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<channel>
	<title>Integrated Learning GMAT Blog</title>
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	<pubDate>Wed, 24 Sep 2008 14:33:25 +0000</pubDate>
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		<title>GMAT Practice Question (Answer)</title>
		<link>http://feedproxy.google.com/~r/il_gmat_blog/~3/IMegGryhGeE/</link>
		<comments>http://integratedlearning.net/gmat/blog/?p=112#comments</comments>
		<pubDate>Wed, 24 Sep 2008 14:33:25 +0000</pubDate>
		<dc:creator>Integrated Learning</dc:creator>
		
	<category>GMAT Practice Questions</category>
		<guid isPermaLink="false">http://integratedlearning.net/gmat/blog/?p=112</guid>
		<description><![CDATA[Yesterday, we posted a 700+ level GMAT question. Below is the answer and explanation. How’d you do?
Answer: E

Explanation:
In order to find the sum of consecutive numbers, we always follow three steps:
1.  Find the number of numbers
2.  Find the middle number
3.  Multiply
Using the 3 steps -
1. Find the number of numbers:
The multiples of five between 23 [...]]]></description>
			<content:encoded><![CDATA[<p><em>Yesterday, we posted a 700+ level GMAT question. Below is the answer and explanation. How’d you do?</em></p>
<p><strong>Answer: E</strong><br />
<span /></p>
<p>Explanation:</p>
<p>In order to find the sum of consecutive numbers, we always follow three steps:</p>
<p>1.  Find the number of numbers</p>
<p>2.  Find the middle number</p>
<p>3.  Multiply</p>
<p>Using the 3 steps -</p>
<p><span />1. Find the number of numbers:</p>
<p>The multiples of five between 23 and 92 are really the numbers starting from 25 and ending with 90.  To find the number of numbers, subtract 25 from 90, divide by 5, and add 1:<br />
90 – 25 = 65<br />
65/5 = 13<br />
13 + 1 = 14</p>
<p>2. Find the middle number:<br />
The middle number between 25 and 90 is the average of 25 and 90:<br />
25 + 90 = 115<br />
115/2 = 57.5</p>
<p>3. Multiply:<br />
57.5*14 = 805
</p>
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		<item>
		<title>GMAT Practice Question</title>
		<link>http://feedproxy.google.com/~r/il_gmat_blog/~3/-jcU8-MwARw/</link>
		<comments>http://integratedlearning.net/gmat/blog/?p=111#comments</comments>
		<pubDate>Tue, 23 Sep 2008 14:06:53 +0000</pubDate>
		<dc:creator>Integrated Learning</dc:creator>
		
	<category>GMAT Practice Questions</category>
		<guid isPermaLink="false">http://integratedlearning.net/gmat/blog/?p=111</guid>
		<description><![CDATA[Every Tuesday we post a 700+ level GMAT question here on our blog, and post the answer and explanation the following day. Do you have what it takes?
What is the sum of the multiples of 5 between 23 and 92, inclusive?
A)      14
B)      65
C)      70
D)      747.5
E)      805


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			<content:encoded><![CDATA[<p><em>Every Tuesday we post a 700+ level GMAT question here on our blog, and post the answer and explanation the following day. Do you have what it takes?</em></p>
<p>What is the sum of the multiples of 5 between 23 and 92, inclusive?</p>
<p>A)      14<br />
B)      65<br />
C)      70<br />
D)      747.5<br />
E)      805
</p>
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		<item>
		<title>GMAT Practice Question (Answer)</title>
		<link>http://feedproxy.google.com/~r/il_gmat_blog/~3/xOj0bfQal4c/</link>
		<comments>http://integratedlearning.net/gmat/blog/?p=109#comments</comments>
		<pubDate>Wed, 17 Sep 2008 13:20:33 +0000</pubDate>
		<dc:creator>Integrated Learning</dc:creator>
		
	<category>GMAT Practice Questions</category>
		<guid isPermaLink="false">http://integratedlearning.net/gmat/blog/?p=109</guid>
		<description><![CDATA[Yesterday, we posted a 700+ level GMAT question. Below is the answer and explanation. How’d you do?

Answer: C
To be a perfect square, you must be able to take the square root of Q.  Practically, that means both x and y need to be even numbers.
 
Statement 1: We learn that Q has at least 4 3’s [...]]]></description>
			<content:encoded><![CDATA[<p><em><span lang="EN">Yesterday, we posted a 700+ level GMAT question. Below is the answer and explanation. How’d you do?</span></em><br />
<span /><strong><span /></strong></p>
<p><strong>Answer: C<br />
</strong><span />To be a perfect square, you must be able to take the square root of Q.  Practically, that means both x and y need to be even numbers.<br />
 <br />
Statement 1: We learn that Q has <em>at least </em>4 3’s and 2 7’s in its prime factors, but we don’t know there aren’t more than that.  Q could have 5 3’s, which case y would be 5 and you would not be able to square root Q.</p>
<p>Statement 2: Since 243 is 3<sup>5</sup> and 343 is 7<sup>3</sup>, Q has less than 5 3’s, and less than 3 7’s in its prime factors.  But again, y could be any number less than 5 and x any number less than 3, even or odd.</p>
<p>Together – Q has exactly 4 3’s and 2 7’s in its prime factors and is therefore a square of an integer.
</p>
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		<item>
		<title>GMAT Practice Question</title>
		<link>http://feedproxy.google.com/~r/il_gmat_blog/~3/OZOFxFgvMxI/</link>
		<comments>http://integratedlearning.net/gmat/blog/?p=110#comments</comments>
		<pubDate>Tue, 16 Sep 2008 15:08:55 +0000</pubDate>
		<dc:creator>Integrated Learning</dc:creator>
		
	<category>GMAT Practice Questions</category>
		<guid isPermaLink="false">http://integratedlearning.net/gmat/blog/?p=110</guid>
		<description><![CDATA[Every Tuesday we post a 700+ level GMAT question here on our blog, and post the answer and explanation the following day. Do you have what it takes?
Q=3y7z. Is Q a square of an integer?
1)   81 and 49 are factors of Q.
2)   243 and 343 are NOT factors of Q.


  addthis_url    [...]]]></description>
			<content:encoded><![CDATA[<p><em><span lang="EN" style="font-size: 10pt; font-family: Arial; mso-ansi-language: EN">Every Tuesday we post a 700+ level GMAT question here on our blog, and post the answer and explanation the following day. Do you have what it takes?</span></em></p>
<p><em><span lang="EN" style="font-size: 10pt; font-family: Arial; mso-ansi-language: EN" /></em>Q=3<sup>y</sup>7<sup>z</sup>. Is Q a square of an integer?</p>
<p>1)   81 and 49 are factors of Q.<br />
<span />2)   243 and 343 are NOT factors of Q.
</p>
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		<item>
		<title>Business School for Free?</title>
		<link>http://feedproxy.google.com/~r/il_gmat_blog/~3/YhS-bxzeRoE/</link>
		<comments>http://integratedlearning.net/gmat/blog/?p=108#comments</comments>
		<pubDate>Wed, 10 Sep 2008 14:46:12 +0000</pubDate>
		<dc:creator>Integrated Learning</dc:creator>
		
	<category>Admissions Tips</category>
		<guid isPermaLink="false">http://integratedlearning.net/gmat/blog/?p=108</guid>
		<description><![CDATA[Huh? For free?  Yeah right, you may be thinking.  But seriously, you may be closer to a scholarship opportunity than you realize, and with some work and planning, you may just find a way to actually get your MBA fully paid for.  With the economy being what it is there’s no better time than now to think [...]]]></description>
			<content:encoded><![CDATA[<p>Huh? For free?  <em>Yeah right</em>, you may be thinking.  But seriously, you may be closer to a scholarship opportunity than you realize, and with some work and planning, you may just find a way to actually get your MBA fully paid for.  With the economy being what it is there’s no better time than now to think outside the box when it comes to saving money.  Your business school expense is no exception.</p>
<p>Getting a scholarship or fellowship award surely takes some hard work, but when you’re talking upwards of $150K for two years of b-school, it may make you think twice.  And consider this: the difference between having a mountain of debt when you graduate and not having student loan debt could make a significant impact on some very important post graduate decisions – an entrepreneurial venture vs. a corporate job, lifestyle choices, where you decide to live, and a whole host of other life choices.</p>
<p><a href="http://www.businessweek.com/" target="_blank">Business Week</a> gives several great tips in Monday’s article “<a href="http://www.businessweek.com/bschools/content/sep2008/bs2008094_639352.htm" target="_blank">How to go to Business School for Free</a>”.  The article gives several pointers for winning scholarships, but the first tip is probably the most important one – <strong><em>start thinking about and planning for your MBA early</em></strong>.  This gives you the chance to consider various schools and give some good thought to which ones are the best fit for you.  You also need time to become familiar with the scholarships and fellowships available at each school.  Planning ahead may also give you the chance to add something to your experience that could enhance your application – volunteering, a key leadership role, etc.  Being ready to apply for the first round of applications is also imperative as in this case and many others, the early bird gets the worm!</p>
<p><a href="http://www.businessweek.com/bschools/content/sep2008/bs2008094_639352.htm" target="_blank">Click here to read the full article.</a>
</p>
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		<item>
		<title>GMAT Practice Question (Answer)</title>
		<link>http://feedproxy.google.com/~r/il_gmat_blog/~3/JdgOjOGLnpA/</link>
		<comments>http://integratedlearning.net/gmat/blog/?p=107#comments</comments>
		<pubDate>Wed, 10 Sep 2008 14:41:08 +0000</pubDate>
		<dc:creator>Integrated Learning</dc:creator>
		
	<category>GMAT Practice Questions</category>
		<guid isPermaLink="false">http://integratedlearning.net/gmat/blog/?p=107</guid>
		<description><![CDATA[Yesterday, we posted a 700+ level GMAT question. Below is the answer and explanation. How’d you do?
Answer: C
The average of the three numbers is 44, so they must add up to 132.
We know the median is 42, so the numbers, arranged in order, look like:
x, 42, y
We want the smallest number that the largest number [...]]]></description>
			<content:encoded><![CDATA[<p><em><span lang="EN">Yesterday, we posted a 700+ level GMAT question. Below is the answer and explanation. How’d you do?</span></em></p>
<p><em><span lang="EN" /></em><strong>Answer: C</strong></p>
<p>The average of the three numbers is 44, so they must add up to 132.</p>
<p>We know the median is 42, so the numbers, arranged in order, look like:<br />
<span /><em>x</em>, 42, y</p>
<p>We want the smallest number that the largest number can be, meaning, we want the smallest value of <em>y</em>.</p>
<p>To get the smallest value of <em>y</em>, we need <em>x</em> to be as large as it can be.  42 is the median, which means it’s in the middle, but it does not mean that the largest <em>x</em> can be is 41.  <em>x</em> can be 42 as well.  If that is the case, then 42 + 42 + <em>y</em> = 132, or <em>y</em> = 48.
</p>
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		<item>
		<title>GMAT Practice Question</title>
		<link>http://feedproxy.google.com/~r/il_gmat_blog/~3/i8UqkT2mCvk/</link>
		<comments>http://integratedlearning.net/gmat/blog/?p=106#comments</comments>
		<pubDate>Tue, 09 Sep 2008 16:44:55 +0000</pubDate>
		<dc:creator>Integrated Learning</dc:creator>
		
	<category>GMAT Practice Questions</category>
		<guid isPermaLink="false">http://integratedlearning.net/gmat/blog/?p=106</guid>
		<description><![CDATA[Every Tuesday we post a 700+ level GMAT question here on our blog, and post the answer and explanation the following day. Do you have what it takes?
The average of three positive integers is 44 and the median is 42.  What is the least possible value of the greatest of the three numbers?
A)      6
B)      42
C)      [...]]]></description>
			<content:encoded><![CDATA[<p><em><span lang="EN">Every Tuesday we post a 700+ level GMAT question here on our blog, and post the answer and explanation the following day. Do you have what it takes?</span></em></p>
<p><em><span lang="EN" /></em>The average of three positive integers is 44 and the median is 42.  What is the least possible value of the greatest of the three numbers?</p>
<p>A)      6<br />
B)      42<br />
C)      48<br />
D)      89<br />
E)      128<br />
<span />
</p>
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		<item>
		<title>GMAT Practice Question (Answer)</title>
		<link>http://feedproxy.google.com/~r/il_gmat_blog/~3/aMAK5WN7sIY/</link>
		<comments>http://integratedlearning.net/gmat/blog/?p=105#comments</comments>
		<pubDate>Wed, 30 Jul 2008 13:34:31 +0000</pubDate>
		<dc:creator>Integrated Learning</dc:creator>
		
	<category>GMAT Practice Questions</category>
		<guid isPermaLink="false">http://integratedlearning.net/gmat/blog/?p=105</guid>
		<description><![CDATA[Yesterday, we posted a 700+ level GMAT question. Below is the answer and explanation. How’d you do?
ANSWER: C
This is the only advanced algebra you’ll need on the test.  It’s not the only way to solve it, but it’s the easiest way to solve it.
To find a maximum or minimum value of an equation with an [...]]]></description>
			<content:encoded><![CDATA[<p><em>Yesterday, we posted a 700+ level GMAT question. Below is the answer and explanation. How’d you do?</em></p>
<p><strong>ANSWER: C</strong></p>
<p>This is the only advanced algebra you’ll need on the test.  It’s not the only way to solve it, but it’s the easiest way to solve it.</p>
<p>To find a maximum or minimum value of an equation with an exponent in it, you take the derivative of the equation, set it to zero, and solve.  That’s the max or min.</p>
<p>In this case we are given<br />
P = -25x<sup>2</sup> + 7500x</p>
<p>To find the derivative, multiply each number by the exponent it’s connected to, and subtract the exponent by 1.  Here, that will look like:<br />
<span />P’ = -50x + 7500<br />
<span />Set P’ to zero, and solve:<br />
<span />0 = -50x + 7500<br />
50x = 7500<br />
x = 150</p>
<p>If you’re not sure this really worked, try plugging in numbers, or even running the original equation in Excel.  You will see that at x = 150, P is the maximum it can be.
</p>
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		<item>
		<title>GMAT Practice Question</title>
		<link>http://feedproxy.google.com/~r/il_gmat_blog/~3/Kj0Kck3wRZc/</link>
		<comments>http://integratedlearning.net/gmat/blog/?p=104#comments</comments>
		<pubDate>Tue, 29 Jul 2008 14:49:50 +0000</pubDate>
		<dc:creator>Integrated Learning</dc:creator>
		
	<category>GMAT Practice Questions</category>
		<guid isPermaLink="false">http://integratedlearning.net/gmat/blog/?p=104</guid>
		<description><![CDATA[Every Tuesday we post a 700+ level GMAT question here on our blog, and post the answer and explanation the following day. Do you have what it takes?
In a certain company, the formula for maximizing profits is P = -25x2 + 7500x, where P is profit and x is the number of machines the company [...]]]></description>
			<content:encoded><![CDATA[<p><em>Every Tuesday we post a 700+ level GMAT question here on our blog, and post the answer and explanation the following day. Do you have what it takes?</em></p>
<p>In a certain company, the formula for maximizing profits is P = -25x<sup>2</sup> + 7500x, where P is profit and x is the number of machines the company operates in its factory.  What value for x will maximize P?</p>
<p>A) 10<br />
B) 50<br />
C) 150<br />
D) 200<br />
E) 300
</p>
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		<title>GMAT Practice Question (Answer)</title>
		<link>http://feedproxy.google.com/~r/il_gmat_blog/~3/lcfe8rTL4BQ/</link>
		<comments>http://integratedlearning.net/gmat/blog/?p=102#comments</comments>
		<pubDate>Wed, 23 Jul 2008 14:51:32 +0000</pubDate>
		<dc:creator>Integrated Learning</dc:creator>
		
	<category>GMAT Practice Questions</category>
		<guid isPermaLink="false">http://integratedlearning.net/gmat/blog/?p=102</guid>
		<description><![CDATA[Yesterday, we posted a 700+ level GMAT question. Below is the answer and explanation. How’d you do?
Answer: C
The sum of three integers is even – they can’t all be odd so the product will be even and B and D are eliminated.
To go further we must actually work.

Let’s make the mode be x. If it [...]]]></description>
			<content:encoded><![CDATA[<p><em><span lang="EN">Yesterday, we posted a 700+ level GMAT question. Below is the answer and explanation. How’d you do?</span></em></p>
<p><em><span lang="EN" /></em><strong>Answer: C</strong></p>
<p>The sum of three integers is even – they can’t all be odd so the product will be even and B and D are eliminated.<br />
<span />To go further we must actually work.</p>
<p><span /></p>
<p><span />Let’s make the mode be x. If it is a mode and there are three integers it must appear twice. Hence our three numbers are x-13 (the smallest), x and x.<br />
<span />x + x + (x – 13) = 50<br />
3x – 13 = 50<br />
x = 21<br />
8*21*21 =<br />
8*441 = 3,528
</p>
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