<?xml version='1.0' encoding='UTF-8'?><rss xmlns:atom="http://www.w3.org/2005/Atom" xmlns:openSearch="http://a9.com/-/spec/opensearchrss/1.0/" xmlns:blogger="http://schemas.google.com/blogger/2008" xmlns:georss="http://www.georss.org/georss" xmlns:gd="http://schemas.google.com/g/2005" xmlns:thr="http://purl.org/syndication/thread/1.0" version="2.0"><channel><atom:id>tag:blogger.com,1999:blog-3045829400714783786</atom:id><lastBuildDate>Sat, 31 Aug 2024 17:06:16 +0000</lastBuildDate><title>TECNOMAX</title><description>Aqui encontrareis toda la informacióm relacionada con el mundo de la Tecnología</description><link>http://tecnologiamaxima.blogspot.com/</link><managingEditor>noreply@blogger.com (Anonymous)</managingEditor><generator>Blogger</generator><openSearch:totalResults>6</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3045829400714783786.post-7361443627065068959</guid><pubDate>Fri, 06 Jun 2014 11:47:00 +0000</pubDate><atom:updated>2014-06-06T04:47:45.539-07:00</atom:updated><title>Resolución del puzzle desde Outlook Express</title><description>&lt;div dir=&#39;ltr&#39;&gt;Solución:&lt;br&gt; Este problema parece que no tiene sentido lo que tan nunca... dos  triángulos de dimensiones aparentemente iguales, consistiendo en  segmentos más pequeños, aparecen cubrir menos área cuando se &amp;nbsp;reordenan  diferentemente... ¿a dónde fue el bloque que falta?&lt;br&gt; &lt;br&gt; La relación del triángulo completo es 13:5, el azul 5:2 y el rojo 8:3. Estos no son cocientes equivalentes.&lt;br&gt; &lt;br&gt; Podemos ver a nuestro buen amigo Pythagoras: dada la hipotenusa de cada  triángulo es la raíz cuadrada de la suma de los otros dos lados al  cuadrado, la hipotenusa de cada triángulo es: triángulo completo: √194  rojo: azul √73: √29 si este &quot;triángulo&quot; es todo lo que parece, la  hipotenusa del rojo y triángulo azul sería igual que el triángulo  completo.&lt;br&gt; &lt;br&gt; La hipotenusa tiene diferentes pendientes, como los ángulos son diferentes.&lt;br&gt;  		 	   		  &lt;/div&gt;</description><link>http://tecnologiamaxima.blogspot.com/2014/06/resolucion-del-puzzle-desde-outlook.html</link><author>noreply@blogger.com (Anonymous)</author><thr:total>0</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3045829400714783786.post-6909034730802071983</guid><pubDate>Fri, 23 May 2014 11:32:00 +0000</pubDate><atom:updated>2014-05-23T04:32:51.307-07:00</atom:updated><title></title><description>&lt;iframe width=&quot;420&quot; height=&quot;315&quot; src=&quot;//www.youtube.com/embed/484ZbQus08E&quot; frameborder=&quot;0&quot; allowfullscreen&gt;&lt;/iframe&gt;</description><link>http://tecnologiamaxima.blogspot.com/2014/05/blog-post_380.html</link><author>noreply@blogger.com (Anonymous)</author><thr:total>0</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3045829400714783786.post-9095399106392261202</guid><pubDate>Thu, 03 Apr 2014 17:20:00 +0000</pubDate><atom:updated>2014-04-03T10:20:47.163-07:00</atom:updated><title></title><description>&lt;iframe width=&quot;425&quot; height=&quot;350&quot; frameborder=&quot;0&quot; scrolling=&quot;no&quot; marginheight=&quot;0&quot; marginwidth=&quot;0&quot; src=&quot;https://maps.google.es/maps?q=156+San+Miguel,+Armilla,+Andaluc%C3%ADa,+Espa%C3%B1a&amp;amp;layer=c&amp;amp;sll=37.141072,-3.618778&amp;amp;cbp=13,217.59,,0,3.44&amp;amp;cbll=37.140915,-3.61851&amp;amp;hl=es&amp;amp;ie=UTF8&amp;amp;hq=&amp;amp;hnear=San+Miguel,+156,+18100+Armilla,+Granada&amp;amp;ll=37.141072,-3.618778&amp;amp;spn=0.007714,0.015278&amp;amp;t=m&amp;amp;z=14&amp;amp;panoid=Rvb8eThyRVgInBDuhksTww&amp;amp;source=embed&amp;amp;output=svembed&quot;&gt;&lt;/iframe&gt;&lt;br /&gt;&lt;small&gt;&lt;a href=&quot;https://maps.google.es/maps?q=156+San+Miguel,+Armilla,+Andaluc%C3%ADa,+Espa%C3%B1a&amp;amp;layer=c&amp;amp;sll=37.141072,-3.618778&amp;amp;cbp=13,217.59,,0,3.44&amp;amp;cbll=37.140915,-3.61851&amp;amp;hl=es&amp;amp;ie=UTF8&amp;amp;hq=&amp;amp;hnear=San+Miguel,+156,+18100+Armilla,+Granada&amp;amp;ll=37.141072,-3.618778&amp;amp;spn=0.007714,0.015278&amp;amp;t=m&amp;amp;z=14&amp;amp;panoid=Rvb8eThyRVgInBDuhksTww&amp;amp;source=embed&quot; style=&quot;color:#0000FF;text-align:left&quot;&gt;Ver mapa más grande&lt;/a&gt;&lt;/small&gt;</description><link>http://tecnologiamaxima.blogspot.com/2014/04/blog-post.html</link><author>noreply@blogger.com (Anonymous)</author><thr:total>0</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3045829400714783786.post-2505443671050654136</guid><pubDate>Fri, 28 Mar 2014 12:02:00 +0000</pubDate><atom:updated>2014-05-30T04:00:44.058-07:00</atom:updated><title></title><description>&lt;a href=&quot;http://www.juntadeandalucia.es/averroes/centros-tic/18700232/helvia/sitio/&quot; style=&quot;margin-left: auto; margin-right: auto;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiiiOpgMCa-LIsUs5dHS11uYBQ5P3LgLcBAWuvZe9Ir_5uOLVS9sx78O9fUPu3FsJil-xaUdsstbnLy4LrByhpOjU2MOC0iA-HyN9CWjsMZGiFIZuYtLLAYeldfcHBBUhSeGJAzh46qshKi/s1600/ies-2.JPG&quot; /&gt;&lt;/a&gt;&lt;a href=&quot;http://www.juntadeandalucia.es/averroes/centros-tic/18700232/helvia/sitio/&quot; target=&quot;_blank&quot;&gt;http://www.juntadeandalucia.es/averroes/centros-tic/18700232/helvia/sitio/ &lt;/a&gt;</description><link>http://tecnologiamaxima.blogspot.com/2014/03/httpwww_28.html</link><author>noreply@blogger.com (Anonymous)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiiiOpgMCa-LIsUs5dHS11uYBQ5P3LgLcBAWuvZe9Ir_5uOLVS9sx78O9fUPu3FsJil-xaUdsstbnLy4LrByhpOjU2MOC0iA-HyN9CWjsMZGiFIZuYtLLAYeldfcHBBUhSeGJAzh46qshKi/s72-c/ies-2.JPG" height="72" width="72"/><thr:total>0</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3045829400714783786.post-2469415796164901041</guid><pubDate>Fri, 21 Mar 2014 12:41:00 +0000</pubDate><atom:updated>2014-05-30T04:45:32.049-07:00</atom:updated><title></title><description>1.&lt;a href=&quot;http://www.youtube.com/?hl=es&amp;amp;gl=ES&quot; target=&quot;_blank&quot;&gt;Youtube&lt;/a&gt;&lt;br /&gt;
2.&lt;a href=&quot;http://es.wikipedia.org/wiki/Wikipedia:Portada&quot; target=&quot;_blank&quot;&gt;Wikipedia&lt;/a&gt;&lt;br /&gt;
3.&lt;a href=&quot;https://www.blogger.com/goog_145476659&quot;&gt; &lt;/a&gt;&lt;a href=&quot;http://www.bing.com/translator/?mkt=es-us&quot;&gt;&lt;cite class=&quot;_md&quot;&gt;Bing Translator&lt;/cite&gt;&lt;/a&gt;‎&lt;br /&gt;
4. &lt;a href=&quot;http://www.apple.com/es/iphone/%E2%80%8E&quot;&gt;Apple&lt;/a&gt;&lt;br /&gt;
5. &lt;a href=&quot;http://translate.google.es/?hl=es%E2%80%8E&quot;&gt;Google Translator&lt;/a&gt; </description><link>http://tecnologiamaxima.blogspot.com/2014/03/httpwww.html</link><author>noreply@blogger.com (Anonymous)</author><thr:total>0</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3045829400714783786.post-1807200915530103677</guid><pubDate>Fri, 14 Mar 2014 12:15:00 +0000</pubDate><atom:updated>2014-03-14T05:15:28.279-07:00</atom:updated><title>Borja Rodríguez Ortiz</title><description>Embajador627@hotmail.com</description><link>http://tecnologiamaxima.blogspot.com/2014/03/borja-rodriguez-ortiz.html</link><author>noreply@blogger.com (Anonymous)</author><thr:total>0</thr:total></item></channel></rss>