<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:blogger='http://schemas.google.com/blogger/2008' xmlns:georss='http://www.georss.org/georss' xmlns:gd="http://schemas.google.com/g/2005" xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-2988068197238554407</id><updated>2026-04-29T15:46:49.781-07:00</updated><category term="5º e 6º ano - Capacidades transversais [Resoluções de problemas]"/><category term="Pensamento algébrico"/><category term="5º e 6º ano - Capacidades transversais [Raciocínio matemático]"/><category term="4º e 5º ano - Capacidades transversais [Resoluções de problemas]"/><category term="5º e 6º ano - Capacidades transversais [Comunicação matemática]"/><category term="6ºano - Álgebra [Relações e regularidades]"/><category term="Conc. - inverso de um número"/><category term="4º e 5º ano - Capacidades transversais [Raciocínio matemático]"/><category term="4ºano - Nºs e operações [Oper. com números naturais]"/><category term="5ºano - Nºs e operações [Números racionais não negativos]"/><category term="Conc. - potência"/><category term="5ºano - Geometria [Sólidos geométricos]"/><category term="Conc. - divisão"/><category term="Conc. - área"/><category term="4º e 5º ano - Capacidades transversais [Comunicação matemática]"/><category term="5ºano - Nºs e operações [Números naturais - Potências]"/><category term="6ºano - Nºs e operações [Nºs racionais não negativos - Operações]"/><category term="3ºano - Nºs e operações [Oper. com números naturais]"/><category term="4ºano - Nºs e operações [Regularidades]"/><category term="5ºano - Geometria [Áreas]"/><category term="6ºano - Álgebra [Relações e regularidades - Sequências e regularidades]"/><category term="Pensamento geométrico"/><category term="3º e 4º ano - Capacidades transversais [Resoluções de problemas]"/><category term="3º e 4º ano - Nºs e operações [Oper. com números naturais]"/><category term="5ºano - Nºs e operações [Números naturais - Decomposição em factores primos; Mínimo múltiplo comum]"/><category term="6º ano - Geometria [Reflexão; rotação e translação]"/><category term="6ºano - Nºs e operações [Nºs racionais não negativos - Noção e representação de número racional; Operações]"/><category term="6ºano - Álgebra [Relações e regularidades - expressões numéricas]"/><category term="1ºano - Nºs e operações [Nºs naturais]"/><category term="5ºano - Geometria [Figuras no Plano - Polígonos: propriedades e classificação]"/><category term="5ºano - Nºs e operações [Números racionais não negativos - Noção e representação de número racional]"/><category term="5ºano - Nºs e operações [Números racionais não negativos - Operações; Percentagens]"/><category term="5ºano - Nºs e operações [Números racionais não negativos - Operações]"/><category term="6ºano - Nºs e operações [Nºs naturais - Potências ]"/><category term="6ºano - Nºs e operações [Nºs racionais não negativos]"/><category term="6ºano - Álgebra [Relações e regularidades - proporcionalidade]"/><category term="Conc. - classes de resto"/><category term="Conc. - divisibilidade/múltiplos"/><category term="Conc. - número triangular"/><category term="Conc. - produto cartesiano"/><category term="Conc. - razão"/><category term="Raciocínio Proporcional"/><category term="2ºano - Nºs e operações [Oper. com números naturais]"/><category term="3º e 4º ano - Capacidades transversais [Comunicação matemática]"/><category term="4º ano - Medida [Comprimento - áreas]"/><category term="4º ano - Nºs e operações [Números racionais não Negativos - fracções]"/><category term="4º e 5º ano - Nºs e operações [Operações com nºs naturais]"/><category term="4ºano - Nºs e operações [Nºs racionais não negativos]"/><category term="4ºano - Nºs e operações [Oper. com números naturais - Divisão]"/><category term="5ºano - Geometria [Figuras no Plano - Ângulos: amplitude e medição]"/><category term="5ºano - Geometria [Áreas - Equivalência de figuras planas]"/><category term="5ºano - Nºs e operações [Números naturais - Critérios de divisibilidade]"/><category term="5ºano - Nºs e operações [Números naturais - Decomposição em factores primos; Máximo divisor comum de dois números]"/><category term="5ºano - Org. e tratamento de dados - média aritmética"/><category term="6ºano - Geometria [Volumes]"/><category term="6ºano - Nºs e operações [Nºs naturais - Propriedades das operações e regras operatórias]"/><category term="6ºano - Nºs e operações [Nºs racionais não negativos - percentagens]"/><category term="Applets"/><category term="Conc. - divisor/factor"/><category term="Conc. - m.d.c."/><category term="Conc. - m.m.c"/><category term="Conc. - número oblongo"/><category term="Conc. - número racional como medida"/><category term="Conc. - número racional como operador"/><category term="Conc. - percentagem"/><category term="Conc. - simetria"/><category term="1º e 2º ano - Nºs e operações [Operações com números naturais - Adição; Subtracção]"/><category term="1ºano - Geometria [Orientação espacial - Posição e localização; Pontos de referência]"/><category term="1ºano - Nºs e operações [Nºs naturais - Noção de número natural]"/><category term="1ºano - Nºs e operações [Operações com números naturais - Adição; Subtracção]"/><category term="2º e 3º ano - Capacidades transversais [Resoluções de problemas]"/><category term="2ºano -  Geometria [Figuras no plano - Reflexão]"/><category term="2ºano - Nºs e operações [Oper. com números naturais - Adição; Subtracção; Multiplicação; Divisão]"/><category term="2ºano - Org. e tratamento de dados [Representação e interpretação de dados]"/><category term="3º ano - Medida [Tempo - unidades de tempo ]"/><category term="3º e 4º ano - Geometria [Figuras no plano e sólidos Geométricos ]"/><category term="3º e 4º ano - Medida"/><category term="3º e 4º ano - Medida [Comprimento; área]"/><category term="3º e 4º ano - Nºs e operações [Oper. com números naturais - Divisão]"/><category term="3ºano - Nºs e operações [Números naturais]"/><category term="4º ano - Geometria [Figuras no plano e sólidos Geométricos ]"/><category term="4º ano - Nºs e operações [Números racionais não Negativos - decimais]"/><category term="4ºano - Nºs e operações [Nºs naturais - múltiplos]"/><category term="4ºano - Nºs e operações [Nºs naturais]"/><category term="5ºano - Geometria [Perímetros]"/><category term="5ºano - Nºs e operações [Números naturais - Potências de base e expoente naturais; Potências de base 10]"/><category term="5ºano - Áreas [Equivalência de figuras planas; Área do triângulo]"/><category term="6ºano - Nºs e operações [Nºs naturais - Multiplicação e divisão de potências]"/><category term="6ºano - Álgebra [Relações e regularidades - expressões numéricas e propriedades das operações]"/><category term="Conc. - algoritmo de Euclides"/><category term="Conc. - distributividade"/><category term="Conc. - média"/><category term="Conc. - múltiplo/divisível"/><category term="Conc. - número quadrado"/><category term="Conc. - número racional como relação parte-todo"/><category term="Conc. - perímetro"/><category term="Conc. - proporção"/><category term="Conc. - relação de Euler"/><category term="Conc. - ângulo"/><category term="Conc. - ângulo convexo"/><category term="Conc. - ângulo côncavo"/><category term="Conc. - ângulos alternos-externos"/><category term="Conc. - ângulos alternos-internos"/><category term="Conc. - ângulos complementares"/><category term="Conc. - ângulos externos"/><category term="Conc. - ângulos suplementares"/><category term="GM4 - [Medida] 5. Medir volumes e capacidades"/><category term="GM5-2 Reconhecer propriedades de triângulos e paralelogramos"/><category term="GM5-3 Resolver problemas"/><category term="NO5-1 Efetuar operações com números racionais não negativos"/><category term="Raciocínio lógico"/><title type='text'>sse for Matemática</title><subtitle type='html'>Pretende este blogue partilhar atividades, tarefas, problemas suscetíveis de serem levados à sala de aula, especialmente, dos 1º e 2º ciclos. Os problemas estão categorizados por nível de escolaridade e pelo tema matemático envolvido. Não quer isto dizer que garantam exclusivamente o envolvimento dos temas e o nível que lhes estão associados. Dependendo do objetivo com que são utilizados, devem ser sempre sujeitos a adaptações de acordo com o público alvo a que se destinam.</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default?redirect=false'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><link rel='next' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default?start-index=26&amp;max-results=25&amp;redirect=false'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>113</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-6578637519087585251</id><published>2018-11-10T07:52:00.002-08:00</published><updated>2018-11-10T07:58:40.613-08:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5º e 6º ano - Capacidades transversais [Resoluções de problemas]"/><category scheme="http://www.blogger.com/atom/ns#" term="6ºano - Álgebra [Relações e regularidades]"/><category scheme="http://www.blogger.com/atom/ns#" term="Conc. - número triangular"/><title type='text'>Torre Triangular</title><content type='html'>&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiZWTiuAcuMNofpm-03fKVoBv-a4KG7LfRzNgsRiVl0TmMvkp3YXz_G4PcIPDDmJOBJ_9VOOI25JcBo83Uh8sK2Xok37l4mC2ooH6drrnv9sEqzB2zMX0TssfDCXHNUNbVvFVK-inuguvk/s1600/empilhamento.png&quot; imageanchor=&quot;1&quot; style=&quot;clear: left; float: left; margin-bottom: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; data-original-height=&quot;216&quot; data-original-width=&quot;143&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiZWTiuAcuMNofpm-03fKVoBv-a4KG7LfRzNgsRiVl0TmMvkp3YXz_G4PcIPDDmJOBJ_9VOOI25JcBo83Uh8sK2Xok37l4mC2ooH6drrnv9sEqzB2zMX0TssfDCXHNUNbVvFVK-inuguvk/s1600/empilhamento.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;br /&gt;
&lt;br /&gt;
O José viu numa montra de uma pastelaria um empilhamento de latas como na figura ao lado. &lt;br /&gt;
&lt;br /&gt;
O José contou 7 andares nesta torre e ficou entusiasmado em fazer uma idêntica em casa, mas com o sêxtuplo dos andares. &lt;br /&gt;
&lt;br /&gt;
Quantas latas vai o José precisar para construir a sua torre? &lt;br /&gt;
&lt;div&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: right;&quot;&gt;
&lt;a href=&quot;https://mega.nz/#!Fp9HyAZZ!4XrYD8HQcPh8BBA8Nvh1sHCgkRbdzHDxnZhEsFGFCwY&quot;&gt;&lt;span style=&quot;font-size: x-small;&quot;&gt;proposta de resolução&lt;/span&gt;&lt;/a&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/6578637519087585251/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/6578637519087585251' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6578637519087585251'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6578637519087585251'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2018/11/torre-triangular.html' title='Torre Triangular'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiZWTiuAcuMNofpm-03fKVoBv-a4KG7LfRzNgsRiVl0TmMvkp3YXz_G4PcIPDDmJOBJ_9VOOI25JcBo83Uh8sK2Xok37l4mC2ooH6drrnv9sEqzB2zMX0TssfDCXHNUNbVvFVK-inuguvk/s72-c/empilhamento.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-9009634245359205884</id><published>2018-09-04T16:14:00.002-07:00</published><updated>2018-09-04T16:19:30.383-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5º e 6º ano - Capacidades transversais [Raciocínio matemático]"/><category scheme="http://www.blogger.com/atom/ns#" term="5º e 6º ano - Capacidades transversais [Resoluções de problemas]"/><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Nºs e operações [Números naturais - Potências]"/><category scheme="http://www.blogger.com/atom/ns#" term="Pensamento algébrico"/><title type='text'>Colheita  do tomate</title><content type='html'>&lt;div class=&quot;MsoNormal&quot;&gt;
&lt;!--[if gte vml 1]&gt;&lt;v:shapetype id=&quot;_x0000_t75&quot; coordsize=&quot;21600,21600&quot;
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 &lt;w:wrap type=&quot;tight&quot;/&gt;
&lt;/v:shape&gt;&lt;![endif]--&gt;&lt;!--[if !vml]--&gt;&lt;!--[endif]--&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjdzovnGU1SfPkwWhyuskmVa5a7XoaoysBRuCsBB0rDPbGUL9iKknW5PpOnJmayjoGq7mpUdjVYpBZItmtnYXYZ36TXnwFGQqNHbsc4NmE9gpExNnMNeHGuq6PPvxEOyXJx6sNxYMTHD3M/s1600/tomate.sseformat.JPG&quot; imageanchor=&quot;1&quot; style=&quot;clear: right; float: right; margin-bottom: 1em; margin-left: 1em;&quot;&gt;&lt;img border=&quot;0&quot; data-original-height=&quot;306&quot; data-original-width=&quot;421&quot; height=&quot;145&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjdzovnGU1SfPkwWhyuskmVa5a7XoaoysBRuCsBB0rDPbGUL9iKknW5PpOnJmayjoGq7mpUdjVYpBZItmtnYXYZ36TXnwFGQqNHbsc4NmE9gpExNnMNeHGuq6PPvxEOyXJx6sNxYMTHD3M/s200/tomate.sseformat.JPG&quot; width=&quot;200&quot; /&gt;&lt;/a&gt;&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;Nas férias de verão, o
Gustavo decidiu ir trabalhar uma semana completa na colheita do tomate. Ficou
acordado que no primeiro dia ganharia 1€ e nos dias seguintes receberia o dobro
do dia anterior. Ao sétimo dia não foi trabalhar porque ficou doente, mas pediu
ao seu amigo Alexandre que o fosse substituir.&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt; mso-ansi-language: PT; mso-bidi-font-family: &amp;quot;Times New Roman&amp;quot;; mso-bidi-language: AR-SA; mso-fareast-font-family: &amp;quot;Times New Roman&amp;quot;; mso-fareast-language: AR-SA;&quot;&gt;Quem ganhou mais
dinheiro nestes 7 dias de trabalho, o Gustavo ou o Alexandre? E por quanto?&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt; mso-ansi-language: PT; mso-bidi-font-family: &amp;quot;Times New Roman&amp;quot;; mso-bidi-language: AR-SA; mso-fareast-font-family: &amp;quot;Times New Roman&amp;quot;; mso-fareast-language: AR-SA;&quot;&gt;&lt;br /&gt;&lt;/span&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt; mso-ansi-language: PT; mso-bidi-font-family: &amp;quot;Times New Roman&amp;quot;; mso-bidi-language: AR-SA; mso-fareast-font-family: &amp;quot;Times New Roman&amp;quot;; mso-fareast-language: AR-SA;&quot;&gt;&lt;br /&gt;&lt;/span&gt;
&lt;div style=&quot;text-align: right;&quot;&gt;
&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;a href=&quot;https://mega.nz/#!w4dHRCKZ!-F0PKNpFDx2T-l0QagiJ85iySNbCIQdx3orjukr1hIQ&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/span&gt;&lt;/div&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt; mso-ansi-language: PT; mso-bidi-font-family: &amp;quot;Times New Roman&amp;quot;; mso-bidi-language: AR-SA; mso-fareast-font-family: &amp;quot;Times New Roman&amp;quot;; mso-fareast-language: AR-SA;&quot;&gt;&lt;br /&gt;&lt;/span&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt; mso-ansi-language: PT; mso-bidi-font-family: &amp;quot;Times New Roman&amp;quot;; mso-bidi-language: AR-SA; mso-fareast-font-family: &amp;quot;Times New Roman&amp;quot;; mso-fareast-language: AR-SA;&quot;&gt;&lt;br /&gt;&lt;/span&gt;
&lt;br /&gt;
&lt;div class=&quot;MsoNormal&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;Nota:
depois da exploração do problema deve conseguir completar de imediato as seguintes igualdades:&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;1 + 2 + 4 + 8 + 1 6 + 32 +
__ = 64&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;2 + 4 + 8+ 16 + 32 + 64 + __
= 128&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;3 + 6 + 12+ 24 + 48 + __ =
96&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;2&lt;sup&gt;2&lt;/sup&gt; + 2&lt;sup&gt;3&lt;/sup&gt;
+ 2&lt;sup&gt;4&lt;/sup&gt; + 2&lt;sup&gt;5&lt;/sup&gt; + 2&lt;sup&gt;6 &lt;/sup&gt;+ 2&lt;sup&gt;7&lt;/sup&gt; + __ = 2&lt;sup&gt;8&lt;/sup&gt;&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt;&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;Sugestão: faça uma extensão a esta situação para
estudar o comportamento das potências de base 3, 4,…&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt;&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;Depois disso deve conseguir completar rapidamente
a igualdade:&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;___ x (3&lt;sup&gt; &lt;/sup&gt;+ 3&lt;sup&gt;2&lt;/sup&gt;
+ 3&lt;sup&gt;3&lt;/sup&gt; + 3&lt;sup&gt;4&lt;/sup&gt; + 3&lt;sup&gt;5&lt;/sup&gt; + 3&lt;sup&gt;6 &lt;/sup&gt;+ 3&lt;sup&gt;7&lt;/sup&gt;)
+__ = 3&lt;sup&gt;8&lt;/sup&gt;&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;&lt;sup&gt;&lt;br /&gt;&lt;/sup&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt;&quot;&gt;&lt;sup&gt;&lt;br /&gt;&lt;/sup&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;span style=&quot;font-family: &amp;quot;Comic Sans MS&amp;quot;; font-size: 11.0pt; mso-ansi-language: PT; mso-bidi-font-family: &amp;quot;Times New Roman&amp;quot;; mso-bidi-language: AR-SA; mso-fareast-font-family: &amp;quot;Times New Roman&amp;quot;; mso-fareast-language: AR-SA;&quot;&gt;&lt;/span&gt;</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/9009634245359205884/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/9009634245359205884' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/9009634245359205884'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/9009634245359205884'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2018/09/colheita-do-tomate.html' title='Colheita  do tomate'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjdzovnGU1SfPkwWhyuskmVa5a7XoaoysBRuCsBB0rDPbGUL9iKknW5PpOnJmayjoGq7mpUdjVYpBZItmtnYXYZ36TXnwFGQqNHbsc4NmE9gpExNnMNeHGuq6PPvxEOyXJx6sNxYMTHD3M/s72-c/tomate.sseformat.JPG" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-4690495495755588444</id><published>2018-08-03T07:37:00.000-07:00</published><updated>2018-09-04T16:25:04.407-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Resoluções de problemas]"/><title type='text'>Festivais de Verão</title><content type='html'>&lt;div class=&quot;MsoNormal&quot; style=&quot;margin-right: -.1pt; text-indent: 35.4pt;&quot;&gt;
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&lt;/div&gt;
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&lt;/div&gt;
&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhj5QAN9N3Hgy3BQd74cmPgAyDEFAKoRy2TAhB-T1EBxcWGNyQbieIf9SyyslUa1rNn_Mzdq4V_VV7QWzS75lgIKjGjFQeHDrL7yunRDRYzEoUzgQlkEh0JSD5mhBH2p1xr2rJprAqS8Xw/s1600/festivais2018.png&quot; imageanchor=&quot;1&quot; style=&quot;clear: left; float: left; margin-bottom: 1em; margin-right: 1em; text-indent: 35.4pt;&quot;&gt;&lt;img border=&quot;0&quot; data-original-height=&quot;140&quot; data-original-width=&quot;557&quot; height=&quot;80&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhj5QAN9N3Hgy3BQd74cmPgAyDEFAKoRy2TAhB-T1EBxcWGNyQbieIf9SyyslUa1rNn_Mzdq4V_VV7QWzS75lgIKjGjFQeHDrL7yunRDRYzEoUzgQlkEh0JSD5mhBH2p1xr2rJprAqS8Xw/s320/festivais2018.png&quot; width=&quot;320&quot; /&gt;&lt;/a&gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Durante o mês de agosto o Ricardo esteve presente em dois festivais de verão. Do dia 9 ao dia 12 este no festival “Bons Sons” em Tomar, e nos últimos dias do mês esteve no festival do Crato, que decorreu de 29 de agosto a 1 de setembro. &lt;br /&gt;
&lt;br /&gt;
Quantos dias, no mês de agosto, esteve o Ricardo em festivais?&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: right;&quot;&gt;
&lt;a href=&quot;https://mega.nz/#!9lkEhCpb!RNsEKqhdg9VRTrtP8HDVG8MZsVw6fuDkZ7JkMszYqyo&quot;&gt;&lt;span style=&quot;font-size: x-small;&quot;&gt;proposta de resolução&lt;/span&gt;&lt;/a&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/4690495495755588444/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/4690495495755588444' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/4690495495755588444'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/4690495495755588444'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2016/08/festivais-de-verao.html' title='Festivais de Verão'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhj5QAN9N3Hgy3BQd74cmPgAyDEFAKoRy2TAhB-T1EBxcWGNyQbieIf9SyyslUa1rNn_Mzdq4V_VV7QWzS75lgIKjGjFQeHDrL7yunRDRYzEoUzgQlkEh0JSD5mhBH2p1xr2rJprAqS8Xw/s72-c/festivais2018.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-6820191500955084022</id><published>2016-08-03T07:37:00.000-07:00</published><updated>2016-08-03T08:17:00.333-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="GM4 - [Medida] 5. Medir volumes e capacidades"/><title type='text'>A Torre</title><content type='html'>&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjjItLdY1y_kkrAIjPho2Sl4CUauI-MxMrL7IQNo-ZPCu5rsSORA2W_x-xjdMzRiFaotnGZ_PE35HT3fKiVURWQOGfkfYrlrl2WHLfeEQGJwj_RTB332JVQ8A0ptBrdoPSH2UrIpxnYgOE/s1600/2016.08.JPG&quot; imageanchor=&quot;1&quot; style=&quot;clear: left; float: left; margin-bottom: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;200&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjjItLdY1y_kkrAIjPho2Sl4CUauI-MxMrL7IQNo-ZPCu5rsSORA2W_x-xjdMzRiFaotnGZ_PE35HT3fKiVURWQOGfkfYrlrl2WHLfeEQGJwj_RTB332JVQ8A0ptBrdoPSH2UrIpxnYgOE/s200/2016.08.JPG&quot; width=&quot;62&quot; /&gt;&lt;/a&gt;&lt;span style=&quot;font-family: &amp;quot;comic sans ms&amp;quot;; font-size: large;&quot;&gt;Que
altura poderá ter uma torre com todos os centímetros cúbicos sobrepostos, existentes num metro cúbico?&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;font-family: &amp;quot;comic sans ms&amp;quot;; font-size: 11.0pt;&quot;&gt;&lt;br /&gt;&lt;/span&gt;
&lt;span style=&quot;font-family: &amp;quot;comic sans ms&amp;quot;; font-size: 11.0pt;&quot;&gt;&lt;br /&gt;&lt;/span&gt;
&lt;span style=&quot;font-family: &amp;quot;comic sans ms&amp;quot;; font-size: 11.0pt;&quot;&gt;&lt;br /&gt;&lt;/span&gt;
&lt;span style=&quot;font-family: &amp;quot;comic sans ms&amp;quot;; font-size: 11.0pt;&quot;&gt;&lt;br /&gt;&lt;/span&gt;
&lt;span style=&quot;font-family: &amp;quot;comic sans ms&amp;quot;; font-size: 11.0pt;&quot;&gt;&lt;br /&gt;&lt;/span&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: right;&quot;&gt;
&lt;span style=&quot;font-family: &amp;quot;comic sans ms&amp;quot;; font-size: xx-small; mso-ansi-language: PT; mso-bidi-font-family: &amp;quot;Times New Roman&amp;quot;; mso-bidi-language: AR-SA; mso-fareast-font-family: &amp;quot;Times New Roman&amp;quot;; mso-fareast-language: AR-SA;&quot;&gt;&lt;a href=&quot;https://drive.google.com/open?id=0B5HEqtig6I0-Si1xREtXQjA4eUE&quot; target=&quot;_blank&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/span&gt;&lt;/div&gt;
&lt;span style=&quot;font-family: &amp;quot;comic sans ms&amp;quot;; font-size: 11.0pt;&quot;&gt;&lt;br /&gt;&lt;/span&gt;</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/6820191500955084022/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/6820191500955084022' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6820191500955084022'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6820191500955084022'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2016/08/a-torre.html' title='A Torre'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjjItLdY1y_kkrAIjPho2Sl4CUauI-MxMrL7IQNo-ZPCu5rsSORA2W_x-xjdMzRiFaotnGZ_PE35HT3fKiVURWQOGfkfYrlrl2WHLfeEQGJwj_RTB332JVQ8A0ptBrdoPSH2UrIpxnYgOE/s72-c/2016.08.JPG" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-8641731144987336614</id><published>2013-09-29T16:31:00.001-07:00</published><updated>2013-09-30T12:07:23.032-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="NO5-1 Efetuar operações com números racionais não negativos"/><title type='text'>Maçãs com racionais</title><content type='html'>&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgVwGBhiJJHCrwz38zBjdLPvb2lOlFGfv9ZTyT-XqPgDc2TdIw__z9CIGwhCeIgh7yDFZQO-3kD3H2ojyLZIo-elSfY6cLmRH-x3V-83vLSlFzggcfCfpcBBQyKCwFE9Lx8gnYGx1VsEqw/s1600/Imagem1.png&quot; imageanchor=&quot;1&quot; style=&quot;clear: right; float: right; margin-bottom: 1em; margin-left: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;212&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgVwGBhiJJHCrwz38zBjdLPvb2lOlFGfv9ZTyT-XqPgDc2TdIw__z9CIGwhCeIgh7yDFZQO-3kD3H2ojyLZIo-elSfY6cLmRH-x3V-83vLSlFzggcfCfpcBBQyKCwFE9Lx8gnYGx1VsEqw/s320/Imagem1.png&quot; width=&quot;320&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;br /&gt;
&lt;br /&gt;
O Rui foi ao mercado comprar maçãs.&lt;br /&gt;
Escreve o significado de cada uma das seguintes expressões numéricas sabendo que cada uma delas representa um valor em cêntimos.&lt;br /&gt;
&lt;div align=&quot;left&quot;&gt;
&lt;a href=&quot;http://lh5.ggpht.com/-0_bXRBLUni8/Uki4R0NBKqI/AAAAAAAACOI/S8i7HnuXRbo/s1600-h/Capturar%25255B3%25255D.jpg&quot;&gt;&lt;img alt=&quot;Capturar&quot; border=&quot;0&quot; height=&quot;206&quot; src=&quot;http://lh6.ggpht.com/-KHmFNh-BcR8/Uki4SeEcXmI/AAAAAAAACOQ/4FreVhdapIA/Capturar_thumb%25255B1%25255D.jpg?imgmax=800&quot; style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; border-right: 0px; border-top: 0px; display: inline; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;Capturar&quot; width=&quot;142&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;span style=&quot;font-size: x-small;&quot;&gt;&lt;i&gt;Domínio:&lt;/i&gt; &lt;span style=&quot;color: blue;&quot;&gt;Números e Operações       &lt;/span&gt;&lt;i&gt;Subdomínio:&lt;/i&gt;&lt;span style=&quot;color: blue;&quot;&gt; Números racionais não negativos&lt;/span&gt;      &lt;br /&gt;&lt;i&gt;Objetivo geral:&lt;/i&gt; &lt;span style=&quot;color: blue;&quot;&gt;1. Efetuar operações com números racionais não negativos&lt;/span&gt;&lt;/span&gt;&lt;span style=&quot;color: blue;&quot;&gt; &lt;/span&gt;&lt;br /&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0094_macas.com.racioanis.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/span&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/8641731144987336614/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/8641731144987336614' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/8641731144987336614'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/8641731144987336614'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2013/09/macas-com-racionais.html' title='Maçãs com racionais'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgVwGBhiJJHCrwz38zBjdLPvb2lOlFGfv9ZTyT-XqPgDc2TdIw__z9CIGwhCeIgh7yDFZQO-3kD3H2ojyLZIo-elSfY6cLmRH-x3V-83vLSlFzggcfCfpcBBQyKCwFE9Lx8gnYGx1VsEqw/s72-c/Imagem1.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-9168837951431733964</id><published>2013-09-14T19:22:00.001-07:00</published><updated>2013-09-14T20:02:02.115-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Geometria [Figuras no Plano - Polígonos: propriedades e classificação]"/><category scheme="http://www.blogger.com/atom/ns#" term="GM5-2 Reconhecer propriedades de triângulos e paralelogramos"/><category scheme="http://www.blogger.com/atom/ns#" term="GM5-3 Resolver problemas"/><title type='text'>Retângulo dividido em 4</title><content type='html'>&lt;a href=&quot;http://lh3.ggpht.com/-mEApJLVa_4w/UjUZ8kenvOI/AAAAAAAACMY/x476ZNTD0rU/s1600-h/retangulo%25255B3%25255D.jpg&quot;&gt;&lt;img align=&quot;left&quot; alt=&quot;retangulo&quot; border=&quot;0&quot; height=&quot;95&quot; src=&quot;http://lh3.ggpht.com/-GM_3GuO_R4g/UjUZ9GsRH5I/AAAAAAAACMc/2LbYE3o3IzA/retangulo_thumb%25255B1%25255D.jpg?imgmax=800&quot; style=&quot;background-image: none; border-bottom-width: 0px; border-left-width: 0px; border-right-width: 0px; border-top-width: 0px; display: inline; float: left; margin: 2px 18px 2px 0px; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;retangulo&quot; width=&quot;223&quot; /&gt;&lt;/a&gt;A figura ao lado é um retângulo, e representa uma parede na escola do Gustavo e do Fernando com 10m&lt;sup&gt;2&lt;/sup&gt; tendo uma altura de 2 metros.&lt;br /&gt;
O Fernando ficou de pintar a região vermelha e o Gustavo a Verde. Será que algum deles trabalhou mais que o outro? Se sim, qual deles?&lt;br /&gt;
&lt;br /&gt;
&lt;span style=&quot;font-size: x-small;&quot;&gt;&lt;i&gt;Domínio:&lt;/i&gt; Geometria e Medida &lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;font-size: x-small;&quot;&gt;&lt;i&gt;Subdomínio:&lt;/i&gt; Propriedades geométricas&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;font-size: x-small;&quot;&gt;&lt;i&gt;Objetivo geral:&lt;/i&gt; 2. Reconhecer propriedades de triângulos e paralelogramos&lt;/span&gt;&lt;br /&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0093_retangulo_em_4.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/span&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/9168837951431733964/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/9168837951431733964' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/9168837951431733964'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/9168837951431733964'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2013/09/retangulo-dividido-em-4.html' title='Retângulo dividido em 4'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh3.ggpht.com/-GM_3GuO_R4g/UjUZ9GsRH5I/AAAAAAAACMc/2LbYE3o3IzA/s72-c/retangulo_thumb%25255B1%25255D.jpg?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-8764747667594661935</id><published>2013-03-10T12:39:00.001-07:00</published><updated>2013-03-10T12:49:52.857-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Nºs e operações [Números naturais - Decomposição em factores primos; Mínimo múltiplo comum]"/><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Nºs e operações [Números racionais não negativos - Operações]"/><category scheme="http://www.blogger.com/atom/ns#" term="6ºano - Geometria [Volumes]"/><title type='text'>Paralelepípedos</title><content type='html'>&lt;p&gt;&lt;a href=&quot;http://lh3.ggpht.com/-D0MOYanAuYY/UTzhYpwwgRI/AAAAAAAAB2g/7oR1alDcM5Y/s1600-h/cubo%25255B3%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;cubo&quot; border=&quot;0&quot; alt=&quot;cubo&quot; align=&quot;right&quot; src=&quot;http://lh6.ggpht.com/-FyXCSL0s0k8/UTzhZPzp3LI/AAAAAAAAB2o/b0u_fw1eL5Q/cubo_thumb%25255B1%25255D.png?imgmax=800&quot; width=&quot;219&quot; height=&quot;221&quot; /&gt;&lt;/a&gt;Na serração do sr. Eduardo foram empilhados paralelepípedos retângulos de madeira de modo a formar um cubo com 12 dm de aresta. &lt;/p&gt;  &lt;p&gt;1. Determina o volume ocupado por cada paralelepípedo retângulo.&lt;/p&gt;  &lt;p&gt;&lt;a href=&quot;http://lh6.ggpht.com/-tpk1fFqSZjI/UTzhZ5suFYI/AAAAAAAAB2w/qbi99NBHKvQ/s1600-h/c1%25255B3%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: block; float: none; margin-left: auto; border-top: 0px; margin-right: auto; border-right: 0px; padding-top: 0px&quot; title=&quot;c1&quot; border=&quot;0&quot; alt=&quot;c1&quot; src=&quot;http://lh6.ggpht.com/-M5x-XYGltU4/UTzhaVIwrRI/AAAAAAAAB24/8wscjVEI3QU/c1_thumb%25255B1%25255D.png?imgmax=800&quot; width=&quot;132&quot; height=&quot;125&quot; /&gt;&lt;/a&gt;&lt;/p&gt;  &lt;p&gt;2. Qual é a massa de cada paralelepípedo retângulo sabendo que o cubo tem uma massa de 180kg?&lt;/p&gt;  &lt;p&gt;3. Quantos paralelepípedos retângulos serão necessários para poder construir o próximo cubo maior que este? &lt;/p&gt;  &lt;p&gt;&lt;a href=&quot;http://lh3.ggpht.com/-FyvoNBWeMfA/UTzhbEpad8I/AAAAAAAAB28/AgQvFqGQrfQ/s1600-h/c2%25255B3%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;c2&quot; border=&quot;0&quot; alt=&quot;c2&quot; align=&quot;right&quot; src=&quot;http://lh6.ggpht.com/-dTTnBBXpHXA/UTzhb5ZaVwI/AAAAAAAAB3I/uyMJnHg3P-M/c2_thumb%25255B1%25255D.png?imgmax=800&quot; width=&quot;220&quot; height=&quot;142&quot; /&gt;&lt;/a&gt;4. Se os paralelepípedos tivessem 60 dm&lt;sup&gt;3 &lt;/sup&gt;como o da figura ao lado, qual seria o volume, em metros cúbicos, do menor cubo formado por estes paralelepípedos retângulos?&lt;/p&gt;          &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;&lt;i&gt;&lt;/i&gt;&lt;/p&gt;  &lt;p&gt;&lt;u&gt;&lt;font color=&quot;#0000ff&quot; size=&quot;2&quot;&gt;Meta curricular associada&lt;/font&gt;&lt;/u&gt;&lt;/p&gt;  &lt;p&gt;&lt;font color=&quot;#0000ff&quot;&gt;&lt;font size=&quot;2&quot;&gt;&lt;i&gt;&lt;font color=&quot;#000000&quot;&gt;Domínio:&lt;/font&gt;&lt;/i&gt; Geometria e Medida - &lt;i&gt;&lt;font color=&quot;#000000&quot;&gt;Subdomínio:&lt;/font&gt;&lt;/i&gt; Medida&lt;/font&gt;&lt;/font&gt;&lt;/p&gt;  &lt;p&gt;&lt;font color=&quot;#0000ff&quot;&gt;&lt;font size=&quot;2&quot;&gt;&lt;i&gt;&lt;font color=&quot;#000000&quot;&gt;Objetivo geral:&lt;/font&gt;&lt;/i&gt; 7. Medir volumes de sólidos&lt;/font&gt;&lt;/font&gt;&lt;/p&gt;  &lt;p&gt;&lt;font color=&quot;#0000ff&quot;&gt;&lt;font size=&quot;2&quot;&gt;&lt;i&gt;&lt;font color=&quot;#000000&quot;&gt;Meta:&lt;/font&gt; &lt;/i&gt;1. Considerar, fixada uma unidade de comprimento e dados três números naturais &lt;b&gt;&lt;i&gt;a&lt;/i&gt;&lt;/b&gt;, &lt;b&gt;&lt;i&gt;b&lt;/i&gt;&lt;/b&gt; e &lt;b&gt;&lt;i&gt;c&lt;/i&gt;&lt;/b&gt;, um cubo unitário decomposto em &lt;b&gt;&lt;i&gt;a x b x c&lt;/i&gt;&lt;/b&gt; paralelepípedos retângulos com dimensões de medidas &lt;b&gt;&lt;i&gt;1/a,&lt;/i&gt;&lt;/b&gt; &lt;b&gt;&lt;i&gt;1/b&lt;/i&gt;&lt;/b&gt; e &lt;b&gt;&lt;i&gt;1/c&lt;/i&gt;&lt;/b&gt; e reconhecer que o volume de cada um é igual a &lt;b&gt;&lt;i&gt;1/a x1/b x1/c&lt;/i&gt;&lt;/b&gt; unidades cúbicas.&lt;/font&gt;&lt;/font&gt;&lt;/p&gt;  &lt;p align=&quot;right&quot;&gt;&lt;font size=&quot;1&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0092_paralelepipedos.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/font&gt;&lt;/p&gt;  </content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/8764747667594661935/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/8764747667594661935' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/8764747667594661935'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/8764747667594661935'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2013/03/paralelepipedos.html' title='Paralelepípedos'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh6.ggpht.com/-FyXCSL0s0k8/UTzhZPzp3LI/AAAAAAAAB2o/b0u_fw1eL5Q/s72-c/cubo_thumb%25255B1%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-2842587086077889606</id><published>2013-02-03T03:39:00.001-08:00</published><updated>2013-02-03T03:42:01.137-08:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Comunicação matemática]"/><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Raciocínio matemático]"/><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Resoluções de problemas]"/><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Org. e tratamento de dados - média aritmética"/><title type='text'>Magia matemática</title><content type='html'>&lt;p align=&quot;justify&quot;&gt;&lt;a href=&quot;http://lh3.ggpht.com/-F9vsxzT2TbE/UQ5MfpmSs6I/AAAAAAAAByI/OfvcmEuf34s/s1600-h/image%25255B3%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; margin: 2px 2px 7px 9px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;right&quot; src=&quot;http://lh4.ggpht.com/-jjKDAistf0s/UQ5MgonPoJI/AAAAAAAAByM/4MHT8pRxM64/image_thumb%25255B1%25255D.png?imgmax=800&quot; width=&quot;204&quot; height=&quot;201&quot; /&gt;&lt;/a&gt;O Ricardo pediu ao João e ao Pedro para adicionarem três números seguidos de uma qualquer linha do calendário do mês de fevereiro.&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;O João revelou que a soma dos seus números era 54. Rapidamente o Ricardo adivinhou os números escolhidos pelo João - o 17, o 18 e o 19. O João ficou admirado com a rápida descoberta do Ricardo.&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;&amp;#160;&lt;/p&gt;  &lt;ul&gt;   &lt;li&gt;     &lt;div align=&quot;justify&quot;&gt;&lt;font color=&quot;#000000&quot;&gt;A soma que o Pedro encontrou foi 42. Que números teria ele escolhido?&lt;/font&gt;&lt;/div&gt;   &lt;/li&gt; &lt;/ul&gt;  &lt;p align=&quot;justify&quot;&gt;&amp;#160;&lt;/p&gt;  &lt;ul&gt;   &lt;li&gt;     &lt;div align=&quot;justify&quot;&gt;A Cristina ficou interessada pela magia do Ricardo e interveio - a minha soma também é 42, mas eu escolhi os números de uma mesma coluna. Mesmo assim o Ricardo adivinhou os números escolhidos pela Cristina. Quais foram?&lt;/div&gt;   &lt;/li&gt; &lt;/ul&gt;  &lt;p align=&quot;justify&quot;&gt;&amp;#160;&lt;/p&gt;  &lt;ul&gt;   &lt;li&gt;     &lt;div align=&quot;justify&quot;&gt;Indica todos os três números seguidos em linha, em coluna ou em diagonal cuja soma seja 36.&lt;/div&gt;   &lt;/li&gt; &lt;/ul&gt;  &lt;p align=&quot;right&quot;&gt;&lt;font color=&quot;#0000ff&quot; size=&quot;2&quot;&gt;&lt;a href=&quot;http://recreamat.blogs.sapo.pt/31766.html&quot;&gt;Referência bibliográfica&lt;/a&gt;: Afonso, Paulo (2010), &lt;em&gt;Xavier e a Magia Matemática&lt;/em&gt;. Lisboa, APM&lt;/font&gt;&lt;/p&gt;  &lt;p align=&quot;right&quot;&gt;&lt;font size=&quot;1&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/0091_magia_matematica.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/font&gt;&lt;/p&gt;  </content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/2842587086077889606/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/2842587086077889606' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/2842587086077889606'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/2842587086077889606'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2013/02/magia-matematica.html' title='Magia matemática'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh4.ggpht.com/-jjKDAistf0s/UQ5MgonPoJI/AAAAAAAAByM/4MHT8pRxM64/s72-c/image_thumb%25255B1%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-6253292060042889935</id><published>2013-02-02T09:33:00.001-08:00</published><updated>2013-02-02T09:48:23.067-08:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5º e 6º ano - Capacidades transversais [Comunicação matemática]"/><category scheme="http://www.blogger.com/atom/ns#" term="5º e 6º ano - Capacidades transversais [Raciocínio matemático]"/><category scheme="http://www.blogger.com/atom/ns#" term="5º e 6º ano - Capacidades transversais [Resoluções de problemas]"/><category scheme="http://www.blogger.com/atom/ns#" term="Pensamento algébrico"/><title type='text'>Um dia de aniversário</title><content type='html'>&lt;p align=&quot;justify&quot;&gt;&lt;a href=&quot;http://lh5.ggpht.com/-_lP-RXl52x8/UQ1Ny4fMItI/AAAAAAAABxo/N4WMrTQ35c4/s1600-h/image%25255B5%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-right-width: 0px; margin: 4px 33px 0px 11px; padding-left: 0px; padding-right: 0px; display: inline; float: left; border-top-width: 0px; border-bottom-width: 0px; border-left-width: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;left&quot; src=&quot;http://lh5.ggpht.com/-zhaSp_-uvyk/UQ1NzwGcd8I/AAAAAAAABxw/9PA3MI2k3x8/image_thumb%25255B3%25255D.png?imgmax=800&quot; width=&quot;157&quot; height=&quot;281&quot; /&gt;&lt;/a&gt;O Raul, no dia do seu aniversário, partiu o mealheiro para saber o valor das suas economias, e convidou os seus cinco melhores amigos para irem todos ao cinema. &lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;Cada bilhete custou ao Raul seis euros e meio. Depois do cinema, os seus pais deram-lhe uma nota de 50€ para o Raul pagar o lanche aos amigos. A conta da pastelaria foi de 63€. &lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;O dinheiro que restou já não dava para a prenda que ele queria comprar, mas o avô dando conta disso, deu-lhe o dobro do dinheiro que o Raul tinha naquele momento.&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;O Raul agradeceu ao avô e disse que ficava exatamente com 27€, que era o preço do jogo que pretendia comprar.&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;Que dinheiro tinha o mealheiro quando foi partido pelo Raul?&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;&lt;/p&gt;  &lt;p align=&quot;right&quot;&gt;&amp;#160;&lt;/p&gt;  &lt;p align=&quot;right&quot;&gt;&lt;font size=&quot;1&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0090_dia_aniversario.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/font&gt;&lt;/p&gt;  </content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/6253292060042889935/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/6253292060042889935' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6253292060042889935'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6253292060042889935'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2013/02/um-dia-de-aniversario.html' title='Um dia de aniversário'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh5.ggpht.com/-zhaSp_-uvyk/UQ1NzwGcd8I/AAAAAAAABxw/9PA3MI2k3x8/s72-c/image_thumb%25255B3%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-2542521522196426244</id><published>2012-11-18T15:52:00.001-08:00</published><updated>2012-11-18T16:00:29.405-08:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5º e 6º ano - Capacidades transversais [Comunicação matemática]"/><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Geometria [Sólidos geométricos]"/><title type='text'>Famílias de poliedros</title><content type='html'>&lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;Considera as seguintes famílias de poliedros &lt;u&gt;convexos&lt;/u&gt;:&lt;/p&gt;  &lt;p&gt;&lt;a href=&quot;http://lh5.ggpht.com/-5qvvoWiPBN4/UKl0kqDtYII/AAAAAAAABm0/-Bd95kQcRNY/s1600-h/image%25255B4%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;right&quot; src=&quot;http://lh4.ggpht.com/-o_KoMqpw5rI/UKl0llvgjLI/AAAAAAAABm8/aH8rdPn_DYY/image_thumb%25255B2%25255D.png?imgmax=800&quot; width=&quot;124&quot; height=&quot;70&quot; /&gt;&lt;/a&gt;&lt;b&gt;Sólido platónico&lt;/b&gt; – poliedro cujas faces são polígonos regulares e todos congruentes. Nos seus vértices encontram-se sempre o mesmo número de arestas.&lt;/p&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;&lt;a href=&quot;http://lh6.ggpht.com/-A1UU6NUBqDc/UKl0m9vBZnI/AAAAAAAABnA/MaT9DCWzUBU/s1600-h/image%25255B8%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;right&quot; src=&quot;http://lh3.ggpht.com/-0f5tv_QaTVo/UKl0nfGE6BI/AAAAAAAABnM/QSwGoW56jh4/image_thumb%25255B4%25255D.png?imgmax=800&quot; width=&quot;179&quot; height=&quot;82&quot; /&gt;&lt;/a&gt;&lt;/p&gt;  &lt;p&gt;&lt;b&gt;Sólido arquimediano&lt;/b&gt; (ou de Arquimedes) – Poliedro cujas faces são polígonos regulares de mais de um tipo, mas os seus vértices são todos do mesmo tipo, ou seja em torno de cada vértice existe o mesmo arranjo de polígonos.&lt;/p&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;&lt;a href=&quot;http://lh3.ggpht.com/-2Ex1LoY51BM/UKl0pdPYOeI/AAAAAAAABnQ/KI1e2zBQ6Mc/s1600-h/image%25255B13%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;right&quot; src=&quot;http://lh3.ggpht.com/-F4DgPVNrQEc/UKl0qURYJwI/AAAAAAAABnY/WW73mIhAqEw/image_thumb%25255B7%25255D.png?imgmax=800&quot; width=&quot;195&quot; height=&quot;85&quot; /&gt;&lt;/a&gt;&lt;/p&gt;  &lt;p&gt;&lt;b&gt;Prisma&lt;/b&gt; – poliedro formado por duas faces paralelas e congruentes, normalmente designadas por bases, e as faces laterais são paralelogramos. O número de faces laterais é igual ao número de lados do polígono da base.&lt;/p&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;&lt;a href=&quot;http://lh3.ggpht.com/-KSCwae2Fx48/UKl0rGhJuqI/AAAAAAAABng/ES3Z61XgvIk/s1600-h/image%25255B22%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;right&quot; src=&quot;http://lh3.ggpht.com/-_mzHg6pk2TM/UKl0r-VOnzI/AAAAAAAABns/fZir4vOqiTk/image_thumb%25255B12%25255D.png?imgmax=800&quot; width=&quot;172&quot; height=&quot;79&quot; /&gt;&lt;/a&gt;&lt;b&gt;Antiprisma &lt;/b&gt;– poliedro formado por duas faces paralelas e congruentes, normalmente designadas por bases, e as faces laterais são triângulos. O número de faces laterais é sempre o dobro do número de lados do polígono da base.&lt;/p&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;&lt;a href=&quot;http://lh6.ggpht.com/-oIfx5NGaJxI/UKl0tVknrWI/AAAAAAAABnw/DPDe2CLQHOw/s1600-h/image%25255B21%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;right&quot; src=&quot;http://lh3.ggpht.com/-FffZmA1iMf0/UKl0uIo9NEI/AAAAAAAABn4/-hBDXpTbQmo/image_thumb%25255B11%25255D.png?imgmax=800&quot; width=&quot;171&quot; height=&quot;86&quot; /&gt;&lt;/a&gt;&lt;b&gt;Deltaedro&lt;/b&gt; – poliedro cujas faces são triângulos equiláteros e todos congruentes.&lt;/p&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;&lt;strong&gt;&lt;/strong&gt;&lt;/p&gt;  &lt;p&gt;&lt;a href=&quot;http://lh6.ggpht.com/-MjCHpDgT9vQ/UKl0vQeLadI/AAAAAAAABoA/BqKFNf-ro10/s1600-h/image%25255B26%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;right&quot; src=&quot;http://lh6.ggpht.com/-zEPEMVEnqrE/UKl0wIk8OZI/AAAAAAAABoI/1oepDqI0Ngk/image_thumb%25255B14%25255D.png?imgmax=800&quot; width=&quot;162&quot; height=&quot;91&quot; /&gt;&lt;/a&gt;&lt;/p&gt;  &lt;p&gt;&lt;b&gt;Sólido de Johnson &lt;/b&gt;- poliedros que não são sólidos platónicos , nem sólidos arquimedianos, nem prismas e nem antiprismas. As faces são polígonos regulares e todas as arestas são de comprimento igual &lt;/p&gt;  &lt;p&gt;&lt;b&gt;&lt;/b&gt;&lt;/p&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;A que famílias pertencem cada um dos seguintes sólidos geométricos?&lt;/p&gt;                        &lt;p&gt;&lt;a href=&quot;http://lh6.ggpht.com/-IhX3E2cFPwM/UKl0wwa5vQI/AAAAAAAABoQ/HwLhduCxEqo/s1600-h/image%25255B35%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: block; float: none; margin-left: auto; border-top: 0px; margin-right: auto; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; src=&quot;http://lh4.ggpht.com/-mM2MJfsZqdU/UKl0x57PSSI/AAAAAAAABoY/2_w1ly7oWJ8/image_thumb%25255B19%25255D.png?imgmax=800&quot; width=&quot;482&quot; height=&quot;199&quot; /&gt;&lt;/a&gt;&lt;/p&gt;    &lt;p&gt;&lt;i&gt;&lt;font color=&quot;#0000ff&quot;&gt;&lt;/font&gt;&lt;/i&gt;&lt;/p&gt;  &lt;p&gt;&lt;i&gt;&lt;font color=&quot;#0000ff&quot;&gt;Sugestão:&lt;strong&gt; &lt;/strong&gt;descarregar software (demo) para mostrar todas as perspetivas dos sólidos (&lt;/font&gt;&lt;font color=&quot;#0000ff&quot;&gt;&lt;a href=&quot;http://poly-pro.softonic.com/universaldownloader-launch&quot;&gt;aqui&lt;/a&gt;)&lt;/font&gt;&lt;/i&gt;&lt;/p&gt;  &lt;p align=&quot;right&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0089_familias_poliedros.pdf?attredirects=0&amp;amp;d=1&quot;&gt;&lt;font size=&quot;1&quot;&gt;proposta de resolução&lt;/font&gt;&lt;/a&gt;&lt;/p&gt;  </content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/2542521522196426244/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/2542521522196426244' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/2542521522196426244'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/2542521522196426244'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/11/familias-de-poliedros.html' title='Famílias de poliedros'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh4.ggpht.com/-o_KoMqpw5rI/UKl0llvgjLI/AAAAAAAABm8/aH8rdPn_DYY/s72-c/image_thumb%25255B2%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-7381923025948738089</id><published>2012-10-14T02:49:00.001-07:00</published><updated>2012-10-14T02:55:48.845-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Raciocínio matemático]"/><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Resoluções de problemas]"/><category scheme="http://www.blogger.com/atom/ns#" term="Pensamento algébrico"/><title type='text'>Em sentido contrário</title><content type='html'>&lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;&lt;a href=&quot;http://lh6.ggpht.com/-DjOFxi093B8/UHqKncLW6tI/AAAAAAAABks/z711oaD60ow/s1600-h/image%25255B5%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; margin: 0px 60px 0px 0px; padding-left: 0px; padding-right: 0px; display: inline; float: left; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;left&quot; src=&quot;http://lh4.ggpht.com/-K3bzO9W3cOo/UHqKolSP8jI/AAAAAAAABkw/9tdNPkUF0Pc/image_thumb%25255B3%25255D.png?imgmax=800&quot; width=&quot;99&quot; height=&quot;164&quot; /&gt;&lt;/a&gt;Na aula de Educação Física a Leonor e o Afonso andavam a correr à volta do campo de jogos. O Afonso é mais rápido que a Leonor, e por essa razão o professor mandou-os correr em sentidos contrários. &lt;/p&gt;  &lt;p&gt;O curioso é que os dois colegas se cruzavam sempre nos mesmos locais – no sítio onde se encontrava o professor, no local onde o João fazia as contagens e ainda junto a uma tabela de basquetebol. Qual a relação das velocidades entre o Afonso e a Leonor?&lt;/p&gt;  &lt;p align=&quot;right&quot;&gt;&lt;font size=&quot;1&quot;&gt;Adaptado de Viana, José (2012),”O Problema do mês Deste Número”. Educação e matemática, 118,43&lt;/font&gt;&lt;/p&gt;  &lt;p align=&quot;right&quot;&gt;&lt;font size=&quot;1&quot;&gt;&lt;/font&gt;&lt;/p&gt;  &lt;p align=&quot;left&quot;&gt;&lt;font color=&quot;#0000ff&quot;&gt;&lt;font size=&quot;2&quot;&gt;&lt;/font&gt;&lt;/font&gt;&lt;/p&gt;  &lt;p align=&quot;left&quot;&gt;&lt;font color=&quot;#0000ff&quot;&gt;&lt;font size=&quot;2&quot;&gt;Sugestão: se tiver a necessidade de concretizar a experiência, carregue esta aplicação em Geogebra (&lt;/font&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/0088_sentido_contrario.ggb?attredirects=0&amp;amp;d=1&quot;&gt;&lt;font size=&quot;2&quot;&gt;aqui&lt;/font&gt;&lt;/a&gt;&lt;/font&gt;&lt;font color=&quot;#0000ff&quot;&gt;&lt;/font&gt;&lt;font color=&quot;#0000ff&quot; size=&quot;2&quot;&gt;)&lt;/font&gt;&lt;/p&gt;  &lt;p align=&quot;left&quot;&gt;&lt;font size=&quot;1&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0088_em_sentido_contrario.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/font&gt;&lt;/p&gt;  </content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/7381923025948738089/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/7381923025948738089' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/7381923025948738089'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/7381923025948738089'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/10/em-sentido-contrario.html' title='Em sentido contrário'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh4.ggpht.com/-K3bzO9W3cOo/UHqKolSP8jI/AAAAAAAABkw/9tdNPkUF0Pc/s72-c/image_thumb%25255B3%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-3646685361526674622</id><published>2012-09-16T11:35:00.001-07:00</published><updated>2012-09-16T11:43:00.303-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º e 3º ano - Capacidades transversais [Resoluções de problemas]"/><category scheme="http://www.blogger.com/atom/ns#" term="2ºano - Nºs e operações [Oper. com números naturais]"/><title type='text'>Viagem</title><content type='html'>&lt;p align=&quot;justify&quot;&gt;&lt;a href=&quot;http://lh4.ggpht.com/-Dk_kn-19BtM/UFYb3jTzgHI/AAAAAAAABj8/21MzSrwGIng/s1600-h/image%25255B5%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; margin: 0px 0px 0px 33px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;right&quot; src=&quot;http://lh5.ggpht.com/-LeyDly-X0hk/UFYb4x_TSuI/AAAAAAAABkE/EqfzRBrIPE8/image_thumb%25255B3%25255D.png?imgmax=800&quot; width=&quot;171&quot; height=&quot;163&quot; /&gt;&lt;/a&gt;Nas férias do verão, o Eduardo fez uma viagem com os seus pais e a sua irmã. Partiu no dia 19 de agosto, ainda o Sol não tinha nascido, e regressou no final do dia 31 do mesmo mês. &lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;A viagem do Eduardo durou quantos dias?&lt;/p&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p align=&quot;right&quot;&gt;&amp;#160;&lt;/p&gt;        &lt;p align=&quot;right&quot;&gt;&lt;em&gt;&lt;font size=&quot;1&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0087_viagem.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/font&gt;&lt;/em&gt;&lt;/p&gt;  </content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/3646685361526674622/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/3646685361526674622' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/3646685361526674622'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/3646685361526674622'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/09/viagem.html' title='Viagem'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh5.ggpht.com/-LeyDly-X0hk/UFYb4x_TSuI/AAAAAAAABkE/EqfzRBrIPE8/s72-c/image_thumb%25255B3%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-4542049636040189572</id><published>2012-09-11T07:54:00.001-07:00</published><updated>2012-09-11T08:10:48.549-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Comunicação matemática]"/><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Raciocínio matemático]"/><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Resoluções de problemas]"/><title type='text'>Casamento da idade com o ano de nascimento</title><content type='html'>&lt;a href=&quot;http://lh6.ggpht.com/-7idHJo1fJ-c/UE9Qp_jXIKI/AAAAAAAABi0/hUdTWDrfW98/s1600-h/image%25255B14%25255D.png&quot;&gt;&lt;img align=&quot;left&quot; alt=&quot;image&quot; border=&quot;0&quot; height=&quot;240&quot; src=&quot;http://lh4.ggpht.com/-3ev_Riyqa4c/UE9QqzipobI/AAAAAAAABi8/VeA8uSwRblc/image_thumb%25255B12%25255D.png?imgmax=800&quot; style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; border-right: 0px; border-top: 0px; display: inline; float: left; margin: 3px 32px 0px 0px; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;image&quot; width=&quot;163&quot; /&gt;&lt;/a&gt;O Pedro vai este ano para a escola e vai ficar numa turma em que todos os alunos têm seis anos. Quando a professora chamou a atenção para esta curiosidade o Tiago disse que também tinha nascido no sexto ano deste século. &lt;br /&gt;
Assim, chegaram todos à conclusão que neste ano, 2012, todos casavam os anos com a sua data de nascimento. O Tiago tomou novamente a palavra para dizer que este ano o seu pai também casou os anos com a sua data de nascimento.&lt;b&gt; &lt;/b&gt;&lt;br /&gt;
a) E aqueles que nascerem este ano quando é que vão casar os anos, isto é, quando é que vão fazer 12 anos?&lt;b&gt; &lt;/b&gt;&lt;br /&gt;
b) Que idade tem o pai do Tiago?&lt;br /&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;em&gt;&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0086_casa_idades.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/span&gt;&lt;/em&gt;&lt;/div&gt;
&lt;div align=&quot;left&quot;&gt;
&lt;i&gt;&lt;/i&gt;&lt;/div&gt;
&lt;div align=&quot;left&quot;&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;Para investigar: Haverá algum ano em que ninguém case a sua idade com o ano em que nasceu?&lt;/span&gt;&lt;/em&gt;&lt;/div&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;a href=&quot;http://www.maismat.blogspot.pt/2009/03/minha-idade-e-do-meu-avo-relacoes.html&quot;&gt;ver mais&lt;/a&gt;&lt;/span&gt;&lt;/em&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/4542049636040189572/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/4542049636040189572' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/4542049636040189572'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/4542049636040189572'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/09/casamento-da-idade-com-o-ano-de.html' title='Casamento da idade com o ano de nascimento'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh4.ggpht.com/-3ev_Riyqa4c/UE9QqzipobI/AAAAAAAABi8/VeA8uSwRblc/s72-c/image_thumb%25255B12%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-3636337954296178843</id><published>2012-08-27T16:41:00.001-07:00</published><updated>2012-08-27T16:50:41.269-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Nºs e operações [Números racionais não negativos - Operações; Percentagens]"/><category scheme="http://www.blogger.com/atom/ns#" term="Conc. - percentagem"/><title type='text'>Início das aulas com percentagens</title><content type='html'>&lt;p&gt;&lt;a href=&quot;http://lh5.ggpht.com/-17JzlLhc_aw/UDwFoEDwYiI/AAAAAAAABh0/LCFmVqUjAlY/s1600-h/clip_image002%25255B5%25255D.jpg&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;clip_image002&quot; border=&quot;0&quot; hspace=&quot;12&quot; alt=&quot;clip_image002&quot; align=&quot;right&quot; src=&quot;http://lh3.ggpht.com/-XQnJlSHiFBY/UDwFokfIvLI/AAAAAAAABh8/Gt4rdPsGF9I/clip_image002_thumb%25255B2%25255D.jpg?imgmax=800&quot; width=&quot;289&quot; height=&quot;188&quot; /&gt;&lt;/a&gt;O André aproveitou uma campanha promocional, numa papelaria do centro comercial, com 23% de desconto na compra de material escolar. Pagou por todo o material 27,72€. &lt;/p&gt;  &lt;p&gt;1. Das opções seguintes, escolhe aquela que indica o preço do material que o André comprou se não houvesse campanha promocional.&lt;/p&gt;  &lt;p&gt;a. 27,72 x 0,23&lt;/p&gt;  &lt;p&gt;b. 27,72 x 0,77&lt;/p&gt;  &lt;p&gt;c. 27,72 : 0,23&lt;/p&gt;  &lt;p&gt;d. 27,72 : 0,77&lt;/p&gt;  &lt;p&gt;2. Quanto conseguiu poupar o André na compra do seu material escolar?&lt;/p&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;&lt;font color=&quot;#0000ff&quot;&gt;&lt;font size=&quot;1&quot;&gt;&lt;em&gt;Meta curricular associada:&lt;/em&gt;        &lt;br /&gt;Resolver problemas de vários passos envolvendo operações com números racionais representados por frações, dízimas, percentagens e numerais mistos.&lt;/font&gt;&lt;/font&gt;&lt;/p&gt;  &lt;p align=&quot;right&quot;&gt;&lt;font size=&quot;1&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0085_inicio_aulas.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/font&gt;&lt;/p&gt;  </content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/3636337954296178843/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/3636337954296178843' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/3636337954296178843'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/3636337954296178843'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/08/inicio-das-aulas-com-percentagens.html' title='Início das aulas com percentagens'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh3.ggpht.com/-XQnJlSHiFBY/UDwFokfIvLI/AAAAAAAABh8/Gt4rdPsGF9I/s72-c/clip_image002_thumb%25255B2%25255D.jpg?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-6692011911661529454</id><published>2012-08-17T03:54:00.000-07:00</published><updated>2012-08-18T05:43:01.773-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Nºs e operações [Números naturais - Potências]"/><category scheme="http://www.blogger.com/atom/ns#" term="Conc. - potência"/><title type='text'>Na reta numérica – potências de base 2</title><content type='html'>&lt;br /&gt;
Considera as seguintes potências: 2&lt;sup&gt;2&lt;/sup&gt;, 2&lt;sup&gt;4&lt;/sup&gt;, 2&lt;sup&gt;6&lt;/sup&gt;, 2&lt;sup&gt;7&amp;nbsp;&lt;/sup&gt;e 2&lt;sup&gt;9&lt;/sup&gt;.&lt;br /&gt;
Coloca na reta numérica, desde que seja possível, as potências que correspondem à sua posição.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;a href=&quot;http://lh4.ggpht.com/-Ig27yffadxA/UCzQNMCzVhI/AAAAAAAABhU/lO3zJZkyQlU/s1600-h/clip_image002%25255B4%25255D.jpg&quot;&gt;&lt;img alt=&quot;clip_image002&quot; border=&quot;0&quot; height=&quot;107&quot; src=&quot;http://lh5.ggpht.com/-5GTqUDZc7Jg/UCzQOK-oI_I/AAAAAAAABhc/nLR8F5UYTuA/clip_image002_thumb%25255B1%25255D.jpg?imgmax=800&quot; style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; border-right: 0px; border-top: 0px; display: block; float: none; margin-left: auto; margin-right: auto; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;clip_image002&quot; width=&quot;240&quot; /&gt;&lt;/a&gt;&lt;br /&gt;
&lt;b&gt;&lt;/b&gt;&lt;br /&gt;
&lt;b&gt;&lt;/b&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue; font-size: x-small;&quot;&gt;&lt;br /&gt;&lt;/span&gt;&lt;/em&gt;
&lt;em&gt;&lt;span style=&quot;color: blue; font-size: x-small;&quot;&gt;Meta curricular associada:&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;span style=&quot;color: blue; font-size: x-small;&quot;&gt;Reconhecer que o quociente de duas potências com a mesma base não nula e expoentes diferentes (sendo o expoente do dividendo superior ao do divisor) é igual a uma potência com a mesma base e cujo expoente é a diferença dos expoentes.&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;color: blue; font-size: x-small;&quot;&gt;&lt;br /&gt;&lt;/span&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0083_potencia_base2.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/span&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/6692011911661529454/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/6692011911661529454' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6692011911661529454'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6692011911661529454'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/08/na-reta-numerica-potencias-de-base-2_17.html' title='Na reta numérica – potências de base 2'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh5.ggpht.com/-5GTqUDZc7Jg/UCzQOK-oI_I/AAAAAAAABhc/nLR8F5UYTuA/s72-c/clip_image002_thumb%25255B1%25255D.jpg?imgmax=800" height="72" width="72"/><thr:total>0</thr:total><georss:featurename>Rua Tomás Mendes da Silva Pinto 26, 6000-319, Portugal</georss:featurename><georss:point>39.825264787925342 -7.5069236755371094</georss:point><georss:box>39.823740287925339 -7.5093911755371092 39.826789287925344 -7.5044561755371095</georss:box></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-6546558160917803818</id><published>2012-08-15T13:39:00.001-07:00</published><updated>2012-08-18T05:45:00.740-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="6ºano - Nºs e operações [Nºs naturais - Multiplicação e divisão de potências]"/><category scheme="http://www.blogger.com/atom/ns#" term="6ºano - Nºs e operações [Nºs naturais - Potências ]"/><category scheme="http://www.blogger.com/atom/ns#" term="Conc. - potência"/><title type='text'>Na reta numérica – potências de base 3</title><content type='html'>&lt;br /&gt;
Localiza na seguinte reta numérica a posição de 3&lt;sup&gt;8&lt;/sup&gt; e de 3&lt;sup&gt;10&lt;/sup&gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;a href=&quot;http://lh6.ggpht.com/-Uf1EVDVh9-U/UCwaegx_E5I/AAAAAAAABg4/8_KIVGm_9rk/s1600-h/clip_image002%25255B6%25255D%25255B4%25255D.jpg&quot;&gt;&lt;img alt=&quot;clip_image002[6]&quot; border=&quot;0&quot; height=&quot;43&quot; src=&quot;http://lh3.ggpht.com/-mwA82c1_Fjc/UCwafDACjRI/AAAAAAAABhA/kU3DvQOd_q4/clip_image002%25255B6%25255D_thumb%25255B2%25255D.jpg?imgmax=800&quot; style=&quot;background-image: none; border-bottom-width: 0px; border-left-width: 0px; border-right-width: 0px; border-top-width: 0px; display: block; float: none; margin-left: auto; margin-right: auto; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;clip_image002[6]&quot; width=&quot;319&quot; /&gt;&lt;/a&gt;&lt;br /&gt;
&lt;br /&gt;
&lt;span style=&quot;color: blue; font-size: x-small;&quot;&gt;&lt;em&gt;&lt;/em&gt;&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;em&gt;Metas curriculares associadas:&lt;/em&gt;&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;span style=&quot;color: blue;&quot;&gt;Reconhecer que o produto de duas potências com a mesma base é igual a uma potência com a mesma base e cujo expoente é igual à soma dos expoentes dos fatores.&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;span style=&quot;color: blue;&quot;&gt;Reconhecer que o quociente de duas potências com a mesma base não nula e expoentes diferentes (sendo o expoente do dividendo superior ao do divisor) é igual a uma potência com a mesma base&amp;nbsp;&lt;/span&gt;&lt;span style=&quot;color: blue;&quot;&gt;e cujo expoente é a diferença dos expoentes.&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;color: blue; font-size: x-small;&quot;&gt;&lt;/span&gt;&lt;br /&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0084_potencia_base3.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/span&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/6546558160917803818/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/6546558160917803818' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6546558160917803818'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6546558160917803818'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/08/na-reta-numerica-potencias-de-base-2.html' title='Na reta numérica – potências de base 3'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh3.ggpht.com/-mwA82c1_Fjc/UCwafDACjRI/AAAAAAAABhA/kU3DvQOd_q4/s72-c/clip_image002%25255B6%25255D_thumb%25255B2%25255D.jpg?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-8207298587371835779</id><published>2012-08-04T12:54:00.001-07:00</published><updated>2018-08-06T16:28:11.582-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Geometria [Figuras no Plano - Polígonos: propriedades e classificação]"/><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Geometria [Áreas - Equivalência de figuras planas]"/><title type='text'>Propriedades de um triângulo</title><content type='html'>&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;/span&gt;&lt;br /&gt;
&lt;a href=&quot;http://lh6.ggpht.com/-TbFzgx-kKqw/UB1982IheiI/AAAAAAAABgI/hy-Mw9-7L6c/s1600-h/ret_insc_triangulo%25255B9%25255D.png&quot;&gt;&lt;img align=&quot;left&quot; alt=&quot;ret_insc_triangulo&quot; border=&quot;0&quot; src=&quot;http://lh4.ggpht.com/-EzBUnoKAT54/UB199iCU8sI/AAAAAAAABgM/1sPfsgrKQNI/ret_insc_triangulo_thumb%25255B7%25255D.png?imgmax=800&quot; height=&quot;173&quot; style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; border-right: 0px; border-top: 0px; display: inline; float: left; margin: 0px 18px 0px 0px; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;ret_insc_triangulo&quot; width=&quot;257&quot; /&gt;&lt;/a&gt;A figura mostra um retângulo inscrito num triângulo e sabe-se que dois dos vértices do retângulo são os pontos médios dos lados do triângulo.&lt;br /&gt;
Qual a relação entre a área do triângulo e a área do retângulo nele inscrito? &lt;br /&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/retangulo_inscrito_triangulo.ggb?attredirects=0&amp;amp;d=1&quot;&gt;&lt;span style=&quot;font-size: xx-small;&quot;&gt;exploração no Geogebra&lt;/span&gt;&lt;/a&gt;&lt;/div&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0082_angulos_internos_triangulo.pdf?attredirects=0&amp;amp;d=1&quot;&gt;&lt;span style=&quot;font-size: xx-small;&quot;&gt;proposta de resolução&lt;/span&gt;&lt;/a&gt;&lt;/div&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;A resposta poderá ser mais evidente após a realização da tarefa que &lt;a href=&quot;https://sites.google.com/site/sseformat/docs/FT_triangulos.pdf?attredirects=0&amp;amp;d=1&quot;&gt;aqui&lt;/a&gt; é proposta:&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;br /&gt;&lt;/span&gt;&lt;/em&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;br /&gt;&lt;/span&gt;&lt;/em&gt;
&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjsVdkwruVasfGFgE8YdIAzWlp9Sw85TVC_O2sUarDeesCwho-EsECSC8rtEoKvwG4ZKNuxNQwP72slfRWJIS-T2daRiIxKORBW7Reb3_aGT1QAm8I4JGo_AG40khVCsh-RqLMzRDDw6nM/s1600/FT_triangulos.JPG&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; data-original-height=&quot;661&quot; data-original-width=&quot;411&quot; height=&quot;640&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjsVdkwruVasfGFgE8YdIAzWlp9Sw85TVC_O2sUarDeesCwho-EsECSC8rtEoKvwG4ZKNuxNQwP72slfRWJIS-T2daRiIxKORBW7Reb3_aGT1QAm8I4JGo_AG40khVCsh-RqLMzRDDw6nM/s640/FT_triangulos.JPG&quot; width=&quot;396&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;br /&gt;&lt;/span&gt;&lt;/em&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;br /&gt;&lt;/span&gt;&lt;/em&gt;
&lt;b&gt;&lt;/b&gt;&lt;br /&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;span style=&quot;font-size: x-small;&quot;&gt;Ideia didática retirada e adaptada de:&lt;/span&gt;&lt;/div&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;span style=&quot;font-size: x-small;&quot;&gt;Tinoco, José (2012), “Soma dos ângulos de um polígono”. &lt;i&gt;Educação e Matemática&lt;/i&gt;, 118, 13&lt;/span&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/8207298587371835779/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/8207298587371835779' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/8207298587371835779'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/8207298587371835779'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/08/propriedades-de-um-triangulo.html' title='Propriedades de um triângulo'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh4.ggpht.com/-EzBUnoKAT54/UB199iCU8sI/AAAAAAAABgM/1sPfsgrKQNI/s72-c/ret_insc_triangulo_thumb%25255B7%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-5153244988603679690</id><published>2012-07-19T07:10:00.001-07:00</published><updated>2012-07-19T07:35:58.239-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Geometria [Áreas - Equivalência de figuras planas]"/><category scheme="http://www.blogger.com/atom/ns#" term="Conc. - área"/><category scheme="http://www.blogger.com/atom/ns#" term="Pensamento geométrico"/><title type='text'>Um retângulo e mais outro</title><content type='html'>&lt;br /&gt;
&lt;div align=&quot;justify&quot;&gt;
&lt;a href=&quot;http://lh3.ggpht.com/-F547ZJU-Smk/UAgVQQ_50CI/AAAAAAAABe4/mfpv7RZjJVY/s1600-h/image%25255B3%25255D.png&quot;&gt;&lt;img align=&quot;left&quot; alt=&quot;image&quot; border=&quot;0&quot; height=&quot;147&quot; src=&quot;http://lh6.ggpht.com/-kDzAyrOvP60/UAgVRJSZ5uI/AAAAAAAABfA/y5GaHOX5j3U/image_thumb%25255B1%25255D.png?imgmax=800&quot; style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; border-right: 0px; border-top: 0px; display: inline; float: left; margin: 0px 35px 0px 0px; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;image&quot; width=&quot;187&quot; /&gt;&lt;/a&gt;Na aula a Catarina desenhou um retângulo, e a partir da sua diagonal o Rodrigo desenhou outro retângulo, de tal modo que o vértice do retângulo da Catarina passou a pertencer a um lado do retângulo desenhado pelo Rodrigo, como se ilustra na figura.&lt;/div&gt;
&lt;div align=&quot;justify&quot;&gt;
As opiniões na turma dividiram-se quando a professora pediu para relacionarem as suas áreas.&lt;/div&gt;
&lt;div align=&quot;justify&quot;&gt;
- O vermelho tem maior área que o azul – disse o Francisco.&lt;/div&gt;
&lt;div align=&quot;justify&quot;&gt;
- Não, o azul á maior – contrapôs o João.&lt;/div&gt;
&lt;div align=&quot;justify&quot;&gt;
- Nada disso - sentenciou a Patrícia – ambos têm a mesma área.&lt;/div&gt;
&lt;div align=&quot;justify&quot;&gt;
- Tudo depende do retângulo azul – discordou a Lena – Nuns casos é ele o maior, noutros é o vermelho.&lt;/div&gt;
&lt;div align=&quot;justify&quot;&gt;
Quem tem razão?&lt;/div&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;span style=&quot;font-size: x-small;&quot;&gt;Adaptado de Viana, José (2012), “O Problema Deste Número”. &lt;i&gt;Educação e Matemática&lt;/i&gt;, 117, 41)&lt;/span&gt;&lt;/div&gt;
&lt;span style=&quot;font-size: x-small;&quot;&gt;&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;font-size: x-small;&quot;&gt;Sugestão: experimentar no Geogebra (&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/0081relacao_retangulos.ggb?attredirects=0&amp;amp;d=1&quot;&gt;aqui&lt;/a&gt;)&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0081_Um_retangulo_mais_outro.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/span&gt;</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/5153244988603679690/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/5153244988603679690' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/5153244988603679690'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/5153244988603679690'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/07/um-retangulo-e-mais-outro.html' title='Um retângulo e mais outro'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh6.ggpht.com/-kDzAyrOvP60/UAgVRJSZ5uI/AAAAAAAABfA/y5GaHOX5j3U/s72-c/image_thumb%25255B1%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-143372608691619045</id><published>2012-04-03T19:20:00.001-07:00</published><updated>2012-04-03T19:20:57.439-07:00</updated><title type='text'>União de Blogs de Matemática</title><content type='html'>&lt;a href=&quot;http://ubmatematica.blogspot.pt/&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; margin: 0px 72px 0px 3px; padding-left: 0px; padding-right: 0px; display: inline; float: right; border-top: 0px; border-right: 0px; padding-top: 0px&quot; border=&quot;0&quot; align=&quot;right&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjanbA16afkkaUg4-zxgFweLPsxeNfu5Edry8LkO3-_bnewa5OKj7vI_mfKvbCFB2Lyp_sNDy-IpWqLxWbQCKAzylGfVOv3E-DYl8t_QTI-yXqldGy6PH0aao-N31VWIYSoDo2aJBmbFM3k/s120/Banner_UBM_M1_120.jpg&quot; /&gt;&lt;/a&gt;  &lt;p&gt;&amp;#160;&lt;/p&gt;  &lt;p&gt;A união dos blogs de matemática é uma iniciativa à qual me associo, principalmente porque se trata de um sítio onde podemos encontrar a matemática. Aproveito para convidar o leitor a dar uma olhadela a onde se oferece o mais diversificado conhecimento matemático. Parabéns à &lt;a href=&quot;http://ubmatematica.blogspot.pt/&quot;&gt;UBM&lt;/a&gt;!&lt;/p&gt;  </content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/143372608691619045/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/143372608691619045' title='2 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/143372608691619045'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/143372608691619045'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/04/uniao-de-blogs-de-matematica.html' title='União de Blogs de Matemática'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjanbA16afkkaUg4-zxgFweLPsxeNfu5Edry8LkO3-_bnewa5OKj7vI_mfKvbCFB2Lyp_sNDy-IpWqLxWbQCKAzylGfVOv3E-DYl8t_QTI-yXqldGy6PH0aao-N31VWIYSoDo2aJBmbFM3k/s72-c/Banner_UBM_M1_120.jpg" height="72" width="72"/><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-4642375322200651390</id><published>2012-03-30T03:10:00.003-07:00</published><updated>2012-10-14T03:13:14.597-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="3º ano - Medida [Tempo - unidades de tempo ]"/><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Raciocínio matemático]"/><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Nºs e operações [Números racionais não negativos - Noção e representação de número racional]"/><title type='text'>Horas e minutos</title><content type='html'>&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;Um problema sobre horas pode servir de metodologia para o desenvolvimento de novos conceitos, por exemplo, os racionais. A divisão de uma hora em doze partes iguais, tendo por base o mostrador de um relógio, é de fácil aceitação. Deste modo, não será difícil a perceção de que três dessas divisões são um quarto de hora. Então admitamos a possibilidade de fazer outras leituras como sendo três horas e quatro doze avos ou três horas e um terço. &lt;/span&gt;&lt;/em&gt;&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;Aliás, quando nos perguntam as horas, deveríamos fazer a leitura apenas em horas, a não ser que nos perguntassem também os minutos. &lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;br /&gt;
&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;Seria interessante lançar o desafio aos alunos para utilizarem apenas a unidade - hora - quando medissem o tempo. Querendo uma leitura mais exata, então que se utilize os sessenta avos. &lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;br /&gt;
&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;a href=&quot;http://lh3.ggpht.com/-aCPToKXzKQc/T3WGe99mj7I/AAAAAAAABZo/YEdybftwgRU/s1600-h/image5.png&quot; style=&quot;clear: left; float: left; margin-bottom: 1em; margin-right: 1em;&quot;&gt;&lt;img align=&quot;right&quot; alt=&quot;image&quot; border=&quot;0&quot; height=&quot;209&quot; src=&quot;http://lh5.ggpht.com/-Edj0v1gFtuE/T3WGftj1m1I/AAAAAAAABZw/JPA4qPfyNdM/image_thumb3.png?imgmax=800&quot; style=&quot;background-image: none; border-bottom-width: 0px; border-left-width: 0px; border-right-width: 0px; border-top-width: 0px; display: inline; float: right; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;image&quot; width=&quot;201&quot; /&gt;&lt;/a&gt;&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;O professor António Rico do &lt;a href=&quot;http://www.anossaescola.com/penamacor/index.asp&quot;&gt;Agrupamento de Escolas Ribeiro Sanches de Penamacor&lt;/a&gt;, propõe o seguinte desafio ficando o livre trânsito às conexões matemáticas que cada um desejar fazer.&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;br /&gt;
&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
A Berta esteve a estudar desde as 9h e 45m até às 11h e 05m.&lt;br /&gt;
O Luís começou a estudar meia hora antes da Berta acabar. &lt;br /&gt;
Estudou metade do tempo da Berta.&lt;br /&gt;
Que horas eram quando o Luís acabou de estudar?&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
(&lt;span style=&quot;color: #274e13;&quot;&gt;carregar aplicação em Geogebra para exploração dos racionais no mostrador do relógio&lt;/span&gt; - &lt;a href=&quot;https://sites.google.com/site/sseformat/docs/relogio3.ggb?attredirects=0&amp;amp;d=1&quot;&gt;aqui&lt;/a&gt;)&lt;br /&gt;
&lt;br /&gt;
&lt;div align=&quot;right&quot;&gt;
&lt;span style=&quot;font-size: xx-small;&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0080_horas_minutos.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/span&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/4642375322200651390/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/4642375322200651390' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/4642375322200651390'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/4642375322200651390'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/03/horas-e-minutos.html' title='Horas e minutos'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh5.ggpht.com/-Edj0v1gFtuE/T3WGftj1m1I/AAAAAAAABZw/JPA4qPfyNdM/s72-c/image_thumb3.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-3954495739299551323</id><published>2012-03-25T17:33:00.002-07:00</published><updated>2012-03-26T16:49:34.316-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5º e 6º ano - Capacidades transversais [Raciocínio matemático]"/><category scheme="http://www.blogger.com/atom/ns#" term="5º e 6º ano - Capacidades transversais [Resoluções de problemas]"/><category scheme="http://www.blogger.com/atom/ns#" term="6ºano - Álgebra [Relações e regularidades]"/><title type='text'>O dobro de</title><content type='html'>&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt; Alguma vez a&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt; idade de um pai&amp;nbsp; poderá ser&lt;/span&gt;&lt;/em&gt; o dobro da idade do seu filho? E no caso de ser o triplo? E o quádruplo? E o quíntuplo? Todas estas situações poderão ocorrer durante a vida do pai? &lt;a href=&quot;http://lh4.ggpht.com/-Of4fxE5HG4w/T2-5TJpIneI/AAAAAAAABZY/jfPqqIYZF1M/s1600-h/image%25255B5%25255D.png&quot;&gt;&lt;img align=&quot;right&quot; alt=&quot;image&quot; border=&quot;0&quot; height=&quot;205&quot; src=&quot;http://lh5.ggpht.com/-5L3GB8cJo0Y/T2-5T3oOCzI/AAAAAAAABZc/gehFjlWMcqE/image_thumb%25255B3%25255D.png?imgmax=800&quot; style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; border-right: 0px; border-top: 0px; display: inline; float: right; margin: 0px 0px 27px 28px; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;image&quot; width=&quot;172&quot; /&gt;&lt;/a&gt;&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;Estas são algumas questões que poderão ser motivo para despoletar uma atividade de investigação em ambiente de sala de aula. &lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;Para começar propõe-se então o seguinte problema:&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
&lt;em&gt;&lt;span style=&quot;color: blue;&quot;&gt;&lt;br /&gt;
&lt;/span&gt;&lt;/em&gt;&lt;br /&gt;
O Afonso tem 19 anos e o seu pai 44. Quando é que o pai tem o dobro da idade do filho?&lt;br /&gt;
&lt;b&gt;&lt;/b&gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;div align=&quot;right&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.079_odobro_de.pdf?attredirects=0&amp;amp;d=1&quot;&gt;&lt;span style=&quot;font-size: x-small;&quot;&gt;proposta de resolução&lt;/span&gt;&lt;/a&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/3954495739299551323/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/3954495739299551323' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/3954495739299551323'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/3954495739299551323'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2012/03/o-dobro-de.html' title='O dobro de'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh5.ggpht.com/-5L3GB8cJo0Y/T2-5T3oOCzI/AAAAAAAABZc/gehFjlWMcqE/s72-c/image_thumb%25255B3%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-7172177642044384729</id><published>2011-12-11T06:08:00.001-08:00</published><updated>2011-12-11T06:10:33.994-08:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="5º e 6º ano - Capacidades transversais [Comunicação matemática]"/><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Nºs e operações [Números naturais - Critérios de divisibilidade]"/><title type='text'>Anos bissextos</title><content type='html'>&lt;p align=&quot;justify&quot;&gt;&lt;a href=&quot;http://lh5.ggpht.com/-dVVcmZ8mhc0/TuS5Qg2Sr8I/AAAAAAAABYk/PLSVAmTIgIc/s1600-h/image%25255B3%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; margin: 2px 22px 0px 0px; padding-left: 0px; padding-right: 0px; display: inline; float: left; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;image&quot; border=&quot;0&quot; alt=&quot;image&quot; align=&quot;left&quot; src=&quot;http://lh5.ggpht.com/-07SpW6JYmK8/TuS5RYDDS-I/AAAAAAAABYs/hVj2Qu5NoX4/image_thumb%25255B1%25255D.png?imgmax=800&quot; width=&quot;340&quot; height=&quot;252&quot; /&gt;&lt;/a&gt;A duração aproximada de um ano é de 365 dias e 6 horas. Ao fim de quatro anos temos mais um dia a acrescentar ao calendário – ano bissexto. &lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;Em bom rigor não são bem 6 horas, mas sim 5 horas, 48 minutos e pouco mais de 45 segundos. Esta diferença, ao longo de 100 anos, adianta aproximadamente 18,5 horas ao calendário. É por isso que de 100 em 100 anos não se acrescenta um dia ao calendário, como seria a regra. Assim deixaremos de andar quase um dia adiantados. Mas a diferença deste “quase” ao longo de 4 séculos faz com que falte aproximadamente um dia no calendário. É por isso que nos anos múltiplos de 400, embora sejam múltiplos de 100, continuam a ser bissextos. &lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;Com estes acertos no calendário ainda ficamos a acumular tempo que vai corresponder aproximadamente a um dia ao fim de 3300 anos. &lt;a href=&quot;http://www.oal.ul.pt/download/O_Ano_Bissexto.pdf&quot;&gt;Nessa altura, haverá outra exceção à regra&lt;/a&gt;&amp;#160; - um dos anos bissextos deixará de o ser. Para já, a regra a ter em conta é a seguinte:&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;· São bissextos todos os anos múltiplos de 400;&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;· São bissextos todos os múltiplos de 4 e não múltiplos de 100;&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;De acordo com a informação do texto, responde às seguintes questões:&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;1. O ano 2000 foi bissexto? Porquê?&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;2. O ano 2100 vai ser bissexto? Porquê?&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;3. Qual vai ser o próximo ano bissexto? Porquê?&lt;/p&gt;  &lt;p align=&quot;justify&quot;&gt;&lt;a href=&quot;http://lh4.ggpht.com/-2TpLyyqicog/TuS5SJq3pKI/AAAAAAAABY0/uBvV2d9gDMI/s1600-h/anobissexto%25255B3%25255D.png&quot;&gt;&lt;img style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; margin: 0px 11px 0px 0px; padding-left: 0px; padding-right: 0px; display: inline; float: left; border-top: 0px; border-right: 0px; padding-top: 0px&quot; title=&quot;anobissexto&quot; border=&quot;0&quot; alt=&quot;anobissexto&quot; align=&quot;left&quot; src=&quot;http://lh5.ggpht.com/-l2CdXUOsFXo/TuS5S27xR5I/AAAAAAAABY4/PcxUK1ARK1g/anobissexto_thumb%25255B1%25255D.png?imgmax=800&quot; width=&quot;250&quot; height=&quot;83&quot; /&gt;&lt;/a&gt;&lt;em&gt;Nota: o conhecimento do critério de divisibilidade por 4 é muito útil para saber se um determinado ano é ou não bissexto. Clica &lt;/em&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/bissexto.xlsx?attredirects=0&amp;amp;d=1&quot;&gt;&lt;em&gt;aqui&lt;/em&gt;&lt;/a&gt;&lt;em&gt; para confirmar, numa aplicação, os anos que são bissextos.&lt;/em&gt;&lt;/p&gt;  </content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/7172177642044384729/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/7172177642044384729' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/7172177642044384729'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/7172177642044384729'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2011/12/anos-bissextos.html' title='Anos bissextos'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh5.ggpht.com/-07SpW6JYmK8/TuS5RYDDS-I/AAAAAAAABYs/hVj2Qu5NoX4/s72-c/image_thumb%25255B1%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-9205530794413046866</id><published>2011-08-08T18:11:00.001-07:00</published><updated>2011-08-08T18:34:38.841-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Comunicação matemática]"/><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Raciocínio matemático]"/><category scheme="http://www.blogger.com/atom/ns#" term="4º e 5º ano - Capacidades transversais [Resoluções de problemas]"/><category scheme="http://www.blogger.com/atom/ns#" term="5ºano - Nºs e operações [Números naturais - Critérios de divisibilidade]"/><category scheme="http://www.blogger.com/atom/ns#" term="Conc. - classes de resto"/><category scheme="http://www.blogger.com/atom/ns#" term="Conc. - divisão"/><category scheme="http://www.blogger.com/atom/ns#" term="Pensamento algébrico"/><title type='text'>Empilhar cubos</title><content type='html'>&lt;p&gt;&lt;a href=&quot;http://lh5.ggpht.com/-BCrBok_CZJA/TkCJPh9KwbI/AAAAAAAABXU/ZX0GPGQhqLw/s1600-h/image%25255B7%25255D.png&quot;&gt;&lt;img style=&quot;display: inline; float: right&quot; title=&quot;image&quot; alt=&quot;image&quot; align=&quot;right&quot; src=&quot;http://lh4.ggpht.com/-ackmYcorBPY/TkCJQFXzJhI/AAAAAAAABXY/ZbTH5yFIglM/image_thumb%25255B5%25255D.png?imgmax=800&quot; width=&quot;197&quot; height=&quot;186&quot; /&gt;&lt;/a&gt;Depois da aula de matemática, o Afonso e o Miguel ficaram a brincar com os cubos do material Cuisenaire que tinham em cima da mesa. &lt;/p&gt;  &lt;p&gt;Foram empilhando os cubos para construir uma torre, mas verificaram que lhes faltavam alguns cubos para completarem a última camada como mostra a figura.&lt;/p&gt;  &lt;p&gt;Das opções seguintes, escolhe o número que representa a quantidade de cubos disponíveis que os dois amigos tinham para brincar. Justifica a tua escolha.&lt;/p&gt;  &lt;p&gt;a) 116&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160; b) 122&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160; c) 130&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160;&amp;#160; d) 144&lt;/p&gt;  &lt;p align=&quot;right&quot;&gt;&lt;font size=&quot;2&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0077_empilhar_cubos.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/font&gt;&lt;/p&gt;  </content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/9205530794413046866/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/9205530794413046866' title='1 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/9205530794413046866'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/9205530794413046866'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2011/08/empilhar-cubos.html' title='Empilhar cubos'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh4.ggpht.com/-ackmYcorBPY/TkCJQFXzJhI/AAAAAAAABXY/ZbTH5yFIglM/s72-c/image_thumb%25255B5%25255D.png?imgmax=800" height="72" width="72"/><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-6364351871661290591</id><published>2011-07-31T15:53:00.001-07:00</published><updated>2011-08-07T13:27:40.958-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="3º e 4º ano - Capacidades transversais [Comunicação matemática]"/><category scheme="http://www.blogger.com/atom/ns#" term="3º e 4º ano - Capacidades transversais [Resoluções de problemas]"/><category scheme="http://www.blogger.com/atom/ns#" term="4º ano - Nºs e operações [Números racionais não Negativos - fracções]"/><title type='text'>Na passagem de ano</title><content type='html'>&lt;a href=&quot;http://lh4.ggpht.com/-WwfnXAywsI0/TjXc5SatffI/AAAAAAAABW4/mHP7RlUdQjc/s1600-h/image%25255B3%25255D.png&quot;&gt;&lt;img align=&quot;left&quot; alt=&quot;image&quot; border=&quot;0&quot; height=&quot;188&quot; src=&quot;http://lh4.ggpht.com/-VHPUuur6zHo/TjXc6ASudqI/AAAAAAAABW8/WucmTY65Z4E/image_thumb%25255B1%25255D.png?imgmax=800&quot; style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; border-right: 0px; border-top: 0px; display: inline; float: left; margin: 0px 24px 0px 0px; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;image&quot; width=&quot;268&quot; /&gt;&lt;/a&gt;Às 00H00 do dia 1 de Janeiro de 2011 o João comenta com o pai:&lt;br /&gt;
&lt;br /&gt;
- faltam 11 minutos para eu fazer 11 anos.&lt;br /&gt;
&lt;br /&gt;
- É precisamente uma terça parte da minha idade - disse o pai.&lt;br /&gt;
&lt;br /&gt;
O mais curioso é que o pai do João também é João e faz anos no dia de S. João.&lt;br /&gt;
&lt;br /&gt;
Em que ano nasceu o pai do João?&lt;br /&gt;
&lt;div align=&quot;right&quot;&gt;&lt;br /&gt;
&lt;/div&gt;&lt;div align=&quot;right&quot;&gt;&lt;span style=&quot;font-size: x-small;&quot;&gt;&lt;a href=&quot;https://sites.google.com/site/sseformat/docs/sol.0076_passagem_ano.pdf?attredirects=0&amp;amp;d=1&quot;&gt;proposta de resolução&lt;/a&gt;&lt;/span&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/6364351871661290591/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/6364351871661290591' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6364351871661290591'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6364351871661290591'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2011/07/na-passagem-de-ano.html' title='Na passagem de ano'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh4.ggpht.com/-VHPUuur6zHo/TjXc6ASudqI/AAAAAAAABW8/WucmTY65Z4E/s72-c/image_thumb%25255B1%25255D.png?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-2988068197238554407.post-6962630380721125635</id><published>2011-05-31T11:46:00.001-07:00</published><updated>2011-05-31T11:52:04.511-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="6º ano - Geometria [Reflexão; rotação e translação]"/><category scheme="http://www.blogger.com/atom/ns#" term="Applets"/><title type='text'>onde estão as simetrias?</title><content type='html'>&lt;a href=&quot;http://lh4.ggpht.com/-yrarP3efgiY/TeU3eIP-QxI/AAAAAAAABTE/ScsEI2MuoyU/s1600-h/reflexao6%25255B3%25255D.jpg&quot;&gt;&lt;img align=&quot;right&quot; alt=&quot;reflexao6&quot; border=&quot;0&quot; height=&quot;169&quot; src=&quot;http://lh3.ggpht.com/-3iXTzCl8sC4/TeU3eieXSUI/AAAAAAAABTI/FDAsAZreYXs/reflexao6_thumb%25255B1%25255D.jpg?imgmax=800&quot; style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; border-right: 0px; border-top: 0px; display: inline; float: right; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;reflexao6&quot; width=&quot;268&quot; /&gt;&lt;/a&gt;&lt;a href=&quot;http://lh4.ggpht.com/-hOl8Vx5uu7Q/TeU3fkrcz5I/AAAAAAAABTM/t78ay2c4eMg/s1600-h/reflexao5%25255B4%25255D.jpg&quot;&gt;&lt;img align=&quot;right&quot; alt=&quot;reflexao5&quot; border=&quot;0&quot; height=&quot;167&quot; src=&quot;http://lh5.ggpht.com/-fN0UEPvkjXE/TeU3gFbXfKI/AAAAAAAABTQ/IsVCDz_FdvI/reflexao5_thumb%25255B2%25255D.jpg?imgmax=800&quot; style=&quot;background-image: none; border-bottom: 0px; border-left: 0px; border-right: 0px; border-top: 0px; display: inline; float: right; margin: 0px 0px 0px 8px; padding-left: 0px; padding-right: 0px; padding-top: 0px;&quot; title=&quot;reflexao5&quot; width=&quot;265&quot; /&gt;&lt;/a&gt;&lt;br /&gt;
Prorurar simetrias em figuras, ou criar figuras com simetrias, pode ser uma atividade de grande potencial matemático recorrendo apenas a este &lt;a href=&quot;http://dl.dropbox.com/u/7039899/aplicacoes/mat_simetria2.exe&quot;&gt;applet aqui disponível&lt;/a&gt;. &lt;br /&gt;
&lt;br /&gt;
Esta ferramenta permite a verificação rápida de uma reflexão feita pelo aluno tendo como suporte uma malha quadrangular. &lt;br /&gt;
&lt;br /&gt;
O eixo de reflexão pode ser manuseado pelo utilizador em torno de um ponto permitindo também a exploração de rotações e a verificação de simetrias rotacionais.</content><link rel='replies' type='application/atom+xml' href='http://sseformat.blogspot.com/feeds/6962630380721125635/comments/default' title='Enviar feedback'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment/fullpage/post/2988068197238554407/6962630380721125635' title='0 Comentários'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6962630380721125635'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/2988068197238554407/posts/default/6962630380721125635'/><link rel='alternate' type='text/html' href='http://sseformat.blogspot.com/2011/05/onde-estao-as-simetrias.html' title='onde estão as simetrias?'/><author><name>J. Filipe</name><uri>http://www.blogger.com/profile/16679502228031863129</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='27' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh-Al4ZJ6PnlibxMeVLH_R9P9GiCVrwtEVdHhwhT-aP0Wj_camRhWJ7ryIECGRuCqnk_BIl7LKAbxvRobTkdPbSC3gYk5Qo3x_p_7BovFpKGFP4sYmglYjk6YL18lN-nL8/s220/Foto1.JF2010.12.png'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="http://lh3.ggpht.com/-3iXTzCl8sC4/TeU3eieXSUI/AAAAAAAABTI/FDAsAZreYXs/s72-c/reflexao6_thumb%25255B1%25255D.jpg?imgmax=800" height="72" width="72"/><thr:total>0</thr:total></entry></feed>