrs1 = 8

Given 21 women and 3women = 2 men . It implies 1 women = 2 / 3 men . Therefore, 21 women = 2/3 * 21 men = 14 men . hence men2 is 14

Hrs 2 =6 and days2=?

Subst. above values in the above eqn --à 15 * 21 * 8/w = 14 * 6 * d2/w

On solving d2=30

.
23. A cylinder is 6 cms in diameter and 6 cms in height. If 2 spheres of the same size are made from the material obtained, what is the diameter of each sphere?

(a) 5 cms
(b) 2 cms
(c) 3 cms
(d) 4 cms

Ans C

Given Data is not correct. But The approach is equate volumes of spheres and cylinders

Volume of cylinder = pi * r * r *h and volume of sphere = 4/3 * pi * r*r*r.

-------- > pi* 3* 3*6 = 4/3 * pi * r*r*r*x (where x is no. of spheres)
Here x should be given to find r.

24. A rectangular plank (2)1/2 meters wide can be placed so that it is on either side of the diagonal of a square shown below.(Figure is not available)What is the area of the plank?

Ans :7*(2)1/2

Diagram is required to solve this question.

25. The difference b/w the compound interest payble half yearly and the simple interest on a
certain sum lent out at 10% p.a for 1 year is Rs 25. What is the sum?

(a) Rs. 15000
(b) Rs. 12000
(c) Rs. 10000
(d) none of these

Ans C

Formula is C.I – S.I =25

Let p be the principal amount

( P( 1+((r/2)/100))^2 - p) – (p * 1 * 10)/100 = 25

On solving p=10000.

26. What is the smallest number by which 2880 must be divided in order to make it into a
perfect square ?

(a) 3
(b) 4
(c) 5
(d) 6

Ans: C

Just substitute d answers and see that the result is a perfect square. For 5 its 576.

27. A father is 30 years older than his son however he will be only thrice as old as the son after 5 years
what is father,s present age ?

(a) 40 yrs
(b) 30 yrs
(c) 50 yrs
(d) none of these

Ans: A
Let father’s age be f and son’s be y.

F= s + 30-----à1 eqn

F+5 = 3 (s + 5)------- > eqn 2

On solving above eqns fathers age = 40 years.

28. An article sold at a profit of 20% if both the cost price and selling price would be Rs.20/-,the profit would be 10% more. What is the cost price of that article?

I think this question is wrong.

29. If an item costs Rs.3 in ,99 and Rs.203 in ,00.What is the % increase in price?

(a) 200/3 %
(b) 200/6 %
(c) 100%
(d) none of these

Ans: A

It is v.v.v simple

(203-3 )/3 * 100 =200/3 %
LOGICAL SECTION

Directions: For questions 30-39 fill the missing number or letter in the given series

30. a, c, e, g, _

(a) h
(b) i
(c) d
(d) j

Ans: B

31. a, e, i, m, q, u, _, _

(a) y,c
(b) b,f
(c) g,i
(d) none

Ans: A

32. ay , bz , cw , dx ,__

(a) gu
(b) ev
(c) fv
(d) eu

Ans: D

33. 1, 2, 3, 5, 7, 11, __

(a) 15
(b) 9
(c) 13
(d) 12

Ans: C (series of prime numbers)

34. kp , lo , mn , __

(a) nm
(b) np
(c) op
(d) pq

Ans: A

35. R,M,__,F,D,__

(a) I, C
(b) A, Q
(c) L, N
(d) B, Q

Ans: A

36. ___, ayw, gec, mki, sqo

(a) awx
(b) usq
(c) prs
(d) lmn

Ans: B

37. 1, 3, 4, 8, 15, 27, __

(a) 60
(b) 59
(c) 43
(d) 50

Ans D

No=sum of previous 3 no.s ------ > 4=3+1,8=4+3+1,15=8+4+3,27=15+8+4,27+15+8=50.

38. 0, 2, 3, 5, 8, 10, 15, 17, 24, 26,__

(a) 45
(b) 55
(c) 35
(d) 48

Ans: C

39. 2, 5, 9, 19, 37,__

(a) 64
(b) 55
(c) 75
(d) 40

Ans C

Double + 1,double – 1 alternatively

37*2+1=75

Directions for questions 40 to 45: Select the alternative that logically follows form the two given statements.

These syllogisms are very easy.Just the table given by Narsimha sir should be remembered.
40. All scientists are fools. All fools are literates.

(a)All literates are scientists
(b) All scientists are literates
(c) No scientists are literates
(d) Both (a) and (b) are correct

Ans: B

41. No apple is an orange. All bananas are oranges.

(a) All apples are oranges
(b) Some apples are oranges
(c) No apple is a banana
(d) None of the above

Ans: A

42. All pens are elephants. Some elephants are cats.

(a) Some pens are cats
(b) No pens are cats
(c) All pens are cats
(d) None of the above

Ans: D

43. All shares are debentures.No debentures are deposits.

(a) All shares are deposits
(b) Some shares are deposits
(c) No shares are deposits
(d) None of the above

Ans: C

44. Many fathers are brothers. All brothers are priests.

(a) No father is a priest
(b) Many fathers are not priests
(c) Many fathers are priests
(d) Both (b) and (c)

Ans: B

45. Some green are blue. No blue are white.

(a) No green are white
(b) Some green are white
(c) No green are white
(d) None of the above

Ans: B

46. If the word "CODING" is represented as DPEJOH , then the word "CURFEW" can be represented?

(a) dvsgfx
(b) dvshfx
(c) dgshfx
(d) dtsgfy

Ans: A

47. If in a certain code "RANGE" is coded as 12345 and "RANDOM" is coded as 123678, then the code for the word "MANGO" would be

(a) 82357
(b) 84563
(c) 82346
(d) 82543

Ans: D

Directions for questions 48-50:The questions are based on the following data

In a class of 150 students 55 speak English;85 speak Telugu and 30 speak neither English nor Telugu

There are 150 students out of which 30 don’t speak any language .Therefore total students any one of the languages is 120.

N(E u T) = n(E) + n(T) – n(E and T)

120 = 55 + 85 –n( E and T)

N( E and T)=20.

48. How many speak both English and Telugu?

(a) 10
(b) 15
(c) 20
(d) 12

Ans: C

49.How many speak only Telugu?

(a) 55
(b) 45
(c) 65
(d) none of the above

Ans:C

50.How many speak at least one of the two languages?

(a) 120
(b) 100
(c) 250
(d) 50

Ans: A

Refer R.S Agarwal books for more questions of the same kind
Verbal -- Page 254 problems 53 to56
246 eg.2
Page 104 Exercise.3a (Series Questions)
Page 354-355 8,13,
Page 115

Nonverbal -- Pages 5,41,54,108,145,158