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      <pubDate>Sat, 18 May 2013 16:07:09 +0000</pubDate>
      <title>Mixing valid and full convolution types</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/0cuil2vDH8o/329074</link>
      <author>David </author>
      <description>Is it possible to have different convolution shapes for each dimension of a matrix (without repmatting or padding)? I would like dimensions 1, 2, and 3 to be valid, while dimension 4 is full.&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/0cuil2vDH8o" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329074#904629</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 14:53:08 +0000</pubDate>
      <title>Re: Genetic Algorithm and Efficient Portfolio</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/i1ELKOuOqzs/328930</link>
      <author>Ryan </author>
      <description>"Phil Goddard" &amp;lt;phil@goddardconsulting.ca&amp;gt; wrote in message &amp;lt;kmmvpf$ls0$1@newscl01ah.mathworks.com&amp;gt;...&lt;br&gt;
&amp;gt; As per the MLEvalString command, the results are generated by the MATLAB command&lt;br&gt;
&amp;gt; [portStd, portRet, portWts, portIndx] = ComputeBestPortfolio(expRet,expCov,portSize,targetRet)&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; i.e. within the function ComputeBestPortfolio&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; Phil.&lt;br&gt;
&lt;br&gt;
&lt;br&gt;
Yes!!  But, I still don't really understand how it works?  Is the VBA code running built-in functions in Matlab?  I assume it is.  I think the VBA is calling, and running, functions in Matlab, and the whole process is controlled by the ExcelLink?  Is that how it works?&lt;br&gt;
&lt;br&gt;
Thanks!!&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/i1ELKOuOqzs" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/328930#904628</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 14:30:12 +0000</pubDate>
      <title>Re: Cocktail Party Problem</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/bo9LgWtHEVE/329071</link>
      <author>Stan24 </author>
      <description>Hi Silvia,&lt;br&gt;
&lt;br&gt;
Try to use the FastICA package for MATLAB:&lt;br&gt;
&lt;a href="http://research.ics.aalto.fi/ica/fastica/"&gt;http://research.ics.aalto.fi/ica/fastica/&lt;/a&gt;&lt;br&gt;
&lt;br&gt;
Regards,&lt;br&gt;
Stan&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/bo9LgWtHEVE" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329071#904627</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 14:19:10 +0000</pubDate>
      <title>Re: gname problem</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/Cd6-cb1kW44/329072</link>
      <author>Stan24 </author>
      <description>I've forgotten to add:&lt;br&gt;
gname(1:10, h1);  % returns the wrong handle&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/Cd6-cb1kW44" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329072#904626</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 14:10:10 +0000</pubDate>
      <title>how do the integration?</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/Ogd9CmM5kwE/329073</link>
      <author>ghasem </author>
      <description>Hi.&lt;br&gt;
I have a simple question about integral.&lt;br&gt;
I have to calculate following integral and next plot it versus theta.my function is:&lt;br&gt;
f1 =  I(z)*sin(theta)*exp(jk*z*cos(theta) &lt;br&gt;
f2 = integral ( f1 , dz)&lt;br&gt;
where:&lt;br&gt;
lower limit of integral : z=0&lt;br&gt;
upper limit of integral : z = 0.7&lt;br&gt;
z= linspace(0,0.7,100);&lt;br&gt;
theta = linspace(0,2*pi,360);&lt;br&gt;
k = a given constant.&lt;br&gt;
I(z) = is a given vector same length with z =&amp;gt; length(I(z)) = length(z)&lt;br&gt;
NOW:&lt;br&gt;
I have to plot "f2(theta)" versus "theta" in a polar diagram.&lt;br&gt;
How can I do it?&lt;br&gt;
I used from " f2 = trapz(z,f1)" for integration and next plot "f2" versus "theta".&lt;br&gt;
is there any better method?&lt;br&gt;
thanks...&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/Ogd9CmM5kwE" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329073#904625</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 13:22:10 +0000</pubDate>
      <title>gname problem</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/wKAs007uxkA/329072</link>
      <author>Stan24 </author>
      <description>Hi,&lt;br&gt;
Can anyone explain how to add case names to plot:&lt;br&gt;
&lt;br&gt;
h1 = plot(1:10, sin(1:10), 'o-');&lt;br&gt;
hold on; &lt;br&gt;
h2 = gscatter(10*rand(1, 10), 2*rand(1,10), 1:10);&lt;br&gt;
hold off;&lt;br&gt;
&lt;br&gt;
gname(1:10, h1); &lt;br&gt;
&lt;br&gt;
Thanks,&lt;br&gt;
Stan&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/wKAs007uxkA" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329072#904624</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 13:03:26 +0000</pubDate>
      <title>Re: ? cal the length and area of contours</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/PGEPSWVI_XE/329068</link>
      <author>Cheng Cosine</author>
      <description>Nasser M. Abbasi於 2013年5月18日星期六UTC+8下午6時54分46秒寫道：&lt;br&gt;
&amp;gt; On 5/18/2013 5:36 AM, Cheng Cosine wrote:&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &amp;gt; Hi:&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &amp;gt;&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &amp;gt;   One can use contour() to plot contours. But how does one calculate the&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &amp;gt; length and area of a contour?&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &amp;gt;&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &amp;gt;   Thanks,&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &amp;gt;&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt;  From help:&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; ---------------&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; load penny;&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; figure;&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; contour(flipud(P));&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; axis square;&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; ------------------&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; So, looking at the above. what length and what area are you&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; refering to?&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; one contour line represent the same value in the data.&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; So, I am not even sure what measure of length you&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; are taking about, and what area you want, since&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; these lines can all change depending on how many&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; contour lines you want. If you ask for 2 lines,&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; you'll get different shapes.&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; May be if you explain what is it you are trying to do,&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; someone might have better suggestion.&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; --Nasser&lt;br&gt;
&lt;br&gt;
The data file you referred to is too complicated. A single value corresponds&lt;br&gt;
to more than one contours.&lt;br&gt;
&lt;br&gt;
Suppose we have a "clean" circular disk and on it we have different contours.&lt;br&gt;
&lt;br&gt;
A single value corresponds to a single contour. To be specific, those contours&lt;br&gt;
&lt;br&gt;
are closed and concentric circular curves.&lt;br&gt;
&lt;br&gt;
&amp;nbsp;If we know the radius of a contour, we can compute its circular length as 2*pi*r and area as pi*( r_outer^2-r_inner^2 ).&lt;br&gt;
&lt;br&gt;
&amp;nbsp;What I aksed for were to compute the perimeter and area when the target contour is not a simply cicle or ellipse.&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/PGEPSWVI_XE" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329068#904623</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 12:30:10 +0000</pubDate>
      <title>Cocktail Party Problem</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/4UUuXviY5iU/329071</link>
      <author>Silvia </author>
      <description>Hi Guys,&lt;br&gt;
&lt;br&gt;
Any body can tell me where I can find a complete Matlab code that deals with the cocktail party problem using TITO (Two-Inputs Two-Outputs) subband BSS (Blind Source Separation), i.e. using subband filters bank.&lt;br&gt;
&lt;br&gt;
Thanks&lt;br&gt;
Silvia&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/4UUuXviY5iU" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329071#904622</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 12:09:13 +0000</pubDate>
      <title>Re: ? cal the length and area of contours</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/uIF55_JY4-E/329068</link>
      <author>Bruno Luong</author>
      <description>Cheng Cosine &amp;lt;asecant@gmail.com&amp;gt; wrote in message &amp;lt;a100acf9-b4a8-47b8-9b2d-fd49d3f0af2c@googlegroups.com&amp;gt;...&lt;br&gt;
&amp;gt; Hi:&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt;  One can use contour() to plot contours. But how does one calculate the&lt;br&gt;
&amp;gt; length and area of a contour?&lt;br&gt;
&lt;br&gt;
Use syntax [c h] = contour(...) to retrieve the contour polygons. Then you can compute the length by summing the lengths of the edges, and use polyarea() to compute the surface.&lt;br&gt;
&lt;br&gt;
Bruno&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/uIF55_JY4-E" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329068#904621</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 11:30:13 +0000</pubDate>
      <title>set the original phase in Simulink</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/B84s70WuTj8/329070</link>
      <author>Mario </author>
      <description>Hi,&lt;br&gt;
&lt;br&gt;
I want to know if there is any block or function in simulink with which I can recover the original phase of the signal.&lt;br&gt;
&lt;br&gt;
By that I avoid the phase offset before to a QAM demodulator, and get the received constellation has the same phase as the signal sent.&lt;br&gt;
&lt;br&gt;
thanks.&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/B84s70WuTj8" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329070#904620</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 11:18:56 +0000</pubDate>
      <title>Re: Handover simulation in 4G networks</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/sGxG3vSva3U/261474</link>
      <author>amirjafary@gmail.com</author>
      <description>2LPZhNin2YUgCtix2YjYstiq2YjZhiDYqNiu24zYsQrYqNio2K7YtNuM2K8g2YXbjNiu2YjYp9iz&lt;br&gt;
2KrZhSDYqNio24zZhtmFINio2KfZhNin2K7YsdmHINiq2YjZhtiz2KrbjNivINiq2KfYrtuM2LEg&lt;br&gt;
2Ygg2KfbjNmGINmH2Kcg2LHYpyDYtNio24zZhyDYs9in2LLbjCDaqdmG24zYr9ifINqG2q/ZiNmG&lt;br&gt;
2Ycg2KfbjNmGINqp2KfYsSDYsdinINin2YbYrNin2YUg2K/Yp9iv24zYr9ifCtii2K7ZhyDZhdmG&lt;br&gt;
2YUg2YXZiNi22YjYudmFINiv2LEg2YfZhduM2YYg2LLZhduM2YbZhyDYp9iz2Kog2Ygg2KjZhyDY&lt;br&gt;
tNio24zZhyDYs9in2LLbjCDZhtuM2KfYsiDYr9in2LHZhQ==&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/sGxG3vSva3U" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/261474#904619</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 10:56:09 +0000</pubDate>
      <title>Re: EPS bounding box problem</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/ySLo365A1No/329069</link>
      <author>Hermano Cappa</author>
      <description>"Hermano Cappa" wrote in message &amp;lt;kn7lko$22t$1@newscl01ah.mathworks.com&amp;gt;...&lt;br&gt;
&amp;gt; Hi,&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; When I save a polar plot in Matlab as an EPS file for use in Latex with "Matlabfrag" or "Save as" the bounding box around the outer border (cricle) of my polar plot is partially removed at 0, 90, 180 and 270 degrees.&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; You can see my polar plot at:&lt;br&gt;
&amp;gt; &lt;a href="http://www.xeryon.be/matlab/synchr_vs_asynchr.eps"&gt;http://www.xeryon.be/matlab/synchr_vs_asynchr.eps&lt;/a&gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; I think this problem is related with the bounding box of my EPS file. How can I make this bigger?&lt;br&gt;
&lt;br&gt;
I was forgot to mention that the polar plot is generated with the "mmpolar" function from the file exchange.&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/ySLo365A1No" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329069#904618</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 10:54:46 +0000</pubDate>
      <title>Re: ? cal the length and area of contours</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/DJVNzVDLmUU/329068</link>
      <author>Nasser M. Abbasi</author>
      <description>On 5/18/2013 5:36 AM, Cheng Cosine wrote:&lt;br&gt;
&amp;gt; Hi:&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt;   One can use contour() to plot contours. But how does one calculate the&lt;br&gt;
&amp;gt; length and area of a contour?&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt;   Thanks,&lt;br&gt;
&amp;gt;&lt;br&gt;
&lt;br&gt;
&lt;br&gt;
&amp;nbsp;From help:&lt;br&gt;
&lt;br&gt;
---------------&lt;br&gt;
load penny;&lt;br&gt;
figure;&lt;br&gt;
contour(flipud(P));&lt;br&gt;
axis square;&lt;br&gt;
------------------&lt;br&gt;
&lt;br&gt;
So, looking at the above. what length and what area are you&lt;br&gt;
refering to?&lt;br&gt;
&lt;br&gt;
one contour line represent the same value in the data.&lt;br&gt;
&lt;br&gt;
So, I am not even sure what measure of length you&lt;br&gt;
are taking about, and what area you want, since&lt;br&gt;
these lines can all change depending on how many&lt;br&gt;
contour lines you want. If you ask for 2 lines,&lt;br&gt;
you'll get different shapes.&lt;br&gt;
&lt;br&gt;
May be if you explain what is it you are trying to do,&lt;br&gt;
someone might have better suggestion.&lt;br&gt;
&lt;br&gt;
--Nasser&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/DJVNzVDLmUU" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329068#904617</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 10:37:12 +0000</pubDate>
      <title>EPS bounding box problem</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/4axilhJbP4U/329069</link>
      <author>Hermano Cappa</author>
      <description>Hi,&lt;br&gt;
&lt;br&gt;
When I save a polar plot in Matlab as an EPS file for use in Latex with "Matlabfrag" or "Save as" the bounding box around the outer border (cricle) of my polar plot is partially removed at 0, 90, 180 and 270 degrees.&lt;br&gt;
&lt;br&gt;
You can see my polar plot at:&lt;br&gt;
&lt;a href="http://www.xeryon.be/matlab/synchr_vs_asynchr.eps"&gt;http://www.xeryon.be/matlab/synchr_vs_asynchr.eps&lt;/a&gt; &lt;br&gt;
&lt;br&gt;
I think this problem is related with the bounding box of my EPS file. How can I make this bigger?&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/4axilhJbP4U" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329069#904616</feedburner:origLink></item>
    <item>
      <pubDate>Sat, 18 May 2013 10:36:24 +0000</pubDate>
      <title>? cal the length and area of contours</title>
      <link>http://feedproxy.google.com/~r/mathworks/zAHF/~3/yTIIVAKiWTM/329068</link>
      <author>Cheng Cosine</author>
      <description>Hi:&lt;br&gt;
&lt;br&gt;
&amp;nbsp;One can use contour() to plot contours. But how does one calculate the&lt;br&gt;
length and area of a contour?&lt;br&gt;
&lt;br&gt;
&amp;nbsp;Thanks,&lt;img src="http://feeds.feedburner.com/~r/mathworks/zAHF/~4/yTIIVAKiWTM" height="1" width="1"/&gt;</description>
    <feedburner:origLink>http://www.mathworks.com/matlabcentral/newsreader/view_thread/329068#904615</feedburner:origLink></item>
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