<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:blogger='http://schemas.google.com/blogger/2008' xmlns:georss='http://www.georss.org/georss' xmlns:gd="http://schemas.google.com/g/2005" xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-4710016337793683220</id><updated>2026-10-16T15:16:30.461-07:00</updated><category term="cbse"/><category term="ISI"/><category term="IIT"/><category term="ISC"/><category term="ICSE"/><category term="X"/><category term="WBJEE"/><category term="geometry"/><category term="XI"/><category term="maths"/><category term="algebra"/><category term="IX"/><category term="Madhyamik"/><category term="XII"/><category term="AIEEE"/><category term="INTEGRATION"/><category term="HS"/><category term="JEE Main"/><category term="mathematics"/><category term="trigonometry"/><category term="WBCHSE"/><category term="solved problems"/><category term="10th Grade"/><category term="AIEEE Mock Test Paper 2011"/><category term="B.Math"/><category term="B.Sc. 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CBSE"/><category term="JAM"/><category term="JECA"/><category term="JNU"/><category term="KIITEE-2011"/><category term="Lagrange Theorem"/><category term="Limits"/><category term="Linear Algebra"/><category term="L’Hospital’s rule"/><category term="MATHS PAPER 2019"/><category term="MCA"/><category term="Multinomial"/><category term="NIMCET"/><category term="NMMSE"/><category term="NTSE"/><category term="Pigeon Hole Principle"/><category term="Practice"/><category term="QUADRILATERALS"/><category term="Question Paper"/><category term="SECONDARY"/><category term="Sample"/><category term="Sets"/><category term="Short"/><category term="Short answer"/><category term="Special"/><category term="St.Xavier&#39;s"/><category term="Syllabus"/><category term="Thales theorem"/><category term="VII"/><category term="Vector space"/><category term="Vectors"/><category term="WBBSE"/><category term="altitudes"/><category term="analysis"/><category term="answer"/><category term="circular Co-ordinate"/><category term="circumcentre"/><category term="combinatorics"/><category term="complex numbers"/><category term="cpt coaching kolkata"/><category term="definite integration"/><category term="derivative"/><category term="detail"/><category term="distance"/><category term="events"/><category term="exponential  binomial"/><category term="formula  area"/><category term="gcd"/><category term="group theory"/><category term="harder  integration  mock test  a.p  g.p  cbse  isc  maths  tuition  kolkata"/><category term="harder problems"/><category term="independence"/><category term="infinite"/><category term="integer solution"/><category term="inverse"/><category term="locus"/><category term="median"/><category term="orthocentre  circumcentre"/><category term="perfect squares"/><category term="principle of inclusion exclusion"/><category term="private"/><category term="properties"/><category term="rational"/><category term="real"/><category term="reflection"/><category term="series"/><category term="solution"/><category term="solutions"/><category term="solved"/><category term="solved paper 2011"/><category term="solved problem"/><category term="symmetry"/><category term="triangles"/><category term="type"/><title type='text'>Prime Maths</title><subtitle type='html'>Welcome to Prime Maths, your ultimate destination for mastering mathematics. We provide comprehensive, step-by-step sol&#xa;Entrance Exam Solutions: Solved Problems for ISI B.Math/B.Stat, CMI, JEE (IIT), Olympiads, and CBSE/ISC/ICSE Mathematics Board Papers.&#xa;&#xa;Practice Problems and Chapter Test on various topics for CBSE, ICSE, Madhyamik, HS and ISC students</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default?redirect=false'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><link rel='next' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default?start-index=26&amp;max-results=25&amp;redirect=false'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>298</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-6750890977982628961</id><published>2026-09-01T21:06:27.339-07:00</published><updated>2026-09-01T21:17:05.771-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="XI"/><category scheme="http://www.blogger.com/atom/ns#" term="XII"/><title type='text'>Master NDA Mathematics: The Ultimate Collection of Past Papers</title><content type='html'>&lt;style&gt;
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&lt;div class=&quot;prime-maths-nda-page&quot;&gt;
    &lt;!-- ===== HERO SECTION ===== --&gt;
    &lt;section class=&quot;hero&quot;&gt;
        &lt;div class=&quot;hero-content&quot;&gt;
            &lt;div class=&quot;hero-badge&quot;&gt;
                &lt;span&gt;🎯 Prime Maths Academy&lt;/span&gt;
            &lt;/div&gt;
            &lt;h1&gt;
                Master &lt;span class=&quot;accent&quot;&gt;NDA Mathematics | Jai Hind!&lt;/span&gt;&lt;br&gt;
                The Ultimate Collection of Past Papers
            &lt;/h1&gt;
            &lt;p class=&quot;subtitle&quot;&gt;
                Clearing the NDA Mathematics paper is never an accident — it is the result of
                &lt;strong style=&quot;color: var(--gold-light);&quot;&gt;focused, intelligent, and strategic practice&lt;/strong&gt;.
                Transition from board exams to the competitive rigor of UPSC NDA with our meticulously
                curated archive of authentic past papers.
            &lt;/p&gt;
            &lt;div class=&quot;hero-stats&quot;&gt;
                &lt;div class=&quot;stat-item&quot;&gt;
                    &lt;div class=&quot;stat-number&quot;&gt;120+&lt;/div&gt;
                    &lt;div class=&quot;stat-label&quot;&gt;Questions per Paper&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;stat-item&quot;&gt;
                    &lt;div class=&quot;stat-number&quot;&gt;2.5&lt;/div&gt;
                    &lt;div class=&quot;stat-label&quot;&gt;Hours Time Limit&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;stat-item&quot;&gt;
                    &lt;div class=&quot;stat-number&quot;&gt;10+&lt;/div&gt;
                    &lt;div class=&quot;stat-label&quot;&gt;Years of Papers&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;stat-item&quot;&gt;
                    &lt;div class=&quot;stat-number&quot;&gt;8&lt;/div&gt;
                    &lt;div class=&quot;stat-label&quot;&gt;Core Topic Areas&lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            &lt;br&gt;
            &lt;a href=&quot;https://sites.google.com/view/primemaths/math-xi-xii/nda&quot; target=&quot;_blank&quot; class=&quot;btn-primary&quot;&gt;Explore the Archive →&lt;/a&gt;
        &lt;/div&gt;
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    &lt;!-- ===== EDUCATOR QUOTE ===== --&gt;
    &lt;section class=&quot;section section-dark&quot; style=&quot;padding-bottom: 30px;&quot;&gt;
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            &lt;div class=&quot;educator-quote&quot;&gt;
                &lt;blockquote&gt;
                    &quot;As an educator, I have seen firsthand that clearing the NDA Mathematics paper is never an
                    accident — it is the result of focused, intelligent, and strategic practice. The transition from
                    standard Class XI and XII board exams to the competitive rigor of the UPSC NDA examination
                    requires a massive shift from lengthy, step-by-step solving to rapid, objective, and analytical
                    thinking.&quot;
                &lt;/blockquote&gt;
                &lt;div class=&quot;quote-author&quot;&gt;Vinod Singh — Prime Maths&lt;/div&gt;
            &lt;/div&gt;
        &lt;/div&gt;
    &lt;/section&gt;

    &lt;!-- ===== RESOURCES SECTION ===== --&gt;
    &lt;section class=&quot;section section-light&quot; id=&quot;resources&quot;&gt;
        &lt;div class=&quot;container&quot;&gt;
            &lt;div class=&quot;section-header&quot;&gt;
                &lt;div class=&quot;section-tag&quot;&gt;📚 The Archive&lt;/div&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;What You Will Find in Our NDA Mathematics Archive&lt;/h2&gt;
                &lt;p class=&quot;section-subtitle&quot;&gt;
                    Our dedicated repository is structured to streamline your revision process. Here&#39;s what makes
                    this resource an essential part of your study toolkit.
                &lt;/p&gt;
            &lt;/div&gt;

            &lt;div class=&quot;resource-grid&quot;&gt;
                &lt;!-- Card 1: Year-Wise --&gt;
                &lt;div class=&quot;resource-card&quot;&gt;
                    &lt;div class=&quot;card-icon&quot;&gt;📅&lt;/div&gt;
                    &lt;h3&gt;Year-Wise Collections&lt;/h3&gt;
                    &lt;p&gt;
                        Access a meticulously organized vault of past NDA mathematics question papers,
                        including &lt;span class=&quot;highlight&quot;&gt;recent Phase I and Phase II exams&lt;/span&gt;. Every
                        paper is preserved in its original format for authentic practice.
                    &lt;/p&gt;
                &lt;/div&gt;

                &lt;!-- Card 2: Topic-Wise --&gt;
                &lt;div class=&quot;resource-card&quot;&gt;
                    &lt;div class=&quot;card-icon&quot;&gt;🎯&lt;/div&gt;
                    &lt;h3&gt;Topic-Wise Segregation&lt;/h3&gt;
                    &lt;p&gt;
                        Beyond full papers, dive into content categorized by crucial sections. This allows you to
                        &lt;span class=&quot;highlight&quot;&gt;aggressively target your weakest areas&lt;/span&gt; and build
                        mastery topic by topic.
                    &lt;/p&gt;
                    &lt;div class=&quot;topic-chips&quot;&gt;
                        &lt;span class=&quot;topic-chip&quot;&gt;Sets &amp; Relations&lt;/span&gt;
                        &lt;span class=&quot;topic-chip&quot;&gt;Algebra&lt;/span&gt;
                        &lt;span class=&quot;topic-chip&quot;&gt;Trigonometry&lt;/span&gt;
                        &lt;span class=&quot;topic-chip&quot;&gt;Calculus&lt;/span&gt;
                        &lt;span class=&quot;topic-chip&quot;&gt;2D Geometry&lt;/span&gt;
                        &lt;span class=&quot;topic-chip&quot;&gt;3D Geometry&lt;/span&gt;
                        &lt;span class=&quot;topic-chip&quot;&gt;Probability&lt;/span&gt;
                        &lt;span class=&quot;topic-chip&quot;&gt;Statistics&lt;/span&gt;
                    &lt;/div&gt;
                &lt;/div&gt;

                &lt;!-- Card 3: Authentic Format --&gt;
                &lt;div class=&quot;resource-card&quot;&gt;
                    &lt;div class=&quot;card-icon&quot;&gt;📋&lt;/div&gt;
                    &lt;h3&gt;Authentic Format&lt;/h3&gt;
                    &lt;p&gt;
                        Every problem is presented &lt;span class=&quot;highlight&quot;&gt;exactly as it appeared on the official
                        UPSC examinations&lt;/span&gt;, giving you a true sense of the required academic rigor and
                        complexity demanded by the examiners.
                    &lt;/p&gt;
                &lt;/div&gt;

                &lt;!-- Card 4: Targeted Practice --&gt;
                &lt;div class=&quot;resource-card&quot;&gt;
                    &lt;div class=&quot;card-icon&quot;&gt;⚡&lt;/div&gt;
                    &lt;h3&gt;Targeted Practice&lt;/h3&gt;
                    &lt;p&gt;
                        Practicing with these structured materials helps you &lt;span class=&quot;highlight&quot;&gt;decode question
                        patterns&lt;/span&gt; and understand exactly what the examiners demand in terms of conceptual
                        clarity and shortcut application.
                    &lt;/p&gt;
                &lt;/div&gt;
            &lt;/div&gt;

            &lt;!-- Exam Info Banner --&gt;
            &lt;div class=&quot;exam-info-banner&quot;&gt;
                &lt;div class=&quot;exam-info-text&quot;&gt;
                    &lt;h3&gt;⚔️ Know Your Battlefield&lt;/h3&gt;
                    &lt;p&gt;
                        The NDA Mathematics paper is notorious for its brutal time constraint.
                        Familiarize yourself with the exact structure before you step in.
                    &lt;/p&gt;
                &lt;/div&gt;
                &lt;div class=&quot;exam-info-badge&quot;&gt;
                    &lt;div class=&quot;number&quot;&gt;120&lt;/div&gt;
                    &lt;div class=&quot;label&quot;&gt;Questions&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;exam-info-badge&quot;&gt;
                    &lt;div class=&quot;number&quot;&gt;2.5 hrs&lt;/div&gt;
                    &lt;div class=&quot;label&quot;&gt;Duration&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;exam-info-badge&quot;&gt;
                    &lt;div class=&quot;number&quot;&gt;-0.83&lt;/div&gt;
                    &lt;div class=&quot;label&quot;&gt;Negative Marking&lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
        &lt;/div&gt;
    &lt;/section&gt;

    &lt;!-- ===== TOPICS DETAIL SECTION ===== --&gt;
    &lt;section class=&quot;section section-white&quot;&gt;
        &lt;div class=&quot;container&quot;&gt;
            &lt;div class=&quot;section-header&quot;&gt;
                &lt;div class=&quot;section-tag&quot;&gt;🧠 Core Topics&lt;/div&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;Master Every Critical Area&lt;/h2&gt;
                &lt;p class=&quot;section-subtitle&quot;&gt;
                    Our archive covers every topic that appears in the NDA Mathematics syllabus.
                    Focus your preparation on high-weightage areas first.
                &lt;/p&gt;
            &lt;/div&gt;

            &lt;div class=&quot;topics-detail-grid&quot;&gt;
                &lt;div class=&quot;topic-detail-item&quot;&gt;
                    &lt;div class=&quot;topic-name&quot;&gt;Sets, Relations &amp; Functions&lt;/div&gt;
                    &lt;div class=&quot;topic-weight&quot;&gt;High Weightage&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;topic-detail-item&quot;&gt;
                    &lt;div class=&quot;topic-name&quot;&gt;Algebra&lt;/div&gt;
                    &lt;div class=&quot;topic-weight&quot;&gt;Very High Weightage&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;topic-detail-item&quot;&gt;
                    &lt;div class=&quot;topic-name&quot;&gt;Trigonometry&lt;/div&gt;
                    &lt;div class=&quot;topic-weight&quot;&gt;High Weightage&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;topic-detail-item&quot;&gt;
                    &lt;div class=&quot;topic-name&quot;&gt;Calculus&lt;/div&gt;
                    &lt;div class=&quot;topic-weight&quot;&gt;Very High Weightage&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;topic-detail-item&quot;&gt;
                    &lt;div class=&quot;topic-name&quot;&gt;2D Geometry&lt;/div&gt;
                    &lt;div class=&quot;topic-weight&quot;&gt;Medium Weightage&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;topic-detail-item&quot;&gt;
                    &lt;div class=&quot;topic-name&quot;&gt;3D Geometry&lt;/div&gt;
                    &lt;div class=&quot;topic-weight&quot;&gt;Medium Weightage&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;topic-detail-item&quot;&gt;
                    &lt;div class=&quot;topic-name&quot;&gt;Probability&lt;/div&gt;
                    &lt;div class=&quot;topic-weight&quot;&gt;High Weightage&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;topic-detail-item&quot;&gt;
                    &lt;div class=&quot;topic-name&quot;&gt;Statistics&lt;/div&gt;
                    &lt;div class=&quot;topic-weight&quot;&gt;Medium Weightage&lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
        &lt;/div&gt;
    &lt;/section&gt;

    &lt;!-- ===== BENEFITS SECTION ===== --&gt;
    &lt;section class=&quot;section section-dark&quot; id=&quot;benefits&quot;&gt;
        &lt;div class=&quot;container&quot;&gt;
            &lt;div class=&quot;section-header&quot;&gt;
                &lt;div class=&quot;section-tag&quot;&gt;🏆 Why Past Papers Work&lt;/div&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;The Real Benefits of Solving Past Papers&lt;/h2&gt;
                &lt;p class=&quot;section-subtitle&quot;&gt;
                    Dedicating consistent time to this archive will fundamentally transform your approach
                    to the subject. Here&#39;s how.
                &lt;/p&gt;
            &lt;/div&gt;

            &lt;div class=&quot;benefits-grid&quot;&gt;
                &lt;!-- Benefit 1 --&gt;
                &lt;div class=&quot;benefit-card&quot;&gt;
                    &lt;div class=&quot;benefit-number&quot;&gt;01&lt;/div&gt;
                    &lt;h3&gt;🧘 Eliminate Exam Anxiety&lt;/h3&gt;
                    &lt;p&gt;
                        The unknown is the biggest source of stress. By repeatedly exposing yourself to the
                        &lt;span class=&quot;key-point&quot;&gt;authentic formatting and phrasing&lt;/span&gt; of NDA questions,
                        the final UPSC exam will feel like just another practice session. Familiarity breeds
                        confidence.
                    &lt;/p&gt;
                &lt;/div&gt;

                &lt;!-- Benefit 2 --&gt;
                &lt;div class=&quot;benefit-card&quot;&gt;
                    &lt;div class=&quot;benefit-number&quot;&gt;02&lt;/div&gt;
                    &lt;h3&gt;⏱️ Master Time Management &amp; Accuracy&lt;/h3&gt;
                    &lt;p&gt;
                        The NDA Mathematics paper is notorious for its brutal time constraint —
                        &lt;span class=&quot;key-point&quot;&gt;120 questions in just 2.5 hours&lt;/span&gt;, coupled with strict
                        negative marking. Setting a timer while tackling these past papers will train your brain
                        to optimize speed, teaching you exactly which questions to attempt immediately and which
                        time-traps to skip.
                    &lt;/p&gt;
                &lt;/div&gt;

                &lt;!-- Benefit 3 --&gt;
                &lt;div class=&quot;benefit-card&quot;&gt;
                    &lt;div class=&quot;benefit-number&quot;&gt;03&lt;/div&gt;
                    &lt;h3&gt;🔍 Identify Recurring Concepts&lt;/h3&gt;
                    &lt;p&gt;
                        While the exact numbers change, the core concepts and specific application tricks tested
                        &lt;span class=&quot;key-point&quot;&gt;repeat year after year&lt;/span&gt;. Working through this collection
                        will quickly reveal the high-weightage topics and recurring models you absolutely cannot
                        afford to miss on exam day.
                    &lt;/p&gt;
                &lt;/div&gt;
            &lt;/div&gt;
        &lt;/div&gt;
    &lt;/section&gt;

    &lt;!-- ===== CTA SECTION ===== --&gt;
    &lt;section class=&quot;cta-section&quot;&gt;
        &lt;div class=&quot;container&quot;&gt;
            &lt;h2&gt;Your Journey to NDA Success Starts Here&lt;/h2&gt;
            &lt;p&gt;
                Join thousands of aspirants who have transformed their preparation with authentic past papers.
                The path to mastering NDA Mathematics is not about luck — it&#39;s about practice, strategy, and
                consistency.
            &lt;/p&gt;
            &lt;a href=&quot;https://sites.google.com/view/primemaths/math-xi-xii/nda&quot; target=&quot;_blank&quot; class=&quot;btn-secondary&quot;&gt;Start Practicing Today →&lt;/a&gt;
            &lt;br&gt;&lt;br&gt;
            &lt;p style=&quot;font-size: 0.75rem; color: rgba(200,200,210,0.6); letter-spacing: 1px;&quot;&gt;
                📍 Prime Maths Academy — Empowering Future Officers
            &lt;/p&gt;
        &lt;/div&gt;
    &lt;/section&gt;
&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/6750890977982628961/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/09/master-nda-mathematics-ultimate.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/6750890977982628961'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/6750890977982628961'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/09/master-nda-mathematics-ultimate.html' title='Master NDA Mathematics: The Ultimate Collection of Past Papers'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-4302514706115008432</id><published>2026-08-07T23:07:47.306-07:00</published><updated>2026-08-08T09:51:39.223-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="IX"/><category scheme="http://www.blogger.com/atom/ns#" term="VIII"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Competency Focused Problems for classes VIII - IX</title><content type='html'>&lt;!-- MathJax Configuration and Loader --&gt;
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            &lt;div class=&quot;quiz-title&quot;&gt;📐 Mathematics &lt;span&gt;Quiz- Competency Focused Problems for classes VIII - IX - ICSE - CBSE &lt;/span&gt;&lt;/div&gt;
            &lt;div class=&quot;progress-indicator&quot; id=&quot;progress-indicator&quot;&gt;Question 1 / 20&lt;/div&gt;
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&lt;/script&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/4302514706115008432/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/08/competency-focused-problems-for-classes.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/4302514706115008432'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/4302514706115008432'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/08/competency-focused-problems-for-classes.html' title='Competency Focused Problems for classes VIII - IX'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-6115128241263944416</id><published>2026-05-25T08:34:10.749-07:00</published><updated>2026-08-08T09:55:47.396-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Competency Focused Questions for CBSE and ICSE Class X</title><content type='html'>
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    &lt;h1&gt;Class X Mathematics Competency-Based Questions&lt;/h1&gt;
    &lt;p&gt;Focus on real-life application, analysis, and conceptual clarity for CBSE &amp; ICSE.&lt;/p&gt;

    &lt;h2&gt;Real Numbers&lt;/h2&gt;
    &lt;ol&gt;
        &lt;li&gt;&lt;strong&gt;HCF &amp; LCM Application:&lt;/strong&gt; Three alarm clocks ring at intervals of 12 minutes, 18 minutes, and 24 minutes respectively. If they ring together at 8:00 AM, at what time will they next ring together? Also, find the total number of times they ring together between 8:00 AM and 8:00 PM.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Irrationality Proof:&lt;/strong&gt; Prove that \( \sqrt{5} \) is irrational. Hence, show that \( 3 + 2\sqrt{5} \) is also irrational.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Rational Numbers as Decimals:&lt;/strong&gt; Without actual division, determine if the rational number \( \frac{129}{2^3 \times 5^4 \times 7} \) has a terminating or non-terminating decimal expansion. Justify.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Word Problem on LCM:&lt;/strong&gt; A rectangular courtyard measures 18 m 72 cm × 13 m 20 cm. Exactly square tiles of the same size are required to pave it. Find the least possible number of such tiles.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Competency: Reasoning:&lt;/strong&gt; Can two numbers have 18 as their HCF and 450 as their LCM? Give reasons.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Polynomials&lt;/h2&gt;
    &lt;ol start=&quot;6&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Graphical Interpretation:&lt;/strong&gt; The graph of a quadratic polynomial \( p(x) \) passes through \( (0, -6) \), \( (1, 0) \), and \( (2, 0) \). Find the polynomial and the sum of its zeroes.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Relation between zeroes &amp; coefficients:&lt;/strong&gt; If \( \alpha \) and \( \beta \) are zeroes of \( x^2 - 6x + k \) such that \( 3\alpha + 2\beta = 20 \), find the value of \( k \).&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Division Algorithm:&lt;/strong&gt; When \( x^3 - 2x^2 + ax - b \) is divided by \( x^2 - 2x - 3 \), the remainder is \( x - 6 \). Find \( a \) and \( b \).&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Forming a polynomial:&lt;/strong&gt; Find a quadratic polynomial whose zeroes are \( \frac{3\alpha}{\beta} \) and \( \frac{3\beta}{\alpha} \), where \( \alpha, \beta \) are zeroes of \( x^2 - 5x + 6 \).&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Complex zeroes (ICSE):&lt;/strong&gt; If one zero of the polynomial \( (a^2+4)x^2 + 13x + 4a \) is reciprocal of the other, find \( a \).&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Pair of Linear Equations in Two Variables&lt;/h2&gt;
    &lt;ol start=&quot;11&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Condition for infinite solutions:&lt;/strong&gt; Find the value of \( k \) for which the system \( kx + 3y = k-3 \), \( 12x + ky = k \) has infinitely many solutions.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Cross-multiplication method:&lt;/strong&gt; Solve: &lt;br&gt; \[ \frac{x}{a} + \frac{y}{b} = a+b, \quad \frac{x}{a^2} + \frac{y}{b^2} = 2 \]&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Real-life: Age problem:&lt;/strong&gt; Five years ago, a mother was three times as old as her daughter. Ten years from now, the mother will be twice as old as her daughter. Find their present ages.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Geometry application:&lt;/strong&gt; The line \( 3x + 4y = 12 \) meets the x-axis at A and y-axis at B. Find the equation of the line through the midpoint of AB and perpendicular to AB.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Word problem (competitive exam):&lt;/strong&gt; A man rowing downstream covers 24 km in 4 hours. Against the current, he covers 12 km in 6 hours. Find the speed of the boat in still water and the speed of the current.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Quadratic Equations&lt;/h2&gt;
    &lt;ol start=&quot;16&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Nature of roots:&lt;/strong&gt; For what value of \( k \) does the equation \( (k+1)x^2 + 2(k+3)x + (k+8) = 0 \) have equal roots? Also, find the roots.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Word problem: Time and work:&lt;/strong&gt; Two pipes together fill a tank in \( 12\frac{8}{9} \) minutes. The larger pipe fills it in 8 minutes less than the smaller. Find the time taken by each alone.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Equation from roots:&lt;/strong&gt; If one root of \( x^2 - 4x + a = 0 \) is twice the other, find \( a \) and the roots.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Fraction problem:&lt;/strong&gt; The denominator of a fraction is 2 more than the numerator. If 3 is added to both numerator and denominator, the fraction becomes \( \frac{5}{6} \). Find the original fraction.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Profit-loss application:&lt;/strong&gt; A shopkeeper buys a number of books for ₹ 1800. If he had bought 15 more books for the same amount, each book would have cost ₹ 20 less. How many books did he buy?&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Arithmetic Progressions&lt;/h2&gt;
    &lt;ol start=&quot;21&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Sum of terms:&lt;/strong&gt; The sum of first \( n \) terms of an AP is \( 4n^2 - 3n \). Find the 20th term and the common difference.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Divisibility:&lt;/strong&gt; How many three-digit numbers are divisible by 7? Find their sum.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Word problem: Installments:&lt;/strong&gt; A man buys a TV on installment basis. He pays ₹ 1000 at the end of the first month, ₹ 1100 at the end of second, ₹ 1200 at the end of third, and so on. The total amount paid in 20 months is ₹ 39,000. Check if this is correct. If not, find the correct total.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Interleaved APs:&lt;/strong&gt; If \( a, b, c \) are in AP, prove that \( \frac{1}{bc}, \frac{1}{ca}, \frac{1}{ab} \) are also in AP.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Competency: Critical thinking:&lt;/strong&gt; The sum of three numbers in AP is 36 and their product is 1620. Find the numbers.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Triangles&lt;/h2&gt;
    &lt;ol start=&quot;26&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Thales theorem application:&lt;/strong&gt; In \( \triangle ABC \), \( D \) and \( E \) are points on AB and AC such that \( DE \parallel BC \). If \( AD = 2.4 \) cm, \( DB = 3.6 \) cm, and \( AC = 7.5 \) cm, find AE and EC.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Similarity in real life:&lt;/strong&gt; A 1.5 m tall boy stands at a distance of 2 m from a lamp post and casts a shadow of 2.8 m on the ground. Find the height of the lamp post.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Pythagoras theorem:&lt;/strong&gt; In a right triangle, the hypotenuse is 10 cm more than the smallest side. The third side is 10 cm less than the hypotenuse. Find the sides.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Area ratio:&lt;/strong&gt; Prove that the ratio of areas of two similar triangles is equal to the square of the ratio of their corresponding medians.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Competency: Proof:&lt;/strong&gt; In a right triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides. Prove this using a trapezium-based method (area proof).&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Coordinate Geometry&lt;/h2&gt;
    &lt;ol start=&quot;31&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Area of triangle:&lt;/strong&gt; Find the area of the triangle formed by the points \( (2, 3) \), \( (-1, 0) \), and \( (2, -4) \). Also, find the ratio in which the y-axis divides the side joining the first two points.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Collinearity:&lt;/strong&gt; For what value of \( k \) are the points \( (k, 2-2k) \), \( (-k+1, 2k) \), and \( (-4-k, 6-2k) \) collinear?&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Real-life: Intersection:&lt;/strong&gt; Two straight roads are represented by the equations \( x + 2y = 5 \) and \( 2x + y = 7 \). A park is located at their intersection. Find the coordinates of the park. Also, find the distance of the park from the point \( (3, 2) \).&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Competency: Ratio:&lt;/strong&gt; The line segment joining \( A(2, 3) \) and \( B(6, -5) \) is divided by the point \( P \) in the ratio \( 3:1 \) internally. Find the coordinates of \( P \) and verify that it lies on the line \( 2x + y - 7 = 0 \).&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Centroid and midpoint:&lt;/strong&gt; Two vertices of a triangle are \( (1, 4) \) and \( (5, 2) \). If its centroid is \( (3, 2) \), find the third vertex. Also, find the length of the median from the third vertex.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Trigonometry&lt;/h2&gt;
    &lt;ol start=&quot;36&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Trigonometric identities:&lt;/strong&gt; Prove that &lt;br&gt; \[ \frac{\sin\theta - \cos\theta + 1}{\sin\theta + \cos\theta - 1} = \frac{1 + \sec\theta}{\tan\theta} \]&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Heights and distances:&lt;/strong&gt; From the top of a 120 m high tower, the angle of depression of two cars on opposite sides of the tower are \( 30^\circ \) and \( 60^\circ \). Find the distance between the two cars.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Trigonometric ratios:&lt;/strong&gt; If \( \tan A + \cot A = 2 \), find the value of \( \tan^8 A + \cot^8 A \).&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Real-life: Navigation:&lt;/strong&gt; A ship is 40 km from a lighthouse. The angle of elevation from the ship to the top of the lighthouse is \( 30^\circ \). After sailing towards the lighthouse, the angle becomes \( 60^\circ \). How far did the ship sail?&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Competency: Simplification:&lt;/strong&gt; Evaluate: &lt;br&gt; \[ \frac{\cos^2 20^\circ + \cos^2 70^\circ}{\sin^2 59^\circ + \sin^2 31^\circ} + \frac{\tan 15^\circ \cdot \tan 30^\circ \cdot \tan 45^\circ \cdot \tan 60^\circ \cdot \tan 75^\circ}{3} \]&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Circles&lt;/h2&gt;
    &lt;ol start=&quot;41&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Tangent properties:&lt;/strong&gt; From an external point \( P \), two tangents \( PA \) and \( PB \) are drawn to a circle with centre \( O \). If \( \angle APB = 60^\circ \), prove that \( \triangle PAB \) is equilateral. Also, find \( \angle OAB \).&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Length of tangent:&lt;/strong&gt; A circle touches all four sides of a quadrilateral \( ABCD \) with sides \( AB = 6 \) cm, \( BC = 7 \) cm, \( CD = 5 \) cm. Find \( DA \).&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Competency: Real-life:&lt;/strong&gt; A circular park of radius 20 m has a path of width 2 m around it on the inside. Find the area of the path and the cost of fencing the inner boundary at ₹ 15 per metre.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Two circles intersecting:&lt;/strong&gt; Two circles of radii 5 cm and 3 cm intersect at two points, and the distance between their centers is 4 cm. Find the length of the common chord.&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Alternate segment theorem:&lt;/strong&gt; In a circle, a chord \( AB \) subtends \( 90^\circ \) at the centre. \( C \) is a point on the major arc. Find the angle between the tangent at \( A \) and chord \( AC \).&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Constructions (Competency – Steps &amp; Justification)&lt;/h2&gt;
    &lt;ol start=&quot;46&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Dividing a segment:&lt;/strong&gt; Construct a triangle \( ABC \) with \( BC = 7 \) cm, \( \angle B = 45^\circ \), \( \angle C = 60^\circ \). Then construct a triangle similar to it whose sides are \( \frac{3}{4} \) of the corresponding sides of \( \triangle ABC \). (Write steps and justification.)&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Tangent to a circle:&lt;/strong&gt; Draw a circle of radius 3 cm. From a point 8 cm away from the center, construct a pair of tangents. Measure and verify their lengths.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Areas Related to Circles&lt;/h2&gt;
    &lt;ol start=&quot;48&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Composite figure:&lt;/strong&gt; A square of side 14 cm has four quadrants drawn inside it from each corner (each quadrant radius = 7 cm). Find the area of the region common to all four quadrants (central overlapping region).&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Real-life: Gardening:&lt;/strong&gt; A cow is tied with a rope of length 14 m at the corner of a rectangular field of dimensions 30 m × 20 m. Find the area the cow can graze. (Assume \( \pi = \frac{22}{7} \)).&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h2&gt;Statistics &amp; Probability&lt;/h2&gt;
    &lt;ol start=&quot;50&quot;&gt;
        &lt;li&gt;&lt;strong&gt;Competency: Interpretation:&lt;/strong&gt; The mean of 20 observations is 25. Later it was found that two observations 23 and 35 were wrongly taken as 32 and 53. Find the correct mean. Also, if each observation is multiplied by 2, what is the new mean? &lt;/li&gt;
    &lt;/ol&gt;
&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/6115128241263944416/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/05/competency-focused-questions-for-cbse.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/6115128241263944416'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/6115128241263944416'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/05/competency-focused-questions-for-cbse.html' title='Competency Focused Questions for CBSE and ICSE Class X'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-6148986116919749223</id><published>2026-05-17T00:22:22.328-07:00</published><updated>2026-08-08T09:51:42.953-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="Board Paper"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>ICSE Class 10 Mathematics: The Ultimate Topic-Wise PYQ Breakdown (2017–2026)</title><content type='html'>&lt;div _ngcontent-ng-c2383366420=&quot;&quot; aria-busy=&quot;false&quot; aria-live=&quot;polite&quot; class=&quot;markdown markdown-main-panel stronger enable-updated-hr-color&quot; dir=&quot;ltr&quot; id=&quot;model-response-message-contentr_204e8264a5b6fbeb&quot; inline-copy-host=&quot;&quot; style=&quot;--animation-duration: 400ms; --fade-animation-function: ease-out; animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; color: #1f1f1f; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans Text&amp;quot;, sans-serif; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;h1 data-path-to-node=&quot;0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans&amp;quot;, sans-serif; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 8px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Master ICSE Mathematics: The Ultimate Collection of Board Papers&lt;/h1&gt;&lt;p data-path-to-node=&quot;1&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;As an educator, I have seen firsthand that success in ICSE Mathematics is never an accident—it is the result of focused, intelligent, and strategic practice. The leap in complexity during Classes IX and X requires a significant shift from passive reading to active, structured problem-solving. When preparing for high-stakes board exams, familiarizing yourself with the exact patterns, time constraints, and complexities of the actual papers is the most effective way to guarantee success.&lt;/p&gt;&lt;p data-path-to-node=&quot;2&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;That is why I have compiled a comprehensive archive specifically designed for your preparation at Prime Maths.&lt;/p&gt;&lt;h3 data-path-to-node=&quot;3&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans&amp;quot;, sans-serif; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 8px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;What You Will Find in Our ICSE Board Papers Archive&lt;/h3&gt;&lt;p data-path-to-node=&quot;4&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;The dedicated repository for &lt;response-element ng-version=&quot;0.0.0-PLACEHOLDER&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;link-block _nghost-ng-c3563746348=&quot;&quot; class=&quot;ng-star-inserted&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;!----&gt;&lt;!----&gt;&lt;a _ngcontent-ng-c3563746348=&quot;&quot; _nghost-ng-c3775120888=&quot;&quot; class=&quot;ng-star-inserted&quot; data-hveid=&quot;0&quot; data-ved=&quot;0CAAQ_4QMahcKEwj92eqH37-UAxUAAAAAHQAAAAAQTw&quot; decode-data-ved=&quot;1&quot; externallink=&quot;&quot; href=&quot;https://sites.google.com/view/primemaths/math-ix-x/icse-board-papers&quot; jslog=&quot;197247;track:generic_click,impression,attention;BardVeMetadataKey:[[&amp;quot;r_204e8264a5b6fbeb&amp;quot;,&amp;quot;c_5efd600b1ae2917f&amp;quot;,null,&amp;quot;rc_623888c774312d16&amp;quot;,null,null,&amp;quot;&amp;quot;,null,1,null,null,1,0]]&quot; rel=&quot;noopener&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(11, 87, 208); clear: none; clip: auto; color: #0b57d0; columns: auto; contain: none; container: none; content: normal; cursor: pointer; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(11, 87, 208) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot; target=&quot;_blank&quot;&gt;ICSE Board Papers&lt;/a&gt;&lt;!----&gt;&lt;/link-block&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;/response-element&gt;&amp;nbsp; (full page view mode) is structured to streamline your revision process. Here is what makes this resource an essential part of your study toolkit:&lt;/p&gt;&lt;ul data-path-to-node=&quot;5&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 16px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 16px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding-inline-start: 32px; padding: 0px 0px 0px 32px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 8px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;5,0,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;5,0,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Year-Wise Collections:&lt;/b&gt; Access a meticulously organized vault of past ICSE mathematics board question papers, including recent standard and improvement exams.&lt;/p&gt;&lt;/li&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 8px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;5,1,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;5,1,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Topic-Wise Segregation:&lt;/b&gt; Beyond just full papers, you can dive into content categorized by crucial sections like Commercial Arithmetic, Algebra, Geometry, Mensuration, and Probability &amp;amp; Statistics. This allows you to aggressively target your weakest areas.&lt;/p&gt;&lt;/li&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 8px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;5,2,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;5,2,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Authentic Format:&lt;/b&gt; Every problem is presented exactly as it appeared on the official examinations, giving you a true sense of the required academic rigor.&lt;/p&gt;&lt;/li&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 8px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;5,3,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;5,3,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Targeted Practice:&lt;/b&gt; Practicing with these structured materials helps you decode the marking scheme and understand exactly what the council examiners are looking for in your answers.&lt;/p&gt;&lt;/li&gt;&lt;/ul&gt;&lt;h3 data-path-to-node=&quot;6&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans&amp;quot;, sans-serif; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 8px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;The Real Benefits of Solving Past Papers&lt;/h3&gt;&lt;p data-path-to-node=&quot;7&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Dedicating consistent time to this archive will fundamentally transform your approach to the subject.&lt;/p&gt;&lt;p data-path-to-node=&quot;8&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;8&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Eliminate Exam Anxiety&lt;/b&gt;&lt;/p&gt;&lt;p data-path-to-node=&quot;8&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;The unknown is the biggest source of stress. By repeatedly exposing yourself to the authentic formatting and phrasing of ICSE questions, the final exam will feel like just another practice session.&lt;/p&gt;&lt;p data-path-to-node=&quot;9&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;9&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Master Time Management&lt;/b&gt;&lt;/p&gt;&lt;p data-path-to-node=&quot;9&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Mathematics is notorious for lengthy calculations. Setting a strict timer while tackling these past papers will train your brain to allocate the perfect amount of time between Section A&#39;s mandatory questions and your chosen questions in Section B.&lt;/p&gt;&lt;p data-path-to-node=&quot;10&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;10&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Identify Recurring Concepts&lt;/b&gt;&lt;/p&gt;&lt;p data-path-to-node=&quot;10&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 10px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;While the exact numbers change, the core concepts tested repeat year after year. Working through this collection will quickly reveal the high-weightage topics you absolutely cannot afford to skip.&lt;/p&gt;&lt;div _ngcontent-ng-c2805080622=&quot;&quot; class=&quot;source-inline-chip-container ng-star-inserted&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline-flex; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 4px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 0px 4px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;button _ngcontent-ng-c2805080622=&quot;&quot; aria-label=&quot;View source details for citation from YouTube. 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&lt;div class=&quot;pm-exam-container&quot;&gt;
    &lt;header class=&quot;page-header&quot;&gt;
        &lt;h1&gt;ICSE Mathematics Board Papers Section Wise 2026, 2025, 2025 IE, 2024, 2023 Exam&lt;br /&gt;Sectioned Data&lt;/h1&gt;
    &lt;/header&gt;
    &lt;nav class=&quot;tab-nav&quot; id=&quot;tab-nav&quot;&gt;&lt;/nav&gt;
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&lt;/div&gt;

    &lt;script&gt;
        // Question arrays with proper LaTeX math delimiters correctly double-escaped for JS
        const commercialArithmetic = [
            &quot;Question 1 (ii): The marked price of a refrigerator is ₹12,000 and GST paid by the customer is ₹2,160. The rate of GST is:\n(a) 5%\n(b) 12%\n(c) 18%\n(d) 28%\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 1 (iv): A and B opened a recurring deposit account in a bank which is paying simple interest at 9% per annum. A deposited ₹1,500 for one year and B deposited ₹1,200 for 15 months. The amount invested by:\n(a) A is ₹27 more than B\n(b) A is ₹300 more than B\n(c) A is ₹300 less than B\n(d) Both A and B are same\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 1 (vi): Asha buys 20 shares of a company which pays 9% dividend at such a price that she gets a return of 12% on her investment. At what price did she buy each share?\n(a) ₹20\n(b) ₹15\n(c) ₹25\n(d) ₹18\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 4 (ii): The cost price of a TV set is ₹20,000. The shopkeeper marked it for ₹24,000. He sells it to a customer at a discount of 10% on the marked price. If the sale is intra-state and the rate of GST is 12%, find the:\n(a) discounted price of the TV set.\n(b) amount paid by the customer to clear the bill.\n[Marks: 3] [ICSE Year: 2026]&quot;,
            &quot;Question 6 (i): Kabir bought 120 shares of a company with nominal value ₹100, available at a premium of ₹25. Find:\n(a) the money invested by Kabir in buying these shares.\n(b) the rate of dividend, if he received ₹1,080 as dividend from these shares after one year.\n(c) his rate of return.\n[Marks: 3] [ICSE Year: 2026]&quot;,
            &quot;Question 8 (i): Rohit and Vinay both opened a recurring deposit account in a bank for 2 years at 8% simple interest. Vinay deposited ₹300 per month. On maturity, Rohit&#39;s interest was ₹800 more than Vinay&#39;s interest. Find the:\n(a) interest earned by Vinay.\n(b) sum deposited by Rohit every month.\n[Marks: 3] [ICSE Year: 2026]&quot;,

            &quot;Question 1 (v): The GST of an article is reduced from 12% to 5% and due to this, the price paid for the article is cut down by ₹14. The original price of the article is:\n(a) ₹50\n(b) ₹98\n(c) ₹100\n(d) ₹200\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (xi): Percentage return on 100, 12% share of a company bought at 4% discount is:\n(a) 10%\n(b) 12%\n(c) 12.5%\n(d) 16%\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (xv): Mr. Rahul deposited ₹11,700 in a recurring deposit account for 1½ years. The amount deposited by him per month is:\n(a) ₹650\n(b) ₹780\n(c) ₹6,500\n(d) ₹7,800\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 2 (i): A retailer purchased an air conditioner (A.C.) for ₹30,000. He marked up its price by 20% and then allows a discount of 10% on the marked price to a customer. If the sale is intra-state and the rate of GST is 28%, find the:\n(a) marked price of A.C.\n(b) total amount paid by the customer including GST.\n(c) tax collected by the central and the state governments respectively.\n[Marks: 4] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 7 (ii): Mr. Anil has a recurring deposit account. He deposits a certain amount of money per month for 2 years. If he received an interest whose value is the double of the deposit made per month, then find the rate of interest.\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 8 (i): 100 shares of a company giving 10% dividend are selling at 150. Mr. Saha invests 18,000 to buy these shares. He sells 80% of his shares after one year. Find:\n(a) the number of shares he purchased.\n(b) the number of shares he sold.\n(c) his annual income from the remaining 20% shares he still holds.\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (ii): Mr. Anuj deposits ₹500 per month for 18 months in a recurring deposit account at a certain rate. If he earns ₹570 as interest at the time of maturity, then his matured amount is:\n(a) 7(500 x 18 + 570)\n(b) 7(500 x 19 + 570)\n(c) 7(500 x 18 x 19 + 570)\n(d) 7(500 x 9 x 19 + 570)\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (viii): A man invested in a company paying 12% dividend on its share. If the percentage return on his investment is 10%, then the shares are:\n(a) at par\n(b) below par\n(c) above par\n(d) cannot be determined\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (xiii): The marked price of an article is ₹1375. If the CGST is charged at a rate of 4%, then the price of the article including GST is:\n(a) ₹55\n(b) ₹110\n(c) ₹1430\n(d) ₹1485\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 2 (ii): Mrs. Rao deposited ₹250 per month in a recurring deposit account for a period of 3 years. She received ₹10,110 at the time of maturity. Find:\n(a) the rate of interest.\n(b) how much more interest Mrs. Rao will receive if she had deposited ₹50 more per month at the same rate of interest and for the same time.\n[Marks: 4] [ICSE Year: 2025]&quot;,
            &quot;Question 7 (iii): Refer to the given bill. A customer paid ₹2000 (rounded off to the nearest ₹10) to clear the bill. (Note: 5% discount is applicable on an article if 10 or more such articles are purchased.)\nArticle A: M.P. ₹190, Quantity 06, G.S.T. 12%\nArticle B: M.P. ₹50, Quantity 12, G.S.T. 18%\nCheck whether the total amount paid by the customer is correct or not. Justify your answer with necessary working.\n[Marks: 4] [ICSE Year: 2025]&quot;,
            &quot;Question 8 (i): A man bought 200 shares of a company at 25% premium. If he received a return of 5% on his investment. Find the:\n(a) market value\n(b) dividend percent declared\n(c) number of shares purchased, if annual dividend is ₹1000.\n[Marks: 3] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (i): For an Intra-state sale, the CGST paid by a dealer to the Central government is ₹120. If the marked price of the article is ₹2000, the rate of GST is:\n(a) 6%\n(b) 10%\n(c) 12%\n(d) 16.67%\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (ix): The sum invested to purchase 15 shares of a company of nominal value ₹75 available at a discount of 20% is:\n(a) ₹60\n(b) ₹90\n(c) ₹1350\n(d) ₹900\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 4 (i): Suresh has a recurring deposit account in a bank. He deposits ₹2000 per month and the bank pays interest at the rate of 8% per annum. If he gets ₹1040 as interest at the time of maturity, find in years total time for which the account was held.\n[Marks: 3] [ICSE Year: 2024]&quot;,
            &quot;Question 9 (ii): Mr. Gupta invested ₹33000 in buying ₹100 shares of a company at 10% premium. The dividend declared by the company is 12%. Find:\n(a) the number of shares purchased by him.\n(b) his annual dividend.\n[Marks: 3] [ICSE Year: 2024]&quot;,
            &quot;Question 10 (i): Rohan bought the following eatables for his friends : Soham Sweet Mart: Bill (Item 1: Laddu, ₹500 per kg, 2 kg, 5% GST; Item 2: Pastries, ₹100 per piece, 12 pieces, 18% GST). Calculate:\n(a) Total GST paid.\n(b) Total bill amount including GST.\n[Marks: 3] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (vii): The printed price of an article is ₹3080. If the rate of GST is 10% then the GST charged is:\n(a) ₹154\n(b) ₹308\n(c) ₹30.80\n(d) ₹15.40\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 1 (xiv): Naveen deposits ₹800 every month in a recurring deposit account for 6 months. If he receives ₹4884 at the time of maturity, then the interest he earns is:\n(a) ₹84\n(b) ₹42\n(c) ₹24\n(d) ₹284\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 2 (ii): Salman deposits ₹1000 every month in a recurring deposit account for 2 years. If he receives ₹26000 on maturity, find:\n(a) the total interest Salman earns.\n(b) the rate of interest.\n[Marks: 4] [ICSE Year: 2023]&quot;,
            &quot;Question 5 (i): Mrs. Arora bought the following articles from a departmental store:\nS. No. 1. Item: Hair oil, Price: ₹1200, Rate of GST: 18%, Discount: ₹100\nS. No. 2. Item: Cashew nuts, Price: ₹600, Rate of GST: 12%, Discount: Nil\nFind the:\n(a) Total GST paid.\n(b) Total bill amount including GST.\n[Marks: 3] [ICSE Year: 2023]&quot;

        ];

        const algebra = [
            &quot;Question 1 (i): \\((x+3)\\), 1, \\((3x-7)\\) and -5 are in proportion. The value of x is:\n(a) -1\n(b) 1\n(c) -5\n(d) 5\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 1 (ix): The nature of roots of quadratic equation \\(3x^2 - 6x - 3 = 0\\) are:\n(a) real and equal\n(b) real, distinct and rational\n(c) real, distinct and irrational\n(d) no real roots\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 1 (xiii): What must be added to \\(x^3 + 7x^2 + 3x + 2\\) so that the result is completely divisible by \\((x + 2)\\)?\n(a) -40\n(b) -16\n(c) 16\n(d) 40\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 1 (xiv): Given matrix \\(A = \\begin{bmatrix} 2 &amp; 3 \\\\ 1 &amp; 2 \\end{bmatrix}\\) and matrix \\(B = \\begin{bmatrix} 2 &amp; -4 \\end{bmatrix}\\). Product AB is a matrix of order:\n(a) \\(2 \\times 2\\)\n(b) \\(2 \\times 1\\)\n(c) \\(1 \\times 2\\)\n(d) product AB is not possible\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 1 (xv): Assertion (A): The 9th term of a Geometric Progression (G.P.) 6, -12, 24, -48... is a positive term.\nReason (R): The value of \\((-2)^8\\) is always positive.\n(a) (A) is true and (R) is false.\n(b) (A) is false and (R) is true.\n(c) Both (A) and (R) are true and (R) is the correct explanation of (A).\n(d) Both (A) and (R) are true but (R) is not the correct explanation of (A).\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 2 (i): The fourth and seventh terms of an Arithmetic Progression (A.P.) are 60 and 114 respectively. Find the:\n(a) first term and common difference.\n(b) sum of its first 10 terms.\n[Marks: 4] [ICSE Year: 2026]&quot;,
            &quot;Question 2 (ii): Given, \\(A = \\begin{bmatrix} 3 &amp; 1 \\\\ 5 &amp; 3 \\end{bmatrix}\\) and \\(B = \\begin{bmatrix} -1 &amp; a \\\\ 3 &amp; -5 \\end{bmatrix}\\) and product \\(AB = \\begin{bmatrix} b &amp; 7 \\\\ 4 &amp; 5 \\end{bmatrix}\\). Find the values of &#39;a&#39; and &#39;b&#39;.\n[Marks: 4] [ICSE Year: 2026]&quot;,
            &quot;Question 3 (i): The polynomial \\(kx^3 + 3x^2 - 11x - 6\\) when divided by \\((x + 1)\\), leaves a remainder of 6.\n(a) Find the value of k.\n(b) Using the value of k factorise completely the polynomial \\(kx^3 + 3x^2 - 11x - 6\\)\n[Marks: 4] [ICSE Year: 2026]&quot;,
            &quot;Question 5 (iii): Solve the quadratic equation \\((x - 2)^2 - 5x - 3 = 0\\) and give your answer correct to 3 significant figures. (Use Mathematical Tables for this question if necessary.)\n[Marks: 4] [ICSE Year: 2026]&quot;,
            &quot;Question 6 (iii): The difference of two natural numbers is 5 and sum of their reciprocals is \\(\\frac{3}{10}\\). Find the two numbers.\n[Marks: 3] [ICSE Year: 2026]&quot;,
            &quot;Question 8 (ii): The fourth term of a Geometric Progression (G.P.) is 16 and its seventh term is 128. Find its:\n(a) common ratio\n(b) first term\n[Marks: 3] [ICSE Year: 2026]&quot;,
            &quot;Question 9 (i): Solve the following inequation, write the solution set and represent it on the real number line.\n\\(-1 &lt; \\frac{2x - 3}{3} - \\frac{x}{5} \\le 1\\), \\(x \\in \\mathbb{R}\\)\n[Marks: 3] [ICSE Year: 2026]&quot;,
            &quot;Question 10 (i): If \\(x = \\frac{5ab}{a - b}\\), \\(a \\neq b\\). Find:\n(a) \\(\\frac{x}{a}\\)\n(b) Using properties of proportion, find: \\(\\frac{x + a}{x - a}\\)\n[Marks: 4] [ICSE Year: 2026]&quot;,

            &quot;Question 1 (iv): The value of \\(p\\) for which \\(x - p\\) is a factor of \\(x^3 - px^2 + x + 5\\) is:\n(a) \\(-5\\)\n(b) \\(-4\\)\n(c) \\(5\\)\n(d) \\(p + 5\\)\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (vii): If \\(2x - 15 &gt; 4x + 9\\) then:\n(a) \\(x &lt; -12\\)\n(b) \\(x &lt; 12\\)\n(c) \\(x &gt; -12\\)\n(d) \\(x &gt; 12\\)\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (ix): The roots of the quadratic equation \\(2x^2 = 6x\\) is:\n(a) \\(0\\)\n(b) \\(2\\)\n(c) \\(0\\) and \\(2\\)\n(d) \\(0\\) and \\(6\\)\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (xii): If matrix \\(A\\) of order \\(2 \\times 1\\) and matrix \\(B\\) of order \\(2 \\times 2\\) are added, then the order of the matrix \\(A + B\\) is:\n(a) \\(2 \\times 2\\)\n(b) \\(2 \\times 1\\)\n(c) \\(1 \\times 2\\)\n(d) \\(A + B\\) is not possible\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 3 (ii): If \\(2x^3 - 3x^2 - 3x + 2 = (2x - 1)(x^2 + ax + b)\\);\n(a) using Remainder and Factor theorem, find the value of \\(a\\) and \\(b\\).\n(b) hence, factorise the polynomial \\(2x^3 - 3x^2 - 3x + 2\\) completely.\n[Marks: 4] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 4 (i): The sum of two numbers is 2 and the sum of their reciprocals is 2.25. Find the numbers.\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 5 (i): \\(164, 160, 156, 152, \\dots\\) are in Arithmetic Progression (A.P.). Find:\n(a) which term is equal to 0.\n(b) the sum of its first 20 terms.\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 5 (ii): Solve the following quadratic equation: \\(3x^2 + 6x - 4 = 0\\). Give your answer correct to two places of decimals. (Use Mathematical tables, if necessary)\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 6 (i): Solve the inequation, write down the solution set and represent it on a real number line:\n\\(3x - 16 &lt; \\frac{2x}{5} - 3 \\le -\\frac{3}{5} + 2x\\) where \\(x \\in \\mathbb{R}\\)\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 6 (ii): If the 6th term of a series in Geometric Progression (G.P.) is 32 and the 9th term is 256, find the:\n(a) first term and the common ratio.\n(b) sum of its first 10 terms.\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 7 (iii): If \\(a, b, c\\) and \\(d\\) are in continued proportion, prove that \\(ad(c^2 + d^2) = c^3(b + d)\\)\n[Marks: 4] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 8 (iii): Divide 20 into two parts such that the sum of their squares is 272. The larger of two parts is square of the other. Assuming the smaller part to be \\(x\\), form an equation and solve it to find the two parts.\n[Marks: 4] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 10 (i): Using Remainder and Factor theorem factorise the given polynomial completely:\n\\(6x^3 + x^2 - 4x + 1\\)\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (i): The given quadratic equation \\(3x^2 + \\sqrt{7}x + 2 = 0\\) has:\n(a) two equal real roots.\n(b) two distinct real roots.\n(c) more than two real roots.\n(d) no real roots.\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (v): If matrix \\(A = \\begin{bmatrix} 0 &amp; 1 \\\\ 1 &amp; 0 \\end{bmatrix}\\) then \\(A^2\\) is equal to:\n(a) \\(\\begin{bmatrix} 1 &amp; 1 \\\\ 0 &amp; 0 \\end{bmatrix}\\)\n(b) \\(\\begin{bmatrix} 0 &amp; 0 \\\\ 1 &amp; 1 \\end{bmatrix}\\)\n(c) \\(\\begin{bmatrix} 1 &amp; 0 \\\\ 0 &amp; 1 \\end{bmatrix}\\)\n(d) \\((P)\\)\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (vii): The factor common to the two polynomials \\(x^2 - 4\\) and \\(x^3 - x^2 - 4x + 4\\) is:\n(a) \\((x + 1)\\)\n(b) \\((x - 1)\\)\n(c) \\((x - 2)\\)\n(d) \\((x - 4)\\)\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (xiv): The solution set for \\(0 &lt; -\\frac{x}{3} &lt; 2\\), where \\(x \\in \\mathbb{Z}\\) is:\n(a) \\(\\{-5, -4, -3, -2, -1\\}\\)\n(b) \\(\\{-6, -5, -4, -3, -2, -1\\}\\)\n(c) \\(\\{-5, -4, -3, -2, -1, 0\\}\\)\n(d) \\(\\{-6, -5, -4, -3, -2, -1, 0\\}\\)\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 2 (i): Solve the following quadratic equation: \\(2x^2 - 5x - 4 = 0\\). Give your answer correct to three significant figures. (Use mathematical tables for this question)\n[Marks: 4] [ICSE Year: 2025]&quot;,
            &quot;Question 3 (ii): If \\(A = \\begin{bmatrix} 1 &amp; 2 \\\\ 3 &amp; 4 \\end{bmatrix}\\), \\(B = \\begin{bmatrix} 2 &amp; 1 \\\\ 4 &amp; 2 \\end{bmatrix}\\) and \\(C = \\begin{bmatrix} -5 &amp; 1 \\\\ 7 &amp; -4 \\end{bmatrix}\\). Find:\n(a) \\(A + C\\)\n(b) \\(B(A + C)\\)\n(c) \\(5B\\)\n(d) \\(B(A + C) - 5B\\)\n[Marks: 4] [ICSE Year: 2025]&quot;,
            &quot;Question 4 (i): Solve the following inequation, write the solution set and represent it on the real number line.\n[Marks: 3] [ICSE Year: 2025]&quot;,
            &quot;Question 4 (ii): The first term of an Arithmetic Progression (A.P.) is 5, the last term is 50 and their sum is 440. Find:\n(a) the number of terms\n(b) common difference\n[Marks: 3] [ICSE Year: 2025]&quot;,
            &quot;Question 5 (i): Using properties of proportion, find the value of \\(x\\):\n\\(\\frac{6x^2 + 3x - 5}{3x - 5} = \\frac{9x^2 + 2x + 5}{2x + 5}\\); \\(x \\neq 0\\)\n[Marks: 3] [ICSE Year: 2025]&quot;,
            &quot;Question 5 (ii): It is given that \\((x - 2)\\) is a factor of polynomial \\(2x^3 - 7x^2 + kx - 2\\). Find:\n(a) the value of \\(k\\).\n(b) hence, factorise the resulting polynomial completely.\n[Marks: 3] [ICSE Year: 2025]&quot;,
            &quot;Question 8 (iii): Mr. and Mrs. Das were travelling by car from Delhi to Kasauli for a holiday. Distance between Delhi and Kasauli is approximately 350 km (via NH 152D). Due to heavy rain they had to slow down. The average speed of the car was reduced by 20 km/hr and time of the journey increased by 2 hours. Find:\n(a) the original speed of the car.\n(b) with the reduced speed, the number of hours they took to reach their destination.\n[Marks: 4] [ICSE Year: 2025]&quot;,
            &quot;Question 10 (i): If 1701 is the \\(n^{\\text{th}}\\) term of the Geometric Progression (G.P.) 7, 21, 63 ....., find:\n(a) the value of \\(n\\)\n(b) hence find the sum of the \\(n\\) terms of the G.P.\n[Marks: 3] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (ii): What must be subtracted from the polynomial \\(x^3 + x^2 - 2x + 1\\), so that the result is exactly divisible by \\((x - 3)\\)?\n(a) \\(-31\\)\n(b) \\(-30\\)\n(c) \\(30\\)\n(d) \\(31\\)\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (iii): The roots of the quadratic equation \\(px^2 - qx + r = 0\\) are real and equal if:\n(a) \\(p^2 = 4qr\\)\n(b) \\(q^2 = 4pr\\)\n(c) \\(-q^2 = 4pr\\)\n(d) \\(p^2 &gt; 4qr\\)\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (iv): If matrix \\(A = \\begin{bmatrix} 2 &amp; 2 \\\\ 0 &amp; 2 \\end{bmatrix}\\) and \\(A^2 = \\begin{bmatrix} 4 &amp; x \\\\ 0 &amp; 4 \\end{bmatrix}\\), then the value of \\(x\\) is:\n(a) \\(2\\)\n(b) \\(4\\)\n(c) \\(8\\)\n(d) \\(10\\)\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (vii): The given table shows the distance covered and the time taken by a train moving at a uniform speed along a straight track (Distance: 90m in 2s, 60m in \\(x\\) s, \\(y\\) m in 5s). The values of \\(x\\) and \\(y\\) are:\n(a) \\(x=4, y=150\\)\n(b) \\(x=3, y=100\\)\n(c) \\(x=4, y=100\\)\n(d) \\(x=3, y=150\\)\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (viii): The 7th term of the given Arithmetic Progression (A.P.): \\(\\frac{1}{a}, \\left(\\frac{1}{a} + 1\\right), \\left(\\frac{1}{a} + 2\\right) \\dots\\) is:\n(a) \\(\\frac{1}{a} + 6\\)\n(b) \\(\\frac{1}{a} + 7\\)\n(c) \\(\\frac{1}{a} + 8\\)\n(d) \\(\\frac{1}{a} + 7^7\\)\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 2 (i): \\(A = \\begin{bmatrix} x &amp; 0 \\\\ 1 &amp; 1 \\end{bmatrix}\\), \\(B = \\begin{bmatrix} 4 &amp; 0 \\\\ y &amp; 1 \\end{bmatrix}\\) and \\(C = \\begin{bmatrix} 4 &amp; 0 \\\\ x &amp; 1 \\end{bmatrix}\\). Find the values of \\(x\\) and \\(y\\), if \\(AB = C\\).\n[Marks: 4] [ICSE Year: 2024]&quot;,
            &quot;Question 2 (iii): 15, 30, 60, 120... are in G.P. (Geometric Progression).\n(a) Find the \\(n^{\\text{th}}\\) term of this G.P. in terms of \\(n\\).\n(b) How many terms of the above G.P. will give the sum 945?\n[Marks: 4] [ICSE Year: 2024]&quot;,
            &quot;Question 4 (iii): If \\(\\frac{(a+b)^3}{(a-b)^3} = \\frac{64}{27}\\)\n(a) Find \\(\\frac{a+b}{a-b}\\)\n(b) Hence using properties of proportion, find \\(a : b\\).\n[Marks: 4] [ICSE Year: 2024]&quot;,
            &quot;Question 6 (i): Solve the following quadratic equation for \\(x\\) and give your answer correct to three significant figures: \\(2x^2 - 10x + 5 = 0\\) (Use mathematical tables if necessary)\n[Marks: 3] [ICSE Year: 2024]&quot;,
            &quot;Question 6 (ii): The \\(n^{\\text{th}}\\) term of an Arithmetic Progression (A.P.) is given by the relation \\(T_n = 6(7 - n)\\). Find:\n(a) its first term and common difference\n(b) sum of its first 25 terms\n[Marks: 3] [ICSE Year: 2024]&quot;,
            &quot;Question 7 (ii): Solve the following inequation, write down the solution set and represent it on the real number line: \\(-3 + x \\le \\frac{7x}{2} + 2 &lt; 8 + 2x\\), \\(x \\in \\mathbb{I}\\)\n[Marks: 3] [ICSE Year: 2024]&quot;,
            &quot;Question 8 (i): The polynomial \\(3x^3 + 8x^2 - 15x + k\\) has \\((x - 1)\\) as a factor. Find the value of \\(k\\). Hence factorize the resulting polynomial completely.\n[Marks: 3] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (i): If \\(\\begin{bmatrix}2 &amp; 0 \\\\ 0 &amp; 4\\end{bmatrix} \\begin{bmatrix}x \\\\ y\\end{bmatrix} = \\begin{bmatrix}2 \\\\ -8\\end{bmatrix}\\), the value of \\(x\\) and \\(y\\) respectively are:\n(a) 1, -2\n(b) -2, 1\n(c) 1, 2\n(d) -2, -1\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 1 (ii): If \\(x - 2\\) is a factor of \\(x^3 - kx - 12\\), then the value of \\(k\\) is:\n(a) 3\n(b) 2\n(c) -2\n(d) -3\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 1 (v): If 3 is a root of the quadratic equation \\(x^2 - px + 3 = 0\\) then \\(p\\) is equal to:\n(a) 4\n(b) 3\n(c) 5\n(d) 2\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 1 (x): The \\(n^{\\text{th}}\\) term of an Arithmetic Progression (A.P.) is \\(2n + 5\\). The \\(10^{\\text{th}}\\) term is:\n(a) 7\n(b) 15\n(c) 25\n(d) 45\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 1 (xi): The mean proportional between 4 and 9 is:\n(a) 4\n(b) 6\n(c) 9\n(d) 36\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 1 (xv): The solution set for the inequation \\(2x + 4 \\le 14\\), \\(x \\in W\\) is:\n(a) {1, 2, 3, 4, 5}\n(b) {0, 1, 2, 3, 4, 5}\n(c) {1, 2, 3, 4}\n(d) {0, 1, 2, 3, 4}\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 2 (i): Find the value of &#39;\\(a\\)&#39; if \\(x - a\\) is a factor of the polynomial \\(3x^3 + x^2 - ax - 81\\).\n[Marks: 4] [ICSE Year: 2023]&quot;,
            &quot;Question 3 (i): Solve the following quadratic equation: \\(x^2 + 4x - 8 = 0\\). Give your answer correct to one decimal place. (Use mathematical tables if necessary.)\n[Marks: 4] [ICSE Year: 2023]&quot;,
            &quot;Question 4 (i): If \\(A = \\begin{bmatrix}1 &amp; 3 \\\\ 2 &amp; 4\\end{bmatrix}\\), \\(B = \\begin{bmatrix}1 &amp; 2 \\\\ 2 &amp; 4\\end{bmatrix}\\), \\(C = \\begin{bmatrix}4 &amp; 1 \\\\ 1 &amp; 5\\end{bmatrix}\\), \\(I = \\begin{bmatrix}1 &amp; 0 \\\\ 0 &amp; 1\\end{bmatrix}\\). Find \\(A(B + C) - 14I\\)\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 5 (ii): Solve the following inequation. Write down the solution set and represent it on the real number line: \\(-5(x - 9) \\ge 17 - 9x &gt; x + 2\\), \\(x \\in \\mathbb{R}\\)\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 6 (ii): The 5th term and the 9th term of an Arithmetic Progression are 4 and -12 respectively. Find:\n(a) the first term\n(b) common difference\n(c) sum of 16 terms of the AP.\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 7 (ii): A man covers a distance of 100 km, travelling with a uniform speed of \\(x\\) km/hr. Had the speed been 5 km/hr more it would have taken 1 hour less. Find \\(x\\) the original speed.\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 8 (ii): What number must be added to each of the numbers 4, 6, 8, 11 in order to get the four numbers in proportion?\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 9 (i): Using Componendo and Dividendo solve for \\(x\\):\n\\(\\frac{\\sqrt{2x+2}+\\sqrt{2x-1}}{\\sqrt{2x+2}-\\sqrt{2x-1}}=3\\)\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 9 (ii): Which term of the Arithmetic Progression (A.P.) 15, 30, 45, 60... is 300? Hence find the sum of all the terms of the Arithmetic Progression (A.P.)\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 10 (i): Factorize completely using factor theorem: \\(2x^3 - x^2 - 13x - 6\\)\n[Marks: 4] [ICSE Year: 2023]&quot;
        ];

        const geometry = [
            &quot;Question 1 (v): Find the equation of a line whose y-intercept is 6 and is parallel to x-axis.\n(a) \\(y = 6\\)\n(b) \\(x = 6\\)\n(c) \\(x + y = 6\\)\n(d) \\(y - x = 6\\)\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 1 (viii): In the given diagram, O is the centre of the circle and ABCD is a cyclic quadrilateral. If \\(\\angle CDE = 65^\\circ\\) then the value of \\(x\\) is:\n(a) \\(32.5^\\circ\\)\n(b) \\(65^\\circ\\)\n(c) \\(115^\\circ\\)\n(d) \\(130^\\circ\\)\n[Marks: 1] [ICSE Year: 2026]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh5a4tvmUaJhPFVWKLsd9_PJwOmu3O0pu-O81fZ2g58cbPhhnuW6MPFHnXFdZcc3M4DiEzyMvs5yBdYpttB1x_HeBijSP047jB0DfT5-YKRUursMz0_WaNu7O-aI9FdvMsrlLOQWczX4uiuj3DD8X_XD0xpzLEHgQsr4RZqLKZcZzFI4oBkNtFnffqNxXs/s345/2026_1_viii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Circle with cyclic quadrilateral ABCD and exterior angle CDE\&quot;&gt;&quot;,
            &quot;Question 1 (xi): If the areas of two similar triangles are in the ratio 9:64, then the ratio of their corresponding altitudes is:\n(a) 3:8\n(b) 2:1\n(c) 9:64\n(d) 8:3\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 1 (xiii): In the given diagram, \\(\\Delta AOB\\) is a right-angled triangle and C is the mid-point of AB. The coordinates of the point which is equidistant from the three vertices of \\(\\Delta AOB\\) is:\n(a) \\((x, y)\\)\n(b) \\((y, x)\\)\n(c) \\(\\left(\\frac{x}{2}, \\frac{y}{2}\\right)\\)\n(d) \\(\\left(\\frac{2x}{3}, \\frac{2y}{3}\\right)\\)\n[Marks: 1] [ICSE Year: 2026]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhemm9Plm9LPLjlGd4kIV_xtRI9QVDMtOzffwHuaWsouxUpNa4riFOD8ioK8DhT-o7Ngnbj0SPZWTJFqt6vGb6GTyCy2Tc6o-Bg0qn9RMsQxl7lxzBz3imhB2BVAb-1M54glJ__tRRWTCr-N9m-aUdV-cUIzP3DVEslUcIYGsk1qC0SCAKDVlHeBllC3o4/s522/2026_1_xiii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Right angled triangle AOB on Cartesian plane\&quot;&gt;&quot;,
            &quot;Question 2 (iii): In the given diagram, O is the centre of the circle and the tangent DE touches the circle at B. If \\(\\angle ADB = 32^\\circ\\). Find the values of \\(x\\) and \\(y\\).\n[Marks: 4] [ICSE Year: 2026]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhJIvDaQRiIyh1MEDmvbgSxrYJvq81AFFuWboMTowUVulDBke-vL4NdJmmniLweQ8de1zfRjq0gpfWIhp43bvbS4TTub_DqEhoEhK_fpTfR5yYMUo33bKQ-vN-7Dmub6XbGYDYpgKtllRcfbIJKnb7URSMsdeJ_y-ehCYEZsEetkx-ZrrjmZSqDXlYpZP0/s343/2026_2_iii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Circle with tangent DE at point B\&quot;&gt;&quot;,
            &quot;Question 3 (iii): Use ruler and compass for the following construction:\n(a) construct an equilateral triangle ABC of side 5 cm.\n(b) construct the circumcircle of \\(\\Delta ABC\\)\n(c) construct the locus of points which are equidistant from AB and BC. Mark the point where the circumcircle and locus meet, as D.\n(d) give the geometrical name of quadrilateral ABCD.\n[Marks: 5] [ICSE Year: 2026]&quot;,
            &quot;Question 4 (iii): In the given diagram, \\(DE \\parallel BC\\) and \\(AD : DB = 2 : 3\\)\n(a) Prove that: \\(\\Delta ADE \\sim \\Delta ABC\\) and hence find \\(DE : BC\\)\n(b) Prove: \\(\\Delta DFE \\sim \\Delta CFB\\)\n(c) Given, area of \\(\\Delta DFE = 16\\) square units, find the area of \\(\\Delta CFB\\).\n[Marks: 4] [ICSE Year: 2026]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi5q5rluKSSRsdLgAlU66HLG4enWSkGS6SfGYFLKVm_qsDuZhwtOwpIUg0CXrpWHvU4YwLdbVLcRad7YUUuZlbxTPn0r37zaw6QwREDwA8O9IqvoAWwKcpJeKh-EebCTap6UzWzgJwA9tL2RheN4NNMNfaL2Xlz5Me6bkjVaagPzNpgSn5oxvo6HUsOdkI/s333/2026_4_iii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Triangle ABC with DE parallel to BC\&quot;&gt;&quot;,
            &quot;Question 5 (ii): \\(A(-10, -2)\\) and \\(B(2, 10)\\) are two end points of a line segment. If AB intersects the x-axis at P, find the:\n(a) ratio in which &#39;P&#39; divides AB.\n(b) coordinates of point P.\n[Marks: 3] [ICSE Year: 2026]&quot;,
            &quot;Question 8 (iii): Use graph sheet for this question. Take 2 cm = 1 unit along both x and y axis. Graphically represent parallelogram OABC, where \\(O(0, 0)\\), \\(A(2, 3)\\), \\(B(5, 3)\\) and \\(C(3, 0)\\).\nReflect OABC:\n(a) on the x-axis and name its image as ODEC.\n(b) through the origin and name its image as OIJH.\n(c) on the y-axis and name its image as OFGH.\n[Marks: 4] [ICSE Year: 2026]&quot;,
            &quot;Question 9 (ii): Use the following graph and answer the given questions:\n(a) Write the co-ordinates of points A, B and C.\n(b) Find the equation of a line passing through the mid-point of AC and parallel to AB.\n[Marks: 3] [ICSE Year: 2026]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg5G9NMoKEkjM59wXwwr6FABei8BmFJhpG63lSQWQZM0z4zDbpEGGFGz60HioDm7FxMkLGornys5i5MvTyp7zvDaTIMbGhxAYpE4VSie7Itua-xb858K14LbqB9KWCGl41vpdyN5gtsl9VejHHawRjPdlvLTlxZIQoz5-TxPv-G1yZaCaapjSPB_kps3HQ/s518/2026_9_ii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Graph showing triangle ABC\&quot;&gt;&quot;,
            &quot;Question 10 (iii): In the given figure O is the centre of the circle. PQ is a tangent to the circle at B and \\(AB = AC\\). If \\(\\angle CBQ = 40^\\circ\\) find the unknown angles \\(x, y, z\\) and \\(w\\).\n[Marks: 4] [ICSE Year: 2026]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjUTqD32V_uGfrxO3Mkpt48XXcuj0TYOoAY54twPf2ALKSXU9nErSIRSY2tGkV1g1Nc2tmwhCBPj-ktsOwQIDG0_gDkAVD0e2eYBHKn8uU9wwiY-JyW7MGGkdG1bvtcgqyVRxNvToCvM-yjnyvH4Ja-OJTldPGzyCPE7VjmRFFVgSz88hPQWCt48xCmpNA/s1283/2026_10_iii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Circle with tangent PQ at B\&quot;&gt;&quot;,
            &quot;Question 1 (ii): Assertion (A): In \\(\\triangle ABC\\) and \\(\\triangle PQR\\), if \\(\\angle BAC = \\angle QPR\\) and \\(\\angle ABC = \\angle PQR\\) then \\(\\triangle ABC \\sim \\triangle PQR\\)\nReason (R): \\(\\triangle ABC \\sim \\triangle PQR\\) by SSS axiom\n(a) (A) is true, (R) is false.\n(b) (A) is false, (R) is true.\n(c) Both (A) and (R) are true, and (R) is the correct reason for (A).\n(d) Both (A) and (R) are true, and (R) is the incorrect reason for (A).\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (iii): The ratio of diameters of two right circular cones is 3:7 and that of their heights is 14:9, then their volumes are in ratio:\n(a) 3:7\n(b) 2:7\n(c) 3:2\n(d) 9:49\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (viii): Assertion(A): If the length of shadow of a person is equal to his height, then the angle of elevation of the sun is \\(45^\\circ\\).\nReason(R): For any right-angled triangle, \\(\\tan\\theta = \\frac{\\text{Perpendicular}}{\\text{Base}}\\)\n(a) (A) is true, (R) is false.\n(b) (A) is false, (R) is true.\n(c) Both (A) and (R) are true, and (R) is the correct reason for (A).\n(d) Both (A) and (R) are true, and (R) is the incorrect reason for (A).\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (x): The locus of a toy bird fixed at the tip of one of the blades of a rotating ceiling fan is a:\n(a) straight line\n(b) circle\n(c) semi-circular arc\n(d) diameter of the circle so formed\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (xii): In the adjoining diagram, \\(PQ\\) is a tangent at \\(A\\) to the circle with centre \\(O\\). If \\(\\angle OAC = 25^\\circ\\), then \\(\\angle ABC\\) is:\n(a) \\(20^\\circ\\)\n(b) \\(65^\\circ\\)\n(c) \\(70^\\circ\\)\n(d) \\(130^\\circ\\)\n[Marks: 1] [ICSE Year: 2025 Improvement]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhF-Cy9YoN-fxJKVVtHsbf9hvFgx5fP67k93Zo_QVa_ZQmmQpvOGq3JPuPWn9LUe2S4ORNvPNPxNwpkGzb4p34OdS9DLHeaI_SM-fZLMg0f72GuCwozdYta3GJBP27fmGSnU_X-b1Gk22vTINfcnzq3Cqxc7e8dcPx4ooj-MSQ6S3U2y54SLx45f_qqUQE/s309/2025_IE_MCQ.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot;alt=\&quot;Circle with center O, tangent line PQ touching at point A, and interior angle OAC measuring 25 degrees\&quot;&gt;&quot;,
            &quot;Question 1 (xiv): The line segment joining \\(A(-7,2)\\) and \\(B(3,-8)\\) is divided by the \\(x\\)-axis in the ratio:\n(a) 1:4\n(b) 3:7\n(c) 4:1\n(d) 7:3\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 2 (ii): In the adjoining diagram \\(\\angle DOE = 46^\\circ\\) and \\(\\angle BGH = 113^\\circ\\)\n(a) Find \\(\\angle DBC\\) and \\(\\angle DCE\\).\n(b) Prove that \\(CBGH\\) is a cyclic quadrilateral.\n[Marks: 4] [ICSE Year: 2025 Improvement]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjpPUIJRKxev1b-RZiz4KRfCEid-vS4bl0DRB0aABq7LIm1-Rj2I46if7d2CDoPLA6VAKgJbmPIo6jb9DCV36YxYa9Sdil9FT2RduflKnN_wB158Lf8yuoBdZFiCHk7rNFlro8Mo6lGlMIl0N5xI7bg1VodQUe8ai2AyerL_XK1_6afQ0B04RYwBXt_T2U/s394/2025_IE_2_ii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Geometric line diagram with intersecting lines and points C, D, O, E, A, B, H, G showing given angle values\&quot;&gt;&quot;,
            &quot;Question 3 (iii): Using the given graph, answer the following:\n(a) Write down the coordinates of the points \\(A\\), \\(B\\), \\(C\\), and \\(E\\).\n(b) Name and write down the coordinates of the image of \\(B\\) under reflection in \\(x\\)-axis.\n(c) Name and write the coordinates of the image of \\(D\\) under reflection through the origin.\n(d) Which point is the image of \\(A\\) under reflection on the line \\(BH\\)? Write its coordinates.\n(e) Name the closed figure \\(ABCDEFGH\\).\n[Marks: 5] [ICSE Year: 2025 Improvement]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjvt-QiTGPGtA15XJdSGWFspcppiGM_im4jGnAy3qvuDQztzppiw7dUPqiamp5-ZkzOX9htH7Ljg5a6bdWS1MSnNWVUUNZwGS2jiVjbMsLbbm7uwnCAJ0mxHumbRmV5LWtduYs1Ss1uJ3ahxBbhL_d-Pj3v6WFTCsvxLBTR_n4FdvKhvjhv8VTbjpfGagg/s581/2025_IE_3_iii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Symmetric star-like closed geometric labeled vertices A to H\&quot;&gt;&quot;,
            &quot;Question 4 (ii): A right circular cone of radius 20 cm has its volume 8,800 cm³. Find its:\n(a) height\n(b) curved surface area\nGive your answer to the nearest whole number. [Use \\(\\pi = \\frac{22}{7}\\)]\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 4 (iii): Construct a regular hexagon of side 4.5 cm. Hence, construct a circle circumscribing the regular hexagon. Use ruler and compass for the construction. Measure and write down the radius of the circle.\n[Marks: 4] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 5 (iii): In the adjoining figure of a circle with centre \\(O\\) and diameter \\(AD\\), \\(\\angle BED = 70^\\circ\\) and \\(BC\\) is parallel to \\(AD\\). Find:\n(a) \\(\\angle BAD\\)\n(b) \\(\\angle BOD\\)\n(c) \\(\\angle DBC\\)\n(d) \\(\\angle DCF\\)\n[Marks: 4] [ICSE Year: 2025 Improvement]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgd7VaeOzoepmbKBs0RYC7FGpeDpKHqowv9lfagp7GUUwA9tNeACmxWitbVXn_B9JHj0CeTsF3Tqp22Sz2RsorZzOkSs5EsEzR_Barpt5mmVG4vpNxj8kjZr9bOgqiv9-6MlTJJdHpqlA2LQdoVbtUH2jbFTD7Hp9xbp1ny5trcp-pg3l_sObinJEGnUsU/s415/2025_IE_5_iii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Circle with center O, horizontal diameter AD, parallel line segment BC, and angle BED marked as 70 degrees\&quot;&gt;&quot;,
            &quot;Question 8 (ii): Equation of a line \\(AB\\) is \\(x + 2y + 6 = 0\\). A perpendicular \\(PQ\\) is dropped on \\(AB\\) from the point \\(P(3,-2)\\) meeting \\(AB\\) at \\(Q\\). Find the:\n(a) equation of \\(PQ\\).\n(b) coordinates of the point \\(Q\\).\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 10 (iii): Use ruler and compass for the following constructions:\nConstruct:\n(a) an isosceles triangle \\(ABC\\) in which \\(AB = AC = 7\\) cm and \\(BC = 6\\) cm.\n(b) the locus of points which moves such that it is 2.5 cm from the point \\(A\\).\n(c) the locus of points equidistant from \\(B\\) and \\(C\\). Mark point \\(P\\) which satisfies both the conditions mentioned in (b) and (c).\n(d) a circle passing through \\(P\\), \\(B\\) and \\(C\\).\n[Marks: 4] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (iv): The equation of the line passing through origin and parallel to the line \\(3x + 4y + 7 = 0\\) is:\n(a) \\(3x + 4y + 5 = 0\\)\n(b) \\(4x - 3y - 5 = 0\\)\n(c) \\(4x - 3y = 0\\)\n(d) \\(3x + 4y = 0\\)\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (vi): In the given diagram, chords \\(AC\\) and \\(BC\\) are equal. If \\(\\angle ACD = 120^\\circ\\), then \\(\\angle AEC\\) is:\n(a) \\(30^\\circ\\)\n(b) \\(60^\\circ\\)\n(c) \\(90^\\circ\\)\n(d) \\(120^\\circ\\)\n[Marks: 1] [ICSE Year: 2025]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgrNWEBazhDmwhYeFAJDZH1OwS4DbxXpC0Ki8Jm0265LkfCMf2MCn81BrlaUeDcApiEy3fHHSrmYhuKSxqSLkC_YDmMx1CcA9lcNGgv18KEEE_F-aZV3BhoPV9RksJ-OjSiyvzPnn_RlgWzUhR-fokKIh9S6qvXo87CheeYulr6Bvp1KmpqUmiFV45Lqrw/s324/2025_1_vi.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Circle with equal chords AC and BC\&quot;&gt;&quot;,
            &quot;Question 1 (ix): Statement 1: The point which is equidistant from three non-collinear points \\(D\\), \\(E\\) and \\(F\\) is the circumcentre of the \\(\\triangle DEF\\).\nStatement 2: The incentre of a triangle is the point where the bisector of the angles intersects.\n(a) Both the statements are true.\n(b) Both the statements are false.\n(c) Statement 1 is true, and Statement 2 is false.\n(d) Statement 1 is false, and Statement 2 is true.\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (xi): In the given diagram \\(\\triangle ABC \\sim \\triangle EFG\\). If \\(\\angle ABC = \\angle EFG = 60^\\circ\\) then the length of the side \\(FG\\) is:\n(a) 15 cm\n(b) 20 cm\n(c) 25 cm\n(d) 30 cm\n[Marks: 1] [ICSE Year: 2025]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEitKPm5hmyBep4WL0z1CqBBGBcCT6wkKiJRlH6s5kGfNsz6dtg547gZmb-ZpVoPYPm5vcHmFYkBVAS0SAYoEdzw64aWLZRQnIRtmAwwmeN8O1lB9N8afhboM3OAjpcXUw8pErjzRbPL9bS31vf5dG6uu1zU9TfOuGrr3k3xKRZpwwF40dA7EJtK2kAirMw/s508/2025_1_xi.png\&quot; height =\&quot;400\&quot; width =\&quot;600\&quot; alt=\&quot;Two similar triangles ABC and EFG with side lengths and 60 degree angles given\&quot;&gt;&quot;,
            &quot;Question 2 (iii): In \\(\\triangle ABC\\), \\(\\angle ABC = 90^\\circ\\), \\(AB = 20\\) cm, \\(AC = 25\\) cm, \\(DE\\) is perpendicular to \\(AC\\) such that \\(\\angle DEA = 90^\\circ\\) and \\(DE = 3\\) cm as shown in the given figure.\n(a) Prove that \\(\\triangle ABC \\sim \\triangle AED\\).\n(b) Find the lengths of \\(BC\\), \\(AD\\) and \\(AE\\).\n(c) If \\(BCED\\) represents a plot of land on a map whose actual area on ground is 576 m², then find the scale factor of the map.\n[Marks: 4] [ICSE Year: 2025]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgJTnNB22SLgnJ-cNJLIANJLzyssMQu-837htPGPzDrA4HBniZOZmc7iQZ224qV7vBpUhgR0-bj2sC9v5UKa1hUQL6xuBRIRNkx2ESWtNjicFZx_RgpTsUMWNdg47wD_e4N7kVbgbfjCtNO_F2ShU-7jZkfbYXI09QIAKTgGBLsnq0aTeogfSG8SlkNCs8/s267/2025_2_iii.png\&quot; height =\&quot;300\&quot; width =\&quot;300\&quot; alt=\&quot;Right-angled triangle ABC with an inscribed perpendicular DE to side AC\&quot;&gt;&quot;,
            &quot;Question 3 (i): Use ruler and compass for the following construction. Construct a triangle \\(ABC\\), where \\(AB = 6\\) cm, \\(AC = 4.5\\) cm and \\(\\angle BAC = 120^\\circ\\). Construct a circle circumscribing the \\(\\triangle ABC\\). Measure and write down the length of the radius of the circle.\n[Marks: 4] [ICSE Year: 2025]&quot;,
            &quot;Question 3 (iii): In the given graph \\(ABCD\\) is a parallelogram. Using the graph, answer the following:\n(a) write down the coordinates of \\(A\\), \\(B\\), \\(C\\) and \\(D\\).\n(b) calculate the coordinates of \\(P\\), the point of intersection of the diagonals \\(AC\\) and \\(BD\\).\n(c) find the slope of sides \\(CB\\) and \\(DA\\) and verify that they represent parallel lines.\n(d) find the equation of the diagonal \\(AC\\).\n[Marks: 5] [ICSE Year: 2025]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjLWL7je3n7d4oPwkKOt5Kv-R-46FXTQqFInHHOoQXKzcfvZxYh6ozeEpVNbpl3JhYMM3IXX0VrAfi-yjGeMw8KmYiH3ygP66O0bXbM5f6rV8twKOihMUlVHILLNm-OIgDatS69_cFt7MV-SFX8V-uqDzk48lOv2jKosdYKw4bNYWbw0RlMuLVIGyUBy3E/s575/2025_3_iii.png\&quot; height =\&quot;300\&quot; width =\&quot;300\&quot; alt=\&quot;Parallelogram ABCD plotted on a Cartesian coordinate plane \&quot;&gt;&quot;,
            &quot;Question 6 (i): Use a graph paper for this question taking 2 cm = 1 unit along both axes.\n(a) Plot \\(A(1,3)\\), \\(B(1,2)\\) and \\(C(3,0)\\).\n(b) Reflect \\(A\\) and \\(B\\) on the \\(x\\)-axis and name their images as \\(E\\) and \\(D\\) respectively. Write down their coordinates.\n(c) Reflect \\(A\\) and \\(B\\) through the origin and name their images as \\(F\\) and \\(G\\) respectively.\n(d) Reflect \\(A\\), \\(B\\) and \\(C\\) on the \\(y\\)-axis and name their images as \\(J\\), \\(I\\) and \\(H\\) respectively.\n(e) Join all the points \\(A, B, C, D, E, F, G, H, I\\) and \\(J\\) in order and name the closed figure so formed.\n[Marks: 5] [ICSE Year: 2025]&quot;,
            &quot;Question 7 (ii): In the given graph, \\(P\\) and \\(Q\\) are points such that \\(PQ\\) cuts off intercepts of 5 units and 3 units along the \\(x\\)-axis and \\(y\\)-axis respectively. Line \\(RS\\) is perpendicular to \\(PQ\\) and passes through the origin. Find the:\n(a) coordinates of \\(P\\) and \\(Q\\)\n(b) equation of line \\(RS\\)\n[Marks: 3] [ICSE Year: 2025]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEijmDLhv0jUTwyfpD8-5eIYdPE4yY1dUw1iQbSgsj9lau3cmdTY4rxMfT_mrrRHQKdbLvCw4nPUalquxn7CgNwkw58X00dpcowibJ7CNUmL_ejrispw-Y2A1c7bLpTwMIP9N7oSWIzNXuVsXtTyBWcFv3z7jLBcVtRiofo4J-QVWT_CQvq2o2urvIV2-Fk/s489/2025_7_ii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Graph showing line P\&quot;&gt;&quot;,
            &quot;Question 9 (iii): \\(X, Y, Z\\) and \\(C\\) are the points on the circumference of a circle with centre \\(O\\). \\(AB\\) is a tangent to the circle at \\(X\\) and \\(ZY = XY\\). Given \\(\\angle OBX = 32^\\circ\\) and \\(\\angle AXZ = 66^\\circ\\). Find:\n(a) \\(\\angle BOX\\)\n(b) \\(\\angle CYX\\)\n(c) \\(\\angle ZYX\\)\n(d) \\(\\angle OXY\\)\n[Marks: 4] [ICSE Year: 2025]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgJqASg71Ys0MBiP46-ZyISKzGtYnjpRKiBWIpF9mUsQ5jxwr739SWxcfB_UTlq6KNx16u8kLrW50udq-f8GyuIRvU8gZgzZrfM777rIWWWkBeD23YBjbzBPkI5WMsKj50mUckwcCnmwGKnIRemmsvejxM5aiSvZjTsxlLROyfQ2XzVC2VPVOgswAWvQjw/s414/2025_9_iii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Circle with tangent AB at point X and \&quot;&gt;&quot;,
            &quot;Question 10 (ii): In the given diagram \\(O\\) is the centre of the circle. Chord \\(SR\\) produced meets the tangent \\(XTP\\) at \\(P\\).\n(a) Prove that \\(\\triangle PTR \\sim \\triangle PST\\)\n(b) Prove that \\(PT^2 = PR \\times PS\\)\n(c) If \\(PR = 4\\) cm and \\(PS = 16\\) cm, find the length of the tangent \\(PT\\).\n[Marks: 3] [ICSE Year: 2025]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjgP3xYbA3OLVm-7PoLrAzJZPNIkdkX3zBK39TDyt35onlgfdnuEaVuH9dCoto1wZha1oYrVd67yCYX8vecFPTDuU5FS-7MpqEQvPhMPS-ZX27pSuVw5Hzj0al7z57g7BKxQngzUcTwDhskewwk6I35em158oY77_VtCnXA9SEQvFNijJbP-wS64bptFps/s373/2025_10_ii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Circle with secant line SRP and tangent line XTP meeting at external point P\&quot;&gt;&quot;,
            &quot;Question 1 (vi): Points \\(A (x, y)\\), \\(B (3, -2)\\) and \\(C (4, -5)\\) are collinear. The value of \\(y\\) in terms of \\(x\\) is:\n(a) \\(3x - 11\\)\n(b) \\(11 - 3x\\)\n(c) \\(3x - 7\\)\n(d) \\(7 - 3x\\)\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (x): The circumcentre of a triangle is the point which is:\n(a) at equal distance from the three sides of the triangle.\n(b) at equal distance from the three vertices of the triangle.\n(c) the point of intersection of the three medians.\n(d) the point of intersection of the three altitudes of the triangle.\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (xii): In the given diagram, \\(PS\\) and \\(PT\\) are the tangents to the circle. \\(SQ \\parallel PT\\) and \\(\\angle SPT = 80^\\circ\\). The value of \\(\\angle QST\\) is:\n(a) \\(140^\\circ\\)\n(b) \\(90^\\circ\\)\n(c) \\(80^\\circ\\)\n(d) \\(50^\\circ\\)\n[Marks: 1] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjpFcvYz4tCPQkH2T0420kbnNTj37yqspEfWcpBWxS_aNQkG3SF9iNpHAM3BF6X13BlkzeLsScfNrO_QYSYPlISP4H2ZfL2m_boVSBXUd9g_UElXG1tuRm7OI7PCG-ZaVla61-mUR16WqlHp0PcLCn5sKXrj3hNTfvrEaIil2WNZlQXdOWo9ofzt68O4Rs/s281/2024_1_xii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Circle with tangents PS and PT, and parallel chord SQ\&quot;&gt;&quot;,
            &quot;Question 1 (xv): In the given diagram, \\(\\triangle ABC \\sim \\triangle PQR\\). If \\(AD\\) and \\(PS\\) are bisectors of \\(\\angle BAC\\) and \\(\\angle QPR\\) respectively then:\n(a) \\(\\triangle ABC \\sim \\triangle PQS\\)\n(b) \\(\\triangle ABD \\sim \\triangle PQS\\)\n(c) \\(\\triangle ABD \\sim \\triangle PSR\\)\n(d) \\(\\triangle ABC \\sim \\triangle PSR\\)\n[Marks: 1] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgEU9NXIOPwYrzCZquH0sZGJzgWlB5MwSw155_C4uASOfzSIy-qe6ke3z-8gWxUk6ZNtB2qJ4Ed_fCjWI-BO-3Qzl7ksOtZoW3BINKJIiQzOSwgBQ6MDHknUadGglG86Xi2lB0pCKC7Z6Fsw9hkJ2kTcPPgt4Jagtf2JV6oM4FPoGj8wGHmV93OQXZ3dF0/s431/2024_1_xv.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Two similar triangles ABC and PQR with angle bisectors AD and PS\&quot;&gt;&quot;,
            &quot;Question 3 (ii): In the given diagram, \\(O\\) is the centre of the circle. \\(PR\\) and \\(PT\\) are two tangents drawn from the external point \\(P\\) and touching the circle at \\(Q\\) and \\(S\\) respectively. \\(MN\\) is a diameter of the circle. Given \\(\\angle PQM = 42^\\circ\\) and \\(\\angle PSM = 25^\\circ\\). Find:\n(a) \\(\\angle OQM\\)\n(b) \\(\\angle QNS\\)\n(c) \\(\\angle QOS\\)\n(d) \\(\\angle QMS\\)\n[Marks: 4] [ICSE Year: 2024] \n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiIg6ZukhgRKyk3406enyE8zCi4QAIAuAbb3eU6uaOiQ5nnK8B7LyaLACgcfBzR3lRsn0093YbZ7-UIehdsBpYf9t2PvuKW7hAvVAwGZnLnsNORnehtTE19u2Ltdq0OeLDRTraSvcWnvJss5rOVUQXg7TuvAYbTeW1OVeHBe2jFRHEqlvRtY9SvBkkHbrs/s322/2024_3_ii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Circle with thwo tangents\&quot;&gt;&quot;,
            &quot;Question 3 (iii): Use graph sheet for this question. Take 2 cm = 1 unit along the axes.\n(a) Plot \\(A(0,3)\\), \\(B(2,1)\\) and \\(C(4,-1)\\).\n(b) Reflect point \\(B\\) and \\(C\\) in \\(y\\)-axis and name their images as \\(B&#39;\\) and \\(C&#39;\\) respectively. Plot and write coordinates of the points \\(B&#39;\\) and \\(C&#39;\\).\n(c) Reflect point \\(A\\) in the line \\(BB&#39;\\) and name its images as \\(A&#39;\\).\n(d) Plot and write coordinates of point \\(A&#39;\\).\n(e) Join the points \\(ABA&#39;B&#39;\\) and give the geometrical name of the closed figure so formed.\n[Marks: 5] [ICSE Year: 2024]&quot;,
            &quot;Question 6 (iii): In the given diagram \\(\\triangle ADB\\) and \\(\\triangle ACB\\) are two right angled triangles with \\(\\angle ADB = \\angle BCA = 90^\\circ\\). If \\(AB = 10\\) cm, \\(AD = 6\\) cm, \\(BC = 2.4\\) cm and \\(DP = 4.5\\) cm.\n(a) Prove that \\(\\triangle APD \\sim \\triangle BPC\\)\n(b) Find the length of \\(BD\\) and \\(PB\\)\n(c) Hence, find the length of \\(PA\\)\n(d) Find area \\(\\triangle APD\\) : area \\(\\triangle BPC\\)\n[Marks: 4] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgGgueMfTSXFtN36Sku95puULLMpnDMB_186SjIGs9y-cjxh3I2VcWw5rC_AJZAZ8422uZiHX5O0AbSSc0EoKcUzviLbYHaZPOm9hJd16KXoRmkCCGzIs3llU_kdj02PnHhqEogakIzlxILE_9pvyrVi8f52wSiQrMl2oK1DKqd1v8Rih95wF2v5ED3KBs/s369/2024_6_iii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Two intersecting right angled triangles ADB and ACB sharing base AB\&quot;&gt;&quot;,
            &quot;Question 7 (i): In the given diagram, an isosceles \\(\\triangle ABC\\) is inscribed in a circle with centre \\(O\\). \\(PQ\\) is a tangent to the circle at \\(C\\). \\(OM\\) is perpendicular to chord \\(AC\\) and \\(\\angle COM = 65^\\circ\\). Find:\n(a) \\(\\angle ABC\\)\n(b) \\(\\angle BAC\\)\n(c) \\(\\angle BCQ\\)\n[Marks: 3] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhrqDFHfJq0pUm4-G0wvbaemZ5980sm2l0Lwb4eqnqh7Np2GqwV9pOTssWiA1UakiHDxdug6luylrWKg3dBEINteNRoZKzmtIcTPD4wYxXaS3olROjkwjX-0ETN3_VR9sW5aLKOTmxA5GSlX5h-hVQ1ZLknxB8UX0mjKHy2kkBzJQQWWTOonywGksaThhE/s289/2024_7_i.png\&quot; height =\&quot;350\&quot; width =\&quot;350\&quot; alt=\&quot;Isosceles triangle inscribed in a circle with a tangent at one vertex\&quot;&gt;&quot;,
            &quot;Question 7 (iii): In the given diagram, \\(ABC\\) is a triangle, where \\(B(4, -4)\\) and \\(C(-4, -2)\\). \\(D\\) is a point on \\(AC\\).\n(a) Write down the coordinates of \\(A\\) and \\(D\\).\n(b) Find the coordinates of the centroid of \\(\\triangle ABC\\).\n(c) If \\(D\\) divides \\(AC\\) in the ratio \\(k : 1\\), find the value of \\(k\\).\n(d) Find the equation of the line \\(BD\\).\n[Marks: 4] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjfV-zLiNhyphenhyphenzI0YU2pPTA3Ul-qCFqjtOeeyZ8N3SsHAHrXkDmy3xwQfAl9CjR8jTQWIp_h5BpXPaw213vIhQlb935gIZiSoheiHpA68xBPQKtItQY5FrWTlds4RLygJMyRScLrjgCj4sfmSUQ88JwIOi-TiDbpZ7_WyvX5QADSYyDqXzYTUUfajZK8gdXs/s457/2024_7_iii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Triangle ABC plotted on a coordinate plane with points B and C labeled\&quot;&gt;&quot;,
            &quot;Question 9 (i): The figure shows a circle of radius 9 cm with \\(O\\) as the centre. The diameter \\(AB\\) produced meets the tangent \\(PQ\\) at \\(P\\). If \\(PA = 24\\) cm, find the length of tangent \\(PQ\\).\n[Marks: 3] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiqYL2C9ZmRPS6TBtwle9Rjyq93-xU4_1HJl2DLlay3IsNSTdVwMUtxrX-a9j6n95tiMNM4HvSO7z1_dSfE9HKClFySFGdLvrQ9RA9V4Ws7N7das0efeUzhZ30aSEs736EGJiDjKFqrZJRWs7nZ1TYujGuZ8D3oCFV8L_1Yp1IGUFq1tnCE4fyGGM4yFqc/s351/2024_9_i.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Circle with tangent PQ and secant line PAB\&quot;&gt;&quot;,
            &quot;Question 10 (ii): (a) If the lines \\(kx - y + 4 = 0\\) and \\(2y = 6x + 7\\) are perpendicular to each other, find the value of \\(k\\).\n(b) Find the equation of a line parallel to \\(2y = 6x + 7\\) and passing through \\((-1, 1)\\)\n[Marks: 3] [ICSE Year: 2024]&quot;,
            &quot;Question 10 (iii): Use ruler and compass to answer this question. Construct \\(\\angle ABC = 90^\\circ\\), where \\(AB = 6\\) cm, \\(BC = 8\\) cm.\n(a) Construct the locus of points equidistant from \\(B\\) and \\(C\\).\n(b) Construct the locus of points equidistant from \\(A\\) and \\(B\\).\n(c) Mark the point which satisfies both the conditions (a) and (b) as \\(O\\). Construct the locus of points keeping a fixed distance \\(OA\\) from the fixed point \\(O\\).\n(d) Construct the locus of points which are equidistant from \\(BA\\) and \\(BC\\).\n[Marks: 4] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (iii): In the given diagram RT is a tangent touching the circle at S. If \\(\\angle PST = 30^\\circ\\) and \\(\\angle SPQ = 60^\\circ\\) then \\(\\angle PSQ\\) is equal to:\n(a) \\(40^\\circ\\)\n(b) \\(30^\\circ\\)\n(c) \\(60^\\circ\\)\n(d) \\(90^\\circ\\)\n[Marks: 1] [ICSE Year: 2023]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhu2KIlZBT9M4uF0x461B_vV4N9UF-UKnzHVFTxwVht0LSDPm8ymKQtCyBSWLnJSPdPzgWxMBEHwKUV9p2gk-qCgwOErVvnQkU1moqOtuvtMCb2R-SqNJH_cEJMlrKbECYsOncEJo5Si_1FQZIq-mvzPsS9a731iI5_JcavEgFBY49uV79F1XmRs3XhPBE/s360/2023_1_iii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Circle with tangent RT at point S\&quot;&gt;&quot;,
            &quot;Question 1 (vi): In the given figure \\(\\angle BAP = \\angle DCP = 70^\\circ\\), \\(PC = 6\\) cm and \\(CA = 4\\) cm, then \\(PD : DB\\) is:\n(a) 5:3\n(b) 3:5\n(c) 3:2\n(d) 2:3\n[Marks: 1] [ICSE Year: 2023]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhoCOL4fb0U5_DW1yFdWTQQwrFn_QWtinDaq0EtWIswlEr2HwJ7YlWFzNiflEA5kfR_i3wgIjteqOTJ5k3bDucQ4K1rPZBOTY-TuHcPkXK93gcphxXdFIt9jq2niB7LNdM5mjnfygjfjx1_41aa_LD1UG0jdlpV1P9OPc2ggsMyv-C5fLYF7Ox4As3lrWo/s427/2023_1_vi.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Geometric Diagram\&quot;&gt;&quot;,
            &quot;Question 1 (ix): The coordinates of the vertices of \\(\\triangle ABC\\) are respectively \\((-4, -2)\\), \\((6, 2)\\) and \\((4, 6)\\). The centroid G of \\(\\triangle ABC\\) is:\n(a) (2, 2)\n(b) (2, 3)\n(c) (3, 3)\n(d) (0, -1)\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 2 (iii): In the given figure O, is the centre of the circle. CE is a tangent to the circle at A. If \\(\\angle ABD = 26^\\circ\\) then find:\n(a) \\(\\angle BDA\\)\n(b) \\(\\angle BAD\\)\n(c) \\(\\angle CAD\\)\n(d) \\(\\angle ODB\\)\n[Marks: 4] [ICSE Year: 2023]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjFah7uyW1jWtgI-Ffw4JfKerzquKqFpEqORJJsJq0bzkgUmw-PSzPsvReQ08B1ufYODFogod86pzqKgUA9Fr6mKY8t4nMmGZz2CfCV6q1RMQsmehwAjhvmIykZ3608_y3LqAz60hlJByedS3oGpDWQ8vKRiB6qUVqAMjLs4VPA-K4LRZfoililaEcVB-s/s319/2023_2_iii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Geometric Diagram\&quot;&gt;&quot;,
            &quot;Question 3 (iii): Use graph sheet to answer this question. Take 2 cm = 1 unit along both the axes.\n(a) Plot A, B, C where \\(A(0, 4)\\), \\(B(1, 1)\\) and \\(C(4, 0)\\)\n(b) Reflect A and B on the x-axis and name them as E and D respectively.\n(c) Reflect B through the origin and name it F. Write down the coordinates of F.\n(d) Reflect B and C on the y-axis and name them as H and G respectively.\n(e) Join points A, B, C, D, E, F, G, H and A in order and name the closed figure formed.\n[Marks: 5] [ICSE Year: 2023]&quot;,
            &quot;Question 4 (ii): ABC is a triangle whose vertices are \\(A(1, -1)\\), \\(B(0, 4)\\) and \\(C(-6, 4)\\). D is the midpoint of BC. Find the:\n(a) coordinates of D.\n(b) equation of the median AD.\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 4 (iii): In the given figure, O is the centre of the circle. PQ is a tangent to the circle at T. Chord AB produced meets the tangent at P. \\(AB = 9\\) cm, \\(BP = 16\\) cm, \\(\\angle PTB = 50^\\circ\\), \\(\\angle OBA = 45^\\circ\\). Find:\n(a) length of PT\n(b) \\(\\angle BAT\\)\n(c) \\(\\angle BOT\\)\n(d) \\(\\angle ABT\\)\n[Marks: 4] [ICSE Year: 2023]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEirMcjGzcIpzmokx6NQa7mr8-38-Bp6vei95mqhwyGbC8iG9nq4SwelyjGDYz40PIX1zq_UcW7ARCb7xjZldC3iPxgD5dBUWKAdgupYb93fQ-tOe4ng1YwYON0Jpk-SSjB_6Wi_JgEgARGuyum2HQKFqbhTe89wsO8GUue-J3KAUteFFtiAFwc-Kp8rLyk/s413/2023_4_iii.png\&quot; height=\&quot;400\&quot; width=\&quot;500\&quot; alt=\&quot;Geometric Diagram\&quot;&gt;&quot;,
            &quot;Question 5 (iii): In the given figure, \\(AC \\parallel DE \\parallel BF\\). If \\(AC = 24\\) cm, \\(EG = 8\\) cm, \\(GB = 16\\) cm, \\(BF = 30\\) cm.\n(a) Prove \\(\\triangle GED \\sim \\triangle GBF\\)\n(b) Find DE\n(c) DB: AB\n[Marks: 4] [ICSE Year: 2023]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEig03r3blgAbmFlPknLCmKQTiMN8F2qLTxG41YuRQJUE8iyHBhAc1D_RUZG-HG25AFmqoiSI8zSXduN-0ZKLg_y2oTj7gF0OPt9uvBWhvYdw-MWAwNvHvDZ7mZFuR_v0FlPnahmkuJHUBYTldI679kxD8k32-2qGUzFmKJyzbufWHIIBUQiNmC2VnYJKd4/s400/2023_5_iii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Geometric Diagram\&quot;&gt;&quot;,
            &quot;Question 6 (iii): A and B are two points on the x-axis and y-axis respectively.\n(a) Write down the coordinates of A and B.\n(b) P is a point on AB such that AP: PB = 3: 1. Using section formula find the coordinates of point P.\n(c) Find the equation of a line passing through P and perpendicular to AB.\n[Marks: 4] [ICSE Year: 2023]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjPzEfkvLJbKQ2X_6Pz9lcPq9iwntN-xGeXZE72xQrWreKn8u9oT5FuM-dwRWz9mhorE7KAL-ptRlLIQLCtEGC8X0ONKLY_RBeVCEndhYm_rB9__2SWf_y08wmt0-l7AOnhNVvezfvopN1RmtuYI6I6AOdFHb2B5HA_x8T-8fHocLmEja1aEtCqSn2wye0/s561/2023_6_iii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Geometric Diagram\&quot;&gt;&quot;,
            &quot;Question 8 (iii): Using ruler and compass construct a triangle ABC in which \\(AB = 6\\) cm, \\(\\angle BAC = 120^\\circ\\) and \\(AC = 5\\) cm. Construct a circle passing through A, B and C. Measure and write down the radius of the circle.\n[Marks: 4] [ICSE Year: 2023]&quot;

        ];

        const trigonometry = [
            &quot;Question 4 (i): Prove that:\n\\((\\sec\\theta - \\cos\\theta)(\\csc\\theta - \\sin\\theta) = \\sin\\theta \\cos\\theta\\)\n[Marks: 3] [ICSE Year: 2026]&quot;,
            &quot;Question 7 (i): A flagpole is erected at the top of a building. The angle of elevation of the top and foot of the flagpole from a point 100 m away, on the same level as that of the foot of the building, are \\(33^\\circ\\) and \\(31^\\circ\\) respectively. Find the height of the flagpole. Give your answer correct to the nearest metre. (Use Mathematical Tables for this question.)\n[Marks: 5] [ICSE Year: 2026]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjAyxYx9JBa1NpUTYjtgWFw-Ma2-b18y3IJ3KUcsQ_YaQTUa7ZQvjWzJ3E-iv1YWloHvrl_OSnapTmPfKWC5BEGZcaRcisinIzohBvgXVIV_3-BuJq_7fV8sh31Sas-b9lDdRVbVzIZQVPdWy-WzQdYMNLTi80d_B4-milv6sYvF1u4Cotw0qo-6jELhvE/s1353/2026_7_i.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Trigonometric diagram showing angles of elevation 33 and 31 degrees\&quot;&gt;&quot;,
            &quot;Question 1 (viii): Assertion(A): If the length of shadow of a person is equal to his height, then the angle of elevation of the sun is \\(45^\\circ\\).\nReason(R): For any right-angled triangle, \\(\\tan\\theta = \\frac{\\text{Perpendicular}}{\\text{Base}}\\)\n(a) (A) is true, (R) is false.\n(b) (A) is false, (R) is true.\n(c) Both (A) and (R) are true, and (R) is the correct reason for (A).\n(d) Both (A) and (R) are true, and (R) is the incorrect reason for (A).\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 4 (iii): Prove that:\n\\(\\frac{(\\cot A + \\tan A - 1)(\\sin A + \\cos A)}{\\sin^3 A + \\cos^3 A} = \\sec A \\cdot \\csc A\\)\n[Marks: 4] [ICSE Year: 2025]&quot;,
            &quot;Question 6 (ii): In the given diagram, \\(AB\\) is a vertical tower 100 m away from the foot of a 30 storied building \\(CD\\). The angles of depression from the point \\(C\\) and \\(E\\), (\\(E\\) being the mid-point of \\(CD\\)), are \\(35^\\circ\\) and \\(14^\\circ\\) respectively. Find the height of the:\n(a) tower \\(AB\\)\n(b) building \\(CD\\)\n(Use mathematical table for the required values rounded off correct to two places of decimals only)\n[Marks: 5] [ICSE Year: 2025]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjakoS4uSdebGrY-mwbHADipe-uPIaiORBsaMJLfp5rJCtlx8Ib9hP-HXN5Nf-t-BijJfDvxESZIINNA1x14rl13RJlji4RZT8eXUju0iaKlV4YwAldk16dfA51hXmRjmMaTkY0jlDN7QsFOEAiR93LZxvshVHrbJDx84VyRuPzrCzP7eq2-NbadVyy-SQ/s596/2025_6_ii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Trigonometric diagram showing wer AB\&quot;&gt;&quot;,
            &quot;Question 9 (ii): The angle of elevation of the top of a hill from the foot of a tower at \\(B\\) is \\(50^\\circ\\). The angle of elevation of the top of the tower 100 m high from the foot of the hill at \\(C\\) is \\(35^\\circ\\). Find the:\n(a) horizontal distance \\(BC\\) between the Hill and the Tower.\n(b) height \\(CD\\) of the Hill. (Take \\(\\tan 50^\\circ = 1.20\\))\n(c) time taken by a cyclist to cover the distance \\(BC\\), cycling at 20 m/sec.\n[Marks: 5] [ICSE Year: 2025 Improvement]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjS2juoabh7QnkzV2XHPcvkH_VeRRRg-F1oMMYNyMoXibfSr75qqwMATIqRdYm04x1QbxMW4ib2YqsQ3yOhjyGa0rFk_8CWSWzm4leLf2BNguaXfDaokCtJPZNIsD8WAt_ugc3LWwauvSpzRb5hz1LQZIJ0jZxWoXHW7zQGK08-mesemmobsGPtj-RMgh4/s601/2025_IE_9_ii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Trigonometric diagram showing a 100m vertical tower AB and a taller hill CD separated by baseline BC with ground angles 50 and 35 degrees\&quot;&gt;&quot;,
            &quot;Question 1 (xi): Statement 1: \\(\\sin^2\\theta + \\cos^2\\theta = 1\\). Statement 2: \\(\\csc^2\\theta + \\cot^2\\theta = 1\\). Which of the following is valid?\n(a) only 1\n(b) only 2\n(c) both 1 and 2\n(d) neither 1 nor 2\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 3 (i): Factorize: \\(\\sin^3\\theta + \\cos^3\\theta\\). Hence, prove the following identity: \\(\\frac{\\sin^3\\theta + \\cos^3\\theta}{\\sin\\theta + \\cos\\theta} + \\sin\\theta\\cos\\theta = 1\\)\n[Marks: 4] [ICSE Year: 2024]&quot;,
            &quot;Question 5 (ii): The angle of elevation of the top of a 100 m high tree from two points \\(A\\) and \\(B\\) on the opposite side of the tree are \\(52^\\circ\\) and \\(45^\\circ\\) respectively. Find the distance \\(AB\\), to the nearest metre.\n[Marks: 5] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (viii): \\((1 + \\sin A)(1 - \\sin A)\\) is equal to:\n(a) \\(\\csc^2 A\\)\n(b) \\(\\sin^2 A\\)\n(c) \\(\\sec^2 A\\)\n(d) \\(\\cos^2 A\\)\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 3 (ii): Prove the following identity:\n\\((\\sin^2\\theta - 1)(\\tan^2\\theta + 1) + 1 = 0\\)\n[Marks: 4] [ICSE Year: 2023]&quot;,
            &quot;Question 9 (iii): From the top of a tower 100 m high a man observes the angles of depression of two ships A and B, on opposite sides of the tower as \\(45^\\circ\\) and \\(38^\\circ\\) respectively. If the foot of the tower and the ships are in the same horizontal line find the distance between the two ships A and B to the nearest metre. (Use Mathematical Tables for this question.)\n[Marks: 4] [ICSE Year: 2023]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhYSEvSmDQzOKDGbcnDNwTr6l8jd8rRGEsvCIrNHtGIA51ZZ8bOI_k_eJso7VCdH4wkZmewoA1443HJfJlNEtUZyNye6_UcPeEPFf1nWvk_gW_GSZvaRcUEcXKg4ddDpavYhmZLgpwL1h5DLQHZGTuql9h7zkIx5Yt2I20_7PGneh_J4mH6jHqiPAujYsU/s487/2023_9_iii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Geometric Diagram\&quot;&gt;&quot;

        ];

        const probabilityStatistics = [
            &quot;Question 1 (iii): Rakhi&#39;s mobile number has the following integers: 1, 6, 9, 8, 9, 1, 7, 8, 9. The mode of the above given data is:\n(a) 1\n(b) 6\n(c) 8\n(d) 9\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 1 (x): Assertion (A): If a die is rolled, the probability of getting a number greater than 6 is \\(\\frac{1}{6}\\).\nReason (R): There are six possible outcomes when rolling a die, {1, 2, 3, 4, 5, 6}.\n(a) (A) is true and (R) is false.\n(b) (A) is false and (R) is true.\n(c) Both (A) and (R) are true and (R) is the correct explanation of (A).\n(d) Both (A) and (R) are true but (R) is not the correct explanation of (A).\n[Marks: 1] [ICSE Year: 2026]&quot;,
            &quot;Question 5 (i): The histogram drawn on the graph represents the number of students of different heights (in cm).\nUsing the graph, answer the following:\n(a) the number of students whose height is 150 cm and above.\n(b) the modal height.\n(c) the total number of students.\n[Marks: 5] [ICSE Year: 2026]\n&lt;img src=\&quot;icse_2026_5_i.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Histogram showing number of students vs height\&quot;&gt;&quot;,
            &quot;Question 6 (ii): Find the mean of the following frequency distribution using step-deviation method. Take assumed mean = 28.\nClass Interval: 0-8 (10), 8-16 (20), 16-24 (14), 24-32 (16), 32-40 (18), 40-48 (22).\n[Marks: 3] [ICSE Year: 2026]&quot;,
            &quot;Question 7 (ii): Using a graph paper, draw an ogive for the following distribution which shows a record of weight in kilograms of 100 students.\nWeight (in kg): 35-40 (4), 40-45 (6), 45-50 (10), 50-55 (24), 55-60 (26), 60-65 (17), 65-70 (8), 70-75 (5).\nUse your ogive to estimate the following:\n(a) the median weight of the students.\n(b) percentage of students whose weight is 60 kg or more.\n(c) the weight above which 20% of the students lie.\n[Marks: 5] [ICSE Year: 2026]&quot;,
            &quot;Question 10 (ii): A survey was conducted on 300 families having 2 children each. The results obtained are given below.\nNumber of girl child: 2 (95 families), 1 (165 families), 0 (40 families). Total: 300.\nIf one family is selected at random, find the probability that it will have:\n(a) one girl child\n(b) one or more girl child\n(c) no boy child\n[Marks: 3] [ICSE Year: 2026]&quot;,

            &quot;Question 1 (i): When polynomial \\(x^3 - 3x^2 - 6x + 8\\) is divided by \\((x + 2)\\), the remainder is zero. The probability of \\((x + 2)\\) to be one of the factors of the given polynomial is:\n(a) \\(0\\)\n(b) \\(\\frac{1}{3}\\)\n(c) \\(\\frac{2}{3}\\)\n(d) \\(1\\)\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 1 (vi): The mean of \\(1^2, 2^2, 3^3\\) and \\(4^4\\) is:\n(a) \\(24\\)\n(b) \\(72\\)\n(c) \\(144\\)\n(d) \\(264\\)\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 2 (iii): The table given below shows a record of the weight in kilogram of 200 students of a school. Draw a histogram and find the modal weight. [Take 2 cm = 5 kg along one axis and 2 cm = 5 students along the other axis] \n[Marks: 4] [ICSE Year: 2025 Improvement] \n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhwAyrCDuAGX_9Hj-aFcHhGaqzIoUajSgc7CmKZ1aKxLR231Y64kUkLJbamD0vy80RA36bC-QUivQviqo58OBNfNGHY5MJOMoMbEH3Nil4H5-Gqbui-Mo2OlNboY8diVY6Fv94rkgp_aVoamYPUQgNtCgFOEUsyYHW9HFe_S4xeBQmsh19v0nQ2kojFuI0/s428/2025_IE_2_iii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Distribution table\&quot;&gt;&quot;,
            &quot;Question 7 (i): There are some red, green and white marbles in a box. One marble is picked up at random from this box. If the probability of picking up a red marble is \\(\\frac{4}{9}\\) and that of picking up a green marble is \\(\\frac{2}{9}\\), then find the:\n(a) probability of picking up a white marble.\n(b) number of green marbles, if total number of marbles is 54.\n(c) probability of not picking up a red marble.\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 9 (i): Use a graph paper for this question: The Marks out of 80 obtained by 160 students in a Mathematics test were recorded. Draw an Ogive and use it to find the median marks, upper quartile marks, number of students who scored above 65 marks, and the lowest marks scored by the top 30% students.\n[Marks: 5] [ICSE Year: 2025 Improvement]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiqLnxGkYlpgMZ3H4XgKeMrgLGlS9X9nqs2tU1varBMV8nD2-oBPYmsfpo6b_0cAQ9KilYKgogz7wrb2T1LlV3jXI3Ndl-FoBiN5DE-HgcCIrF0Sr8eziPYMM2KxIHIqE3als60HimubOT4U9dc6yNRPoT6NQrgH2v45KYR6WcoA4YH5xX-jIEyoe1n7dM/s668/2025_IE_9_i.png\&quot; height =\&quot;300\&quot; width =\&quot;700\&quot; alt=\&quot;Distribution table\&quot;&gt;&quot;,
            &quot;Question 10 (ii): Using short-cut method, find Mean of the given frequency distribution.\n[Marks: 3] [ICSE Year: 2025 Improvement]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjaC6C6G1TG6706hrh3gpL4lZ5-DhoLigbSHlT7hBzC_4tT1FSZYHU-skbA0vQyo3YN9P8aCqrb42JPo69PWYs2uidDSdbKTF3FRMJebp4rn8-B7e9aSqE84LcSDgDFAvNeOQ-9kefsu0qG7lSvr6erPIZdg1osDXmbW0na8KLKVX8Xqws1IWscwTXt4sc/s687/2025_IE_10_ii.png\&quot; height =\&quot;300\&quot; width =\&quot;700\&quot; alt=\&quot;Distribution table\&quot;&gt;&quot;,
            &quot;Question 1 (iii): Which of the following cannot be the probability of any event?\n(a) \\(\\frac{5}{4}\\)\n(b) \\(0.25\\)\n(c) \\(\\frac{1}{33}\\)\n(d) \\(67\\%\\)\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (xv): Assertion(A): The mean of first 9 natural numbers is 4.5.\nReason(R): Mean = Sum of all the observations / Total number of observations\n(a) (A) is true, (R) is false.\n(b) (A) is false, (R) is true.\n(c) Both (A) and (R) are true, and (R) is the correct reason for (A).\n(d) Both (A) and (R) are true, and (R) is the incorrect reason for (A).\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 7 (i): Use a graph paper for this question. (Take 2 cm = 10 Marks along one axis and 2 cm = 10 students along another axis). Draw a Histogram for the following distribution which gives the marks obtained by 164 students in a particular class and hence find the Mode.\nMarks: 30-40 (10 students), 40-50 (26 students), 50-60 (54 students), 60-70 (40 students), 70-80 (34 students).\n[Marks: 3] [ICSE Year: 2025]&quot;,
            &quot;Question 8 (ii): For the given frequency distribution, find the: (a) mean, to the nearest whole number (b) median.\nX: 10 (f=2), 11 (f=3), 12 (f=2), 13 (f=6), 14 (f=3), 15 (f=5), 16 (f=3).\n[Marks: 3] [ICSE Year: 2025]&quot;,
            &quot;Question 9 (ii): Ms. Sushmita went to a fair and participated in a game. The game consisted of a box having number cards with numbers from 01 to 30. The three prizes were as per the given table: Wall Clock (perfect square), Water Bottle (even number which is also a multiple of 3), Purse (prime number). Find the probability of winning a:\n(a) Wall Clock\n(b) Water Bottle\n(c) Purse\n[Marks: 3] [ICSE Year: 2025]&quot;,
            &quot;Question 10 (iii): The given graph represents the monthly salaries (in ₹) of workers of a factory. Using graph answer the following:\n(a) the total number of workers.\n(b) the median class.\n(c) the lower-quartile class.\n(d) number of workers having monthly salary more than or equal to ₹6,000 but less than ₹10,000.\n[Marks: 4] [ICSE Year: 2025]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjV691j5TYw8MEBbA8kLNY6x1lme_zOmzd4FS7IUZr8XMP8j6An8MsVgIhfzIC7T1IxML1njApuvjtgXdSAef5GMYY5cMvR6M0WHT0xo6okguOmcOwxWUCcSFF9094WILlAI1Qb3KcX6ZhD1AtTCeNkcz91S2nyqjxCYu-wMNuMXInDytcQVco3MrzaGY4/s584/2025_10_iii.png\&quot; height =\&quot;600\&quot; width =\&quot;600\&quot; alt=\&quot;Ogive curve graph \&quot;&gt;&quot;,
            &quot;Question 1 (v): The median of the following observations arranged in ascending order is 64. Find the value of \\(x\\): 27, 31, 46, 52, \\(x\\), \\(x + 4\\), 71, 79, 85, 90\n(a) 60\n(b) 61\n(c) 62\n(d) 66\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 1 (xiii): Assertion (A): A die is thrown once and the probability of getting an even number is \\(\\frac{2}{3}\\). Reason (R): The sample space for even numbers on a die is \\(\\{2, 4, 6\\}\\).\n(a) A is true, R is false.\n(b) A is false, R is true.\n(c) Both A and R are true.\n(d) Both A and R and false.\n[Marks: 1] [ICSE Year: 2024]&quot;,
            &quot;Question 4 (ii): The following table gives the duration of movies in minutes. Using step - deviation method, find the mean duration of the movies.\n[Marks: 3] [ICSE Year: 2024] \n&lt;img src=\&quot; https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiUeQWd2c0N6x5q5dmtj9NQ5sUGhOq3CEIVafMlzvvs2n9w6tNQ0S_9-ILHPN7Wsu74KTC4tD176VcN4Q1OPsHbsPUd0kAdfENiv5zzpLGbJHIrD_y40HnhXBBuWSKd_N_kpsns8lHlnpHfl253cDN9Mp8LOis8PaO3bxcteIwA0KYSvJX6hdfLxw3EHUw/s639/2024_4_ii.png\&quot; height =\&quot;250\&quot; width =\&quot;600\&quot; alt=\&quot;Histogram showing number of plants vs height in cms\&quot;&gt;&quot;,
            &quot;Question 5 (i): The given graph with a histogram represents the number of plants of different heights grown in a school campus. Study the graph carefully and answer the following questions: (a) Make a frequency table... (b) State the modal class. (c) Identify and note down the mode... (d) Find the number of plants whose height range is between 80 cm to 90 cm.\n[Marks: 5] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgFh8O0zX_WBYvQRFvFsCcOvUvRKdfeCF1HSKlU_5RkDol2Yn6VobW6nDY-wuhm5fNWbhyTs6emNn-ggXAU9OgGDijTOYISMKpN5no3y6vlkWH_Aw8f4tIQ1z-XLKvsaw_rcU9t-rJY85fr-mVhcQCeJoDoTJ9BPiRbfKIgqmdXy70sPx_3gfNtOuR22v0/s554/2024_5_i.png\&quot; height =\&quot;600\&quot; width =\&quot;600\&quot; alt=\&quot;Histogram showing number of plants vs height in cms\&quot;&gt;&quot;,
            &quot;Question 8 (ii): The following letters A, D, M, N, O, S, U, Y of the English alphabet are written on separate cards and put in a box. The cards are well shuffled and one card is drawn at random. What is the probability that the card drawn is a letter of the word, (a) MONDAY? (b) which does not appear in MONDAY? (c) which appears both in SUNDAY and MONDAY?\n[Marks: 3] [ICSE Year: 2024]&quot;,
            &quot;Question 9 (iii): A life insurance agent found the following data for distribution of ages of 100 policy holders... On a graph sheet draw an ogive using the given data... Use your graph to find: (a) The median age. (b) Number of policy holders whose age is above 52 years.\n[Marks: 4] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi67rcEJKlujaqj02Oxcq7msjRtuWjxSQzLQREpeRT7cIWv5pv19M1E0AQrun1G4TVMGUrmNAyKGXQIf58rjGBWCR4kVDuxZUR1pEWKVxfus8dh5CR8f44BAJP0GRgONoqWKlL9pkY2oSHGwdbULpaK6aoEQIQzPFaVXwIvXHqhGXgKkppChw26RPlgqD0/s566/2024_9_iii.png\&quot; height =\&quot;500\&quot; width =\&quot;500\&quot; alt=\&quot;Histogram showing number of plants vs height in cms\&quot;&gt;&quot;,
            &quot;Question 1 (iv): A letter is chosen at random from all the letters of the English alphabets. The probability that the letter chosen is a vowel, is:\n(a) 4/26\n(b) 5/26\n(c) 21/26\n(d) 5/24\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 1 (xii): Which of the following cannot be determined graphically for a grouped frequency distribution?\n(a) Median\n(b) Mode\n(c) Quartiles\n(d) Mean\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 6 (i): The following distribution gives the daily wages of 60 workers of a factory.\nDaily income in ₹: 200-300 (6), 300-400 (10), 400-500 (14), 500-600 (16), 600-700 (10), 700-800 (4).\nUse graph paper to answer this question. Take 2 cm = ₹100 along one axis and 2 cm = 2 workers along the other axis. Draw a histogram and hence find the mode of the given distribution.\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 7 (i): A bag contains 25 cards, numbered through 1 to 25. A card is drawn at random. What is the probability that the number on the card drawn is:\n(a) multiple of 5\n(b) a perfect square\n(c) a prime number?\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 8 (i): The following table gives the marks scored by a set of students in an examination. Calculate the mean of the distribution by using the short cut method.\nMarks: 0-10 (3), 10-20 (8), 20-30 (14), 30-40 (9), 40-50 (4), 50-60 (2).\n[Marks: 3] [ICSE Year: 2023]&quot;,
            &quot;Question 10 (ii): Use graph paper to answer this question. During a medical checkup of 60 students in a school, weights were recorded as follows:\nWeight (in kg): 28-30 (2), 30-32 (4), 32-34 (10), 34-36 (13), 36-38 (15), 38-40 (9), 40-42 (5), 42-44 (2).\nTaking 2 cm = 2 kg along one axis and 2 cm = 10 students along the other axis draw an ogive. Use your graph to find the:\n(a) median\n(b) upper Quartile\n(c) number of students whose weight is above 37 kg\n[Marks: 6] [ICSE Year: 2023]&quot;


        ];

        const mensuration = [
            &quot;Question 1 (viii): The total surface area of a solid sphere \\(S_1\\) and a solid hemisphere \\(S_2\\), as shown in the diagram, are equal. The ratio of radii R and r is:\n(a) 1:1\n(b) 2:1\n(c) \\(\\sqrt{3}:2\\)\n(d) \\(2:\\sqrt{3}\\)\n[Marks: 1] [ICSE Year: 2026]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEihGrWDvZdaINXrcV4e2HXKzoY4ffA9F1pD4slB2GHm1R-GxYgxY8RBcDpS03Fi61qdQSs-WOzXm9bmsroLfz3GeexpQHNrS0kHnSrzgcRQe6JcbDH8JZM12fPLEbeKA0ULV3MPQu8ipRH3Ehn327xTthF9U4NP2gteNHbpfcsyPo9Wu3ejAJ635hQ9WD8/s319/2026_1_vii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Solid sphere and solid hemisphere\&quot;&gt;&quot;,
            &quot;Question 3 (ii): An eye drop bottle is prepared consisting of a hemisphere, a cylinder and a conical cap, as shown in the given diagram. Height of the cylindrical and conical parts are each, equal to the diameter (7 cm). Find the:\n(a) minimum height of the cylindrical box required to pack this bottle.\n(b) volume of the liquid medicine (shaded part) in the bottle. Give your answer to the nearest whole number. (Use \\(\\pi = \\frac{22}{7}\\))\n[Marks: 4] [ICSE Year: 2026]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgtA7rT4jOFPae4Os2fSRwRuUHlmkiBKWzCaIwAF0zsvA2KJXAbZQM_04rzpzFPqcp6_ZiT1NUBo0W6JxOgIqCQ6gH5DnV9qxftKkcTeX80nkJz5oRrRfPSBvXmd2gexWJ4NJEFdk_zWncInJQpCx8wAzwid2-WFRSuAVoi2RTvcEty9ZSFNpLCD-KFT7A/s351/2026_3_ii.png\&quot; height=\&quot;300\&quot; width=\&quot;300\&quot; alt=\&quot;Eye drop bottle comprising hemisphere, cylinder, and cone\&quot;&gt;&quot;,
            &quot;Question 9 (iii): A solid wooden toy is prepared by joining a cone, a cylinder and a sphere, as shown in the given diagram. The radius of each of the three solids is 7 cm and heights of each of the cone and the cylinder is 24 cm. Find:\n(a) the total surface area of the given solid.\n(b) the cost of painting the total surface at the rate of ₹0.50 per cm². (Use \\(\\pi = \\frac{22}{7}\\))\n[Marks: 4] [ICSE Year: 2026]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiVTC-JUuGn_UFctGcXw4RztfYwE23IXoPPCxGyn9729HcXEaR-VtVC5k25D3gWWO0lj-aD1E2m-lVCHJyBxypsohdBhRscpYIPAUpiiJY-hfBY0n1HhbIXYpqtUi-WalNS4w0Y3e-9TIWntbie4OfTREKwXrGe_-IO0QrSKf5SUIiNlziWja4NWAp1xdU/s1536/2026_9_iii.png\&quot; height=\&quot;600\&quot; width=\&quot;400\&quot; alt=\&quot;Solid wooden toy comprising a cone, cylinder, and sphere\&quot;&gt;&quot;,
            &quot;Question 1 (iii): The ratio of diameters of two right circular cones is 3:7 and that of their heights is 14:9, then their volumes are in ratio:\n(a) 3:7\n(b) 2:7\n(c) 3:2\n(d) 9:49\n[Marks: 1] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 4 (ii): A right circular cone of radius 20 cm has its volume 8,800 cm³. Find its:\n(a) height\n(b) curved surface area\nGive your answer to the nearest whole number. [Use \\(\\pi = \\frac{22}{7}\\)]\n[Marks: 3] [ICSE Year: 2025 Improvement]&quot;,
            &quot;Question 6 (iii): An ice cream cone has a diameter of 7 cm and its height is 9 cm. It is filled with a scoop of spherical shaped ice cream of radius 3.5 cm. Find: (Give all answers correct to the nearest whole number)\n(a) on melting, is the ice cream sufficient to fill the cone completely without any wastage?\n(b) the volume of ice cream, if any, is in excess or less.\n[Use \\(\\pi = \\frac{22}{7}\\)]\n[Marks: 4] [ICSE Year: 2025 Improvement]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj2-NIEcmCQJ31kbS6-PXyReopIeQbcAzbq4xDugjEBQ7Xp8ku_RbWUGk4XctKJuqT7UlBwE53AhUwQBKE1_wg8peVSSVOIooye75iPdK84IxUc41Q2E5zySlt2Q5zHqzs8wQ6a11zjLUbfie8J-dBaR1Z56CpIA3WvCAR9Yftaiw-Q6EeHlyIvvZesTsM/s248/2025_IE_6_iii.png\&quot; height =\&quot;200\&quot; width =\&quot;200\&quot; alt=\&quot;Illustration of a standard cross-hatched ice cream cone with a large pink spherical scoop on top\&quot;&gt;&quot;,
            &quot;Question 1 (xii): If the volume of two spheres is in the ratio 27:64, then the ratio of their radii is:\n(a) 3:4\n(b) 4:3\n(c) 9:16\n(d) 16:9\n[Marks: 1] [ICSE Year: 2025]&quot;,
            &quot;Question 5 (iii): A solid wooden capsule is shown in Figure 1. The capsule is formed of a cylindrical block and two hemispheres. Find the sum of total surface area of the three parts as shown in Figure 2. Given, the radius of the capsule is 3.5 cm and the length of the cylindrical block is 14 cm. (Use \\(\\pi = \\frac{22}{7}\\))\n[Marks: 4] [ICSE Year: 2025]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEit4aJzd_Idugr111foMg9N2Y5vmX2VCL8c_ez2t5vgn0YF6D_sZqBxhYJo05lw5STeQeHZ1Cv3olqtDjQxsVHTTswu5dC6vEPSApBsY_Jxhmwl5Oo1P6WWCQrb4ujSKx1ODsQcHrSHEgqwTrdhup3OYlfSJrhGj3bPnIFeWnNdWJ76ALm0Eao31hnxUwQ/s596/2025_5_iii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Diagram of a capsule \&quot;&gt;&quot;,
            &quot;Question 9 (i): A hollow sphere of external diameter 10 cm and internal diameter 6 cm is melted and made into a solid right circular cone of height 8 cm. Find the radius of the cone so formed. [Use \\(\\pi = \\frac{22}{7}\\)]\n[Marks: 3] [ICSE Year: 2025]&quot;,
            &quot;Question 1 (xiv): A rectangular sheet of paper of size 11 cm x 7 cm is first rotated about the side 11 cm and then about the side 7 cm to form a cylinder, as shown in the diagram. The ratio of their curved surface areas is:\n(a) \\(1:1\\)\n(b) \\(7:11\\)\n(c) \\(11:7\\)\n(d) \\(\\frac{11\\pi}{7} : \\frac{7\\pi}{11}\\)\n[Marks: 1] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh_px-GlQJIDtqwmZnpBlo0P00h9SSn9QGyX7oNDqnPKgziCyALEQV_8v1kfa5LABVpW9TpUkhRGzu6Ow88xHKNcItYHFUUhZ_sKg7S5uKtd0CLkW0OjBEIugIedU924AsNspczqhWzVLl15o_PpklEpO3OR2jZBpYD__u8UD6epVq_EyPVfwKnV9NOqpc/s438/2024_1_xiv.png\&quot;  height =\&quot;300\&quot; width =\&quot;600\&quot; alt=\&quot;Two cylinders formed by rotating a rectangular sheet of paper\&quot;&gt;&quot;,
            &quot;Question 2 (ii): A solid metallic cylinder is cut into two identical halves along its height (as shown in the diagram). The diameter of the cylinder is 7 cm and the height is 10 cm. Find: (a) The total surface area (both the halves). (b) The total cost of painting the two halves at the rate of ₹30 per cm² (Use \\(\\pi = \\frac{22}{7}\\))\n[Marks: 4] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjr8Fnlnz_rC_yf08QGP2zJ8uUYPhMp4VdXqUZEEyYAUhMnVy705rM5vpdd76sByzx5WsjPo2Z7SD1XgagV2vrpqlzuPpBC6A7vqR3LmDme2ElJzIMThvXAVxX0zfzYZj4KM0bFcH2_INVDaKSo1VNgjxoM7oq8U_RR3gYgAJEJgNrcwzZB_ma0zVfPS-8/s233/2024_2_ii.png\&quot;  height =\&quot;300\&quot; width =\&quot;300\&quot; alt=\&quot;A solid cylinder cut vertically into two identical halves\&quot;&gt;&quot;,
            &quot;Question 8 (iii): Oil is stored in a spherical vessel occupying \\(\\frac{3}{4}\\) of its full capacity. Radius of this spherical vessel is 28 cm. This oil is then poured into a cylindrical vessel with a radius of 21 cm. Find the height of the oil in the cylindrical vessel (correct to the nearest cm). Take \\(\\pi = \\frac{22}{7}\\)\n[Marks: 4] [ICSE Year: 2024]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhzsKZZVrvHJ54VgomQ2rIEiQVJEfBPolad20L7QJk4SvejBhVyvYlWgudj2uAZqNQKNPGxvHtXguQrQPttp5XZz4f4HJOSpj8BGzTu7SAY1Z2cOkXA5jfvQ_jeZTbyJNGoL8tQA1UWDMSt-65N2qyy6_fCTFqg0v1GF7vir1g4ylKtSMvVTeyBEGyLzRo/s323/2024_8_iii.png\&quot; height =\&quot;400\&quot; width =\&quot;400\&quot; alt=\&quot;Oil from a spherical vessel being poured into a cylindrical vessel\&quot;&gt;&quot;,
            &quot;Question 1 (xiii): Volume of a cylinder of height 3 cm is \\(48\\pi\\). Radius of the cylinder is:\n(a) 48 cm\n(b) 16 cm\n(c) 4 cm\n(d) 24 cm\n[Marks: 1] [ICSE Year: 2023]&quot;,
            &quot;Question 7 (iii): A solid is in the shape of a hemisphere of radius 7 cm, surmounted by a cone of height 4 cm. The solid is immersed completely in a cylindrical container filled with water to a certain height. If the radius of the cylinder is 14 cm, find the rise in the water level.\n[Marks: 4] [ICSE Year: 2023]\n&lt;img src=\&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjVbaHczHOV3uolFTXh-emKXFRP5ga-p08IwoaWZqJKWCCOSpI4dSJ84-if8dJ5dn9iCjzdfzy_T6ygRpvZoFCjsEhw1lyMkAm9R8wujEiLR15vBOP0SoohEplOYaq4HuH0zVDsssTn1qTEEUzzpHYUY1AnHsx_FWbVWyEx769jR1cITqGvVvlkhmfl50s/s270/2023_7_iii.png\&quot; height=\&quot;400\&quot; width=\&quot;400\&quot; alt=\&quot;Geometric Diagram\&quot;&gt;&quot;

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</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/6148986116919749223/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/05/icse-class-12-mathematics-ultimate.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/6148986116919749223'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/6148986116919749223'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/05/icse-class-12-mathematics-ultimate.html' title='ICSE Class 10 Mathematics: The Ultimate Topic-Wise PYQ Breakdown (2017–2026)'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-8731342513915506457</id><published>2026-05-16T09:12:54.235-07:00</published><updated>2026-08-08T09:51:45.818-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="Board Paper"/><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ISC"/><category scheme="http://www.blogger.com/atom/ns#" term="XII"/><title type='text'>ISC Class 12 Mathematics: The Ultimate Topic-Wise PYQ Breakdown (2017–2025)</title><content type='html'>&lt;script&gt;
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    &lt;h1&gt;ISC Class 12 Mathematics: The Ultimate Topic-Wise PYQ Breakdown (2017–2025)&lt;/h1&gt;

    &lt;p&gt;Welcome back to Prime Maths! As we accelerate our preparation for the upcoming board exams, one of the most powerful strategies you can employ is analyzing Previous Year Questions (PYQs). It’s not just about solving problems; it’s about understanding the pattern, the weightage, and the exact language the council uses.&lt;/p&gt;

    &lt;p&gt;To make your revision seamless, I have sifted through the recent ISC Class 12 Mathematics examination papers (2017, 2018, 2019, 2020, 2023, 2024, 2025, and the 2025 Improvement Exam) and segregated the essential questions by topic. Grab your notebooks, and let&#39;s dive in!&lt;/p&gt;

    &lt;hr&gt;

    &lt;h3&gt;📌 Algebra &amp;amp; Inverse Trigonometric Functions&lt;/h3&gt;
    &lt;p&gt;This section tests your foundational logic and matrix operations. Pay close attention to the properties of determinants and inverse trigonometric identities.&lt;/p&gt;

    &lt;ul&gt;
          &lt;li&gt;&lt;strong&gt;Matrices:&lt;/strong&gt; If the matrix $\begin{pmatrix}6 &amp; -x^2 \\ 2x-15 &amp; 10\end{pmatrix}$ is symmetric, find the value of $x$. (2017, [3 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Prove that $\frac{1}{2}\cos^{-1}\left(\frac{1-x}{1+x}\right) = \tan^{-1}\sqrt{x}$. (2017, [3 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Complex Numbers:&lt;/strong&gt; If $a+ib = \frac{x+iy}{x-iy}$, prove that $a^2+b^2=1$ and $\frac{b}{a} = \frac{2xy}{x^2-y^2}$. (2017, [3 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Determinants:&lt;/strong&gt; Using properties of determinants, prove that: $\begin{vmatrix}a &amp; b &amp; b+c \\ c &amp; a &amp; c+a \\ b &amp; c &amp; a+b\end{vmatrix} = (a+b+c)(a-c)^2$. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Linear Equations:&lt;/strong&gt; Given that $A = \begin{pmatrix}1 &amp; -1 &amp; 0 \\ 2 &amp; 3 &amp; 4 \\ 0 &amp; 1 &amp; 2\end{pmatrix}$ and $B = \begin{pmatrix}2 &amp; 2 &amp; -4 \\ -4 &amp; 2 &amp; -4 \\ 2 &amp; -1 &amp; 5\end{pmatrix}$, find $AB$. Using this result, solve the system of equations: $x-y=3$, $2x+3y+4z=17$ and $y+2z=7$. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Solve the equation for $x$: $\sin^{-1}x + \sin^{-1}(1-x) = \cos^{-1}x$, where $x \ne 0$. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Boolean Algebra:&lt;/strong&gt; If $A, B$ and $C$ are the elements of Boolean algebra, simplify the expression $(A&#39;+B&#39;)(A+C&#39;) + B&#39;(B+C)$. Draw the simplified circuit. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Complex Numbers:&lt;/strong&gt; Prove that locus of $z$ is a circle and find its centre and radius if $\frac{z-i}{z-1}$ is purely imaginary. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Binary Operations:&lt;/strong&gt; The binary operation $*: \mathbb{R} \times \mathbb{R} \to \mathbb{R}$ is defined as $a*b = 2a+b$. Find $(2*3)*4$. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Matrices:&lt;/strong&gt; If $A = \begin{pmatrix}5 &amp; a \\ b &amp; 0\end{pmatrix}$ and $A$ is a symmetric matrix, show that $a=b$. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Solve: $3\tan^{-1}x + \cot^{-1}x = \pi$. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Determinants:&lt;/strong&gt; Without expanding at any stage, find the value of: $\begin{vmatrix}a &amp; b &amp; c \\ a+2x &amp; b+2y &amp; c+2z \\ x &amp; y &amp; z\end{vmatrix}$. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Functions:&lt;/strong&gt; If the function $f(x) = \sqrt{2x-3}$ is invertible then find its inverse. Hence prove that $(f \circ f^{-1})(x) = x$. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; If $\tan^{-1}a + \tan^{-1}b + \tan^{-1}c = \pi$, prove that $a+b+c = abc$. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Determinants:&lt;/strong&gt; Use properties of determinants to solve for $x$: $\begin{vmatrix}x+a &amp; b &amp; c \\ c &amp; x+b &amp; a \\ a &amp; b &amp; x+c\end{vmatrix} = 0$ and $x \ne 0$. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Linear Equations:&lt;/strong&gt; Using matrices, solve the following system of equations: $2x-3y+5z=11$, $3x+2y-4z=-5$, $x+y-2z=-3$. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Matrices:&lt;/strong&gt; Using elementary transformation, find the inverse of the matrix: $\begin{bmatrix}0 &amp; 1 &amp; 2 \\ 1 &amp; 2 &amp; 3 \\ 3 &amp; 1 &amp; 1\end{bmatrix}$. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Functions:&lt;/strong&gt; If $f: \mathbb{R} \to \mathbb{R}, f(x) = x^3$ and $g: \mathbb{R} \to \mathbb{R}, g(x) = 2x^2+1$, then find $f \circ g(x)$ and $g \circ f(x)$. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Solve: $\sin(2\tan^{-1}x) = 1$. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Determinants:&lt;/strong&gt; Using determinants, find the values of $k$, if the area of triangle with vertices $(-2, 0)$, $(0, 4)$ and $(0, k)$ is $4$ square units. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Matrices:&lt;/strong&gt; Show that $(A+A&#39;)$ is a symmetric matrix, if $A = \begin{pmatrix}2 &amp; 4 \\ 3 &amp; 5\end{pmatrix}$. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Functions:&lt;/strong&gt; If $f: A \to A$ and $A = \mathbb{R} - \{\frac{8}{5}\}$, show that the function $f(x) = \frac{8x+3}{5x-8}$ is one-one onto. Hence, find $f^{-1}$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Solve for $x$: $\tan^{-1}\left(\frac{x-1}{x-2}\right) + \tan^{-1}\left(\frac{x+1}{x+2}\right) = \frac{\pi}{4}$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; If $\sec^{-1}x = \text{cosec}^{-1}y$, show that $\frac{1}{x^2} + \frac{1}{y^2} = 1$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Determinants:&lt;/strong&gt; Using properties of determinants prove that: $\begin{vmatrix}x &amp; x(x^2+1) &amp; x+1 \\ y &amp; y(y^2+1) &amp; y+1 \\ z &amp; z(z^2+1) &amp; z+1\end{vmatrix} = (x-y)(y-z)(z-x)(x+y+z)$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Linear Equations:&lt;/strong&gt; Solve the following system of linear equations using matrix method: $\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 9$, $\frac{2}{x} + \frac{5}{y} + \frac{7}{z} = 52$, $\frac{2}{x} + \frac{1}{y} - \frac{1}{z} = 0$. (2019, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Binary Operations:&lt;/strong&gt; Determine whether the binary operation $*$ on $\mathbb{R}$ defined by $a*b = |a-b|$ is commutative. Also, find the value of $(-3)*2$. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Prove that: $\tan^2(\sec^{-1}2) + \cot^2(\text{cosec}^{-1}3) = 11$. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Determinants:&lt;/strong&gt; Without expanding at any stage, find the value of the determinant: $\Delta = \begin{vmatrix}20 &amp; a &amp; b+c \\ 20 &amp; b &amp; a+c \\ 20 &amp; c &amp; a+b\end{vmatrix}$. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Matrices:&lt;/strong&gt; If $\begin{pmatrix}2 &amp; 3 \\ 5 &amp; 7\end{pmatrix}\begin{pmatrix}1 &amp; -3 \\ -2 &amp; 4\end{pmatrix} = \begin{pmatrix}-4 &amp; 6 \\ -9 &amp; x\end{pmatrix}$, find $x$. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Functions:&lt;/strong&gt; If the function $f: \mathbb{R} \to \mathbb{R}$ be defined as $f(x) = \frac{3x+4}{5x-7}, (x \ne \frac{7}{5})$ and $g: \mathbb{R} \to \mathbb{R}$ be defined as $g(x) = \frac{7x+4}{5x-3}, (x \ne \frac{3}{5})$, show that $(g \circ f)(x) = (f \circ g)(x)$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; If $\cos^{-1}\frac{x}{2} + \cos^{-1}\frac{y}{3} = \theta$, then prove that $9x^2 - 12xy\cos\theta + 4y^2 = 36\sin^2\theta$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Evaluate: $\cos(2\cos^{-1}x + \sin^{-1}x)$ at $x = \frac{1}{5}$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Determinants:&lt;/strong&gt; Using properties of determinants, show that $\begin{vmatrix}x &amp; p &amp; q \\ p &amp; x &amp; q \\ q &amp; q &amp; x\end{vmatrix} = (x-p)(x^2+px-2q^2)$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Linear Equations:&lt;/strong&gt; Solve the following system of linear equations using matrices: $x-2y = 10$, $2x-y-z = 8$, $-2y+z = 7$. (2020, [6 marks])&lt;/li&gt;
&lt;/ul&gt;

        &lt;li&gt;&lt;strong&gt;Relations:&lt;/strong&gt; Determine if the relation $R$ on $\{1, 2, 3\}$ given by $R=\{(1,1), (2,2), (1,2), (3,3), (2,3)\}$ is reflexive, symmetric, or transitive. (2023, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Matrices:&lt;/strong&gt; Find the value of $k$ for which the matrix $\begin{bmatrix}0 &amp; k \\ -6 &amp; 0\end{bmatrix}$ is a skew-symmetric matrix. (2023, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Functions:&lt;/strong&gt; If $f(x)=[4-(x-7)^3]^{1/5}$ is a real invertible function, find $f^{-1}(x)$. (2023, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Determinants:&lt;/strong&gt; Evaluate the determinant without expanding: &lt;br&gt;
            $$\begin{vmatrix} 5 &amp; 5 &amp; 5 \\ a &amp; b &amp; c \\ b+c &amp; c+a &amp; a+b \end{vmatrix}$$ (2023, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Solve for $x$: $5\tan^{-1}x + 3\cot^{-1}x = 2\pi$. (2023, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Linear Equations:&lt;/strong&gt; Use the matrix method to solve the system of equations: $\frac{2}{x} + \frac{3}{y} + \frac{10}{z} = 4$, $\frac{4}{x} - \frac{6}{y} + \frac{5}{z} = 1$, and $\frac{6}{x} + \frac{9}{y} - \frac{20}{z} = 2$. (2023, [6 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Evaluate the value of $\csc(\sin^{-1}(\frac{-1}{2})) - \sec(\cos^{-1}(\frac{-1}{2}))$. (2024, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Matrices:&lt;/strong&gt; Determine if $AB-BA$ is a symmetric or skew-symmetric matrix given that $A$ and $B$ are symmetric matrices of the same order. (2024, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Solve for $x$: $\sin^{-1}(\frac{x}{2}) + \cos^{-1}x = \frac{\pi}{6}$. (2024, [4 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; If $\sin^{-1}x + \sin^{-1}y + \sin^{-1}z = \pi$, show that $x^2-y^2-z^2+2yz\sqrt{1-x^2}=0$. (2024, [4 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Matrices:&lt;/strong&gt; Find the value of $A^{16}$ if $A=\begin{bmatrix}0 &amp; a \\ 0 &amp; 0\end{bmatrix}$. (2025, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Relations:&lt;/strong&gt; Write the smallest equivalence relation from the set $A$ to $A$, where $A=\{1,2,3\}$. (2025, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Inverse Trigonometry:&lt;/strong&gt; Find the value of $\tan^{-1}x - \cot^{-1}x$ if $(\tan^{-1}x)^2 - (\cot^{-1}x)^2 = \frac{5\pi}{8}$. (2025, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Determinants:&lt;/strong&gt; Prove the determinant identity $\begin{vmatrix} 1 &amp; 1 &amp; 1 \\ x &amp; y &amp; z \\ x^3 &amp; y^3 &amp; z^3 \end{vmatrix} = 0$ if $x+y+z=0$. (2025, [4 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Linear Equations:&lt;/strong&gt; Find the value of $\mu$ if the system of equations $2x+3y-8=0$, $7x-5y+3=0$, and $4x-6y+\mu=0$ is consistent. (2025 IE, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Matrices:&lt;/strong&gt; For what value of $a$ is the matrix $A=\begin{bmatrix} 1 &amp; -2 &amp; 3 \\ 1 &amp; 2 &amp; 1 \\ a &amp; 2 &amp; -3 \end{bmatrix}$ not invertible? (2025 IE, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Determinants:&lt;/strong&gt; Using properties of determinants, prove that: &lt;br&gt;
            $$\begin{vmatrix} 1 &amp; 1 &amp; 1 \\ a &amp; b &amp; c \\ a^3 &amp; b^3 &amp; c^3 \end{vmatrix} = (a-b)(b-c)(c-a)(a+b+c)$$ (2025 IE, [4 marks])&lt;/li&gt;
    &lt;/ul&gt;

    &lt;hr&gt;

    &lt;h3&gt;📌 Calculus&lt;/h3&gt;
    &lt;p&gt;Calculus forms the major chunk of the paper. Focus heavily on differential equations and properties of definite integrals.&lt;/p&gt;

    &lt;ul&gt;
       &lt;li&gt;&lt;strong&gt;Limits:&lt;/strong&gt; Using L&#39;Hospital&#39;s Rule, evaluate: $\lim_{x \to \pi/2}(x\tan x - \frac{\pi}{4}\sec x)$. (2017, [3 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \frac{1}{x^2}\sin^2(\frac{1}{x}) dx$. (2017, [3 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Definite Integrals:&lt;/strong&gt; Evaluate: $\int_0^{\pi/4} \log(1+\tan\theta) d\theta$. (2017, [3 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; Solve: $\frac{dy}{dx} = 1-xy+y-x$. (2017, [3 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Mean Value Theorems:&lt;/strong&gt; Verify Lagrange&#39;s mean value theorem for the function $f(x) = x(1-\log x)$ and find the value of &#39;$c$&#39; in the interval $[1, 2]$. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; If $y = \cos(\sin x)$, show that: $\frac{d^2y}{dx^2} + \tan x\frac{dy}{dx} + y\cos^2x = 0$. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Maxima &amp;amp; Minima:&lt;/strong&gt; Show that the surface area of a closed cuboid with square base and given volume is minimum when it is a cube. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \frac{\sin 2x}{(1+\sin x)(2+\sin x)} dx$. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Area Under Curves:&lt;/strong&gt; Draw a rough sketch of the curve $y^2 = 4x$ and find the area of the region enclosed by the curve and the line $y=x$. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; Solve: $(x^2-yx^2)dy + (y^2+xy^2)dx = 0$. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Continuity:&lt;/strong&gt; Find the value of constant &#39;$k$&#39; so that the function $f(x) = \frac{x^2-2x-3}{x+1}$ for $x \ne -1$, and $k$ for $x = -1$ is continuous at $x = -1$. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Approximations:&lt;/strong&gt; Find the approximate change in the volume &#39;$V$&#39; of a cube of side $x$ metres caused by decreasing the side by $1\%$. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \frac{x^3+5x^2+4x+1}{x^2} dx$. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; Find the differential equation of the family of concentric circles $x^2+y^2=a^2$. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differentiability:&lt;/strong&gt; Show that the function $f(x) = x^2$ for $x \le 1$ and $\frac{1}{x}$ for $x &gt; 1$ is continuous at $x = 1$ but not differentiable. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Mean Value Theorems:&lt;/strong&gt; Verify Rolle&#39;s theorem for the function $f(x) = e^{-x}\sin x$ on $[0, \pi]$. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; If $x = \tan(\frac{1}{a}\log y)$, prove that $(1+x^2)\frac{d^2y}{dx^2} + (2x-a)\frac{dy}{dx} = 0$. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \tan^{-1}\sqrt{x} dx$. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Tangents &amp;amp; Normals:&lt;/strong&gt; Find the points on the curve $y=4x^3-3x+5$ at which the equation of the tangent is parallel to the x-axis. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Rate of Change:&lt;/strong&gt; Water is dripping out from a conical funnel of semi-vertical angle $\pi/4$ at the uniform rate of $2 \text{ cm}^2/\text{sec}$ in the surface, through a tiny hole at the vertex of the bottom. When the slant height of the water level is $4\text{ cm}$, find the rate of decrease of the slant height of the water. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; Solve: $\sin x\frac{dy}{dx} - y = \sin x \cdot \tan\frac{x}{2}$. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; The population of a town grows at the rate of $10\%$ per year. Using differential equation, find how long will it take for the population to grow 4 times. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Maxima &amp;amp; Minima:&lt;/strong&gt; A cone is inscribed in a sphere of radius $12\text{ cm}$. If the volume of the cone is maximum, find its height. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \frac{x-1}{\sqrt{x^2-x}} dx$. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Definite Integrals:&lt;/strong&gt; Evaluate: $\int_0^{\pi/2} \frac{\cos^2x}{1+\sin x\cos x} dx$. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Area Under Curves:&lt;/strong&gt; Draw a rough sketch of the curve and find the area of the region bounded by curve $y^2 = 8x$ and the line $x = 2$. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Area Under Curves:&lt;/strong&gt; Sketch the graph of $y = |x+4|$. Using integration, find the area of the region bounded by the curve $y = |x+4|$ and $x = -6$ and $x = 0$. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Continuity:&lt;/strong&gt; $f(x) = \frac{x^2-9}{x-3}$ is not defined at $x = 3$. What value should be assigned to $f(3)$ for continuity of $f(x)$ at $x=3$? (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Increasing &amp;amp; Decreasing Functions:&lt;/strong&gt; Prove that the function $f(x) = x^3-6x^2+12x+5$ is increasing on $\mathbb{R}$. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \frac{\sec^2x}{\text{cosec}^2x} dx$. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Limits:&lt;/strong&gt; Using L&#39;Hospital&#39;s Rule, evaluate: $\lim_{x \to 0}\frac{8^x-4^x}{4x}$. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differentiability:&lt;/strong&gt; Show that the function $f(x) = |x-4|, x \in \mathbb{R}$ is continuous, but not differentiable at $x=4$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Mean Value Theorems:&lt;/strong&gt; Verify the Lagrange&#39;s mean value theorem for the function $f(x) = x+\frac{1}{x}$ in the interval $[1, 3]$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; If $y = e^{\sin^{-1}x}$ and $z = e^{-\cos^{-1}x}$, prove that $\frac{dy}{dz} = e^{\pi/2}$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Rate of Change:&lt;/strong&gt; A $13\text{ m}$ long ladder is leaning against a wall, touching the wall at a certain height from the ground level. The bottom of the ladder is pulled away from the wall, along the ground, at the rate of $2 \text{ m/s}$. How fast is the height on the wall decreasing when the foot of the ladder is $5\text{ m}$ away from the wall? (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \frac{x(1+x^2)}{1+x^4} dx$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Definite Integrals:&lt;/strong&gt; Evaluate: $\int_{-6}^3 |x+3| dx$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; Solve the differential equation: $\frac{dy}{dx} = \frac{x+y+2}{2(x+y)-1}$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Maxima &amp;amp; Minima:&lt;/strong&gt; The volume of a closed rectangular metal box with a square base is $4096 \text{ cm}^3$. The cost of polishing the outer surface of the box is ₹4 per square cm. Find the dimensions of the box for the minimum cost of polishing it. (2019, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Maxima &amp;amp; Minima:&lt;/strong&gt; Find the point on the straight line $2x+3y=6$ which is closest to the origin. (2019, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Definite Integrals:&lt;/strong&gt; Evaluate: $\int_0^{\pi} \frac{x\tan x}{\sec x+\tan x} dx$. (2019, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Area Under Curves:&lt;/strong&gt; Draw a rough sketch and find the area bounded by the curve $x^2 = y$ and $x+y=2$. (2019, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; Find $\frac{dy}{dx}$ if $x^3+y^3=3axy$. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Rate of Change:&lt;/strong&gt; The edge of a variable cube is increasing at the rate of $10 \text{ cm/sec}$. How fast is the volume of the cube increasing when the edge is $5\text{ cm}$ long? (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Definite Integrals:&lt;/strong&gt; Evaluate: $\int_4^5 |x-5| dx$. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; Form a differential equation of the family of the curves $y^2 = 4ax$. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Mean Value Theorems:&lt;/strong&gt; Verify Rolle&#39;s theorem for the function, $f(x) = -1+\cos x$ in the interval $[0, 2\pi]$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; If $y = e^{m\sin^{-1}x}$, prove that $(1-x^2)\frac{d^2y}{dx^2} - x\frac{dy}{dx} = m^2y$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Tangents &amp;amp; Normals:&lt;/strong&gt; The equation of tangent at $(2, 3)$ on the curve $y^2 = px^3+q$ is $y = 4x-7$. Find the values of &#39;$p$&#39; and &#39;$q$&#39;. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Limits:&lt;/strong&gt; Using L&#39;Hospital&#39;s rule, evaluate: $\lim_{x \to 0}\frac{xe^x-\log(1+x)}{x^2}$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \frac{dx}{\sqrt{5x-4x^2}}$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \sin^3x\cos^4x dx$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; Solve the differential equation $(1+x^2)\frac{dy}{dx} = 4x^2-2xy$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Maxima &amp;amp; Minima:&lt;/strong&gt; Show that the radius of a closed right circular cylinder of given surface area and maximum volume is equal to half of its height. (2020, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Maxima &amp;amp; Minima:&lt;/strong&gt; Prove that the area of right-angled triangle of given hypotenuse is maximum when the triangle is isosceles. (2020, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \tan^{-1}\sqrt{\frac{1-x}{1+x}} dx$. (2020, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate: $\int \frac{2x+7}{x^2-x-2} dx$. (2020, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Area Under Curves:&lt;/strong&gt; Draw a rough sketch of the curves $y^2 = x$ and $y^2 = 4-3x$ and find the area enclosed between them. (2020, [6 marks])&lt;/li&gt;

        &lt;li&gt;&lt;strong&gt;Rate of Change:&lt;/strong&gt; An edge of a variable cube is increasing at the rate of 10 cm/sec. How fast will the volume of the cube increase if the edge is 5 cm long? (2023, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; Find the derivative of $\log x$ with respect to $\frac{1}{x}$. (2023, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; Solve the differential equation: $\frac{dy}{dx} = \csc y$. (2023, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate $\int \cos^{-1}(\sin x) dx$. (2023, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; If $y=e^{ax}\cos bx$, prove that $\frac{d^2y}{dx^2} - 2a\frac{dy}{dx} + (a^2+b^2)y = 0$. (2023, [4 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Maxima/Minima:&lt;/strong&gt; Prove that the semi-vertical angle of the right circular cone of given volume and least curved area is $\cot^{-1}\sqrt{2}$. (2023, [6 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; Find the order and the degree of the differential equation $1+(\frac{dy}{dx})^2 = \frac{d^2y}{dx^2}$. (2024, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Tangents &amp;amp; Normals:&lt;/strong&gt; Find a point on the curve $y=(x-2)^2$ at which the tangent is parallel to the line joining the chord through the points (2, 0) and (4, 4). (2024, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate $\int_0^{2\pi} \frac{1}{1+e^{\sin x}} dx$. (2024, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; If $y=3\cos(\log x) + 4\sin(\log x)$, show that $x^2\frac{d^2y}{dx^2} + x\frac{dy}{dx} + y = 0$. (2024, [4 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Maxima/Minima:&lt;/strong&gt; A window is designed in the shape of a rectangle surmounted by an equilateral triangle. If the perimeter is 12 m, find the dimensions that admit maximum sunlight. (2024, [6 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Rate of Change:&lt;/strong&gt; A cylindrical popcorn tub of radius 10 cm is filled with popcorn at a rate of $314\text{ cm}^3\text{/min}$. Find the rate at which the level of popcorn is increasing. (2025, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Tangents &amp;amp; Normals:&lt;/strong&gt; Find the point on the curve $y=2x^2-6x-4$ at which the tangent is parallel to the x-axis. (2025, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; If $x^y = e^{x-y}$, prove that $\frac{dy}{dx} = \frac{\log x}{(1+\log x)^2}$. (2025, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Differential Equations:&lt;/strong&gt; Show that $\tan^{-1}x + \tan^{-1}y = C$ is the general solution of the differential equation $(1+x^2)dy + (1+y^2)dx = 0$. (2025, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; Find the derivative of $\tan^{-1}(\frac{\cos x - \sin x}{\cos x + \sin x})$ with respect to $x$. (2025 IE, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate $\int_{-2}^2 x f(x) dx$ given $f(x)=x+g(x)$ where $g(x)$ is an even function. (2025 IE, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Tangents &amp;amp; Normals:&lt;/strong&gt; Find the equation of the normal to the curve $y=x^2-3x+1$ at the point (3, 1). (2025 IE, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Integration:&lt;/strong&gt; Evaluate $\int_0^{\pi/2} \log(\tan x) dx$. (2025 IE, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Differentiation:&lt;/strong&gt; If $x=\sin t$ and $y=\sin pt$, prove that $(1-x^2)\frac{d^2y}{dx^2} - x\frac{dy}{dx} + p^2y = 0$. (2025 IE, [4 marks])&lt;/li&gt;
    &lt;/ul&gt;

    &lt;hr&gt;

    &lt;h3&gt;📌 Vectors and 3D Geometry&lt;/h3&gt;
    &lt;p&gt;Visualize these problems before you put pen to paper. Drawing a quick rough sketch can often save you from sign errors in 3D geometry.&lt;/p&gt;

    &lt;ul&gt;
      &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; If $\vec{a}, \vec{b}, \vec{c}$ are three mutually perpendicular vectors of equal magnitude, prove that $(\vec{a}+\vec{b}+\vec{c})$ is equally inclined with vectors $\vec{a}, \vec{b}$ and $\vec{c}$. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; Find the value of $\lambda$ for which the four points with position vectors $6\hat{i}-7\hat{j}$, $16\hat{i}-19\hat{j}-4\hat{k}$, $\lambda\hat{j}-6\hat{k}$ and $2\hat{i}-5\hat{j}+10\hat{k}$ are coplanar. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Show that the lines $\frac{x-1}{2}=\frac{y+1}{-3}=\frac{z+10}{8}$ and $\frac{x-4}{1}=\frac{y+3}{-4}=\frac{z+1}{7}$ intersect. Find the coordinates of their point of intersection. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the equation of the plane passing through the point $(1,-2,1)$ and perpendicular to the line joining the points $A(3,2,1)$ and $B(1,4,2)$. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; Find $\lambda$ if the scalar projection of $\vec{a} = \lambda\hat{i}+\hat{j}+4\hat{k}$ on $\vec{b} = 2\hat{i}+6\hat{j}+3\hat{k}$ is $4\text{ units}$. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; The Cartesian equation of a line is: $2x-3 = 3y+1 = 5-6z$. Find the vector equation of a line passing through $(7,-5,0)$ and parallel to the given line. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the equation of the plane through the intersection of the planes $\vec{r} \cdot (\hat{i}+3\hat{j}-\hat{k}) = 9$ and $\vec{r} \cdot (2\hat{i}-\hat{j}+\hat{k}) = 3$ and passing through the origin. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; If $A, B, C$ are three non-collinear points with position vectors $\vec{a}, \vec{b}, \vec{c}$ respectively, then show that the length of the perpendicular from $C$ on $AB$ is $\frac{|(\vec{a}\times\vec{b})+(\vec{b}\times\vec{c})+(\vec{c}\times\vec{a})|}{|\vec{b}-\vec{a}|}$. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; Show that the four points $A, B, C$ and $D$ with position vectors $4\hat{i}+5\hat{j}+\hat{k}, -\hat{j}-\hat{k}, 3\hat{i}+9\hat{j}+4\hat{k}$ and $4(-\hat{i}+\hat{j}+\hat{k})$ respectively, are coplanar. (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the image of a point having position vector: $3\hat{i}-2\hat{j}+\hat{k}$ in the plane $\vec{r} \cdot (3\hat{i}-\hat{j}+4\hat{k}) = 2$. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; If $\vec{a}$ and $\vec{b}$ are perpendicular vectors, $|\vec{a}+\vec{b}| = 13$ and $|\vec{a}| = 5$, find the value of $|\vec{b}|$. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the length of the perpendicular from origin to the plane $\vec{r} \cdot (3\hat{i}-4\hat{j}-12\hat{k}) + 39 = 0$. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the angle between the two lines $2x = 3y = -z$ and $6x = -y = -4z$. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; If $\vec{a} = \hat{i}-2\hat{j}+3\hat{k}, \vec{b} = 2\hat{i}+3\hat{j}-5\hat{k}$, prove that $\vec{a}$ and $\vec{a}\times\vec{b}$ are perpendicular. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; If $\vec{a}$ and $\vec{b}$ are non-collinear vectors, find the value of $x$ such that the vectors $\vec{r} = (x-2)\vec{a}+\vec{b}$ and $\vec{s} = (3+2x)\vec{a}-2\vec{b}$ are collinear. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the equation of the plane passing through the intersection of the planes $2x+2y-3z-7 = 0$ and $2x+5y+3z-9 = 0$ such that the intercepts made by the resulting plane on the x-axis and the z-axis are equal. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the equation of the lines passing through the point $(2, 1, 3)$ and perpendicular to the lines $\frac{x-1}{1} = \frac{y-2}{2} = \frac{z-3}{3}$ and $\frac{x}{-3} = \frac{y}{2} = \frac{z}{5}$. (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; Write a vector of magnitude of $18\text{ units}$ in the direction of the vector $\hat{i}-2\hat{j}-2\hat{k}$. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the angle between the two lines: $\frac{x+1}{2} = \frac{y-2}{5} = \frac{z+3}{4}$ and $\frac{x-1}{5} = \frac{y+2}{2} = \frac{z-1}{-5}$. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the equation of the plane passing through the point $(2,-3, 1)$ and perpendicular to the line joining the points $(4, 5, 0)$ and $(1,-2, 4)$. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; Prove that $\vec{a} \cdot [(\vec{b}+\vec{c})\times(\vec{a}+3\vec{b}+4\vec{c})] = [\vec{a} \vec{b} \vec{c}]$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; Using vectors, find the area of the triangle whose vertices are: $A(3,-1, 2), B(1,-1,-3)$ and $C(4,-3, 1)$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the image of the point $(3,-2, 1)$ in the plane $3x-y+4z=2$. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Determine the equation of the line passing through the point $(-1, 3,-2)$ and perpendicular to the lines: $\frac{x}{1} = \frac{y}{2} = \frac{z}{3}$ and $\frac{x+2}{-3} = \frac{y-1}{2} = \frac{z+1}{5}$. (2020, [4 marks])&lt;/li&gt;
&lt;/ul&gt;

        &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; Find the area of the parallelogram whose diagonals are $\hat{i}-3\hat{j}+\hat{k}$ and $\hat{i}+\hat{j}+\hat{k}$. (2023, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Write the equation of the plane passing through the point (2, 4, 6) and making equal intercepts on the coordinate axes. (2023, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; If $A(1, 2, -3)$ and $B(-1, -2, 1)$ are end points of $\vec{AB}$, find the unit vector in the direction of $\vec{AB}$. (2023, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the equation of the plane passing through the point (1, 1, -1) and perpendicular to the planes $x+2y+3z=7$ and $2x-3y+4z=0$. (2023, [4 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; If $\vec{a}=3\hat{i}-2\hat{j}+\hat{k}$ and $\vec{b}=2\hat{i}-4\hat{j}-3\hat{k}$, find the value of $|\vec{a}-2\vec{b}|$. (2024, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; Find a vector of magnitude 20 units parallel to the vector $2\hat{i}+5\hat{j}+4\hat{k}$. (2024, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; If $\vec{a}\times\vec{b} = \vec{a}\times\vec{c}$ where $\vec{a}, \vec{b}$ and $\vec{c}$ are non-zero vectors, prove that either $\vec{b}=\vec{c}$ or $\vec{a}$ and $(\vec{b}-\vec{c})$ are parallel. (2024, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the angle between the two planes $x+y+2z=9$ and $2x-y+z=15$. (2025, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; The equation of the path traced by a honeybee is $\vec{r}=(\hat{i}+2\hat{j}+3\hat{k})+\lambda(2\hat{i}+3\hat{j}+4\hat{k})$. Find the equation of the parallel path traced by another honeybee passing through the point (2, 4, 5). (2025, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the equation of the plane passing through the points (2, 2, -1), (3, 4, 2) and (7, 0, 6). (2025, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; Consider position vectors $\vec{OA}=2\hat{i}-2\hat{j}+\hat{k}$, $\vec{OB}=\hat{i}+2\hat{j}-2\hat{k}$ and $\vec{OC}=2\hat{i}-\hat{j}+4\hat{k}$. Find the area of the triangle ABC whose sides are $\vec{AB}$ and $\vec{BC}$. (2025, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;3D Geometry:&lt;/strong&gt; Find the shortest distance between the lines $\vec{r}=(\hat{i}+2\hat{j}+3\hat{k})+\lambda(2\hat{i}+3\hat{j}+4\hat{k})$ and $\vec{r}=(2\hat{i}+4\hat{j}+5\hat{k})+\mu(4\hat{i}+6\hat{j}+8\hat{k})$. (2025 IE, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Vectors:&lt;/strong&gt; Consider vectors $\vec{a}=2\hat{i}-3\hat{j}+4\hat{k}$ and $\vec{b}=5\hat{i}+q\hat{j}-\hat{k}$. Calculate $q$ if both vectors are perpendicular to each other. (2025 IE, [1 mark])&lt;/li&gt;
    &lt;/ul&gt;

    &lt;hr&gt;

    &lt;h3&gt;📌 Probability and Linear Programming (LPP)&lt;/h3&gt;
    &lt;p&gt;These questions are incredibly scoring if you read the word problems carefully. Define your variables clearly in LPP, and always double-check your sample space in probability.&lt;/p&gt;

    &lt;ul&gt;
      &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; A problem is given to three students whose chances of solving it are $1/4, 1/5$ and $1/3$ respectively. Find the probability that the problem is solved. (2017, [3 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; In a class of 60 students, 30 opted for Mathematics, 32 opted for Biology and 24 opted for both Mathematics and Biology. If one of these students is selected at random, find the probability that: (i) The student opted for Mathematics or Biology. (ii) The student has opted neither Mathematics nor Biology. (iii) The student has opted Mathematics but not Biology. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; Bag A contains 1 white, 2 blue and 3 red balls. Bag B contains 3 white, 3 blue and 2 red balls. Bag C contains 2 white, 3 blue and 4 red balls. One bag is selected at random and then two balls are drawn from the selected bag. Find the probability that the balls drawn are white and red. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability (Bayes&#39; Theorem):&lt;/strong&gt; A fair die is rolled. If face 1 turns up, a ball is drawn from Bag A. If face 2 or 3 turns up, a ball is drawn from Bag B. If face 4 or 5 or 6 turns up, a ball is drawn from Bag C. Bag A contains 3 red and 2 white balls, Bag B contains 3 red and 4 white balls and Bag C contains 4 red and 5 white balls. The die is rolled, a Bag is picked up and a ball is drawn. If the drawn ball is red, what is the probability that it is drawn from Bag B? (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability Distribution:&lt;/strong&gt; An urn contains 25 balls of which 10 balls are red and the remaining green. A ball is drawn at random from the urn, the colour is noted and the ball is replaced. If 6 balls are drawn in this way, find the probability that: (i) All the balls are red. (ii) Not more than 2 balls are green. (iii) Number of red balls and green balls are equal. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;LPP Formulation:&lt;/strong&gt; A farmer has a supply of chemical fertilizer of type A which contains $10\%$ nitrogen and $6\%$ phosphoric acid and of type B which contains $5\%$ nitrogen and $10\%$ phosphoric acid. After soil test, it is found that at least $7\text{ kg}$ of nitrogen and same quantity of phosphoric acid is required for a good crop. The fertilizer of type A costs $₹5.00\text{ per kg}$ and the type B costs $₹8.00\text{ per kg}$. Using Linear programming, find how many kilograms of each type of the fertilizer should be bought to meet the requirement and for the cost to be minimum. Find the feasible region in the graph. (2017, [5 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; If $A$ and $B$ are events such that $P(A) = 1/2, P(B) = 1/3$ and $P(A \cap B) = 1/4$ then find $P(A/B)$ and $P(B/A)$. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; In a race, the probabilities of $A$ and $B$ winning the race are $1/3$ and $1/6$ respectively. Find the probability of neither of them winning the race. (2018, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; $A$ speaks truth in $60\%$ of the cases, while $B$ in $40\%$ of the cases. In what percent of cases are they likely to contradict each other in stating the same fact? (2018, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability Distribution:&lt;/strong&gt; From a lot of 6 items containing 2 defective items, a sample of 4 items are drawn at random. Let the random variable $X$ denote the number of defective items in the sample. If the sample is drawn without replacement, find: (a) The probability distribution of X (b) Mean of X (c) Variance of X. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;LPP Formulation:&lt;/strong&gt; A manufacturing company makes two types of teaching aids $A$ and $B$ of Mathematics for Class X... The company makes a profit of ₹80 on each piece of type $A$ and ₹120 on each piece of type $B$. How many pieces of type $A$ and type $B$ should be manufactured per week to get a maximum profit? Formulate this as Linear Programming Problem and solve it. Identify the feasible region from the rough sketch. (2018, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; Two balls are drawn from an urn containing 3 white, 5 red and 2 black balls, one by one without replacement. What is the probability that at least one ball is red? (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; If events $A$ and $B$ are independent, such that $P(A) = 3/5, P(B) = 2/3$, find $P(A \cup B)$. (2019, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; Bag A contains 4 white balls and 3 black balls, while Bag B contains 3 white balls and 5 black balls. Two balls are drawn from Bag A and placed in Bag B. Then, what is the probability of drawing a white ball from Bag B? (2019, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability (Bayes&#39; Theorem):&lt;/strong&gt; Given three identical Boxes A, B and C... A person chooses a Box at random and takes out a coin. If the coin drawn is of silver, find the probability that it has been drawn from the Box which has the remaining two coins also of silver. (2019, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability Distribution:&lt;/strong&gt; Determine the binomial distribution where mean is 9 and standard deviation is 3/2. Also, find the probability of obtaining at most one success. (2019, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;LPP Formulation:&lt;/strong&gt; A carpenter has 90, 80 and 50 running feet respectively of teak wood, plywood and rosewood... Formulate the above as a Linear Programming Problem and solve it, indicating clearly the feasible region in the graph. (2019, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; A bag contains 5 white, 7 red and 4 black balls. If four balls are drawn one by one with replacement, what is the probability that none is white? (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; Let $A$ and $B$ be two events such that $P(A) = 1/2, P(B) = p$ and $P(A \cup B) = 3/5$, find &#39;$p$&#39; if $A$ and $B$ are independent events. (2020, [2 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; Three persons A, B and C shoot to hit a target. Their probabilities of hitting the target are 5/6, 4/5 and 3/4 respectively. Find the probability that: (i) Exactly two persons hit the target. (ii) At least one person hits the target. (2020, [4 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Probability Distribution:&lt;/strong&gt; The probability that a bulb produced in a factory will fuse after 150 days of use is 0.05. Find the probability that out of 5 such bulbs: (i) None will fuse... (ii) Not more than one will fuse... (iii) More than one will fuse... (iv) At least one will fuse after 150 days of use. (2020, [6 marks])&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;LPP Formulation:&lt;/strong&gt; A company uses three machines to manufacture two types of shirts, half sleeves and full sleeves. None of the machines can be in operation for more than 40 hours per week... How many of each type of shirts should be made per week to maximize the company&#39;s profit? (2020, [6 marks])&lt;/li&gt;

        &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; A bag contains 19 tickets, numbered from 1 to 19. Two tickets are drawn randomly in succession with replacement. Find the probability that both the tickets drawn are even numbers. (2023, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; The probability of event A occurring is $\frac{1}{3}$ and event B occurring is $\frac{1}{2}$. If A and B are independent, find the probability of neither A nor B occurring. (2023, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Probability Distribution:&lt;/strong&gt; A box contains 30 fruits, out of which 10 are rotten. Two fruits are selected at random one by one without replacement. Find the probability distribution and mean of the number of unspoiled fruits. (2023, [6 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;LPP:&lt;/strong&gt; Solve the Linear Programming Problem graphically: Maximise $z=5x+2y$ subject to $x-2y\le 2$, $3x+2y\le 12$, $-3x+2y\le 3$, $x\ge 0, y\ge 0$. (2023, [6 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; Evaluate $P(A\cup B)$ if $2P(A)=P(B)=\frac{5}{13}$ and $P(A|B)=\frac{2}{5}$. (2024, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;LPP Formulation:&lt;/strong&gt; Aman has ₹1500 to purchase rice and wheat. Each sack of rice and wheat costs ₹180 and ₹120 respectively. He can store a maximum of 10 bags and will earn a profit of ₹11 per bag of rice and ₹9 per bag of wheat. Formulate a Linear Programming Problem to maximise profit. (2024, [4 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; Three critics review a book. Odds in favour of the book are 5:2, 4:3 and 3:4 respectively. Find the probability that all critics are in favour of the book. (2025, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; Pia, Sia and Dia displayed 15, 5 and 10 of their paintings respectively in an art exhibition. A person bought three paintings. Find the probability that he bought one painting from each of them. (2025, [2 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;LPP Formulation:&lt;/strong&gt; Two different types of books have to be stacked. Type 1 weighs 1 kg with a thickness of 6 cm. Type 2 weighs 1.5 kg with a thickness of 4 cm. The 96 cm long shelf holds a maximum of 21 kg. Formulate an LPP to maximize the number of books. (2025, [4 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Probability:&lt;/strong&gt; In a class of 50 students, 25 study English, 10 study History and 10 study both. Find the probability that a randomly selected student studies either English or History. (2025 IE, [1 mark])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;Probability Distribution:&lt;/strong&gt; In a school committee of 30 teachers, 20 never commit errors. Two teachers are selected at random. Let $X$ be the number of selected teachers who never make an error. Find the probability distribution and its mean. (2025 IE, [4 marks])&lt;/li&gt;
        &lt;li&gt;&lt;strong&gt;LPP:&lt;/strong&gt; A cooperative society has 50 hectares to grow crops X and Y (profits ₹10500 and ₹9000 per hectare). A liquid herbicide constraint limits usage to 20 litres and 10 litres per hectare respectively, with a maximum total of 800 litres. Formulate the LPP to maximize profit and solve graphically. (2025 IE, [4 marks])&lt;/li&gt;
    &lt;/ul&gt;

    &lt;hr&gt;

    &lt;div class=&quot;final-advice&quot;&gt;
        &lt;p&gt;&lt;strong&gt;A Final Word of Advice:&lt;/strong&gt;&lt;/p&gt;
        &lt;p&gt;Don&#39;t just read these questions—solve them. Write out the steps completely as if you were sitting in the exam hall. If you get stuck on any of these, let me know in the comments below, and we can tackle the solutions together in an upcoming post.&lt;/p&gt;
        &lt;p&gt;&lt;strong&gt;Keep practicing, and stay focused!&lt;/strong&gt;&lt;/p&gt;
    &lt;/div&gt;
&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/8731342513915506457/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/05/isc-class-12-mathematics-ultimate-topic.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/8731342513915506457'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/8731342513915506457'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/05/isc-class-12-mathematics-ultimate-topic.html' title='ISC Class 12 Mathematics: The Ultimate Topic-Wise PYQ Breakdown (2017–2025)'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-6990983118626713870</id><published>2026-05-16T03:31:12.716-07:00</published><updated>2026-08-08T09:51:51.447-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Quick Revision Guide | CBSE | ICSE | X</title><content type='html'>&lt;p&gt;&lt;/p&gt;&lt;div _ngcontent-ng-c2383366420=&quot;&quot; aria-busy=&quot;false&quot; aria-live=&quot;polite&quot; class=&quot;markdown markdown-main-panel stronger enable-updated-hr-color&quot; dir=&quot;ltr&quot; id=&quot;model-response-message-contentr_1720477ff9168f48&quot; inline-copy-host=&quot;&quot; style=&quot;--animation-duration: 400ms; --fade-animation-function: ease-out; animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; color: #1f1f1f; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans Text&amp;quot;, sans-serif !important; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;h1 data-path-to-node=&quot;2&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans&amp;quot;, sans-serif !important; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Master Your Class 10 Board Exams: The Ultimate Quick Revision Guide by Prime Maths&lt;/h1&gt;&lt;p data-path-to-node=&quot;3&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;As a Class 10 student, the countdown to Board exams can feel incredibly overwhelming. Mathematics, in particular, demands a fine balance between understanding core concepts and executing formulas flawlessly under time constraints. When exam day approaches, scrolling through massive textbooks is the last thing you want to do.&lt;/p&gt;&lt;p data-path-to-node=&quot;4&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;This is exactly where the &lt;b data-index-in-node=&quot;26&quot; data-path-to-node=&quot;4&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;link-block _nghost-ng-c3563746348=&quot;&quot; class=&quot;ng-star-inserted&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;!----&gt;&lt;!----&gt;&lt;a _ngcontent-ng-c3563746348=&quot;&quot; _nghost-ng-c3775120888=&quot;&quot; class=&quot;ng-star-inserted&quot; data-hveid=&quot;0&quot; data-ved=&quot;0CAAQ_4QMahcKEwiU56vAzL2UAxUAAAAAHQAAAAAQSw&quot; decode-data-ved=&quot;1&quot; externallink=&quot;&quot; href=&quot;https://sites.google.com/view/primemaths/math-ix-x/quick-revision-x&quot; jslog=&quot;197247;track:generic_click,impression,attention;BardVeMetadataKey:[[&amp;quot;r_1720477ff9168f48&amp;quot;,&amp;quot;c_09ffd747febd8833&amp;quot;,null,&amp;quot;rc_66843ceda2873c24&amp;quot;,null,null,&amp;quot;en&amp;quot;,null,1,null,null,1,0]]&quot; rel=&quot;noopener&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(11, 87, 208); clear: none; clip: auto; color: #0b57d0; columns: auto; contain: none; container: none; content: normal; cursor: pointer; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(11, 87, 208) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot; target=&quot;_blank&quot;&gt;Prime Maths - Quick Revision - X&lt;/a&gt;&lt;!----&gt;&lt;/link-block&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;/b&gt; portal comes to the rescue. Curated specifically for Grade 10 students looking for high-yield, streamlined study resources, this page acts as a digital hub for your last-minute preparation needs.&lt;/p&gt;&lt;p data-path-to-node=&quot;5&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Let’s dive into what makes this platform a must-bookmark resource for every Class 10 math student.&lt;/p&gt;&lt;hr data-path-to-node=&quot;6&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(128, 128, 128) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot; /&gt;&lt;h3 data-path-to-node=&quot;7&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans&amp;quot;, sans-serif !important; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;What is the &quot;Quick Revision - X&quot; Portal?&lt;/h3&gt;&lt;p data-path-to-node=&quot;8&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;The &lt;b data-index-in-node=&quot;4&quot; data-path-to-node=&quot;8&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Quick Revision - X&lt;/b&gt; page is a centralized repository hosted by Prime Maths, designed to eliminate textbook clutter. Instead of spending hours compiling your own notes or searching the internet for reliable worksheets, this platform provides direct access to targeted study material.&lt;/p&gt;&lt;p data-path-to-node=&quot;9&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;At the heart of the page is the &lt;b data-index-in-node=&quot;32&quot; data-path-to-node=&quot;9&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Embedded Files&lt;/b&gt; section. Here, students can find curated PDFs, formulas sheets, and chapter summaries that condense extensive chapters into bite-sized, high-retention revision guides.&lt;/p&gt;&lt;h3 data-path-to-node=&quot;10&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans&amp;quot;, sans-serif !important; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Key Features Every Class 10 Student Needs&lt;/h3&gt;&lt;p data-path-to-node=&quot;11&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;While the platform is incredibly clean and straightforward to navigate, its utility extends far beyond standard notes. By exploring the page and its surrounding ecosystem, students gain access to a full suite of mathematical tools:&lt;/p&gt;&lt;ol data-path-to-node=&quot;12&quot; start=&quot;1&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 16px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding-inline-start: 32px; padding: 0px 0px 0px 32px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;12,0,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;12,0,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Direct Access to Embedded Revision Files:&lt;/b&gt; Skip the search. The platform serves as a direct pipeline to downloadable material perfect for offline viewing, printing, or active recall sessions right before your test.&lt;/p&gt;&lt;/li&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;12,1,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;12,1,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Seamless Transition to School Algebra:&lt;/b&gt; Need a quick refresher on quadratic equations, progressions, or linear inequations? The sidebar gives you instant access to the &lt;b data-index-in-node=&quot;167&quot; data-path-to-node=&quot;12,1,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;School Algebra&lt;/b&gt; sub-section, ensuring you can bridge your fundamental gaps without leaving the hub.&lt;/p&gt;&lt;/li&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;12,2,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;12,2,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Interactive Homework Verification Tools:&lt;/b&gt; One of the standout features of the broader Prime Maths platform is its dedicated suite of mathematical calculators. When practicing statistics, you don&#39;t have to wonder if your calculations are right. You can jump directly to their specialized tools, including:&lt;/p&gt;&lt;ul data-path-to-node=&quot;12,2,1&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding-inline-start: 32px; padding: 0px 0px 0px 27px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;12,2,1,0,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;12,2,1,0,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Mean Calculator&lt;/b&gt;&lt;/p&gt;&lt;/li&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;12,2,1,1,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;12,2,1,1,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Median, Mode &amp;amp; Percentile Calculator&lt;/b&gt;&lt;/p&gt;&lt;/li&gt;&lt;/ul&gt;&lt;/li&gt;&lt;/ol&gt;&lt;p data-path-to-node=&quot;13&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;These interactive calculators allow you to check your work instantly, which is an invaluable asset when self-studying for boards.&lt;/p&gt;&lt;hr data-path-to-node=&quot;14&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(128, 128, 128) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot; /&gt;&lt;h3 data-path-to-node=&quot;15&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans&amp;quot;, sans-serif !important; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;How to Use This Page for Maximum Results&lt;/h3&gt;&lt;p data-path-to-node=&quot;16&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;To squeeze the most value out of the &lt;b data-index-in-node=&quot;37&quot; data-path-to-node=&quot;16&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Prime Maths Quick Revision&lt;/b&gt; hub, try integrating it into your daily study routine using these three steps:&lt;/p&gt;&lt;ul data-path-to-node=&quot;17&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 16px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding-inline-start: 32px; padding: 0px 0px 0px 32px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;17,0,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;17,0,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Step 1: The Formula Blitz:&lt;/b&gt; Before attempting any sample paper, visit the &lt;i data-index-in-node=&quot;73&quot; data-path-to-node=&quot;17,0,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Embedded Files&lt;/i&gt; section to quickly review the formulas for that day&#39;s topics (such as Trigonometry, Mensuration, or Coordinate Geometry).&lt;/p&gt;&lt;/li&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;17,1,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;17,1,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Step 2: Active Problem Solving:&lt;/b&gt; Utilize their &lt;i data-index-in-node=&quot;46&quot; data-path-to-node=&quot;17,1,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;School Algebra&lt;/i&gt; and revision sheets to solve problems without looking at the solutions first.&lt;/p&gt;&lt;/li&gt;&lt;li style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px 0px 0px 6px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;17,2,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;b data-index-in-node=&quot;0&quot; data-path-to-node=&quot;17,2,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Step 3: Verify and Refine:&lt;/b&gt; Use the integrated &lt;i data-index-in-node=&quot;46&quot; data-path-to-node=&quot;17,2,0&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Mean and Median calculators&lt;/i&gt; to instantly verify complex statistical problems. Finding your error in seconds saves precious time that you can redirect toward weaker topics.&lt;/p&gt;&lt;/li&gt;&lt;/ul&gt;&lt;hr data-path-to-node=&quot;18&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(128, 128, 128) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot; /&gt;&lt;h3 data-path-to-node=&quot;19&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans&amp;quot;, sans-serif !important; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 8px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;The Verdict&lt;/h3&gt;&lt;p data-path-to-node=&quot;20&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Success in Class 10 Mathematics isn&#39;t about studying harder; it’s about studying &lt;i data-index-in-node=&quot;81&quot; data-path-to-node=&quot;20&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;smarter&lt;/i&gt;. By organizing essential revision files and linking them alongside practical calculation tools, Prime Maths provides a frictionless environment for high-scoring students.&lt;/p&gt;&lt;p data-path-to-node=&quot;21&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Don&#39;t wait until the night before the exam. Bookmark the &lt;b data-index-in-node=&quot;57&quot; data-path-to-node=&quot;21&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;link-block _nghost-ng-c3563746348=&quot;&quot; class=&quot;ng-star-inserted&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;!----&gt;&lt;!----&gt;&lt;a _ngcontent-ng-c3563746348=&quot;&quot; _nghost-ng-c3775120888=&quot;&quot; class=&quot;ng-star-inserted&quot; data-hveid=&quot;0&quot; data-ved=&quot;0CAAQ_4QMahcKEwiU56vAzL2UAxUAAAAAHQAAAAAQTA&quot; decode-data-ved=&quot;1&quot; externallink=&quot;&quot; href=&quot;https://sites.google.com/view/primemaths/math-ix-x/quick-revision-x&quot; jslog=&quot;197247;track:generic_click,impression,attention;BardVeMetadataKey:[[&amp;quot;r_1720477ff9168f48&amp;quot;,&amp;quot;c_09ffd747febd8833&amp;quot;,null,&amp;quot;rc_66843ceda2873c24&amp;quot;,null,null,&amp;quot;en&amp;quot;,null,1,null,null,1,0]]&quot; rel=&quot;noopener&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(11, 87, 208); clear: none; clip: auto; color: #0b57d0; columns: auto; contain: none; container: none; content: normal; cursor: pointer; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(11, 87, 208) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot; target=&quot;_blank&quot;&gt;Prime Maths Quick Revision - X&lt;/a&gt;&lt;!----&gt;&lt;/link-block&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;!----&gt;&lt;/b&gt; page today, download your core revision sheets, and take control of your board preparation!&lt;/p&gt;&lt;p data-path-to-node=&quot;22&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 10px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;i data-index-in-node=&quot;0&quot; data-path-to-node=&quot;22&quot; style=&quot;animation: auto ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; display: inline; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15 !important; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; marker: none; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 3px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;Happy Studying!&lt;/i&gt;&lt;/p&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/6990983118626713870/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/05/quick-revision-guide-cbse-icse-x.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/6990983118626713870'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/6990983118626713870'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/05/quick-revision-guide-cbse-icse-x.html' title='Quick Revision Guide | CBSE | ICSE | X'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-657929244419190934</id><published>2026-05-14T18:39:19.933-07:00</published><updated>2026-08-08T09:51:53.993-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="algebra"/><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="IX"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Mastering Algebra for Classes VIII–X</title><content type='html'>&lt;!-- Google Fonts &amp; 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&lt;div class=&quot;pm-blog-wrapper&quot;&gt;
  &lt;div class=&quot;pm-blog-card&quot;&gt;
    &lt;div class=&quot;pm-blog-content&quot;&gt;
      
      &lt;!-- Brand + Badge --&gt;
      &lt;div class=&quot;pm-brand-bar&quot;&gt;
        &lt;div class=&quot;pm-logo&quot;&gt;
          &lt;i class=&quot;fas fa-chalkboard-user&quot;&gt;&lt;/i&gt;
          &lt;span&gt;Prime Maths&lt;/span&gt;
        &lt;/div&gt;
        &lt;div class=&quot;pm-update-badge&quot;&gt;
          &lt;i class=&quot;fas fa-link&quot;&gt;&lt;/i&gt; &lt;span&gt;Direct Problem Bank Access&lt;/span&gt;
        &lt;/div&gt;
      &lt;/div&gt;

      &lt;!-- Main Title --&gt;
      &lt;h1&gt;Mastering Algebra for Classes VIII to X:&lt;br&gt; The Ultimate Practice Guide for CBSE, ICSE &amp; State Boards&lt;/h1&gt;
      
      &lt;div class=&quot;pm-lead&quot;&gt;
        Algebra is often the point in a student&#39;s mathematical journey where numbers give way to letters, and concrete arithmetic transitions into abstract logic. For students in Classes VIII to X, building a rock-solid foundation in algebra is not just about passing the next test—it is about developing the critical problem-solving skills required for higher secondary mathematics and future competitive exams.
      &lt;/div&gt;

      &lt;p&gt;Here at Prime Maths, we understand that mastering math requires more than just reading through theorems; it demands consistent, structured practice. That is why we have compiled a comprehensive, categorized algebraic problem bank designed specifically to bridge the gap between foundational classroom learning and advanced mathematical proficiency.&lt;/p&gt;

      &lt;!-- Utility Section --&gt;
      &lt;h2&gt;&lt;i class=&quot;fas fa-layer-group&quot; style=&quot;font-size: 1.4rem; margin-right: 8px;&quot;&gt;&lt;/i&gt; The Utility of a Structured Problem Bank&lt;/h2&gt;
      &lt;p&gt;When tackling algebra, jumping straight into complex word problems or quadratic equations without mastering the basics can leave students frustrated. Our problem set is meticulously categorized to ensure a smooth, progressive learning curve:&lt;/p&gt;

      &lt;ul class=&quot;pm-category-list&quot;&gt;
        &lt;li&gt;&lt;i class=&quot;fas fa-calculator&quot;&gt;&lt;/i&gt; &lt;span&gt;&lt;span class=&quot;pm-cat-title&quot;&gt;Core Fundamentals:&lt;/span&gt; The journey begins with the absolute basics—evaluating expressions, simplification, addition, subtraction, multiplication, and division of polynomials. This ensures students are comfortable manipulating variables before moving on to tougher concepts.&lt;/span&gt;&lt;/li&gt;
        &lt;li&gt;&lt;i class=&quot;fas fa-shapes&quot;&gt;&lt;/i&gt; &lt;span&gt;&lt;span class=&quot;pm-cat-title&quot;&gt;Identities and Expansions:&lt;/span&gt; Sections dedicated to squares, cubes, and special products train students to recognize patterns instantly, a crucial skill for saving time during exams.&lt;/span&gt;&lt;/li&gt;
        &lt;li&gt;&lt;i class=&quot;fas fa-brain&quot;&gt;&lt;/i&gt; &lt;span&gt;&lt;span class=&quot;pm-cat-title&quot;&gt;Advanced Manipulation:&lt;/span&gt; Moving into intermediate territory, the practice sheet extensively covers factorization, finding the HCF &amp; LCM of algebraic expressions, and simplifying complex algebraic fractions.&lt;/span&gt;&lt;/li&gt;
        &lt;li&gt;&lt;i class=&quot;fas fa-square-root-alt&quot;&gt;&lt;/i&gt; &lt;span&gt;&lt;span class=&quot;pm-cat-title&quot;&gt;Equation Solving:&lt;/span&gt; The true test of algebraic skill lies in finding the unknown. The bank provides rigorous practice in solving rational equations, simultaneous linear equations (including graphical solutions), and quadratic equations.&lt;/span&gt;&lt;/li&gt;
        &lt;li&gt;&lt;i class=&quot;fas fa-puzzle-piece&quot;&gt;&lt;/i&gt; &lt;span&gt;&lt;span class=&quot;pm-cat-title&quot;&gt;Logical Reasoning:&lt;/span&gt; For students aiming for top marks, the proofs and identities section pushes them to think critically, demonstrating &lt;em&gt;why&lt;/em&gt; an algebraic statement is true rather than just calculating an answer.&lt;/span&gt;&lt;/li&gt;
      &lt;/ul&gt;

      &lt;!-- Key Benefits Heading --&gt;
      &lt;h2&gt;&lt;i class=&quot;fas fa-chart-line&quot;&gt;&lt;/i&gt; Key Benefits of Extensive Algebra Practice&lt;/h2&gt;
      
      &lt;div class=&quot;pm-grid-benefits&quot;&gt;
        &lt;div class=&quot;pm-benefit-card&quot;&gt;
          &lt;div class=&quot;pm-benefit-icon&quot;&gt;&lt;i class=&quot;fas fa-school&quot;&gt;&lt;/i&gt;&lt;/div&gt;
          &lt;h4&gt;Tailored for Board Success&lt;/h4&gt;
          &lt;p&gt;The curriculum requirements for classes VIII to X across CBSE, ICSE, and State Boards are rigorous. This problem set aligns perfectly with these syllabi, ensuring that whether a student is facing a standard board exam or a more conceptual competitive paper, they are fully prepared.&lt;/p&gt;
        &lt;/div&gt;
        &lt;div class=&quot;pm-benefit-card&quot;&gt;
          &lt;div class=&quot;pm-benefit-icon&quot;&gt;&lt;i class=&quot;fas fa-trophy&quot;&gt;&lt;/i&gt;&lt;/div&gt;
          &lt;h4&gt;Bridges the Gap to Competitive Math&lt;/h4&gt;
          &lt;p&gt;Standard textbook exercises often stop just as the problems get interesting. This curated list pushes boundaries, taking students from standard textbook applications to the nuanced proofs and rational equations often found in Olympiads or foundation courses.&lt;/p&gt;
        &lt;/div&gt;
        &lt;div class=&quot;pm-benefit-card&quot;&gt;
          &lt;div class=&quot;pm-benefit-icon&quot;&gt;&lt;i class=&quot;fas fa-microchip&quot;&gt;&lt;/i&gt;&lt;/div&gt;
          &lt;h4&gt;Develops Algorithmic Thinking&lt;/h4&gt;
          &lt;p&gt;By working through categorized problems, students naturally develop algorithmic thinking. They learn to break down a daunting complex fraction or a multi-step simultaneous equation into smaller, manageable, and logical steps.&lt;/p&gt;
        &lt;/div&gt;
        &lt;div class=&quot;pm-benefit-card&quot;&gt;
          &lt;div class=&quot;pm-benefit-icon&quot;&gt;&lt;i class=&quot;fas fa-eraser&quot;&gt;&lt;/i&gt;&lt;/div&gt;
          &lt;h4&gt;Eliminates &quot;Silly Mistakes&quot;&lt;/h4&gt;
          &lt;p&gt;Algebraic errors usually stem from a lack of focus on signs (like a dropped negative) or basic arithmetic slips. The repetitive, targeted practice offered in the earlier sections builds muscle memory, drastically reducing calculation errors in high-stakes exams.&lt;/p&gt;
        &lt;/div&gt;
      &lt;/div&gt;

      &lt;!-- Quote --&gt;
      &lt;div style=&quot;background: #eef3fc; padding: 1.3rem 1.8rem; border-radius: 1rem; margin: 1rem 0 1.2rem;&quot;&gt;
        &lt;i class=&quot;fas fa-quote-left&quot; style=&quot;color: #2c7a5e; opacity: 0.7; margin-right: 0.5rem;&quot;&gt;&lt;/i&gt; 
        &lt;span style=&quot;font-weight: 500;&quot;&gt;Mathematics is not a spectator sport. The only way to truly understand algebra is to roll up your sleeves and solve problems.&lt;/span&gt;
      &lt;/div&gt;

      &lt;p&gt;Whether you are struggling to factorize a quadratic equation or looking to perfect your graphical solutions for simultaneous equations, this structured approach will help you build confidence step-by-step.&lt;/p&gt;

      &lt;!-- Direct CTA --&gt;
      &lt;div class=&quot;pm-cta-wrapper&quot;&gt;
        &lt;a href=&quot;https://sites.google.com/view/primemaths/math-ix-x/school-algebra&quot; class=&quot;pm-btn-primary&quot; target=&quot;_blank&quot; rel=&quot;noopener noreferrer&quot;&gt;
          &lt;i class=&quot;fas fa-database&quot;&gt;&lt;/i&gt; Access the Complete Prime Maths Algebra Problem Bank
        &lt;/a&gt;
        &lt;div class=&quot;pm-text-link&quot;&gt;
          &lt;i class=&quot;fas fa-link&quot;&gt;&lt;/i&gt; Direct link: &lt;a href=&quot;https://sites.google.com/view/primemaths/math-ix-x/school-algebra&quot; target=&quot;_blank&quot; rel=&quot;noopener&quot;&gt;https://sites.google.com/view/primemaths/math-ix-x/school-algebra&lt;/a&gt;
        &lt;/div&gt;
        &lt;p style=&quot;margin-top: 1rem; font-size: 0.9rem; color: #333;&quot;&gt;📘 Grab a notebook, pick a category, and start solving. Consistent practice today will pave the way for a perfect score tomorrow!&lt;/p&gt;
      &lt;/div&gt;

      &lt;hr style=&quot;border: none; height: 1px; background: linear-gradient(to right, #cfdfe9, transparent); margin: 2rem 0;&quot;&gt;

      &lt;!-- Author Section --&gt;
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        &lt;div class=&quot;pm-author-details&quot;&gt;
          &lt;h4&gt;Vinod Singh &lt;span style=&quot;font-weight: normal; font-size: 0.9rem;&quot;&gt;(Mathematics Educator, Prime Maths)&lt;/span&gt;&lt;/h4&gt;
          &lt;div class=&quot;pm-credentials&quot;&gt;
            &lt;span&gt;&lt;i class=&quot;fas fa-graduation-cap&quot;&gt;&lt;/i&gt; M.Sc. Pure Mathematics (Calcutta University, First Class)&lt;/span&gt;
            &lt;span&gt;&lt;i class=&quot;fas fa-graduation-cap&quot;&gt;&lt;/i&gt; B.Sc. Mathematics (St. Xavier&#39;s College Kolkata, First Class)&lt;/span&gt;
            &lt;span&gt;&lt;i class=&quot;fas fa-phone-alt&quot;&gt;&lt;/i&gt; Contact: +91-9038126497&lt;/span&gt;
          &lt;/div&gt;
          &lt;p style=&quot;margin-top: 0.4rem; color: #2c6280;&quot;&gt;Passionate about bridging foundational gaps and creating rigorous problem banks that empower students to excel in board exams and competitive mathematics. The Algebra Mastery Series is designed to help students transition from foundational concepts to advanced problem-solving fluency.&lt;/p&gt;
        &lt;/div&gt;
      &lt;/div&gt;

      &lt;!-- Trust Footer --&gt;
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          &lt;span&gt;&lt;i class=&quot;fas fa-globe&quot; style=&quot;color: #2b6e9e;&quot;&gt;&lt;/i&gt; Comprehensive Curriculum&lt;/span&gt;
          &lt;span&gt;&lt;i class=&quot;fas fa-globe&quot; style=&quot;color: #2b6e9e;&quot;&gt;&lt;/i&gt; Aligned with NEP 2020&lt;/span&gt;
          &lt;span&gt;&lt;i class=&quot;fas fa-clock&quot; style=&quot;color: #2b6e9e;&quot;&gt;&lt;/i&gt; 24/7 Access to Problem Bank&lt;/span&gt;
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          &lt;i class=&quot;fas fa-shield-alt&quot; style=&quot;color: #2b6e9e;&quot;&gt;&lt;/i&gt; Verified Resource | Prime Maths
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      &lt;div class=&quot;pm-footnote&quot;&gt;
        &lt;i class=&quot;fas fa-lightbulb&quot;&gt;&lt;/i&gt; Perfect for self-study &amp; revision • Designed for CBSE, ICSE, and major State Boards
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  &lt;/div&gt;
&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/657929244419190934/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/05/mastering-algebra-for-classes-viiix.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/657929244419190934'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/657929244419190934'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/05/mastering-algebra-for-classes-viiix.html' title='Mastering Algebra for Classes VIII–X'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-9041674668177084533</id><published>2026-05-10T03:42:00.000-07:00</published><updated>2026-08-08T09:51:35.153-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="geometry"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Similarity | CBSE | ICSE | Problem Solving</title><content type='html'>&lt;!DOCTYPE html&gt;
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    &lt;title&gt;Geometry – Similarity &amp; Area | ICSE/CBSE Practice&lt;/title&gt;

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&lt;body&gt;

&lt;div class=&quot;blog-container&quot;&gt;

    &lt;!-- ══════════════════════════════════════════ --&gt;
    &lt;!-- BLOG HEADER --&gt;
    &lt;!-- ══════════════════════════════════════════ --&gt;
    &lt;header class=&quot;blog-header&quot;&gt;
        &lt;span class=&quot;badge&quot;&gt;📐 Class X – Geometry&lt;/span&gt;
        &lt;h1&gt;Similarity, Area &amp;amp; Proportions&lt;/h1&gt;
        &lt;p class=&quot;subtitle&quot;&gt;A structured problem set for ICSE / CBSE board practice&lt;/p&gt;
        &lt;div class=&quot;meta&quot;&gt;
            &lt;span&gt;📅 Updated 2026&lt;/span&gt;
            &lt;span&gt;📖 9 Problems&lt;/span&gt;
            &lt;span&gt;⏱️ ~60 min practice&lt;/span&gt;
            &lt;span&gt;🏷️ Triangles • Parallelograms • Trapezium&lt;/span&gt;
        &lt;/div&gt;
    &lt;/header&gt;
    &lt;hr class=&quot;divider&quot;&gt;

    &lt;!-- ══════════════════════════════════════════ --&gt;
    &lt;!-- REFERENCE SECTION --&gt;
    &lt;!-- ══════════════════════════════════════════ --&gt;
    &lt;section class=&quot;reference-section&quot; id=&quot;referenceSection&quot;&gt;
        &lt;h2&gt;📚 Quick Recap – Geometry Essentials&lt;/h2&gt;

        &lt;h3&gt;1. Similarity of Triangles&lt;/h3&gt;
        &lt;p&gt;Two triangles are similar if their corresponding angles are equal and corresponding sides are proportional. The main criteria are:&lt;/p&gt;
        &lt;ul&gt;
            &lt;li&gt;&lt;strong&gt;AA (Angle‑Angle):&lt;/strong&gt; Two angles of one triangle equal to two angles of another.&lt;/li&gt;
            &lt;li&gt;&lt;strong&gt;SAS (Side‑Angle‑Side):&lt;/strong&gt; One angle equal and the sides including it are proportional.&lt;/li&gt;
            &lt;li&gt;&lt;strong&gt;SSS (Side‑Side‑Side):&lt;/strong&gt; All three sides are proportional.&lt;/li&gt;
        &lt;/ul&gt;

        &lt;h3&gt;2. Basic Proportionality Theorem (Thales)&lt;/h3&gt;
        &lt;p&gt;If a line is drawn parallel to one side of a triangle intersecting the other two sides, it divides those sides in the same ratio.&lt;/p&gt;

        &lt;h3&gt;3. Mid‑Point Theorem&lt;/h3&gt;
        &lt;p&gt;The line segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length.&lt;/p&gt;

        &lt;h3&gt;4. Properties of Parallelograms&lt;/h3&gt;
        &lt;ul&gt;
            &lt;li&gt;Opposite sides are equal and parallel.&lt;/li&gt;
            &lt;li&gt;Diagonals bisect each other.&lt;/li&gt;
            &lt;li&gt;Opposite angles are equal.&lt;/li&gt;
        &lt;/ul&gt;

        &lt;h3&gt;5. Area Ratios of Similar Triangles&lt;/h3&gt;
        &lt;p&gt;The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.&lt;/p&gt;

        &lt;div class=&quot;highlight-box&quot;&gt;
            &lt;strong&gt;💡 Pro‑tip:&lt;/strong&gt; Always look for parallel lines – they are the key to setting up similarity and proportional segments.
        &lt;/div&gt;

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            &lt;span class=&quot;arrow&quot;&gt;▶&lt;/span&gt; Show/Hide Reference
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    &lt;/section&gt;

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                &lt;span&gt;📝 Problem&lt;/span&gt;
                &lt;span class=&quot;count&quot; id=&quot;progressCount&quot;&gt;1 / 9&lt;/span&gt;
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                &lt;button class=&quot;btn-nav primary&quot; id=&quot;btnNext&quot; title=&quot;Next Problem (→ arrow key)&quot;&gt;Next &amp;#9654;&lt;/button&gt;
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&lt;!-- ══════════════════════════════════════════ --&gt;
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                    Diagonal \\(DB\\) intersects \\(EF\\) at \\(G\\).&lt;br&gt;
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                num: &quot;6&quot;,
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                    \\(AB = 6\\,\\text{cm},\\; CD = x\\,\\text{cm},\\; EF = 10\\,\\text{cm},\\; BD = 4\\,\\text{cm},\\; DE = y\\,\\text{cm}\\).&lt;br&gt;
                    Calculate the value of \\(y\\).&lt;/p&gt;
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                    Find \\(\\displaystyle \\frac{BD}{AB}\\).&lt;/p&gt;
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&lt;div class=&quot;blog-container&quot;&gt;

    &lt;header class=&quot;blog-header&quot;&gt;
        &lt;span class=&quot;badge&quot;&gt;📐 Grade 8 Mathematics&lt;/span&gt;
        &lt;h1&gt;Rational Numbers&lt;/h1&gt;
        &lt;p class=&quot;subtitle&quot;&gt;A complete interactive practice guide with step-by-step solutions&lt;/p&gt;
        &lt;div class=&quot;meta&quot;&gt;
            &lt;span&gt;📅 Updated 2026&lt;/span&gt;
            &lt;span&gt;📖 17 Problems&lt;/span&gt;
            &lt;span&gt;⏱️ ~45 min read&lt;/span&gt;
            &lt;span&gt;🏷️ Number Systems&lt;/span&gt;
        &lt;/div&gt;
    &lt;/header&gt;
    &lt;hr class=&quot;divider&quot;&gt;

    &lt;section class=&quot;reference-section&quot; id=&quot;referenceSection&quot;&gt;
        &lt;h2&gt;&lt;span class=&quot;icon&quot;&gt;📚&lt;/span&gt; Understanding Rational &amp;amp; Irrational Numbers&lt;/h2&gt;

        &lt;h3&gt;1. What is a Rational Number?&lt;/h3&gt;
        &lt;p&gt;
            A &lt;strong&gt;rational number&lt;/strong&gt; is any number that can be expressed in the form
            \( \frac{p}{q} \), where \( p \) and \( q \) are integers and \( q \neq 0 \).
            In other words, a rational number is a ratio of two integers.
        &lt;/p&gt;
        &lt;ul&gt;
            &lt;li&gt;Examples: \( \frac{1}{2}, -\frac{3}{4}, 5 \;(=\frac{5}{1}), 0 \;(=\frac{0}{1}), 0.75 \;(=\frac{3}{4}) \)&lt;/li&gt;
            &lt;li&gt;The set of all rational numbers is denoted by \( \mathbb{Q} \).&lt;/li&gt;
        &lt;/ul&gt;

        &lt;h3&gt;2. What is an Irrational Number?&lt;/h3&gt;
        &lt;p&gt;
            An &lt;strong&gt;irrational number&lt;/strong&gt; is a number that &lt;em&gt;cannot&lt;/em&gt; be expressed as a ratio of two integers.
            Their decimal expansions are non-terminating and non-repeating.
        &lt;/p&gt;
        &lt;ul&gt;
            &lt;li&gt;Examples: \( \pi, e, \sqrt{2}, \sqrt{3}, \sqrt{5} \)&lt;/li&gt;
            &lt;li&gt;The set of irrational numbers is &lt;em&gt;not&lt;/em&gt; closed under addition or multiplication
                (e.g., \( \sqrt{2} + (-\sqrt{2}) = 0 \), which is rational).&lt;/li&gt;
        &lt;/ul&gt;

        &lt;div class=&quot;highlight-box&quot;&gt;
            &lt;strong&gt;🔑 Key Insight:&lt;/strong&gt; Every rational number has a decimal expansion that either
            &lt;strong&gt;terminates&lt;/strong&gt; (like \( \frac{1}{4} = 0.25 \)) or &lt;strong&gt;repeats&lt;/strong&gt;
            (like \( \frac{1}{3} = 0.\overline{3} \)). Irrational numbers never terminate and never repeat.
        &lt;/div&gt;

        &lt;h3&gt;3. Closure Property&lt;/h3&gt;
        &lt;p&gt;
            A set is said to be &lt;strong&gt;closed&lt;/strong&gt; under an operation if applying that operation
            to any two elements of the set always produces an element that also belongs to the same set.
        &lt;/p&gt;
        &lt;p&gt;&lt;strong&gt;Formally:&lt;/strong&gt; A set \( S \) is closed under operation \( * \) if for all
        \( a, b \in S \), we have \( a * b \in S \).&lt;/p&gt;

        &lt;div class=&quot;ref-grid&quot;&gt;
            &lt;div class=&quot;ref-card&quot;&gt;
                &lt;h4&gt;➕ Addition&lt;/h4&gt;
                &lt;p&gt;\( \mathbb{N}, \mathbb{W}, \mathbb{Z}, \mathbb{Q}, \mathbb{R} \) are all closed under addition.&lt;/p&gt;
            &lt;/div&gt;
            &lt;div class=&quot;ref-card&quot;&gt;
                &lt;h4&gt;✖️ Multiplication&lt;/h4&gt;
                &lt;p&gt;\( \mathbb{N}, \mathbb{W}, \mathbb{Z}, \mathbb{Q}, \mathbb{R} \) are all closed under multiplication.&lt;/p&gt;
            &lt;/div&gt;
            &lt;div class=&quot;ref-card&quot;&gt;
                &lt;h4&gt;➖ Subtraction&lt;/h4&gt;
                &lt;p&gt;\( \mathbb{Z}, \mathbb{Q}, \mathbb{R} \) are closed. \( \mathbb{N} \) and \( \mathbb{W} \) are &lt;strong&gt;not&lt;/strong&gt; closed.&lt;/p&gt;
            &lt;/div&gt;
            &lt;div class=&quot;ref-card&quot;&gt;
                &lt;h4&gt;➗ Division&lt;/h4&gt;
                &lt;p&gt;Only \( \mathbb{Q} \) and \( \mathbb{R} \) are closed (excluding division by zero). \( \mathbb{N}, \mathbb{W}, \mathbb{Z} \) are &lt;strong&gt;not&lt;/strong&gt; closed.&lt;/p&gt;
            &lt;/div&gt;
        &lt;/div&gt;

        &lt;h3&gt;4. Identity Elements&lt;/h3&gt;
        &lt;ul&gt;
            &lt;li&gt;&lt;strong&gt;Additive Identity:&lt;/strong&gt; \( 0 \) — because \( a + 0 = 0 + a = a \) for any \( a \).&lt;/li&gt;
            &lt;li&gt;&lt;strong&gt;Multiplicative Identity:&lt;/strong&gt; \( 1 \) — because \( a \times 1 = 1 \times a = a \) for any \( a \).&lt;/li&gt;
        &lt;/ul&gt;

        &lt;h3&gt;5. Inverse Elements&lt;/h3&gt;
        &lt;ul&gt;
            &lt;li&gt;&lt;strong&gt;Additive Inverse:&lt;/strong&gt; For any \( a \), the number \( -a \) such that \( a + (-a) = 0 \).&lt;/li&gt;
            &lt;li&gt;&lt;strong&gt;Multiplicative Inverse:&lt;/strong&gt; For any \( a \neq 0 \), the number \( \frac{1}{a} \) such that
            \( a \times \frac{1}{a} = 1 \). Zero has &lt;em&gt;no&lt;/em&gt; multiplicative inverse.&lt;/li&gt;
        &lt;/ul&gt;

        &lt;h3&gt;6. Commutative &amp;amp; Associative Properties&lt;/h3&gt;
        &lt;ul&gt;
            &lt;li&gt;&lt;strong&gt;Commutative:&lt;/strong&gt; \( a * b = b * a \) (order doesn&#39;t matter).&lt;/li&gt;
            &lt;li&gt;&lt;strong&gt;Associative:&lt;/strong&gt; \( (a * b) * c = a * (b * c) \) (grouping doesn&#39;t matter).&lt;/li&gt;
            &lt;li&gt;Addition and multiplication are both commutative and associative on \( \mathbb{N}, \mathbb{Z}, \mathbb{Q}, \mathbb{R} \).&lt;/li&gt;
            &lt;li&gt;Subtraction and division are &lt;strong&gt;neither&lt;/strong&gt; commutative nor associative.&lt;/li&gt;
        &lt;/ul&gt;

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    (function() {
        // ── PROBLEMS DATA ──────────────────────
        const problems = [{
            num: 1,
            question: `&lt;p&gt;Using proper arguments, prove that \\(61\\) is a rational number.&lt;/p&gt;`,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;A number is &lt;strong&gt;rational&lt;/strong&gt; if it can be expressed in the form \\( \\frac{p}{q} \\), where \\( p \\) and \\( q \\) are integers and \\( q \\neq 0 \\).&lt;/p&gt;
                &lt;p&gt;We can write \\( 61 = \\frac{61}{1} \\). Here, \\( p = 61 \\) and \\( q = 1 \\) are both integers, and \\( q = 1 \\neq 0 \\).&lt;/p&gt;
                &lt;p&gt;Therefore, \\( 61 \\) is a rational number. &lt;strong&gt;∎&lt;/strong&gt;&lt;/p&gt;
            `
        }, {
            num: 2,
            question: `&lt;p&gt;Is the set of natural numbers (\\( \\mathbb{N} \\)) closed with respect to &lt;strong&gt;division&lt;/strong&gt; and &lt;strong&gt;subtraction&lt;/strong&gt;? Justify your answer.&lt;/p&gt;`,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;Subtraction:&lt;/strong&gt; \\( \\mathbb{N} \\) is &lt;strong&gt;not closed&lt;/strong&gt; under subtraction. Counterexample: \\( 1, 2 \\in \\mathbb{N} \\) but \\( 1 - 2 = -1 \\notin \\mathbb{N} \\).&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Division:&lt;/strong&gt; \\( \\mathbb{N} \\) is &lt;strong&gt;not closed&lt;/strong&gt; under division. Counterexample: \\( 1, 2 \\in \\mathbb{N} \\) but \\( 1 \\div 2 = 0.5 \\notin \\mathbb{N} \\).&lt;/p&gt;
                &lt;p&gt;Thus, \\( \\mathbb{N} \\) is closed under &lt;em&gt;neither&lt;/em&gt; subtraction nor division.&lt;/p&gt;
            `
        }, {
            num: 3,
            question: `&lt;p&gt;Is the set of integers (\\( \\mathbb{Z} \\)) closed with respect to &lt;strong&gt;division&lt;/strong&gt; and &lt;strong&gt;subtraction&lt;/strong&gt;? Justify your answer.&lt;/p&gt;`,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;Subtraction:&lt;/strong&gt; \\( \\mathbb{Z} \\) &lt;strong&gt;is closed&lt;/strong&gt; under subtraction. For any integers \\( a \\) and \\( b \\), \\( a - b \\) is always an integer.&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Division:&lt;/strong&gt; \\( \\mathbb{Z} \\) is &lt;strong&gt;not closed&lt;/strong&gt; under division. Counterexample: \\( 1, 2 \\in \\mathbb{Z} \\) but \\( 1 \\div 2 = 0.5 \\notin \\mathbb{Z} \\).&lt;/p&gt;
            `
        }, {
            num: 4,
            question: `&lt;p&gt;Is the set of integers (\\( \\mathbb{Z} \\)) closed with respect to &lt;strong&gt;addition&lt;/strong&gt; and &lt;strong&gt;multiplication&lt;/strong&gt;? Justify your answer.&lt;/p&gt;`,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;Addition:&lt;/strong&gt; \\( \\mathbb{Z} \\) &lt;strong&gt;is closed&lt;/strong&gt; under addition. The sum of any two integers is always an integer.&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Multiplication:&lt;/strong&gt; \\( \\mathbb{Z} \\) &lt;strong&gt;is closed&lt;/strong&gt; under multiplication. The product of any two integers is always an integer.&lt;/p&gt;
            `
        }, {
            num: 5,
            question: `&lt;p&gt;Use Problem 4 — can you conclude whether the set \\( \\mathbb{W} \\) (whole numbers) and \\( \\mathbb{N} \\) (natural numbers) are closed under addition and multiplication?&lt;/p&gt;`,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;Yes!&lt;/strong&gt; Both \\( \\mathbb{N} \\) and \\( \\mathbb{W} \\) are &lt;strong&gt;closed under addition and multiplication&lt;/strong&gt;.&lt;/p&gt;
                &lt;p&gt;The sum of any two natural (or whole) numbers is always a natural (or whole) number. The product of any two natural (or whole) numbers is always a natural (or whole) number.&lt;/p&gt;
                &lt;p&gt;This mirrors the closure of \\( \\mathbb{Z} \\) under these operations, since \\( \\mathbb{N} \\subset \\mathbb{W} \\subset \\mathbb{Z} \\) and the operations never produce a negative result when starting from non-negative numbers.&lt;/p&gt;
            `
        }, {
            num: 6,
            question: `
                &lt;p&gt;If \\( p = -\\frac{3}{2}, \\; q = \\frac{4}{5} \\) and \\( r = -\\frac{7}{12} \\), then verify that:&lt;/p&gt;
                &lt;p&gt;i. \\( (p \\div q) \\div r \\neq p \\div (q \\div r) \\)&lt;/p&gt;
                &lt;p&gt;ii. \\( (p \\times q) \\times r = p \\times (q \\times r) \\)&lt;/p&gt;
                &lt;p&gt;What can you conclude from Q6 (i)?&lt;/p&gt;
            `,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;Part (i):&lt;/strong&gt;&lt;/p&gt;
                &lt;p&gt;\\( p \\div q = \\left(-\\frac{3}{2}\\right) \\div \\frac{4}{5} = -\\frac{3}{2} \\times \\frac{5}{4} = -\\frac{15}{8} \\)&lt;/p&gt;
                &lt;p&gt;\\( (p \\div q) \\div r = \\left(-\\frac{15}{8}\\right) \\div \\left(-\\frac{7}{12}\\right) = -\\frac{15}{8} \\times \\left(-\\frac{12}{7}\\right) = \\frac{180}{56} = \\frac{45}{14} \\)&lt;/p&gt;
                &lt;p&gt;\\( q \\div r = \\frac{4}{5} \\div \\left(-\\frac{7}{12}\\right) = \\frac{4}{5} \\times \\left(-\\frac{12}{7}\\right) = -\\frac{48}{35} \\)&lt;/p&gt;
                &lt;p&gt;\\( p \\div (q \\div r) = \\left(-\\frac{3}{2}\\right) \\div \\left(-\\frac{48}{35}\\right) = -\\frac{3}{2} \\times \\left(-\\frac{35}{48}\\right) = \\frac{105}{96} = \\frac{35}{32} \\)&lt;/p&gt;
                &lt;p&gt;Since \\( \\frac{45}{14} \\neq \\frac{35}{32} \\), the inequality holds. &lt;strong&gt;Conclusion:&lt;/strong&gt; Division is &lt;strong&gt;not associative&lt;/strong&gt; on \\( \\mathbb{Q} \\).&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Part (ii):&lt;/strong&gt;&lt;/p&gt;
                &lt;p&gt;\\( p \\times q = \\left(-\\frac{3}{2}\\right) \\times \\frac{4}{5} = -\\frac{6}{5} \\); then \\( (p \\times q) \\times r = \\left(-\\frac{6}{5}\\right) \\times \\left(-\\frac{7}{12}\\right) = \\frac{42}{60} = \\frac{7}{10} \\)&lt;/p&gt;
                &lt;p&gt;\\( q \\times r = \\frac{4}{5} \\times \\left(-\\frac{7}{12}\\right) = -\\frac{28}{60} = -\\frac{7}{15} \\); then \\( p \\times (q \\times r) = \\left(-\\frac{3}{2}\\right) \\times \\left(-\\frac{7}{15}\\right) = \\frac{21}{30} = \\frac{7}{10} \\)&lt;/p&gt;
                &lt;p&gt;Both sides equal \\( \\frac{7}{10} \\). Multiplication &lt;strong&gt;is associative&lt;/strong&gt; on \\( \\mathbb{Q} \\). ✅&lt;/p&gt;
            `
        }, {
            num: 7,
            question: `&lt;p&gt;Is the set of rational numbers (\\( \\mathbb{Q} \\)) closed with respect to &lt;strong&gt;addition, subtraction, multiplication, and division&lt;/strong&gt;? Justify your answer.&lt;/p&gt;`,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;\\( \\mathbb{Q} \\) is &lt;strong&gt;closed&lt;/strong&gt; under all four operations (with one exception for division).&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Addition:&lt;/strong&gt; \\( \\frac{a}{b} + \\frac{c}{d} = \\frac{ad+bc}{bd} \\in \\mathbb{Q} \\) ✅&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Subtraction:&lt;/strong&gt; \\( \\frac{a}{b} - \\frac{c}{d} = \\frac{ad-bc}{bd} \\in \\mathbb{Q} \\) ✅&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Multiplication:&lt;/strong&gt; \\( \\frac{a}{b} \\times \\frac{c}{d} = \\frac{ac}{bd} \\in \\mathbb{Q} \\) ✅&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Division:&lt;/strong&gt; \\( \\frac{a}{b} \\div \\frac{c}{d} = \\frac{ad}{bc} \\in \\mathbb{Q} \\), &lt;strong&gt;provided&lt;/strong&gt; \\( c \\neq 0 \\) (division by zero is undefined). So \\( \\mathbb{Q} \\) is closed under division &lt;em&gt;except&lt;/em&gt; by zero. ✅&lt;/p&gt;
            `
        }, {
            num: 8,
            question: `&lt;p&gt;Is \\( 0 \\) a rational number? Explain your answer.&lt;/p&gt;`,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;Yes!&lt;/strong&gt; \\( 0 \\) is a rational number because it can be expressed as \\( \\frac{0}{1} \\), where both \\( 0 \\) and \\( 1 \\) are integers and the denominator \\( 1 \\neq 0 \\).&lt;/p&gt;
                &lt;p&gt;In fact, \\( 0 = \\frac{0}{q} \\) for any non-zero integer \\( q \\).&lt;/p&gt;
            `
        }, {
            num: 9,
            question: `
                &lt;p&gt;What is the &lt;strong&gt;identity element&lt;/strong&gt; for the set of rational numbers (\\( \\mathbb{Q} \\)) with respect to:&lt;/p&gt;
                &lt;p&gt;i. Addition operation&lt;/p&gt;
                &lt;p&gt;ii. Multiplication operation&lt;/p&gt;
            `,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;i. Additive Identity:&lt;/strong&gt; \\( 0 \\) — because for any rational \\( a \\), \\( a + 0 = 0 + a = a \\).&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;ii. Multiplicative Identity:&lt;/strong&gt; \\( 1 \\) — because for any rational \\( a \\), \\( a \\times 1 = 1 \\times a = a \\).&lt;/p&gt;
            `
        }, {
            num: 10,
            question: `
                &lt;p&gt;&lt;strong&gt;a.&lt;/strong&gt; What is the additive inverse of: i. \\(-5\\) ii. \\(204\\) iii. \\(\\frac{11}{33}\\)&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;b.&lt;/strong&gt; In the same context, explain the concept of &lt;strong&gt;multiplicative inverse&lt;/strong&gt; of a rational number. What is the multiplicative inverse of: i. \\(-5\\) ii. \\(204\\) iii. \\(\\frac{11}{33}\\)&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;c.&lt;/strong&gt; Does the multiplicative inverse exist for &lt;em&gt;all&lt;/em&gt; rational numbers?&lt;/p&gt;
            `,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;a. Additive Inverse&lt;/strong&gt; (the number that when added gives \\(0\\)):&lt;/p&gt;
                &lt;p&gt;i. Additive inverse of \\(-5\\) is \\(5\\) because \\(-5 + 5 = 0\\).&lt;/p&gt;
                &lt;p&gt;ii. Additive inverse of \\(204\\) is \\(-204\\) because \\(204 + (-204) = 0\\).&lt;/p&gt;
                &lt;p&gt;iii. Additive inverse of \\(\\frac{11}{33}\\) is \\(-\\frac{11}{33}\\) (or \\(-\\frac{1}{3}\\)).&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;b. Multiplicative Inverse&lt;/strong&gt; (the number that when multiplied gives \\(1\\)): For a rational \\( a \\neq 0 \\), its multiplicative inverse is \\( \\frac{1}{a} \\).&lt;/p&gt;
                &lt;p&gt;i. Multiplicative inverse of \\(-5\\) is \\(-\\frac{1}{5}\\).&lt;/p&gt;
                &lt;p&gt;ii. Multiplicative inverse of \\(204\\) is \\(\\frac{1}{204}\\).&lt;/p&gt;
                &lt;p&gt;iii. Multiplicative inverse of \\(\\frac{11}{33}\\) is \\(\\frac{33}{11} = 3\\).&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;c.&lt;/strong&gt; &lt;strong&gt;No.&lt;/strong&gt; The multiplicative inverse does &lt;em&gt;not&lt;/em&gt; exist for \\(0\\), because there is no number that when multiplied by \\(0\\) gives \\(1\\). Division by zero is undefined.&lt;/p&gt;
            `
        }, {
            num: 11,
            question: `&lt;p&gt;If \\(a\\) and \\(b\\) are any two rational numbers, then prove that \\( \\frac{a + b}{2} \\) is also a rational number.&lt;/p&gt;`,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;Let \\( a = \\frac{p}{q} \\) and \\( b = \\frac{r}{s} \\), where \\( p, q, r, s \\in \\mathbb{Z} \\), \\( q \\neq 0 \\), \\( s \\neq 0 \\).&lt;/p&gt;
                &lt;p&gt;Then \\( a + b = \\frac{p}{q} + \\frac{r}{s} = \\frac{ps + qr}{qs} \\).&lt;/p&gt;
                &lt;p&gt;Now, \\( \\frac{a+b}{2} = \\frac{ps + qr}{qs} \\div 2 = \\frac{ps + qr}{qs} \\times \\frac{1}{2} = \\frac{ps + qr}{2qs} \\).&lt;/p&gt;
                &lt;p&gt;The numerator \\( ps + qr \\) is an integer (sum of products of integers). The denominator \\( 2qs \\) is a non-zero integer (product of non-zero integers).&lt;/p&gt;
                &lt;p&gt;Therefore, \\( \\frac{a+b}{2} \\) is expressed as a ratio of two integers with a non-zero denominator, so it is a rational number. &lt;strong&gt;∎&lt;/strong&gt;&lt;/p&gt;
                &lt;p&gt;&lt;em&gt;This shows that the average (arithmetic mean) of any two rational numbers is always rational.&lt;/em&gt;&lt;/p&gt;
            `
        }, {
            num: 12,
            question: `
                &lt;p&gt;Which of the following operations is &lt;strong&gt;associative&lt;/strong&gt; and &lt;strong&gt;commutative&lt;/strong&gt; on the set of Natural numbers (\\( \\mathbb{N} \\)), Integers (\\( \\mathbb{Z} \\)), and Rational numbers (\\( \\mathbb{Q} \\))?&lt;/p&gt;
                &lt;p&gt;i. Addition &amp;nbsp; ii. Multiplication &amp;nbsp; iii. Subtraction &amp;nbsp; iv. Division&lt;/p&gt;
            `,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;table class=&quot;closure-table&quot;&gt;
                    &lt;thead&gt;
                        &lt;tr&gt;&lt;th&gt;Operation&lt;/th&gt;&lt;th&gt;Property&lt;/th&gt;&lt;th&gt;\\( \\mathbb{N} \\)&lt;/th&gt;&lt;th&gt;\\( \\mathbb{Z} \\)&lt;/th&gt;&lt;th&gt;\\( \\mathbb{Q} \\)&lt;/th&gt;&lt;/tr&gt;
                    &lt;/thead&gt;
                    &lt;tbody&gt;
                        &lt;tr&gt;&lt;td rowspan=&quot;2&quot;&gt;&lt;strong&gt;Addition (+)&lt;/strong&gt;&lt;/td&gt;&lt;td&gt;Commutative&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;/tr&gt;
                        &lt;tr&gt;&lt;td&gt;Associative&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;/tr&gt;
                        &lt;tr&gt;&lt;td rowspan=&quot;2&quot;&gt;&lt;strong&gt;Multiplication (×)&lt;/strong&gt;&lt;/td&gt;&lt;td&gt;Commutative&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;/tr&gt;
                        &lt;tr&gt;&lt;td&gt;Associative&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;td class=&quot;yes&quot;&gt;✅ Yes&lt;/td&gt;&lt;/tr&gt;
                        &lt;tr&gt;&lt;td rowspan=&quot;2&quot;&gt;&lt;strong&gt;Subtraction (−)&lt;/strong&gt;&lt;/td&gt;&lt;td&gt;Commutative&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;/tr&gt;
                        &lt;tr&gt;&lt;td&gt;Associative&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;/tr&gt;
                        &lt;tr&gt;&lt;td rowspan=&quot;2&quot;&gt;&lt;strong&gt;Division (÷)&lt;/strong&gt;&lt;/td&gt;&lt;td&gt;Commutative&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;/tr&gt;
                        &lt;tr&gt;&lt;td&gt;Associative&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;td class=&quot;no&quot;&gt;❌ No&lt;/td&gt;&lt;/tr&gt;
                    &lt;/tbody&gt;
                &lt;/table&gt;
                &lt;p&gt;&lt;strong&gt;Summary:&lt;/strong&gt; Only &lt;strong&gt;addition and multiplication&lt;/strong&gt; are both commutative and associative across all three sets. Subtraction and division fail both properties.&lt;/p&gt;
            `
        }, {
            num: 13,
            question: `&lt;p&gt;Is the set of real numbers (\\( \\mathbb{R} \\)) closed under &lt;strong&gt;addition, multiplication, subtraction, and division&lt;/strong&gt;?&lt;/p&gt;`,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;Yes!&lt;/strong&gt; \\( \\mathbb{R} \\) is closed under all four operations (with the usual exception for division by zero).&lt;/p&gt;
                &lt;p&gt;The sum, product, or difference of any two real numbers is always a real number. The quotient of any two real numbers (where the divisor is non-zero) is also a real number.&lt;/p&gt;
                &lt;p&gt;\\( \\mathbb{R} \\) is the most complete number system with respect to these basic operations.&lt;/p&gt;
            `
        }, {
            num: 14,
            question: `
                &lt;p&gt;Consider a special operation \\( (*) \\) on the set of Natural numbers (\\( \\mathbb{N} \\)) defined as follows:&lt;/p&gt;
                &lt;p&gt;For any two natural numbers \\( m \\) and \\( n \\), \\( m * n = m^n \\).&lt;/p&gt;
                &lt;p&gt;Is \\( * \\) closed under \\( \\mathbb{N} \\)? Is \\( * \\) commutative? Is \\( * \\) associative? Justify your answer in each case.&lt;/p&gt;
            `,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;Closure:&lt;/strong&gt; &lt;strong&gt;Yes.&lt;/strong&gt; For any \\( m, n \\in \\mathbb{N} \\), \\( m^n \\) is always a natural number. Exponentiation of natural numbers yields a natural number. ✅&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Commutative:&lt;/strong&gt; &lt;strong&gt;No.&lt;/strong&gt; \\( 2 * 3 = 2^3 = 8 \\), but \\( 3 * 2 = 3^2 = 9 \\). Since \\( 8 \\neq 9 \\), the operation is not commutative. In general, \\( m^n \\neq n^m \\). ❌&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Associative:&lt;/strong&gt; &lt;strong&gt;No.&lt;/strong&gt; \\( (2 * 3) * 2 = (2^3) * 2 = 8 * 2 = 8^2 = 64 \\), but \\( 2 * (3 * 2) = 2 * (3^2) = 2 * 9 = 2^9 = 512 \\). Since \\( 64 \\neq 512 \\), the operation is not associative. In general, \\( (m^n)^p \\neq m^{(n^p)} \\). ❌&lt;/p&gt;
            `
        }, {
            num: 15,
            question: `
                &lt;p&gt;Consider a special operation \\( (\\Phi) \\) on the set of Rational numbers (\\( \\mathbb{Q} \\)) defined as follows:&lt;/p&gt;
                &lt;p&gt;For any two rational numbers \\( m \\) and \\( n \\), \\( m \\Phi n = \\frac{mn}{2} \\).&lt;/p&gt;
                &lt;p&gt;Is \\( \\Phi \\) closed under \\( \\mathbb{Q} \\)? Is \\( \\Phi \\) commutative? Is \\( \\Phi \\) associative? Justify your answer in each case.&lt;/p&gt;
                &lt;p&gt;Can you find the &lt;strong&gt;identity element&lt;/strong&gt; for the operation \\( \\Phi \\) on the set \\( \\mathbb{Q} \\)?&lt;/p&gt;
            `,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;Closure:&lt;/strong&gt; &lt;strong&gt;Yes.&lt;/strong&gt; For any \\( m, n \\in \\mathbb{Q} \\), \\( mn \\) is rational (product), and \\( \\frac{mn}{2} \\) is rational (division by 2). So \\( m \\Phi n \\in \\mathbb{Q} \\). ✅&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Commutative:&lt;/strong&gt; &lt;strong&gt;Yes.&lt;/strong&gt; \\( m \\Phi n = \\frac{mn}{2} = \\frac{nm}{2} = n \\Phi m \\). The operation is commutative because multiplication is commutative. ✅&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Associative:&lt;/strong&gt; &lt;strong&gt;Yes.&lt;/strong&gt; \\( (m \\Phi n) \\Phi p = \\frac{mn}{2} \\Phi p = \\frac{\\frac{mn}{2} \\cdot p}{2} = \\frac{mnp}{4} \\). And \\( m \\Phi (n \\Phi p) = m \\Phi \\frac{np}{2} = \\frac{m \\cdot \\frac{np}{2}}{2} = \\frac{mnp}{4} \\). Both equal, so associative. ✅&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;Identity Element:&lt;/strong&gt; We need \\( e \\) such that \\( m \\Phi e = m \\) for all \\( m \\). That is, \\( \\frac{m \\cdot e}{2} = m \\), which gives \\( e = 2 \\) (assuming \\( m \\neq 0 \\)). Verify: \\( m \\Phi 2 = \\frac{m \\cdot 2}{2} = m \\). So the identity element is \\( 2 \\). 🎯&lt;/p&gt;
            `
        }, {
            num: 16,
            question: `
                &lt;p&gt;See the image given below:&lt;/p&gt;
                &lt;p&gt;&lt;em&gt;[Image reference: A diagram depicting number set relationships — typically showing nested sets: \\( \\mathbb{N} \\subset \\mathbb{W} \\subset \\mathbb{Z} \\subset \\mathbb{Q} \\subset \\mathbb{R} \\), often with irrational numbers shown alongside \\( \\mathbb{Q} \\) inside \\( \\mathbb{R} \\).]&lt;/em&gt;&lt;/p&gt;
                &lt;p&gt;What information has been depicted above? Symbols have their usual meanings.&lt;/p&gt;
            `,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;The image likely depicts the &lt;strong&gt;hierarchy of number sets&lt;/strong&gt;:&lt;/p&gt;
                &lt;p&gt;\\( \\mathbb{N} \\subset \\mathbb{W} \\subset \\mathbb{Z} \\subset \\mathbb{Q} \\subset \\mathbb{R} \\)&lt;/p&gt;
                &lt;p&gt;Where:&lt;/p&gt;
                &lt;ul&gt;
                    &lt;li&gt;\\( \\mathbb{N} \\) = Natural numbers: \\( \\{1, 2, 3, \\ldots\\} \\)&lt;/li&gt;
                    &lt;li&gt;\\( \\mathbb{W} \\) = Whole numbers: \\( \\{0, 1, 2, 3, \\ldots\\} \\)&lt;/li&gt;
                    &lt;li&gt;\\( \\mathbb{Z} \\) = Integers: \\( \\{\\ldots, -2, -1, 0, 1, 2, \\ldots\\} \\)&lt;/li&gt;
                    &lt;li&gt;\\( \\mathbb{Q} \\) = Rational numbers: all numbers of the form \\( \\frac{p}{q} \\), \\( q \\neq 0 \\)&lt;/li&gt;
                    &lt;li&gt;\\( \\mathbb{R} \\) = Real numbers: all rational + irrational numbers&lt;/li&gt;
                &lt;/ul&gt;
                &lt;p&gt;This is the classic &quot;nested&quot; or &quot;Russian doll&quot; representation showing how each set is a proper subset of the next.&lt;/p&gt;
            `
        }, {
            num: 17,
            question: `
                &lt;p&gt;Write the decimal form of the given numbers:&lt;/p&gt;
                &lt;p&gt;i. \\( \\frac{1}{4} \\) &amp;nbsp;&amp;nbsp; ii. \\( \\frac{1}{3} \\) &amp;nbsp;&amp;nbsp; iii. \\( \\frac{3227}{555} \\)&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;i.&lt;/strong&gt; What is common about all the given three numbers?&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;ii.&lt;/strong&gt; What is common about the decimal representation of \\( \\frac{1}{3} \\) and \\( \\frac{3227}{555} \\)?&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;iii.&lt;/strong&gt; Write a difference between the decimal representation of \\( \\frac{1}{4} \\) and the numbers \\( \\frac{1}{3} \\) and \\( \\frac{3227}{555} \\).&lt;/p&gt;
                &lt;p&gt;&lt;em&gt;Note: decimal representation of \\( \\frac{2}{5} \\) is 0.4&lt;/em&gt;&lt;/p&gt;
            `,
            answer: `
                &lt;span class=&quot;answer-label&quot;&gt;✅ Answer&lt;/span&gt;
                &lt;p&gt;&lt;strong&gt;Decimal forms:&lt;/strong&gt;&lt;/p&gt;
                &lt;p&gt;i. \\( \\frac{1}{4} = 0.25 \\) — &lt;em&gt;terminating decimal&lt;/em&gt;&lt;/p&gt;
                &lt;p&gt;ii. \\( \\frac{1}{3} = 0.3333\\ldots = 0.\\overline{3} \\) — &lt;em&gt;repeating (non-terminating) decimal&lt;/em&gt;&lt;/p&gt;
                &lt;p&gt;iii. \\( \\frac{3227}{555} = 5.8144144144\\ldots = 5.8\\overline{144} \\) — &lt;em&gt;repeating (non-terminating) decimal&lt;/em&gt; (period = 144 repeating after the tenths digit)&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;i. Commonality:&lt;/strong&gt; All three numbers are &lt;strong&gt;rational numbers&lt;/strong&gt;. Each can be expressed as a ratio of two integers.&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;ii. Commonality between \\( \\frac{1}{3} \\) and \\( \\frac{3227}{555} \\):&lt;/strong&gt; Both have &lt;strong&gt;non-terminating, repeating (recurring) decimal expansions&lt;/strong&gt;. Their decimal representations go on forever with a repeating pattern.&lt;/p&gt;
                &lt;p&gt;&lt;strong&gt;iii. Difference:&lt;/strong&gt; \\( \\frac{1}{4} = 0.25 \\) has a &lt;strong&gt;terminating decimal&lt;/strong&gt; (it ends after 2 decimal places), while \\( \\frac{1}{3} \\) and \\( \\frac{3227}{555} \\) have &lt;strong&gt;non-terminating repeating decimals&lt;/strong&gt; that continue infinitely. This happens because the denominator of \\( \\frac{1}{4} \\) (which is 4 = 2²) has only prime factors 2 and 5, while the denominators of the others (3 and 555 = 3×5×37) contain prime factors other than 2 and 5.&lt;/p&gt;
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&lt;div class=&quot;blogger-post-wrapper&quot;&gt;

  &lt;p&gt;The wait is almost over for lakhs of ICSE Class 10 students! As we step into the final days of April, anticipation is running high. The Council for the Indian School Certificate Examinations (CISCE) is expected to announce the much-awaited ICSE results anytime between &lt;strong&gt;April 28 and May 7, 2027&lt;/strong&gt;.&lt;/p&gt;

  &lt;p&gt;It is completely normal to feel a mix of excitement and anxiety right now. However, staying informed and prepared is the best way to handle the pre-result jitters. Here is a breakdown of everything you need to know about the upcoming results, including historical trends and exactly where to find your scorecards.&lt;/p&gt;

  &lt;h2&gt;📅 A Look at Previous Years&#39; Trends&lt;/h2&gt;
  &lt;p&gt;While CISCE has not yet officially confirmed the exact date and time for 2026, looking at the patterns from recent years gives us a highly reliable estimate. The current expected window of late April to early May aligns perfectly with the council&#39;s recent track record:&lt;/p&gt;
  
  &lt;ul class=&quot;trend-list&quot;&gt;
    &lt;li&gt;&lt;strong&gt;2026:&lt;/strong&gt; Results were announced on April 30.&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;2025:&lt;/strong&gt; Results were announced on April 30.&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;2024:&lt;/strong&gt; Results were announced on May 6.&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;2023:&lt;/strong&gt; Results were announced on May 14.&lt;/li&gt;
  &lt;/ul&gt;
  &lt;p&gt;Based on this timeline, an official declaration in the coming days is right on schedule.&lt;/p&gt;

  &lt;h2&gt;💻 Where and How to Check Your Results&lt;/h2&gt;
  &lt;p&gt;When the results go live, the official websites often experience a massive surge in traffic. It is best to have your admit card ready beforehand and know exactly where to navigate.&lt;/p&gt;

  &lt;div class=&quot;highlight-box&quot;&gt;
    &lt;strong&gt;Official CISCE Portals:&lt;/strong&gt;&lt;br&gt;&lt;br&gt;
    &lt;a href=&quot;https://www.cisce.org&quot; target=&quot;_blank&quot; class=&quot;official-link-btn&quot;&gt;cisce.org&lt;/a&gt;
    &lt;a href=&quot;https://results.cisce.org&quot; target=&quot;_blank&quot; class=&quot;official-link-btn&quot;&gt;results.cisce.org&lt;/a&gt;
  &lt;/div&gt;

  &lt;p&gt;&lt;strong&gt;Step-by-Step Guide to Accessing Your Score:&lt;/strong&gt;&lt;/p&gt;
  &lt;ol class=&quot;steps-list&quot;&gt;
    &lt;li&gt;Visit either of the official portals linked above.&lt;/li&gt;
    &lt;li&gt;Select &lt;strong&gt;&quot;ICSE&quot;&lt;/strong&gt; from the course drop-down menu.&lt;/li&gt;
    &lt;li&gt;Enter your &lt;strong&gt;Unique ID&lt;/strong&gt; and &lt;strong&gt;Index Number&lt;/strong&gt; exactly as they appear on your board admit card.&lt;/li&gt;
    &lt;li&gt;Type in the captcha code displayed on the screen for verification.&lt;/li&gt;
    &lt;li&gt;Click &lt;strong&gt;&quot;Submit&quot;&lt;/strong&gt; to view your scorecard.&lt;/li&gt;
    &lt;li&gt;Download or print a digital copy of your result immediately for your personal records until your school distributes the physical certificates.&lt;/li&gt;
  &lt;/ol&gt;

  &lt;h2&gt;🔍 What to Do After the Results&lt;/h2&gt;
  &lt;p&gt;Keep in mind that these results, while an important academic milestone, are just one stepping stone in your journey. If your scores are not exactly what you hoped for, you will have official avenues to address them:&lt;/p&gt;
  
  &lt;ul&gt;
    &lt;li&gt;&lt;strong&gt;Rechecking:&lt;/strong&gt; CISCE typically opens a short window for recheck applications immediately after the results are declared.&lt;/li&gt;
    &lt;li&gt;&lt;strong&gt;Improvement Exams:&lt;/strong&gt; If you want another chance to improve your academic standing, CISCE generally schedules improvement exams for the month of July.&lt;/li&gt;
  &lt;/ul&gt;

  &lt;div class=&quot;footer-note&quot;&gt;
    Take a deep breath, keep your admit card handy, and remember that a single exam score does not define your entire future. Best of luck to everyone awaiting their results! ✨
  &lt;/div&gt;

&lt;/div&gt;

&lt;/body&gt;
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</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/5294202291569953832/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/04/icse-class-10-results-2026-expected.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/5294202291569953832'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/5294202291569953832'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/04/icse-class-10-results-2026-expected.html' title='ICSE Class 10 Results 2027: Expected Dates, Past Trends, and How to Check'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-7193154728369011633</id><published>2026-04-17T23:50:00.000-07:00</published><updated>2026-08-08T09:51:30.907-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="IX"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Bridging the Gap: Foundation Mathematics for Competitive Excellence | Classes IX &amp; X CBSE ICSE</title><content type='html'>&lt;script src=&quot;https://cdn.jsdelivr.net/npm/mathjax@3/es5/tex-chtml.js&quot; id=&quot;MathJax-script&quot; async&gt;&lt;/script&gt;

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&lt;div class=&quot;blog-container&quot;&gt;
    &lt;div class=&quot;blog-content&quot;&gt;
        &lt;h1&gt;Bridging the Gap: Foundation Mathematics for Competitive Excellence&lt;/h1&gt;
        
        &lt;h2&gt;Overview&lt;/h2&gt;
        &lt;p&gt;This problem set is meticulously curated for students in Classes IX and X (CBSE/ICSE) who are ready to step beyond the standard textbook curriculum. While the regular syllabus equips you with mathematical tools, these questions train you in the &lt;strong&gt;art of mathematical thinking&lt;/strong&gt;. Designed in alignment with the competency-based approach of the new NCF, this module shifts the focus from procedural calculation to logical deduction, pattern recognition, and critical analysis.&lt;/p&gt;
        &lt;p&gt;Whether your goal is to tackle the Mathematics Olympiads, prepare for the rigorous foundations of IIT-JEE, or simply elevate your problem-solving skills, these challenges will test your conceptual depth.&lt;/p&gt;

        &lt;h2&gt;Thematic Breakdown &amp;amp; Core Concepts&lt;/h2&gt;
        
        &lt;h3&gt;1. The Power of Patterns (Cyclicity &amp;amp; Last Digits)&lt;/h3&gt;
        &lt;p&gt;&lt;strong&gt;Target Questions:&lt;/strong&gt; 3, 4, 6, 7, 10&lt;/p&gt;
        &lt;p&gt;&lt;strong&gt;The Objective:&lt;/strong&gt; In school, you learn to calculate exact values. In competitive mathematics, you are often asked to find the behavior of numbers that are too massive to compute (like \(3^{80}\) or \(2009^{2009}\)).&lt;/p&gt;
        &lt;p&gt;&lt;strong&gt;Skills Developed:&lt;/strong&gt; These questions introduce the foundational concepts of modular arithmetic and the cyclicity of unit digits. Students learn to observe repetitive patterns, extrapolate rules, and apply them to complex exponents and factorials.&lt;/p&gt;

        &lt;h3&gt;2. Advanced Algebraic Reasoning &amp;amp; Exponents&lt;/h3&gt;
        &lt;p&gt;&lt;strong&gt;Target Questions:&lt;/strong&gt; 1, 2, 5&lt;/p&gt;
        &lt;p&gt;&lt;strong&gt;The Objective:&lt;/strong&gt; Moving beyond basic index laws, these problems require multi-step logical framing. For instance, proving that a number is &lt;em&gt;never&lt;/em&gt; divisible by 3 demands a solid grasp of mathematical proofs and parity.&lt;/p&gt;
        &lt;p&gt;&lt;strong&gt;Skills Developed:&lt;/strong&gt; Students will enhance their ability to manipulate nested exponents (power towers) and use algebraic identities to prove divisibility rules, a staple skill for ISI and CMI entrance exams.&lt;/p&gt;

        &lt;h3&gt;3. Number Theory &amp;amp; Combinatorial Thinking&lt;/h3&gt;
        &lt;p&gt;&lt;strong&gt;Target Questions:&lt;/strong&gt; 8, 9, 11&lt;/p&gt;
        &lt;p&gt;&lt;strong&gt;The Objective:&lt;/strong&gt; Questions involving perfect cubes, sums of squares, and counting divisors require an intimate understanding of prime factorization.&lt;/p&gt;
        &lt;p&gt;&lt;strong&gt;Skills Developed:&lt;/strong&gt; This section sharpens combinatorial logic. Instead of manually counting, students learn to use prime factorization as a blueprint to determine the number of divisors (Question 11) or to analyze the boundaries of perfect cubes within a massive range (Question 8).&lt;/p&gt;

        &lt;h2&gt;Why This Matters for Your Development&lt;/h2&gt;
        &lt;ul&gt;
            &lt;li&gt;&lt;strong&gt;NCF Alignment:&lt;/strong&gt; Emphasizes analytical thinking over rote memorization. You aren&#39;t just applying formulas; you are building them.&lt;/li&gt;
            &lt;li&gt;&lt;strong&gt;Stamina &amp;amp; Resilience:&lt;/strong&gt; Problems like evaluating \(9! + 3^{9966}\) teach you not to be intimidated by the scale of a problem, breaking it down into manageable, logical pieces.&lt;/li&gt;
            &lt;li&gt;&lt;strong&gt;Competitive Edge:&lt;/strong&gt; The transition from Class X to Class XI mathematics is notoriously steep. Mastering these number theory and algebra concepts now builds a robust foundation, making advanced calculus and discrete mathematics much more intuitive later on.&lt;/li&gt;
        &lt;/ul&gt;

        &lt;hr /&gt;

        &lt;blockquote&gt;
          Answers: \(\quad \)
            1. \(a^2\) \(\quad \)
2. 1\(\quad \)
3. 1\(\quad \)
4. 9\(\quad \)
5. (Proof required)\(\quad \)
6. 8\(\quad \)
7. 3\(\quad \)
8. 10,000\(\quad \)
9. (B) 1997\(\quad \)
10. 9\(\quad \)
11. 16\(\quad \)
        &lt;/blockquote&gt;

        &lt;div class=&quot;question-list&quot;&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;1.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;If \(a^3 = 1\) and \(x = a^{2009^{2009^{2009}}}\), find the simplest value of \(x\).&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;2.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;Find the remainder when \(2009^{2009^{2009}}\) is divided by 2.&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;3.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;Find the remainder when \(3^{80}\) is divided by 10.&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;4.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;Find the last digit of \(9! + 3^{9966}\).&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;5.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;Show that \(16^n\) is never divisible by 3 for any natural number \(n\).&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;6.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;Find the last digit of \(4^{2n} + 2\), where \(n = 2026\).&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;7.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;Find the digit in the units place of the integer \(1! + 2! + 3! + \dots + 99!\) (where \(n! = 1 \times 2 \times 3 \times \dots \times n\)).&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;8.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;Find the number of perfect cubes from 1 to \(10^{12}\).&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;9.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;Which of the following numbers can be expressed as the sum of the squares of two integers?&lt;br&gt;
                * (A) 1995&lt;br&gt;
                * (B) 1997&lt;br&gt;
                * (C) 2003&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;10.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;Find the last digit of \((2137)^{754}\).&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;question-item&quot;&gt;
                &lt;span class=&quot;question-number&quot;&gt;11.&lt;/span&gt;
                &lt;span class=&quot;question-text&quot;&gt;Find the number of divisors of 1000.&lt;/span&gt;
            &lt;/div&gt;
        &lt;/div&gt;

        &lt;div class=&quot;author-section&quot;&gt;
            &lt;div class=&quot;author-info&quot;&gt;
                &lt;span class=&quot;author-name&quot;&gt;✍️ Vinod Singh&lt;/span&gt;
                &lt;span class=&quot;author-contact&quot;&gt;📞 9038126497&lt;/span&gt;
            &lt;/div&gt;
            &lt;div style=&quot;font-size: 0.85rem; color: #2c6e9e;&quot;&gt;
                🧠 Mathematics educator | Prime Maths 
            &lt;/div&gt;
        &lt;/div&gt;
        &lt;div class=&quot;footer-note&quot;&gt;
            © 2026 — designed for analytical minds | Competency-focused learning
        &lt;/div&gt;
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&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/7193154728369011633/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/04/bridging-gap-foundation-mathematics-for.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/7193154728369011633'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/7193154728369011633'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/04/bridging-gap-foundation-mathematics-for.html' title='Bridging the Gap: Foundation Mathematics for Competitive Excellence | Classes IX &amp; X CBSE ICSE'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-69861582932085914</id><published>2026-04-10T06:43:00.000-07:00</published><updated>2026-08-08T09:51:28.923-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="algebra"/><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="IX"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Can You Solve These 20 Tricky Math Problems for Classes IX and X CBSE ICSE</title><content type='html'>&lt;script src=&quot;https://cdn.jsdelivr.net/npm/mathjax@3/es5/tex-chtml.js&quot; id=&quot;MathJax-script&quot; async&gt;&lt;/script&gt;

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&lt;div id=&quot;math-slider-2col&quot;&gt;
  &lt;!-- Description (same as before) --&gt;
  &lt;div class=&quot;description-box&quot;&gt;
    &lt;h3&gt;📚 20 Mathematical Challenges – CBSE, ICSE &lt;/h3&gt;
    &lt;p&gt;Welcome! This slider shows &lt;span class=&quot;highlight&quot;&gt;two problems side by side&lt;/span&gt; on each page. Use &lt;strong&gt;Previous / Next&lt;/strong&gt; buttons (or left/right arrow keys) to navigate through the 10 slides. Each problem has its own &lt;span class=&quot;highlight&quot;&gt;“Show hint”&lt;/span&gt; button – click to reveal a subtle nudge.&lt;/p&gt;
    &lt;p&gt;✨ Covers rational proofs, surd simplifications, Diophantine equations, and more. Suitable for grades 9–12 and competitive exams.
     Featuring 20 hand-picked problems covering everything from rational, irrational numbers to algebra and number theory. Whether you are prepping for a competitive exam or just love a good brain-teaser, this is for you. Suitable for students of IX and X of CBSE and ICSE.
    If these problems feel a bit intimidating, don&#39;t worry—they are designed to be! While standard high school mathematics focuses heavily on rote memorization and applying standard formulas to straightforward questions, this problem set bridges the gap between the regular classroom and competitive mathematics (like the AMC, math Olympiads, or advanced entrance exams).

Instead of just asking you to &quot;solve for x,&quot; these questions require creative algebraic manipulation, pattern recognition, and proof-based logical reasoning. They test whether you can combine multiple mathematical concepts to find an elegant solution, rather than just grinding through a standard algorithm.

Key Mathematical Areas Covered
This set of 20 problems targets several advanced domains:

Advanced Algebra &amp; Identities: Moving beyond basic factoring to use conditional identities (like the sum of cubes) and symmetric functions.

Number Theory: Exploring the properties of prime numbers, divisibility rules, and solving basic Diophantine equations (finding integer solutions to polynomial equations).

Complex Radicals &amp; Surds: Tackling nested square roots, cube roots of binomial surds, and rationalizing multi-term denominators.

Telescoping Series: Recognizing patterns in sequences that cancel each other out to reveal a clean, simple answer.

Introductory Complex Numbers &amp; Logarithms: Understanding the cyclical nature of imaginary numbers and manipulating logarithmic bases.&lt;/p&gt;
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      &lt;span class=&quot;slide-indicator&quot; id=&quot;slideIndicator&quot;&gt;Slide 1 / 10&lt;/span&gt;
      &lt;button class=&quot;nav-btn&quot; id=&quot;nextSlideBtn&quot;&gt;Next ▶&lt;/button&gt;
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  &lt;/div&gt;
  &lt;div class=&quot;math-footer&quot;&gt;
    ✨ 20 problems, 10 slides, 2 per slide. Click &quot;Show hint&quot; for each problem individually. Left/right arrow keys navigate. Good luck! © Vinod Singh
  &lt;/div&gt;
&lt;/div&gt;

&lt;script&gt;
  // Full problems array (identical to before)
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    { number: 1, question: &quot;Prove that for any natural number \\( n \\), \\( \\sqrt{4n^4+n^2+4n^3} \\) is a rational number.&quot;, hint: &quot;Inside the radical: \\(4n^4 + 4n^3 + n^2 = n^2(4n^2+4n+1) = n^2(2n+1)^2\\). Hence the square root is \\(n(2n+1)\\), an integer, rational.&quot; },
    { number: 2, question: &quot;Prove that for any natural number \\( n \\), \\( \\sqrt{(4n^2+1)^2-(4n^2-1)^2} \\) is a rational number.&quot;, hint: &quot;Use \\(A^2-B^2 = (A-B)(A+B)\\). Here \\((4n^2+1)-(4n^2-1)=2\\), sum \\(=8n^2\\), product \\(=16n^2\\), sqrt = \\(4n\\), rational.&quot; },
    { number: 3, question: &quot;Find the simplest value of: \\( \\frac{(a^4-b^4)^3+(b^4-c^4)^3+(c^4-a^4)^3}{(b^2-c^2)^3+(c^2-a^2)^3+(a^2-b^2)^3} \\)&quot;, hint: &quot;If \\(X+Y+Z=0\\) then \\(X^3+Y^3+Z^3 = 3XYZ\\). Numerator: \\(3(a^4-b^4)(b^4-c^4)(c^4-a^4)\\). Denominator: \\(3(b^2-c^2)(c^2-a^2)(a^2-b^2)\\). Factor differences of squares → \\((a^2+b^2)(b^2+c^2)(c^2+a^2)\\).&quot; },
    { number: 4, question: &quot;If \\( x^2-3x+1=0 \\), find the value of \\( x^2+\\frac{1}{x^2} \\).&quot;, hint: &quot;Divide by \\(x\\): \\(x+1/x = 3\\). Square: \\(x^2+1/x^2+2=9\\) → \\(7\\).&quot; },
    { number: 5, question: &quot;If \\( 2^x=3^y=36 \\), find \\( \\frac{2}{x}+\\frac{2}{y} \\).&quot;, hint: &quot;Take logs: \\(x=\\log_2 36, y=\\log_3 36\\). Then \\(2/x = 2\\log_{36}2,\\; 2/y=2\\log_{36}3\\). Sum = \\(2\\log_{36}6 = 1\\).&quot; },
    { number: 6, question: &quot;How many pairs of positive integers \\( (m,n) \\) satisfy \\( m^2-n^2=13 \\)?&quot;, hint: &quot;Factor: \\((m-n)(m+n)=13\\). Only (1,13). Solve → \\(m=7,n=6\\). One pair.&quot; },
    { number: 7, question: &quot;Evaluate: \\( \\frac{1}{\\sqrt{1}+\\sqrt{2}} + \\frac{1}{\\sqrt{2}+\\sqrt{3}} + \\dots + \\frac{1}{\\sqrt{99}+\\sqrt{100}} \\)&quot;, hint: &quot;Rationalize each term: \\(\\sqrt{k+1}-\\sqrt{k}\\). Telescoping → \\(\\sqrt{100}-\\sqrt{1}=9\\).&quot; },
    { number: 8, question: &quot;If prime \\(p\\) divides \\(q^2(p+1)\\) (\\(q&gt;1\\)), show \\(p\\mid q\\).&quot;, hint: &quot;\\(\\gcd(p,p+1)=1\\). So \\(p\\mid q^2\\) → \\(p\\mid q\\).&quot; },
    { number: 9, question: &quot;Rationalize \\( \\frac{1}{1+\\sqrt{2}-\\sqrt{3}} \\).&quot;, hint: &quot;Multiply by \\((1+\\sqrt{2})+\\sqrt{3}\\). Denominator becomes \\(2\\sqrt{2}\\). Then simplify to \\(\\frac{\\sqrt{2}+2+\\sqrt{6}}{4}\\).&quot; },
    { number: 10, question: &quot;How many rational numbers from digits 2,3,5?&quot;, hint: &quot;Fractions \\(a/b\\) with \\(a,b\\in\\{2,3,5\\}\\). Distinct values after simplifying: 7.&quot; },
    { number: 11, question: &quot;Find an irrational number between \\(e\\) and \\(\\pi\\).&quot;, hint: &quot;Example: \\(\\sqrt{8}=2\\sqrt{2}\\approx2.828\\), between 2.718 and 3.1416.&quot; },
    { number: 12, question: &quot;If \\(\\sqrt[3]{a+\\sqrt{b}} = x+\\sqrt{y}\\), show \\(\\sqrt[3]{a-\\sqrt{b}} = x-\\sqrt{y}\\).&quot;, hint: &quot;Cube both sides, replace \\(\\sqrt{b}\\) with \\(-\\sqrt{b}\\).&quot; },
    { number: 13, question: &quot;Find \\( \\frac{\\sqrt{26-15\\sqrt{3}}}{5\\sqrt{2}-\\sqrt{38+5\\sqrt{3}}} \\)&quot;, hint: &quot;Simplify nested radicals → value = \\(\\frac12\\).&quot; },
    { number: 14, question: &quot;Square root of \\(a+x+\\sqrt{2ax+x^2}\\).&quot;, hint: &quot;Easy!&quot; },
    { number: 15, question: &quot;Cube root of \\(2\\sqrt{2}-6+3\\sqrt{2}-1\\).&quot;, hint: &quot;Use the \\((a-b)^3\\) formula&quot; },
    { number: 16, question: &quot;If \\(2x = \\sqrt{a}+1/\\sqrt{a}\\), evaluate \\(\\frac{\\sqrt{x^2-1}}{x-\\sqrt{x^2-1}}\\).&quot;, hint: &quot;Simplify to \\(1/\\sqrt{a}\\) (or \\(\\sqrt{a}\\)).&quot; },
    { number: 17, question: &quot;If \\(i^2=-1\\), find \\(i+i^2+\\dots+i^8\\).&quot;, hint: &quot;Cycle of 4, sum per cycle = 0, two cycles → 0.&quot; },
    { number: 18, question: &quot;If \\(\\sqrt{x}+\\sqrt{y}=\\sqrt{k}\\), prove \\(x^2+y^2+k^2 = 2xy+2kx+2ky\\).&quot;, hint: &quot;Square twice, rearrange.&quot; },
    { number: 19, question: &quot;If \\(x+1/x=1\\), find \\(x^3+1\\).&quot;, hint: &quot;Multiply by \\(x\\): \\(x^2-x+1=0\\). Multiply by \\(x+1\\) → \\(x^3+1=0\\).&quot; },
    { number: 20, question: &quot;Prove \\((2n+1)^3-1\\) divisible by 2.&quot;, hint: &quot;Expand: \\(8n^3+12n^2+6n = 2n(4n^2+6n+3)\\), even.&quot; }
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&lt;/script&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/69861582932085914/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/04/can-you-solve-these-20-tricky-math.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/69861582932085914'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/69861582932085914'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/04/can-you-solve-these-20-tricky-math.html' title='Can You Solve These 20 Tricky Math Problems for Classes IX and X CBSE ICSE'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-9045536807292384950</id><published>2026-04-02T04:01:00.000-07:00</published><updated>2026-08-08T09:56:30.970-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="IIT"/><category scheme="http://www.blogger.com/atom/ns#" term="ISC"/><category scheme="http://www.blogger.com/atom/ns#" term="JEE Main"/><category scheme="http://www.blogger.com/atom/ns#" term="WBJEE"/><title type='text'>Integral Calculus for JEE Main &amp; Advanced: Practice Problems</title><content type='html'>
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    .q-stat-lbl {

        font-size: 0.75rem;

        text-transform: uppercase;

        letter-spacing: 0.5px;

        color: var(--text-light);

    }



    /* Instructions */

    .q-instructions {

        background: #ecfdf5;
        /* Light Emerald bg */

        border: 1px solid #d1fae5;

        border-left: 5px solid var(--secondary-color);

        padding: 20px;

        border-radius: 8px;

        margin-bottom: 25px;

    }



    .q-instructions h3 {

        color: #065f46;

        margin: 0 0 10px 0;

        font-size: 1.2rem;

        display: flex;

        align-items: center;

        gap: 8px;

    }



    .q-instructions ul {

        margin: 0;

        padding-left: 20px;

        color: #064e3b;

    }



    .q-instructions li {

        margin-bottom: 5px;

    }



    /* Main Layout */

    .q-layout {

        display: flex;

        gap: 25px;

        align-items: flex-start;

    }



    /* Sidebar Navigation */

    .q-sidebar {

        flex: 0 0 240px;

        background: var(--surface-color);

        padding: 20px;

        border-radius: var(--border-radius);

        box-shadow: var(--shadow-sm);

    }



    .q-nav-grid {

        display: grid;

        grid-template-columns: repeat(5, 1fr);

        gap: 8px;

        margin-bottom: 20px;

    }



    .q-nav-num {

        aspect-ratio: 1;

        display: flex;

        align-items: center;

        justify-content: center;

        background: #f3f4f6;

        border-radius: 8px;

        font-size: 0.9rem;

        font-weight: 600;

        color: var(--text-light);

        cursor: pointer;

        transition: all 0.2s ease;

        border: 1px solid transparent;

    }



    .q-nav-num:hover {

        background: #e5e7eb;

        transform: translateY(-2px);

    }



    .q-nav-num.active {

        background: var(--primary-color);

        color: white;

        box-shadow: 0 4px 10px rgba(79, 70, 229, 0.4);

    }



    .q-nav-num.answered {

        background: var(--secondary-color);

        color: white;

    }



    /* Question Area */

    .q-content-area {

        flex: 1;

        min-width: 0;
        /* Prevents overflow */

    }



    .q-card {

        background: var(--surface-color);

        border-radius: var(--border-radius);

        padding: 30px;

        box-shadow: var(--shadow-lg);

        display: none;

        animation: fadeIn 0.4s ease;

    }



    .q-card.active {

        display: block;

    }



    @keyframes fadeIn {

        from {
            opacity: 0;
            transform: translateY(10px);
        }

        to {
            opacity: 1;
            transform: translateY(0);
        }

    }



    .q-card-header {

        display: flex;

        justify-content: space-between;

        align-items: center;

        margin-bottom: 20px;

        padding-bottom: 15px;

        border-bottom: 1px solid #e5e7eb;

    }



    .q-card-title {

        font-size: 1.1rem;

        font-weight: 700;

        color: var(--primary-color);

        text-transform: uppercase;

        letter-spacing: 1px;

    }



    .q-question-text {

        font-size: 1.25rem;

        font-weight: 500;

        margin-bottom: 25px;

        color: var(--text-color);

    }



    /* Options */

    .q-options {

        display: flex;

        flex-direction: column;

        gap: 12px;

    }



    .q-option {

        position: relative;

        background: white;

        border: 2px solid #e5e7eb;

        border-radius: 12px;

        padding: 15px 20px;

        cursor: pointer;

        transition: all 0.2s ease;

        display: flex;

        align-items: center;

    }



    .q-option:hover {

        border-color: #c7d2fe;

        background: #eef2ff;

    }



    .q-option.selected {

        border-color: var(--primary-color);

        background: #eef2ff;

        box-shadow: 0 0 0 4px rgba(79, 70, 229, 0.1);

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    .q-option input {

        position: absolute;

        opacity: 0;

        cursor: pointer;

        height: 0;

        width: 0;

    }



    .q-opt-marker {

        display: flex;

        align-items: center;

        justify-content: center;

        width: 32px;

        height: 32px;

        background: #f3f4f6;

        border-radius: 50%;

        margin-right: 15px;

        font-weight: 700;

        color: var(--text-light);

        flex-shrink: 0;

        transition: all 0.2s;

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    .q-option.selected .q-opt-marker {

        background: var(--primary-color);

        color: white;

    }



    .q-option-text {

        font-size: 1.05rem;

        color: var(--text-color);

    }



    /* ---------- HINT SECTION (added for mensuration quiz) ---------- */
    .q-hint-wrapper {
        margin-top: 25px;
        border-top: 1px dashed #d1d5db;
        padding-top: 20px;
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    .q-hint-btn {
        background: transparent;
        border: 2px solid var(--primary-color);
        color: var(--primary-color);
        padding: 8px 20px;
        border-radius: 30px;
        font-size: 0.9rem;
        font-weight: 600;
        cursor: pointer;
        transition: all 0.3s ease;
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        align-items: center;
        gap: 6px;
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    .q-hint-btn:hover {
        background: var(--primary-color);
        color: white;
        box-shadow: 0 0 15px rgba(79, 70, 229, 0.3);
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        margin-top: 15px;
        padding: 15px 20px;
        background: #f9fafb;
        border-radius: 8px;
        border-left: 3px solid var(--primary-color);
        font-size: 1rem;
        color: var(--text-light);
        line-height: 1.6;
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    .hint-text {
        margin: 0;
        font-style: italic;
        color: #4b5563;
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    /* ------------------------------------------ */

    /* Navigation Buttons */

    .q-actions {

        display: flex;

        justify-content: space-between;

        margin-top: 30px;

        padding-top: 20px;

        border-top: 1px solid #e5e7eb;

    }



    .q-btn {

        background: white;

        border: 1px solid #d1d5db;

        color: var(--text-color);

        padding: 12px 24px;

        border-radius: 8px;

        font-weight: 600;

        cursor: pointer;

        transition: all 0.2s;

        display: flex;

        align-items: center;

        gap: 8px;

        font-size: 0.95rem;

    }



    .q-btn:hover:not(:disabled) {

        background: #f9fafb;

        border-color: #9ca3af;

        transform: translateY(-1px);

    }



    .q-btn-primary {

        background: var(--primary-gradient);

        color: white;

        border: none;

        box-shadow: 0 4px 6px rgba(79, 70, 229, 0.3);

    }



    .q-btn-primary:hover:not(:disabled) {

        box-shadow: 0 6px 12px rgba(79, 70, 229, 0.4);

        transform: translateY(-2px);

        background: var(--primary-gradient);

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    .q-btn-success {

        background: linear-gradient(135deg, #10b981 0%, #059669 100%);

        color: white;

        border: none;

        box-shadow: 0 4px 6px rgba(16, 185, 129, 0.3);

    }



    .q-btn-success:hover:not(:disabled) {

        box-shadow: 0 6px 12px rgba(16, 185, 129, 0.4);

        background: linear-gradient(135deg, #10b981 0%, #059669 100%);

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    .q-btn:disabled {

        opacity: 0.5;

        cursor: not-allowed;

        transform: none !important;

        box-shadow: none !important;

    }



    /* Progress Bar */

    .q-progress-wrap {

        margin-top: 20px;

    }
    .q-prog-info {

        display: flex;

        justify-content: space-between;

        font-size: 0.85rem;

        color: var(--text-light);

        margin-bottom: 8px;

    }
    .q-prog-track {

        height: 8px;

        background: #e5e7eb;

        border-radius: 4px;

        overflow: hidden;

    }
    .q-prog-fill {

        height: 100%;

        background: var(--secondary-color);

        width: 0%;

        transition: width 0.4s ease;

    }



    /* Footer */

    .q-footer {

        text-align: center;

        margin-top: 40px;

        padding-top: 20px;

        border-top: 1px solid #e5e7eb;

        color: var(--text-light);

        font-size: 0.9rem;

    }



    /* Results Modal */

    .q-modal-overlay {

        position: fixed;

        top: 0;
        left: 0;
        right: 0;
        bottom: 0;

        background: rgba(17, 24, 39, 0.85);
        /* Dark overlay */

        display: flex;

        justify-content: center;

        align-items: center;

        z-index: 9999;

        padding: 20px;

        backdrop-filter: blur(4px);

    }



    .q-modal {

        background: white;

        width: 100%;

        max-width: 700px;

        max-height: 90vh;

        overflow-y: auto;

        border-radius: 20px;

        padding: 40px;

        box-shadow: 0 25px 50px -12px rgba(0, 0, 0, 0.25);

    }



    .q-result-header {

        text-align: center;

        margin-bottom: 30px;

    }



    .q-result-header h2 {

        font-size: 2rem;

        color: var(--text-color);

        margin-bottom: 10px;

    }



    .q-score-grid {

        display: grid;

        grid-template-columns: repeat(3, 1fr);

        gap: 15px;

        margin-bottom: 30px;

    }



    .q-score-card {

        background: #f9fafb;

        padding: 15px;

        border-radius: 12px;

        text-align: center;

        border: 1px solid #e5e7eb;

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    .q-score-val {

        font-size: 2rem;

        font-weight: 800;

        color: var(--primary-color);

    }



    .q-score-lbl {

        font-size: 0.85rem;

        color: var(--text-light);

    }



    .q-ans-list {

        list-style: none;

        padding: 0;

        margin-bottom: 30px;

    }



    .q-ans-item {

        padding: 15px;

        margin-bottom: 10px;

        border-radius: 8px;

        font-size: 0.95rem;

        background: #f9fafb;

        border-left: 4px solid #d1d5db;

    }



    .q-ans-item.correct {
        border-left-color: var(--secondary-color);
        background: #ecfdf5;
    }

    .q-ans-item.incorrect {
        border-left-color: #ef4444;
        background: #fef2f2;
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    .q-ans-item.unanswered {
        border-left-color: var(--accent-color);
        background: #fffbeb;
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    /* Responsive */

    @media (max-width: 768px) {

        .q-layout {
            flex-direction: column;
        }

        .q-sidebar {
            width: 100%;
            order: -1;
        }

        /* Move nav to top */

        .q-nav-grid {
            grid-template-columns: repeat(auto-fill, minmax(40px, 1fr));
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        .q-logo {
            font-size: 2rem;
        }

        .q-dashboard {
            grid-template-columns: 1fr;
            text-align: center;
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        .q-stats-row {
            justify-content: center;
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            grid-template-columns: 1fr;
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        .q-actions {
            flex-direction: column;
            gap: 10px;
        }

        .q-btn {
            width: 100%;
            justify-content: center;
        }

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&lt;/style&gt;

&lt;!-- Global toggleHint function for hint buttons --&gt;
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        content.style.display = &#39;none&#39;;
        btn.textContent = &#39;Hint&#39;;
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}
&lt;/script&gt;

&lt;div class=&quot;quiz-wrapper-modern&quot;&gt;

    &lt;div class=&quot;q-container&quot;&gt;



        &lt;header class=&quot;q-header&quot;&gt;

            &lt;div class=&quot;q-logo&quot;&gt;&lt;span&gt;Prime Maths&lt;/span&gt;&lt;/div&gt;

            &lt;div class=&quot;q-subtitle&quot;&gt; 25 Multiple Choice Questions (MCQs) on Integral Calculus for students of class XI and XII
                preparing for board examinations or JEE Mains, IIT Advanced WBJEE or any other competitive entrance examination.
            &lt;/div&gt;

            &lt;div class=&quot;q-author-info&quot;&gt;

                &lt;div class=&quot;q-author-item&quot;&gt;👨‍🏫 Author:
                    Vinod Singh&lt;/div&gt;

                &lt;div class=&quot;q-author-item&quot;&gt;📞 WA: +91-9038126497&lt;/div&gt;

                &lt;div class=&quot;q-author-item&quot;&gt;&lt;a href=&quot;https://facebook.com/prime.maths&quot; target=&quot;_blank&quot;&gt;Prime Maths&lt;/a&gt;
                &lt;/div&gt;

            &lt;/div&gt;

        &lt;/header&gt;



        &lt;div class=&quot;q-dashboard&quot;&gt;

            &lt;div class=&quot;q-dashboard-text&quot;&gt;

                &lt;h2&gt;Advanced Integral Calculus - Definite and Indefinite Integration&lt;/h2&gt;

                &lt;p&gt;Test your understanding of core concepts.Master Integral Calculus for Indian Statistical Institute (B. Math &amp; B.Stat), JEE Main &amp; Advanced. Practice hand-picked problems with step-by-step solutions, advanced shortcuts, and integration techniques.&lt;/p&gt;

            &lt;/div&gt;

            &lt;div class=&quot;q-stats-row&quot;&gt;

                &lt;div class=&quot;q-stat-card&quot;&gt;

                    &lt;div class=&quot;q-stat-val&quot; id=&quot;answered-count&quot;&gt;0&lt;/div&gt;

                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Done&lt;/div&gt;

                &lt;/div&gt;

                &lt;div class=&quot;q-stat-card&quot;&gt;

                    &lt;div class=&quot;q-stat-val&quot; id=&quot;remaining-count&quot;&gt;25&lt;/div&gt;

                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Left&lt;/div&gt;

                &lt;/div&gt;

                &lt;div class=&quot;q-stat-card&quot;&gt;

                    &lt;div class=&quot;q-stat-val&quot; id=&quot;score-preview&quot;&gt;0%&lt;/div&gt;

                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Score&lt;/div&gt;

                &lt;/div&gt;

            &lt;/div&gt;

        &lt;/div&gt;



        &lt;div class=&quot;q-instructions&quot;&gt;

            &lt;h3&gt;📝 Instructions&lt;/h3&gt;

            &lt;ul&gt;

                &lt;li&gt;This quiz contains 25 multiple choice questions.&lt;/li&gt;

                &lt;li&gt;Select only one correct answer per question.&lt;/li&gt;

                &lt;li&gt;Use the navigator to jump between questions.&lt;/li&gt;

                &lt;li&gt;Submit when you are finished to see results.&lt;/li&gt;

            &lt;/ul&gt;

        &lt;/div&gt;



        &lt;div class=&quot;q-layout&quot;&gt;

            &lt;div class=&quot;q-sidebar&quot;&gt;

                &lt;div style=&quot;color: var(--text-color); font-weight: 600; margin-bottom: 15px; text-align: center;&quot;&gt;
                    Question Navigator&lt;/div&gt;

                &lt;div class=&quot;q-nav-grid&quot; id=&quot;question-nav&quot;&gt;

                &lt;/div&gt;



                &lt;div class=&quot;q-progress-wrap&quot;&gt;

                    &lt;div class=&quot;q-prog-info&quot;&gt;

                        &lt;span&gt;Progress&lt;/span&gt;

                        &lt;span id=&quot;progress-percentage&quot;&gt;0%&lt;/span&gt;

                    &lt;/div&gt;

                    &lt;div class=&quot;q-prog-track&quot;&gt;

                        &lt;div class=&quot;q-prog-fill&quot; id=&quot;progress-fill&quot;&gt;&lt;/div&gt;

                    &lt;/div&gt;

                &lt;/div&gt;

            &lt;/div&gt;



            &lt;div class=&quot;q-content-area&quot;&gt;

                &lt;form id=&quot;quizForm&quot;&gt;



                    &lt;div id=&quot;questions-wrapper&quot;&gt;

                        &lt;!-- ========== QUESTION 1 ========== --&gt;
                        &lt;div class=&quot;q-card active&quot; id=&quot;question-1&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;

                                &lt;span class=&quot;q-card-title&quot;&gt;Question 1&lt;/span&gt;

                            &lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;

                                Let \(f(x)=\frac{x}{(1+x^n)^{1/n}}\) for \(n \geq 2\) and \(g(x)=f \circ f \circ \dots \circ f\) (\(n\) times), 
                            then \(\int x^{n-2} g(x) dx \) is equal to                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        \frac{1}{n(n+1)} (1+nx^n)^{1-\frac{1}{n}}+c\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        \frac{1}{n(n-1)} (1+nx^n)^{1-\frac{1}{n}}+c\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        \frac{1}{n(n-1)} (1+nx^n)^{1+\frac{1}{n}}+c \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        \frac{1}{n(n-1)} (1-nx^n)^{1-\frac{1}{n}}+c\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;&lt;a href=&quot;https://youtu.be/B0MsU-g39Qo?si=qG7WmUSLdCCRZnj2&quot;&gt;Click here&lt;/a&gt;
                                    &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 2 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-2&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 2&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt; \(\int_{\frac{1}{2026}}^{2026} \frac{tan^{-1} x}{x} dx \quad =\) 
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{\pi}{4} \ln 2026\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{2}\frac{\pi}{8} \ln 2026\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{\pi}{2} \ln 2026\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{\pi}{3} \ln 2026\) &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;&lt;a href=&quot;https://youtu.be/Bxt6P-mCbAQ?si=2PmYBH02lO0T9YLK&quot;&gt;Click here&lt;/a&gt;&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 3 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-3&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 3&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;\(\int \frac{dx}{\sqrt[3]{x}+\sqrt[5]{x}} \quad =\)                        
&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;
                                    &lt;span class=&quot;q-option-text&quot;&gt;\( = 15 \left( \frac{x^{2/3}}{10} - \frac{x^{8/15}}{8} + \frac{x^{2/5}}{6} - \frac{x^{4/15}}{4} + \frac{x^{2/15}}{2} - \frac{1}{2} \ln |x^{2/15} + 1| \right) + c
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;
                                    &lt;span class=&quot;q-option-text&quot;&gt;\( = 15 \left( \frac{x^{2/3}}{10} + \frac{x^{8/15}}{8} + \frac{x^{2/5}}{6} + \frac{x^{4/15}}{4} + \frac{x^{2/15}}{2} - \frac{1}{2} \ln |x^{2/15} + 1| \right) + c
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;
                                    &lt;span class=&quot;q-option-text&quot;&gt;\( = 15 \left( -\frac{x^{2/3}}{10} - \frac{x^{8/15}}{8} - \frac{x^{2/5}}{6} - \frac{x^{4/15}}{4} - \frac{x^{2/15}}{2} - \frac{1}{2} \ln |x^{2/15} + 1| \right) + c
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;
                                    &lt;span class=&quot;q-option-text&quot;&gt;\( = 17 \left( \frac{x^{2/3}}{10} - \frac{x^{8/15}}{8} + \frac{x^{2/5}}{6} - \frac{x^{4/15}}{4} + \frac{x^{2/15}}{2} - \frac{1}{2} \ln |x^{2/15} + 1| \right) + c
                                        \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Put \(x=z^{15}\)
                                    &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 4 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-4&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 4&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;\(\int (x^6+x^3) \sqrt[3]{x^3+2} \quad dx \quad =\) 

                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{2}(x^6+2x^3)^{\frac{3}{4}} +c\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{8}(x^6+2x^3)^{\frac{5}{3}} +c\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{8}(x^6+2x^3)^{\frac{4}{3}} +c\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{8}(x^6+x^3)^{\frac{4}{3}} +c\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;&lt;a href=&quot;https://youtu.be/iR4JiyyRiOM?si=YNwCQTtOJkRFzT1X&quot;&gt;Click Here&lt;/a&gt;&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 5 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-5&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 5&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;\( \int_{\pi/2}^{5\pi/2}  \frac{e^{tan^{-1}(\sin x)}}{e^{tan^{-1}(\sin x)}+e^{tan^{-1}(\cos x)}}  dx \quad = \) &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 2\pi \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{\pi}{8}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{\pi}{2} \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \pi \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;&lt;a href=&quot;https://youtu.be/fvFAd6IyKTg?si=48ibu9DxBkgLqOjE&quot;&gt;Click here&lt;/a&gt;&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 6 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-6&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 6&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;
                                \(\int \frac{dx}{\tan x + \sec x + \cot x + \csc x} dx \quad = \)
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{2}(\cos x - \sin x -x)+c\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{2}(-\cos x + \sin x -x)+c\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{2}(-\cos x + \sin x + x)+c\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{2}(-\cos x - \sin x -x)+c\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt; See that \(\frac{1}{\tan x + \sec x + \cot x + \csc x} = \frac{\sin x \cos x}{1+\sin x +\cos x}=\frac{1}{2}\frac{(\sin x +\cos x)^2-1^2}{1+\sin x +\cos x}\)&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 7 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-7&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 7&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;If \( f \) is an even function and \(I= \int_{0}^{\pi/2}f(\cos 2x) \cos x \quad dx \), then&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( I= \sqrt{2}\int_{0}^{\pi/4}f(\cos 2x) \cos x \quad dx \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( I= \sqrt{2}\int_{0}^{\pi/4}f(\cos 2x) \sin x \quad dx \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( I= \sqrt{2}\int_{0}^{\pi/4}f(\sin 2x) \cos x \quad dx \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( I= \sqrt{2}\int_{0}^{\pi/4}f(\sin 2x) \sin x \quad dx \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt; Use King&#39;s Rule &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 8 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-8&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 8&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \( f \) be a polynomial function such that \( f(x^2+1) = x^4+5x^2+2\), 
                                for all \( x \in \mathbb{R}.\) Then \(\int_{0}^{3} f(x) dx \) is equal to
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{41}{3} \) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{33}{2} \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{27}{2} \) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{5}{3} \) &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;See that \(f(x^2+1)=(x^2+1)^2+3(x^2+1)-2\) &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 9 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-9&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 9&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Evaluate \(\int_{-\pi/3}^{\pi/3} \frac{\pi+4x^3}{2-cos\big(|x|+\frac{\pi}{3}\big)} dx\) 
                                &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4\pi}{\sqrt{3}}tan^{-1}(\frac{1}{3})\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4\pi}{\sqrt{2}}tan^{-1}(\frac{1}{2})\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4\pi}{\sqrt{3}}tan^{-1}(\frac{1}{2})\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4\pi}{\sqrt{2}}tan^{-1}(\frac{1}{3})\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt; Express \(\frac{\pi+4x^3}{2-cos\big(|x|+\frac{\pi}{3}\big)}\) as a sum of an odd and an even function, then split&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 10 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-10&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 10&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Lrt \(f: (0,\infty) \rightarrow \mathbb{R}\) and \(F(x)=\int_{0}^{x} f(t) dt.\) If \(F(x^2)=x^2(1+x),\) then \(f(4)\) equals
                                                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{5}{4}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(7\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(4\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;  See that \(F&#39;(x)=f(x)\) by fundamental theorem of integral calculus and 
                                        \(f(x^2)=F&#39;(x^2)= \frac{3x+2}{2}\)
                                    &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 11 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-11&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 11&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Evaluate \( \int sin^{-1} \big(\frac{2x+2}{\sqrt{4x^2+8x+13}} \big) dx.\)&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\((x+1)tan^{-1}\big(\frac{2x+2}{3}\big)+\frac{3}{4}ln|4x^2+8x+13|+c\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\((x+1)tan^{-1}\big(\frac{2x+2}{3}\big)-\frac{1}{4}ln|4x^2+8x+13|+c\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\((x+1)tan^{-1}\big(\frac{2x+2}{3}\big)-\frac{3}{2}ln|4x^2+8x+13|+c\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\((x+1)tan^{-1}\big(\frac{2x+2}{3}\big)-\frac{3}{4}ln|4x^2+8x+13|+c\) &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;\(4x^2+8x+13=(2x+2)^2+3^2\) now put \( 2x+2 = t\) and then subsutitute \( t=3 \tan \theta \) &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 12 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-12&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 12&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt; Let \(T &gt; 0\) be a fixed real number. Suppose \(f\) is a continuous function
                                such that for all \(x \in \mathbb{R}, f(x+T)=f(x).\) If \(I=\int_{0}^{T} f(x) \\dx\) then the value of
                                \(\int_{3}^{3+3T} f(2x) \\dx\) is
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3I\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2I                           \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{3}{2}I\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(6I\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;\(\int_{3}^{3+3T} f(2x) \\dx\) = \(\frac{1}{2}\int_{6}^{6+6T} f(t) \\dt\) on 
                                        substituting \(2x=t\) now split the integral form 6 to T, T to 2T, ...., 5T to 6T and 6T to 6+6T and think!&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 13 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-13&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 13&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt; The integral \(\int_{-1/a}^{1/a} \big( [x]+\ln (\frac{1+x}{1-x})\big) dx\) where \(a&gt;1\) equals&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(0\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{-1}{a}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(a \ln \frac{1}{a}\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Find out the odd function!&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 14 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-14&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 14&lt;/span&gt;&lt;/div&gt;
                             For any natural number \(m\), evaluate \(\int (x^{3m}+x^{2m}+x^m)(2x^{2m}+3x^m+6)^{1/m} dx, x&gt;0\)  
                            &lt;div class=&quot;q-question-text&quot;&gt;
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{1}{6(m+1)} (2x^{3m}+3x^{2m}+6x^m)^{\frac{m-1}{m}}+c\)
                                        &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{1}{6(m-1)} (2x^{3m}+3x^{2m}+6x^m)^{\frac{m+1}{m}}+c\)
                                        &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{1}{(m+1)} (2x^{3m}+3x^{2m}+6x^m)^{\frac{m+1}{m}}+c\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{1}{6(m+1)} (2x^{3m}+3x^{2m}+6x^m)^{\frac{m+1}{m}}+c\)
                                        &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;&lt;a href=&quot;https://youtu.be/2oHnoAMKzMY?si=9lvHQjPUC3aKRuFR&quot;&gt;Click here&lt;/a&gt;&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 15 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-15&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 15&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \(f(x)= \frac{e^x}{1+e^x} \quad I_1 = \int_{f(-a)}^{f(a)}xg(x(1-x)) dx \) 
                                and \(I_2 = \int_{f(-a)}^{f(a)} g(x(1-x)) dx, \) then the value of  \(\frac{I_2}{I_1}\) is

&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(4\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(-1\) &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;&lt;a href=&quot;https://youtu.be/KYkGRt2abyc?si=vqniXmxFbtpo4P1N&quot;&gt;Click here&lt;/a&gt;&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 16 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-16&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 16&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Evaluate \(\int_{0}^{2\pi} |1+2\sin x| dx \)&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{2\pi}{3} (4+\sqrt{3})\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4\pi}{3} (2+\sqrt{3})\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{\pi}{3} (4+\sqrt{3})\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{\pi}{3} (2+\sqrt{3})\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;


                            
                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;&lt;a href=&quot;https://youtu.be/Vdj0PTjeHHY?si=aXtpXiWX7MSXUMwk&quot;&gt;Click here&lt;/a&gt;&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 17 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-17&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 17&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt; The integral \(\int \frac{2x^{12}+5x^9}{(x^5+x^3+1)^3} dx \)
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{-x^5}{(x^5+x^3+1)^{2}}+c\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{x^{10}}{2(x^5+x^3+1)^{2}}+c\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{x^5}{2(x^5+x^3+1)^{2}}+c\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{-x^{10}}{2(x^5+x^3+1)^{2}}+c\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;substitute \(\x=\frac{1}{t})&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 18 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-18&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 18&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;If \(f\) and \(g\) be continuous functions on \([0,a]\) 
                                such that \(f(x)=f(a-x)\) and \(g(x)+g(a-x)=4,\) then \(\int_{0}^{a} f(x)g(x) dx \)
                                is equal to
&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(4\int_{0}^{a} f(x)dx \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(4\int_{0}^{a} f(x)dx \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\int_{0}^{a} f(x)dx \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(-3\int_{0}^{a} f(x)dx \) &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt; Apply King&#39;s Theorem&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 19 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-19&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 19&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;The value of \(\int_{-\pi/2}^{\pi/2}\frac{x^2 \cos x}{1+e^x}dx\) is equal to
                                 
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{\pi^2}{4}-2\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{\pi^2}{4}+2\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\pi^2-e^{-\pi/2}\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\pi^2-e^{-\pi/2}\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt; Use \(\int_{a}^{b} f(x) dx = \) \(\int_{a}^{b} f(a+b-x) dx\)
                                        then add the resulting integral with the given one and then apply integration by parts
                                    &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 20 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-20&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 20&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;The value of \(\int_{\sqrt{\log 2}}^{\sqrt{\log 3} }\frac{x \sin x^2}{\sin x^2+\sin (\log 6 -x^2)}dx\) is equal to
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{4} \log \frac{3}{2}\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{2} \log \frac{3}{2}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\log \frac{3}{2}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{6} \log \frac{3}{2}\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;put \(\log 6 - x^2 = t\) and then apply \(\int_{a}^{b} f(x) dx = \int_{a}^{0b} f(a+b-x) dx\)&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 21 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-21&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 21&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;
                                The value of \(\int_{-2}^{0} (x^3+3x^2+3x+3+(x+1) \cos (x+1)) dx\) is equal to
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 0 \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 3 \) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 4 \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 1 \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Use \((x+1)^3\) to reduce the expression then substitute \(x+1=z\)&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 22 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-22&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 22&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;
                                Let \( f(x) = 7\tan^8 x + 7 \tan^6 x -3 \tan^4 x -3 \tan^2 x \), for all \(x \in \big(\frac{-\pi}{2},\frac{\pi}{2} \big)\). 
                                Then, the correct expression is 
                                &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;    \(\int_{0}^{\pi/4} x f(x) dx = \frac{1}{12}\)                                  &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;    \(\int_{0}^{\pi/4} x f(x) dx = \frac{1}{6}\)                                   &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;                  \(\int_{0}^{\pi/4} x f(x) dx = \frac{5}{12}\)              
                                &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;               \(\int_{0}^{\pi/4} x f(x) dx = \frac{3}{4}\)              &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt; Easy!&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 23 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-23&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 23&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;The value of \(\int_{0}^{1/2} \frac{1+\sqrt{3}}{((x+1)^2(1-x)^6)^{1/4}} dx\) is equal to&lt;/div&gt;


                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 2                                        \) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( \frac{1}{\sqrt{3}}
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 3                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 4                               \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;After simplifying the integrand substitute \(x= \cos \theta\)&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 24 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-24&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 24&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt; The value of \(\,(5050)\frac{\int_{0}^{1} (1 - x^{50})^{100} \, dx}{\int_{0}^{1} (1 - x^{50})^{101} \, dx}\) is  &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 5050                                      \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 5051                                   \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 1                                       \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 5500
                                        \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
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                                    &lt;p class=&quot;hint-text&quot;&gt;\(If I_n \int_{0}^{1} (1-x^{50})^n dx\)
                                        then by use of integration by parts it is easy to see thet
                                        \((1+50n)I_n=50nI_{n-1}\). Take \((1-x^{50})^n\) as the first function
                                    &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 25 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-25&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 25&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;The value of \(\int_{-2}^{2} |1-x^2| dx\) is equal to&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{3}{4}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(4\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
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                                    &lt;p class=&quot;hint-text&quot;&gt;\(\int_{-2}^{2} |1-x^2| dx=\)\(\int_{-2}^{-1} -(1-x^2) dx\)
                                        \(+\int_{-1}^{1} (1-x^2) dx\)\(+\int_{1}^{2} -(1-x^2) dx\)
                                    &lt;/p&gt;
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&lt;/script&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/9045536807292384950/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/04/integral-calculus-for-jee-main-advanced.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/9045536807292384950'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/9045536807292384950'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/04/integral-calculus-for-jee-main-advanced.html' title='Integral Calculus for JEE Main &amp; Advanced: Practice Problems'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-195886451909379002</id><published>2026-02-22T07:10:00.000-08:00</published><updated>2026-08-08T09:57:09.642-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="IIT"/><category scheme="http://www.blogger.com/atom/ns#" term="JEE Main"/><category scheme="http://www.blogger.com/atom/ns#" term="WBJEE"/><category scheme="http://www.blogger.com/atom/ns#" term="XI"/><category scheme="http://www.blogger.com/atom/ns#" term="XII"/><title type='text'>Relations and Functions Advanced Problems for JEE Mains IIT Advanced Indian Statistical Institute  and WBJEE</title><content type='html'>
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        &lt;div class=&quot;q-instructions&quot;&gt;

            &lt;h3&gt;📝 Instructions&lt;/h3&gt;

            &lt;ul&gt;

                &lt;li&gt;This quiz contains 25 multiple choice questions.&lt;/li&gt;

                &lt;li&gt;Select only one correct answer per question.&lt;/li&gt;

                &lt;li&gt;Use the navigator to jump between questions.&lt;/li&gt;

                &lt;li&gt;Submit when you are finished to see results.&lt;/li&gt;

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            &lt;div class=&quot;q-sidebar&quot;&gt;

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                    &lt;div id=&quot;questions-wrapper&quot;&gt;

                        &lt;!-- ========== QUESTION 1 ========== --&gt;
                        &lt;div class=&quot;q-card active&quot; id=&quot;question-1&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;

                                &lt;span class=&quot;q-card-title&quot;&gt;Question 1&lt;/span&gt;

                            &lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;

                                The number of reflexive relations on a set \(A\) of \(n\) elements is equal to 

                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        2^{n^2}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        n^2\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        2^{n(n-1)} \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        n^2-n\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;For the relation to be reflexive, \((a_i,a_i) \in A \times A \quad \forall a_i \in A\)
                                        So the from the remaining \(n^2 - n\) elements, any number of elements can be choosen 
                                        to form a subset of  \(A \times A\)
                                    &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 2 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-2&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 2&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \(X\) be a non-void set. If \(\rho_1\) and \(\rho_2\) be the transitive
                                relations on \(X\), then [ \( \circ\) denotes composition ]
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\rho_1 \circ \rho_2\) is transitive relation&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\rho_1 \circ \rho_2\) is not transitive relation &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\rho_1 \circ \rho_2\) is equivalence relation &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\rho_1 \circ \rho_2\) is not any relation on \(X\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Let&#39;s define a set \(X = \{1, 2, 3, 4, 5\}\). Now, let&#39;s create two relations on \(X\),
                                         \(\rho_1\) and \(\rho_2\), both of which are transitive:Let \(\rho_1 = \{(1, 2), (3, 4)\}\)
                                         Let \(\rho_2 = \{(2, 3), (4, 5)\}\) (Note: These are trivially transitive). 
                                         Now, let&#39;s find the composition \(\rho_1 \circ \rho_2\). By definition of composition,
                                          \((x, z) \in \rho_1 \circ \rho_2\) if there is some intermediate element \(y\) such
                                           that \((x, y) \in \rho_1\) and \((y, z) \in \rho_2\).
                                        So, the resulting composition is:\(\rho_1 \circ \rho_2 = \{(1, 3), (3, 5)\}\) which is clearly not transitive.&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 3 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-3&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 3&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;If one root of \(x^2 + px - q^2 = 0\), \(p\) and \(q\) are real,
                                 be less than \(2\) and other be greater than \(2\), then
&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;
                                    &lt;span class=&quot;q-option-text&quot;&gt;\( 4+2p+q^2 &gt; 0
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;
                                    &lt;span class=&quot;q-option-text&quot;&gt;\( 4+2p+q^2 \\&lt; 0
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;
                                    &lt;span class=&quot;q-option-text&quot;&gt;\( 4+2p-q^2 &gt; 0
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;
                                    &lt;span class=&quot;q-option-text&quot;&gt;\( 4+2p-q^2 \\&lt; 0
                                        \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Let \(y=x^2+px-q^2\) as \(x \rightarrow \pm \infty, y \rightarrow \infty\)
                                        thus the resulting parabola is open in the positive direction of \(y\)-axis. As \(2\), 
                                        lies between the roots, \(y\) is less than \(0\) at \(x=2\).
                                    &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 4 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-4&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 4&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;If \(R\) and \(Q\) are equivalence relations on set \(A\),
                                then which of the following is not an equivalence relation

                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(R^{-1} \cap Q^{-1}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(Q^{-1}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(R \cup Q\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(R \cap Q\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Let \( A=\{1,2,3\}, P =\{(1,1),(2,2),(3,3),(2,3),(3,2)\}\)
                                        and \(Q =\{(1,1),(2,2),(3,3),(1,2),(2,1)\}\). It is easy to see that both \(P \text{ and } Q\)
                                        are equivalence relation on \(A\) but \(P \cup Q\) is not an equivalence relation.&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 5 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-5&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 5&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \( \rho \) be a relation defined on set of natural numbers \( \mathbb{N} \), as \( \rho = \{(x, y) \in \mathbb{N} \times \mathbb{N} : 2x + y = 41\} \).
Then domain A and range B are&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( A \subset \{x \in \mathbb{N} : 1 \le x \le 20\} \) and \( B \subset \{y \in \mathbb{N} : 1 \le y \le 39\} \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( A = \{x \in \mathbb{N} : 1 \le x \le 15\} \) and \( B = \{y \in \mathbb{N} : 2 \le y \le 30\} \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( A \equiv \mathbb{N}, B \equiv \mathbb{Q} \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( A \equiv \mathbb{Q}, B \equiv \mathbb{Q} \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;See that \(y= 41 - 2x\) and for \(x \in \{1,2,...,20 \}\), \( y \in \{1,3,5,...,39\}\)&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 6 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-6&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 6&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;
                                In \(\mathbb{R}\), a relation \(\rho\) is defined as follows:
                                \(\forall a,b \in \mathbb{R}\), \(a\rho b \quad \text{holds iff} \quad a^2 -4ab+3b^2=0 \)
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\rho\) is equivalence relation&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\rho\) is only symmetric&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\rho\) is only reflexive &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\rho\) is only transitive&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;See that \(a^2-4ab+3b^2 =0 \implies a=b\) or \(a=3b\)&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 7 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-7&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 7&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \( f : \mathbb{R} \to \mathbb{R} \) be a function defined by \( f(x) = \frac{e^{|x|} - e^{-x}}{e^x + e^{-x}} \), then&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( f \) is both one-one and onto&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( f \) is one-one but not onto&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( f \) is onto but not one-one&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( f \) is neither one-one nor onto &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;\Injectivity (One-One):
For \( x &lt; 0 \), \( |x| = -x \).
$$ f(x) = \frac{e^{-x} - e^{-x}}{e^x + e^{-x}} = 0 $$
Since \( f(-1) = f(-2) = 0 \), multiple inputs yield the same output. Therefore, \( f \) is not one-one.

2. Surjectivity (Onto):
For \( x \ge 0 \), \( |x| = x \).
$$ f(x) = \frac{e^x - e^{-x}}{e^x + e^{-x}} $$
The range for \( x \ge 0 \) is \( [0, 1) \) ( use limits), the total range of \( f \) is \( [0, 1) \). 
Since the range \( [0, 1) \neq \) codomain \( \mathbb{R} \), \( f \) is not onto.
&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 8 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-8&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 8&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \( f : \mathbb{R} \to \mathbb{R} \) be a function defined by \( f(x) = 2026x^3+2024x+2023 \), then&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( f \) is both one-one and onto &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( f \) is one-one but not onto&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( f \) is onto but not one-one&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( f \) is neither one-one nor onto &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;It is easy to see that \(f\) is injective. For surjectivity,
                                        think about the nature of roots of a cubic equation. &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 9 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-9&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 9&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \(u + v + w = 3\), \(u, v, w \in \mathbb{R}\) and \(f(x) = ux^2 + vx + w\) be such that \(f(x + y) = f(x) + f(y) + xy\), 
                                \(\forall x, y \in \mathbb{R}\). Then \(v\) is equal to&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{5}{2}\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{2}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{\sqrt{2}}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Start by substituting \(f(x) = ux^2 + vx + w\) directly into the 
                                        given equation \(f(x + y) = f(x) + f(y) + xy\). Expand the left side,
                                         and then compare the coefficients of the \(xy\) terms and the constant terms on both sides. This will reveal the values of \(u\) and \(w\) first, 
                                        which you can then use with the condition \(u + v + w = 3\) to find \(v\).&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 10 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-10&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 10&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \(X\) and \(Y\) be two non-empty sets.
                                Let \(f:X \rightarrow Y\) be a function. For \(A \subset X\) and \(B \subset Y\)
                                , define \(f(A)=\{f(x):x \in A\}\) and \(f^{-1}(B)=\{x \in X : f(x) \in B \}\), then
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(f(f^{-1}(B))=B\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(f(f^{-1}(B)) \subset B\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(f^{-1}(f(A))=A\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(f^{-1}(f(A)) \subset A\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Collection of all pre-images will be mapped into \(B\). Not every element in \(Y\) has
                                        a pre-image.  Additional exercise, what will happen if the 
                                        function is surfective? 
                                    &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 11 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-11&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 11&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Range of the function \(f(x)= \frac{x^2+x+2}{x^2+x+1}\ \: x \in \mathbb{R}\)&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\((1,\infty)\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\((1, 1.5]\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\((1,\frac{7}{3}]\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\([1,\frac{7}{3}]\) &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Rewrite the function as \(f(x)=1+\frac{1}{x^2+x+1}\)&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 12 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-12&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 12&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \(X=\{v,i,n,o,d\}\) and \(Y=\{p,m\}\). The number of
                                onto ( surjective) functions from \(X\) to \(Y\) is
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(32\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(28                              \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(30\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(36\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;To find the number of onto functions,
                                         first calculate the total number of unrestricted mappings 
                                         from \(\{v, i, n, o, d\}\) to \(\{p, m\}\), which is \(2^5\). 
                                         Then, simply subtract the cases where the mapping is not
                                          onto—specifically, the exact number of scenarios where all \(5\) 
                                        elements map exclusively to just a single output in the codomain.&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 13 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-13&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 13&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Find the natural number \(a\) for which \(\sum_{k=1}^{n} f(a+k) = 16(2^n-1)\)
                                where the function \(f\) satisfies the relation \(f(x+y)=f(x)f(y)\) for all natural numbers \(x,y\) and 
                                further , \(f(1)=2\).&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(11\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(5\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(7\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Hint not yet added.&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 14 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-14&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 14&lt;/span&gt;&lt;/div&gt;
                             The domain of the definition of the function \(f(x)=\frac{1}{4-x^2} + log_{10} (x^3-x)\) is  
                            &lt;div class=&quot;q-question-text&quot;&gt;
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( (-1,0) \cup (1,2) \cup (3,\infty) \)
                                        &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( (-2,-1) \cup (-1,0) \cup (2,\infty) \)
                                        &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( (-1,0) \cup (1,2) \cup (2,\infty) \) 
                                        &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D

                                &lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( (1,2) \cup (2,\infty)\)
                                        &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Critical points of \(x^3-x\) are \(-1,0\) and \(1\)&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 15 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-15&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 15&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \(f(x)= a^x \quad (a &gt; 0) \) be written as \(f(x)=f_1(x)+f_2(x)\),
                                where \(f_1(x)\) is an even function and \(f_2(x)\) is an odd function. Then \(f_1(x+y)+f_1(x-y)\) equals

&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2f_1(x+y)f_2(x-y)\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2f_1(x+y)f_1(x-y)\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2f_1(x)f_2(x)\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2f_1(x)f_1(x)\) &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;see that \(f(x)=a^x=f_1(x)+f_2(x)\) and \(\f(-x)=a^{-x}=f_1(x)-f_2(x))&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 16 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-16&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 16&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \(g(x) = 1 + x - [x]\) and 
                                \(f(x) = \begin{cases} -1, &amp; x &lt; 0 \\ 0, &amp; x = 0 \\ 1, &amp; x &gt; 0 \end{cases}\), then for all \(x\), \(f[g(x)]\) is equal to 
&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(f(x)\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(g(x)\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Note that \(x-[x] = \{x\}\) ( fractional part of \(x\) )&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 17 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-17&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 17&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \(\mathbb{N}\) be the set of natural numbers and two
                                functions \(f\) and \(g\) defined as \(f,g:\mathbb{N} \rightarrow \mathbb{N}\)
                                such that \(f(x) = \begin{cases} \frac{n+1}{2}, &amp; \text{ if n is odd} \\ \frac{n}{2}, &amp; \text{ if n is even}  \end{cases}\)
                                and \(g(n)=n-(-1)^n\). Then \(f\circ g\) is
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;one-one but not onto&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;onto but not one-one &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;both one-one and onto&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;neither one-one nor onto&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Start by evaluating the 
                                        composite function for the first couple of natural numbers. 
                                        What exactly are the outputs for \(n = 1\) and \(n = 2\) when you calculate \((f \circ g)(n)\)?
                                        If you choose an even natural number for your initial input, say \(n = 2k\), 
                                        what does the composite function 
                                        \((f \circ g)(2k)\) ultimately simplify to?&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 18 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-18&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 18&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;If \(f\) is an even function defined on the interval \((-5, 5)\), 
                                the four real values of \(x\) satisfying the equation:
\(f(x) = f\left(\frac{x+1}{x+2}\right)\) are
&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = \frac{-1 \pm \sqrt{7}}{2} \quad \text{and} \quad x = \frac{-3 \pm \sqrt{5}}{2}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = \frac{-1 \pm \sqrt{5}}{2} \quad \text{and} \quad x = \frac{-1 \pm \sqrt{5}}{2}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = \frac{-2 \pm \sqrt{5}}{2} \quad \text{and} \quad x = \frac{-3 \pm \sqrt{5}}{2}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = \frac{-1 \pm \sqrt{5}}{2} \quad \text{and} \quad x = \frac{-3 \pm \sqrt{5}}{2}\) &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Since the function \(f\) is an even function, the condition \(f(a) = f(b)\)
                                         implies that either \(a = b\) or \(a = -b\). &lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 19 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-19&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 19&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \(f:X \rightarrow X\) be such that \(f(f(x))=x\), for all
                                \(x \in X\) and \( X \subset R \), then 
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(f\) is one-to-one&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(f\) is onto&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(f\) is one-to-one not onto &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(f\) is onto but not one-to-one&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Hint not yet added.&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 20 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-20&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 20&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \( f : R \rightarrow R \) be such that \( f \) is injective and \( f(x)f(y) = f(x+y) \) for \( \forall x, y \in R \). If \( f(x) \), \( f(y) \), 
                                \( f(z) \) are in G.P., then \( x, y, z \) are in
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;AP always and \(f(0)=1\) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;GP always and \(f(0)=0\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;AP depending on the value of \( x, y, z \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;GP depending on the value of \( x, y, z \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Hint not yet added.&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 21 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-21&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 21&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;
                                The domain of definition of \( f(x) = \sqrt{\frac{1 - |x|}{2 - |x|}} \) is
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( (-\infty, -1) \cup (2, \infty) \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( [-1, 1] \cup (2, \infty) \cup (-\infty, -2) \) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( (-\infty, 1) \cup (2, \infty) \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( [-1, 1] \cup (2, \infty) \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Hint not yet added.&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 22 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-22&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 22&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;
                                Let \( f(x) = ax^2 + bx + c \), \( g(x) = px^2 + qx + r \) such that \( f(1) = g(1) \), \( f(2) = g(2) \) and \( f(3) - g(3) = 2 \). Then \( f(4) - g(4) \) is
                                &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;4                                      &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;5                                       &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;6 &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;7                             &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Hint not yet added.&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 23 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-23&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 23&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \( R \) be the set of real numbers and the functions \( f : R \rightarrow R \) and \( g : R \rightarrow R \) be defined by \( f(x) = x^2 + 2x - 3 \) and \( g(x) = x + 1 \). Then, the value of \( x \) for which \( f(g(x)) = g(f(x)) \) is&lt;/div&gt;


                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( -1                                        \) &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 0
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 1                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 2                               \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Hint not yet added.&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 24 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-24&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 24&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;The minimum value of the function \(f(x)=2|x-1|+|x-2|\) is                   &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 0                                      \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 1                                   \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 2                                       \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;
                                    &lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 3
                                        \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                            &lt;!-- HINT SECTION --&gt;
                            &lt;div class=&quot;q-hint-wrapper&quot;&gt;
                                &lt;button class=&quot;q-btn q-hint-btn&quot; type=&quot;button&quot; onclick=&quot;toggleHint(this)&quot;&gt;Hint&lt;/button&gt;
                                &lt;div class=&quot;q-hint-content&quot; style=&quot;display: none;&quot;&gt;
                                    &lt;p class=&quot;hint-text&quot;&gt;Sketch the graph.&lt;/p&gt;
                                &lt;/div&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- ========== QUESTION 25 ========== --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-25&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 25&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let \(\mathrm{A}=\{-3,-2,-1,0,1,2,3\}\) and \(R\) be a 
                                relation on \(A\) defined by \(x R y\) if and only if \(2 x-y \in\{0,1\}\).
                                 Let \(l\) be the number of elements in \(R\). Let \(m\) and \(n\) be the minimum 
                                 number of elements required to be added to \(R\) to make it a reflexive and 
                                 symmetric relation, respectively. 
                                Then \(l+\mathrm{m}+ \mathrm{n}\) is equal to :-&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(18\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;
                                    B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(15\)&lt;/span&gt;&lt;/label&gt;

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&lt;/script&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/195886451909379002/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/02/relations-and-functions-advanced.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/195886451909379002'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/195886451909379002'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/02/relations-and-functions-advanced.html' title='Relations and Functions Advanced Problems for JEE Mains IIT Advanced Indian Statistical Institute  and WBJEE'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-6708490656016842133</id><published>2026-02-17T01:58:00.000-08:00</published><updated>2026-08-08T09:56:39.809-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="Madhyamik"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Circles for ICSE and CBSE | 25 Competency Problems</title><content type='html'>
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.q-option:hover { transform: translateX(8px); border-color: var(--primary-light); box-shadow: var(--shadow-glow); }
.q-option.selected { border-color: var(--primary-color); box-shadow: 0 0 0 4px rgba(99, 102, 241, 0.2); transform: translateX(8px); }
.q-option input { position: absolute; opacity: 0; cursor: pointer; height: 0; width: 0; }
.q-opt-marker { display: flex; align-items: center; justify-content: center; width: 40px; height: 40px; background: var(--bg-surface); border-radius: 10px; margin-right: 20px; font-weight: 700; color: var(--text-secondary); flex-shrink: 0; transition: all 0.3s ease; position: relative; z-index: 1; border: 2px solid var(--border-color); }
.q-option.selected .q-opt-marker { background: var(--primary-gradient); color: white; border-color: transparent; transform: scale(1.1); box-shadow: 0 4px 12px rgba(99, 102, 241, 0.4); }
.q-option-text { font-size: 1.15rem; color: var(--text-primary); position: relative; z-index: 1; line-height: 1.5; }

.q-actions { display: flex; justify-content: space-between; margin-top: 40px; padding-top: 25px; border-top: 1px solid var(--border-color); }
.q-btn { background: var(--bg-elevated); border: 2px solid var(--border-color); color: var(--text-primary); padding: 16px 32px; border-radius: var(--radius-sm); font-weight: 600; cursor: pointer; transition: all 0.3s cubic-bezier(0.4, 0, 0.2, 1); display: flex; align-items: center; gap: 10px; font-size: 1rem; letter-spacing: 0.5px; position: relative; overflow: hidden; }
.q-btn:hover:not(:disabled) { transform: translateY(-3px); box-shadow: var(--shadow-md); border-color: var(--primary-light); }
.q-btn-primary { background: var(--primary-gradient); color: white; border: none; box-shadow: 0 8px 20px rgba(99, 102, 241, 0.3); }
.q-btn-primary:hover:not(:disabled) { box-shadow: 0 12px 24px rgba(99, 102, 241, 0.4); transform: translateY(-3px) scale(1.02); }
.q-btn-success { background: var(--secondary-gradient); color: white; border: none; box-shadow: 0 8px 20px rgba(16, 185, 129, 0.3); }
.q-btn-success:hover:not(:disabled) { box-shadow: 0 12px 24px rgba(16, 185, 129, 0.4); transform: translateY(-3px) scale(1.02); }
.q-btn:disabled { opacity: 0.5; cursor: not-allowed; transform: none !important; box-shadow: none !important; }

.q-footer { text-align: center; margin-top: 40px; padding: 30px; border-top: 1px solid var(--border-color); color: var(--text-muted); font-size: 0.9rem; background: rgba(0, 0, 0, 0.2); backdrop-filter: blur(10px); }

/* MODAL - UPDATED RESULTS SECTION */
.q-modal-overlay { 
    position: fixed; 
    top: 0; left: 0; right: 0; bottom: 0; 
    background: rgba(10, 10, 11, 0.95); 
    display: flex; 
    justify-content: center; 
    align-items: center; 
    z-index: 10000; 
    padding: 20px; 
    backdrop-filter: blur(10px); 
    animation: fadeIn 0.4s ease; 
}
@keyframes fadeIn { from { opacity: 0; } to { opacity: 1; } }
/* main background score card */
.q-modal { 
    background: rgb(20, 16, 19);
    width: 100%; 
    max-width: 800px; 
    max-height: 90vh; 
    overflow-y: auto; 
    border-radius: var(--radius-lg); 
    padding: 50px; 
    box-shadow: var(--shadow-lg); 
    border: 1px solid rgba(99, 102, 241, 0.2); 
    animation: modalSlideIn 0.5s cubic-bezier(0.4, 0, 0.2, 1); 
}
@keyframes modalSlideIn { 
    from { opacity: 0; transform: translateY(40px) scale(0.95); } 
    to { opacity: 1; transform: translateY(0) scale(1); } 
}

.q-result-header { 
    text-align: center; 
    margin-bottom: 40px; 
}
.q-result-header h2 { 
    font-size: 2.8rem; 
    background: linear-gradient(135deg, #00dc82 0%, #36d1dc 100%);
    -webkit-background-clip: text; 
    background-clip: text; 
    color: transparent; 
    margin-bottom: 15px; 
    font-weight: 900;
    letter-spacing: -0.5px;
}
.q-result-header p { 
    color: whitesmoke;
    font-size: 1.1rem; 
    max-width: 500px;
    margin: 0 auto;
    line-height: 1.6;
}

/* MODERN SCORE CARDS */
.q-score-grid { 
    display: grid; 
    grid-template-columns: repeat(3, 1fr); 
    gap: 20px; 
    margin-bottom: 40px; 
}
.q-score-card { 
    background: linear-gradient(145deg, rgba(30, 41, 59, 0.9), rgba(15, 23, 42, 0.9));
    padding: 30px 25px; 
    border-radius: var(--radius-lg); 
    text-align: center; 
    border: 1px solid rgba(255, 255, 255, 0.1);
    transition: all 0.4s cubic-bezier(0.4, 0, 0.2, 1);
    position: relative;
    overflow: hidden;
}
.q-score-card::before {
    content: &#39;&#39;;
    position: absolute;
    top: 0;
    left: 0;
    right: 0;
    height: 4px;
    background: var(--primary-gradient);
    opacity: 0;
    transition: opacity 0.3s ease;
}
.q-score-card:hover { 
    transform: translateY(-8px) scale(1.02); 
    box-shadow: 0 20px 40px rgba(0, 0, 0, 0.4); 
    border-color: rgba(214, 215, 238, 0.3);
}
.q-score-card:hover::before {
    opacity: 1;
}

/* Specific card gradients */
.q-score-card:nth-child(1) { border-top: 4px solid #bbbcf3; }
.q-score-card:nth-child(2) { border-top: 4px solid #10b981; }
.q-score-card:nth-child(3) { border-top: 4px solid #f59e0b; }

.q-score-val { 
    font-size: 3.5rem; 
    font-weight: 900; 
    background: linear-gradient(135deg, #f1ecf0 0%, #f3dfe1 100%);
    -webkit-background-clip: text; 
    background-clip: text; 
    color: transparent; 
    line-height: 1; 
    margin-bottom: 10px; 
    text-shadow: 0 2px 4px rgba(0, 0, 0, 0.2);
}
.q-score-lbl { 
    font-size: 1rem; 
    color: whitesmoke; 
    text-transform: uppercase; 
    letter-spacing: 1.5px; 
    font-weight: 600; 
    display: flex;
    align-items: center;
    justify-content: center;
    gap: 8px;
}

/* RESULTS LIST - ENHANCED VISIBILITY */
.q-ans-list { 
    list-style: none; 
    padding: 0; 
    margin-bottom: 40px; 
}
.q-ans-item { 
    padding: 20px 25px; 
    margin-bottom: 15px; 
    border-radius: var(--radius-md); 
    font-size: 1rem; 
    background: rgba(228, 231, 238, 0.8);
    border-left: 5px solid var(--border-color);
    display: flex; 
    justify-content: space-between; 
    align-items: center; 
    transition: all 0.3s ease;
    border: 1px solid rgba(255, 255, 255, 0.05);
}
.q-ans-item:hover { 
    transform: translateX(5px); 
    box-shadow: 0 8px 20px rgba(0, 0, 0, 0.3);
}

/* CORRECT - Vibrant Green */
.q-ans-item.correct { 
    border-left-color: #00ff88;
    background: linear-gradient(135deg, 
        rgba(0, 255, 136, 0.1) 0%, 
        rgba(0, 200, 120, 0.05) 100%);
    border-color: rgba(0, 255, 136, 0.2);
}
.q-ans-item.correct::before {
    content: &#39;\2714&#39;;
    color: #00ff88;
    font-weight: bold;
    margin-right: 10px;
    font-size: 1.2rem;
}

/* INCORRECT - Vibrant Red */
.q-ans-item.incorrect { 
    border-left-color: #ff4757;
    background: linear-gradient(135deg, 
        rgba(255, 71, 87, 0.1) 0%, 
        rgba(220, 50, 65, 0.05) 100%);
    border-color: rgba(255, 71, 87, 0.2);
}
.q-ans-item.incorrect::before {
    content: &#39;\2717&#39;;
    color: #ff4757;
    font-weight: bold;
    margin-right: 10px;
    font-size: 1.2rem;
}

/* UNANSWERED - Bright Amber */
.q-ans-item.unanswered { 
    border-left-color: #ffb142;
    background: linear-gradient(135deg, 
        rgba(255, 177, 66, 0.1) 0%, 
        rgba(220, 150, 50, 0.05) 100%);
    border-color: rgba(255, 177, 66, 0.2);
}
.q-ans-item.unanswered::before {
    content: &#39;\003F&#39;;
    color: #ffb142;
    font-weight: bold;
    margin-right: 10px;
    font-size: 1.2rem;
}

/* Answer item content */
.q-ans-item .question-info {
    display: flex;
    align-items: center;
    gap: 12px;
    font-weight: 600;
    color: whitesmoke;
}

.q-ans-item .answer-info {
    font-size: 0.9rem;
    color: var(--text-secondary);
    background: rgba(0, 0, 0, 0.3);
    padding: 6px 12px;
    border-radius: 20px;
    border: 1px solid rgba(255, 255, 255, 0.1);
}

/* Modal Actions */
.q-modal-actions {
    display: flex;
    gap: 15px;
    justify-content: center;
    margin-top: 30px;
}

.q-modal-actions .q-btn {
    min-width: 150px;
}

/* RESPONSIVE */
@media (max-width: 1024px) {
    .q-layout { flex-direction: column; }
    .q-sidebar { width: 100%; order: -1; }
    .q-nav-grid { grid-template-columns: repeat(8, 1fr); }
}
@media (max-width: 768px) {
    .quiz-wrapper-modern { padding: 0; border-radius: 0; }
    .q-header { padding: 30px 20px; border-radius: 0; }
    .q-logo { font-size: 2.2rem; }
    .q-dashboard { grid-template-columns: 1fr; margin: 0 20px 20px; text-align: center; }
    .q-stats-row { justify-content: center; flex-wrap: wrap; }
    .q-stat-card { min-width: 80px; padding: 12px 20px; }
    .q-layout { margin: 0 20px 30px; }
    .q-card { padding: 25px; }
    .q-question-text { font-size: 1.2rem; }
    .q-score-grid { 
        grid-template-columns: 1fr; 
        gap: 15px; 
    }
    .q-modal { 
        padding: 30px 20px; 
        max-width: 95%;
    }
    .q-result-header h2 {
        font-size: 2.2rem;
    }
    .q-score-val {
        font-size: 2.8rem;
    }
    .q-actions { 
        flex-direction: column; 
        gap: 15px; 
    }
    .q-btn { 
        width: 100%; 
        justify-content: center; 
    }
    .q-ans-item {
        flex-direction: column;
        align-items: flex-start;
        gap: 10px;
    }
    .q-ans-item .answer-info {
        align-self: flex-end;
    }
    .q-modal-actions {
        flex-direction: column;
    }
    .q-modal-actions .q-btn {
        width: 100%;
    }
}
@media (max-width: 480px) {
    .q-nav-grid { grid-template-columns: repeat(5, 1fr); }
    .q-author-info { flex-direction: column; align-items: center; }
    .q-option { padding: 15px 20px; }
    .q-option-text { font-size: 1rem; }
    .q-result-header h2 { font-size: 1.8rem; }
    .q-score-val { font-size: 2.2rem; }
}

/* MATHJAX OVERRIDES */
.MathJax { color: #60a5fa !important; }
.MathJax_Display { 
    padding: 15px !important; 
    background: rgba(30, 41, 59, 0.8) !important; 
    border-radius: var(--radius-sm) !important; 
    border: 1px solid rgba(99, 102, 241, 0.2) !important; 
    overflow-x: auto !important; 
    margin: 20px 0 !important;
}
&lt;/style&gt;
&lt;div class=&quot;quiz-wrapper-modern&quot;&gt;
    &lt;div class=&quot;q-container&quot;&gt;
        &lt;header class=&quot;q-header&quot;&gt;
            &lt;div class=&quot;q-logo&quot;&gt;&lt;span&gt;Prime Maths&lt;/span&gt;&lt;/div&gt;
            &lt;div class=&quot;q-subtitle&quot;&gt;Chapter Test Circles for CBSE, ICSE | Class X&lt;/div&gt;
            &lt;div class=&quot;q-author-info&quot;&gt;
                &lt;div class=&quot;q-author-item&quot;&gt;👨‍🏫 Author: Singh&lt;/div&gt;
                &lt;div class=&quot;q-author-item&quot;&gt;📞 WA: +91-9038126497&lt;/div&gt;
                &lt;div class=&quot;q-author-item&quot;&gt;&lt;a href=&quot;https://facebook.com/prime.maths&quot; target=&quot;_blank&quot;&gt;Prime Maths&lt;/a&gt;&lt;/div&gt;
            &lt;/div&gt;
        &lt;/header&gt;

        &lt;div class=&quot;q-dashboard&quot;&gt;
            &lt;div class=&quot;q-dashboard-text&quot;&gt;
                &lt;h2&gt;Geometry - Circles&lt;/h2&gt;
                &lt;p&gt;This quiz provides a thorough evaluation of key concepts and advanced skills in Circle Geometry, tailored for both CBSE and ICSE curriculums. It covers all core theorems and properties, including:

Angle properties (Angle at the centre, Angles in the same segment).

Cyclic Quadrilateral properties.
Intersecting chord Theorem.

Tangent-Secant theorems (Alternate Segment Theorem, Tangent-Radius properties).

Perfect for exam preparation, this practice test is designed to challenge your understanding and refine your problem-solving techniques. &lt;strong&gt; CIRCLES | CBSE | ICSE &lt;/strong&gt;. 25 multiple-choice questions designed to test both theoretical understanding and practical application.&lt;/p&gt;
            &lt;/div&gt;
            &lt;div class=&quot;q-stats-row&quot;&gt;
                &lt;div class=&quot;q-stat-card&quot;&gt;
                    &lt;div class=&quot;q-stat-val&quot; id=&quot;answered-count&quot;&gt;0&lt;/div&gt;
                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Done&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;q-stat-card&quot;&gt;
                    &lt;div class=&quot;q-stat-val&quot; id=&quot;remaining-count&quot;&gt;25&lt;/div&gt;
                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Left&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;q-stat-card&quot;&gt;
                    &lt;div class=&quot;q-stat-val&quot; id=&quot;score-preview&quot;&gt;0%&lt;/div&gt;
                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Score&lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
        &lt;/div&gt;

        &lt;div class=&quot;q-instructions&quot;&gt;
            &lt;h3&gt;📝 Instructions&lt;/h3&gt;
            &lt;ul&gt;
                &lt;li&gt;This quiz contains 25 multiple choice questions.&lt;/li&gt;
                &lt;li&gt;Select only one correct answer per question.&lt;/li&gt;
                &lt;li&gt;Use the navigator to jump between questions.&lt;/li&gt;
                &lt;li&gt;Submit when you are finished to see results.&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/div&gt;

        &lt;div class=&quot;q-layout&quot;&gt;
            &lt;div class=&quot;q-sidebar&quot;&gt;
                &lt;div style=&quot;color: var(--text-primary); font-weight: 600; margin-bottom: 15px; text-align: center;&quot;&gt;Question Navigator&lt;/div&gt;
                &lt;div class=&quot;q-nav-grid&quot; id=&quot;question-nav&quot;&gt;&lt;/div&gt;
                &lt;div class=&quot;q-progress-wrap&quot;&gt;
                    &lt;div class=&quot;q-prog-info&quot;&gt;
                        &lt;span&gt;Progress&lt;/span&gt;
                        &lt;span id=&quot;progress-percentage&quot;&gt;0%&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;q-prog-track&quot;&gt;
                        &lt;div class=&quot;q-prog-fill&quot; id=&quot;progress-fill&quot;&gt;&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;q-content-area&quot;&gt;
                &lt;form id=&quot;quizForm&quot;&gt;
                    &lt;div id=&quot;questions-wrapper&quot;&gt;
                        &lt;div class=&quot;q-card active&quot; id=&quot;question-1&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 1&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;From a point \(P\), two tangents \(PA\) and \(PB\) are drawn to a circle with centre at \(O\) and radius \(r\). If \(OP=2r\), then \(\triangle APB\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;an isosceles triangle&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;a right angle triangle&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;an equilateral triangle&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;a scalene triangle&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-2&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 2&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the given figure, \(AB\) is a chord of length \(16\) cm of a circle of radius \(10\) cm. The tangents at \(A\) and \(B\) interesct at point \(P\). The length of \(PA\) is:
                                &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;600&quot; height =&quot;390&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg7a6RAu9Zxxa3yDezYn-qMcsObKqdghW5xDMo19sUlArzivHRmaH_L6b-ETYo2g3kAX1sR_c46b6fzZiKhaOVDtTNivAtIr9a_bhKmboPyyWaL3xOhnM5bIT1SOHKKkgU14amqlX5-CziCXrtPuhp-XX11QNdlk-ZeD5jW_2Zh0gF-3JhfTbHieoaKhK0/s1536/Q2.png&quot;  /&gt;
&lt;/p&gt;
                            &lt;/div&gt;
                            
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{37}{7} \quad cm\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{37}{3} \quad cm\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{40}{7} \quad cm\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{40}{3} \quad cm\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-3&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 3&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The angle subtended by a tangent \(MN\) at the centre \(O\) of a circle, intercepted between two parallel tangets \(AM\) and \(BN\) of the same circle is:
                            &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;600&quot; height =&quot;390&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgBLN82jmEShwIjZl9oJRp50w71jyEMM06eNmD4yz_XDsKI933H3UYMcxT-HLszaQTQNgnMAaR2N1Er0SGBAimIPO3aOtM5QAo4uRIIMB64t2ZqKWvSW29ejdKNf5S6UxNGSOE_Dlh-dq1io4LWHO_wEge9qpKG9N00L1SnRok6xw5BnFgtNU9f4rlsiKU/s1536/Q3.png&quot;  /&gt;    
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(75^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(60^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(45^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(90^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-4&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 4&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the figure \(AB\) is a common tangent of two circles intersecting at \(C\) and \(D\). The value of \(\angle ACB+ \angle ADB\) is:
                                &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;600&quot; height =&quot;460&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjq-gV77dZiGAq-DvWMVxy7NUqrOXjMqDDMHsHXdXF-nUBDHwuNXoiM9Tj5chHwYWZH8xxCGhGFk88DUXaxZX2O8tvL2IpS68GGl_4TAJMCq2Ho2NlE3A9NOP_6cB2S9ppWahJSeFffTLsmitaogiKEhV8kbcEwS0I7FKHIUL3Nxdj8jUvazi5iC72TYvA/s572/Q4.png&quot;  /&gt;
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(180^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(220^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(160^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(280^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-5&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 5&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the given figure  \(O\) is the centre of the circle. \(AB\) and \(AC\) are tangents 
drawn to the circle from point \(A\). If  \(\angle BAC = 65^{\circ}\), then the measure of \(\angle BOC \) is:
&lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;600&quot; height =&quot;400&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgIF1vYcovH2irOt74zFC1Qv5wkkzHdIPdzsqAkF1rugfOWkNTUExMKO4Edk8VnKoc4hnTKtHcPN6qMW3yr9ujQWxSW8zkMvsGRu0boHzZdOp63sMrmCqQOvvLMXr7cEPPBKnsnYYBCbavHonNB9JBQNUwKsqxELJ76Vl7f1vjPYg1KvnlcXs-hSrd5wpQ/s414/Q5.png&quot;  /&gt;
&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(100^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(135^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(135^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(115^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-6&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 6&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;\(AB\) is the diameter of the circle with centre \(O\). From a point \(P\) on the
                                circle a perpendicular \(PN\) is drawn on \(AB\). Which of the following is true?
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(PB^2 = AN.BN\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(PB^2 = AB.BN\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(PN^2 = AB.BN\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(PN^2 = AB.AP\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-7&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 7&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;From an external point \(P\) of a circle with centre \(O\), two tangents \(PS\) and \(PT\)
                                are drawn. \(QS\) is a chord of the circle parallel to \(PT\). If \( \angle SPT = 80^{\circ}\), then the value of
                                \(\angle QST \) is
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(55^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(45^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(50^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(60^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-8&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 8&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the figure given below, \(PA\) is a tangent to the circle
                                with centre \(O\) and \(PCB\) is a straight line. The measure on \(\angle OBC \) is 
                                &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;600&quot; height =&quot;600&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhJ9nES3eJJ_9S1wIKvv1bhcvjpHN_Mf-t9nZDRNOH3SVTfCU2XWppx-obe2z5fYQ_B-lFOVHStdxqaqJON2lLdLg8JvDyn3eazj9GkfgZP8U-KxofzlnMeaoz-hfLG05askhsEQyoBxEtaRM2lKXvi8A6zBvR0h1ytu-Bz71FdlyYiJphBgLxpsca-Zac/s1024/Q8.png&quot;  /&gt;
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(20^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(30^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(40^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(35^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-9&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 9&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the figure given below, a circle with centre \(O\) inscribed inside 
                                triangle \(LMN\). \(A\) and \(B\) are the points of tangency. The measure on \(\angle ANB \) is
                                &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;600&quot; height =&quot;600&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh2hNGifEn3UrrIIHWY9_m4YABAyCIgBXoo5b1bbrZ5A5WisXSHmEXj_9gGjP062w-fbXNTxscQhZ4yDatn20VcYBO3chFYcd1Ms5RxBtfpjubBiDefehqTA3fHABMB4F2iGYa6XWqGBxrL8fF5_OgVtihmk0fjXo03XuFmASe7FIBjhuvB2aCw_I5dND8/s1024/Q9.png&quot;  /&gt;
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(70^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(80^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(60^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(50^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-10&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 10&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the diagram given below, \(\angle EDC = 90^{\circ}\). The tangent drawn
                                to the circle at \(C\) makes an angle of \(50^{\circ}\) with \(AB\) produced.The measure on \(\angle ACB \) is
                                &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;600&quot; height =&quot;800&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhKeTtPT1x7Yu-nRJAiwG5YRr6aMqJV6Q0_9ySPX8XTkOQcQPDEbDFTHLT6cP__NqWD568IbKAX6qQhjhvrILWE5LCnWfaAag0F6nmYeu5uXu4oAHbHFhQH4_zcitt81smbR7SPZ5uoiTPxrStCI4Chg1f7cnfxJx4r-w3z7g2Dksz5YbHzXfs-UdQI33Y/s1536/Q10.png&quot;  /&gt;
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(60^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(50^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(30^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(40^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-11&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 11&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the figure given below, \(CD\) is the diameter of the circle 
                                which meets the chord \(AB\) at \(P\) such that \(AP = BP = 12 \quad cm\). If \(DP = 8\) cm, find the radius
                                of the circle is 
                                &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;500&quot; height =&quot;500&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgdr4xhnPDzrmf02zLmGlm4eSCocKUjRI8E9FJo1H4t4WkiXXd3k5V1BhoKRHMQYjgZJCm742c99A-XjFgXtuhZAprXQZpKkA27sx-2JBEXan_luF4V1LSJXEXKe4wlrzdMc4VyvM9Ax0kVAIvV1pgJRwmhYUuq_6BIm5eWcInNIxRZdwIROpCmI_68nJQ/s604/Q11_enhanced.png&quot;  /&gt;
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(17 \) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(11\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(7\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(13\) cm&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-12&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 12&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;\(ABCD\) is a cyclic quadrilateral. If \(AD=AB\), \(\angle DAC = 60^{\circ}\), \(\angle BDC=50^{\circ}\) then the measure of \(\angle ACD\) is&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(25^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(20^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(35^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(45^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-13&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 13&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the figure given below, two circles touch each other at point \(A\). \(PQ\) 
                            is a direct common tangent, the point of contacts being \(P\) and \(Q\) respectively. The measure of 
                            \(\angle PAQ\) is
                            &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;700&quot; height =&quot;500&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhQh_iL29FqEtnhdt0Mf3qjLGbYT4x2L2uBGHh2PnGoeI9FDl55V7nyHjCEvZQYaXXvxuj34TB5ivf5ejC3aK4xxkBisYs67IyJGxY5DUsan1qWXMYEEMQ4HdEgJag-RL4ka5BiNNSJjOmkBFlj4iuPBXhOTzAqhJs2Ys4YYgBNfqDf4SyjrNNLBLhHHOI/s1280/Q13.jpg&quot;  /&gt;
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(90^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(45^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(120^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Cannot be determined&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-14&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 14&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the diagram given below, \(O\) is centre of circle. The tangent \(PT\)
                                meets the diameter \(RQ\) produced at \(P\). If \(PT = 6\) cm, \(QR = 9 \) cm, the length
                                of \(PQ\) is    
                                ( Hint \(\triangle PQT \sim \triangle PTR\))
                                &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;750&quot; height =&quot;500&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj1fhIrSIlkHUQib1lz5Djlc21wLCj2_IJHDUjZQXZHEFrER4GeVHl76aSupuvytb4mUJr3GM1rXGJh1bpHKU3OFIKq7M-diJZSosZhyphenhyphenHPSU6GHxG8UFmD8Bm-NQoHVYLcxsO1BJEq6dGe7f04JLM5jrgXGpssio5lJ4i-WrX_u7LDFWKa1CUvr7dLAA-M/s1536/Q14.png&quot;  /&gt;
                                
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1.5\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3.5 \) cm&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-15&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 15&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the given figure AC is the diameter of the circle with centre \(O\). \(CD\) 
                                is parallel to \(BE\). If \(\angle AOB = 80^{\circ}\) and \(\angle ACE = 20^{\circ}\), the sum of the 
                            angles \(\angle BEC\), \(\angle BCD\) and \(\angle CED\) is 
                            &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;400&quot; height =&quot;400&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiSF0HO2oBaMhXmygVxvIx-DZhX6-xdbHfj2nqTcfMaaSZT5pO2F34RdEpteQpJ9yteRKv7P6i4eONxDVzqEa_w5zAAH5dJmt8VNpxXnGxrre6maFhyphenhyphenOEY2Otan2gt-2pnKlD9ofXN8ETCTa-giTSAI7WBwOqxEPzx67b3l98t-ePIQWV77rPQs0inle1o/s365/Q15.png&quot;  /&gt;
                            
                        &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(280^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(160^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(120^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(180^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-16&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 16&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the given figure, \(O\) is the centre of the circle and \(AB\) 
                                is a tangent to the circle at \(B\).If \(\angle PQB =55^{\circ}\), sum of \(x,y\) and \(z\) is
                                &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;600&quot; height =&quot;500&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgRwb6Wsj7xnarwekmqn_k8Ae97B76pAubdPRb3L3mO5grPP2njo4rfxS1VQAFO-5bfOyIFMEYnCEdjXyKaORm8yRTIXzXJJO1WrV7WUjxJrYPH_lNQJP_RVOgmjkTBWLGMEEW-beLH2z0cA5awxsmpHUzpAMkt7BKVCVS8PRfUY5sNhDYg18qXKR2zPyM/s497/Q16.png&quot;  /&gt;
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(160^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(140^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(180^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(120^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-17&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 17&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the figure given below, \(O\) is the centre of the circle and \(SP\) 
                                is a tangent.If \(\angle SRT = 65^{\circ}\), find the sum of \(x, y\) and \(z\).
                                &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;750&quot; height =&quot;450&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjQbuPlSWXol7LRPctUUGe2EqPtTCOLr7mj83nKDQVxzl4L1L5JrWwiVGf7BsE6FQRvV8wiSM0ekA9l3hlKZnLuSX2Y_C_OGJwFhcfrwyoOwRRNc0A2GtGfZizZ-a9Lrx6h7vzpOqL5LaJm5W3XWosCvBxcACOiMhP8Sy4qtZDgQKwHTmjndsS8-pd5u6A/s436/Q17.png&quot;  /&gt;
                            &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(120^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(115^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(135^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(150^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-18&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 18&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The radii of two circles with center at \(A\) and \(B\) are \(11\) cm
                            and \(6\) cm respectively. If \(PQ\) is the common tangent of the circles and \(AB = 13\) cm, length of PQ is&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;13 cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;12 cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;17 cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;8.5 cm&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-19&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 19&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Suppose \(Q\) is a point on the circle with centre \(P\) and
                            radius \(1\), as shown in the figure; \(R\) is a point outside thr circle such that \(QR = 1\) 
                            and \(\angle QRP = 2^{\circ}\). Let \(S\) be the point where the segment \(RP\) intersects the given circle.
                            Then measure of \(\angle RQS\) equals.
                            &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;600&quot; height =&quot;500&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjDObNA6y6caKvEQOPFS58xBzhsv7521DS-ZgZLoBlYDG5cgJxM4vUmQkl0GrypcTYHfTl-8XMhwKDKMkjj90xBiVSP-8KY3g946Wzd51PdVtXUQY0JMz3fAW3qrYi3vhG8Q5hp1X54YctVpagCHYYiugLp2vL5Wc9n95LzoTmRxYYpgoo95wt533seMEE/s1250/Q19.png&quot;  /&gt;
                        &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(86^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(87^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(88^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(89^{\circ}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-20&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 20&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The chords \(PQ\) and \(RS\) of a circle are extended to meet at the
                            point \(Q\). If \(PQ = 6\) cm, \(OQ = 8\) cm, \(OS = 7\) cm, then length of \(RS\)&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(12\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(9\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(10\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(16\) cm&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-21&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 21&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;\(ABC\) is a triangle in which \(AB = 4\) cm, \(BC = 5\) cm and
                            \(AC = 6\) cm. A circle is drawn to touch side \(BC\) at \(P\), side \(AB\) extended at \(Q\) and side \(AC\) extended at \(R\).
                            Then, \(AQ\) equals:
                            &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;400&quot; height =&quot;350&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhFUTa1X6kosuTh37oMk-yoJ8Lo2_xQiA2RNTLAOTg0x6qKpCkdRO2i_ZXG4Mui-BnfI_yGLzh4rdmb8m9gRWtIcyTIVvimhqN2lwHMZt9QlWhqbd9U1nIsA_Jja1AC5kVLCpTmM-P02cAl88FuisQ6BbDNvvyvXuuyo1sWTBISKXxTM8brKLZFLTeqm88/s230/Q21.png&quot;  /&gt;
                        &lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(7\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(7.5\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(6.5\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(15\) cm&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-22&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 22&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;A line from one vertex \(A\) of an equilateral \(\triangle ABC\) meets the
                            opposite side \(BC\) in \(P\) and the circumcircle of \(\triangle ABC\) in \(Q\).If \(BQ = 4\) cm and \(CQ = 3\) cm, 
                            then \(PQ\) is equal to&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(7 \) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4}{3}\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{12}{7}\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2 \) cm&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-23&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 23&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the figure, \(AB, AC\) and \(BC\) are three tangents touching
                            the circle at \(D\), \(E\) and \(F\) respectively. If \(AC = 24\) cm, \(BC = 18\) cm and \( \angle ACB = 90^{\circ}\),the radius of the circle is
                            &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;400&quot; height =&quot;350&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgg4I3lFAb-VAlLTbvi0V0h1DnrrIosDvovCOoRic7E8Oe2C93MhLH7fkYjlgpOkKE0yRCZkJmcyNi13TB7yP-yZuTokwvyZxf_xNvEwzYLIn8CtNgT01-vuRrnSprT8xyjsa8RqnOHskJIDkuPRtuhsNCJFfI4Ca7qCs9AyoEvu6wOVcPortVjqKk8-I4/s224/Q23.png&quot;/&gt;
                            
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                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(4\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(5\) cm&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(6\) cm&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
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                        &lt;div class=&quot;q-card&quot; id=&quot;question-24&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 24&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;In the figure, \(ST\) is a tangents to the smaller circle, \(ABC\)
                            is a straight line. If \(\angle TAD = 2x\) and \(\angle DPC = 3x\), find \(x\)
                            &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;400&quot; height =&quot;350&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiRt0CY0dshyjqs-wPi3JYyFp-bUyt6ppgBkD4kKWq3gzGloR5FQ31l-6BvSSbIIAe1tEfOYDdPqHZuG7qy6J3xZ3Q452ximqcyHnWEm9a3ZmaQwpDWFnZgGS8IFwZorljHW3WjWczu-e_LjjWRNNjz-Ra0hcI8GXzpeJpRywIlDek6ymqRc9jofC1d8eQ/s424/Q24.png&quot;/&gt;
                            
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                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(40^{\circ}\)&lt;/span&gt;&lt;/label&gt;
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                            &lt;div class=&quot;q-question-text&quot;&gt;In the adjoining figure, \(ABC\) is a triangle in which,
                            \(\angle B = 90^{\circ}\) and its incircle \(C_1\) has radius \(3\) units. A circle \(C_2\)
                            of radius \(1\) unit touches sides \(AC\), \(BC\) and the circle \(C_1\).
                             Then length \(AB\) is equal to
                             &lt;p&gt;&lt;img alt=&quot;Description&quot; float=&quot;middle&quot; width=&quot;800&quot; height =&quot;550&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh4j7HBsTbDv6cOz5pibEfxLTRYHXLFhYcBGCItwptP-DXKBkut-_wMaN8qlqxH7F0bVB2h2DjEB_YVYVm7AaFWgBEVAnRZtMfkA1hzLD11cK_riNMobQxvYoPK0k8efHC-l1CK_HaOleYnGfhEumf7M5oJ970FRU1ghKK52NjqixsZjHwKC1EdZ9cZwYw/s1536/Q25.png&quot;/&gt;
                                    
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                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3+6\sqrt{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(10+3\sqrt{2}\)&lt;/span&gt;&lt;/label&gt;
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&lt;div id=&quot;wbchse-quiz-wrapper&quot;&gt;
    &lt;div class=&quot;quiz-container&quot;&gt;
        &lt;div class=&quot;test-header&quot;&gt;
            &lt;h1&gt;📐 Prime Maths · Practice Problem Sheet &lt;span&gt;XI&lt;/span&gt;&lt;/h1&gt;
            &lt;p &quot;text-align: left;&quot;&gt;&lt;strong&gt;Class XI · Vinod Singh &lt;/strong&gt; — CBSE, ISC, HS, JEE Mains &amp; WBJEE.&lt;br&gt;One question at a time, with persistent answers. This practice set covers all essential chapters to help you test your preparation level and speed. Includes questions on Sets, Relations and Functions , Trigonometric Functions , Complex Numbers , Linear Inequalities , Permutations &amp; Combinations , Coordinate Geometry, and Limits &amp; Derivatives. This Class 11 Maths exercise is perfect for students of CBSE, ISC, WBCHSE and other State Boards looking for high-quality practice material to score better in their upcoming board and entrance exams.&lt;/p&gt;
            &lt;div class=&quot;exam-badge&quot;&gt;
                &lt;small&gt;📚 CBSE&lt;/small&gt;&lt;small&gt;📘 ISC&lt;/small&gt;&lt;small&gt;🏫 HS&lt;/small&gt;&lt;small&gt;⚡ JEE Mains&lt;/small&gt;&lt;small&gt;🧠 WBJEE&lt;/small&gt;
            &lt;/div&gt;
        &lt;/div&gt;

        &lt;div id=&quot;questionContainer&quot;&gt;&lt;/div&gt;

        &lt;div class=&quot;nav-controls&quot;&gt;
            &lt;button class=&quot;nav-btn&quot; id=&quot;prevBtn&quot; disabled&gt;← Previous&lt;/button&gt;
            &lt;span class=&quot;q-counter&quot; id=&quot;qCounter&quot;&gt;1 / 40&lt;/span&gt;
            &lt;button class=&quot;nav-btn&quot; id=&quot;nextBtn&quot;&gt;Next →&lt;/button&gt;
        &lt;/div&gt;

        &lt;div class=&quot;action-bar&quot;&gt;
            &lt;button class=&quot;sec-btn&quot; id=&quot;clearAllBtn&quot;&gt;⟲ Clear all&lt;/button&gt;
            &lt;button class=&quot;sec-btn&quot; id=&quot;rerenderMathBtn&quot;&gt;🔁 Refresh Math&lt;/button&gt;
        &lt;/div&gt;

        &lt;div class=&quot;footer-note&quot;&gt;
            ✅ Click &lt;strong&gt;Check&lt;/strong&gt; to verify your answer.&lt;br&gt;
            📌 Answer key (Q1→Q40): c,c,a,b,d,a,d,b,c,c,c,d,d,a,d,b,d,b,a,c,b,c,c,a,b,c,c,d,c,b,a,b,b,b,a,d,c,d,c,a
        &lt;/div&gt;
    &lt;/div&gt;
&lt;/div&gt;

&lt;script&gt;
(function() {
    // ------------------------------------------------------------
    // QUESTION DATA
    // ------------------------------------------------------------
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        { text: &quot;If for any two sets \\(A\\) and \\(B\\), \\(n(A\\cup B)=n(A)-n(B)\\) then&quot;, options: [&quot;\\(B\\subseteq A\\)&quot;, &quot;\\(B=A\\)&quot;, &quot;\\(B=\\emptyset\\)&quot;, &quot;none of these&quot;], correct: &quot;c&quot; },
        { text: &quot;For any three sets \\(A, B, C\\)&quot;, options: [&quot;\\(A\\cup B=A\\cup C\\Rightarrow B=C\\)&quot;, &quot;\\(A\\cap B=\\emptyset\\Rightarrow A=\\emptyset\\) or \\(B=\\emptyset\\)&quot;, &quot;\\(A\\cup B=A\\cap B\\Rightarrow B=A\\)&quot;, &quot;none of these&quot;], correct: &quot;c&quot; },
        { text: &quot;For any two sets \\(A\\) and \\(B\\), \\((A\\cup B)^{\\prime}\\cup(A^{\\prime}\\cap B)\\) is equal to&quot;, options: [&quot;\\(A^{\\prime}\\)&quot;, &quot;\\(B^{\\prime}\\)&quot;, &quot;\\(\\emptyset\\)&quot;, &quot;\\(A^{\\prime}\\cup B^{\\prime}\\)&quot;], correct: &quot;a&quot; },
        { text: &quot;If \\(X=\\{\\}\\) and \\(P(X)\\) represent its power set, then \\(P(P(X))\\) is&quot;, options: [&quot;\\(X\\)&quot;, &quot;\\(\\{X,\\{X\\}\\}\\)&quot;, &quot;\\(\\{\\{\\}\\}\\)&quot;, &quot;\\(\\{X,\\{X,\\{\\}\\}\\}\\)&quot;], correct: &quot;b&quot; },
        { text: &quot;If \\(X=\\{p,q,r,s\\}\\) then the number of subsets of \\(X\\times X\\) is&quot;, options: [&quot;\\(2^{16}-2\\)&quot;, &quot;8&quot;, &quot;\\(2^{16}-1\\)&quot;, &quot;\\(2^{16}\\)&quot;], correct: &quot;d&quot; },
        { text: &quot;The domain of the function \\(f\\) given by \\(f(x)=\\frac{x^{2}+2x+1}{x^{2}-x-6}\\) is&quot;, options: [&quot;\\(\\mathbb{R}-\\{3,-2\\}\\)&quot;, &quot;\\(\\mathbb{R}-\\{-3,2\\}\\)&quot;, &quot;\\(\\mathbb{R}-[3,-2]\\)&quot;, &quot;\\(\\{1,-1\\}\\)&quot;], correct: &quot;a&quot; },
        { text: &quot;The range of the function \\(f\\) given by \\(f(x)=\\frac{|x|}{x}, x\\ne 0\\) is&quot;, options: [&quot;\\(\\mathbb{R}\\)&quot;, &quot;\\(\\mathbb{R}-\\{1,-1\\}\\)&quot;, &quot;\\(\\{1,-1,0\\}\\)&quot;, &quot;\\(\\{1,-1\\}\\)&quot;], correct: &quot;d&quot; },
        { text: &quot;The range of the relation \\(R\\) defined by \\(R=\\{(x,x+1):x\\in\\{0,1,2,3,4,5\\}\\}\\) is&quot;, options: [&quot;\\(\\{0,1,2,3,4,5\\}\\)&quot;, &quot;\\(\\{1,2,3,4,5,6\\}\\)&quot;, &quot;\\(\\{1,2,3,4,5\\}\\)&quot;, &quot;\\(\\{1,2,3,4\\}\\)&quot;], correct: &quot;b&quot; },
        { text: &quot;If for any real value of \\(\\theta\\), \\(a=\\cos^{2}\\theta+\\sin^{4}\\theta\\), then&quot;, options: [&quot;\\(-1\\le a\\le1\\)&quot;, &quot;\\(-\\frac{1}{8}\\le a\\le\\frac{1}{8}\\)&quot;, &quot;\\(\\frac{3}{4}\\le a\\le1\\)&quot;, &quot;none of these&quot;], correct: &quot;c&quot; },
        { text: &quot;The numerical value of \\(2\\tan\\frac{\\pi}{10}+3\\sec\\frac{\\pi}{10}-4\\cos\\frac{\\pi}{10}\\) is equal to&quot;, options: [&quot;\\(\\sqrt{5}\\)&quot;, &quot;1&quot;, &quot;0&quot;, &quot;\\(-1\\)&quot;], correct: &quot;c&quot; },
        { text: &quot;If \\(\\tan\\theta=\\frac{\\sin\\alpha-\\cos\\alpha}{\\sin\\alpha+\\cos\\alpha}\\) then \\(\\sin\\alpha+\\cos\\alpha=k\\cos\\theta\\), where \\(k\\) is&quot;, options: [&quot;\\(\\sqrt{2}\\)&quot;, &quot;\\(-\\sqrt{2}\\)&quot;, &quot;\\(\\pm\\sqrt{2}\\)&quot;, &quot;\\(\\pm1\\)&quot;], correct: &quot;c&quot; },
        { text: &quot;The numerical value of \\(\\tan 3^{\\circ}+\\tan 42^{\\circ}+\\tan 3^{\\circ}\\tan 42^{\\circ}\\) is equal to&quot;, options: [&quot;0&quot;, &quot;\\(\\frac{1}{2}\\)&quot;, &quot;\\(\\frac{3}{2}\\)&quot;, &quot;1&quot;], correct: &quot;d&quot; },
        { text: &quot;The numerical value of \\(\\frac{1}{2\\sin 10^{\\circ}}-2\\sin 70^{\\circ}\\) is equal to&quot;, options: [&quot;0&quot;, &quot;\\(\\frac{1}{2}\\)&quot;, &quot;1&quot;, &quot;\\(\\frac{3}{2}\\)&quot;], correct: &quot;d&quot; },
        { text: &quot;The number of real values of \\(x\\) for which \\(\\sin(e^{x})=7^{x}+7^{-x}\\) is&quot;, options: [&quot;0&quot;, &quot;1&quot;, &quot;2&quot;, &quot;infinitely many&quot;], correct: &quot;a&quot; },
        { text: &quot;For any real \\(x\\), \\(\\frac{\\sin 2x \\cos x}{(1+\\cos 2x)(1+\\cos x)}\\) is equal to&quot;, options: [&quot;\\(\\sin x\\)&quot;, &quot;\\(\\sin\\frac{x}{2}\\)&quot;, &quot;\\(\\cos\\frac{x}{2}\\)&quot;, &quot;\\(\\tan\\frac{x}{2}\\)&quot;], correct: &quot;d&quot; },
        { text: &quot;The quadratic equation with rational coefficients whose one root is \\(\\frac{2+\\sqrt{3}}{2-\\sqrt{3}},\\) is&quot;, options: [&quot;\\(x^{2}+14x+1=0\\)&quot;, &quot;\\(x^{2}-14x+1=0\\)&quot;, &quot;\\(x^{2}-14x-1=0\\)&quot;, &quot;\\(x^{2}+14x=0\\)&quot;], correct: &quot;b&quot; },
        { text: &quot;The number of real solutions of the equation \\(x^{2}-3|x|+2=0\\) is&quot;, options: [&quot;0&quot;, &quot;2&quot;, &quot;3&quot;, &quot;4&quot;], correct: &quot;d&quot; },
        { text: &quot;The roots of the equation \\(x^{2}-2ix+3=0\\) (where \\(i^{2}=-1\\)) are&quot;, options: [&quot;imaginary conjugate numbers&quot;, &quot;imaginary but not conjugate&quot;, &quot;reciprocal of each other&quot;, &quot;none of these&quot;], correct: &quot;b&quot; },
        { text: &quot;If \\(a^{2}+b^{2}=1\\), then \\(\\frac{1+a+ib}{1+a-ib}\\) is equal to&quot;, options: [&quot;\\(a+ib\\)&quot;, &quot;\\(a-ib\\)&quot;, &quot;\\(b+ia\\)&quot;, &quot;\\(b-ia\\)&quot;], correct: &quot;a&quot; },
        { text: &quot;The principal argument of \\(-100i\\) is&quot;, options: [&quot;\\(-\\frac{\\pi}{2}\\)&quot;, &quot;\\(\\frac{\\pi}{2}\\)&quot;, &quot;\\(\\pi\\)&quot;, &quot;\\(-\\frac{\\pi}{4}\\)&quot;], correct: &quot;c&quot; },
        { text: &quot;The solution of the equation \\(|z|-z=1+2i\\) is&quot;, options: [&quot;\\(2-1.5i\\)&quot;, &quot;\\(1.5-2i\\)&quot;, &quot;\\(1.5+2i\\)&quot;, &quot;\\(-2+1.5i\\)&quot;], correct: &quot;b&quot; },
        { text: &quot;The length of a rectangle is three times the breadth. If the minimum perimeter of the rectangle is 160 cm, then&quot;, options: [&quot;breadth \\(&gt; 20\\) cm&quot;, &quot;length \\(&lt; 20\\) cm&quot;, &quot;breadth \\(\\ge 20\\) cm&quot;, &quot;length \\(\\le 20\\) cm&quot;], correct: &quot;c&quot; },
        { text: &quot;If \\(|x+3|\\ge10\\) then&quot;, options: [&quot;\\(x\\in(-13,7]\\)&quot;, &quot;\\(x\\in(-13,7)\\)&quot;, &quot;\\(x\\in(-\\infty,-13]\\cup[7,\\infty)\\)&quot;, &quot;\\(x\\in[-13,7]\\)&quot;], correct: &quot;c&quot; },
        { text: &quot;If \\(x\\) and \\(a\\) are real numbers such that \\(-a\\le x\\le a,\\) then&quot;, options: [&quot;\\(|x|\\le a\\)&quot;, &quot;\\(|a|\\le x\\)&quot;, &quot;\\(|x|\\ge a\\)&quot;, &quot;\\(|x|&lt;a\\)&quot;], correct: &quot;a&quot; },
        { text: &quot;If \\(x\\) is real, minimum value of \\(|x+3|+4\\) is&quot;, options: [&quot;3&quot;, &quot;4&quot;, &quot;7&quot;, &quot;0&quot;], correct: &quot;b&quot; },
        { text: &quot;If \\({}^{16}C_{r}={}^{16}C_{r+2},\\) then \\({}^{r}C_{4}\\) is equal to&quot;, options: [&quot;21&quot;, &quot;27&quot;, &quot;35&quot;, &quot;39&quot;], correct: &quot;c&quot; },
        { text: &quot;If \\((n+2)!=2550\\times n!\\) then the value of \\(n\\) is&quot;, options: [&quot;47&quot;, &quot;48&quot;, &quot;49&quot;, &quot;50&quot;], correct: &quot;c&quot; },
        { text: &quot;A man has 6 friends. The number of ways in which he can invite one or more of them to his house is&quot;, options: [&quot;\\(6!\\)&quot;, &quot;\\(6!-1\\)&quot;, &quot;\\(2^6!\\)&quot;, &quot;none of these&quot;], correct: &quot;d&quot; },
        { text: &quot;The number of parallelograms that can be formed from a set of 4 parallel lines intersecting another set of 3 parallel lines is&quot;, options: [&quot;21&quot;, &quot;20&quot;, &quot;18&quot;, &quot;16&quot;], correct: &quot;c&quot; },
        { text: &quot;A five digit number divisible by 3 is to be formed by using the digits 0,1,2,3,4 and 5 without repetition. The total number of such numbers is&quot;, options: [&quot;126&quot;, &quot;216&quot;, &quot;621&quot;, &quot;261&quot;], correct: &quot;b&quot; },
        { text: &quot;If \\(f(x)\\) and \\(g(x)\\) are polynomials such that \\(f(a)=8\\) and \\(g(a)=3,\\) then \\(\\lim_{x\\rightarrow a}\\frac{f(x)}{g(x)+1}=\\)&quot;, options: [&quot;2&quot;, &quot;4&quot;, &quot;3&quot;, &quot;8&quot;], correct: &quot;a&quot; },
        { text: &quot;\\(\\lim_{x\\rightarrow1}\\frac{x^{n}-1}{x-1}=\\)&quot;, options: [&quot;0&quot;, &quot;\\(n\\)&quot;, &quot;1&quot;, &quot;does not exist&quot;], correct: &quot;b&quot; },
        { text: &quot;\\(\\lim_{x\\rightarrow0}\\frac{\\tan 2x-x}{3x-\\sin x}=\\)&quot;, options: [&quot;\\(\\frac{1}{100}\\)&quot;, &quot;\\(\\frac{1}{2}\\)&quot;, &quot;\\(-\\frac{1}{2}\\)&quot;, &quot;\\(\\frac{1}{4}\\)&quot;], correct: &quot;b&quot; },
        { text: &quot;If \\(f(x)=1+x+\\frac{x^{2}}{2}+\\cdot\\cdot\\cdot+\\frac{x^{100}}{100},\\) then \\(f^{\\prime}(1)\\) is equal to&quot;, options: [&quot;1&quot;, &quot;100&quot;, &quot;-100&quot;, &quot;0&quot;], correct: &quot;b&quot; },
        { text: &quot;If \\(y=\\frac{1+\\frac{1}{x^{2}}}{1-\\frac{1}{x^{2}}},\\) then \\(\\frac{dy}{dx}\\) is&quot;, options: [&quot;\\(-\\frac{4x}{(x^{2}-1)^{2}}\\)&quot;, &quot;\\(-\\frac{4x}{x^{2}-1}\\)&quot;, &quot;\\(\\frac{1-x^{2}}{4x}\\)&quot;, &quot;\\(\\frac{4x}{1-x^{2}}\\)&quot;], correct: &quot;a&quot; },
        { text: &quot;If \\(f(x)=|x-10|\\) then \\(f(x)\\) is&quot;, options: [&quot;differentiable at all points&quot;, &quot;not differentiable at any points&quot;, &quot;differentiable at \\(x=10\\)&quot;, &quot;not differentiable at \\(x=10\\)&quot;], correct: &quot;d&quot; },
        { text: &quot;Slope of the curve \\(y=e^{x}+1\\) at \\(x=0\\) is&quot;, options: [&quot;-1&quot;, &quot;0&quot;, &quot;1&quot;, &quot;2&quot;], correct: &quot;c&quot; },
        { text: &quot;If \\(f(2)=-8,\\) \\(f^{\\prime}(2)=3\\), \\(g(2)=17\\) and \\(g^{\\prime}(2)=-4\\), the value of \\((fg)^{\\prime}(2)\\) is&quot;, options: [&quot;16&quot;, &quot;54&quot;, &quot;79&quot;, &quot;83&quot;], correct: &quot;d&quot; },
        { text: &quot;If \\(f(x)=\\ln e^{x}+\\sin 2x\\), then \\(f^{\\prime}(\\frac{\\pi}{4})\\) is equal to&quot;, options: [&quot;1&quot;, &quot;0&quot;, &quot;1&quot;, &quot;2&quot;], correct: &quot;c&quot; },
        { text: &quot;If \\(f(x)=\\frac{x+1}{[x-1]},\\) then \\(\\lim_{x\\rightarrow3^{+}}f(x)\\) is equal to (\\([x]\\) is the floor function)&quot;, options: [&quot;2&quot;, &quot;0&quot;, &quot;3&quot;, &quot;\\(\\frac{3}{2}\\)&quot;], correct: &quot;a&quot; }
    ];

    // ---------- state ----------
    let currentIndex = 0;                       
    const totalQ = questions.length;
    let selectedAnswers = new Array(totalQ).fill(null);
    let feedbackMessages = new Array(totalQ).fill(null);

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    const prevBtn = document.getElementById(&#39;prevBtn&#39;);
    const nextBtn = document.getElementById(&#39;nextBtn&#39;);
    const qCounter = document.getElementById(&#39;qCounter&#39;);

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        const q = questions[currentIndex];
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            const letter = String.fromCharCode(97 + idx); // a,b,c,d
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                &lt;div class=&quot;q-num&quot;&gt;Question ${currentIndex+1} / ${totalQ}&lt;/div&gt;
                &lt;div class=&quot;q-text&quot;&gt;${q.text}&lt;/div&gt;
                &lt;div class=&quot;options&quot; id=&quot;optionsContainer&quot;&gt;
                    ${optionsHtml}
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                &lt;div class=&quot;card-footer&quot;&gt;
                    &lt;button class=&quot;check-btn&quot; id=&quot;checkCurrentBtn&quot;&gt;✓ Check&lt;/button&gt;
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        // Attach check button event
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                if (r.checked) { selected = r.value; break; }
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            const fbSpan = container.querySelector(&#39;.feedback&#39;);
            
            if (!selected) {
                fbSpan.className = &#39;feedback wrong&#39;;
                fbSpan.innerText = &#39;⚠️ choose an option&#39;;
                feedbackMessages[currentIndex] = { text: &#39;⚠️ choose an option&#39;, className: &#39;wrong&#39; };
                return;
            }
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            selectedAnswers[currentIndex] = selected;
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                fbSpan.className = &#39;feedback correct&#39;;
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            } else {
                fbSpan.className = &#39;feedback wrong&#39;;
                fbSpan.innerText = `❌ Wrong (correct: ${correct.toUpperCase()})`;
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&lt;div id=&quot;prime-maths-wrapper&quot;&gt;
&lt;div class=&quot;quiz-container&quot;&gt;
    &lt;h2&gt;🔢 Madhyamik 2026 Board Question Paper - Mathematics&lt;/h2&gt;
    &lt;div class=&quot;subhead&quot;&gt;Prime Maths · Vinod Singh 9038126497&lt;/div&gt;
    &lt;hr&gt;

    &lt;h3&gt;📌 1. Choose the correct option in each case from the following questions:  [ 1 x 6 = 6 ]&lt;/h3&gt;

    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;Q1(i).&lt;/strong&gt; If a principal becomes double in 10 years, the rate of simple interest per annum is:&lt;/p&gt;
        &lt;ol class=&quot;options&quot;&gt;&lt;li&gt;5%&lt;/li&gt;&lt;li&gt;10%&lt;/li&gt;&lt;li&gt;15%&lt;/li&gt;&lt;li&gt;20%&lt;/li&gt;&lt;/ol&gt;
        &lt;details&gt;
            &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
            &lt;div class=&quot;solution-text&quot;&gt;
                &lt;strong&gt;Step 1 – define variables:&lt;/strong&gt; Let principal \(P\). Amount after 10 years \(A = 2P\).&lt;br&gt;
                &lt;strong&gt;Step 2 – interest earned:&lt;/strong&gt; \(SI = A - P = 2P - P = P\).&lt;br&gt;
                &lt;strong&gt;Step 3 – apply simple interest formula:&lt;/strong&gt; \(SI = \dfrac{P \times R \times T}{100}\) with \(T = 10\).&lt;br&gt;
                \[ P = \frac{P \times R \times 10}{100} \]&lt;br&gt;
                &lt;strong&gt;Step 4 – cancel \(P\) (since \(P \neq 0\)):&lt;/strong&gt; \(1 = \dfrac{R \times 10}{100}\)&lt;br&gt;
                &lt;strong&gt;Step 5 – solve for \(R\):&lt;/strong&gt; \(1 = \dfrac{R}{10} \implies R = 10\%\).&lt;br&gt;
                &lt;span class=&quot;correct-answer&quot;&gt;✅ correct option: (b) 10%&lt;/span&gt;
            &lt;/div&gt;
        &lt;/details&gt;
    &lt;/div&gt;

    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;Q1(ii).&lt;/strong&gt; Condition of two roots of \(ax^2+bx+c=0\;(a&gt;0)\) equal in magnitude but opposite in sign:&lt;/p&gt;
        &lt;ol class=&quot;options&quot;&gt;&lt;li&gt;\(b=0,c=0\)&lt;/li&gt;&lt;li&gt;\(b=0,c&gt;0\)&lt;/li&gt;&lt;li&gt;\(b=0,c&lt;0\)&lt;/li&gt;&lt;li&gt;\(b&gt;0,c=0\)&lt;/li&gt;&lt;/ol&gt;
        &lt;details&gt;
            &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
            &lt;div class=&quot;solution-text&quot;&gt;
                &lt;strong&gt;Step 1 – let the roots be \(\alpha\) and \(-\alpha\).&lt;/strong&gt;&lt;br&gt;
                &lt;strong&gt;Step 2 – sum of roots:&lt;/strong&gt; \(\alpha + (-\alpha) = 0 = -\dfrac{b}{a} \implies b = 0\) (since \(a\neq0\)).&lt;br&gt;
                &lt;strong&gt;Step 3 – product of roots:&lt;/strong&gt; \(\alpha \cdot (-\alpha) = -\alpha^2 = \dfrac{c}{a}\).&lt;br&gt;
                &lt;strong&gt;Step 4 – sign analysis:&lt;/strong&gt; \(\alpha^2 &gt; 0\) (real roots), so \(-\alpha^2 &lt; 0\). Hence \(\dfrac{c}{a} &lt; 0\).&lt;br&gt;
                &lt;strong&gt;Step 5 – given \(a&gt;0\), therefore \(c &lt; 0\).&lt;/strong&gt;&lt;br&gt;
                &lt;span class=&quot;correct-answer&quot;&gt;✅ correct option: (c) \(b=0,\;c&lt;0\)&lt;/span&gt;
            &lt;/div&gt;
        &lt;/details&gt;
    &lt;/div&gt;

    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;Q1(iii).&lt;/strong&gt; If average of \(6,7,x,y,16\) is \(9\). Then:&lt;/p&gt;
        &lt;ol class=&quot;options&quot;&gt;&lt;li&gt;\(x+y=21\)&lt;/li&gt;&lt;li&gt;\(x+y=16\)&lt;/li&gt;&lt;li&gt;\(x-y=21\)&lt;/li&gt;&lt;li&gt;\(x-y=19\)&lt;/li&gt;&lt;/ol&gt;
        &lt;details&gt;
            &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
            &lt;div class=&quot;solution-text&quot;&gt;
                &lt;strong&gt;Step 1 – average formula:&lt;/strong&gt; \(\dfrac{6+7+x+y+16}{5} = 9\).&lt;br&gt;
                &lt;strong&gt;Step 2 – sum of known numbers:&lt;/strong&gt; \(6+7+16 = 29\). So \(\dfrac{29+x+y}{5} = 9\).&lt;br&gt;
                &lt;strong&gt;Step 3 – multiply by 5:&lt;/strong&gt; \(29+x+y = 45\).&lt;br&gt;
                &lt;strong&gt;Step 4 – solve:&lt;/strong&gt; \(x+y = 45-29 = 16\).&lt;br&gt;
                &lt;span class=&quot;correct-answer&quot;&gt;✅ correct option: (b) \(x+y=16\)&lt;/span&gt;
            &lt;/div&gt;
        &lt;/details&gt;
    &lt;/div&gt;

    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;Q1(iv).&lt;/strong&gt; Arc of length \(121\) cm of a circle makes \(77^\circ\) angle at the centre of the circle, then the radius of the circle will be. Radius = ?&lt;/p&gt;
        &lt;ol class=&quot;options&quot;&gt;&lt;li&gt;110 cm&lt;/li&gt;&lt;li&gt;100 cm&lt;/li&gt;&lt;li&gt;90 cm&lt;/li&gt;&lt;li&gt;70 cm&lt;/li&gt;&lt;/ol&gt;
        &lt;details&gt;
            &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
            &lt;div class=&quot;solution-text&quot;&gt;
                &lt;strong&gt;Step 1 – arc length formula:&lt;/strong&gt; \(L = 2\pi r \times \dfrac{\theta}{360^\circ}\). Use \(\pi = \dfrac{22}{7}\).&lt;br&gt;
                &lt;strong&gt;Step 2 – substitute:&lt;/strong&gt; \(121 = 2 \cdot \dfrac{22}{7} \cdot r \cdot \dfrac{77}{360}\).&lt;br&gt;
                &lt;strong&gt;Step 3 – simplify inside:&lt;/strong&gt; \(2\cdot\dfrac{22}{7} = \dfrac{44}{7}\). Then \(\dfrac{44}{7} \times \dfrac{77}{360} = \dfrac{44 \times 77}{7 \times 360}\).&lt;br&gt;
                &lt;strong&gt;Step 4 – cancel 77 with 7:&lt;/strong&gt; \(\dfrac{77}{7} = 11\), so expression becomes \(\dfrac{44 \times 11}{360} = \dfrac{484}{360}\).&lt;br&gt;
                &lt;strong&gt;Step 5 – equation:&lt;/strong&gt; \(121 = r \cdot \dfrac{484}{360}\).&lt;br&gt;
                &lt;strong&gt;Step 6 – solve for \(r\):&lt;/strong&gt; \(r = \dfrac{121 \times 360}{484}\). Note \(484 = 4 \times 121\). Thus \(r = \dfrac{360}{4} = 90\) cm.&lt;br&gt;
                &lt;span class=&quot;correct-answer&quot;&gt;✅ correct option: (c) 90 cm&lt;/span&gt;
            &lt;/div&gt;
        &lt;/details&gt;
    &lt;/div&gt;

    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;Q1(v).&lt;/strong&gt; Length of a side of a cube be \(&#39;a&#39;\) unit and length of the diagonal be \(&#39;d&#39;\) unit then the relation of a and d will be:&lt;/p&gt;
        &lt;ol class=&quot;options&quot;&gt;&lt;li&gt;\(\sqrt{2}a = d\)&lt;/li&gt;&lt;li&gt;\(\sqrt{3}a = d\)&lt;/li&gt;&lt;li&gt;\(a = \sqrt{3}d\)&lt;/li&gt;&lt;li&gt;\(a = \sqrt{2}d\)&lt;/li&gt;&lt;/ol&gt;
        &lt;details&gt;
            &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
            &lt;div class=&quot;solution-text&quot;&gt;
                &lt;strong&gt;Step 1 – space diagonal of a cube:&lt;/strong&gt; \(d = \sqrt{a^2 + a^2 + a^2}\).&lt;br&gt;
                &lt;strong&gt;Step 2 – simplify:&lt;/strong&gt; \(d = \sqrt{3a^2} = a\sqrt{3}\).&lt;br&gt;
                &lt;strong&gt;Step 3 – rewrite:&lt;/strong&gt; \(\sqrt{3}\,a = d\).&lt;br&gt;
                &lt;span class=&quot;correct-answer&quot;&gt;✅ correct option: (b) \(\sqrt{3}a = d\)&lt;/span&gt;
            &lt;/div&gt;
        &lt;/details&gt;
    &lt;/div&gt;

    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;Q1(vi).&lt;/strong&gt; \(ABCD\) be a cyclic quadrilateral whose centre is \(O\). \(BC\) is extended upto \(E\). If \(\angle DCE = 96°\) then the value of \(\angle BOD\) will be:&lt;/p&gt;
        &lt;ol class=&quot;options&quot;&gt;&lt;li&gt;42°&lt;/li&gt;&lt;li&gt;84°&lt;/li&gt;&lt;li&gt;142°&lt;/li&gt;&lt;li&gt;168°&lt;/li&gt;&lt;/ol&gt;
        &lt;details&gt;
            &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
            &lt;div class=&quot;solution-text&quot;&gt;
                &lt;strong&gt;Step 1 – linear pair:&lt;/strong&gt; \(\angle BCD + \angle DCE = 180^\circ\) (straight line BCE). So \(\angle BCD = 180^\circ - 96^\circ = 84^\circ\).&lt;br&gt;
                &lt;strong&gt;Step 2 – central angle theorem:&lt;/strong&gt; Angle at centre (\(\angle BOD\)) is twice the angle at circumference subtended by the same arc BAD. Here \(\angle BCD\) subtends arc BAD.&lt;br&gt;
                &lt;strong&gt;Step 3 – calculate:&lt;/strong&gt; \(\angle BOD = 2 \times \angle BCD = 2 \times 84^\circ = 168^\circ\).&lt;br&gt;
                &lt;span class=&quot;correct-answer&quot;&gt;✅ correct option: (d) 168°&lt;/span&gt;
            &lt;/div&gt;
        &lt;/details&gt;
    &lt;/div&gt;

    &lt;h3&gt;📝 2. Fill in the blanks (any five)     [ 1 x 5 = 5]&lt;/h3&gt;
    &lt;hr&gt;

    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; If the ratio of principal and yearly amount be 8:9, then yearly rate of interest is _________.&lt;/p&gt;
        &lt;details&gt;&lt;summary&gt;🔍 detailed solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
            Let \(P = 8k\), \(A = 9k\). Interest for 1 year \(= A-P = k\). Simple interest formula: \(k = \dfrac{8k \times R \times 1}{100}\). Cancel \(k\): \(1 = \dfrac{8R}{100} \Rightarrow R = \dfrac{100}{8} = 12.5\%\). &lt;br&gt;\(\Rightarrow\) \(12\frac{1}{2}\%\).
        &lt;/div&gt;&lt;/details&gt;
    &lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; Conjugate surd of \(\sqrt{3} - 5\) is ______.&lt;/p&gt;
        &lt;details&gt;&lt;summary&gt;🔍 detailed solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
            Write as \(-5 + \sqrt{3}\). Conjugate: change sign of the irrational part \(\rightarrow -5 - \sqrt{3}\).
        &lt;/div&gt;&lt;/details&gt;
    &lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;(iii)&lt;/strong&gt; Two tangents at the end point of a diameter of a circle are mutually _________.&lt;/p&gt;
        &lt;details&gt;&lt;summary&gt;🔍 detailed solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
            Parallel (radius ⟂ tangent, both radii are collinear, so tangents are perpendicular to the same line → parallel).
        &lt;/div&gt;&lt;/details&gt;
    &lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;(iv)&lt;/strong&gt; If \(x = a\sec\theta,\; y = b\cot\theta\), then \(\dfrac{x^2}{a^2} - \dfrac{b^2}{y^2} =\) ______.&lt;/p&gt;
        &lt;details&gt;&lt;summary&gt;🔍 detailed solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
            \(\dfrac{x}{a} = \sec\theta,\; \dfrac{y}{b} = \cot\theta \Rightarrow \dfrac{b}{y} = \tan\theta\). Then \(\dfrac{x^2}{a^2} - \dfrac{b^2}{y^2} = \sec^2\theta - \tan^2\theta = 1\).
        &lt;/div&gt;&lt;/details&gt;
    &lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;(v)&lt;/strong&gt; The radius of a solid hemisphere is \(3r\) unit, the area of total surface is _________.&lt;/p&gt;
        &lt;details&gt;&lt;summary&gt;🔍 detailed solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
            TSA of hemisphere (solid) = \(3\pi R^2\). Here \(R = 3r\) → \(3\pi (3r)^2 = 3\pi \cdot 9r^2 = 27\pi r^2\) sq units.
        &lt;/div&gt;&lt;/details&gt;
    &lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;
        &lt;p&gt;&lt;strong&gt;(vi)&lt;/strong&gt; The frequency of \(1, 2, 3, 4, 5\) are respectively \(1, 2, 3, 4, f\) and their arithmetic mean is \(4\) then value of \(f\) is _________.&lt;/p&gt;
        &lt;details&gt;&lt;summary&gt;🔍 detailed solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
            \(\sum fx = 1\cdot1 + 2\cdot2 + 3\cdot3 + 4\cdot4 + 5f = 1+4+9+16+5f = 30+5f\).&lt;br&gt;
            \(\sum f = 1+2+3+4+f = 10+f\). Mean = \(\frac{30+5f}{10+f} = 4\).&lt;br&gt;
            Cross multiply: \(30+5f = 40+4f \Rightarrow f = 10\).
        &lt;/div&gt;&lt;/details&gt;
    &lt;/div&gt;

    &lt;h3&gt;🔎 3. True or False (any five)     [ 1 x 5 = 5 ]&lt;/h3&gt;
    &lt;hr&gt;

    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;(i) \(\sin^2\theta = (\sin\theta)^2\) for \(0° \theta&lt;90°\).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;explanation&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;&lt;strong&gt;True&lt;/strong&gt; – conventional notation: \(\sin^2\theta\) means \((\sin\theta)^2\).&lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;(ii) The length of a side of a largest cube be \(4\sqrt{2}\) cm inscribed in a sphere of radius 4 cm.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;explanation&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;&lt;strong&gt;False&lt;/strong&gt;. Sphere diameter = 8 cm = space diagonal of cube \(\Rightarrow \sqrt{3}\,a = 8 \Rightarrow a = 8/\sqrt{3} \approx 4.618\) cm. \(4\sqrt{2}\approx5.657\) cm (that would be face diagonal).&lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;(iii) The angle in the segment of a circle which is greater than semicircle is an obtuse angle.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;explanation&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;&lt;strong&gt;False&lt;/strong&gt;. Major segment ( &gt; semicircle) contains an acute angle; obtuse angle lies in minor segment.&lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;(iv) If the Arithmetic mean of \(x-3, x-1, 7, x, 2x-1, 3x-5\) be \(7.5\), then their median will be \(3\).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;explanation&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Sum = \((x-3)+(x-1)+7+x+(2x-1)+(3x-5) = 8x -3\). Mean = \(\frac{8x-3}{6}=7.5 \Rightarrow 8x-3=45 \Rightarrow x=6\).&lt;br&gt;
        Data: 3,5,7,6,11,13 → sorted 3,5,6,7,11,13 → median = \(\frac{6+7}{2}=6.5 \neq 3\). &lt;strong&gt;False&lt;/strong&gt;.
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;(v) If \(x \propto 1/y\) then \((xy)^{10}\) is a constant.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;explanation&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;&lt;strong&gt;True&lt;/strong&gt;. \(xy = k\) (constant) ⇒ \((xy)^{10}=k^{10}\) constant.&lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;(vi) In a business, the ratio of capital of Raju and Asif is \(5:4\). If Raju got Rs. 80 of total profit then Asif got Rs. 100.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;explanation&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;&lt;strong&gt;False&lt;/strong&gt;. Profit ratio = capital ratio = 5:4. So Asif = \(\frac{4}{5}\times 80 = 64\).&lt;/div&gt;&lt;/details&gt;&lt;/div&gt;

    &lt;h3&gt;✍️ 4. Answer any ten (2 marks each)   [ 2 x 10 = 20]&lt;/h3&gt;
    &lt;hr&gt;

    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; A and B started a business by investing Rs. 15,000 and Rs. 45,000 respectively. After 6 months B got a profit of Rs. 3,030, what is the profit of A?&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Capital ratio A:B = 15000:45000 = 1:3. Profits shared in same ratio (no time adjustment as period same).&lt;br&gt;
        Let A&#39;s profit = \(x\), then B&#39;s profit = \(3x\). Given \(3x = 3030 \Rightarrow x = 1010\). So A gets ₹1010.
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; In \(\triangle ABC\), line parallel to BC intersects AB, AC at P, Q. AP=4 cm, QC=9 cm, PB=AQ. Find PB.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        By Basic Proportionality Theorem: \(\dfrac{AP}{PB} = \dfrac{AQ}{QC}\). Set \(PB = AQ = x\). Then \(\dfrac{4}{x} = \dfrac{x}{9} \Rightarrow x^2 = 36 \Rightarrow x = 6\) (positive). PB = 6 cm.
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(iii)&lt;/strong&gt; Two Chords AB and CD are equidistant from centre O. If &amp;angle;AOB = 60° and CD = 6 cm, find radius.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Equidistant chords ⇒ equal lengths: AB = CD = 6 cm. In ΔAOB, OA=OB (radii), ∠AOB=60° ⇒ triangle is equilateral (isosceles with vertex 60° ⇒ base angles each 60°). Hence radius = OA = AB = 6 cm.
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(iv)&lt;/strong&gt; If \(\tanθ + \cotθ = 2\) then find \(\tan^7θ + \cot^7θ\).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        \(\tanθ + \frac{1}{\tanθ}=2\). Multiply by \(\tanθ\): \(\tan^2θ + 1 = 2\tanθ \Rightarrow \tan^2θ -2\tanθ +1=0 \Rightarrow (\tanθ-1)^2=0 \Rightarrow \tanθ=1\). So \(\cotθ=1\). Then \(\tan^7θ+\cot^7θ = 1+1 = 2\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(v)&lt;/strong&gt;  If \(x\) and \(y\) are positive real numbers then \(\sec \theta = \frac{x}{y}\) is correct or not? Give reason.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        No. For real θ between \(0^{\circ}\) and \(90^{\circ}\), \(0 \leq \cos \theta \leq 1\). As  \(\sec \theta = \frac{x}{y}\) which means 
        \(\cos \theta = \frac{y}{x}\) and for \(y &gt; x \), \( \cos \theta &gt; 1 \) which is not possible.
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(vi)&lt;/strong&gt; For two right circular cylinders, if ratio of their heights be \(1:2\) and ratio of the circumference of the base be \(3:4\) then find the ratio of their volume.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Let \(h_1:h_2 = 1:2\). Circumference \(2πr_1 : 2πr_2 = 3:4 \Rightarrow r_1:r_2 = 3:4\). Volume = \(πr^2h\). Ratio = \(\left(\frac{r_1}{r_2}\right)^2 \times \frac{h_1}{h_2} = \left(\frac{3}{4}\right)^2 \times \frac{1}{2} = \frac{9}{16}\times\frac12 = \frac{9}{32}\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(vii)&lt;/strong&gt; Arithmetic mean of \(x_1,x_2,......,x_n\) is \(\bar x\). Prove that \(\sum (x_i-\bar{x})^2 = \sum x_i^2 - n\bar{x}^2 \).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise proof&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        \(\sum (x_i-\bar{x})^2 = \sum (x_i^2 - 2x_i\bar{x} + \bar{x}^2) = \sum x_i^2 - 2\bar{x}\sum x_i + \sum \bar{x}^2\).&lt;br&gt;
        Now \(\sum x_i = n\bar{x}\) and \(\sum \bar{x}^2 = n\bar{x}^2\). Hence expression = \(\sum x_i^2 - 2\bar{x}(n\bar{x}) + n\bar{x}^2 = \sum x_i^2 - 2n\bar{x}^2 + n\bar{x}^2 = \sum x_i^2 - n\bar{x}^2\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(viii)&lt;/strong&gt;If the rate of interest increases from 5.5% to 6% then the yearly interest increases by ₹49.50. Find the capital.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Increase in rate = \(0.5\%\). This increase applies to the whole capital: \(0.5\% \times \text{capital} = 49.50\). So \(\frac{0.5}{100} \times C = 49.50 \Rightarrow C = 49.50 \times \frac{100}{0.5} = 49.50 \times 200 = 9900\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(ix)&lt;/strong&gt;If the sum of the roots of the equation \(x^2-4x = K(x-1)-5\) is 7. Find the value of \(K\).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Expand RHS: \(Kx - K -5\). Bring all terms: \(x^2 -4x - Kx + K +5 =0 \Rightarrow x^2 -(4+K)x + (K+5)=0\). Sum of roots = \(4+K\). Given \(4+K = 7 \Rightarrow K=3\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(x)&lt;/strong&gt; If \((a+b):\sqrt{ab}=2:1\) then find \(a:b\).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        \(\frac{a+b}{\sqrt{ab}} = 2 \Rightarrow a+b = 2\sqrt{ab}\). Square both sides: \((a+b)^2 = 4ab \Rightarrow a^2+2ab+b^2 = 4ab \Rightarrow a^2-2ab+b^2=0 \Rightarrow (a-b)^2=0 \Rightarrow a=b\). Ratio \(1:1\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(xi)&lt;/strong&gt; If the radius of the sphere is increased by 50% find the percentage increase of the volume.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        New radius = \(1.5r\). Volume ∝ \(r^3\). New volume = \((1.5)^3 = 3.375\) times original. Increase = \(3.375-1 = 2.375\) → \(237.5\%\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(xii)&lt;/strong&gt; \(ABCD\) is a cyclic quadrilateral. If \(AD=AB\), ∠DAC=60°, ∠BDC=50° then find the ∠ACD.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        &lt;strong&gt;1.&lt;/strong&gt; Angles in same segment: \(\angle BAC = \angle BDC = 50^\circ\) (subtended by arc BC).&lt;br&gt;
        &lt;strong&gt;2.&lt;/strong&gt; So \(\angle DAB = \angle DAC + \angle CAB = 60^\circ+50^\circ=110^\circ\).&lt;br&gt;
        &lt;strong&gt;3.&lt;/strong&gt; In \(\triangle ADB\), \(AD=AB\) ⇒ base angles equal: \(\angle ABD = \angle ADB = \frac{180^\circ-110^\circ}{2}=35^\circ\).&lt;br&gt;
        &lt;strong&gt;4.&lt;/strong&gt; Again, \(\angle ACD = \angle ABD\) (angles subtended by arc AD). Hence \(\angle ACD = 35^\circ\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;

    &lt;h3&gt;📊 5. Arithmetic (answer any one)&lt;/h3&gt;
    &lt;hr&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; If the rate of compound interest be 4% in the 1st year and 5% in the 2nd year, 
        then find the interest of Rs. 25,000 for two years.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Amount = \(25000 \times \left(1+\frac{4}{100}\right) \times \left(1+\frac{5}{100}\right) = 25000 \times 1.04 \times 1.05\).&lt;br&gt;
        \(1.04\times1.05 = 1.092\). So \(A = 25000\times1.092 = 27300\). Interest = \(27300-25000 = 2300\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; Three friends invest Rs. 4,800, Rs. 6,600 and Rs. 9,600. respectively in a business.
        1&lt;sup&gt;st&lt;/sup&gt; person received 1/8 th of the profit as salary for looking after the business and the 
    remaining profit  was distributed among them in ratio of their capitals. If after one year 1&lt;sup&gt;st&lt;/sup&gt; person
received Rs. 780 find the amount recieved by other two.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Capitals ratio = 48:66:96 = 8:11:16 (sum 35). Let total profit = \(P\). Salary = \(P/8\). Remaining = \(7P/8\) divided in ratio 8:11:16.&lt;br&gt;
        1st&#39;s extra = \(\frac{8}{35}\times\frac{7P}{8} = \frac{P}{5}\). So 1st total = \(\frac{P}{8} + \frac{P}{5} = \frac{5P+8P}{40} = \frac{13P}{40}\). Given \(\frac{13P}{40}=780 \Rightarrow P = 2400\).&lt;br&gt;
        Remaining after salary = \(2400 - 2400/8 = 2400-300 = 2100\).&lt;br&gt;
        2nd gets \(\frac{11}{35}\times2100 = 660\); 3rd gets \(\frac{16}{35}\times2100 = 960\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;

    &lt;h3&gt;🧩 6. Algebra – quadratic eq. (any one)&lt;/h3&gt;
    &lt;hr&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; Solve: \(b(c-a)x^2 + c(a-b)x + a(b-c)=0\).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Check sum of coefficients: \(b(c-a)+c(a-b)+a(b-c) = bc - ab + ac - bc + ab - ac = 0\). Hence one root is \(1\).&lt;br&gt;
        Product of roots = \(\frac{a(b-c)}{b(c-a)}\). Thus other root = \(\frac{a(b-c)}{b(c-a)}\).
        &lt;br&gt;Alternatively: \(b(c-a)x^2 + c(a-b)x + a(b-c)=0 \)
        \(\implies b(c-a)x^2 -(b(c-a)+a(b-c))x + a(b-c)=0\)
        \(\implies b(c-a)x^2 -b(c-a)x-a(b-c)x + a(b-c)=0\)
        \(\implies b(c-a)x(x-1)-a(b-c)(x-1)=0\) 
         Now complete!
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; Digit in ten&#39;s place of a two digit number is less by 3 than the digit in the unit place. Product of digits is less than the number by 15. Find the number.&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Let units = \(y\), tens = \(x = y-3\). Number = \(10x+y = 10(y-3)+y = 11y-30\).&lt;br&gt;
        Product \(xy = (y-3)y = y^2-3y\). Given \(xy = (11y-30) - 15\) → \(y^2-3y = 11y-45\).&lt;br&gt;
        Rearr: \(y^2 -14y +45=0\) ⇒ \((y-5)(y-9)=0\) ⇒ \(y=5\) or \(9\). Then numbers: \(25\) or \(69\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;

    &lt;h3&gt;⚡ 7. Algebra – variation / surds (any one)&lt;/h3&gt;
    &lt;hr&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; If \((x^3+y^3)\propto (x^3-y^3)\), then prove that \((x^2+y^2)\propto xy\).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise proof&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        \(\frac{x^3+y^3}{x^3-y^3}=k\) (constant). Apply componendo-dividendo: \(\frac{(x^3+y^3)+(x^3-y^3)}{(x^3+y^3)-(x^3-y^3)} = \frac{k+1}{k-1}\) ⇒ \(\frac{2x^3}{2y^3} = \frac{k+1}{k-1}\) ⇒ \(\left(\frac{x}{y}\right)^3 = \text{constant}\). Hence \(\frac{x}{y}=c\) (constant). Then \(\frac{x^2+y^2}{xy} = \frac{c^2+1}{c}\) = constant ⇒ \((x^2+y^2)\propto xy\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; If \(x(2-\sqrt3)=y(2+\sqrt3)=1\) then find the value of  \(3x^2-5xy+3y^2\).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        \(x = \frac{1}{2-\sqrt3}\). Rationalise: multiply numerator and denominator by \(2+\sqrt3\) ⇒ \(x = 2+\sqrt3\).&lt;br&gt;
        \(y = \frac{1}{2+\sqrt3} = 2-\sqrt3\). Then \(x+y=4,\; xy=1\).&lt;br&gt;
        \(3x^2-5xy+3y^2 = 3(x^2+y^2)-5\). Now \(x^2+y^2 = (x+y)^2 - 2xy = 16-2=14\). So expression = \(3\times14-5 = 42-5=37\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;

    &lt;h3&gt;⚖️ 8. Ratio &amp; proportion (any one)&lt;/h3&gt;
    &lt;hr&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; If \(\frac{a+b-c}{a+b}=\frac{b+c-a}{b+c}=\frac{c+a-b}{c+a}\) and \(a+b+c \neq 0\), then prove that \(a=b=c\).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise proof&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        Subtract each fraction from 1: \(1-\frac{a+b-c}{a+b} = \frac{c}{a+b}\); similarly \(\frac{a}{b+c}\) and \(\frac{b}{c+a}\). So \(\frac{c}{a+b}=\frac{a}{b+c}=\frac{b}{c+a}\). Add 1 to each: \(\frac{a+b+c}{a+b}=\frac{a+b+c}{b+c}=\frac{a+b+c}{c+a}\). Assuming \(a+b+c\neq0\), denominators equal ⇒ \(a+b=b+c=c+a\) ⇒ \(a=b=c\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;div class=&quot;question-box&quot;&gt;&lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; If \(x=\frac{8ab}{a+b}\), then find the value of \(\frac{x+4a}{x-4a}+\frac{x+4b}{x-4b}\).&lt;/p&gt;&lt;details&gt;&lt;summary&gt;stepwise solution&lt;/summary&gt;&lt;div class=&quot;solution-text&quot;&gt;
        \(\frac{x}{4a} = \frac{2b}{a+b}\). Apply componendo-dividendo: \(\frac{x+4a}{x-4a} = \frac{2b+(a+b)}{2b-(a+b)} = \frac{a+3b}{b-a}\).&lt;br&gt;
        Similarly \(\frac{x}{4b} = \frac{2a}{a+b}\) ⇒ \(\frac{x+4b}{x-4b} = \frac{2a+(a+b)}{2a-(a+b)} = \frac{3a+b}{a-b} = -\frac{3a+b}{b-a}\).&lt;br&gt;
        Sum = \(\frac{a+3b - (3a+b)}{b-a} = \frac{-2a+2b}{b-a} = 2\).
    &lt;/div&gt;&lt;/details&gt;&lt;/div&gt;
    &lt;br&gt;
    &lt;hr&gt;
    &lt;div style=&quot;text-align: right; color: #1c3f7a; padding-top: 1rem;&quot;&gt;🧠 For more problems keep visiting Prime Maths&lt;/div&gt;
    &lt;h3&gt;📐 9. Geometry theorems (any one)&lt;/h3&gt;
&lt;hr&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; Prove that the angle subtended by an arc at the centre of a circle is double the angle subtended by the same arc at any point on the remaining part of the circle.&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise proof&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Given:&lt;/strong&gt; Circle with centre \(O\). Arc \(AB\) subtends \(\angle AOB\) at the centre and \(\angle ACB\) at a point \(C\) on the remaining part.&lt;br&gt;
            &lt;strong&gt;To prove:&lt;/strong&gt; \(\angle AOB = 2\angle ACB\).&lt;br&gt;
            &lt;strong&gt;Construction:&lt;/strong&gt; Join \(CO\) and extend it to point \(D\).&lt;br&gt;
            &lt;strong&gt;Proof:&lt;/strong&gt;
            &lt;ul style=&quot;margin-left: 1.2rem; line-height: 1.8;&quot;&gt;
                &lt;li&gt;In \(\triangle AOC\), \(OA = OC\) (radii) ⇒ \(\angle OAC = \angle OCA\).&lt;/li&gt;
                &lt;li&gt;Exterior angle \(\angle AOD = \angle OAC + \angle OCA = 2\angle OCA\).&lt;/li&gt;
                &lt;li&gt;In \(\triangle BOC\), \(OB = OC\) ⇒ \(\angle OBC = \angle OCB\).&lt;/li&gt;
                &lt;li&gt;Exterior angle \(\angle BOD = \angle OBC + \angle OCB = 2\angle OCB\).&lt;/li&gt;
                &lt;li&gt;Adding: \(\angle AOD + \angle BOD = 2(\angle OCA + \angle OCB)\).&lt;/li&gt;
                &lt;li&gt;But \(\angle AOD + \angle BOD = \angle AOB\) and \(\angle OCA + \angle OCB = \angle ACB\).&lt;/li&gt;
                &lt;li&gt;Hence \(\angle AOB = 2\angle ACB\). ∎&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; If two circles touch each other, prove that the point of contact lies on the straight line joining their centres.&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise proof&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Given:&lt;/strong&gt; Two circles with centres \(A\) and \(B\) touching at point \(P\).&lt;br&gt;
            &lt;strong&gt;To prove:&lt;/strong&gt; \(A\), \(P\), \(B\) are collinear.&lt;br&gt;
            &lt;strong&gt;Construction:&lt;/strong&gt; Draw a common tangent \(ST\) at \(P\).&lt;br&gt;
            &lt;strong&gt;Proof:&lt;/strong&gt;
            &lt;ul style=&quot;margin-left: 1.2rem; line-height: 1.8;&quot;&gt;
                &lt;li&gt;Radius \(AP\) is perpendicular to tangent \(ST\) ⇒ \(\angle APT = 90^\circ\).&lt;/li&gt;
                &lt;li&gt;Radius \(BP\) is perpendicular to tangent \(ST\) ⇒ \(\angle BPT = 90^\circ\).&lt;/li&gt;
                &lt;li&gt;Thus \(\angle APT + \angle BPT = 180^\circ\).&lt;/li&gt;
                &lt;li&gt;Angles \(\angle APT\) and \(\angle BPT\) form a linear pair on line \(ST\).&lt;/li&gt;
                &lt;li&gt;Therefore, \(AP\) and \(BP\) are along the same straight line ⇒ \(A\), \(P\), \(B\) are collinear. ∎&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;h3&gt;🔧 10. Geometry applications (any one)&lt;/h3&gt;
&lt;hr&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; In an isosceles \(\triangle ABC\), \(\angle B = 90^\circ\). The bisector of \(\angle BAC\) meets \(BC\) at \(D\). Prove that \(CD^2 = 2\,BD^2\).&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Given:&lt;/strong&gt; \(AB = BC\) (isosceles right‑angled at \(B\)). \(AD\) bisects \(\angle BAC\).&lt;br&gt;
            &lt;strong&gt;To prove:&lt;/strong&gt; \(CD^2 = 2 BD^2\).&lt;br&gt;
            &lt;strong&gt;Proof:&lt;/strong&gt;
            &lt;ul style=&quot;margin-left: 1.2rem; line-height: 1.8;&quot;&gt;
                &lt;li&gt;Let \(AB = BC = a\). Then hypotenuse \(AC = \sqrt{a^2 + a^2} = a\sqrt{2}\).&lt;/li&gt;
                &lt;li&gt;By angle‑bisector theorem in \(\triangle ABC\):
                    \[
                    \frac{BD}{CD} = \frac{AB}{AC} = \frac{a}{a\sqrt{2}} = \frac{1}{\sqrt{2}}.
                    \]
                &lt;/li&gt;
                &lt;li&gt;Hence \(CD = \sqrt{2}\, BD\).&lt;/li&gt;
                &lt;li&gt;Squaring both sides: \(CD^2 = 2 BD^2\). ∎&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; \(O\) is any point inside rectangle \(ABCD\). Prove that \(OA^2 + OC^2 = OB^2 + OD^2\).&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Construction:&lt;/strong&gt; Through \(O\) draw lines parallel to the sides, meeting \(AB, BC, CD, DA\) at \(P, Q, R, S\) respectively.&lt;br&gt;
            &lt;strong&gt;Proof:&lt;/strong&gt;
            &lt;ul style=&quot;margin-left: 1.2rem; line-height: 1.8;&quot;&gt;
                &lt;li&gt;By Pythagoras in right triangles:
                    \[
                    \begin{aligned}
                    OA^2 &amp;= AP^2 + OP^2,\\
                    OC^2 &amp;= CQ^2 + OQ^2,\\
                    OB^2 &amp;= BP^2 + OP^2,\\
                    OD^2 &amp;= DQ^2 + OQ^2.
                    \end{aligned}
                    \]
                &lt;/li&gt;
                &lt;li&gt;Because of the parallel lines, \(AP = BQ\) and \(CQ = PD\).&lt;/li&gt;
                &lt;li&gt;Adding the first two: \(OA^2 + OC^2 = AP^2 + OP^2 + CQ^2 + OQ^2\).&lt;/li&gt;
                &lt;li&gt;Adding the last two: \(OB^2 + OD^2 = BP^2 + OP^2 + DQ^2 + OQ^2\).&lt;/li&gt;
                &lt;li&gt;But \(AP^2 = BQ^2\) and \(CQ^2 = DQ^2\). Hence both sums are equal. ∎&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;h3&gt;🛠️ 11. Construction (any one)&lt;/h3&gt;
&lt;hr&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; Construct the circumcircle of \(\triangle ABC\) where \(BC = 6\ \text{cm}\), \(\angle ABC = 60^\circ\) and \(AB = 8\ \text{cm}\). (Write the main steps.)&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view construction steps&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;ul style=&quot;margin-left: 1.2rem; line-height: 1.8;&quot;&gt;
                &lt;li&gt;Draw a line segment \(BC = 6\ \text{cm}\).&lt;/li&gt;
                &lt;li&gt;At \(B\), construct \(\angle CBA = 60^\circ\) and cut \(AB = 8\ \text{cm}\) from the ray.&lt;/li&gt;
                &lt;li&gt;Join \(AC\) to complete \(\triangle ABC\).&lt;/li&gt;
                &lt;li&gt;Draw the perpendicular bisectors of sides \(AB\) and \(BC\). Let them intersect at \(O\).&lt;/li&gt;
                &lt;li&gt;With centre \(O\) and radius \(OA\) (or \(OB\) or \(OC\)), draw the circle – this is the required circumcircle.&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; Construct a square equal in area to an equilateral triangle of side \(6\ \text{cm}\). (Write the main steps.)&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view construction steps&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;ul style=&quot;margin-left: 1.2rem; line-height: 1.8;&quot;&gt;
                &lt;li&gt;Draw an equilateral triangle \(ABC\) with side \(6\ \text{cm}\).&lt;/li&gt;
                &lt;li&gt;Compute (or measure) its altitude: \(h = \sqrt{6^2 - 3^2} = \sqrt{36-9} = \sqrt{27} = 3\sqrt{3}\ \text{cm}\).&lt;/li&gt;
                &lt;li&gt;Area of triangle = \(\frac{1}{2}\times 6 \times 3\sqrt{3} = 9\sqrt{3}\ \text{cm}^2\).&lt;/li&gt;
                &lt;li&gt;Construct a rectangle with length \(6\ \text{cm}\) and width \(3\sqrt{3}\ \text{cm}\) (using a right triangle to obtain \(\sqrt{3}\)).&lt;/li&gt;
                &lt;li&gt;Now construct a square with area equal to that rectangle using the mean‑proportional method:
                    &lt;ul style=&quot;list-style-type: circle; margin-left: 1.5rem;&quot;&gt;
                        &lt;li&gt;Extend the rectangle’s length \(L\) by its width \(W\).&lt;/li&gt;
                        &lt;li&gt;Draw a semicircle on the total segment as diameter.&lt;/li&gt;
                        &lt;li&gt;Erect a perpendicular at the junction; its length to the circle gives the side of the square.&lt;/li&gt;
                    &lt;/ul&gt;
                &lt;/li&gt;
            &lt;/ul&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;h3&gt;📐 12. Trigonometry (any two)&lt;/h3&gt;
&lt;hr&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; If the ratio of three angles of a triangle is \(2:3:4\) then determine
        the circular value of the greatest angle.&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Step 1:&lt;/strong&gt; Let the angles be \(2x,\ 3x,\ 4x\). Sum = \(2x+3x+4x = 9x\).&lt;br&gt;
            &lt;strong&gt;Step 2:&lt;/strong&gt; In a triangle, \(9x = 180^\circ\) ⇒ \(x = 20^\circ\).&lt;br&gt;
            &lt;strong&gt;Step 3:&lt;/strong&gt; Greatest angle = \(4x = 80^\circ\).&lt;br&gt;
            &lt;strong&gt;Step 4:&lt;/strong&gt; Convert to radians: \(80^\circ \times \frac{\pi}{180} = \frac{4\pi}{9}\).&lt;br&gt;
            &lt;span class=&quot;correct-answer&quot;&gt;✅ Greatest angle = \(\frac{4\pi}{9}\) radians&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; If \(\tan\theta = \frac{4}{3}\), find \(\sin\theta + \cos\theta\).&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Step 1:&lt;/strong&gt; Construct a right triangle with opposite = \(4\), adjacent = \(3\). Hypotenuse = \(\sqrt{4^2+3^2} = \sqrt{16+9}=5\).&lt;br&gt;
            &lt;strong&gt;Step 2:&lt;/strong&gt; \(\sin\theta = \frac{\text{opp}}{\text{hyp}} = \frac{4}{5}\), \(\cos\theta = \frac{\text{adj}}{\text{hyp}} = \frac{3}{5}\).&lt;br&gt;
            &lt;strong&gt;Step 3:&lt;/strong&gt; \(\sin\theta + \cos\theta = \frac{4}{5} + \frac{3}{5} = \frac{7}{5}\).&lt;br&gt;
            &lt;span class=&quot;correct-answer&quot;&gt;✅ \(\sin\theta + \cos\theta = \frac{7}{5}\)&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(iii)&lt;/strong&gt; If \(A\) and \(B\) are complementary angles, prove that \((\sin A + \cos B)^2 = 1 + 2\sin A \sin B\).&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise proof&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Given:&lt;/strong&gt; \(A + B = 90^\circ\). Hence \(\cos B = \sin A\) and \(\sin B = \cos A\).&lt;br&gt;
            &lt;strong&gt;Proof:&lt;/strong&gt;
            \[
            \begin{aligned}
            \text{LHS} &amp;= (\sin A + \cos B)^2 \\
            &amp;= (\sin A + \sin A)^2 \quad (\because \cos B = \sin A)\\
            &amp;= (2\sin A)^2 = 4\sin^2 A.
            \end{aligned}
            \]
            &lt;strong&gt;Wrong Problem!!.&lt;/strong&gt; Usually the intended statement is: \((\sin A + \sin B)^2 = 1 + 2\sin A \sin B\) because \(\sin B = \cos A\). Let&#39;s verify the standard form:
            \[
            (\sin A + \sin B)^2 = \sin^2 A + \sin^2 B + 2\sin A\sin B.
            \]
            Since \(\sin^2 A + \sin^2 B = \sin^2 A + \cos^2 A = 1\), we get \(1 + 2\sin A\sin B\).&lt;br&gt;
            &lt;em&gt;If the problem statement uses \(\cos B\) instead of \(\sin B\), then note \(\cos B = \sin A\) and the expression becomes \((\sin A + \sin A)^2 = 4\sin^2 A\), which is not generally equal to \(1+2\sin A\sin B\).&lt;/em&gt;&lt;br&gt;
            &lt;strong&gt;Assuming the intended identity uses \(\sin B\) (common in complementary angle problems):&lt;/strong&gt;&lt;br&gt;
            \[
            (\sin A + \sin B)^2 = 1 + 2\sin A \sin B \quad\text{(proved above).}
            \]
            &lt;span class=&quot;correct-answer&quot;&gt;✅ Full marks on attempt.&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;br&gt;
&lt;hr&gt;
&lt;div style=&quot;text-align: right; color: #1c3f7a; padding-top: 1rem;&quot;&gt;Feel free to contact us at 9038126497 &lt;/div&gt;
&lt;h3&gt;📏 13. Height and Distance (any one)&lt;/h3&gt;
&lt;hr&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; From the roof of a building, the angles of depression of the top and foot of
         a lamp post are \(30^\circ\) and \(\theta^\circ\) respectively. The ratio of the heights of 
         the building and the lamp post is \(3:2\), then find the value of \(\theta\).&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;img alt=&quot;Description&quot; style=&quot;float:none; display:block; margin:0 auto; max-width:100%;&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiwLlzjl1eluAqwgHeftFGjv3QIRG_cTkZkCdGBxgpq1WUBKULLGRvwWxOewqSlmwgWn_Da3lDlwtVEr3u5ymgMzm8uRNhHutqgW3ug3Ki7kaOQJmHuTpHOy32UoSjsYGJDDJVUSHoun8BGNlirfkWtzIrzvxlQdxNBf_nhVJKCOo9VIECMhTeHYrbOnaw/s691/hEIGHT_dISTANCE_1.png&quot;  /&gt;
            &lt;br&gt;
            &lt;strong&gt;Step 1 – assign variables:&lt;/strong&gt; Let height of building \(H = 3x\), height of lamp post \(h = 2x\).&lt;br&gt;
            &lt;strong&gt;Step 2 – vertical difference:&lt;/strong&gt; The top of the lamp is \(H-h = 3x - 2x = x\) below the roof.&lt;br&gt;
            &lt;strong&gt;Step 3 – horizontal distance \(d\):&lt;/strong&gt; From roof, angle of depression \(30^\circ\) to top of lamp ⇒ \(\tan 30^\circ = \frac{x}{d}\).&lt;br&gt;
            \[
            \frac{1}{\sqrt{3}} = \frac{x}{d} \quad\Rightarrow\quad d = x\sqrt{3}.
            \]
            &lt;strong&gt;Step 4 – angle \(\theta\) to foot of lamp:&lt;/strong&gt; From roof, foot is at depth \(3x\) below, same horizontal distance \(d\).&lt;br&gt;
            \[
            \tan\theta = \frac{3x}{d} = \frac{3x}{x\sqrt{3}} = \sqrt{3}.
            \]
            &lt;strong&gt;Step 5 – solve for \(\theta\):&lt;/strong&gt; \(\tan\theta = \sqrt{3} \Rightarrow \theta = 60^\circ\).&lt;br&gt;
            &lt;span class=&quot;correct-answer&quot;&gt;✅ \(\theta = 60^\circ\)&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; From the foot of a Tilla the angle of elevation of the top is 
        \(45^\circ\). By moving \(100\) m towards the Tilla along a slope of \(30^\circ\), 
        the angle of elevation of the top becomes\(60^\circ\). Find the height of the Tilla.&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;img alt=&quot;Description&quot; style=&quot;float:none; display:block; margin:0 auto; max-width:100%;&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgJKqe_BwPZVzOLKcJvSeA00n-SDYPpwP70XBHK2BeeNpx6gTzI_rcmg5ideTynUd9slzdYyVUg74qgs0JR2Ze3B8O1sLsu1l9jPONVfw6bE5nJeVJuwid-Q-2hJU1tW4p1vY9WG5_MytgpZioL9Glz0Gt-uxN2xGsWdV3e6vPjB9JEB6hhWOWpTubNuPc/s616/hEIGHT_dISTANCE_1.png&quot;  /&gt;
            &lt;br&gt;
            &lt;strong&gt;Step 1 – Main triangle:&lt;/strong&gt; The distance of the point from the foot of the Tilla is \(h\), since \(\tan 45^{\circ}=1=\frac{h}{distance}\)&lt;br&gt;
            &lt;strong&gt;Step 2 – movement along slope:&lt;/strong&gt; From the starting point walk \(100\) m at \(30^\circ\) upward slope (towards the Tilla). The displacement components: Horizontal distance \( = 100\cos30^\circ = 100 \times \frac{\sqrt3}{2} = 50\sqrt3\), Vertical distance \(= 100\sin30^\circ = 50\). 
            So the new position is at a horizontal distance of \(h-50\sqrt{3}\) from the Tilla and its vertical distance from the top of the Tilla is \(h-50\)&lt;br&gt;
            &lt;strong&gt;Step 3 – elevation from \(B\):&lt;/strong&gt; Angle of elevation to top of Tilla is \(60^\circ\). 
            \[
            \tan60^\circ =  \frac{h-50}{h - 50\sqrt3}.
            \]
            &lt;strong&gt;Step 4 – solve for \(h\):&lt;/strong&gt; \(\tan60^\circ = \sqrt3\):
            \[
            \sqrt3 = \frac{h-50}{h - 50\sqrt3}
            \implies \sqrt3\,(h - 50\sqrt3) = h - 50
            \implies \sqrt3\,h - 150 = h - 50.
            \]
            \[
            (\sqrt3 - 1)h = 100 \quad\Rightarrow\quad h = \frac{100}{\sqrt3 - 1}.
            \]
            &lt;strong&gt;Step 5 – rationalise:&lt;/strong&gt; Multiply numerator and denominator by \(\sqrt3 + 1\):
            \[
            h = \frac{100(\sqrt3+1)}{3-1} = 50(\sqrt3 + 1)\ \text{m}.
            \]
            &lt;span class=&quot;correct-answer&quot;&gt;✅ Height \(= 50(\sqrt3 + 1)\) m&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;h3&gt;🧊 14. Mensuration (any two)&lt;/h3&gt;
&lt;hr&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; The ratio of the length, breadth and height of a solid rectangular
        parallelopiped is \(4:3:2\) and area of the whole surface is \(468\ \text{cm}^2\). Find the volume of the parallelopiped.&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Step 1 – let dimensions:&lt;/strong&gt; Let length \(l = 4x\), breadth \(b = 3x\), height \(h = 2x\).&lt;br&gt;
            &lt;strong&gt;Step 2 – total surface area (TSA):&lt;/strong&gt;
            \[
            TSA = 2(lb + bh + hl) = 2\bigl(4x\cdot3x + 3x\cdot2x + 2x\cdot4x\bigr)
            = 2(12x^2 + 6x^2 + 8x^2) = 2 \times 26x^2 = 52x^2.
            \]
            &lt;strong&gt;Step 3 – given TSA = 468:&lt;/strong&gt;
            \[
            52x^2 = 468 \quad\Rightarrow\quad x^2 = 9 \quad\Rightarrow\quad x = 3.
            \]
            &lt;strong&gt;Step 4 – actual dimensions:&lt;/strong&gt; \(l = 12\ \text{cm},\ b = 9\ \text{cm},\ h = 6\ \text{cm}\).&lt;br&gt;
            &lt;strong&gt;Step 5 – volume:&lt;/strong&gt;
            \[
            V = l \times b \times h = 12 \times 9 \times 6 = 648\ \text{cm}^3.
            \]
            &lt;span class=&quot;correct-answer&quot;&gt;✅ Volume = \(648\ \text{cm}^3\)&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; The internal and external radius of a hollow cylinder of height
         \(20\ \text{cm}\) are  \(4\ \text{cm}\) and \(5\ \text{cm}\) respectively. By meltingthis cylinder
         a solid cone of height equal to one‑third the height of the cylinder is formed. Find the diameter 
         of the base of the cone.&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Step 1 – volume of hollow cylinder:&lt;/strong&gt;
            \[
            V_{\text{cyl}} = \pi h_{\text{cyl}} (R^2 - r^2) = \pi \times 20 \times (5^2 - 4^2)
            = 20\pi (25-16) = 20\pi \times 9 = 180\pi\ \text{cm}^3.
            \]
            &lt;strong&gt;Step 2 – height of cone:&lt;/strong&gt; \(h_{\text{cone}} = \frac{1}{3}\times 20 = \frac{20}{3}\ \text{cm}\).&lt;br&gt;
            &lt;strong&gt;Step 3 – volume of cone:&lt;/strong&gt; \(V_{\text{cone}} = \frac13 \pi r_{\text{cone}}^2 h_{\text{cone}}\). Equate volumes:
            \[
            \frac13 \pi r_{\text{cone}}^2 \times \frac{20}{3} = 180\pi.
            \]
            Cancel \(\pi\) and simplify:
            \[
            \frac{20}{9} r_{\text{cone}}^2 = 180 \quad\Rightarrow\quad r_{\text{cone}}^2 = 180 \times \frac{9}{20} = 81.
            \]
            &lt;strong&gt;Step 4 – radius and diameter:&lt;/strong&gt; \(r_{\text{cone}} = 9\ \text{cm}\) (positive). Diameter = \(2\times 9 = 18\ \text{cm}\).&lt;br&gt;
            &lt;span class=&quot;correct-answer&quot;&gt;✅ Base diameter = \(18\ \text{cm}\)&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(iii)&lt;/strong&gt; A hemispherical bowl of internal radius \(9 \text{cm}\) is full of water. 
        How many cylindrical 
        bottles each of diameter \(3\ \text{cm}\) and height \(4\ \text{cm}\) are required to fill this water?&lt;/p&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Step 1 – volume of hemispherical bowl:&lt;/strong&gt;
            \[
            V_{\text{bowl}} = \frac23 \pi R^3 = \frac23 \pi (9)^3 = \frac23 \pi \times 729 = 486\pi\ \text{cm}^3.
            \]
            &lt;strong&gt;Step 2 – volume of one cylindrical bottle:&lt;/strong&gt; radius \(r = \frac{3}{2} = 1.5\ \text{cm}\), height \(h = 4\ \text{cm}\).
            \[
            V_{\text{bottle}} = \pi r^2 h = \pi (1.5)^2 \times 4 = \pi \times 2.25 \times 4 = 9\pi\ \text{cm}^3.
            \]
            &lt;strong&gt;Step 3 – number of bottles:&lt;/strong&gt;
            \[
            n = \frac{V_{\text{bowl}}}{V_{\text{bottle}}} = \frac{486\pi}{9\pi} = 54.
            \]
            &lt;span class=&quot;correct-answer&quot;&gt;✅ 54 bottles are required&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;h3&gt;📊 15. Statistics (any two)&lt;/h3&gt;
&lt;hr&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(i)&lt;/strong&gt; Find the arithmetic mean for the following frequency distribution:&lt;/p&gt;
    &lt;table style=&quot;margin: 0.5rem 0; border-collapse: collapse;&quot;&gt;
        &lt;tr&gt;&lt;th style=&quot;padding: 0 1rem 0 0; text-align: left;&quot;&gt;Class&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;5-14&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;15-24&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;25-34&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;35-44&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;45-54&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;55-64&lt;/th&gt;&lt;/tr&gt;
        &lt;tr&gt;&lt;td&gt;Frequency&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;3&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;6&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;18&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;20&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;10&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;3&lt;/td&gt;&lt;/tr&gt;
    &lt;/table&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Step 1 – find midpoints (class marks):&lt;/strong&gt;
            \[
            x_1 = \frac{5+14}{2} = 9.5,\; x_2 = 19.5,\; x_3 = 29.5,\; x_4 = 39.5,\; x_5 = 49.5,\; x_6 = 59.5.
            \]
            &lt;strong&gt;Step 2 – compute \(f_i x_i\):&lt;/strong&gt;
            \[
            \begin{aligned}
            f_1x_1 &amp;= 3 \times 9.5 = 28.5,\\
            f_2x_2 &amp;= 6 \times 19.5 = 117,\\
            f_3x_3 &amp;= 18 \times 29.5 = 531,\\
            f_4x_4 &amp;= 20 \times 39.5 = 790,\\
            f_5x_5 &amp;= 10 \times 49.5 = 495,\\
            f_6x_6 &amp;= 3 \times 59.5 = 178.5.
            \end{aligned}
            \]
            &lt;strong&gt;Step 3 – total frequency and sum of products:&lt;/strong&gt;
            \[
            \sum f = 3+6+18+20+10+3 = 60,
            \]
            \[
            \sum fx = 28.5 + 117 + 531 + 790 + 495 + 178.5 = 2140.
            \]
            &lt;strong&gt;Step 4 – arithmetic mean:&lt;/strong&gt;
            \[
            \bar{x} = \frac{\sum fx}{\sum f} = \frac{2140}{60} \approx 35.666\ldots \approx 35.67.
            \]
            &lt;span class=&quot;correct-answer&quot;&gt;✅ Mean \(\approx 35.67\)&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(ii)&lt;/strong&gt; For the following frequency distribution, construct a &#39;greater than&#39; cumulative frequency table and draw the ogive (more than type).&lt;/p&gt;
    &lt;table style=&quot;margin: 0.5rem 0; border-collapse: collapse;&quot;&gt;
        &lt;tr&gt;&lt;th style=&quot;padding: 0 1rem 0 0; text-align: left;&quot;&gt;Class&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;100-120&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;120-140&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;140-160&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;160-180&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;180-200&lt;/th&gt;&lt;/tr&gt;
        &lt;tr&gt;&lt;td&gt;Frequency&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;8&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;14&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;10&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;12&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;4&lt;/td&gt;&lt;/tr&gt;
    &lt;/table&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Step 1 – compute total frequency:&lt;/strong&gt;
            \[
            N = 8 + 14 + 10 + 12 + 4 = 48.
            \]
            &lt;strong&gt;Step 2 – obtain &#39;greater than&#39; cumulative frequencies:&lt;/strong&gt;
            &lt;ul style=&quot;margin-left: 1.2rem;&quot;&gt;
                &lt;li&gt;More than 100 : \(48\)&lt;/li&gt;
                &lt;li&gt;More than 120 : \(48 - 8 = 40\)&lt;/li&gt;
                &lt;li&gt;More than 140 : \(40 - 14 = 26\)&lt;/li&gt;
                &lt;li&gt;More than 160 : \(26 - 10 = 16\)&lt;/li&gt;
                &lt;li&gt;More than 180 : \(16 - 12 = 4\)&lt;/li&gt;
                &lt;li&gt;More than 200 : \(4 - 4 = 0\) (optional)&lt;/li&gt;
            &lt;/ul&gt;
            &lt;strong&gt;Step 3 – points to plot for the ogive:&lt;/strong&gt;
            \[
            (100,\,48),\quad (120,\,40),\quad (140,\,26),\quad (160,\,16),\quad (180,\,4).
            \]
            &lt;strong&gt;Step 4 – drawing the ogive:&lt;/strong&gt; On a graph sheet, take the upper limits (or the lower limits for more‑than) on the x‑axis and cumulative frequencies on the y‑axis. Plot the points and join them with a smooth freehand curve. The resulting graph is the &#39;more than&#39; ogive.&lt;br&gt;
            &lt;span class=&quot;correct-answer&quot;&gt;✅ Table and points ready for plotting.&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;div class=&quot;question-box&quot;&gt;
    &lt;p&gt;&lt;strong&gt;(iii)&lt;/strong&gt; Find the mode of the following frequency distribution:&lt;/p&gt;
    &lt;table style=&quot;margin: 0.5rem 0; border-collapse: collapse;&quot;&gt;
        &lt;tr&gt;&lt;th style=&quot;padding: 0 1rem 0 0; text-align: left;&quot;&gt;Marks obtained&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;less than 10&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;less than 20&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;less than 30&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;less than 40&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;less than 50&lt;/th&gt;&lt;th style=&quot;padding: 0 1rem;&quot;&gt;less than 60&lt;/th&gt;&lt;/tr&gt;
        &lt;tr&gt;&lt;td&gt;Number of students&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;8&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;15&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;29&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;42&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;60&lt;/td&gt;&lt;td style=&quot;text-align: center;&quot;&gt;70&lt;/td&gt;&lt;/tr&gt;
    &lt;/table&gt;
    &lt;details&gt;
        &lt;summary&gt;📘 view stepwise solution&lt;/summary&gt;
        &lt;div class=&quot;solution-text&quot;&gt;
            &lt;strong&gt;Step 1 – convert to ordinary frequency distribution:&lt;/strong&gt; The given cumulative frequencies are for &quot;less than&quot; limits. Subtract successive cumulatives to obtain class frequencies.
            &lt;ul style=&quot;margin-left: 1.2rem;&quot;&gt;
                &lt;li&gt;\(0-10\) : \(8\)&lt;/li&gt;
                &lt;li&gt;\(10-20\): \(15 - 8 = 7\)&lt;/li&gt;
                &lt;li&gt;\(20-30\): \(29 - 15 = 14\)&lt;/li&gt;
                &lt;li&gt;\(30-40\): \(42 - 29 = 13\)  (this is \(f_0\))&lt;/li&gt;
                &lt;li&gt;\(40-50\): \(60 - 42 = 18\)  (this is \(f_1\) – modal class)&lt;/li&gt;
                &lt;li&gt;\(50-60\): \(70 - 60 = 10\)  (this is \(f_2\))&lt;/li&gt;
            &lt;/ul&gt;
            &lt;strong&gt;Step 2 – identify modal class:&lt;/strong&gt; The highest frequency is \(18\) in the class \(40-50\). So modal class = \(40-50\) with
            \[
            l = 40,\quad f_1 = 18,\quad f_0 = 13,\quad f_2 = 10,\quad h = 10.
            \]
            &lt;strong&gt;Step 3 – apply mode formula:&lt;/strong&gt;
            \[
            \text{Mode} = l + \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h
            = 40 + \frac{18 - 13}{2\times18 - 13 - 10} \times 10.
            \]
            &lt;strong&gt;Step 4 – simplify:&lt;/strong&gt;
            \[
            2f_1 - f_0 - f_2 = 36 - 13 - 10 = 13,\quad f_1-f_0 = 5.
            \]
            \[
            \text{Mode} = 40 + \frac{5}{13} \times 10 = 40 + \frac{50}{13} \approx 40 + 3.846 = 43.846.
            \]
            &lt;span class=&quot;correct-answer&quot;&gt;✅ Mode \(\approx 43.85\) (rounded to two decimals)&lt;/span&gt;
        &lt;/div&gt;
    &lt;/details&gt;
&lt;/div&gt;

&lt;br&gt;
&lt;hr&gt;
&lt;div style=&quot;text-align: right; color: #1c3f7a; padding-top: 1rem;&quot;&gt;📈 Prime Maths &lt;/div&gt;

&lt;br&gt;
&lt;hr&gt;
&lt;/div&gt;
&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/431103317033743683/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/02/madhyamik-mathematics-board-paper-2026.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/431103317033743683'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/431103317033743683'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/02/madhyamik-mathematics-board-paper-2026.html' title='Madhyamik Mathematics Board Paper 2026 | Full Solution | English Version'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiwLlzjl1eluAqwgHeftFGjv3QIRG_cTkZkCdGBxgpq1WUBKULLGRvwWxOewqSlmwgWn_Da3lDlwtVEr3u5ymgMzm8uRNhHutqgW3ug3Ki7kaOQJmHuTpHOy32UoSjsYGJDDJVUSHoun8BGNlirfkWtzIrzvxlQdxNBf_nhVJKCOo9VIECMhTeHYrbOnaw/s72-c/hEIGHT_dISTANCE_1.png" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-674828035566765942</id><published>2026-02-12T22:22:00.000-08:00</published><updated>2026-02-13T02:48:51.229-08:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><title type='text'>Important Questions for ICSE, CBSE Board Examination</title><content type='html'>&lt;link href=&quot;https://fonts.googleapis.com/css2?family=Inter:opsz,wght@14..32,400;14..32,500;14..32,600;14..32,700&amp;family=Space+Grotesk:wght@400;500;600&amp;display=swap&quot; rel=&quot;stylesheet&quot;&gt;
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&quot;&gt;
  &lt;span style=&quot;display: inline-block; font-size: 1.7rem; margin-right: 0.6rem; vertical-align: middle; color: #3b82f6;&quot;&gt;📘&lt;/span&gt;
  &lt;strong style=&quot;color: #0f2b4a;&quot;&gt;A comprehensive, interactive revision tool&lt;/strong&gt; for Class 10 Mathematics. 
  Features &lt;strong style=&quot;color: #2563eb;&quot;&gt;30 curated problems&lt;/strong&gt; across all major units with step-by-step hints to aid understanding. 
  Ideal for self‑assessment and board preparation. 
  &lt;em style=&quot;color: #1e4a7a; font-weight: 600; display: inline-block; margin-top: 0.4rem;&quot;&gt;Test yourself before the finals!&lt;/em&gt;&lt;br&gt;
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        &lt;h2&gt;
          &lt;i class=&quot;fas fa-infinity&quot;&gt;&lt;/i&gt; 30 Challenging Problems for ICSE, CBSE and other State Boards
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        &lt;span class=&quot;mw-badge&quot;&gt;Prime Maths&lt;/span&gt;
        
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        &lt;i class=&quot;fas fa-chalkboard-teacher&quot;&gt;&lt;/i&gt; Curated by Vinod Singh — Mathematics Educator — 9038126497
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&lt;script&gt;
(function() {
  // Problems Data
  const problems = [
    { topic: &quot;Quadratic Equations&quot;, icon: &quot;fa-square-root-variable&quot;, text: &quot;A plane left $30$ minutes later than its scheduled time and in order to reach the destination $1500$ km away in time, it had to increase its speed by $250$ km/h from its usual speed. Find its usual speed.&quot;, hint: &quot;Let usual speed = $x$ km/h. Then $\\frac{1500}{x} - \\frac{1500}{x+250} = \\frac12$. Solve: $x^2+250x-750000=0 \\Rightarrow x=750$ km/h.&quot; },
    { topic: &quot;Nature of Roots&quot;, icon: &quot;fa-dice-d6&quot;, text: &quot;If the quadratic equation $(k-12)x^2 + 2(k-12)x + 2 = 0$ has real and equal roots. Find the value of $k$.&quot;, hint: &quot;$D = 0$: $4(k-12)^2 - 8(k-12)=0$. $(k-12)(4k-56)=0 \\Rightarrow k=12$ (invalid) or $k=14$.&quot; },
    { topic: &quot;Arithmetic Progression&quot;, icon: &quot;fa-chart-line&quot;, text: &quot;If the sum of first n terms of an AP is $S_n = 3n^2 + 5n$. Find $n^{th}$ term and $25^{th}$ term.&quot;, hint: &quot;$a_n = S_n - S_{n-1} = 6n+2$. Then $a_{25}=152$.&quot; },
    { topic: &quot;AP Logic&quot;, icon: &quot;fa-calculator&quot;, text: &quot;If the $m^{th}$ term of an AP is $\\frac{1}{n}$ and $n^{th}$ term is $\\frac{1}{m}$. Show that sum of first $mn$ terms is $\\frac12(mn+1)$.&quot;, hint: &quot;$a = \\frac{1}{mn}, d = \\frac{1}{mn}$. $S_{mn} = \\frac{mn}{2}\\left[\\frac{2}{mn}+(mn-1)\\frac{1}{mn}\\right] = \\frac12(mn+1)$.&quot; },
    { topic: &quot;Geometric Progression&quot;, icon: &quot;fa-chart-pie&quot;, text: &quot;Sum of three numbers in GP is $21$ and sum of  their squares is $189$. Find the numbers.&quot;, hint: &quot;Terms $a/r, a, ar$. $a(1/r+1+r)=21$, $a^2(1/r^2+1+r^2)=189$. Solve: $a=6$, $r=2$ or $\\frac12$ → numbers $3,6,12$.&quot; },
    { topic: &quot;AP-GP Concept&quot;, icon: &quot;fa-basketball&quot;, text: &quot;If $\\sqrt[a]{x}=\\sqrt[b]{y}=\\sqrt[c]{z}$ where $a,b,c$ are in A.P., then show that, $x,y,z$ are in G.P.&quot;, hint: &quot;There exists a non-zero real number, $k$ such that $\\sqrt[a]{x}=\\sqrt[b]{y}=\\sqrt[c]{z}=k$&quot; },
    { topic: &quot;Matrices&quot;, icon: &quot;fa-table&quot;, text: &quot;If $A = \\begin{bmatrix} 2 &amp; 1 \\\\ 0 &amp; 1 \\end{bmatrix}$. Find $A^2 - 3A + 2I$.&quot;, hint: &quot;$A^2 = \\begin{bmatrix}4&amp;3\\\\0&amp;1\\end{bmatrix}$. Then $A^2-3A+2I = \\begin{bmatrix}0&amp;0\\\\0&amp;0\\end{bmatrix}$ (zero matrix).&quot; },
    { topic: &quot;Factor Theorem&quot;, icon: &quot;fa-cubes&quot;, text: &quot;$x^3 + ax^2 + bx -6$ is divisible by $(x-2)$ and leaves a remainder $3$ when divided by $(x-3)$. Find $a,b$.&quot;, hint: &quot;$p(2)=0 \\Rightarrow 8+4a+2b-6=0$, $p(3)=3 \\Rightarrow 27+9a+3b-6=3$. Solve $a=-2$, $b=-3$.&quot; },
    { topic: &quot;Linear Inequations&quot;, icon: &quot;fa-equals&quot;, text: &quot;$-3 &lt; -\\frac12 - \\frac{2x}{3} \\le \\frac56$, $x\\in \\mathbb{R}$. Solve and represent on number line.&quot;, hint: &quot;Multiply by $6$: $-18 &lt; -3 -4x \\le 5$. Add $3$: $-15 &lt; -4x \\le 8$. Divide by $-4$: $-2 \\le x &lt; \\frac{15}{4}$.&quot; },
    { topic: &quot;Componendo &amp; Dividendo&quot;, icon: &quot;fa-divide&quot;, text: &quot; Use componendo and dividendo to find $x$: $\\frac{\\sqrt{3x+4} + \\sqrt{3x-5}}{\\sqrt{3x+4} - \\sqrt{3x-5}} = 9$.&quot;, hint: &quot;Using C/D: $\\frac{2\\sqrt{3x+4}}{2\\sqrt{3x-5}} = \\frac{9+1}{9-1} \\Rightarrow \\sqrt{\\frac{3x+4}{3x-5}} = \\frac54$. Solve $x=3$.&quot; },
    { topic: &quot;GST&quot;, icon: &quot;fa-file-invoice&quot;, text: &quot;A shopkeeper buys an article for ₹8,000 and sells it to a consumer at a profit of 15%. If the GST rate is 18% and the transaction is intra-state, find the total amount paid by the consumer and the tax paid by the shopkeeper to the State Government.&quot;, hint: &quot;SP = $9200$. GST = $18\\% \\times 9200 = 1656$. Total = $10856$. SGST = $828$ (half of GST).&quot; },
    { topic: &quot;Banking (RD)&quot;, icon: &quot;fa-piggy-bank&quot;, text: &quot;Mr. Singh has a Recurring Deposit account in a bank for 2 years at 10% p.a. If he gets ₹1,200 as interest at the time of maturity, find the monthly installment and the maturity value.&quot;, hint: &quot;$I = P \\times \\frac{n(n+1)}{24} \\times \\frac{r}{100}$. $n=24$, $r=10$, $I=1200$ gives $P=800$. Maturity = $800\\times24 +1200 = 20400$.&quot; },
    { topic: &quot;Shares &amp; Dividends&quot;, icon: &quot;fa-chart-simple&quot;, text: &quot;A man invests ₹45,000 in shares of a company paying 12% dividend at ₹100 shares available at a premium of ₹25. Find his annual income and the percentage return on his investment.&quot;, hint: &quot;Market price = $125$, number shares = $45000/125 = 360$. Income = $360 \\times 12 = 4320$. Return = $4320/45000 \\times 100 = 9.6\\%$.&quot; },
    { topic: &quot;Cyclic Quadrilateral&quot;, icon: &quot;fa-circle&quot;, text: &quot;In a cyclic quadrilateral $ABCD$, $\\angle A = (2x+4)^\\circ$, $\\angle B = (y+3)^\\circ$, $\\angle C = (2y+10)^\\circ$, $\\angle D = (4x-5)^\\circ$. Find four angles.&quot;, hint: &quot;Opposite angles sum $180^\\circ$: $(2x+4)+(2y+10)=180$, $(y+3)+(4x-5)=180$. Solve $x=31$, $y=25$. Angles: $A=66^\\circ$, $B=28^\\circ$, $C=60^\\circ$, $D=119^\\circ$.&quot; },
    { topic: &quot;Tangent intercept&quot;, icon: &quot;fa-pen-ruler&quot;, text: &quot;Prove that intercept of a tangent between two parallel tangents to a circle subtends a right angle at the center.&quot;, hint: &quot;Draw radii to points of contact. Use tangents perpendicular radii, and quadrilateral sum is $360^\\circ$.&quot; },
    { topic: &quot;Similarity (DE∥BC)&quot;, icon: &quot;fa-shapes&quot;, text: &quot;In $\\triangle ABC$, $DE \\parallel BC$. $AD = x$, $DB = x-2$, $AE = x+2$, $EC = x-1$. Find $x$.&quot;, hint: &quot;$\\frac{AD}{DB} = \\frac{AE}{EC} \\Rightarrow \\frac{x}{x-2} = \\frac{x+2}{x-1} \\Rightarrow x=4$.&quot; },
    { topic: &quot;Coordinate (Circumcenter)&quot;, icon: &quot;fa-location-dot&quot;, text: &quot;$A(8,6), B(8,-2), C(2,-2)$. Find circumcenter.&quot;, hint: &quot;Midpoint AB = $(8,2)$ (horizontal line? vertical), perpendicular bisector $y=2$. Midpoint BC = $(5,-2)$, perpendicular bisector $x=5$. Circumcenter $(5,2)$.&quot; },
    { topic: &quot;Section Formula&quot;, icon: &quot;fa-arrows-left-right&quot;, text: &quot;In what ratio does the line $2x+y-4=0$ divides the line segment joining $A(2,-2)$ and $B(3,7)$. Find ratio.&quot;, hint: &quot;Let ratio $k:1$, point $P = \\left(\\frac{3k+2}{k+1}, \\frac{7k-2}{k+1}\\right)$. Substitute: $2\\cdot\\frac{3k+2}{k+1}+\\frac{7k-2}{k+1}-4=0 \\Rightarrow k= \\frac{2}{9}$. Ratio $2:9$.&quot; },
    { topic: &quot;Equation of a line&quot;, icon: &quot;fa-chart-scatter&quot;, text: &quot;Find the equation of a line passing through the intersection of  $2x+3y=5$ and $3x-y=2$, and perpendicular to the line $4x-5y=6$.&quot;, hint: &quot;Intersection = $(1,1)$. Slope of $4x-5y=6$ is $\\frac45$, so perpendicular slope = $-\\frac54$. Equation: $y-1 = -\\frac54(x-1)$.&quot; },
    { topic: &quot;Locus&quot;, icon: &quot;fa-vector-square&quot;, text: &quot;Find the equation of the locus of a point P such that its distance from $(2,3)$ is equal to its distance from the $y$-axis.&quot;, hint: &quot;Distance from y-axis = $|x|$. $\\sqrt{(x-2)^2+(y-3)^2}=|x| \\Rightarrow (y-3)^2 = 4x-4$.&quot; },
    { topic: &quot;Trig Identity&quot;, icon: &quot;fa-wave-square&quot;, text: &quot;Prove: $\\frac{\\sin\\theta - \\cos\\theta + 1}{\\sin\\theta + \\cos\\theta - 1} = \\frac{1}{\\sec\\theta - \\tan\\theta}$.&quot;, hint: &quot;Divide numerator and denominator by $\\cos\\theta$, use $\\tan\\theta$, $\\sec\\theta$. Or rationalize.&quot; },
    { topic: &quot;Trigonometric Equations&quot;, icon: &quot;fa-superscript&quot;, text: &quot;$x = a\\sec\\theta + b\\tan\\theta$, $y = a\\tan\\theta + b\\sec\\theta$. Prove $x^2 - y^2 = a^2 - b^2$.&quot;, hint: &quot;$x^2-y^2 = (a^2\\sec^2+2ab\\sec\\tan+b^2\\tan^2) - (a^2\\tan^2+2ab\\tan\\sec+b^2\\sec^2) = a^2-b^2$.&quot; },
    { topic: &quot;Height &amp; Distance&quot;, icon: &quot;fa-cloud&quot;, text: &quot;The angle of elevation of a cloud from a point h meters above a lake is $\\alpha$, and the angle of depression of its reflection in the lake is $\\beta$. Prove that the height of the cloud is $h\\frac{\\tan\\beta+\\tan\\alpha}{\\tan\\beta-\\tan\\alpha}$.&quot;, hint: &quot;Let height = $H$, $x$ horizontal. $\\tan\\alpha = (H-h)/x$, $\\tan\\beta = (H+h)/x$. Eliminate $x$.&quot; },
    { topic: &quot;Two-point observation&quot;, icon: &quot;fa-ship&quot;, text: &quot;Two ships are on the same side of a lighthouse such that the angles of depression of the ships as observed from the top of the lighthouse are $30^\\circ$ and $45^\\circ$,If the lighthouse is $100$ m high, find the distance between the ships. &quot;, hint: &quot;$d = 100(\\cot30^\\circ - \\cot45^\\circ) = 100(\\sqrt3 - 1) \\approx 73.2$ m.&quot; },
    { topic: &quot;Cylinder + hemispheres&quot;, icon: &quot;fa-cube&quot;, text: &quot;A solid is in the form of a cylinder with hemispherical ends. The total height of the solid is 20cm and the diameter of the cylinder is 7cm. Find the total volume.&quot;, hint: &quot;Radius $3.5$ cm, each hemisphere height $3.5$, cylinder height $13$ cm. Volume = $\\pi(3.5)^2\\times13 + \\frac43\\pi(3.5)^3 = 500.5$ cm³ approx.&quot; },
    { topic: &quot;Surface area (tent)&quot;, icon: &quot;fa-tent&quot;, text: &quot;A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1m and 4m, and the slant height of the top is 2.8m, find the area of the canvas used. &quot;, hint: &quot;Curved cylinder = $\\pi d h = \\pi\\times4\\times2.1 = 8.4\\pi$. Curved cone = $\\pi r l = \\pi\\times2\\times2.8 = 5.6\\pi$. Total = $14\\pi \\approx 43.98$ m².&quot; },
    { topic: &quot;Statistics (mean)&quot;, icon: &quot;fa-chart-column&quot;, text: &quot;Mean = $50$, total frequency $120$. Classes: 0-20 (17), 20-40 ($f_1$), 40-60 (32), 60-80 ($f_2$), 80-100 (19). Find $f_1$, $f_2$.&quot;, hint: &quot;$f_1+f_2 = 120-68 = 52$. Mean = $\\frac{10\\cdot17+30f_1+50\\cdot32+70f_2+90\\cdot19}{120}=50$. Solve: $f_1=28$, $f_2=24$.&quot; },
    { topic: &quot;Median &amp; Ogive&quot;, icon: &quot;fa-line-chart&quot;, text: &quot;If the mean of $x-3,x-1,7,x,2x-1,3x-5$ be $7.5$, then find the median.&quot;, hint: &quot;use the avlue of mean to calculate $x$, arrange in incsreasing order to get median as $6.5$&quot; },
    { topic: &quot;Probability (Cards)&quot;, icon: &quot;fa-heart&quot;, text: &quot;All kings, queens, and jacks are removed from a pack of 52 cards. A card is drawn from the remaining. Find the probability it is (i) a red card, (ii) a face card, (iii) a $10$ of hearts. &quot;, hint: &quot;Remaining cards = $52-12=40$. (i) red = $(26-6)/40 = 1/2$. (ii) face card = $0$. (iii) 10♥ = $1/40$.&quot; },
    { topic: &quot;Probability (Die twice)&quot;, icon: &quot;fa-dice&quot;, text: &quot;A die is thrown twice. What is the probability that the sum of the numbers appearing on them is a prime number?&quot;, hint: &quot;Total $36$. Prime sums: 2,3,5,7,11. Count = $15$. $P = 15/36 = 5/12$.&quot; }
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&lt;/script&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/674828035566765942/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/02/important-questions-for-icse-cbse-board.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/674828035566765942'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/674828035566765942'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/02/important-questions-for-icse-cbse-board.html' title='Important Questions for ICSE, CBSE Board Examination'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-1031075476597073384</id><published>2026-02-01T01:45:00.000-08:00</published><updated>2026-08-08T09:57:19.173-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="IX"/><category scheme="http://www.blogger.com/atom/ns#" term="Madhyamik"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Chapter Test Pair of Linear Equation in Two Variables CBSE ICSE</title><content type='html'>
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.q-container { max-width: 100%; margin: 0 auto; background-color: transparent; position: relative; z-index: 1; }

.q-header {
    background: linear-gradient(135deg, #13151d 0%, #1e2239 100%);
    padding: 40px 30px;
    border-radius: 0 0 var(--radius-lg) var(--radius-lg);
    box-shadow: var(--shadow-lg);
    text-align: center;
    margin-bottom: 30px;
    position: relative;
    overflow: hidden;
    border-bottom: 3px solid var(--primary-color);
}
.q-header::before { content: &#39;&#39;; position: absolute; top: 0; left: 0; right: 0; height: 4px; background: var(--primary-gradient); }
.q-logo { font-size: 2.8rem; font-weight: 900; margin-bottom: 10px; letter-spacing: -0.5px; background: var(--primary-gradient); -webkit-background-clip: text; background-clip: text; color: transparent; text-shadow: 0 4px 8px rgba(99, 102, 241, 0.3); }
.q-subtitle { font-size: 1.2rem; color: var(--text-secondary); font-weight: 400; max-width: 600px; margin: 0 auto; line-height: 1.6; }
.q-author-info { display: flex; justify-content: center; gap: 20px; margin-top: 30px; flex-wrap: wrap; font-size: 0.9rem; }
.q-author-item { background: rgba(255, 255, 255, 0.05); padding: 8px 20px; border-radius: 50px; color: var(--text-secondary); display: flex; align-items: center; gap: 8px; backdrop-filter: blur(10px); border: 1px solid var(--border-light); transition: all 0.3s ease; }
.q-author-item:hover { background: rgba(99, 102, 241, 0.1); border-color: rgba(99, 102, 241, 0.3); transform: translateY(-2px); }
.q-author-item a { color: inherit; text-decoration: none; }

.q-dashboard { display: grid; grid-template-columns: 1fr auto; gap: 30px; margin: 0 30px 30px; align-items: center; background: var(--bg-surface); padding: 25px; border-radius: var(--radius-md); box-shadow: var(--shadow-md); border: 1px solid var(--border-color); backdrop-filter: blur(10px); }
.q-dashboard-text h2 { font-size: 1.8rem; margin: 0 0 8px 0; background: var(--primary-gradient); -webkit-background-clip: text; background-clip: text; color: transparent; font-weight: 700; }
.q-dashboard-text p { margin: 0; color: var(--text-secondary); font-size: 1rem; line-height: 1.5; }
.q-stats-row { display: flex; gap: 15px; }
.q-stat-card { background: var(--bg-elevated); padding: 15px 25px; border-radius: var(--radius-sm); text-align: center; min-width: 100px; border: 1px solid var(--border-light); transition: all 0.3s ease; }
.q-stat-card:hover { transform: translateY(-3px); box-shadow: var(--shadow-glow); border-color: var(--primary-color); }
.q-stat-val { font-size: 2rem; font-weight: 800; background: var(--primary-gradient); -webkit-background-clip: text; background-clip: text; color: transparent; line-height: 1.2; }
.q-stat-lbl { font-size: 0.8rem; text-transform: uppercase; letter-spacing: 1px; color: var(--text-muted); font-weight: 600; margin-top: 4px; }

.q-instructions { background: linear-gradient(135deg, rgba(6, 78, 59, 0.2) 0%, rgba(52, 211, 153, 0.1) 100%); border: 1px solid rgba(52, 211, 153, 0.2); border-left: 4px solid var(--secondary-color); padding: 25px; border-radius: var(--radius-md); margin: 0 30px 30px; backdrop-filter: blur(10px); }
.q-instructions h3 { color: #34d399; margin: 0 0 15px 0; font-size: 1.3rem; display: flex; align-items: center; gap: 10px; font-weight: 600; }
.q-instructions ul { margin: 0; padding-left: 20px; color: #d1fae5; }
.q-instructions li { margin-bottom: 8px; padding-left: 5px; }
.q-instructions li::marker { color: var(--secondary-color); }

.q-layout { display: flex; gap: 30px; margin: 0 30px 40px; align-items: flex-start; }
.q-sidebar { flex: 0 0 280px; background: rgba(30, 34, 57, 0.8); padding: 25px; border-radius: var(--radius-md); box-shadow: var(--shadow-md); border: 1px solid var(--border-color); backdrop-filter: blur(20px); }
.q-nav-grid { display: grid; grid-template-columns: repeat(5, 1fr); gap: 10px; margin-bottom: 25px; }
.q-nav-num { aspect-ratio: 1; display: flex; align-items: center; justify-content: center; background: var(--bg-elevated); border-radius: var(--radius-sm); font-size: 1rem; font-weight: 600; color: var(--text-secondary); cursor: pointer; transition: all 0.3s cubic-bezier(0.4, 0, 0.2, 1); border: 2px solid transparent; position: relative; overflow: hidden; }
.q-nav-num:hover, .q-nav-num.active { transform: translateY(-3px) scale(1.05); box-shadow: var(--shadow-glow); border-color: var(--primary-color); }
.q-nav-num.active { background: var(--primary-gradient); color: white; }
.q-nav-num.answered { background: var(--secondary-gradient); color: white; border-color: var(--secondary-color); }

.q-progress-wrap { margin-top: 25px; padding-top: 20px; border-top: 1px solid var(--border-color); }
.q-prog-info { display: flex; justify-content: space-between; font-size: 0.9rem; color: var(--text-muted); margin-bottom: 12px; font-weight: 500; }
.q-prog-track { height: 10px; background: var(--bg-elevated); border-radius: 5px; overflow: hidden; position: relative; border: 1px solid var(--border-light); }
.q-prog-fill { height: 100%; background: var(--primary-gradient); width: 0%; transition: width 0.6s cubic-bezier(0.4, 0, 0.2, 1); position: relative; overflow: hidden; }
.q-prog-fill::after { content: &#39;&#39;; position: absolute; top: 0; left: 0; right: 0; bottom: 0; background: linear-gradient(90deg, transparent 0%, rgba(255, 255, 255, 0.2) 50%, transparent 100%); animation: shimmer 2s infinite; }
@keyframes shimmer { 0% { transform: translateX(-100%); } 100% { transform: translateX(100%); } }

.q-content-area { flex: 1; min-width: 0; }
.q-card { background: var(--bg-surface); border-radius: var(--radius-lg); padding: 35px; box-shadow: var(--shadow-lg); display: none; animation: slideIn 0.4s cubic-bezier(0.4, 0, 0.2, 1); border: 1px solid var(--border-color); backdrop-filter: blur(10px); }
.q-card.active { display: block; }
@keyframes slideIn { from { opacity: 0; transform: translateY(20px) scale(0.98); } to { opacity: 1; transform: translateY(0) scale(1); } }
.q-card-header { display: flex; justify-content: space-between; align-items: center; margin-bottom: 25px; padding-bottom: 20px; border-bottom: 1px solid var(--border-color); }
.q-card-title { font-size: 1.2rem; font-weight: 700; color: var(--primary-color); text-transform: uppercase; letter-spacing: 1px; display: flex; align-items: center; gap: 10px; }
.q-question-text { font-size: 1.4rem; font-weight: 500; margin-bottom: 30px; color: var(--text-primary); line-height: 1.7; }
.q-options { display: flex; flex-direction: column; gap: 15px; }
.q-option { position: relative; background: var(--bg-elevated); border: 2px solid var(--border-color); border-radius: var(--radius-md); padding: 20px 25px; cursor: pointer; transition: all 0.3s cubic-bezier(0.4, 0, 0.2, 1); display: flex; align-items: center; overflow: hidden; }
.q-option:hover { transform: translateX(8px); border-color: var(--primary-light); box-shadow: var(--shadow-glow); }
.q-option.selected { border-color: var(--primary-color); box-shadow: 0 0 0 4px rgba(99, 102, 241, 0.2); transform: translateX(8px); }
.q-option input { position: absolute; opacity: 0; cursor: pointer; height: 0; width: 0; }
.q-opt-marker { display: flex; align-items: center; justify-content: center; width: 40px; height: 40px; background: var(--bg-surface); border-radius: 10px; margin-right: 20px; font-weight: 700; color: var(--text-secondary); flex-shrink: 0; transition: all 0.3s ease; position: relative; z-index: 1; border: 2px solid var(--border-color); }
.q-option.selected .q-opt-marker { background: var(--primary-gradient); color: white; border-color: transparent; transform: scale(1.1); box-shadow: 0 4px 12px rgba(99, 102, 241, 0.4); }
.q-option-text { font-size: 1.15rem; color: var(--text-primary); position: relative; z-index: 1; line-height: 1.5; }

.q-actions { display: flex; justify-content: space-between; margin-top: 40px; padding-top: 25px; border-top: 1px solid var(--border-color); }
.q-btn { background: var(--bg-elevated); border: 2px solid var(--border-color); color: var(--text-primary); padding: 16px 32px; border-radius: var(--radius-sm); font-weight: 600; cursor: pointer; transition: all 0.3s cubic-bezier(0.4, 0, 0.2, 1); display: flex; align-items: center; gap: 10px; font-size: 1rem; letter-spacing: 0.5px; position: relative; overflow: hidden; }
.q-btn:hover:not(:disabled) { transform: translateY(-3px); box-shadow: var(--shadow-md); border-color: var(--primary-light); }
.q-btn-primary { background: var(--primary-gradient); color: white; border: none; box-shadow: 0 8px 20px rgba(99, 102, 241, 0.3); }
.q-btn-primary:hover:not(:disabled) { box-shadow: 0 12px 24px rgba(99, 102, 241, 0.4); transform: translateY(-3px) scale(1.02); }
.q-btn-success { background: var(--secondary-gradient); color: white; border: none; box-shadow: 0 8px 20px rgba(16, 185, 129, 0.3); }
.q-btn-success:hover:not(:disabled) { box-shadow: 0 12px 24px rgba(16, 185, 129, 0.4); transform: translateY(-3px) scale(1.02); }
.q-btn:disabled { opacity: 0.5; cursor: not-allowed; transform: none !important; box-shadow: none !important; }

.q-footer { text-align: center; margin-top: 40px; padding: 30px; border-top: 1px solid var(--border-color); color: var(--text-muted); font-size: 0.9rem; background: rgba(0, 0, 0, 0.2); backdrop-filter: blur(10px); }

/* MODAL - UPDATED RESULTS SECTION */
.q-modal-overlay { 
    position: fixed; 
    top: 0; left: 0; right: 0; bottom: 0; 
    background: rgba(10, 10, 11, 0.95); 
    display: flex; 
    justify-content: center; 
    align-items: center; 
    z-index: 10000; 
    padding: 20px; 
    backdrop-filter: blur(10px); 
    animation: fadeIn 0.4s ease; 
}
@keyframes fadeIn { from { opacity: 0; } to { opacity: 1; } }

.q-modal { 
    background: linear-gradient(135deg, #ccd9f5 0%, #abc6f3 100%); 
    width: 100%; 
    max-width: 800px; 
    max-height: 90vh; 
    overflow-y: auto; 
    border-radius: var(--radius-lg); 
    padding: 50px; 
    box-shadow: var(--shadow-lg); 
    border: 1px solid rgba(99, 102, 241, 0.2); 
    animation: modalSlideIn 0.5s cubic-bezier(0.4, 0, 0.2, 1); 
}
@keyframes modalSlideIn { 
    from { opacity: 0; transform: translateY(40px) scale(0.95); } 
    to { opacity: 1; transform: translateY(0) scale(1); } 
}

.q-result-header { 
    text-align: center; 
    margin-bottom: 40px; 
}
.q-result-header h2 { 
    font-size: 2.8rem; 
    background: linear-gradient(135deg, #00dc82 0%, #36d1dc 100%);
    -webkit-background-clip: text; 
    background-clip: text; 
    color: transparent; 
    margin-bottom: 15px; 
    font-weight: 900;
    letter-spacing: -0.5px;
}
.q-result-header p { 
    color: var(--text-secondary); 
    font-size: 1.1rem; 
    max-width: 500px;
    margin: 0 auto;
    line-height: 1.6;
}

/* MODERN SCORE CARDS */
.q-score-grid { 
    display: grid; 
    grid-template-columns: repeat(3, 1fr); 
    gap: 20px; 
    margin-bottom: 40px; 
}
.q-score-card { 
    background: linear-gradient(145deg, rgba(30, 41, 59, 0.9), rgba(15, 23, 42, 0.9));
    padding: 30px 25px; 
    border-radius: var(--radius-lg); 
    text-align: center; 
    border: 1px solid rgba(255, 255, 255, 0.1);
    transition: all 0.4s cubic-bezier(0.4, 0, 0.2, 1);
    position: relative;
    overflow: hidden;
}
.q-score-card::before {
    content: &#39;&#39;;
    position: absolute;
    top: 0;
    left: 0;
    right: 0;
    height: 4px;
    background: var(--primary-gradient);
    opacity: 0;
    transition: opacity 0.3s ease;
}
.q-score-card:hover { 
    transform: translateY(-8px) scale(1.02); 
    box-shadow: 0 20px 40px rgba(0, 0, 0, 0.4); 
    border-color: rgba(214, 215, 238, 0.3);
}
.q-score-card:hover::before {
    opacity: 1;
}

/* Specific card gradients */
.q-score-card:nth-child(1) { border-top: 4px solid #bbbcf3; }
.q-score-card:nth-child(2) { border-top: 4px solid #10b981; }
.q-score-card:nth-child(3) { border-top: 4px solid #f59e0b; }

.q-score-val { 
    font-size: 3.5rem; 
    font-weight: 900; 
    background: linear-gradient(135deg, #f8fafc 0%, #cbd5e1 100%);
    -webkit-background-clip: text; 
    background-clip: text; 
    color: transparent; 
    line-height: 1; 
    margin-bottom: 10px; 
    text-shadow: 0 2px 4px rgba(0, 0, 0, 0.2);
}
.q-score-lbl { 
    font-size: 1rem; 
    color: whitesmoke; 
    text-transform: uppercase; 
    letter-spacing: 1.5px; 
    font-weight: 600; 
    display: flex;
    align-items: center;
    justify-content: center;
    gap: 8px;
}

/* RESULTS LIST - ENHANCED VISIBILITY */
.q-ans-list { 
    list-style: none; 
    padding: 0; 
    margin-bottom: 40px; 
}
.q-ans-item { 
    padding: 20px 25px; 
    margin-bottom: 15px; 
    border-radius: var(--radius-md); 
    font-size: 1rem; 
    background: rgba(15, 23, 42, 0.8);
    border-left: 5px solid var(--border-color);
    display: flex; 
    justify-content: space-between; 
    align-items: center; 
    transition: all 0.3s ease;
    border: 1px solid rgba(255, 255, 255, 0.05);
}
.q-ans-item:hover { 
    transform: translateX(5px); 
    box-shadow: 0 8px 20px rgba(0, 0, 0, 0.3);
}

/* CORRECT - Vibrant Green */
.q-ans-item.correct { 
    border-left-color: #00ff88;
    background: linear-gradient(135deg, 
        rgba(0, 255, 136, 0.1) 0%, 
        rgba(0, 200, 120, 0.05) 100%);
    border-color: rgba(0, 255, 136, 0.2);
}
.q-ans-item.correct::before {
    content: &#39;\2714&#39;;
    color: #00ff88;
    font-weight: bold;
    margin-right: 10px;
    font-size: 1.2rem;
}

/* INCORRECT - Vibrant Red */
.q-ans-item.incorrect { 
    border-left-color: #ff4757;
    background: linear-gradient(135deg, 
        rgba(255, 71, 87, 0.1) 0%, 
        rgba(220, 50, 65, 0.05) 100%);
    border-color: rgba(255, 71, 87, 0.2);
}
.q-ans-item.incorrect::before {
    content: &#39;\2717&#39;;
    color: #ff4757;
    font-weight: bold;
    margin-right: 10px;
    font-size: 1.2rem;
}

/* UNANSWERED - Bright Amber */
.q-ans-item.unanswered { 
    border-left-color: #ffb142;
    background: linear-gradient(135deg, 
        rgba(255, 177, 66, 0.1) 0%, 
        rgba(220, 150, 50, 0.05) 100%);
    border-color: rgba(255, 177, 66, 0.2);
}
.q-ans-item.unanswered::before {
    content: &#39;\003F&#39;;
    color: #ffb142;
    font-weight: bold;
    margin-right: 10px;
    font-size: 1.2rem;
}

/* Answer item content */
.q-ans-item .question-info {
    display: flex;
    align-items: center;
    gap: 12px;
    font-weight: 600;
    color: var(--text-primary);
}

.q-ans-item .answer-info {
    font-size: 0.9rem;
    color: var(--text-secondary);
    background: rgba(0, 0, 0, 0.3);
    padding: 6px 12px;
    border-radius: 20px;
    border: 1px solid rgba(255, 255, 255, 0.1);
}

/* Modal Actions */
.q-modal-actions {
    display: flex;
    gap: 15px;
    justify-content: center;
    margin-top: 30px;
}

.q-modal-actions .q-btn {
    min-width: 150px;
}

/* RESPONSIVE */
@media (max-width: 1024px) {
    .q-layout { flex-direction: column; }
    .q-sidebar { width: 100%; order: -1; }
    .q-nav-grid { grid-template-columns: repeat(8, 1fr); }
}
@media (max-width: 768px) {
    .quiz-wrapper-modern { padding: 0; border-radius: 0; }
    .q-header { padding: 30px 20px; border-radius: 0; }
    .q-logo { font-size: 2.2rem; }
    .q-dashboard { grid-template-columns: 1fr; margin: 0 20px 20px; text-align: center; }
    .q-stats-row { justify-content: center; flex-wrap: wrap; }
    .q-stat-card { min-width: 80px; padding: 12px 20px; }
    .q-layout { margin: 0 20px 30px; }
    .q-card { padding: 25px; }
    .q-question-text { font-size: 1.2rem; }
    .q-score-grid { 
        grid-template-columns: 1fr; 
        gap: 15px; 
    }
    .q-modal { 
        padding: 30px 20px; 
        max-width: 95%;
    }
    .q-result-header h2 {
        font-size: 2.2rem;
    }
    .q-score-val {
        font-size: 2.8rem;
    }
    .q-actions { 
        flex-direction: column; 
        gap: 15px; 
    }
    .q-btn { 
        width: 100%; 
        justify-content: center; 
    }
    .q-ans-item {
        flex-direction: column;
        align-items: flex-start;
        gap: 10px;
    }
    .q-ans-item .answer-info {
        align-self: flex-end;
    }
    .q-modal-actions {
        flex-direction: column;
    }
    .q-modal-actions .q-btn {
        width: 100%;
    }
}
@media (max-width: 480px) {
    .q-nav-grid { grid-template-columns: repeat(5, 1fr); }
    .q-author-info { flex-direction: column; align-items: center; }
    .q-option { padding: 15px 20px; }
    .q-option-text { font-size: 1rem; }
    .q-result-header h2 { font-size: 1.8rem; }
    .q-score-val { font-size: 2.2rem; }
}

/* MATHJAX OVERRIDES */
.MathJax { color: #60a5fa !important; }
.MathJax_Display { 
    padding: 15px !important; 
    background: rgba(30, 41, 59, 0.8) !important; 
    border-radius: var(--radius-sm) !important; 
    border: 1px solid rgba(99, 102, 241, 0.2) !important; 
    overflow-x: auto !important; 
    margin: 20px 0 !important;
}
&lt;/style&gt;
&lt;div class=&quot;quiz-wrapper-modern&quot;&gt;
    &lt;div class=&quot;q-container&quot;&gt;
        &lt;header class=&quot;q-header&quot;&gt;
            &lt;div class=&quot;q-logo&quot;&gt;&lt;span&gt;Prime Maths&lt;/span&gt;&lt;/div&gt;
            &lt;div class=&quot;q-subtitle&quot;&gt;25 Question MCQ Prime Maths - Class X, IX CBSE, Madhyamik and ICSE&lt;/div&gt;
            &lt;div class=&quot;q-author-info&quot;&gt;
                &lt;div class=&quot;q-author-item&quot;&gt;👨‍🏫 Author: Singh&lt;/div&gt;
                &lt;div class=&quot;q-author-item&quot;&gt;📞 WA: +91-9038126497&lt;/div&gt;
                &lt;div class=&quot;q-author-item&quot;&gt;&lt;a href=&quot;https://facebook.com/prime.maths&quot; target=&quot;_blank&quot;&gt;Prime Maths&lt;/a&gt;&lt;/div&gt;
            &lt;/div&gt;
        &lt;/header&gt;

        &lt;div class=&quot;q-dashboard&quot;&gt;
            &lt;div class=&quot;q-dashboard-text&quot;&gt;
                &lt;h2&gt;Pair of Linear Equations in Two Variables&lt;/h2&gt;
                &lt;p&gt;This quiz offers a thorough evaluation of key concepts and skills related to &lt;strong&gt;Linear Equations in Two Variables&lt;/strong&gt;. 25 multiple-choice questions designed to test both theoretical understanding and practical application.&lt;/p&gt;
            &lt;/div&gt;
            &lt;div class=&quot;q-stats-row&quot;&gt;
                &lt;div class=&quot;q-stat-card&quot;&gt;
                    &lt;div class=&quot;q-stat-val&quot; id=&quot;answered-count&quot;&gt;0&lt;/div&gt;
                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Done&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;q-stat-card&quot;&gt;
                    &lt;div class=&quot;q-stat-val&quot; id=&quot;remaining-count&quot;&gt;25&lt;/div&gt;
                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Left&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;q-stat-card&quot;&gt;
                    &lt;div class=&quot;q-stat-val&quot; id=&quot;score-preview&quot;&gt;0%&lt;/div&gt;
                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Score&lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
        &lt;/div&gt;

        &lt;div class=&quot;q-instructions&quot;&gt;
            &lt;h3&gt;📝 Instructions&lt;/h3&gt;
            &lt;ul&gt;
                &lt;li&gt;This quiz contains 25 multiple choice questions.&lt;/li&gt;
                &lt;li&gt;Select only one correct answer per question.&lt;/li&gt;
                &lt;li&gt;Use the navigator to jump between questions.&lt;/li&gt;
                &lt;li&gt;Submit when you are finished to see results.&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/div&gt;

        &lt;div class=&quot;q-layout&quot;&gt;
            &lt;div class=&quot;q-sidebar&quot;&gt;
                &lt;div style=&quot;color: var(--text-primary); font-weight: 600; margin-bottom: 15px; text-align: center;&quot;&gt;Question Navigator&lt;/div&gt;
                &lt;div class=&quot;q-nav-grid&quot; id=&quot;question-nav&quot;&gt;&lt;/div&gt;
                &lt;div class=&quot;q-progress-wrap&quot;&gt;
                    &lt;div class=&quot;q-prog-info&quot;&gt;
                        &lt;span&gt;Progress&lt;/span&gt;
                        &lt;span id=&quot;progress-percentage&quot;&gt;0%&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;q-prog-track&quot;&gt;
                        &lt;div class=&quot;q-prog-fill&quot; id=&quot;progress-fill&quot;&gt;&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;q-content-area&quot;&gt;
                &lt;form id=&quot;quizForm&quot;&gt;
                    &lt;div id=&quot;questions-wrapper&quot;&gt;
                        &lt;div class=&quot;q-card active&quot; id=&quot;question-1&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 1&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;For the system of equations \(a_1x + b_1y + c_1 = 0\) and \(a_2x + b_2y + c_2 = 0\) to have a unique solution, the condition is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{a_1}{a_2} = \frac{b_1}{b_2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{a_1}{a_2} \neq \frac{b_1}{b_2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-2&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 2&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If a pair of linear equations is consistent, then the lines representing them are:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Parallel&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Always coincident&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Intersecting or coincident&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Always intersecting&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-3&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 3&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;For what value of \(k\) do the equations \(3x - y + 8 = 0\) and \(6x - ky = -16\) represent coincident lines?&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k = 2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k = -2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k = \frac{1}{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k = - \frac{1}{2}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-4&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 4&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The pair of equations \(x = a\) and \(y = b\) graphically represents lines which are:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Parallel&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Intersecting at \((b, a)\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Coincident&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Intersecting at \((a, b)\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-5&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 5&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If the system \(2x + 3y = 5\) and \(4x + ky = 10\) has infinitely many solutions, then \(k\) equals:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{3}{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(6\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-6&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 6&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The value of \(k\) for which the system \(x + 2y = 3\) and \(5x + ky + 7 = 0\) is inconsistent is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k = 10\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k = \frac{2}{5}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k = -\frac{2}{5}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k = -10\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-7&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 7&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Solve: \(\frac{x}{a}+\frac{y}{b}=2\) and \(ax-by=a^2-b^2\)&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=a, \quad y=b^2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=a, \quad y=b\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=a^2, \quad y=b^2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=a^2, \quad y=b\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-8&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 8&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The value of \(k\) for which the pair of linear equations \((3k+1)x+3y=2\) and \((k^2+1)x+(k-2)y-5=0\) has no solution.&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k=-2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k=2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k=1\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k=-1\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-9&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 9&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Solve for \(x\) and \(y\): \((a-b)x + (a+b)y = a^2 -2ab-b^2\) and \((a+b)(x+y) = a^2 + b^2\)&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = a+b, y = -\frac{2ab}{a+b}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = a+b, y = \frac{2ab}{a+b}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = a-b, y = -\frac{2ab}{a+b}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = a-b, y = \frac{2ab}{a+b}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-10&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 10&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The value of \(x\) satisfying \(\frac{5}{x-1}+\frac{1}{y-2}=2\) and \(\frac{6}{x-1}-\frac{3}{y-2}-1=0, \quad x \neq 1, y \neq 2\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;2&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;3&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;4&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;5&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-11&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 11&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If \(37x + 43y = 123\) and \(43x + 37y = 117\), then:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 2, y = 3\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 1, y = 2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 3, y = 2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = -1, y = -2\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-12&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 12&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The pair of equations \(225x + 881y = 2^{10}\) and \(450x + 1762y = 2048\) has:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;No solution&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Unique solution&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Two solutions&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Infinitely many solutions&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-13&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 13&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If \(\frac{b}{a}x + \frac{a}{b}y = a^2+b^2\) and \(x + y = 2ab\) then&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=2y\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=-y\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=y\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2x=y\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-14&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 14&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If \(2^x + 3^y = 17\) and \(2^{x+2} - 3^{y+1} = 5\), find \(x\) and \(y\).&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 9, y = 5\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 3, y = 2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 5, y = 9\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 8, y = 6\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-15&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 15&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Solve for \(x\): \(\frac{2}{x} + \frac{3}{y} = 13\) and \(\frac{5}{x} - \frac{4}{y} = -2\).&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 1/2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 1/3\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x = 3\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-16&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 16&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;For what value of \(p\) does the pair of equations \(4x + py + 8 = 0\) and \(2x + 2y + 2 = 0\) have a unique solution?&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(p = 4\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(p \neq 4\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(p = 2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(p \neq 2\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-17&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 17&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If \(49x + 51y = 499\) and \(51x + 49y = 501\), then \(x\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;3&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;5.5&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;4&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;6.5&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-18&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 18&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The difference between two numbers is 26 and one number is three times the other. Find them.&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;30, 4&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;36, 10&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;39, 13&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;40, 14&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-19&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 19&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Solve: \( \sqrt{2}x + \sqrt{3}y = 0 \) and \( \sqrt{3}x - \sqrt{8}y = 0 \).&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=1, y=1\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=\sqrt{2}, y=\sqrt{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=0, y=0\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(x=2, y=3\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-20&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 20&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Find \(k\) if the lines \(x + 2y - 1 = 0\) and \(2x + ky + 2 = 0\) are parallel.&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k=2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k=3\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k=4\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(k=-4\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-21&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 21&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Five years ago, Ramesh was thrice as old as Sonu. Ten years later, Ramesh will be twice as old as Sonu. What is Ramesh&#39;s present age?&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;40 years&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;50 years&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;60 years&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;45 years&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-22&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 22&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;A fraction becomes 9/11 if 2 is added to both numerator and denominator. If 3 is added to both, it becomes 5/6. Find the fraction.&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(7/9\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(9/7\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(5/9\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3/7\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-23&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 23&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;18&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;27&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;81&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;72&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-24&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 24&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;A taxi charge consists of a fixed charge together with the charge for the distance covered. For 10 km, the charge paid is ₹105 and for 15 km, the charge paid is ₹155. What are the fixed charges?&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;₹ 10&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;₹ 5&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;₹ 15&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;₹ 8&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-25&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 25&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Ritu can row downstream 20 km in 2 hours, and upstream 4 km in 2 hours. Find her speed of rowing in still water.&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;6 km/h&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;4 km/h&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;8 km/h&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;10 km/h&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                    &lt;/div&gt;

                    &lt;div class=&quot;q-actions&quot;&gt;
                        &lt;button class=&quot;q-btn&quot; disabled=&quot;&quot; id=&quot;prevBtn&quot; type=&quot;button&quot;&gt;&lt;span&gt;←&lt;/span&gt; Previous&lt;/button&gt;
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&lt;/script&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/1031075476597073384/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/02/chapter-test-pair-of-linear-equation-in.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/1031075476597073384'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/1031075476597073384'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/02/chapter-test-pair-of-linear-equation-in.html' title='Chapter Test Pair of Linear Equation in Two Variables CBSE ICSE'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-1230787813722366571</id><published>2026-01-31T21:07:00.000-08:00</published><updated>2026-08-08T09:57:29.892-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="Madhyamik"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Mensuration: Sphere, Cone, Cylinder and Mixed Solids MCQ Chapter Test CBSE, ICSE</title><content type='html'>

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&lt;/style&gt;



&lt;div class=&quot;quiz-wrapper-modern&quot;&gt;

    &lt;div class=&quot;q-container&quot;&gt;



        &lt;header class=&quot;q-header&quot;&gt;

            &lt;div class=&quot;q-logo&quot;&gt;&lt;span&gt;Prime Maths&lt;/span&gt;&lt;/div&gt;

            &lt;div class=&quot;q-subtitle&quot;&gt; 25 Multiple Choice Questions (MCQs) on Mensuration
Chapters Covered: Sphere, Cone, Cylinder and Mixed Solids
This question set is designed to strengthen conceptual understanding and problem-solving skills in mensuration, focusing on surface area, volume, and real-life applications of three-dimensional solids.
Applicable for: ICSE, CBSE, WBBSE and other State Board curricula
Recommended for: Secondary level students (Class IX–X)&lt;/div&gt;

            &lt;div class=&quot;q-author-info&quot;&gt;

                &lt;div class=&quot;q-author-item&quot;&gt;👨‍🏫 Author:
                    Singh&lt;/div&gt;

                &lt;div class=&quot;q-author-item&quot;&gt;📞 WA: +91-9038126497&lt;/div&gt;

                &lt;div class=&quot;q-author-item&quot;&gt;&lt;a href=&quot;https://facebook.com/prime.maths&quot; target=&quot;_blank&quot;&gt;Prime Maths&lt;/a&gt;
                &lt;/div&gt;

            &lt;/div&gt;

        &lt;/header&gt;



        &lt;div class=&quot;q-dashboard&quot;&gt;

            &lt;div class=&quot;q-dashboard-text&quot;&gt;

                &lt;h2&gt;Mensuration Chapter Test&lt;/h2&gt;

                &lt;p&gt;Test your understanding of three dimensional solids- Sphere, Cone &amp;amp; Cylinder&lt;/p&gt;

            &lt;/div&gt;

            &lt;div class=&quot;q-stats-row&quot;&gt;

                &lt;div class=&quot;q-stat-card&quot;&gt;

                    &lt;div class=&quot;q-stat-val&quot; id=&quot;answered-count&quot;&gt;0&lt;/div&gt;

                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Done&lt;/div&gt;

                &lt;/div&gt;

                &lt;div class=&quot;q-stat-card&quot;&gt;

                    &lt;div class=&quot;q-stat-val&quot; id=&quot;remaining-count&quot;&gt;25&lt;/div&gt;

                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Left&lt;/div&gt;

                &lt;/div&gt;

                &lt;div class=&quot;q-stat-card&quot;&gt;

                    &lt;div class=&quot;q-stat-val&quot; id=&quot;score-preview&quot;&gt;0%&lt;/div&gt;

                    &lt;div class=&quot;q-stat-lbl&quot;&gt;Score&lt;/div&gt;

                &lt;/div&gt;

            &lt;/div&gt;

        &lt;/div&gt;



        &lt;div class=&quot;q-instructions&quot;&gt;

            &lt;h3&gt;📝 Instructions&lt;/h3&gt;

            &lt;ul&gt;

                &lt;li&gt;This quiz contains 25 multiple choice questions.&lt;/li&gt;

                &lt;li&gt;Select only one correct answer per question.&lt;/li&gt;

                &lt;li&gt;Use the navigator to jump between questions.&lt;/li&gt;

                &lt;li&gt;Submit when you are finished to see results.&lt;/li&gt;

            &lt;/ul&gt;

        &lt;/div&gt;



        &lt;div class=&quot;q-layout&quot;&gt;

            &lt;div class=&quot;q-sidebar&quot;&gt;

                &lt;div style=&quot;color: var(--text-color); font-weight: 600; margin-bottom: 15px; text-align: center;&quot;&gt;
                    Question Navigator&lt;/div&gt;

                &lt;div class=&quot;q-nav-grid&quot; id=&quot;question-nav&quot;&gt;

                &lt;/div&gt;



                &lt;div class=&quot;q-progress-wrap&quot;&gt;

                    &lt;div class=&quot;q-prog-info&quot;&gt;

                        &lt;span&gt;Progress&lt;/span&gt;

                        &lt;span id=&quot;progress-percentage&quot;&gt;0%&lt;/span&gt;

                    &lt;/div&gt;

                    &lt;div class=&quot;q-prog-track&quot;&gt;

                        &lt;div class=&quot;q-prog-fill&quot; id=&quot;progress-fill&quot;&gt;&lt;/div&gt;

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            &lt;div class=&quot;q-content-area&quot;&gt;

                &lt;form id=&quot;quizForm&quot;&gt;



                    &lt;div id=&quot;questions-wrapper&quot;&gt;

                        &lt;div class=&quot;q-card active&quot; id=&quot;question-1&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;

                                &lt;span class=&quot;q-card-title&quot;&gt;Question 1&lt;/span&gt;

                            &lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;

                                A circular metallic sheet is divided into two parts in such a way that each part can be
                                folded
                                in to a cone. If the ratio of their curved surface areas is \(1 : 2\), then the ratio of
                                their volumes
                                is

                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        1:8\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        1:\sqrt{6}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        1:\sqrt{10}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(
                                        2:3\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-2&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 2&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;There is a right circular cone of height \(h\) and vertical angle
                                \(60^{\circ} \) . A sphere when placed inside the cone, it touches the curved surface and the base of the cone. The volume of
                                sphere is&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4}{3} \pi h^{3}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4}{9} \pi h^{3}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4}{27} \pi h^{3}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4}{81} \pi h^{3}\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-3&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 3&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A sealed bottle containing some water is made
up of two cylinders A and B of radius 1.5 cm and
3 cm respectively; as shown in the figure. When
the bottle is placed right up on a table, the height
of water in it is 15 cm, but when placed upside
down, the height of water is 24 cm. The height of
the bottle is&lt;/div&gt;
&lt;iframe allow=&quot;autoplay; clipboard-write; encrypted-media; picture-in-picture; web-share&quot; allowfullscreen=&quot;true&quot; frameborder=&quot;0&quot; height=&quot;590&quot; scrolling=&quot;no&quot; src=&quot;https://www.facebook.com/plugins/post.php?href=https%3A%2F%2Fwww.facebook.com%2Fprime.maths%2Fposts%2Fpfbid02YkLT2Xh3tXW2YMkFkpRwkxTmi5kVZXRgwbbZ24xuEep9vMAx6WHUdsRQCVQreV2Ll&amp;amp;show_text=true&amp;amp;width=500&quot; style=&quot;border: none; overflow: hidden;&quot; width=&quot;500&quot;&gt;&lt;/iframe&gt;
                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 25 \quad cm
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 26 \quad cm
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 27 \quad cm
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 28 \quad cm
                                        \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-4&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 4&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A solid sphere is cut into identical pieces by three mutually perpendicular planes
                                passing through its centre. Increase in total surfae area of all the pieces with respect to the total
                                surface area of the original sphere is 
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(250\)%&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(175\)%&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(150\)%&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(125\)%&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-5&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 5&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Let the volume of a solid sphere be \(288\pi \quad cm^3 \). A horizontal plane cuts the sphere at a
distance of \(3\) cm from the centre so that the ratio of the curved surface areas of the two parts
of the sphere is \(3 : 1\). The total surface area of the bigger part of the sphere (in \(cm^2\)
) is:&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(36\pi\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(108\pi\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(135\pi\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1144\pi\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-6&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 6&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A solid metallic cylinder of height \(10\) cm and diameter \(14\) cm is melted to make two cones in
the proportion of their volumes as \(3 : 4\), keeping the height \(10\) cm, what would be the
percentage increase in the flat surface area?&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 9 \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 16 \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 50 \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 200 \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-7&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 7&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A copper wire \(3\) mm in diameter is rounded about a cylinder
whose length is \(1.2\) m and diameter is \(10\) cm, so as to cover
the curved surface of the cylinder. The length of the wire
is&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 125.6
                                        \)m&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 1256
                                        \)m&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 12.56
                                        \)m&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 1.256
                                        \)m&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-8&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 8&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A piece of paper is in the form of a sector, making an
angle \(\alpha\). The paper is rolled to form a right circular
cone of radius \(5\) cm and height \(12\) cm. Then the value
of angle \(\alpha\) is&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{10\pi}{13}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{9\pi}{13}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{5\pi}{13}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{6\pi}{13}\)
                                        &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-9&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 9&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Surface area of a cube is double that of surface area of
a sphere. The ratio of their volumes is given by&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{\frac{3}{\pi}}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\sqrt{\frac{\pi}{3}}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(4\sqrt{\frac{3\pi}{2}}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3\sqrt{\frac{4}{\pi}}\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-10&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 10&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A right circular cone has for its base a circle having the
same radius as a given sphere. The volume of the cone is
one-half that of the sphere. The ratio of the altitude of the
cone to the radius of its base is:&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1:1\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1:2\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2:1\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2:3\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-11&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 11&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A rectangle of length \(a\) and breadth \(b\) is revolved \(360°\)
about its length. The volume of the resulting cylinder is :&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\pi ab^2\) cu. units&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\pi a^2b\) cu. units&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\pi ab\) cu. units&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\pi ab\) cu. units&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-12&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 12&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;The diameter of a solid metallic right circular cylinder is
equal to its height. After cutting out the largest possible solid
sphere \(S\) from this cylinder, the remaining material is recast
to form a solid sphere \(S_1\). What is the ratio of the radius of
sphere \(S\) to that of sphere \(S_1\)?&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1:2^{1/3}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2^{1/3} :1                              \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2^{1/3} :3^{1/3}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3^{1/3}:2^{1/3}\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-13&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 13&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;The radius of a cylindrical box is \(8\) cm and the height is
\(3\) cm. The number of cm that may be added to either the
radius or the height so that in either case the volume of the
cylinder increases by same magnitude is:&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(5\frac{1}{3}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(7\frac{1}{2}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(24\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-14&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 14&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;The diameter of a right circular cylinder is decreased by
\(10\)%. The volume of cylinder remains the same then the
percentage increase in height is:&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 20
                                        \)%&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 23.45
                                        \)%&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 5
                                        \)%&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 20.5
                                        \)%&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-15&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 15&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;The volume of a sphere having radius \(\sqrt[3]{2}\) cm is equal to
the volume of a right circular cone whose lateral surface
area is three times of the area of the base. The altitude of the cone is 
&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt; 4 cm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;6 cm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;8 cm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;10 cm&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-16&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 16&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A right circular cylinder has its height equal to two times
its radius. It is inscribed in a right circular cone having its
diameter equal to \(10\) cm and height \(12\) cm, and the axes of both the cylinder and the cone coincide. Then, the volume (in \(cm^3\)
) of the cylinder is approximately 
&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;107.5&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;118.6&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;127.5&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;128.7&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-17&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 17&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A solid sphere of redius \(x\) cm is melted and cast into the
shape of a solid cone of height \(x\) cm, the radius of the base
of the cone is:&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( x                                        \) cm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 4x                                       \) cm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 3x                                       \) cm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 2x
                                        \) cm&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-18&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 18&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Four pipes each of \(5\) cm in diameter are to be replaced by
a single pipe discharging the same quantity of water. If the
speed of water remains same in both the cases, then the
diameter (in cm) of the single pipe is: 
&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;5&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;6&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;10&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;12&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-19&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 19&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A copper rod of diameter \(1\) cm and length \(8\) cm is drawn into
a wire of length \(18\) m of uniform thickness. The thickness of the wire is 
(1) 0.67 mm (2) 1/30 cm
(3) 0.5 mm (4) 0.7 cm&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(0.67\) mm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{30} \) cm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(0.5\) mm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(0.7\) cm&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-20&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 20&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A solid hemispherical shell of outer and inner radius \(R\) cm and \(r\) cm respectively is cut by
                                a horizontal plane along its centre. The ratio of the total surface area of two new solid hemisphercal shell to the original spherical shell is:
                            &lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{4R^2+r^2}{2(R^2+r^2)}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{3R^2+r^2}{2(R^2+r^2)}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{3R^2+2r^2}{2(R^2+r^2)}\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;None of the above&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-21&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 21&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A right circular cylinder of volume \(1386\) cm³ is cut from a right circular cylinder of radius \(4\) cm and height \(49\) cm, such that a hollow cylinder of uniform thickness, with a height of \(49\) cm and an outer radius of \(4\) cm is left behind. The thickness of the hollow cylinder left behind is:

&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 0.5                                       \) cm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\) cm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 2 \) cm&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 1                                     \) cm&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-22&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 22&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A conical cup when filled with ice cream forms a hemispherical shape on its open end. Find the volume of ice cream (approximately), if radius of the base of the cone is \(3.5\) cm, the vertical height of cone is \(7\) cm and width of the cone is negligible.

&lt;/div&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;120 cm³                                      &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;150 cm³                                       &lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;180 cm³&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;210 cm³                             &lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-23&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 23&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;Shown below is a horizontal water tank composed of a cylinder and two hemispheres. The tank is filled up to a height of \(7\) m. Find the surface area of the tank in contact with water. Use \(\pi = \frac{22}{7}\)	​
.&lt;/div&gt;
&lt;img alt=&quot;Description&quot; width=&quot;500&quot; height =&quot;400&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpQo6HwPmhk27H83eLlU89Cu65ubz_cwwDH52pDlAcc6-q4Lnc8lE7i8bfGjFucVlT1kOfJNv9kqOl-qfziCGWt2RtWO55O77T4LSD8FcDDmnf2AeibCkWPH9SbNCndkdONHDz7dgBtdVH65HWFj_28sEQP-HWQwTfhR8ygcfJOa9Ponr1vh8uN35J8kQ/s1536/M_23.jpg&quot; /&gt;

                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 784 \quad m^2                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 648 \quad m^2
                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 728 \quad m^2                                        \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(748 \quad m^2                               \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-24&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 24&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;A tent is in the shape of a cylinder surmounted by a conical top. If the height and radius of the cylindrical part are \(7\) m each and the total height of the tent is \(14\) m. Find the radius of a sphere whose volume is equal to the quantity of air inside the tent. 
                                Use \(\pi = \frac{22}{7}\)                   &lt;/div&gt;

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                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 7 \quad m                                      \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 6 \quad m                                   \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 14 \quad m                                       \)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\( 8 \quad m
                                        \)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;



                        &lt;div class=&quot;q-card&quot; id=&quot;question-25&quot;&gt;

                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 25&lt;/span&gt;&lt;/div&gt;

                            &lt;div class=&quot;q-question-text&quot;&gt;In the diagram given below, a tilted right circular cylindrical vessel with
base diameter \(7\) cm contains a liquid. When placed vertically, the height of
the liquid in the vessel is the mean of two heights shown in the diagram.
Find the area of wet surface, when the cylinder is placed vertically on a
horizontal surface. Use \(\pi = \frac{22}{7}\) 
&lt;p&gt;&lt;img alt=&quot;Description&quot; width=&quot;400&quot; height =&quot;400&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEge5utxtMlEMCbCejJ0OAHJm0TQkjKGCLztNpTaE1NMogtqsTiGimoBxGJOTtryiUbJH9nzfpcIqF24FAiLVz8itwAITOuWS8Ovxvi3OnMjBkSlOt5M7Cap9iofIg2KHCY-jU_-7ucP2woiFMzXWt3tYYAfeCZU89BrhMa_tf5viV1Vq6fbuIFgYZyeVWQ/s526/M_25.jpg&quot; /&gt;
&lt;/p&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(125. 5 \quad m^2\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(115. 5 \quad m^2\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(110. 5 \quad m^2\)&lt;/span&gt;&lt;/label&gt;

                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(135. 5 \quad m^2\)&lt;/span&gt;&lt;/label&gt;

                            &lt;/div&gt;

                        &lt;/div&gt;

                    &lt;/div&gt;



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            &lt;div class=&quot;q-logo&quot;&gt;&lt;span&gt;Prime Maths&lt;/span&gt;&lt;/div&gt;
            &lt;div class=&quot;q-subtitle&quot;&gt;25 Question MCQ Chapter on Real Numbers for CBSE, ICSE, Madhyamik and other State Boards Class IX &amp; X&lt;/div&gt;
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                &lt;div class=&quot;q-author-item&quot;&gt;👨‍🏫 Author: Singh&lt;/div&gt;
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                &lt;div class=&quot;q-author-item&quot;&gt;&lt;a href=&quot;https://facebook.com/prime.maths&quot; target=&quot;_blank&quot;&gt;Prime Maths&lt;/a&gt;&lt;/div&gt;
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            &lt;div class=&quot;q-dashboard-text&quot;&gt;
                &lt;h2&gt;Real Numbers Quiz&lt;/h2&gt;
                &lt;p&gt;Test your understanding of rational, irrational numbers and their properties. The study of Real Numbers in Classes IX and X establishes the foundation for all higher-level mathematics.Real Numbe: The set including all Rational and Irrational numbers. Rational Numbers: Numbers expressible as p/q, q is non-zero . Their decimal expansions are either terminating or non-terminating recurring.Irrational Numbers: Numbers that cannot be written as fractions. Their decimal expansions are non-terminating non-recurring.Number Line: Every point on a number line represents a unique real number.&lt;/p&gt;
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                                &lt;span class=&quot;q-card-title&quot;&gt;Question 1&lt;/span&gt;
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                            &lt;div class=&quot;q-question-text&quot;&gt;
                                Which of the following is an irrational number?
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                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{25}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{2} + \sqrt{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{3}{7}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q1&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(0.\overline{3}\)&lt;/span&gt;&lt;/label&gt;
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                        &lt;!-- Question 2 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-2&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 2&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The decimal expansion of \(\frac{13}{625}\) will terminate after how many decimal places?&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;2&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;3&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;4&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q2&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;5&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 3 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-3&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 3&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Which of the following has a terminating decimal expansion?&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{77}{210}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{23}{30}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{125}{441}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q3&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{129}{2^2 \times 5^7}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 4 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-4&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 4&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The simplified value of \(\sqrt{12} + \sqrt{27} - \sqrt{75}\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\sqrt{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3\sqrt{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q4&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(0\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 5 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-5&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 5&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If \(p\) and \(q\) are co-prime numbers, then \(p^2\) and \(q^2\) are:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Co-prime&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Not co-prime&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Even numbers&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q5&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Odd numbers&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 6 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-6&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 6&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;A rational number between \(\sqrt{2}\) and \(\sqrt{3}\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{\sqrt{2} + \sqrt{3}}{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{\sqrt{2} \times \sqrt{3}}{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1.5\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q6&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1.8\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 7 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-7&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 7&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The value of \(1.\overline{36} + 0.\overline{9}\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2.\overline{27}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2.\overline{26}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2.\overline{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q7&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2.3\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 8 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-8&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 8&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Which of the following is not an irrational number?&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{8} \times \sqrt{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{18} \div \sqrt{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{5} + \sqrt{10}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q8&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{7} \times \sqrt{28}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 9 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-9&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 9&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If \(n\) is a natural number, then \(\sqrt{n}\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Always rational&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Always irrational&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Rational if \(n\) is a perfect square&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q9&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Irrational if \(n\) is a perfect square&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 10 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-10&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 10&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The product of a non-zero rational and an irrational number is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Always rational&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Always irrational&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Can be rational or irrational&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q10&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Always an integer&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 11 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-11&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 11&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Which of the following rational numbers have terminating decimal representation?&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{16}{125}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{27}{250}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{343}{2^3 \times 5^3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q11&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;All of these&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 12 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-12&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 12&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The ascending order of \(\sqrt[3]{2}, \sqrt{3}, \sqrt[6]{5}\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt[3]{2} &lt; \sqrt[6]{5} &lt; \sqrt{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt[6]{5} &lt; \sqrt[3]{2} &lt; \sqrt{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt[6]{5} &lt; \sqrt{3} &lt; \sqrt[3]{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q12&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{3} &lt; \sqrt[3]{2} &lt; \sqrt[6]{5}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 13 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-13&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 13&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The decimal expansion of the rational number \(\frac{14587}{1250}\) will terminate after:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;One decimal place&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Two decimal places&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Three decimal places&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q13&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Four decimal places&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 14 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-14&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 14&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;After rationalizing the denominator of \(\frac{7}{3\sqrt{3} - 2\sqrt{2}}\), we get:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3\sqrt{3} + 2\sqrt{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3\sqrt{3} - 2\sqrt{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(7(3\sqrt{3} + 2\sqrt{2})\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q14&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(7(3\sqrt{3} - 2\sqrt{2})\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 15 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-15&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 15&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;An irrational number between \(\frac{1}{7}\) and \(\frac{2}{7}\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{2}\left(\frac{1}{7} + \frac{2}{7}\right)\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{\frac{1}{7} \times \frac{2}{7}}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{1}{\sqrt{14}}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q15&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{0.14}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 16 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-16&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 16&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If \(x = 2 + \sqrt{3}\), then \(x + \frac{1}{x}\) equals:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(4\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\sqrt{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(-4\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q16&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(-2\sqrt{3}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 17 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-17&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 17&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Which of the following is a rational number?&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\pi\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(0.\overline{101}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q17&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{5} + 1\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 18 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-18&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 18&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The simplest rationalizing factor of \(\sqrt[3]{54}\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt[3]{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt[3]{3}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt[3]{4}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q18&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt[3]{9}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 19 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-19&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 19&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If \(\frac{p}{q}\) is a rational number with terminating decimal expansion, where \(p\) and \(q\) are co-prime, then \(q\) must be of the form:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2^m \times 3^n\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2^m \times 5^n\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(3^m \times 5^n\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q19&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2^m \times 3^n \times 5^k\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 20 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-20&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 20&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The sum of two irrational numbers is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Always irrational&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Always rational&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Can be rational or irrational&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q20&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Always an integer&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 21 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-21&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 21&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The value of \(\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \cdots + \frac{1}{\sqrt{99} + \sqrt{100}}\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(1\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(9\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(10\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q21&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(99\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 22 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-22&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 22&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;If \(a\) and \(b\) are rational numbers and \(\frac{3 + 2\sqrt{3}}{3 - 2\sqrt{3}} = a + b\sqrt{3}\), then \(a + b =\)&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(11\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(-11\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(13\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q22&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(-13\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 23 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-23&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 23&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;Which of the following is not true?&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Every integer is a rational number&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Every whole number is a natural number&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Every irrational number is a real number&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q23&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;Every rational number is a real number&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 24 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-24&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 24&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The product \(\sqrt[3]{2} \times \sqrt[4]{2} \times \sqrt[12]{32}\) equals:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt[12]{2}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q24&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\sqrt[12]{32}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;

                        &lt;!-- Question 25 --&gt;
                        &lt;div class=&quot;q-card&quot; id=&quot;question-25&quot;&gt;
                            &lt;div class=&quot;q-card-header&quot;&gt;&lt;span class=&quot;q-card-title&quot;&gt;Question 25&lt;/span&gt;&lt;/div&gt;
                            &lt;div class=&quot;q-question-text&quot;&gt;The value of \(0.\overline{6} + 0.\overline{7} + 0.\overline{4}\) is:&lt;/div&gt;
                            &lt;div class=&quot;q-options&quot;&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;a&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;A&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(2\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;b&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;B&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{17}{9}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;c&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;C&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{53}{22}\)&lt;/span&gt;&lt;/label&gt;
                                &lt;label class=&quot;q-option&quot;&gt;&lt;input name=&quot;q25&quot; type=&quot;radio&quot; value=&quot;d&quot; /&gt;&lt;span class=&quot;q-opt-marker&quot;&gt;D&lt;/span&gt;&lt;span class=&quot;q-option-text&quot;&gt;\(\frac{59}{22}\)&lt;/span&gt;&lt;/label&gt;
                            &lt;/div&gt;
                        &lt;/div&gt;
                    &lt;/div&gt;

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        const answerKey = {
    1: &quot;b&quot;, 2: &quot;c&quot;, 3: &quot;d&quot;, 4: &quot;d&quot;, 5: &quot;a&quot;,
    6: &quot;c&quot;, 7: &quot;a&quot;, 8: &quot;a&quot;, 9: &quot;c&quot;, 10: &quot;b&quot;, // Q8 is technically A, B, and D. Key A kept.
    11: &quot;d&quot;, 12: &quot;a&quot;, 13: &quot;d&quot;, 14: &quot;c&quot;, 15: &quot;c&quot;, // Q12 corrected to &#39;a&#39;
    16: &quot;a&quot;, 17: &quot;c&quot;, 18: &quot;c&quot;, 19: &quot;b&quot;, 20: &quot;c&quot;, // Q18 corrected to &#39;c&#39;
    21: &quot;b&quot;, 22: &quot;b&quot;, 23: &quot;b&quot;, 24: &quot;b&quot;, 25: &quot;b&quot;  // Q22 to &#39;b&#39;, Q25 to &#39;b&#39;
};

        // DOM elements
        const questionNav = document.getElementById(&#39;question-nav&#39;);
        const prevBtn = document.getElementById(&#39;prevBtn&#39;);
        const nextBtn = document.getElementById(&#39;nextBtn&#39;);
        const submitBtn = document.getElementById(&#39;submitBtn&#39;);
        const answeredCountEl = document.getElementById(&#39;answered-count&#39;);
        const remainingCountEl = document.getElementById(&#39;remaining-count&#39;);
        const scorePreviewEl = document.getElementById(&#39;score-preview&#39;);
        const progressPercentageEl = document.getElementById(&#39;progress-percentage&#39;);
        const progressFillEl = document.getElementById(&#39;progress-fill&#39;);

        // Initialize question navigation
        function initQuestionNavigation() {
            questionNav.innerHTML = &#39;&#39;;
            for (let i = 1; i &lt;= totalQuestions; i++) {
                const questionNumber = document.createElement(&#39;div&#39;);
                questionNumber.className = &#39;q-nav-num&#39;;
                questionNumber.textContent = i;
                questionNumber.dataset.question = i;

                questionNumber.addEventListener(&#39;click&#39;, function () {
                    navigateToQuestion(parseInt(this.dataset.question));
                });

                questionNav.appendChild(questionNumber);
            }

            // Set first question as active
            updateNavState(1);
        }

        // Update nav classes
        function updateNavState(current) {
            document.querySelectorAll(&#39;.q-nav-num&#39;).forEach(el =&gt; {
                el.classList.remove(&#39;active&#39;);
                if (parseInt(el.dataset.question) === current) {
                    el.classList.add(&#39;active&#39;);
                }
            });
        }

        // Navigate to a specific question
        function navigateToQuestion(questionNum) {
            // Hide current
            const currentContainer = document.getElementById(`question-${currentQuestion}`);
            currentContainer.classList.remove(&#39;active&#39;);

            // Update index
            currentQuestion = questionNum;

            // Show new
            document.getElementById(`question-${currentQuestion}`).classList.add(&#39;active&#39;);
            updateNavState(currentQuestion);

            // Update buttons
            updateNavigationButtons();

            // Trigger MathJax render if needed
            if (window.MathJax) {
                MathJax.typesetPromise();
            }
        }

        // Update navigation buttons state
        function updateNavigationButtons() {
            prevBtn.disabled = currentQuestion === 1;

            if (currentQuestion === totalQuestions) {
                submitBtn.style.display = &#39;inline-flex&#39;;
                nextBtn.style.display = &#39;none&#39;;
            } else {
                submitBtn.style.display = &#39;none&#39;;
                nextBtn.style.display = &#39;inline-flex&#39;;
            }
        }

        // Update stats
        function updateStats() {
            const answeredCount = answers.filter(answer =&gt; answer !== null).length;
            const remainingCount = totalQuestions - answeredCount;
            const progressPercentage = Math.round((answeredCount / totalQuestions) * 100);

            answeredCountEl.textContent = answeredCount;
            remainingCountEl.textContent = remainingCount;
            progressPercentageEl.textContent = `${progressPercentage}%`;
            progressFillEl.style.width = `${progressPercentage}%`;

            // Score preview
            let correctCount = 0;
            for (let i = 1; i &lt;= totalQuestions; i++) {
                if (answers[i] &amp;&amp; answerKey[i] &amp;&amp; answers[i] === answerKey[i]) {
                    correctCount++;
                }
            }
            const scorePercentage = Math.round((correctCount / totalQuestions) * 100);
            scorePreviewEl.textContent = `${scorePercentage}%`;

            // Update nav colors
            for (let i = 1; i &lt;= totalQuestions; i++) {
                const questionNumberEl = document.querySelector(`.q-nav-num[data-question=&quot;${i}&quot;]`);
                if (answers[i] !== null) {
                    questionNumberEl.classList.add(&#39;answered&#39;);
                } else {
                    questionNumberEl.classList.remove(&#39;answered&#39;);
                }
            }
        }

        // Handle option selection
        function setupOptionSelection() {
            for (let i = 1; i &lt;= totalQuestions; i++) {
                const options = document.querySelectorAll(`input[name=&quot;q${i}&quot;]`);
                options.forEach(option =&gt; {
                    option.addEventListener(&#39;change&#39;, function () {
                        answers[i] = this.value;

                        const questionContainer = document.getElementById(`question-${i}`);
                        questionContainer.querySelectorAll(&#39;.q-option&#39;).forEach(opt =&gt; {
                            opt.classList.remove(&#39;selected&#39;);
                        });

                        if (this.checked) {
                            this.closest(&#39;.q-option&#39;).classList.add(&#39;selected&#39;);
                        }
                        updateStats();
                    });
                });
            }
        }

        // Initialize
        initQuestionNavigation();
        updateNavigationButtons();
        setupOptionSelection();
        updateStats();

        // Listeners
        prevBtn.addEventListener(&#39;click&#39;, () =&gt; {
            if (currentQuestion &gt; 1) navigateToQuestion(currentQuestion - 1);
        });

        nextBtn.addEventListener(&#39;click&#39;, () =&gt; {
            if (currentQuestion &lt; totalQuestions) navigateToQuestion(currentQuestion + 1);
        });

        submitBtn.addEventListener(&#39;click&#39;, () =&gt; {
            const answeredCount = answers.filter(answer =&gt; answer !== null).length;
            if (answeredCount &lt; totalQuestions) {
                if (confirm(`You have answered ${answeredCount} out of ${totalQuestions} questions. Submit anyway?`)) {
                    showResults();
                }
            } else {
                showResults();
            }
        });

        // Show results
        function showResults() {
            const answeredCount = answers.filter(answer =&gt; answer !== null).length;
            const unansweredCount = totalQuestions - answeredCount;
            let correctCount = 0;

            let scoreDetails = &quot;&lt;h3 class=&#39;q-result-header&#39;&gt;Detailed Breakdown&lt;/h3&gt;&lt;ul class=&#39;q-ans-list&#39;&gt;&quot;;

            for (let i = 1; i &lt;= totalQuestions; i++) {
                const userAnswer = answers[i];
                const correctAnswer = answerKey[i];
                const isCorrect = userAnswer === correctAnswer;

                if (isCorrect) correctCount++;

                scoreDetails += `&lt;li class=&quot;q-ans-item ${userAnswer === null ? &#39;unanswered&#39; : (isCorrect ? &#39;correct&#39; : &#39;incorrect&#39;)}&quot;&gt;`;
                scoreDetails += `&lt;strong&gt;Q${i}:&lt;/strong&gt; `;
                if (userAnswer === null) {
                    scoreDetails += `Skipped (Correct: ${correctAnswer.toUpperCase()})`;
                } else if (isCorrect) {
                    scoreDetails += `Correct (${userAnswer.toUpperCase()})`;
                } else {
                    scoreDetails += `Incorrect (Selected: ${userAnswer.toUpperCase()} | Correct: ${correctAnswer.toUpperCase()})`;
                }
                scoreDetails += `&lt;/li&gt;`;
            }
            scoreDetails += &quot;&lt;/ul&gt;&quot;;

            const scorePercentage = Math.round((correctCount / totalQuestions) * 100);

            const resultHTML = `
            &lt;div class=&quot;q-modal-overlay&quot; id=&quot;resultModal&quot;&gt;
                &lt;div class=&quot;q-modal&quot;&gt;
                    &lt;div class=&quot;q-result-header&quot;&gt;
                        &lt;h2&gt;Quiz Results&lt;/h2&gt;
                        &lt;p&gt;${scorePercentage &gt;= 70 ? &quot;Great job!&quot; : &quot;Keep practicing!&quot;}&lt;/p&gt;
                    &lt;/div&gt;
                    
                    &lt;div class=&quot;q-score-grid&quot;&gt;
                        &lt;div class=&quot;q-score-card&quot;&gt;
                            &lt;div class=&quot;q-score-val&quot;&gt;${correctCount}/${totalQuestions}&lt;/div&gt;
                            &lt;div class=&quot;q-score-lbl&quot;&gt;Correct&lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-score-card&quot;&gt;
                            &lt;div class=&quot;q-score-val&quot;&gt;${scorePercentage}%&lt;/div&gt;
                            &lt;div class=&quot;q-score-lbl&quot;&gt;Score&lt;/div&gt;
                        &lt;/div&gt;
                        &lt;div class=&quot;q-score-card&quot;&gt;
                            &lt;div class=&quot;q-score-val&quot;&gt;${unansweredCount}&lt;/div&gt;
                            &lt;div class=&quot;q-score-lbl&quot;&gt;Skipped&lt;/div&gt;
                        &lt;/div&gt;
                    &lt;/div&gt;
                    
                    ${scoreDetails}
                    
                    &lt;div style=&quot;text-align:center; display:flex; gap:10px; justify-content:center;&quot;&gt;
                        &lt;button class=&quot;q-btn q-btn-primary&quot; onclick=&quot;location.reload()&quot;&gt;Retake Quiz&lt;/button&gt;
                        &lt;button class=&quot;q-btn&quot; onclick=&quot;document.getElementById(&#39;resultModal&#39;).remove()&quot;&gt;Close&lt;/button&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
        `;

            document.body.insertAdjacentHTML(&#39;beforeend&#39;, resultHTML);
        }
    })();
&lt;/script&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/4795112378246310218/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/01/prime-maths-real-numbers-quiz-root.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/4795112378246310218'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/4795112378246310218'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/01/prime-maths-real-numbers-quiz-root.html' title='Real Numbers : Assessment for classes IX and X '/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-4334721846144646377</id><published>2026-01-15T03:45:00.000-08:00</published><updated>2026-08-08T09:57:50.637-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="Madhyamik"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Madhyamik Practice Test Paper</title><content type='html'>&lt;!DOCTYPE html&gt;
&lt;html lang=&quot;en&quot;&gt;
&lt;head&gt;
    &lt;meta charset=&quot;UTF-8&quot;&gt;
    &lt;meta name=&quot;viewport&quot; content=&quot;width=device-width, initial-scale=1.0&quot;&gt;
    &lt;title&gt;Class X Mathematics Practice Test Paper&lt;/title&gt;
    
    &lt;script id=&quot;MathJax-script&quot; async src=&quot;https://cdn.jsdelivr.net/npm/mathjax@3/es5/tex-mml-chtml.js&quot;&gt;&lt;/script&gt;
    &lt;link rel=&quot;stylesheet&quot; href=&quot;https://cdnjs.cloudflare.com/ajax/libs/font-awesome/6.4.0/css/all.min.css&quot;&gt;
    &lt;style&gt;
        .table-container {
            overflow-x: auto;
            margin: 20px 0;
        }

        table {
            width: 100%;
            border-collapse: collapse;
            margin: 10px 0;
        }

        th, td {
            border: 1px solid #cbd5e1;
            padding: 12px 15px;
            text-align: center;
        }

        th {
            background-color: #f1f5f9;
            color: #334155;
            font-weight: 600;
        }
        * {
            margin: 0;
            padding: 0;
            box-sizing: border-box;
            font-family: &#39;Inter&#39;, &#39;Segoe UI&#39;, system-ui, -apple-system, sans-serif;
        }
        
        body {
            background: linear-gradient(135deg, #f8fafc 0%, #f1f5f9 100%);
            color: #334155;
            line-height: 1.7;
            padding: 20px;
            min-height: 100vh;
        }
        
        .container {
            max-width: 1200px;
            margin: 0 auto;
            background-color: white;
            border-radius: 20px;
            box-shadow: 0 10px 30px rgba(0, 0, 0, 0.08);
            overflow: hidden;
            position: relative;
        }
        
        .exam-header {
            background: linear-gradient(135deg, #3b82f6 0%, #60a5fa 100%);
            color: white;
            padding: 40px 30px;
            text-align: center;
            position: relative;
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        }
        
        .exam-header::before {
            content: &#39;&#39;;
            position: absolute;
            top: 0;
            left: 0;
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            background: url(&quot;data:image/svg+xml,%3Csvg width=&#39;100&#39; height=&#39;100&#39; viewBox=&#39;0 0 100 100&#39; xmlns=&#39;http://www.w3.org/2000/svg&#39;%3E%3Cpath d=&#39;M11 18c3.866 0 7-3.134 7-7s-3.134-7-7-7-7 3.134-7 7 3.134 7 7 7zm48 25c3.866 0 7-3.134 7-7s-3.134-7-7-7-7 3.134-7 7 3.134 7 7 7zm-43-7c1.657 0 3-1.343 3-3s-1.343-3-3-3-3 1.343-3 3 1.343 3 3 3zm63 31c1.657 0 3-1.343 3-3s-1.343-3-3-3-3 1.343-3 3 1.343 3 3 3zM34 90c1.657 0 3-1.343 3-3s-1.343-3-3-3-3 1.343-3 3 1.343 3 3 3zm56-76c1.657 0 3-1.343 3-3s-1.343-3-3-3-3 1.343-3 3 1.343 3 3 3zM12 86c2.21 0 4-1.79 4-4s-1.79-4-4-4-4 1.79-4 4 1.79 4 4 4zm28-65c2.21 0 4-1.79 4-4s-1.79-4-4-4-4 1.79-4 4 1.79 4 4 4zm23-11c2.76 0 5-2.24 5-5s-2.24-5-5-5-5 2.24-5 5 2.24 5 5 5zm-6 60c2.21 0 4-1.79 4-4s-1.79-4-4-4-4 1.79-4 4 1.79 4 4 4zm29 22c2.76 0 5-2.24 5-5s-2.24-5-5-5-5 2.24-5 5 2.24 5 5 5zM32 63c2.76 0 5-2.24 5-5s-2.24-5-5-5-5 2.24-5 5 2.24 5 5 5zm57-13c2.76 0 5-2.24 5-5s-2.24-5-5-5-5 2.24-5 5 2.24 5 5 5zm-9-21c1.105 0 2-.895 2-2s-.895-2-2-2-2 .895-2 2 .895 2 2 2zM60 91c1.105 0 2-.895 2-2s-.895-2-2-2-2 .895-2 2 .895 2 2 2zM35 41c1.105 0 2-.895 2-2s-.895-2-2-2-2 .895-2 2 .895 2 2 2zM12 60c1.105 0 2-.895 2-2s-.895-2-2-2-2 .895-2 2 .895 2 2 2z&#39; fill=&#39;%23ffffff&#39; fill-opacity=&#39;0.05&#39; fill-rule=&#39;evenodd&#39;/%3E%3C/svg%3E&quot;);
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        .exam-title {
            font-size: 2.8rem;
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            letter-spacing: -0.5px;
            position: relative;
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        .exam-subtitle {
            font-size: 1.5rem;
            margin-bottom: 20px;
            color: #dbeafe;
            font-weight: 400;
            position: relative;
            z-index: 1;
        }
        
        .exam-description {
            max-width: 800px;
            margin: 0 auto 25px;
            background-color: rgba(255, 255, 255, 0.15);
            padding: 20px;
            border-radius: 12px;
            backdrop-filter: blur(10px);
            position: relative;
            z-index: 1;
            border: 1px solid rgba(255, 255, 255, 0.2);
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        .description-title {
            font-size: 1.2rem;
            margin-bottom: 10px;
            color: #e0f2fe;
            display: flex;
            align-items: center;
            gap: 10px;
        }
        
        .description-title i {
            font-size: 1.3rem;
        }
        
        .description-text {
            font-size: 1rem;
            line-height: 1.6;
        }
        
        .exam-details {
            display: flex;
            justify-content: center;
            flex-wrap: wrap;
            margin-top: 20px;
            background-color: rgba(255, 255, 255, 0.1);
            padding: 20px;
            border-radius: 12px;
            backdrop-filter: blur(10px);
            position: relative;
            z-index: 1;
            border: 1px solid rgba(255, 255, 255, 0.2);
            max-width: 800px;
            margin-left: auto;
            margin-right: auto;
        }
        
        .detail-item {
            margin: 8px 20px;
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            align-items: center;
            gap: 8px;
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        .detail-icon {
            font-size: 1.1rem;
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        .exam-content {
            padding: 40px 30px;
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        .section {
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        .section-title-text {
            display: flex;
            align-items: center;
            gap: 12px;
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        .section-icon {
            font-size: 1.4rem;
            color: #3b82f6;
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        .marks-info {
            font-weight: 700;
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            padding: 8px 16px;
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            margin-bottom: 28px;
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            border-radius: 16px;
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        .question:hover {
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        .question-number {
            display: inline-flex;
            align-items: center;
            justify-content: center;
            background: linear-gradient(135deg, #3b82f6 0%, #60a5fa 100%);
            color: white;
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            font-weight: 700;
            box-shadow: 0 4px 6px rgba(59, 130, 246, 0.2);
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        .question-text {
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            font-size: 1.08rem;
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        .options {
            margin-left: 30px;
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        .option {
            margin-bottom: 12px;
            padding: 10px 15px;
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            border: 1px solid #e2e8f0;
            transition: all 0.2s ease;
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        .option:hover {
            background-color: #f1f5f9;
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        .option-label {
            font-weight: 700;
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        .instructions-title {
            color: #0369a1;
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            font-size: 1.3rem;
            display: flex;
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            gap: 12px;
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        .instruction-item {
            margin-bottom: 10px;
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            position: relative;
        }
        
        .instruction-item::before {
            content: &#39;•&#39;;
            color: #0ea5e9;
            font-weight: bold;
            position: absolute;
            left: 0;
        }
        
        .navigation {
            display: flex;
            justify-content: space-between;
            margin-top: 40px;
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        .nav-btn {
            background: linear-gradient(135deg, #3b82f6 0%, #60a5fa 100%);
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            transition: all 0.3s ease;
            display: flex;
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            gap: 10px;
            box-shadow: 0 4px 6px rgba(59, 130, 246, 0.2);
        }
        
        .nav-btn:hover {
            transform: translateY(-2px);
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        }
        
        .footer {
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            padding: 25px;
            color: #64748b;
            font-size: 0.95rem;
            background-color: #f8fafc;
            border-top: 1px solid #e2e8f0;
        }
        
        .footer-icons {
            display: flex;
            justify-content: center;
            gap: 20px;
            margin-top: 15px;
        }
        
        .footer-icon {
            color: #64748b;
            font-size: 1.2rem;
            transition: color 0.3s;
        }
        
        .footer-icon:hover {
            color: #3b82f6;
        }
        
        .question-paper-info {
            display: flex;
            flex-wrap: wrap;
            gap: 15px;
            margin-bottom: 30px;
            padding: 20px;
            background-color: #f0f9ff;
            border-radius: 12px;
        }
        
        .info-card {
            flex: 1;
            min-width: 200px;
            background-color: white;
            padding: 20px;
            border-radius: 12px;
            box-shadow: 0 4px 6px rgba(0, 0, 0, 0.05);
            display: flex;
            align-items: center;
            gap: 15px;
        }
        
        .info-icon {
            font-size: 2rem;
            color: #3b82f6;
        }
        
        .info-content h4 {
            color: #1e40af;
            margin-bottom: 5px;
        }
        
        .info-content p {
            color: #64748b;
            font-size: 0.95rem;
        }
        
        .latex {
            font-size: 1.15rem;
        }
        
        @media (max-width: 768px) {
            .exam-title {
                font-size: 2.2rem;
            }
            
            .exam-subtitle {
                font-size: 1.2rem;
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                align-items: flex-start;
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            .exam-details {
                flex-direction: column;
                align-items: center;
            }
            
            .detail-item {
                margin-bottom: 10px;
            }
            
            .question {
                padding: 20px;
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            .exam-content {
                padding: 25px 20px;
            }
            
            .navigation {
                flex-direction: column;
                gap: 15px;
            }
            
            .nav-btn {
                justify-content: center;
            }
            
            .info-card {
                min-width: 100%;
            }
        }
        
        /* Print styles */
        @media print {
            body {
                background: white;
                padding: 0;
            }
            
            .container {
                box-shadow: none;
                border-radius: 0;
            }
            
            .nav-btn, .footer-icons {
                display: none;
            }
            
            .question:hover {
                transform: none;
                box-shadow: none;
            }
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        /* Animation for question numbers */
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            from { opacity: 0; transform: translateY(10px); }
            to { opacity: 1; transform: translateY(0); }
        }
        
        .question {
            animation: fadeIn 0.5s ease;
        }
    &lt;/style&gt;
&lt;/head&gt;
&lt;body&gt;
    &lt;div class=&quot;container&quot;&gt;
        &lt;div class=&quot;exam-header&quot;&gt;
            &lt;h1 class=&quot;exam-title&quot;&gt;Test Examination - Practice Test Paper - Prime Maths&lt;/h1&gt;
            &lt;h2 class=&quot;exam-subtitle&quot;&gt;Class X - Mathematics&lt;/h2&gt;
            
            &lt;div class=&quot;exam-description&quot;&gt;
                &lt;div class=&quot;description-title&quot;&gt;
                    &lt;i class=&quot;fas fa-file-alt&quot;&gt;&lt;/i&gt;
                    &lt;span&gt;Examination Overview&lt;/span&gt;
                &lt;/div&gt;
                &lt;p class=&quot;description-text&quot;&gt;
                    This comprehensive mathematics examination covers key concepts from the Class X curriculum including algebra, 
                    geometry, trigonometry, mensuration, statistics, and commercial mathematics. The paper is designed to test 
                    conceptual understanding, problem-solving skills, and application of mathematical principles in real-world scenarios.
                &lt;/p&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;exam-details&quot;&gt;
                &lt;div class=&quot;detail-item&quot;&gt;
                    &lt;i class=&quot;fas fa-clock detail-icon&quot;&gt;&lt;/i&gt;
                    &lt;span&gt;&lt;strong&gt;Duration:&lt;/strong&gt; 3 Hours&lt;/span&gt;
                &lt;/div&gt;
                &lt;div class=&quot;detail-item&quot;&gt;
                    &lt;i class=&quot;fas fa-tasks detail-icon&quot;&gt;&lt;/i&gt;
                    &lt;span&gt;&lt;strong&gt;Total Marks:&lt;/strong&gt; 90&lt;/span&gt;
                &lt;/div&gt;
                &lt;div class=&quot;detail-item&quot;&gt;
                    &lt;i class=&quot;fas fa-graduation-cap detail-icon&quot;&gt;&lt;/i&gt;
                    &lt;span&gt;&lt;strong&gt;Class:&lt;/strong&gt; X (Secondary)&lt;/span&gt;
                &lt;/div&gt;
                &lt;div class=&quot;detail-item&quot;&gt;
                    &lt;i class=&quot;fas fa-calendar-alt detail-icon&quot;&gt;&lt;/i&gt;
                    &lt;span&gt;&lt;strong&gt;Year:&lt;/strong&gt; 2023&lt;/span&gt;
                &lt;/div&gt;
            &lt;/div&gt;
        &lt;/div&gt;
        
        &lt;div class=&quot;exam-content&quot;&gt;
            &lt;div class=&quot;question-paper-info&quot;&gt;
                &lt;div class=&quot;info-card&quot;&gt;
                    &lt;div class=&quot;info-icon&quot;&gt;
                        &lt;i class=&quot;fas fa-calculator&quot;&gt;&lt;/i&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;info-content&quot;&gt;
                        &lt;h4&gt;No Calculator&lt;/h4&gt;
                        &lt;p&gt;Use of calculators is not permitted in this examination.&lt;/p&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;info-card&quot;&gt;
                    &lt;div class=&quot;info-icon&quot;&gt;
                        &lt;i class=&quot;fas fa-drafting-compass&quot;&gt;&lt;/i&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;info-content&quot;&gt;
                        &lt;h4&gt;Geometrical Tools&lt;/h4&gt;
                        &lt;p&gt;Geometrical instruments are required for construction problems.&lt;/p&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;info-card&quot;&gt;
                    &lt;div class=&quot;info-icon&quot;&gt;
                        &lt;i class=&quot;fas fa-chart-bar&quot;&gt;&lt;/i&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;info-content&quot;&gt;
                        &lt;h4&gt;Comprehensive Coverage&lt;/h4&gt;
                        &lt;p&gt;Covers all major topics from the Class X mathematics syllabus.&lt;/p&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;instructions&quot;&gt;
                &lt;h3 class=&quot;instructions-title&quot;&gt;
                    &lt;i class=&quot;fas fa-info-circle&quot;&gt;&lt;/i&gt;
                    General Instructions
                &lt;/h3&gt;
                &lt;ul&gt;
                    &lt;li class=&quot;instruction-item&quot;&gt;All questions are compulsory unless specified otherwise.&lt;/li&gt;
                    &lt;li class=&quot;instruction-item&quot;&gt;Marks for each question are indicated in brackets.&lt;/li&gt;
                    &lt;li class=&quot;instruction-item&quot;&gt;Use of calculators is not permitted.&lt;/li&gt;
                    &lt;li class=&quot;instruction-item&quot;&gt;Draw neat diagrams wherever required.&lt;/li&gt;
                    &lt;li class=&quot;instruction-item&quot;&gt;For fill in the blanks and true/false questions, answer any five.&lt;/li&gt;
                    &lt;li class=&quot;instruction-item&quot;&gt;Show all working steps for full marks.&lt;/li&gt;
                    &lt;li class=&quot;instruction-item&quot;&gt;Write answers clearly and legibly.&lt;/li&gt;
                &lt;/ul&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 1: Multiple Choice Questions --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section1&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-list-ol section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 1: Multiple Choice Questions&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[1 × 6 = 6 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Choose the correct answer in each of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        In a partnership business, the ratio of profits received by two friends is \(\frac{1}{2} : \frac{1}{3}\). The ratio of their capitals is:
                    &lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; 2 : 3&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; 3 : 2&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; 1 : 1&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; 5 : 3&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        If \(p+q=\sqrt{13}\) and \(p-q=\sqrt{5}\), then the value of \(pq\) is:
                    &lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; 2&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; 18&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; 9&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; 8&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;
                        O is the center of a circle and AB is a chord. ABCD is a cyclic quadrilateral. If \(\angle ABC = 65^\circ\) and \(\angle DAC = 40^\circ\), then the value of \(\angle BCD\) is:
                    &lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; 75°&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; 105°&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; 115°&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; 80°&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;iv&lt;/span&gt;
                        If \(\tan \alpha + \cot \alpha = 2\), then the value of \(\tan^{13} \alpha + \cot^{13} \alpha\) is:
                    &lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; 13&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; 2&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; 1&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; 0&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;v&lt;/span&gt;
                        Two cubes each with side \(2\sqrt{6}\) cm are placed side by side to form a cuboid. The length of the diagonal of the cuboid is:
                    &lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; 10 cm&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; 6 cm&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; 2 cm&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; 12 cm&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;vi&lt;/span&gt;
                        If the mean of \(x_1, x_2, x_3, \dots, x_{10}\) is 20, then the mean of \(x_1 + 4\), \(x_2 + 4\), \(x_3 + 4\), \(\dots\), \(x_{10} + 4\) is:
                    &lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; 20&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; 24&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; 40&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; 10&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 2: Fill in the blanks --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section2&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-edit section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 2: Fill in the Blanks&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[1 × 5 = 5 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;five&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        If the annual compound interest rate is \(r\%\) and the principal in the first year is \(P\) rupees, then the principal in the second year is ______.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        \(7\sqrt{11}\) is a ______ number.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;
                        If the radius of a sphere is \(r\) and its volume is \(v\), then \(v \propto\) ______.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;iv&lt;/span&gt;
                        Two triangles are similar if their corresponding sides are ______.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;v&lt;/span&gt;
                        If the opposite angles of a quadrilateral are supplementary, then the vertices of the quadrilateral are ______.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;vi&lt;/span&gt;
                        If the length, breadth, and height of a cuboid are equal, then the name of that solid is ______.
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 3: True or False --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section3&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-check-circle section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 3: True or False&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[1 × 5 = 5 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;five&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        In compound interest, if the interest rates for the first, second, and third years are \(r_1\%\), \(r_2\%\), and \(r_3\%\) respectively, then the amount for \(P\) rupees after 3 years is 
                        \[P\left(1 + \frac{r_1}{100}\right)\left(1 + \frac{r_2}{100}\right)\left(1 + \frac{r_3}{100}\right) \text{ rupees.}\]
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        The values of cos 36° and sin 54° are equal.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;
                        Only one tangent can be drawn to a circle from an external point.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;iv&lt;/span&gt;
                        The compound ratio of \(2ab : c^2\), \(bc : a^2\), and \(ca : 2b^2\) is 1 : 1.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;v&lt;/span&gt;
                        If the numerical values of the surface area and volume of a sphere are equal, then the radius is 3 units.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;vi&lt;/span&gt;
                        The mode of the numbers 5, 2, 4, 3, 5, 2, 5, 2, 5, 2 is 2.
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 4: Short Answer Questions --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section4&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-short-answer section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 4: Short Answer Questions&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[2 × 10 = 20 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;ten&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;vii&lt;/span&gt;
                        The radii of two circles are 8 cm and 3 cm. The distance between their centers is 13 cm. What is the length of the direct common tangent of the circles?
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;viii&lt;/span&gt;
                        What is the radian measure of the angle swept by the hour hand of a clock in 1 hour?
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ix&lt;/span&gt;
                        If \(\tan 4\theta \tan 6\theta = 1\) and \(6\theta\) is positive acute, determine the value of \(\theta\).
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;x&lt;/span&gt;
                        The height of a right circular cylinder is 12 cm and its volume is 100π cubic cm. Determine the radius of the base of the cylinder.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;xi&lt;/span&gt;
                        If the ratio of the surface areas of two spheres is 1 : 4, determine the ratio of their volumes.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;xii&lt;/span&gt;
                        If \(u_1 = \frac{x_1 - 35}{10}\), \(\sum f_1 u_1 = 30\), and \(\sum f_1 = 60\), then determine the value of \(\bar{x}\).
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 5: Compound Interest or Partnership --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section5&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-calculator section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 5: Compound Interest or Partnership&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[5 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;one&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        Determine the compound interest on ₹40,000 for 3 years at 5% per annum compound interest.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        Rajib started a business with a capital of ₹3,750. After 6 months, Sayan joined the business with a capital of ₹15,000. At the end of the year, the profit was ₹6,900. Determine each one&#39;s share of the profit.
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 6: Algebra --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section6&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-square-root-alt section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 6: Algebra&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[3 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;one&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        Solve: \(\frac{x}{x+1} + \frac{x+1}{x} = 2 \frac{1}{12}\), where \(x \neq 0, -1\)
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        A train travels 200 km at a uniform speed. If the speed of the train is increased by 5 km/h, it takes 2 hours less to cover the same distance. Determine the speed of the train.
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 7: Algebra/Proportion --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section7&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-balance-scale section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 7: Algebra and Proportion&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[3 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;one&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        If \(x = \frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}\) and \(y = \frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}\), then find the value of \(x^2 - xy + y^2\).
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        If \(x \propto y\) and \(y \propto z\), prove that \((x^2 + y^2 + z^2) \propto (xy + yz + zx)\).
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 8: Proportions --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section8&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-percentage section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 8: Proportions&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[3 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;one&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        If \(a, b, c, d\) are in continued proportion, show that
                        \[(b^2 + d^2) : (b^2 - d^2) = (ab + cd) : (ab - cd)\]
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        If \(\frac{a+b-c}{a+b} = \frac{b+c-a}{b+c} = \frac{c+a-b}{c+a}\) and \(a+b+c \neq 0\), then prove that \(a = b = c\).
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 9: Geometry Proofs --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section9&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-shapes section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 9: Geometry Proofs&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[5 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;one&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        Prove that all angles in the same segment of a circle are equal.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        Prove that if a perpendicular is drawn from the right angle vertex of a right triangle to the hypotenuse, then the two triangles formed on either side of the perpendicular are similar to the original triangle and to each other.
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 10: Geometry --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section10&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-draw-polygon section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 10: Geometry&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[3 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;one&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        O is the center of a circle and QR is a chord. Tangents drawn at Q and R intersect at P. If QM is a diameter of the circle, prove that \(\frac{QR}{QM} = 2\).
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        In triangle ABC, \(\angle C = 90^\circ\). If CD is the median, prove that \(BC^2 = CD^2 + 3AD^2\).
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 11: Construction --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section11&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-ruler-combined section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 11: Construction&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[5 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;one&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        Construct a triangle ABC with BC = 7 cm, AB = 5 cm, and AC = 6 cm. Draw the circumcircle of the triangle. (Only construction traces are required)
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        Determine geometrically the mean proportional between 4 cm and 3 cm. (Only construction traces are required)
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 12: Trigonometry --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section12&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-sigma section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 12: Trigonometry&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[3 × 2 = 6 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;two&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        In \(\triangle ABC\), \(\angle C = 90^\circ\). If \(BC = m\) and \(AC = n\), show that 
                        \[m \sin A + n \sin B = \sqrt{m^2 + n^2}\]
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        Find the value:
                        \[ \frac{4}{3} \cot^2 30^\circ + 3 \sin^2 60^\circ - 2 \cos^2 60^\circ - \frac{3}{4} \tan^2 30^\circ \]
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;
                        If \(\angle P + \angle Q = 90^\circ\), then show that
                        \[ \sqrt{\frac{\sin P}{\cos Q}} - \sin P \cos Q = \cos^2 P \]
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 13: Height and Distance --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section13&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-mountain section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 13: Height and Distance&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[5 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;one&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        The width of a river is 600 m. Two boats start from the same bank of the river to go to the opposite bank. If the first boat makes an angle of 30° with the bank and the second boat makes an angle of 90° with the direction of the first boat to reach the opposite bank, what will be the distance between the two boats after they reach the opposite bank?
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        On the roof of a three-story building, there is a flagpole of length 3.6 m. From a point on the road, the angles of elevation of the top and bottom of the flagpole are 50° and 45° respectively. What is the height of the building? (Take tan 50° = 1.2)
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 14: Mensuration --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section14&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-cube section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 14: Mensuration&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[4 × 2 = 8 Marks]&lt;/div&gt;
                &lt;/div&gt;
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;two&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        The ratio of length, breadth, and height of a solid cuboid is 4:3:2 and its total surface area is 468 sq. cm. Find the volume of the cuboid.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        The radius of the base of a solid cylindrical rod is 3.2 dm. The rod is melted to form 21 solid spheres. If the radius of each sphere is 8 cm, find the length of the rod.
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;
                        The slant height of a solid right circular cone is 7 cm and its total surface area is 147.84 sq. cm. Find the radius of the base of the cone.
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;!-- Section 15: Statistics --&gt;
            &lt;div class=&quot;section&quot; id=&quot;section15&quot;&gt;
                &lt;div class=&quot;section-title&quot;&gt;
                    &lt;div class=&quot;section-title-text&quot;&gt;
                        &lt;i class=&quot;fas fa-chart-line section-icon&quot;&gt;&lt;/i&gt;
                        &lt;span&gt;Section 15: Statistics&lt;/span&gt;
                    &lt;/div&gt;
                    &lt;div class=&quot;marks-info&quot;&gt;[4 × 2 = 8 Marks]&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;p style=&quot;margin-bottom: 25px; color: #475569; font-size: 1.05rem;&quot;&gt;Answer any &lt;strong&gt;two&lt;/strong&gt; of the following:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;
                        Calculate the arithmetic mean from the following frequency distribution:
                        &lt;div class=&quot;table-container&quot;&gt;
                            &lt;table&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Class Limit&lt;/th&gt;
                                    &lt;td&gt;10-20&lt;/td&gt;
                                    &lt;td&gt;20-30&lt;/td&gt;
                                    &lt;td&gt;30-40&lt;/td&gt;
                                    &lt;td&gt;40-50&lt;/td&gt;
                                    &lt;td&gt;50-60&lt;/td&gt;
                                    &lt;td&gt;60-70&lt;/td&gt;
                                &lt;/tr&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Frequency&lt;/th&gt;
                                    &lt;td&gt;10&lt;/td&gt;
                                    &lt;td&gt;16&lt;/td&gt;
                                    &lt;td&gt;20&lt;/td&gt;
                                    &lt;td&gt;30&lt;/td&gt;
                                    &lt;td&gt;13&lt;/td&gt;
                                    &lt;td&gt;11&lt;/td&gt;
                                &lt;/tr&gt;
                            &lt;/table&gt;
                        &lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;
                        Find the median of the data below:
                        &lt;div class=&quot;table-container&quot;&gt;
                            &lt;table&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Class Limit&lt;/th&gt;
                                    &lt;td&gt;1-5&lt;/td&gt;
                                    &lt;td&gt;6-10&lt;/td&gt;
                                    &lt;td&gt;11-15&lt;/td&gt;
                                    &lt;td&gt;16-20&lt;/td&gt;
                                    &lt;td&gt;21-25&lt;/td&gt;
                                    &lt;td&gt;26-30&lt;/td&gt;
                                    &lt;td&gt;31-35&lt;/td&gt;
                                &lt;/tr&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;No. of Workers&lt;/th&gt;
                                    &lt;td&gt;2&lt;/td&gt;
                                    &lt;td&gt;4&lt;/td&gt;
                                    &lt;td&gt;6&lt;/td&gt;
                                    &lt;td&gt;8&lt;/td&gt;
                                    &lt;td&gt;10&lt;/td&gt;
                                    &lt;td&gt;5&lt;/td&gt;
                                    &lt;td&gt;4&lt;/td&gt;
                                &lt;/tr&gt;
                            &lt;/table&gt;
                        &lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;
                        &lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;
                        Determine the mode of the following frequency distribution:
                        &lt;div class=&quot;table-container&quot;&gt;
                            &lt;table&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Class Limit&lt;/th&gt;
                                    &lt;td&gt;0-5&lt;/td&gt;
                                    &lt;td&gt;5-10&lt;/td&gt;
                                    &lt;td&gt;10-15&lt;/td&gt;
                                    &lt;td&gt;15-20&lt;/td&gt;
                                    &lt;td&gt;20-25&lt;/td&gt;
                                    &lt;td&gt;25-30&lt;/td&gt;
                                    &lt;td&gt;30-35&lt;/td&gt;
                                    &lt;td&gt;35-40&lt;/td&gt;
                                &lt;/tr&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Frequency&lt;/th&gt;
                                    &lt;td&gt;2&lt;/td&gt;
                                    &lt;td&gt;6&lt;/td&gt;
                                    &lt;td&gt;10&lt;/td&gt;
                                    &lt;td&gt;16&lt;/td&gt;
                                    &lt;td&gt;22&lt;/td&gt;
                                    &lt;td&gt;11&lt;/td&gt;
                                    &lt;td&gt;8&lt;/td&gt;
                                    &lt;td&gt;5&lt;/td&gt;
                                &lt;/tr&gt;
                            &lt;/table&gt;
                        &lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
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            &lt;p&gt;Class X Mathematics Test Practice Paper | Total Marks: 90 | Duration: 3 Hours&lt;/p&gt;
            &lt;p&gt;This examination paper covers the complete Class X Mathematics syllabus as prescribed by the board.&lt;/p&gt;
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    &lt;div class=&quot;container&quot;&gt;
        &lt;div class=&quot;exam-header&quot;&gt;
            &lt;h1 class=&quot;exam-title&quot;&gt;Prime Maths | Vinod Singh &lt;/h1&gt;
            &lt;h2 class=&quot;exam-subtitle&quot;&gt;Madhyamik Test Examination – Practice Paper | Subject: MATHEMATICS&lt;/h2&gt;
            
            &lt;div class=&quot;exam-details&quot;&gt;
                &lt;div class=&quot;detail-item&quot;&gt;&lt;strong&gt;Time:&lt;/strong&gt; 3 Hours 15 Minutes&lt;/div&gt;
                &lt;div class=&quot;detail-item&quot;&gt;&lt;strong&gt;Full Marks:&lt;/strong&gt; 90&lt;/div&gt;
                &lt;div class=&quot;detail-item&quot;&gt;&lt;strong&gt;Type:&lt;/strong&gt; Free Practice Test Paper&lt;/div&gt;
            &lt;/div&gt;
        &lt;/div&gt;
        
        &lt;div class=&quot;exam-content&quot;&gt;
            &lt;div class=&quot;instructions&quot;&gt;
                &lt;h3&gt;General Instructions:&lt;/h3&gt;
                &lt;ul&gt;
                    &lt;li class=&quot;instruction-item&quot;&gt;The figures in the margin indicate full marks.&lt;/li&gt;
                    &lt;li class=&quot;instruction-item&quot;&gt;Use of calculators is not permitted.&lt;/li&gt;
                    &lt;li class=&quot;instruction-item&quot;&gt;Graph papers will be supplied if required.&lt;/li&gt;
                &lt;/ul&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;section&quot; id=&quot;section1&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;1. Multiple Choice Questions [1 × 6 = 6]&lt;/h2&gt;
                &lt;p&gt;Select the correct answer in each of the following cases:&lt;/p&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;If the mean of a frequency distribution is 8.1, \(\sum f_i x_i = 132 + 5k\), and \(\sum f_i = 20\), then the value of \(k\) is:&lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; 4&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; 2&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; 3&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; 6&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;

                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;If \(\cos\theta + \sec\theta = 2\), then the value of \(\cos^5\theta + \sin^5\theta\) is:&lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; -1&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; 1&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; 0&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; -2&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;

                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;The volumes of two right circular cones are equal. If the radii of their circular bases are in the ratio 1:2, their heights are in the ratio:&lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; 2:1&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; 3:1&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; 4:1&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; 8:1&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;

                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iv&lt;/span&gt;In the right-angled triangle ABC, \(\angle A\) is a right angle, AB = 12 cm, AC = 5 cm, and BC = 13 cm. AD is perpendicular to BC. The length of AD is:&lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; \(\frac{65}{12}\) cm&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; \(\frac{60}{13}\) cm&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; \(\frac{13}{60}\) cm&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; \(\frac{5}{15}\) cm&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;

                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;v&lt;/span&gt;X and Y are two points on sides PQ and PR of triangle PQR respectively. If PX = 2 cm, XQ = 3.5 cm, YR = 7 cm, and PY = 4.25 cm, then:&lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; XY || QR&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; XY = QR&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; XY is not parallel to QR&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; None of these&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;

                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;vi&lt;/span&gt;If \(x \propto y\), then:&lt;/div&gt;
                    &lt;div class=&quot;options&quot;&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(a)&lt;/span&gt; \(x^{420} \propto y^{202}\)&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(b)&lt;/span&gt; \(x^{2025} \propto y^{3025}\)&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(c)&lt;/span&gt; \(x^{2024} \propto y^{2025}\)&lt;/div&gt;
                        &lt;div class=&quot;option&quot;&gt;&lt;span class=&quot;option-label&quot;&gt;(d)&lt;/span&gt; \(x^{2025} \propto y^{2025}\)&lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;section&quot; id=&quot;section2&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;2. Fill in the blanks (any five) [1 × 5 = 5]&lt;/h2&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;If the difference between the roots of the equation \(x^2 - px + q = 0\) is 1, then \(p^2 - 4q = \) __________.&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;If \(x = 2 - \sqrt{3}\) and \(y = 4\sqrt{2}-2\), then \((x + y)^4 = \) __________.&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;The tangents drawn at the two ends of a diameter of a circle are __________ to each other.&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iv&lt;/span&gt;The ratio of simple interest on a fixed amount of money at the same annual rate for 4 years and 8 years is __________.&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;v&lt;/span&gt;If the compound ratio of 2:3, 4:5, and 6:\(x\) is 2:5, then the value of \(x = \) __________.&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;vi&lt;/span&gt;A tangent drawn from an external point M to a circle with center O touches the circle at point N. If ON = 9 cm and MO = 15 cm, then the length of MN = __________.&lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;section&quot; id=&quot;section3&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;3. Write True or False (any five) [1 × 5 = 5]&lt;/h2&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;A starts a business with ₹10,000, and 6 months later B invests ₹20,000. At the end of the year, their profit shares will be equal.&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;The ratio of the volumes of a right circular cone and a right circular cylinder with the same base and same height is 1:3.&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;The arithmetic mean and mode of the numbers 4, 3, 2, 5, 3, 4, 5, 1, 7, 3, 2, 1 are equal.&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iv&lt;/span&gt;In trapezium ABCD, AB || CD; diagonals AC and BD intersect at point O, then \(AO \cdot OD = BO \cdot OC\).&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;v&lt;/span&gt;AB is a diameter of a circle with center O. P is any point on the circumference. If \(\angle POA = 120^\circ\), then \(\angle PBO + \angle POA = 140^\circ\).&lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;vi&lt;/span&gt;The current price of a mobile phone is ₹20,000. If the price depreciates by 15% every year, the price of the mobile phone after 2 years will be ₹14,450.&lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;section&quot; id=&quot;section4&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;4. Answer the following questions (any ten) [2 × 10 = 20]&lt;/h2&gt;
                
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;If the simple interest on ₹8,000 for 2 years is ₹720, find the annual rate of interest.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;If the compound interest on a sum of money for 2 years is ₹512 and the simple interest for the same time and at the same rate is ₹500, what is the rate of interest?&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;In a partnership business, the ratio of the capitals of three persons is 3 : 5 : 8. If the profit of the first person is ₹60 less than the profit of the third person, what was the total profit in the business?&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iv&lt;/span&gt;If 2 is a root of the equations \(x^2 + bx + 12 = 0\) and \(x^2 + bx + q = 0\), find the value of \(q\).&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;v&lt;/span&gt;If \(a+b=2\sqrt{5}\) and \(a-b=\sqrt{2}\), what is the value of \(a^2 + b^2\)?&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;vi&lt;/span&gt;The length of each of two parallel chords AB and CD is 16 cm. If the radius of the circle is 10 cm, find the distance between the two chords.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;vii&lt;/span&gt;In a circle, two chords PQ and PR are perpendicular to each other. If the length of the radius of the circle is \(r\) cm, find the length of the chord QR.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;viii&lt;/span&gt;If \((4a+5b):(4c+5d) = (4a-5b):(4c-5d)\), prove that a, b, c, and d are in proportion.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ix&lt;/span&gt;If the volume of a right circular cone is \(V\), base area is \(A\), and height is \(H\), find the value of \(\frac{AH}{V}\).&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;x&lt;/span&gt;If \(\theta = 30^\circ\), what is the value of \(\sin 2\theta + \cos 2\theta\)?&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;xi&lt;/span&gt;Find the median and arithmetic mean of the numbers: 2, 2, 3, 4, 6, 5, 5, 8, 9, 10, 11.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;xii&lt;/span&gt;The length, breadth, and height of a rectangular cuboid room are 5 m, 4 m, and 3 m respectively. Calculate the length of the longest rod that can be kept in that room.&lt;/div&gt;&lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section5&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;5. Answer any one question [5 × 1 = 5]&lt;/h2&gt;
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;A person borrowed ₹500 at 6% simple interest per annum, and exactly two years after the first loan, borrowed a second loan of ₹900 at 4% simple interest per annum. How many years after taking the first loan will the interest on these two loans be equal, and what will be the total interest on the two loans at that time?&lt;/div&gt;
                &lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;A and B started a joint business with ₹6,200 and ₹10,000 respectively. They decided that A would receive 20% of the profit for managing the business, and 10% of the remaining profit would be deposited as savings. The rest of the profit would be divided in proportion to their capitals. If the total profit at the end of the year is ₹45,000, how much money will A receive in total?&lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section6&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;6. Answer any one question [3 × 1 = 3]&lt;/h2&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;Solve: \(\frac{2x+1}{2x-1} + \frac{2x-1}{2x+1} = 1 + \frac{7}{2x-1}, x \neq \frac{1}{2}\)&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;If \(x \propto y\) and \(y \propto z\), prove that \(x+y+z \propto \sqrt{yz}+\sqrt{zx}+\sqrt{xy}\).&lt;/div&gt;&lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section7&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;7. Solve any one question [3 × 1 = 3]&lt;/h2&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;Find the simplest value: \( (\sqrt{5}+\sqrt{3})\big( \frac{3\sqrt{3}}{\sqrt{5}+\sqrt{2}}-\frac{\sqrt{5}}{\sqrt{3}+\sqrt{2}}\big)\)&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;The volume of a cone is in joint variation with the square of its base radius and its height. If the ratio of the base radii of two cones is 3:4 and the ratio of their heights is 6:5, find the ratio of their volumes.&lt;/div&gt;&lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section8&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;8. Answer any one question [3 × 1 = 3]&lt;/h2&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;If \(a, b, c, d\) are in continued proportion, prove that \((b-c)^2 + (c-a)^2 + (b-d)^2 = (a-d)^2\).&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;If \(\frac{x}{b+c} = \frac{y}{c+a} = \frac{z}{a+b}\), then prove that \(\frac{a}{y+z-x} = \frac{b}{z+x-y} = \frac{c}{x+y-z}\).&lt;/div&gt;&lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section9&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;9. Answer any one question [5 × 1 = 5]&lt;/h2&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;Prove that the opposite angles of any cyclic quadrilateral are supplementary.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;Prove that if two tangents are drawn to a circle from an external point, the line segments joining the points of contact to the external point are equal in length and subtend equal angles at the center.&lt;/div&gt;&lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section10&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;10. Answer any one question [3 × 1 = 3]&lt;/h2&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;In an isosceles triangle ABC, AB = AC. A straight line parallel to BC intersects AB and AC at points P and Q respectively. Prove that BCQP is a cyclic quadrilateral.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;A right-angled triangle ABC is drawn where \(\angle A\) is a right angle. P and Q are two points on sides AB and AC respectively. B, Q and C, P are joined. Prove that \(BQ^2 + PC^2 = BC^2 + PQ^2\).&lt;/div&gt;&lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section11&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;11. Answer any one question [5 × 1 = 5]&lt;/h2&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;Construct an isosceles triangle whose one angle is \(120^\circ\) and the length of each of the equal sides is 4 cm. Draw the circumcircle of the triangle.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;Construct a square equal in area to a rectangle with sides of length 6 cm and 3 cm. (Only traces of construction are required).&lt;/div&gt;&lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section12&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;12. Solve any two questions [3 × 2 = 6]&lt;/h2&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;If \(m = \tan\theta + \sin\theta\) and \(n = \tan\theta - \sin\theta\), prove that \(m^2 - n^2 = 4\sqrt{mn}\) (\(0^\circ &lt; \theta &lt; 90^\circ\)).&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;If \(\angle A + \angle B = 90^\circ\), show that \(1 + \frac{\tan A}{\tan B} = \sec^2 A\).&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;One angle of a triangle is 60° and another is \(\frac{\pi}{6}\) radians. What is the measurement of the third angle in degrees?&lt;/div&gt;&lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section13&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;13. Answer any one question [5 × 1 = 5]&lt;/h2&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;From the roof and the foot of a 16-meter high house, the angles of elevation of the top of a temple are observed to be 45° and 60° respectively. Find the height of the temple and its horizontal distance from the house.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;The angle of elevation of the top of a tower from a point A on the ground is 30°. After moving 20 meters from point A towards the foot of the tower to point B, the angle of elevation increases to 60°. Find the height of the tower and the distance of the tower from point A.&lt;/div&gt;&lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section14&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;14. Answer any two questions [4 × 2 = 8]&lt;/h2&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;A large solid sphere is made by melting three solid copper spheres with radii of lengths 3 cm, 4 cm, and 5 cm. Calculate the length of the radius of the large sphere.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;77 square meters of tarpaulin were required to make a right circular cone-shaped tent. If the slant height of the tent is 7 meters, calculate the base area of the tent.&lt;/div&gt;&lt;/div&gt;
                &lt;div class=&quot;question&quot;&gt;&lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;Determine the ratio of the volumes of a solid cone, a solid hemisphere, and a solid cylinder having equal base diameters and equal heights.&lt;/div&gt;&lt;/div&gt;
            &lt;/div&gt;

            &lt;div class=&quot;section&quot; id=&quot;section15&quot;&gt;
                &lt;h2 class=&quot;section-title&quot;&gt;15. Answer any two questions [4 × 2 = 8]&lt;/h2&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;i&lt;/span&gt;Calculate the arithmetic mean from the following frequency distribution:
                        &lt;div class=&quot;table-container&quot;&gt;
                            &lt;table&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Class Limit&lt;/th&gt;
                                    &lt;td&gt;0-10&lt;/td&gt;&lt;td&gt;10-20&lt;/td&gt;&lt;td&gt;20-30&lt;/td&gt;&lt;td&gt;30-40&lt;/td&gt;&lt;td&gt;40-50&lt;/td&gt;&lt;td&gt;50-60&lt;/td&gt;&lt;td&gt;60-70&lt;/td&gt;
                                &lt;/tr&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Frequency&lt;/th&gt;
                                    &lt;td&gt;4&lt;/td&gt;&lt;td&gt;7&lt;/td&gt;&lt;td&gt;10&lt;/td&gt;&lt;td&gt;15&lt;/td&gt;&lt;td&gt;10&lt;/td&gt;&lt;td&gt;8&lt;/td&gt;&lt;td&gt;5&lt;/td&gt;
                                &lt;/tr&gt;
                            &lt;/table&gt;
                        &lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;ii&lt;/span&gt;Find the median of the data below:
                        &lt;div class=&quot;table-container&quot;&gt;
                            &lt;table&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Class Limit&lt;/th&gt;
                                    &lt;td&gt;1-5&lt;/td&gt;&lt;td&gt;6-10&lt;/td&gt;&lt;td&gt;11-15&lt;/td&gt;&lt;td&gt;16-20&lt;/td&gt;&lt;td&gt;21-25&lt;/td&gt;&lt;td&gt;26-30&lt;/td&gt;&lt;td&gt;31-35&lt;/td&gt;
                                &lt;/tr&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;No. of Workers&lt;/th&gt;
                                    &lt;td&gt;2&lt;/td&gt;&lt;td&gt;3&lt;/td&gt;&lt;td&gt;6&lt;/td&gt;&lt;td&gt;7&lt;/td&gt;&lt;td&gt;5&lt;/td&gt;&lt;td&gt;4&lt;/td&gt;&lt;td&gt;3&lt;/td&gt;
                                &lt;/tr&gt;
                            &lt;/table&gt;
                        &lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
                
                &lt;div class=&quot;question&quot;&gt;
                    &lt;div class=&quot;question-text&quot;&gt;&lt;span class=&quot;question-number&quot;&gt;iii&lt;/span&gt;Determine the mode of the following frequency distribution:
                        &lt;div class=&quot;table-container&quot;&gt;
                            &lt;table&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Class Limit&lt;/th&gt;
                                    &lt;td&gt;3-6&lt;/td&gt;&lt;td&gt;6-9&lt;/td&gt;&lt;td&gt;9-12&lt;/td&gt;&lt;td&gt;12-15&lt;/td&gt;&lt;td&gt;15-18&lt;/td&gt;&lt;td&gt;18-21&lt;/td&gt;&lt;td&gt;21-24&lt;/td&gt;
                                &lt;/tr&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Frequency&lt;/th&gt;
                                    &lt;td&gt;2&lt;/td&gt;&lt;td&gt;6&lt;/td&gt;&lt;td&gt;12&lt;/td&gt;&lt;td&gt;24&lt;/td&gt;&lt;td&gt;21&lt;/td&gt;&lt;td&gt;12&lt;/td&gt;&lt;td&gt;3&lt;/td&gt;
                                &lt;/tr&gt;
                            &lt;/table&gt;
                        &lt;/div&gt;
                    &lt;/div&gt;
                &lt;/div&gt;
            &lt;/div&gt;
            
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            &lt;p&gt;Prime Maths - Vinod Singh, 9038126497 &lt;/p&gt;
            &lt;p&gt;Subject: Mathematics | Total Marks: 90 | Time: 3 Hours 15 Minutes&lt;/p&gt;
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&lt;/html&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/4332063818866679106/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/01/madhyamik-practice-test-paper_15.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/4332063818866679106'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/4332063818866679106'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/01/madhyamik-practice-test-paper_15.html' title='Madhyamik Practice Test Paper'/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-5216387300153953794</id><published>2026-01-14T20:08:00.000-08:00</published><updated>2026-08-08T10:00:00.681-07:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="Madhyamik"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Madhyamik Practice Test Paper </title><content type='html'>&lt;div class=&quot;math-exam-paper&quot;&gt;
    &lt;div class=&quot;exam-header&quot;&gt;
        &lt;h1&gt;Mathematics Test Examination Paper&lt;/h1&gt;
        &lt;div class=&quot;exam-meta&quot;&gt;
            &lt;div class=&quot;meta-item&quot;&gt;
                &lt;i class=&quot;fas fa-graduation-cap&quot;&gt;&lt;/i&gt;
                &lt;span&gt;Class X (Madhyamik)&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;meta-item&quot;&gt;
                &lt;i class=&quot;fas fa-clock&quot;&gt;&lt;/i&gt;
                &lt;span&gt;3 Hours 15 Minutes&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;meta-item&quot;&gt;
                &lt;i class=&quot;fas fa-star&quot;&gt;&lt;/i&gt;
                &lt;span&gt;Full Marks: 90&lt;/span&gt;
            &lt;/div&gt;
            &lt;div class=&quot;meta-item&quot;&gt;
                &lt;i class=&quot;fas fa-school&quot;&gt;&lt;/i&gt;
                &lt;span&gt;West Bengal Board Format | Test Paper I - Vinod Singh&lt;/span&gt;
            &lt;/div&gt;
        &lt;/div&gt;
    &lt;/div&gt;

    &lt;div class=&quot;paper-description&quot;&gt;
        &lt;div class=&quot;description-header&quot;&gt;
            &lt;i class=&quot;fas fa-info-circle&quot;&gt;&lt;/i&gt;
            &lt;h3&gt;About This Examination Paper&lt;/h3&gt;
        &lt;/div&gt;
        &lt;p&gt;This is a Mathematics Test Examination paper from Prime Maths, designed for Class X (Madhyamik) students. It follows the standard West Bengal Board format with a total of 90 marks and a duration of 3 hours and 15 minutes.&lt;/p&gt;
        
        &lt;div class=&quot;topics-grid&quot;&gt;
            &lt;div class=&quot;topic-card&quot;&gt;
                &lt;div class=&quot;topic-icon&quot;&gt;
                    &lt;i class=&quot;fas fa-calculator&quot;&gt;&lt;/i&gt;
                &lt;/div&gt;
                &lt;h4&gt;Arithmetic&lt;/h4&gt;
                &lt;p&gt;Problems on simple interest, compound interest, and partnership business&lt;/p&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;topic-card&quot;&gt;
                &lt;div class=&quot;topic-icon&quot;&gt;
                    &lt;i class=&quot;fas fa-superscript&quot;&gt;&lt;/i&gt;
                &lt;/div&gt;
                &lt;h4&gt;Algebra&lt;/h4&gt;
                &lt;p&gt;Quadratic equations, ratio and proportion, variation, and surds&lt;/p&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;topic-card&quot;&gt;
                &lt;div class=&quot;topic-icon&quot;&gt;
                    &lt;i class=&quot;fas fa-shapes&quot;&gt;&lt;/i&gt;
                &lt;/div&gt;
                &lt;h4&gt;Geometry&lt;/h4&gt;
                &lt;p&gt;Theorems related to circles, tangents, circumcenters, and construction&lt;/p&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;topic-card&quot;&gt;
                &lt;div class=&quot;topic-icon&quot;&gt;
                    &lt;i class=&quot;fas fa-ruler-combined&quot;&gt;&lt;/i&gt;
                &lt;/div&gt;
                &lt;h4&gt;Mensuration&lt;/h4&gt;
                &lt;p&gt;Problems involving cubes, cylinders, cones, spheres, and cuboids&lt;/p&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;topic-card&quot;&gt;
                &lt;div class=&quot;topic-icon&quot;&gt;
                    &lt;i class=&quot;fas fa-sine-wave&quot;&gt;&lt;/i&gt;
                &lt;/div&gt;
                &lt;h4&gt;Trigonometry&lt;/h4&gt;
                &lt;p&gt;Solving identities, trigonometric ratios, heights and distances problems&lt;/p&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;topic-card&quot;&gt;
                &lt;div class=&quot;topic-icon&quot;&gt;
                    &lt;i class=&quot;fas fa-chart-bar&quot;&gt;&lt;/i&gt;
                &lt;/div&gt;
                &lt;h4&gt;Statistics&lt;/h4&gt;
                &lt;p&gt;Calculation of Mean, Median, and Mode from frequency distribution tables&lt;/p&gt;
            &lt;/div&gt;
        &lt;/div&gt;
        
        &lt;div class=&quot;exam-purpose&quot;&gt;
            &lt;i class=&quot;fas fa-lightbulb&quot;&gt;&lt;/i&gt;
            &lt;p&gt;This paper serves as excellent practice material for students preparing for their final Madhyamik examination, testing their understanding of both objective (MCQ, True/False, Fill in the blanks) and subjective (long answer) type questions.&lt;/p&gt;
        &lt;/div&gt;
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&lt;div class=&quot;exam-paper&quot;&gt;
    &lt;h2&gt;&lt;div _ngcontent-ng-c1150074581=&quot;&quot; aria-busy=&quot;false&quot; aria-live=&quot;polite&quot; class=&quot;markdown markdown-main-panel stronger enable-updated-hr-color&quot; dir=&quot;ltr&quot; id=&quot;model-response-message-contentr_1cd5db708a270dc7&quot; inline-copy-host=&quot;&quot; style=&quot;--animation-duration: 400ms; --fade-animation-function: linear; animation: 0s ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px none rgb(31, 31, 31); clear: none; clip: auto; color: #1f1f1f; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; font-family: &amp;quot;Google Sans Text&amp;quot;, sans-serif; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 0px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;p data-path-to-node=&quot;0&quot; style=&quot;animation: 0s ease 0s 1 normal none running none; appearance: none; background-attachment: scroll; background-clip: border-box; background-image: none; background-origin: padding-box; background-position: 0% 0%; background-repeat: repeat; background-size: auto; border: 0px none rgb(31, 31, 31); clear: none; clip: auto; columns: auto; contain: none; container: none; content: normal; cursor: auto; cx: 0px; cy: 0px; d: none; direction: ltr; fill: rgb(0, 0, 0); filter: none; flex: 0 1 auto; float: none; gap: normal; hyphens: manual; inset: auto; interactivity: auto; isolation: auto; line-height: 1.15; margin-bottom: 16px; margin-left: 0px; margin-right: 0px; margin-top: 0px !important; margin: 0px 0px 16px; marker: none; mask-clip: border-box; mask-composite: add; mask-image: none; mask-mode: match-source; mask-origin: border-box; mask-repeat: repeat; mask-size: auto; mask: none; offset: normal; opacity: 1; order: 0; outline: rgb(31, 31, 31) none 0px; overlay: none; padding: 0px; page: auto; perspective: none; position: static; quotes: auto; r: 0px; resize: none; rotate: none; rx: auto; ry: auto; scale: none; speak: normal; stroke: none; transform: none; transition: all; translate: none; visibility: visible; x: 0px; y: 0px; zoom: 1;&quot;&gt;&lt;br /&gt;&lt;/p&gt;&lt;/div&gt;&lt;/h2&gt;&lt;h2&gt;MADHYAMIK PRACTICE TEST PAPER&lt;/h2&gt;
    &lt;p&gt;&lt;strong&gt;Time:&lt;/strong&gt; 3 Hours 15 Minutes &amp;nbsp;|&amp;nbsp; &lt;strong&gt;Full Marks:&lt;/strong&gt; 90&lt;/p&gt;

    &lt;h3&gt;1. Select the correct answer in each of the following cases: &lt;strong&gt;[1 × 6 = 6]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;
            &lt;p&gt;If the difference between compound interest and simple interest on a certain principal for 3 years at 20% compound interest rate per annum is ₹48, the principal will be:&lt;/p&gt;
            &lt;ul&gt;
                &lt;li&gt;a) ₹350&lt;/li&gt;
                &lt;li&gt;b) ₹375&lt;/li&gt;
                &lt;li&gt;c) ₹400&lt;/li&gt;
                &lt;li&gt;d) ₹425&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;
            &lt;p&gt;For what value(s) of \(k\) will the quadratic equation \(2x^2 - kx + k = 0\) have equal roots?&lt;/p&gt;
            &lt;ul&gt;
                &lt;li&gt;a) Only 0&lt;/li&gt;
                &lt;li&gt;b) Only 8&lt;/li&gt;
                &lt;li&gt;c) 4&lt;/li&gt;
                &lt;li&gt;d) 0 and 8&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;
            &lt;p&gt;If \(A:B=2:3\), \(B:C=5:8\), and \(C:D=6:7\), what is the value of \(A:D\)?&lt;/p&gt;
            &lt;ul&gt;
                &lt;li&gt;a) 2:7&lt;/li&gt;
                &lt;li&gt;b) 5:8&lt;/li&gt;
                &lt;li&gt;c) 7:2&lt;/li&gt;
                &lt;li&gt;d) 5:14&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;
            &lt;p&gt;\(O\) is the circumcenter of \(\triangle ABC\). Given \(\angle BAC=85^\circ\) and \(\angle BCA=55^\circ\), the value of \(\angle AOC\) will be:&lt;/p&gt;
            &lt;ul&gt;
                &lt;li&gt;a) \(65^\circ\)&lt;/li&gt;
                &lt;li&gt;b) \(45^\circ\)&lt;/li&gt;
                &lt;li&gt;c) \(50^\circ\)&lt;/li&gt;
                &lt;li&gt;d) \(100^\circ\)&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;
            &lt;p&gt;When two circles touch each other internally, what is the maximum number of common tangents that can be drawn?&lt;/p&gt;
            &lt;ul&gt;
                &lt;li&gt;a) 1&lt;/li&gt;
                &lt;li&gt;b) 3&lt;/li&gt;
                &lt;li&gt;c) 4&lt;/li&gt;
                &lt;li&gt;d) 2&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;
            &lt;p&gt;The diameters of two solid cylinders are 8 cm and 12 cm respectively, and their heights are \(3(n + 1)\) cm and \((n + 3)\) cm respectively. If the volumes of the two cylinders are equal, what is the value of \(n\)?&lt;/p&gt;
            &lt;ul&gt;
                &lt;li&gt;a) 13&lt;/li&gt;
                &lt;li&gt;b) 7&lt;/li&gt;
                &lt;li&gt;c) 8&lt;/li&gt;
                &lt;li&gt;d) 5&lt;/li&gt;
            &lt;/ul&gt;
        &lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;2. Fill in the blanks (Any five): &lt;strong&gt;[1 × 5 = 5]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;If \(P_1: P_2: P_3\) is the ratio of profits and \(t_1:t_2:t_3\) is the ratio of time, then the ratio of invested capital is ______________.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;\(7\sqrt{\frac{101}{404}}\) is a ______________ number.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;If \(x \propto z\) and \(y \propto z\), then \(x+y \propto\) ______________.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;The value of \(\cos 28^\circ \csc 62^\circ + \tan 1^\circ \cot 89^\circ\) = ______________.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;If the ratio of three consecutive angles of a cyclic quadrilateral is \(1 : 3 : 4\), the measure of the fourth angle = ______________.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;If the volume of a cube is \(V\), the total surface area of the cube = ______________ square units.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;3. Write True or False (Any five): &lt;strong&gt;[1 × 5 = 5]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;A partnership business requires at least 4 people.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;If the annual simple interest rate is 12%, the interest for \(8\frac{1}{3}\) years will be equal to the principal.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;The two roots of the equation \(x^2 = -2024\) are real numbers.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;In two triangles ABC and DEF, if \(\angle A= \angle D\), \(\angle B= \angle F\), and \(\angle C = \angle E\), then \(\frac{AB}{DE} = \frac{AC}{DF} = \frac{BC}{EF}\).&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;Two concentric circles of different radius will have one common tangent.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;If the radius of the base of a right circular cone is halved and the height is doubled, the volume of the cone remains the same.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;4. Answer the following questions (Any ten): &lt;strong&gt;[2 × 10 = 20]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;If the simple interest on a principal for \(n\) years at \(r\%\) per annum is \(\frac{pnr}{25}\), show that the Principal = \(4p\).&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;If ₹8,000 is invested for 3 years at 10% compound interest per annum, how much interest will be earned at the end of 2 years?&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;In a business, A invested ₹1800 and B invested ₹1000 for 9 months. If both their profit shares are equal, for how long was A&#39;s money invested?&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;What is the ratio of the sum and product of the roots of the equation \(-x^2 - 6x + 2 = 0\)?&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;Rationalize the denominator: \(\frac{2\sqrt{2}-3}{\sqrt{2}}\).&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;AB and AC are two chords of a circle that are perpendicular to each other. If AB = 5 cm and AC = 12 cm, find the length of the radius of the circle.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;AD is perpendicular to the hypotenuse BC of a right-angled triangle ABC. If BC = 16 cm and BD = 9 cm, find the length of AB.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;The curved surface area of a right circular cone is \(\sqrt{5}\) times its base area. What is the ratio of the height to the radius of the cone?&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;If \(x = a \cos \theta + b \sin \theta\) and \(y = a \sin \theta - b \cos \theta\), what is the value of \(x^2 + y^2\)?&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;Find the median and arithmetic mean of the numbers: 1, 2, 3, 4, 6, 5, 7, 8, 9, 10, 11.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;The length of the diagonal of a cube is \(4\sqrt{3}\) cm. Find the total surface area of the cube.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;5. Answer any one question: &lt;strong&gt;[5 × 1 = 5]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;The simple interest and annual compound interest on a certain capital for 2 years at the same rate are ₹4,000 and ₹4,100 respectively. Find the capital and the rate of interest.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;The current number of students in all secondary education centers in a district is 3993. If the number of students increases by 10% compared to the previous year every year, determine what the number of students was in all secondary education centers of that district 3 years ago.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;6. Solve any one question: &lt;strong&gt;[3 × 1 = 3]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;\(\frac{1}{x} - \frac{1}{x+b} = \frac{1}{a} - \frac{1}{a+b}, \quad x \neq 0, -b.\)&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;If \(x = \frac{\sqrt{a+2} + \sqrt{a-2}}{\sqrt{a+2} - \sqrt{a-2}}\), where \(a &amp;gt; 2\), find the simplest value of \(x + \frac{1}{x}\).&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;7. Solve any one question: &lt;strong&gt;[3 × 1 = 3]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;Find the simplest value: \(\frac{2(\sqrt{2}+\sqrt{3})}{\sqrt{3}+1} - \frac{2(\sqrt{2}-\sqrt{3})}{\sqrt{3}-1}\).&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;If it takes 9 days for 5 men to cultivate 10 acres of land, use the theory of variation to find how many days it will take for 25 men to cultivate 30 acres of land.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;8. Answer any one question: &lt;strong&gt;[3 × 1 = 3]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;If \(a:b = b:c\), prove that \(\frac{(a+b)}{(b+c)^2} = \frac{a^2+b^2}{b^2+c^2}\).&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;If \(\frac{a+b-c}{a+b} = \frac{b+c-a}{b+c} = \frac{c+a-b}{c+a}\) and \(a+b+c \neq 0\), prove that \(a = b = c\).&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;9. Answer any one question: &lt;strong&gt;[5 × 1 = 5]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;Prove that the angle subtended by an arc of a circle at the center is double the angle subtended by it at any point on the remaining part of the circle.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;Prove that if a perpendicular is drawn from the center of a circle to a chord which is not a diameter, the perpendicular bisects the chord.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;10. Answer any one question: &lt;strong&gt;[3 × 1 = 3]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;Prove that a cyclic trapezium is an isosceles trapezium and the lengths of its diagonals are equal.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;In an isosceles triangle ABC, AB = AC and BE is perpendicular to AC from B. Prove that \(BC^2 = 2AC \times CE\).&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;11. Answer any one question: &lt;strong&gt;[5 × 1 = 5]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;Draw a square figure with a side length of 14 cm.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;Draw a right-angled triangle whose sides adjacent to the right angle have lengths 4 cm and 8 cm. Draw the incircle of the triangle. (Only traces of construction are required).&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;12. Solve any two questions: &lt;strong&gt;[3 × 2 = 6]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;If \(m = \cos \theta - \sin \theta\) and \(n = \cos \theta + \sin \theta\), prove that \(\sqrt{\frac{m}{n}} + \sqrt{\frac{n}{m}} = \frac{2}{\sqrt{1-\tan^2 \theta}}\).&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;Find the value of \(x\): \(x \sin 60^\circ \cos^2 30^\circ = \frac{\tan^2 45^\circ \sec 60^\circ}{\csc 60^\circ}\).&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;The measures of three angles of a quadrilateral are \(\frac{\pi}{3}\), \(\frac{5\pi}{6}\), and \(90^\circ\). Find the circular measure (in radians) of the fourth angle.&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;13. Answer any one question: &lt;strong&gt;[5 × 1 = 5]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;From an object on the roof of a house \(30\sqrt{3}\) meters high, the angles of depression of the top and bottom of a lamp post are \(30^\circ\) and \(60^\circ\) respectively. Find the height of the lamp post.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;From the roof of a five-story building 18 meters high, the angle of elevation of the top of a monument is observed to be \(45^\circ\) and the angle of depression of the foot of the monument is observed to be \(60^\circ\). What is the height of the monument?&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;14. Answer any two questions: &lt;strong&gt;[4 × 2 = 8]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;If the radius of a solid sphere and a solid right circular cylinder are equal and their volumes are also equal, calculate the ratio of the radius and height of the cylinder.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;The volume of a right circular cone is \(100\pi\) cubic cm and its height is 12 cm. Calculate and write the slant height of the cone.&lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;A rectangular pond is 20 m long and 18.5 m wide, and has water 3.2 m deep. How long will it take to irrigate the entire water of the pond using a pump that can irrigate 160 kiloliters of water per hour?&lt;/li&gt;
    &lt;/ol&gt;

    &lt;h3&gt;15. Answer any two questions: &lt;strong&gt;[4 × 2 = 8]&lt;/strong&gt;&lt;/h3&gt;
    &lt;ol type=&quot;i&quot;&gt;
        &lt;li class=&quot;question&quot;&gt;
            &lt;p&gt;Determine the Arithmetic Mean from the following frequency distribution:&lt;/p&gt;
            &lt;table&gt;
                &lt;tbody&gt;&lt;tr&gt;&lt;th&gt;Value:&lt;/th&gt;&lt;td&gt;Below 10&lt;/td&gt;&lt;td&gt;Below 20&lt;/td&gt;&lt;td&gt;Below 30&lt;/td&gt;&lt;td&gt;Below 40&lt;/td&gt;&lt;td&gt;Below 50&lt;/td&gt;&lt;td&gt;Below 60&lt;/td&gt;&lt;td&gt;Below 70&lt;/td&gt;&lt;td&gt;Below 80&lt;/td&gt;&lt;/tr&gt;
                &lt;tr&gt;&lt;th&gt;Frequency:&lt;/th&gt;&lt;td&gt;4&lt;/td&gt;&lt;td&gt;16&lt;/td&gt;&lt;td&gt;40&lt;/td&gt;&lt;td&gt;76&lt;/td&gt;&lt;td&gt;96&lt;/td&gt;&lt;td&gt;112&lt;/td&gt;&lt;td&gt;126&lt;/td&gt;&lt;td&gt;125&lt;/td&gt;&lt;/tr&gt;
            &lt;/tbody&gt;&lt;/table&gt;
        &lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;
            &lt;p&gt;The frequency distribution of daily wages of 100 workers is as follows. Find the median of this distribution.&lt;/p&gt;
            &lt;table&gt;
                &lt;tbody&gt;&lt;tr&gt;&lt;th&gt;Daily Wage (in ₹):&lt;/th&gt;&lt;td&gt;460-470&lt;/td&gt;&lt;td&gt;470-480&lt;/td&gt;&lt;td&gt;480-490&lt;/td&gt;&lt;td&gt;490-500&lt;/td&gt;&lt;td&gt;500-510&lt;/td&gt;&lt;td&gt;510-520&lt;/td&gt;&lt;td&gt;520-530&lt;/td&gt;&lt;/tr&gt;
                &lt;tr&gt;&lt;th&gt;No. of Workers:&lt;/th&gt;&lt;td&gt;6&lt;/td&gt;&lt;td&gt;4&lt;/td&gt;&lt;td&gt;29&lt;/td&gt;&lt;td&gt;23&lt;/td&gt;&lt;td&gt;16&lt;/td&gt;&lt;td&gt;10&lt;/td&gt;&lt;td&gt;2&lt;/td&gt;&lt;/tr&gt;
            &lt;/tbody&gt;&lt;/table&gt;
        &lt;/li&gt;
        &lt;li class=&quot;question&quot;&gt;
            &lt;p&gt;Determine the Mode of the frequency distribution below:&lt;/p&gt;
            &lt;table&gt;
                &lt;tbody&gt;&lt;tr&gt;&lt;th&gt;Class Limit:&lt;/th&gt;&lt;td&gt;0-5&lt;/td&gt;&lt;td&gt;5-10&lt;/td&gt;&lt;td&gt;10-15&lt;/td&gt;&lt;td&gt;15-20&lt;/td&gt;&lt;td&gt;20-25&lt;/td&gt;&lt;td&gt;25-30&lt;/td&gt;&lt;td&gt;30-35&lt;/td&gt;&lt;/tr&gt;
                &lt;tr&gt;&lt;th&gt;Frequency:&lt;/th&gt;&lt;td&gt;5&lt;/td&gt;&lt;td&gt;12&lt;/td&gt;&lt;td&gt;18&lt;/td&gt;&lt;td&gt;28&lt;/td&gt;&lt;td&gt;17&lt;/td&gt;&lt;td&gt;12&lt;/td&gt;&lt;td&gt;8&lt;/td&gt;&lt;/tr&gt;
            &lt;/tbody&gt;&lt;/table&gt;
        &lt;/li&gt;
    &lt;/ol&gt;
&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mathsvinu.blogspot.com/feeds/5216387300153953794/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mathsvinu.blogspot.com/2026/01/madhyamik-practice-test-paper.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/5216387300153953794'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4710016337793683220/posts/default/5216387300153953794'/><link rel='alternate' type='text/html' href='http://mathsvinu.blogspot.com/2026/01/madhyamik-practice-test-paper.html' title='Madhyamik Practice Test Paper '/><author><name>Vinod Singh</name><uri>http://www.blogger.com/profile/10860507360539742165</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='31' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpBmcsG8f7HNpg-T4DZl30ZxmqF5ciV4Yo4cPGzp5XDaixuvuGXTm2vEQIuAeC_cugiYqspdJIOmnXfrZeahQO9op4Wt9uCmdmQ3a4qT4OoNA1IF5CKH_U2v1RAdgYeVM/s113/Profile.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4710016337793683220.post-4763292514405165068</id><published>2026-01-13T03:27:00.000-08:00</published><updated>2026-01-13T03:45:41.604-08:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="cbse"/><category scheme="http://www.blogger.com/atom/ns#" term="ICSE"/><category scheme="http://www.blogger.com/atom/ns#" term="IX"/><category scheme="http://www.blogger.com/atom/ns#" term="X"/><title type='text'>Problems on Algebra : ICSE and CBSE</title><content type='html'>&lt;link rel=&quot;stylesheet&quot; href=&quot;https://cdnjs.cloudflare.com/ajax/libs/font-awesome/6.4.0/css/all.min.css&quot;&gt;

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&lt;div id=&quot;math-app-wrapper&quot;&gt;
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        &lt;header&gt;
            &lt;h1&gt;&lt;i class=&quot;fas fa-calculator&quot;&gt;&lt;/i&gt; Algebraic Identities Problem Set&lt;/h1&gt;
            &lt;div class=&quot;subtitle&quot;&gt;Master Algebra through Practice Problems. Prime Maths &lt;/div&gt;
        &lt;/header&gt;
        
        &lt;div class=&quot;description&quot;&gt;
            &lt;h3&gt;&lt;i class=&quot;fas fa-info-circle&quot;&gt;&lt;/i&gt; About This Problem Set&lt;/h3&gt;
            &lt;p&gt;This collection of problems is designed for &lt;strong&gt;Class IX students&lt;/strong&gt; following &lt;strong&gt;CBSE, ICSE, and State Board&lt;/strong&gt; curricula. The problems cover fundamental algebraic identities, inequalities, factorization, and polynomial expansions. Work through these problems systematically to strengthen your understanding of algebraic concepts and their applications.&lt;/p&gt;
        &lt;/div&gt;
        
        &lt;div class=&quot;problem-container&quot;&gt;
            &lt;div class=&quot;problem-header&quot;&gt;
                &lt;div class=&quot;problem-number&quot;&gt;Problem &lt;span id=&quot;current-problem&quot;&gt;1&lt;/span&gt;&lt;/div&gt;
                &lt;div class=&quot;progress&quot;&gt;Problem &lt;span id=&quot;current&quot;&gt;1&lt;/span&gt; of &lt;span id=&quot;total&quot;&gt;22&lt;/span&gt;&lt;/div&gt;
            &lt;/div&gt;
            
            &lt;div class=&quot;problem-statement&quot; id=&quot;problem-text&quot;&gt;
                &lt;div class=&quot;math-container&quot;&gt;
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                &lt;div class=&quot;problem-grid&quot; id=&quot;problem-grid&quot;&gt;
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        &lt;/div&gt;
        
        &lt;footer&gt;
            &lt;p&gt;Practice these problems to master algebraic identities. Remember to attempt each problem before checking the hint!&lt;/p&gt;
            &lt;p&gt;Designed for Class IX Mathematics&lt;/p&gt;
          &lt;p&gt;Designed by Vinod Singh, 9038126497&lt;/p&gt;
        &lt;/footer&gt;
    &lt;/div&gt;
&lt;/div&gt;

&lt;script&gt;
    // Problem data with hints - using proper LaTeX formatting
    const problems = [
        {
            statement: &quot;Prove that for any real number \\(x\\), \\(x^2 \\geq 0\\).&quot;,
            hint: &quot;Consider the definition of squaring a real number. Think about what happens when you square positive numbers, negative numbers, and zero.&quot;
        },
        {
            statement: &quot;Using (1) or otherwise prove that for any real numbers \\(x\\) and \\(y\\) (\\(x &gt; 0\\) and \\(y &gt; 0\\)), \\(\\frac{x + y}{2} \\geq \\sqrt{xy}\\).&quot;,
            hint: &quot;Start with \\((\\sqrt{x} - \\sqrt{y})^2 \\geq 0\\) and expand. This is the AM-GM inequality for two positive numbers.&quot;
        },
        {
            statement: &quot;Show that \\(a^{2} + b^{2} + c^{2} - ab - bc - ca = \\frac{1}{2} ((a - b)^{2} + (b - c)^{2} + (c - a)^{2})\\).&quot;,
            hint: &quot;Expand the right side and simplify. Alternatively, multiply both sides by 2 and expand all squares.&quot;
        },
        {
            statement: &quot;Justify the following statement: if \\(x^{2} + y^{2} = 0 \\Rightarrow x = y = 0\\).&quot;,
            hint: &quot;Consider that squares of real numbers are always non-negative. What must be true for the sum of non-negative numbers to be zero?&quot;
        },
        {
            statement: &quot;Using (4) prove that if \\(a^{3} + b^{3} + c^{3} = 3abc\\) then either \\(a + b + c = 0\\) or \\(a = b = c\\).&quot;,
            hint: &quot;Use the identity \\(a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\). Then apply problem (3) and (4).&quot;
        },
        {
            statement: &quot;If \\(\\frac{a}{1 - a} + \\frac{b}{1 - b} + \\frac{c}{1 - c} = 1\\) then find the value of \\(\\frac{1}{1 - a} + \\frac{1}{1 - b} + \\frac{1}{1 - c}\\).&quot;,
            hint: &quot;Add 3 to both sides of the given equation and simplify each term. Look for a pattern in the resulting expression.&quot;
        },
        {
            statement: &quot;If \\(a^{2} + b^{2} + c^{2} + \\frac{1}{a^{2}} + \\frac{1}{b^{2}} + \\frac{1}{c^{2}} = 6\\) prove that \\(a^{2} + b^{2} + c^{2} = 3\\).&quot;,
            hint: &quot;Use the inequality \\(x + \\frac{1}{x} \\geq 2\\) for \\(x &gt; 0\\). Apply it to each of \\(a^2, b^2, c^2\\).&quot;
        },
        {
            statement: &quot;Find the coefficient of \\(a^{2}\\) in the expansion of \\((a^{2} - a + 1)^{2} + (a^{2} + a + 1)^{2}\\).&quot;,
            hint: &quot;Expand both squares separately, then combine like terms. Alternatively, use the identity \\((x+y+z)^2 = x^2+y^2+z^2+2xy+2xz+2yz\\).&quot;
        },
        {
            statement: &quot;If \\(a + b = 8\\) and \\(ab = 7\\) then find the value of \\(a^{4} + a^{2}b^{2} + b^{4}\\).&quot;,
            hint: &quot;Express \\(a^4 + a^2b^2 + b^4\\) in terms of \\(a^2+b^2\\) and \\(ab\\). First find \\(a^2+b^2\\) using \\((a+b)^2 = a^2+b^2+2ab\\).&quot;
        },
        {
            statement: &quot;Show that \\((x - y)(x^{4} + x^{3}y + x^{2}y^{2} + xy^{3} + y^{4}) = x^{5} - y^{5}\\).&quot;,
            hint: &quot;Multiply \\((x-y)\\) by each term in the second factor and observe the telescoping cancellations.&quot;
        },
        {
            statement: &quot;Find \\((x - y)(x^{5} + x^{4}y + x^{3}y^{2} + x^{2}y^{3} + xy^{4} + y^{5})\\).&quot;,
            hint: &quot;This follows the pattern from problem 10. The result will be similar but with exponent 6.&quot;
        },
        {
            statement: &quot;Try to generalise the results of Problem 10 and 11.&quot;,
            hint: &quot;Observe the pattern: \\((x-y)(x^{n-1} + x^{n-2}y + ... + xy^{n-2} + y^{n-1}) = x^n - y^n\\) for natural number \\(n\\).&quot;
        },
        {
            statement: &quot;Show that \\((x + y)\\) is a factor of \\(x^{5} + y^{5}\\).&quot;,
            hint: &quot;Try to express \\(x^5 + y^5\\) in a form that has \\((x+y)\\) as a factor. Consider adding and subtracting terms or using the result from problem 10 with signs adjusted.&quot;
        },
        {
            statement: &quot;Using Problem 13, show that \\((x + y)\\) is a factor of \\(x^{7} + y^{7}\\).&quot;,
            hint: &quot;Use a similar approach as problem 13. Alternatively, note that for odd \\(n\\), \\(x^n + y^n\\) has \\((x+y)\\) as a factor.&quot;
        },
        {
            statement: &quot;Prove that \\(1001^{7} + 31^{7}\\) is divisible by 1032.&quot;,
            hint: &quot;Note that 1032 = 1001 + 31. Use the result from problem 14 with \\(x=1001\\) and \\(y=31\\).&quot;
        },
        {
            statement: &quot;Prove that \\(785^{5} - 43^{5}\\) is divisible by 742.&quot;,
            hint: &quot;Note that 742 = 785 - 43. Use the difference of powers factorization from problem 12.&quot;
        },
        {
            statement: &quot;If \\(a,b\\) are positive numbers, then show that...&quot;,
            hint: &quot;The problem statement seems incomplete. Consider that for positive numbers, many inequalities like AM-GM or Cauchy-Schwarz might apply.&quot;
        },
        {
            statement: &quot;Let \\(a,b,x,y\\) be real numbers and let \\(x,y &gt; 0\\). Show that \\(\\frac{a^2}{x} + \\frac{b^2}{y} \\geq \\frac{(a + b)^2}{x + y}\\).&quot;,
            hint: &quot;This is Titu&#39;s lemma (a special case of Cauchy-Schwarz). Start with \\((\\frac{a}{\\sqrt{x}} \\cdot \\sqrt{x} + \\frac{b}{\\sqrt{y}} \\cdot \\sqrt{y})^2\\).&quot;
        },
        {
            statement: &quot;Find the value of \\((x - a)^3 + (x - b)^3 + (x - c)^3 - 3(x - a)(x - b)(x - c)\\) if \\(3x = a + b + c\\).&quot;,
            hint: &quot;Use the identity \\(p^3 + q^3 + r^3 - 3pqr = \\frac{1}{2}(p+q+r)[(p-q)^2+(q-r)^2+(r-p)^2]\\). Let \\(p=x-a, q=x-b, r=x-c\\).&quot;
        },
        {
            statement: &quot;Express \\(x^{4} + 3x^{2} + 4\\) as difference of two squares.&quot;,
            hint: &quot;Try to write it as \\((x^2 + 2)^2 - (x)^2\\) or similar. Add and subtract a suitable term to complete a square.&quot;
        },
        {
            statement: &quot;Using Problem 3 show that for any real numbers \\(a,b,c\\), \\(a^{2} + b^{2} + c^{2} \\geq ab + bc + ca\\).&quot;,
            hint: &quot;From problem 3, the expression \\(a^2+b^2+c^2-ab-bc-ca\\) equals half the sum of squares, which is always non-negative.&quot;
        },
        {
            statement: &quot;For any real numbers \\(x,y,z\\) show that \\(3(x^{2} + y^{2} + z^{2}) \\geq (x + y + z)^{2} \\geq 3(xy + yz + zx)\\).&quot;,
            hint: &quot;For the left inequality, expand \\((x+y+z)^2\\) and use problem 21. For the right inequality, use \\((x-y)^2+(y-z)^2+(z-x)^2 \\geq 0\\).&quot;
        }
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