<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:blogger='http://schemas.google.com/blogger/2008' xmlns:georss='http://www.georss.org/georss' xmlns:gd="http://schemas.google.com/g/2005" xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-4651990009734372491</id><updated>2024-09-12T04:30:33.783-07:00</updated><category term="squaring"/><category term="dividing"/><category term="multiplying"/><title type='text'>flash math</title><subtitle type='html'>how to make math easier and funny</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default?redirect=false'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>16</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-8151481476301459781</id><published>2008-10-11T18:08:00.001-07:00</published><updated>2008-10-11T18:08:41.380-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="squaring"/><title type='text'>Squaring a 2-digit Number Ending in 5</title><content type='html'>STEPS&lt;br /&gt;&lt;br /&gt;Choose a 2-digit number ending in 5.&lt;br /&gt;Multiply the first digit by the next consecutive number.&lt;br /&gt;The product is the first two digit: XX__.&lt;br /&gt;The last part of the answer is always 25: __25.&lt;br /&gt;&lt;br /&gt;Example&lt;br /&gt;&lt;br /&gt;If the number is 35, 3 x 4 = 12 (first digit times next number) : 12__&lt;br /&gt;The last part of the answer is always 25: __25.&lt;br /&gt;So  35 x 35 = 1225</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/8151481476301459781/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/10/squaring-2-digit-number-ending-in-5.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8151481476301459781'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8151481476301459781'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/10/squaring-2-digit-number-ending-in-5.html' title='Squaring a 2-digit Number Ending in 5'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-8851968375219596818</id><published>2008-09-01T18:54:00.001-07:00</published><updated>2008-09-01T18:54:59.642-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="squaring"/><title type='text'>Squaring a 2-digit number ending in 4</title><content type='html'>Steps&lt;br /&gt;take a 2 digit number ending in 4.&lt;br /&gt;square the 4; the last digit is 6: ___6 (keep carry, 1).&lt;br /&gt;multiply the first digit by 8 and add the carry (1); the secondnumber will be the next to the last digit: __X6 (keep carry).&lt;br /&gt;square the first digit and add the carry: XX__.&lt;br /&gt;&lt;br /&gt;Example&lt;br /&gt;if the number is 34, 4 x 4 =16 (keep carry, 1); the last digit is ___6.&lt;br /&gt;8 x 3 = 24 (multiply the first digit by 8), 24 + 1 = 25 (add the carry): the next digit is 5: __56. (keep carry, 2).&lt;br /&gt;square the first digit and add the carry, 2: 1156.&lt;br /&gt;so 34 x 34 =1156.</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/8851968375219596818/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/09/squaring-2-digit-number-ending-in-4.html#comment-form' title='2 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8851968375219596818'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8851968375219596818'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/09/squaring-2-digit-number-ending-in-4.html' title='Squaring a 2-digit number ending in 4'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-4823108094215733049</id><published>2008-08-29T18:52:00.001-07:00</published><updated>2008-08-29T18:52:28.256-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="squaring"/><title type='text'>Squaring a 2-digit ending in 3</title><content type='html'>Steps&lt;br /&gt;take a 2-digit number ending in 3.&lt;br /&gt;the last digit will be ___9.&lt;br /&gt;multiply the first digit by 6: the second number will be the next to the last digit: __X9.&lt;br /&gt;square the first digit and add the number carried from the previous step: XX__.&lt;br /&gt;&lt;br /&gt;Example&lt;br /&gt;if the number is 43, the last digit&lt;br /&gt;is ___9.&lt;br /&gt;6 x 4 = 24: __49.&lt;br /&gt;4 x 4 = 16, 16 + 2 = 18 (add carry): 1849. &lt;br /&gt;so 43 x 43 = 1849</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/4823108094215733049/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/08/squaring-2-digit-ending-in-3.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/4823108094215733049'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/4823108094215733049'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/08/squaring-2-digit-ending-in-3.html' title='Squaring a 2-digit ending in 3'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-8015442021114328139</id><published>2008-08-29T18:36:00.001-07:00</published><updated>2008-08-29T18:36:10.857-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="squaring"/><title type='text'>Squaring a 2-digit number ending in 2</title><content type='html'>Steps&lt;br /&gt;take a 2-digit number ending in 2.&lt;br /&gt;the last digit will be ___4.&lt;br /&gt;multiply the first digit by 4: the second number will be the next to the last digit: __X4.&lt;br /&gt;square the first digit and add the number carried from the previous step: XX__.&lt;br /&gt;&lt;br /&gt;Example&lt;br /&gt;if the number is 52, the last digit is ___4.&lt;br /&gt;4 x 5 = 20 : __04.&lt;br /&gt;5 x 5 = 25, 25 + 2 = 27 (add carry): 2704.&lt;br /&gt;so 52 x 52 = 2704.</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/8015442021114328139/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/08/squaring-2-digit-number-ending-in-2.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8015442021114328139'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8015442021114328139'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/08/squaring-2-digit-number-ending-in-2.html' title='Squaring a 2-digit number ending in 2'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-4534851733384634247</id><published>2008-08-02T20:15:00.001-07:00</published><updated>2008-08-02T20:15:55.671-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="squaring"/><title type='text'>SQUARING a 2-DIGIT NUMBER ENDING IN 1</title><content type='html'>STEPS&lt;br /&gt;&lt;br /&gt;take a-2 digit number ending in 1.&lt;br /&gt;substract 1 from the number.&lt;br /&gt;square the difference.&lt;br /&gt;add the difference twice to its square.&lt;br /&gt;add 1.&lt;br /&gt;&lt;br /&gt;EXAMPLE&lt;br /&gt;&lt;br /&gt;If the number is 41, substract 1 : 41-1=40.&lt;br /&gt;40 x 40 = 1600 ( square the difference ).&lt;br /&gt;1600 + 40 + 40 =1680 ( add the difference twice to its square ).&lt;br /&gt;1680 + 1 = 1681 ( add 1 ).&lt;br /&gt;so 41 x 41 = 1681</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/4534851733384634247/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/08/squaring-2-digit-number-ending-in-1.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/4534851733384634247'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/4534851733384634247'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/08/squaring-2-digit-number-ending-in-1.html' title='SQUARING a 2-DIGIT NUMBER ENDING IN 1'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-2221560087572590524</id><published>2008-06-07T23:10:00.000-07:00</published><updated>2008-08-02T20:20:49.088-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="dividing"/><title type='text'>Dividing a 2-digit number by 1 1/7</title><content type='html'>STEPS&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Select a 2-digit number.     &lt;/li&gt;&lt;li&gt;Multiply it by 7.     &lt;/li&gt;&lt;li&gt;Divide the product by 8.    &lt;/li&gt;&lt;/ol&gt;    &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;The number chosen to divide by 1 1/7 is &lt;b&gt;26&lt;/b&gt;.     &lt;/li&gt;&lt;li&gt;Multiply by 7: 7 × 26 = 140 + 42 = 182     &lt;/li&gt;&lt;li&gt;Divide by 8: 182/8 = 22 3/4     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;26 divided by 1 1/7 = 22 3/4&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;The number chosen to divide by 1 1/7 is &lt;b&gt;61&lt;/b&gt;.     &lt;/li&gt;&lt;li&gt;Multiply by 7: 7 × 61 = 427     &lt;/li&gt;&lt;li&gt;Divide by 8: 427/8 = 53 3/8     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;61 divided by 1 1/7 = 53 3/8&lt;/b&gt;&lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/2221560087572590524/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/dividing-2-digit-number-by-1-17.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/2221560087572590524'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/2221560087572590524'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/dividing-2-digit-number-by-1-17.html' title='Dividing a 2-digit number by 1 1/7'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-6969712818329074779</id><published>2008-06-07T23:09:00.000-07:00</published><updated>2008-08-02T20:23:01.091-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="dividing"/><title type='text'>Dividing a 2-digit number by 1 1/8</title><content type='html'>STEPS&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Select a 2-digit number.     &lt;/li&gt;&lt;li&gt;Multiply by 8.     &lt;/li&gt;&lt;li&gt;Divide the result by 9.    &lt;/li&gt;&lt;/ol&gt;    &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;The 2-digit number chosen to divide by 1 1/8 is &lt;b&gt;42&lt;/b&gt;.     &lt;/li&gt;&lt;li&gt;Multiply by 8: 8 × 42 = 320 + 16 = 336     &lt;/li&gt;&lt;li&gt;Divide by 9: 336/9 = 37 1/3     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;42 divided by 1 1/8 = 37 1/3&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;The 2-digit number chosen to divide by 1 1/8 is &lt;b&gt;71&lt;/b&gt;.     &lt;/li&gt;&lt;li&gt;Multiply by 8: 8 × 71 = 568     &lt;/li&gt;&lt;li&gt;Divide by 9: 568/9 = 63 1/9     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;71 divided by 1 1/8 = 63 1/9&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/6969712818329074779/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/dividing-2-digit-number-by-1-18.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/6969712818329074779'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/6969712818329074779'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/dividing-2-digit-number-by-1-18.html' title='Dividing a 2-digit number by 1 1/8'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-8964223232855342915</id><published>2008-06-07T23:08:00.000-07:00</published><updated>2008-08-02T20:23:51.324-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="dividing"/><title type='text'>Dividing a number by 0.125</title><content type='html'>steps&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Select a number.     &lt;/li&gt;&lt;li&gt;Multiply it by 8.    &lt;/li&gt;&lt;/ol&gt;    &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;The number chosen to divide by 0.125 is &lt;b&gt;21&lt;/b&gt;.     &lt;/li&gt;&lt;li&gt;Multiply it by 8: 8 × 21 = 168.     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;21 divided by 0.125 = 168&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;The 2-digit number chosen to divide by 1/8 is &lt;b&gt;68&lt;/b&gt;.     &lt;/li&gt;&lt;li&gt;Multiply it by 8: 8 × 68 = 480 + 64 = 544.     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;68 divided by 0.125 = 544&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/8964223232855342915/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/dividing-number-by-0125.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8964223232855342915'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8964223232855342915'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/dividing-number-by-0125.html' title='Dividing a number by 0.125'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-1183777054609229579</id><published>2008-06-07T23:07:00.000-07:00</published><updated>2008-08-02T20:24:49.993-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="dividing"/><title type='text'>Dividing a 2-digit number by 1 1/9</title><content type='html'>steps&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Select a 2-digit number.     &lt;/li&gt;&lt;li&gt;Multiply by 9.     &lt;/li&gt;&lt;li&gt;Move the decimal point one place to the left.    &lt;/li&gt;&lt;/ol&gt;    &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;The 2-digit number chosen to divide by 1 1/9 is &lt;b&gt;24&lt;/b&gt;.     &lt;/li&gt;&lt;li&gt;Multiply by 9: 9 × 24 = 180 + 36 = 216     &lt;/li&gt;&lt;li&gt;Move the decimal point one place to the left: 21.6     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;24 divided by 1 1/9 = 21.6&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;The 2-digit number chosen to divide by 1 1/9 is &lt;b&gt;91&lt;/b&gt;.     &lt;/li&gt;&lt;li&gt;Multiply by 9: 9 × 91 = 819     &lt;/li&gt;&lt;li&gt;Move the decimal point one place to the left: 81.9     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;91 divided by 1 1/9 = 81.9&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/1183777054609229579/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/dividing-2-digit-number-by-1-19.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/1183777054609229579'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/1183777054609229579'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/dividing-2-digit-number-by-1-19.html' title='Dividing a 2-digit number by 1 1/9'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-3617730828253132358</id><published>2008-06-07T23:06:00.000-07:00</published><updated>2008-08-02T20:27:16.044-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="multiplying"/><title type='text'>Multiplying two selected 3-digit numbers</title><content type='html'>steps&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Select a 3-digit number with a middle digit of 0.     &lt;/li&gt;&lt;li&gt;Choose a multiplier with the same first two digits, whose third digit sums to     10 with the third digit of the first 3-digit number.     &lt;/li&gt;&lt;li&gt;The first digit(s) will be the square of the first digit:&lt;br /&gt;    X _ _ _ _ or X X _ _ _ _.     &lt;/li&gt;&lt;li&gt;The next digit will be the first digit of the numbers:&lt;br /&gt;    _ X _ _ _ or _ _ X _ _ _.     &lt;/li&gt;&lt;li&gt;The next digit is zero: _ _ 0 _ _ or _ _ _ 0 _ _.     &lt;/li&gt;&lt;li&gt;The last two digits will be the product of the third digits:&lt;br /&gt;    _ _ _ X X or _ _ _ _ X X.    &lt;/li&gt;&lt;/ol&gt;    &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;If the first number is &lt;b&gt;407&lt;/b&gt;, choose &lt;b&gt;403&lt;/b&gt; as the second number (same     first digits, second digits add to 10).     &lt;/li&gt;&lt;li&gt;4 × 4 = 16 (square the first digit): 1 6 _ _ _ _.     &lt;/li&gt;&lt;li&gt;The next digit will be the first digit of the numbers:&lt;br /&gt;    _ _ 4 _ _ .     &lt;/li&gt;&lt;li&gt;The next digit is zero: _ _ 0 _ _ .     &lt;/li&gt;&lt;li&gt;7 × 3 = 21 (the last two digits will be the product of the third digits: _ _     _ 2 1.     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;407 × 403 = 164021&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;If the first number is &lt;b&gt;201&lt;/b&gt;, choose &lt;b&gt;209&lt;/b&gt; as the second number (same     first digits, second digits add to 10).     &lt;/li&gt;&lt;li&gt;2 × 2 = 4 (square the first digit): 4 _ _ _ _.     &lt;/li&gt;&lt;li&gt;The next digit will be the first digit of the numbers:&lt;br /&gt;    _ 2 _ _ _ .     &lt;/li&gt;&lt;li&gt;The next digit is zero: _ _ 0 _ _ .     &lt;/li&gt;&lt;li&gt;1 × 9 = 09 (the last two digits will be the product of the third digits: _ _     _ 0 9.     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;201 × 209 = 42009&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/3617730828253132358/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/multiplying-two-selected-3-digit.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/3617730828253132358'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/3617730828253132358'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/multiplying-two-selected-3-digit.html' title='Multiplying two selected 3-digit numbers'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-3513734233556704860</id><published>2008-06-07T23:05:00.000-07:00</published><updated>2008-08-02T20:28:12.902-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="multiplying"/><title type='text'>Multiplying two 2-digit numbers</title><content type='html'>steps&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Both numbers should have the same second digit.     &lt;/li&gt;&lt;li&gt;Choose first digits whose sum is 10.     &lt;/li&gt;&lt;li&gt;Multiply the first digits and add one second: X X _ _.     &lt;/li&gt;&lt;li&gt;Multiply the second digits together: _ _ X X.    &lt;/li&gt;&lt;/ol&gt;    &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;If the first number is &lt;b&gt;67&lt;/b&gt;, choose &lt;b&gt;47&lt;/b&gt; as the second number (same     second digit, first digits add to 10).     &lt;/li&gt;&lt;li&gt;Multiply the 1st digits, add one 2nd.&lt;br /&gt;    6x4 = 24, 24+7 = 31. 3 1 _ _     &lt;/li&gt;&lt;li&gt;Multiply the 2nd digits. 7x7 = 49 _ _ 4 9     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;67 × 47 = 3149&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;If the first number is &lt;b&gt;93&lt;/b&gt;, choose &lt;b&gt;13&lt;/b&gt; as the second number (same     second digit, first digits add to 10).     &lt;/li&gt;&lt;li&gt;Multiply the 1st digits, add one 2nd. 9x1 = 9, 9+3 = 12.&lt;br /&gt;    1 2 _ _     &lt;/li&gt;&lt;li&gt;Multiply the 2nd digits. 3x3 = 9 _ _ 0 9     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;93 × 13 = 1209&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/3513734233556704860/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/multiplying-two-2-digit-numbers_9576.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/3513734233556704860'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/3513734233556704860'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/multiplying-two-2-digit-numbers_9576.html' title='Multiplying two 2-digit numbers'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-8011985551230165125</id><published>2008-06-07T23:03:00.000-07:00</published><updated>2008-08-02T20:29:11.018-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="multiplying"/><title type='text'>Multiplying two 2-digit numbers</title><content type='html'>steps&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Select two 2-digit numbers with the same first digit.     &lt;/li&gt;&lt;li&gt;Multiply their second digits (keep the carry).   _ _ _ X     &lt;/li&gt;&lt;li&gt;Multiply the sum of the second digits by the first digit,&lt;br /&gt;    add the carry (keep the carry).   _ _ X _     &lt;/li&gt;&lt;li&gt;Multiply the first digits (add the carry).   X X _ _    &lt;/li&gt;&lt;/ol&gt;    &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;If the first number is &lt;b&gt;42&lt;/b&gt;, choose &lt;b&gt;45&lt;/b&gt; as the second number (any     2-digit number with first digit 4).     &lt;/li&gt;&lt;li&gt;Multiply the last digits: 2 × 5 = 10 (keep carry)  &lt;br /&gt;    _ _ _ 0     &lt;/li&gt;&lt;li&gt;Multiply the sum of the 2nd digits by the first:&lt;br /&gt;    5 + 2 = 7; 7 × 4 = 28; 28 + 1 = 29 (keep carry)  &lt;br /&gt;    _ _ 9 _     &lt;/li&gt;&lt;li&gt;Multiply the first digits (add the carry)&lt;br /&gt;    4 × 4 = 16; 16 + 2 = 18                              &lt;br /&gt;    1 8 _ _&lt;br /&gt;    &lt;br /&gt;         &lt;/li&gt;&lt;li&gt;So &lt;b&gt;42 × 45 = 1890&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;If the first number is &lt;b&gt;62&lt;/b&gt;, choose &lt;b&gt;67&lt;/b&gt; as the second number&lt;br /&gt;    (any 2-digit number with first digit 6).     &lt;/li&gt;&lt;li&gt;Multiply the last digits: 2 × 7 = 14 (keep carry)  &lt;br /&gt;    _ _ _ 4     &lt;/li&gt;&lt;li&gt;Multiply the sum of the 2nd digits by the first (add carry):&lt;br /&gt;    2 + 7 = 9; 6 × 9 = 54; 54 + 1 = 55 (keep carry)  &lt;br /&gt;    _ _ 5 _     &lt;/li&gt;&lt;li&gt;Multiply the first digits (add the carry)&lt;br /&gt;    6 × 6 = 36; 36 + 5 = 41                              &lt;br /&gt;    4 1 _ _&lt;br /&gt;    &lt;br /&gt;         &lt;/li&gt;&lt;li&gt;So &lt;b&gt;62 × 67 = 4154&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/8011985551230165125/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/multiplying-two-2-digit-numbers_07.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8011985551230165125'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8011985551230165125'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/multiplying-two-2-digit-numbers_07.html' title='Multiplying two 2-digit numbers'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-6755951671214223849</id><published>2008-06-07T23:00:00.000-07:00</published><updated>2008-08-02T20:30:04.209-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="multiplying"/><title type='text'>Multiplying two 2-digit numbers</title><content type='html'>steps&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Both numbers should have the same first digit।     &lt;/li&gt;&lt;li&gt;Choose second digits whose sum is 10.     &lt;/li&gt;&lt;li&gt;Multiply the first digit by one number greater than itself; this number will     be the first part of the answer:&lt;br /&gt;    X X _ _.     &lt;/li&gt;&lt;li&gt;Multiply the two second digits together; the product&lt;br /&gt;    will be the last part of the answer: _ _ X X.    &lt;/li&gt;&lt;/ol&gt;      &lt;blockquote&gt;    &lt;p&gt;Note: If the two second digits are 1 and 9 (or, more generally, have a product    that is less than ten), insert a 0 (zero) for the first X in step 4.&lt;/p&gt;     &lt;p&gt;(Thanks to Michael Richardson, age 10, for this note.)     &lt;/p&gt;&lt;/blockquote&gt;     &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;If the first number is &lt;b&gt;47&lt;/b&gt;, choose &lt;b&gt;43&lt;/b&gt; as the second number (same     first digit, second digits add to 10).     &lt;/li&gt;&lt;li&gt;4 × 5 = 20 (multiply the first digit by one number greater than itself): the     first part of the answer is&lt;br /&gt;    2 0 _ _.     &lt;/li&gt;&lt;li&gt;7 × 3 = 21 (multiply the two second digits together); the last part of the answer     is _ _ 2 1.     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;47 × 43 = 2021&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;If the first number is &lt;b&gt;62&lt;/b&gt;, choose &lt;b&gt;68&lt;/b&gt; as the second number (same     first digit, second digits add to 10).     &lt;/li&gt;&lt;li&gt;6 × 7 = 42 (multiply the first digit by one greater), the first part of the answer     is 4 2 _ _.     &lt;/li&gt;&lt;li&gt;2 × 8 = 16 (multiply the two second digits together); the last part of the answer     is _ _ 1 6.     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;62 × 68 = 4216&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/6755951671214223849/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/multiplying-two-2-digit-numbers.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/6755951671214223849'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/6755951671214223849'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/06/multiplying-two-2-digit-numbers.html' title='Multiplying two 2-digit numbers'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-7595406916874525904</id><published>2008-05-27T23:32:00.000-07:00</published><updated>2008-08-02T20:34:53.316-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="squaring"/><title type='text'>Squaring a 2-digit number beginning with 9</title><content type='html'>steps&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Take a 2-digit number beginning with 9.     &lt;/li&gt;&lt;li&gt;Subtract it from 100.     &lt;/li&gt;&lt;li&gt;Subtract the difference from the original number:&lt;br /&gt;    this is the first part of the answer.     &lt;/li&gt;&lt;li&gt;Square the difference: this is the last part of the answer.    &lt;/li&gt;&lt;/ol&gt;    &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;If the number is &lt;b&gt;96&lt;/b&gt;, subtract: 100 - 96 = 4, 96 - 4 = 92.     &lt;/li&gt;&lt;li&gt;The first part of the answer is 92 _ _ .     &lt;/li&gt;&lt;li&gt;Take the first difference (4) and square it: 4 × 4 = 16.     &lt;/li&gt;&lt;li&gt;The last part of the answer is _ _ 16.     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;96 × 96 = 9216&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;For 98 × 98, subtract: 100 - 98 = 2, 98 - 2 = 96.     &lt;/li&gt;&lt;li&gt;The first part of the answer is 96 _ _.     &lt;/li&gt;&lt;li&gt;Take the first difference (2) and square it: 2 × 2 = 4.     &lt;/li&gt;&lt;li&gt;The last part of the answer is _ _ 04.     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;98 × 98 = 9604&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/7595406916874525904/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/05/squaring-2-digit-number-beginning-with_5886.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/7595406916874525904'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/7595406916874525904'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/05/squaring-2-digit-number-beginning-with_5886.html' title='Squaring a 2-digit number beginning with 9'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-3221768451934453073</id><published>2008-05-27T23:30:00.000-07:00</published><updated>2008-08-02T20:32:21.609-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="squaring"/><title type='text'>Squaring a 2-digit number beginning with 5</title><content type='html'>&lt;ol&gt;&lt;li&gt;Take a 2-digit number beginning with 5.     &lt;/li&gt;&lt;li&gt;Square the first digit.     &lt;/li&gt;&lt;li&gt;Add this number to the second number to find the first part of the answer.     &lt;/li&gt;&lt;li&gt;Square the second digit: this is the last part of the answer.    &lt;/li&gt;&lt;/ol&gt;    &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;If the number is &lt;b&gt;58&lt;/b&gt;, multiply 5 × 5 = 25 (square the first digit).     &lt;/li&gt;&lt;li&gt;25 + 8 = 33 (25 plus second digit).     &lt;/li&gt;&lt;li&gt;The first part of the answer is 33   3 3 _ _     &lt;/li&gt;&lt;li&gt;8 × 8 = 64 (square second digit).     &lt;/li&gt;&lt;li&gt;The last part of the answer is 64    _ _ 6 4     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;58 × 58 = 3364&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;For 53 × 53, multiply 5 × 5 = 25 (square the first digit).     &lt;/li&gt;&lt;li&gt;25 + 3 = 28 (25 plus second digit).     &lt;/li&gt;&lt;li&gt;The first part of the answer is 28   2 8 _ _     &lt;/li&gt;&lt;li&gt;3 × 3 = 9 (square second digit).     &lt;/li&gt;&lt;li&gt;The last part of the answer is 09    _ _ 0 9     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;53 × 53 = 2809&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/3221768451934453073/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/05/squaring-2-digit-number-beginning-with_27.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/3221768451934453073'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/3221768451934453073'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/05/squaring-2-digit-number-beginning-with_27.html' title='Squaring a 2-digit number beginning with 5'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4651990009734372491.post-8779175101992497115</id><published>2008-05-27T23:11:00.000-07:00</published><updated>2008-08-02T20:33:19.755-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="squaring"/><title type='text'>Squaring a 2-digit number beginning with 1</title><content type='html'>&lt;h3&gt;&lt;span style=&quot;color:#000077;&quot;&gt;the steps&lt;br /&gt;&lt;/span&gt;&lt;span style=&quot;color:#aa0000;&quot;&gt;&lt;/span&gt;&lt;/h3&gt;    &lt;ol&gt;&lt;li&gt;Take a 2-digit number beginning with 1.     &lt;/li&gt;&lt;li&gt;Square the second digit&lt;br /&gt;     (keep the carry)   _ _ X     &lt;/li&gt;&lt;li&gt;Multiply the second digit by 2 and&lt;br /&gt;     add the carry (keep the carry)   _ X _     &lt;/li&gt;&lt;li&gt;The first digit is one&lt;br /&gt;     (plus the carry)   X _ _    &lt;/li&gt;&lt;/ol&gt;    &lt;h4&gt;   Example:&lt;/h4&gt;    &lt;ol&gt;&lt;li&gt;If the number is &lt;b&gt;16&lt;/b&gt;, square the second digit:&lt;br /&gt;     6 × 6 = 36   _ _ 6     &lt;/li&gt;&lt;li&gt;Multiply the second digit by 2 and&lt;br /&gt;     add the carry: 2 × 6 + 3 = 15   _ 5 _     &lt;/li&gt;&lt;li&gt;The first digit is one plus the carry:&lt;br /&gt;     1 + 1 = 2   2 _ _     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;16 × 16 = 256&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;    &lt;p&gt;&lt;b&gt;   See the pattern?&lt;/b&gt;    &lt;/p&gt;&lt;ol&gt;&lt;li&gt;For 19 × 19, square the second digit:&lt;br /&gt;     9 × 9 = 81   _ _ 1     &lt;/li&gt;&lt;li&gt;Multiply the second digit by 2 and&lt;br /&gt;     add the carry: 2 × 9 + 8 = 26   _ 6 _     &lt;/li&gt;&lt;li&gt;The first digit is one plus the carry:&lt;br /&gt;     1 + 2 = 3   3 _ _     &lt;/li&gt;&lt;li&gt;So &lt;b&gt;19 × 19 = 361&lt;/b&gt;.    &lt;/li&gt;&lt;/ol&gt;</content><link rel='replies' type='application/atom+xml' href='http://flasharithmetic.blogspot.com/feeds/8779175101992497115/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://flasharithmetic.blogspot.com/2008/05/squaring-2-digit-number-beginning-with.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8779175101992497115'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4651990009734372491/posts/default/8779175101992497115'/><link rel='alternate' type='text/html' href='http://flasharithmetic.blogspot.com/2008/05/squaring-2-digit-number-beginning-with.html' title='Squaring a 2-digit number beginning with 1'/><author><name>Anonymous</name><uri>http://www.blogger.com/profile/13903513874929320867</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry></feed>