<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" media="screen" href="/~d/styles/rss2enclosuresfull.xsl"?><?xml-stylesheet type="text/css" media="screen" href="http://feeds.feedburner.com/~d/styles/itemcontent.css"?><rss xmlns:media="http://search.yahoo.com/mrss/" xmlns:feedburner="http://rssnamespace.org/feedburner/ext/1.0" version="2.0"><channel><title>Today's Puzzle</title><link>http://perdayapuzzle.blogspot.com/</link><atom10:link xmlns:atom10="http://www.w3.org/2005/Atom" rel="self" type="application/rss+xml" href="http://feeds.feedburner.com/blogspot/vODb" /><description>Solve today's puzzle and check for the answer the next day</description><language>en</language><managingEditor>noreply@blogger.com (Vja Students)</managingEditor><lastBuildDate>Thu, 16 Feb 2012 05:51:38 PST</lastBuildDate><generator>Blogger http://www.blogger.com</generator><openSearch:totalResults xmlns:openSearch="http://a9.com/-/spec/opensearch/1.1/">201</openSearch:totalResults><openSearch:startIndex xmlns:openSearch="http://a9.com/-/spec/opensearch/1.1/">1</openSearch:startIndex><openSearch:itemsPerPage xmlns:openSearch="http://a9.com/-/spec/opensearch/1.1/">25</openSearch:itemsPerPage><feedburner:info uri="blogspot/vodb" /><atom10:link xmlns:atom10="http://www.w3.org/2005/Atom" rel="hub" href="http://pubsubhubbub.appspot.com/" /><item><title>Prime</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/Q6eujIpenSc/prime.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Thu, 27 Jan 2011 09:54:02 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-1171859565552277926</guid><description>&lt;div&gt;&lt;p class="MsoNormal"&gt;&lt;span style="line-height: 115%; font-family: Arial, sans-serif; "&gt;&lt;span class="Apple-style-span" &gt;Let T&lt;sub&gt;n &lt;/sub&gt;=11111.....1(n times)..Then&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt;  &lt;p class="MsoNormal"&gt;&lt;span style="line-height: 115%; font-family: Arial, sans-serif; "&gt;&lt;span class="Apple-style-span" &gt;Which of the following is/prime numbers&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt;  &lt;p class="MsoNormal"&gt;&lt;span style="line-height: 115%; font-family: Arial, sans-serif; "&gt;&lt;o:p&gt;&lt;span class="Apple-style-span" &gt; &lt;/span&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/p&gt;  &lt;ol style="margin-top: 0in; " start="1" type="1"&gt;  &lt;li class="MsoNormal"&gt;&lt;span style="line-height: 115%; font-family: Arial, sans-serif; "&gt;&lt;span class="Apple-style-span" &gt;T&lt;sub&gt;741&lt;/sub&gt;&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/span&gt;&lt;/li&gt;  &lt;li class="MsoNormal"&gt;&lt;span style="line-height: 115%; font-family: Arial, sans-serif; "&gt;&lt;span class="Apple-style-span" &gt;T&lt;sub&gt;534&lt;/sub&gt;&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/span&gt;&lt;/li&gt;  &lt;li class="MsoNormal"&gt;&lt;span style="line-height: 115%; font-family: Arial, sans-serif; "&gt;&lt;span class="Apple-style-span" &gt;T&lt;sub&gt;123&lt;/sub&gt;&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/span&gt;&lt;/li&gt; &lt;/ol&gt;&lt;div&gt;&lt;span class="Apple-style-span" &gt;&lt;span class="Apple-style-span" style="font-size: 11px; line-height: 18px;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;/div&gt;&lt;div&gt;&lt;span class="Apple-style-span" &gt;&lt;span class="Apple-style-span" style="font-size: 11px; line-height: 18px;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;/div&gt;  &lt;p class="MsoNormal"&gt;&lt;span style="line-height: 115%; font-family: Arial, sans-serif; "&gt;&lt;span class="Apple-style-span"&gt;&lt;span class="Apple-style-span" &gt;Check the blog tomorrow for solution…………….&lt;/span&gt;&lt;o:p&gt;&lt;/o:p&gt;&lt;/span&gt;&lt;/span&gt;&lt;/p&gt;  &lt;p class="MsoNormal"&gt;&lt;o:p&gt;&lt;span class="Apple-style-span"&gt; &lt;/span&gt;&lt;/o:p&gt;&lt;/p&gt;  &lt;p class="MsoNormal"&gt;&lt;o:p&gt;&lt;span class="Apple-style-span"&gt; &lt;/span&gt;&lt;/o:p&gt;&lt;/p&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-1171859565552277926?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/Q6eujIpenSc" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2011-01-27T23:24:02.952+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">0</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2011/01/prime.html</feedburner:origLink></item><item><title>What day is today</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/KV3u4jqXp8o/when-day-before-yesterday-was-referred.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Thu, 27 Jan 2011 09:25:07 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-792570419306455563</guid><description>&lt;span class="Apple-style-span" style="  -webkit-border-horizontal-spacing: 8px; -webkit-border-vertical-spacing: 8px; font-family:Verdana, Arial, Helvetica, sans-serif;font-size:13px;"&gt;When the day before yesterday was referred to as the day after tomorrow, the day that was then called yesterday was as far away from the day we now call tomorrow as yesterday is from the day which we shall now be able to speak of last Monday as a week ago yesterday. What day is it?&lt;/span&gt;&lt;div&gt;&lt;span class="Apple-style-span" style="font-family:Verdana, Arial, Helvetica, sans-serif;font-size:100%;"&gt;&lt;span class="Apple-style-span" style=" -webkit-border-horizontal-spacing: 8px; -webkit-border-vertical-spacing: 8px;font-size:13px;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;/div&gt;&lt;div&gt;&lt;span class="Apple-style-span"  &gt;&lt;span class="Apple-style-span" style="-webkit-border-horizontal-spacing: 8px; -webkit-border-vertical-spacing: 8px;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;/div&gt;&lt;div&gt;&lt;span class="Apple-style-span"  &gt;&lt;span class="Apple-style-span" style="-webkit-border-horizontal-spacing: 8px; -webkit-border-vertical-spacing: 8px;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;/div&gt;&lt;div&gt;&lt;span class="Apple-style-span"  &gt;&lt;span class="Apple-style-span" style="-webkit-border-horizontal-spacing: 8px; -webkit-border-vertical-spacing: 8px;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/span&gt;&lt;/div&gt;&lt;div&gt;&lt;span class="Apple-style-span"  &gt;&lt;span class="Apple-style-span" style="-webkit-border-horizontal-spacing: 8px; -webkit-border-vertical-spacing: 8px;"&gt;Answer : Thursday&lt;/span&gt;&lt;/span&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-792570419306455563?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/KV3u4jqXp8o" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2011-01-27T22:55:07.055+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">5</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/when-day-before-yesterday-was-referred.html</feedburner:origLink></item><item><title>Connect It</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/zl2i9xXsNUA/connect-it.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Thu, 21 Jan 2010 10:25:16 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-6809890228906342594</guid><description>There are three houses, and three utilities: gas, electricity and water. Your task is to connect each house to all three utilities. Therefore each house will have three lines and each utility will also have three lines. However, you cannot cross lines. You cannot pass lines through houses or utilities. You cannot share lines. Can you draw the 9 lines required?&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_WTFGZ7vMsnA/S1dEaNvwabI/AAAAAAAAFl0/L9-03qmJWCA/s1600-h/gwe.gif"&gt;&lt;img style="cursor:pointer; cursor:hand;width: 150px; height: 150px;" src="http://2.bp.blogspot.com/_WTFGZ7vMsnA/S1dEaNvwabI/AAAAAAAAFl0/L9-03qmJWCA/s320/gwe.gif" border="0" alt="" id="BLOGGER_PHOTO_ID_5428883092975675826" /&gt;&lt;/a&gt;&lt;div&gt;&lt;br /&gt;&lt;/div&gt;&lt;div&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_WTFGZ7vMsnA/S1dEaNvwabI/AAAAAAAAFl0/L9-03qmJWCA/s1600-h/gwe.gif"&gt;&lt;/a&gt;&lt;br /&gt;&lt;div&gt;&lt;br /&gt;&lt;/div&gt;&lt;div&gt;Solution :&lt;/div&gt;&lt;div&gt;&lt;img src="http://4.bp.blogspot.com/_WTFGZ7vMsnA/S1ib9Zw8RuI/AAAAAAAAFl8/veOYTh2mH4Y/s320/torus.gif" style="cursor:pointer; cursor:hand;width: 266px; height: 194px;" border="0" alt="" id="BLOGGER_PHOTO_ID_5429260829985621730" /&gt;&lt;/div&gt;&lt;div&gt;&lt;br /&gt;&lt;/div&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-6809890228906342594?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/zl2i9xXsNUA" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2010-01-21T23:55:16.998+05:30</app:edited><media:thumbnail url="http://2.bp.blogspot.com/_WTFGZ7vMsnA/S1dEaNvwabI/AAAAAAAAFl0/L9-03qmJWCA/s72-c/gwe.gif" height="72" width="72" /><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">0</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/connect-it.html</feedburner:origLink></item><item><title></title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/bLpU1CNLUVk/during-recent-plane-and-train-spotting.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Wed, 20 Jan 2010 09:45:20 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-2773485062799176060</guid><description>During a recent plane and train spotting contest, five eager entrants were lined up ready to be tested on their spotting ability. They had each spotted a number of planes (26, 86, 123, 174, 250) and a number of trains (5, 42, 45, 98, 105). From the clues below, can you determine what colour anorak each was wearing, their position, their age (21, 23, 31, 36, 40) and the number of trains and planes spotted?&lt;br /&gt;&lt;br /&gt;1. Simon spotted 44 less trains than planes.&lt;br /&gt;2. Keith was 36 years old.&lt;br /&gt;3. The person on the far right was 8 years younger than Simon, and spotted 174 planes.&lt;br /&gt;4. James was wearing a beige anorak and spotted 37 trains fewer than Simon.&lt;br /&gt;5. The person who was wearing a green anorak, was 19 years younger than the person to his left.&lt;br /&gt;6. Steven spotted 105 trains and 250 planes.&lt;br /&gt;7. The person in the centre was 31 years old, was wearing a blue anorak and spotted 42 trains.&lt;br /&gt;8. Alan, who was on the far left, spotted 26 planes, and spotted 72 trains more than planes.&lt;br /&gt;9. The person who was wearing a red anorak, was 4 years older than Keith and was not next to the person wearing a blue anorak.&lt;br /&gt;10.The person who was next to the 31 year old but not next to the person who spotted 26 planes, was wearing a orange anorak, and spotted 45 trains.&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Solution&lt;br /&gt;&lt;br /&gt;# Name    Anorak  Age  Planes  Trains&lt;br /&gt;1 Alan    red     40    26      98&lt;br /&gt;2 Steven  green   21   250     105&lt;br /&gt;3 Simon   blue    31    86      42&lt;br /&gt;4 Keith   orange  36   123      45&lt;br /&gt;5 James   beige   23   174       5&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-2773485062799176060?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/bLpU1CNLUVk" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2010-01-20T23:15:20.140+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">1</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/during-recent-plane-and-train-spotting.html</feedburner:origLink></item><item><title>Time up</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/mpNMuGOQRWM/time-up.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Mon, 18 Jan 2010 10:19:13 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-2468828506008347351</guid><description>You have the misfortune to own an unreliable clock. This one loses exactly 20 minutes every hour. It is now showing 8.00am and you know that is was correct at midnight, when you set it. The clock stopped 10 hours ago, what is the correct time now?&lt;br /&gt;&lt;br /&gt;Answere&lt;br /&gt;10:00pm: since the clock is losing 20 minutes every hour, for every real hour that has passed, the clock will only show 40 minutes. Since the clock shows 8:00am, we know that 480 clock minutes have passed. This therefore equals 720 real minutes and hence 12 hours. The clock stopped 10 hours ago and so the time must now be 10.00pm.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-2468828506008347351?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/mpNMuGOQRWM" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2010-01-18T23:49:13.513+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">0</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/time-up.html</feedburner:origLink></item><item><title>Plan to Escape?</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/DZm8MqVxGtU/plan-to-escape.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Sun, 17 Jan 2010 10:22:38 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-1457162064487924819</guid><description>100 prisoners are locked up in individual cells, unable to see, speak or communicate in any way with each other. There is a central living room with a single light bulb, the bulb is initially off and no prisoner can see the light bulb from their own cell.&lt;br /&gt;&lt;br /&gt;Every day, the warden picks a prisoner at random, and that prisoner goes to the central living room. While there, the prisoner can toggle the bulb if they wish (off to on, or on to off). At any point, any prisoner can claim that all 100 prisoners have been to the living room. If they are wrong then all 100 prisoners will locked up forever! However, if they are correct all of the prisoners are set free.&lt;br /&gt;&lt;br /&gt;Before the random picking begins, the prisoners are allowed to discuss a plan. What is their best plan to determine when all 100 prisoners have visited the living room?&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Answere&lt;br /&gt;&lt;br /&gt;One person is chosen as the Counter. When a prisoner enters the living room, if the light is off they turn it on - but only if they have never switched it on before. When the Counter enters the room, if the light is on, they will turn it off. When the Counter has turned the light off 99 times, they will know that 99 prisoners have turned it on, and therefore every one of them has visited the living room and this will allow them all to be set free. QED.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-1457162064487924819?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/DZm8MqVxGtU" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2010-01-17T23:52:38.176+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">0</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/plan-to-escape.html</feedburner:origLink></item><item><title>Summer is Near</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/fIUznAQMo94/summer-is-near.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Sat, 16 Jan 2010 10:18:26 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-1419538720685060918</guid><description>We have been quite lucky with the weather recently, it has got steadily warmer each day, over the last five days. By this, I mean that the temperature rose by the same amount each day. The average temperature was 2 degrees C and I know it froze on two occasions. I also know the product of the temperatures was over 500 degrees but below 2,000 degrees and each temperature was an integer. What were the last 5 temperatures?&lt;br /&gt;&lt;br /&gt;Answere :&lt;br /&gt;&lt;br /&gt;The temperatures were -6, -2, 2, 6, 10 degrees C. Each day increased by a steady 4 degrees.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-1419538720685060918?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/fIUznAQMo94" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2010-01-16T23:48:26.323+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">1</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/summer-is-near.html</feedburner:origLink></item><item><title>Cakes &amp; Numbers</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/R1bLU5B6-lI/cakes-numbers.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Fri, 15 Jan 2010 09:58:44 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-2668807821281360823</guid><description>An errand boy was collecting boxes of cakes for the Summer Fair. He collected boxes from various people in his local village and each box was labelled in Roman Numerals with the number of cakes in the box. By the time the errand boy had collected the last box, he was quite hungry, and really needed to eat at least one cake. Luckily the last box was marked with an underlined XI, meaning there were 11 cakes in it. He had the brain wave of turning the box around and underlining the number again to give the impression there were IX, that is 9 cakes. However, after eating the 2 cakes, he was still hungry. How can he change the number shown on the box again and eat more cakes?&lt;br /&gt;&lt;br /&gt;Answere:&lt;br /&gt;He could add an S to the IX to give the impression there were supposed to be 6 cakes in the box, so eating 5 cakes in total.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-2668807821281360823?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/R1bLU5B6-lI" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2010-01-15T23:28:44.098+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">0</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/cakes-numbers.html</feedburner:origLink></item><item><title>Fishy</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/zI86S5-vj5s/fishy.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Thu, 14 Jan 2010 09:45:55 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-3795269816893043584</guid><description>There are 5 houses in 5 different colours. In each house lives a person of a different nationality. The 5 owners drink a certain type of beverage, smoke a certain brand of cigar, and keep a certain pet. Using the clues below can you determine who owns the fish?&lt;br /&gt;&lt;br /&gt;The Brit lives in a red house.&lt;br /&gt;The Swede keeps dogs as pets.&lt;br /&gt;The Dane drinks tea.&lt;br /&gt;The green house is on the immediate left of the white house.&lt;br /&gt;The green house owner drinks coffee.&lt;br /&gt;The person who smokes Pall Mall rears birds.&lt;br /&gt;The owner of the yellow house smokes Dunhill.&lt;br /&gt;The man living in the house right in the middle drinks milk.&lt;br /&gt;The Norwegian lives in the first house.&lt;br /&gt;The man who smokes Blend lives next door to the one who keeps cats.&lt;br /&gt;The man who keeps horses lives next door to the man who smokes Dunhill.&lt;br /&gt;The owner who smokes Blue Master drinks beer.&lt;br /&gt;The German smokes Prince.&lt;br /&gt;The Norwegian lives next to the blue house.&lt;br /&gt;The man who smokes Blend has a neighbour who drinks water.&lt;br /&gt;&lt;br /&gt;Answere:&lt;br /&gt;&lt;br /&gt;This puzzle is usually attributed to Einstein, who may or may not have written it. The German owns the fish and the table below details the full answer:&lt;br /&gt;Nationality: Norweg   Dane    Brit       German   Swede&lt;br /&gt;Colour     : Yellow   Blue    Red        Green    White&lt;br /&gt;Beverage   : water    tea     milk       coffee   beer&lt;br /&gt;Smokes     : Dunhill  Blend   Pall Mall  Prince   Blue Master&lt;br /&gt;Pet        : cats     horses  birds      fish     dogs&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-3795269816893043584?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/zI86S5-vj5s" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2010-01-14T23:15:55.713+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">1</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/fishy.html</feedburner:origLink></item><item><title>Time of tunnel</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/BGo7kwv8fdQ/time-of-tunnel.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Wed, 13 Jan 2010 10:06:22 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-5535456703339434916</guid><description>A long train, half a kilometre long, is about to enter a long tunnel. The tunnel is 10k long. If the speed of the train is 35kph, how long will it take for the entire train to pass through the tunnel - from the front of the train entering to the end of the train leaving the tunnel?&lt;br /&gt;&lt;br /&gt;Answere:&lt;br /&gt;&lt;br /&gt;The train takes 18 minutes. The front of the train has to initially travel 10k to leave the tunnel, and then a further 0.5k until the rear of the train has left the tunnel - a total of 10.5k. Which takes 60 * (10.5 / 35) = 18 minutes.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-5535456703339434916?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/BGo7kwv8fdQ" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2010-01-13T23:36:22.879+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">1</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/time-of-tunnel.html</feedburner:origLink></item><item><title>Whos is What</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/LZtjHGn4zQc/whos-is-what.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Tue, 12 Jan 2010 10:55:53 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-3362045107869435967</guid><description>Messrs Butcher, Baker, Carpenter and Plumber are currently attending another convention. No-one is currently, nor ever has been in the same profession as their name and no-one has had the same profession twice. Alan is now a butcher, whereas Mr Brian Butcher used to be a baker. The person who is now a carpenter used to be a butcher. Charlie has never been a baker, Mr Darren Carpenter has never been a butcher and Mr Baker is not now a carpenter. Can you determine their full names, along with their current and previous professions?&lt;br /&gt;&lt;br /&gt;For solution visit blog tomorrow...&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Answere&lt;br /&gt;&lt;br /&gt;                Current   Previous&lt;br /&gt;&lt;br /&gt;Alan Baker       Butcher   Carpenter&lt;br /&gt;Brian Butcher    Plumber   Baker&lt;br /&gt;Charlie Plumber  Carpenter Butcher&lt;br /&gt;Darren Carpenter Baker     Plumber&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-3362045107869435967?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/LZtjHGn4zQc" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2010-01-13T00:25:53.693+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">2</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/whos-is-what.html</feedburner:origLink></item><item><title>Know abt Earth</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/V9CZBh2S0LQ/know-abt-earth.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Mon, 11 Jan 2010 06:57:10 PST</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-119623125685616898</guid><description>Assume for a moment that the earth is a perfectly uniform sphere of radius 6400 km. Suppose a thread equal to the length of the circumference of the earth was placed along the equator, and drawn to a tight fit.&lt;br /&gt;&lt;br /&gt;Now suppose that the length of the thread is increased by 12 cm, and that it is pulled away uniformly in all directions.&lt;br /&gt;&lt;br /&gt;By how many cm. will the thread be separated from the earth's surface? &lt;br /&gt;&lt;br /&gt;&lt;br /&gt;For Answere Visit the blog tomorrow...&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Answer&lt;br /&gt;&lt;br /&gt;The cicumference of the earth is&lt;br /&gt;&lt;br /&gt;= 2 * PI * r&lt;br /&gt;&lt;br /&gt;= 2 * PI * 6400 km&lt;br /&gt;&lt;br /&gt;= 2 * PI * 6400 * 1000 m&lt;br /&gt;&lt;br /&gt;= 2 * PI * 6400 * 1000 * 100 cm&lt;br /&gt;&lt;br /&gt;= 1280000000 * PI cm&lt;br /&gt;&lt;br /&gt;where r = radius of the earth, PI = 3.141592654&lt;br /&gt;&lt;br /&gt;Hence, the length of the thread is = 1280000000 * PI cm&lt;br /&gt;&lt;br /&gt;Now length of the thread is increasd by 12 cm. So the new length is = (1280000000 * PI) + 12 cm&lt;br /&gt;&lt;br /&gt;This thread will make one concentric circle with the earth which is slightly away from the earth. The circumfernce of that circle is nothing but (1280000000 * PI) + 12 cm&lt;br /&gt;&lt;br /&gt;Assume that radius of the outer circle is R cm&lt;br /&gt;&lt;br /&gt;Therefore,&lt;br /&gt;&lt;br /&gt;2 * PI * R = (1280000000 * PI) + 12 cm&lt;br /&gt;&lt;br /&gt;Solving above equation, R = 640000001.908 cm&lt;br /&gt;&lt;br /&gt;Radius of the earth is r = 640000000 cm&lt;br /&gt;&lt;br /&gt;Hence, the thread will be separatedfrom the earth by&lt;br /&gt;&lt;br /&gt;= R - r cm&lt;br /&gt;&lt;br /&gt;= 640000001.908 - 640000000&lt;br /&gt;&lt;br /&gt;= 1.908 cm&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-119623125685616898?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/V9CZBh2S0LQ" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2010-01-11T20:27:10.821+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">0</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2010/01/know-abt-earth.html</feedburner:origLink></item><item><title>Which Sock??</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/IHYxnEyffVo/which-sock.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Fri, 05 Sep 2008 11:48:23 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-1716710022709588007</guid><description>Your sock drawer contains ten pairs of white socks and ten pairs of black socks. If you're only allowed to take one sock from the drawer at a time and you can't see what color sock you're taking until you've taken it, how many socks do you have to take before you're guaranteed to have at least one matching pair?&lt;br /&gt;&lt;br /&gt;To know the solution view the blog everyday . .  .&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-1716710022709588007?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/IHYxnEyffVo" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-09-06T00:18:23.651+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">20</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/09/which-sock.html</feedburner:origLink></item><item><title>Where is champion ?</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/5ympDusYdew/where-is-champion.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Fri, 05 Sep 2008 11:47:26 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-2089889623053480153</guid><description>97 baseball teams participate in an annual state tournament. The champion is chosen for this tournament by the usual elimination scheme. That is, the 97 teams are divided into pairs, and the two teams of each pair play against each other. The loser of each pair is eliminated, and the remaining teams are paired up again, etc. How many games must be played to determine a champion?&lt;br /&gt;&lt;br /&gt;Ans  96. All teams but the champion team will lose a game exactly once.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-2089889623053480153?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/5ympDusYdew" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-09-06T00:17:26.420+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">1</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/08/where-is-champion.html</feedburner:origLink></item><item><title>Know your family</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/p-nUTd8Rt_g/know-your-family.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Thu, 28 Aug 2008 09:57:54 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-9115393421441957301</guid><description>At a family reunion were the following people: one grandfather, one grandmother, two fathers, two mothers, four children, three grandchildren, one brother, two sisters, two sons, two daughters, one father-in-law, one mother-in-law, and one daughter-in-law. But not as many people attended as it sounds. How many were there, and who were they?&lt;br /&gt;&lt;br /&gt;Ans  There were two little girls and a boy, their parents, and their father's parents, totaling seven people.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-9115393421441957301?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/p-nUTd8Rt_g" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-08-28T22:27:54.259+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">2</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/08/know-your-family.html</feedburner:origLink></item><item><title>Who won the prize</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/IIa9CxekW3U/who-won-prize.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Sat, 23 Aug 2008 09:43:36 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-1850634777944839602</guid><description>&lt;p&gt;Isaac and Albert were excitedly describing the result of the Third Annual International Science Fair Extravaganza in Sweden. There were three contestants, Louis, Rene, and Johannes. Isaac reported that Louis won the fair, while Rene came in second. Albert, on the other hand, reported that Johannes won the fair, while Louis came in second.&lt;/p&gt; &lt;p&gt;In fact, neither Isaac nor Albert had given a correct report of the results of the science fair. Each of them had given one correct statement and one false statement. 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&lt;br /&gt;&lt;/p&gt;  &lt;p&gt;&lt;/p&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-1850634777944839602?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/IIa9CxekW3U" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-08-23T22:13:36.328+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">1</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/08/who-won-prize.html</feedburner:origLink></item><item><title>Digits</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/GrOKl_Mk3tg/digits.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Sun, 10 Aug 2008 21:57:33 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-2153271244750990397</guid><description>If A= 1999^1999&lt;br /&gt;B = sum of digits of A&lt;br /&gt;C = sum of digits of B&lt;br /&gt;D = sum of digits of C&lt;br /&gt;Find sum of digits of D.&lt;br /&gt;&lt;br /&gt;&lt;strong&gt;For solution visit the blog tomorrow...................&lt;/strong&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-2153271244750990397?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/GrOKl_Mk3tg" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-08-11T10:27:33.647+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">0</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/08/digits.html</feedburner:origLink></item><item><title>Arrange the Coins</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/vPTFM5cJZdI/nine-dots.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Sat, 26 Jul 2008 06:06:48 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-6725545886966099284</guid><description>Place three silver coins and three copper coins in a row like this:&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_WTFGZ7vMsnA/SIsg_xzI2sI/AAAAAAAAAAw/Vx8rvc-wZlA/s1600-h/coinmove.gif"&gt;&lt;img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer;" src="http://1.bp.blogspot.com/_WTFGZ7vMsnA/SIsg_xzI2sI/AAAAAAAAAAw/Vx8rvc-wZlA/s320/coinmove.gif" alt="" id="BLOGGER_PHOTO_ID_5227308072565267138" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;Moving only two adjoining coins at a time can you in three moves, change it to this:&lt;div style="text-align: center;"&gt;&lt;br /&gt;&lt;br /&gt;&lt;p class="MsoNormal" style="margin-bottom: 0.0001pt; line-height: normal;"&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_WTFGZ7vMsnA/SIshFEDc57I/AAAAAAAAAA4/Erp3PjAteFo/s1600-h/coinmove2.gif"&gt;&lt;img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer;" src="http://2.bp.blogspot.com/_WTFGZ7vMsnA/SIshFEDc57I/AAAAAAAAAA4/Erp3PjAteFo/s320/coinmove2.gif" alt="" id="BLOGGER_PHOTO_ID_5227308163364874162" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;b&gt;&lt;i&gt;&lt;o:p&gt;&lt;/o:p&gt;&lt;/i&gt;&lt;/b&gt;&lt;/p&gt;  &lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-6725545886966099284?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/vPTFM5cJZdI" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-07-26T18:36:48.408+05:30</app:edited><media:thumbnail url="http://1.bp.blogspot.com/_WTFGZ7vMsnA/SIsg_xzI2sI/AAAAAAAAAAw/Vx8rvc-wZlA/s72-c/coinmove.gif" height="72" width="72" /><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">2</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/07/nine-dots.html</feedburner:origLink></item><item><title>Matchsticks Puzzle</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/6SgiOJUoyuw/matchsticks-puzzle.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Sat, 31 May 2008 19:38:36 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-6288411026092917942</guid><description>There are 16 matchsticks arranged in 4 rows&lt;br /&gt;             &lt;br /&gt;---------------1--------------row 1&lt;br /&gt;-------------2  3  4                               ----------- row 2&lt;br /&gt;-----------5  6  7  8  9                            ----------row 3&lt;br /&gt;-----10 11 12 13 14 15 16                         ----row 4&lt;br /&gt;&lt;br /&gt;A player can remove as many matchsticks he wants but all from a particular row(he gets to chose any row). The player who removes the last stick wins. If two players play this game alternatively by removing sticks in the way described above what would be the strategy the players should follow to maximize their winning chances (i.e try not to lose, ofcourse one of the players has to lose but it should be decisive, in the sense player 1 wins becouse he starts to play first and follows the strategy all along the game).&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-6288411026092917942?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/6SgiOJUoyuw" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-06-01T08:08:36.108+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">0</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/06/matchsticks-puzzle.html</feedburner:origLink></item><item><title>Lady where r u?</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/3OVTWaWcP64/once-again-there-are-three-rooms.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Thu, 15 May 2008 20:36:36 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-7461703404698540866</guid><description>Once again, there are three rooms, containing yet again one lady and two tigers. The signs on the doors of the rooms this time are:&lt;br /&gt;Room1:A TIGER IS IN ROOM II&lt;br /&gt;Room2:A TIGER IS IN THIS ROOM&lt;br /&gt;Room3:A TIGER IS IN ROOM I&lt;br /&gt;The sign on the door of the room containing the lady is true, but at least one of the other two signs is false. What should your choice be?&lt;br /&gt;&lt;br /&gt;To know the solution view the blog tomorrow . . . . . .&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-7461703404698540866?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/3OVTWaWcP64" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-05-16T09:06:36.803+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">9</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/05/once-again-there-are-three-rooms.html</feedburner:origLink></item><item><title>Again lady &amp; tiger</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/boyw-shx3AE/again-lady-tiger.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Thu, 15 May 2008 20:27:19 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-2991767487593736091</guid><description>There are now three rooms to choose from. Only one contains a lady while the other two contain tigers. The signs on the doors of the three rooms are as follows:&lt;br /&gt;&lt;br /&gt;Room1:A TIGER IS IN THIS ROOM&lt;br /&gt;Room2:A LADY IS IN THIS ROOM&lt;br /&gt;Room3:A TIGER IS IN ROOM II&lt;br /&gt;&lt;br /&gt;At most one of the three signs is true. Which room contains the lady?&lt;br /&gt;&lt;br /&gt;Solution::&lt;br /&gt;Signs II and III contradict each other, so at least one of them is true. Since at most one of the three signs is true, then the first one must be false, so the lady is in Room I.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-2991767487593736091?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/boyw-shx3AE" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-05-16T08:57:19.197+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">3</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/05/again-lady-tiger.html</feedburner:origLink></item><item><title>who is which</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/6KL-flmYBv8/who-is-which.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Wed, 14 May 2008 01:12:51 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-8475218367461220054</guid><description>You are confronted with three bankers, one from Albania, one from America, and one from Austria. You do not know which is which, but you do know that one always tells the truth, a second always lies, and a third sometimes lies and sometimes tells the truth. How many questions are needed to identify their respective nationalities?&lt;br /&gt;&lt;br /&gt;Solution::&lt;br /&gt;Not more than 4 questions will be necessary, but sometimes (in one case out of three) 3 questions will suffice.&lt;br /&gt;1st question (addressed to the 1st banker): "If I asked you whether the 2nd banker is an equivocator (i.e. a person who sometimes tells lies and sometimes tells the truth), would you say yes?" If he answers yes, we know that the 3rd banker cannot possibly be an equivocator and we accordingly address our subsequent questions to him; if the 1st banker answers no, we know that the second banker is not an equivocator and we ask him our subsequent questions.&lt;br /&gt;2nd question (addressed to the 3rd or the 2nd banker depending on whether the answer to the 1st question was yes or no respectively): "If I asked you whether the 1st banker is Albanian, would you answer yes?" If the answer is yes, the 3rd question (asked to the same person as the 2nd question) is: "If I asked you whether the 2nd banker is American, would you say yes?" By elimination, we know the identity of the 3rd banker also.&lt;br /&gt;If, on the other hand, the answer to the 2nd question is no, two further questions will be required (a total of 4). 3rd question: "If I asked you whether the 1st banker is American, would you say yes?" If the answer is yes, we know that the 1st banker is American; if it is no, we know that he is Austrian. In either case we require one further question (the 4th question) to identify the two remaining bankers.&lt;br /&gt;Since the 1st question 'eliminates' the equivocator, we know that the remaining questions are addressed to someone who is consistently honest or consistently dishonest; and the questions are so worded that the answers will be the same whether he is honest or dishonest. The moral is that consistently dishonest people are far more dependable than those who occasionally tell the truth.&lt;br /&gt;&lt;p&gt; &lt;/p&gt;&lt;p&gt; &lt;/p&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-8475218367461220054?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/6KL-flmYBv8" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-05-14T13:42:51.545+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">0</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/05/who-is-which.html</feedburner:origLink></item><item><title>Divide camels</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/_AKH2BzDj8E/divide-camels.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Tue, 13 May 2008 07:18:20 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-3443194190985774544</guid><description>In his Last Will and Testament the Sheik says that anything not specifically bequeathed to a member of his family shall go to the Great Mosque. In the clause concerning his camels he makes the following provisions: "My eldest son will get half my camels, my middle son will get one-third, and my youngest son one-ninth."&lt;br /&gt;Since there are seventeen camels, the sons do not know how to divide them without cutting one of the camels into pieces. While they are discussing the difficulty, a wise man (the very same sage from Puzzle #1) appears on a camel. The sons ask him what they should do. "Quite simple," he says. "Let us add my camel to yours. There are then eighteen camels, so the eldest of you will get nine, the second will get six, and the youngest two, which makes a total of seventeen, precisely the number that the Sheik left you." The sons divide the seventeen camels accordingly, and the wise man rides off on his own camel. Is this arrangement satisfactory from everyone's point of view? If not, why not?&lt;br /&gt;&lt;br /&gt;Solution::&lt;br /&gt;No. Though each of the sons gets more than was specified by their father's Will, and though the camels happily escape mutilation, the Will itself has been violated, because it provided that 17/18 of a camel (i.e. 17 minus 17/2 minus 17/3 minus 17/9) was to remain after the divison between the sons. The Great Mosque (the residuary legatee) and anyone who believed that the term of the Sheik's Will should be strictly observed would be dissatisfied with the wise man's arrangement.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-3443194190985774544?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/_AKH2BzDj8E" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-05-13T19:48:20.688+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">1</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/05/divide-camels.html</feedburner:origLink></item><item><title>How can Both Lose</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/hFXkg4FQsXw/how-can-both-lose.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Sun, 11 May 2008 21:28:41 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-2828098564968431239</guid><description>On his deathbed the Grand Vizier, who has two sons, announces that his entire fortune will go to the son whose horse loses a race in which the two of them must compete simultaneously. The sons, both keen horsemen, are accustomed to winning races but do not know how to lose them. Since in this case both are determined to lose, they do not see how such a race is possible, but a wise man explains how it can be managed. What simple method does he suggest?&lt;br /&gt;&lt;br /&gt;Solution::&lt;br /&gt;Each son rides the other son's horse&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-2828098564968431239?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/hFXkg4FQsXw" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-05-12T09:58:41.794+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">2</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/05/how-can-both-lose.html</feedburner:origLink></item><item><title>2 ladies ,tiger</title><link>http://feedproxy.google.com/~r/blogspot/vODb/~3/JvSxxSHNXWk/2-ladies-tiger.html</link><author>noreply@blogger.com (Vja Students)</author><pubDate>Sat, 10 May 2008 22:48:27 PDT</pubDate><guid isPermaLink="false">tag:blogger.com,1999:blog-5134711868733774250.post-1915498404746209122</guid><description>If a lady is in Room I, then the sign on the door is true, but if a tiger is in it, the sign is false. In Room II, the situation is the opposite: a lady in the room means the sign on the door is false, and a tiger in the room means the sign is true. Again, it is possible that both rooms contain ladies or both rooms contain tigers, or that one room contains a lady and the other a tiger. The signs on the doors of the rooms are as follows:&lt;br /&gt;&lt;br /&gt;Room1:BOTH ROOMS CONTAIN LADIES&lt;br /&gt;Room2:BOTH ROOMS CONTAIN LADIES&lt;br /&gt;&lt;br /&gt;Which door should you open (assuming, of course, that you prefer the lady to the tiger)?&lt;br /&gt;&lt;br /&gt;Solution:&lt;br /&gt;Since the signs say the same thing, they are both true or both false. Suppose they are true; then both rooms contain ladies. This would mean in particular that Room II contains a lady. But we have been told that if Room II contains a lady, the sign is false. This is a contradiction, so the signs are not true; they are both false. Therefore, Room I contains a tiger and Room II contains a lady, so you should choose Room II.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/5134711868733774250-1915498404746209122?l=perdayapuzzle.blogspot.com' alt='' /&gt;&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/blogspot/vODb/~4/JvSxxSHNXWk" height="1" width="1"/&gt;</description><app:edited xmlns:app="http://www.w3.org/2007/app">2008-05-11T11:18:27.331+05:30</app:edited><thr:total xmlns:thr="http://purl.org/syndication/thread/1.0">2</thr:total><feedburner:origLink>http://perdayapuzzle.blogspot.com/2008/05/2-ladies-tiger.html</feedburner:origLink></item><media:rating>nonadult</media:rating><media:description type="plain">Subscribe</media:description></channel></rss>

