<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:wfw="http://wellformedweb.org/CommentAPI/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
	xmlns:slash="http://purl.org/rss/1.0/modules/slash/"
	>

<channel>
	<title>Mind Your Decisions</title>
	<atom:link href="https://mindyourdecisions.com/blog/feed/" rel="self" type="application/rss+xml" />
	<link>https://mindyourdecisions.com/blog</link>
	<description>Math Videos, Math Puzzles, Game Theory. By Presh Talwalkar</description>
	<lastBuildDate>Fri, 21 Aug 2026 21:31:16 +0000</lastBuildDate>
	<language>en-US</language>
	<sy:updatePeriod>
	hourly	</sy:updatePeriod>
	<sy:updateFrequency>
	1	</sy:updateFrequency>
	

<image>
	<url>https://mindyourdecisions.com/blog/wp-content/uploads/2015/10/cropped-blog-logo-icon-32x32.gif</url>
	<title>Mind Your Decisions</title>
	<link>https://mindyourdecisions.com/blog</link>
	<width>32</width>
	<height>32</height>
</image> 
	<item>
		<title>Area Of Square From 3 External Distances</title>
		<link>https://mindyourdecisions.com/blog/2026/08/21/area-of-square-from-3-external-distances/</link>
		
		<dc:creator><![CDATA[Presh Talwalkar]]></dc:creator>
		<pubDate>Fri, 21 Aug 2026 21:31:16 +0000</pubDate>
				<category><![CDATA[Math]]></category>
		<category><![CDATA[Puzzle]]></category>
		<category><![CDATA[Video]]></category>
		<category><![CDATA[math puzzle]]></category>
		<category><![CDATA[video]]></category>
		<category><![CDATA[youtube]]></category>
		<guid isPermaLink="false">https://mindyourdecisions.com/blog/?p=38853</guid>

					<description><![CDATA[(This is a throwback to a 2021 puzzle with the numbers changed). Thanks to Willem for the suggestion! Point E is exterior to square ABCD with EA = 6, EB = 3, and EC = 5. What is the area of square ABCD? As usual, watch the video for a solution. Or keep reading. . &#8230; <a href="https://mindyourdecisions.com/blog/2026/08/21/area-of-square-from-3-external-distances/" class="more-link">Continue reading <span class="screen-reader-text">Area Of Square From 3 External Distances</span></a>]]></description>
										<content:encoded><![CDATA[<p>(This is a throwback to a <a href="https://mindyourdecisions.com/blog/2021/01/22/area-of-square-from-an-external-point/">2021 puzzle</a> with the numbers changed).</p>
<p>Thanks to Willem for the suggestion!</p>
<p>Point <i>E</i> is exterior to square <i>ABCD</i> with <i>EA</i> = 6, <i>EB</i> = 3, and <i>EC</i> = 5. What is the area of square <i>ABCD</i>?</p>
<p><img fetchpriority="high" decoding="async" src="https://mindyourdecisions.com/blog/wp-content/uploads/2026/07/square-area-3-distances-problem-blog-letters.png" alt="" width="600" height="757" class="alignnone size-full wp-image-38860" srcset="https://mindyourdecisions.com/blog/wp-content/uploads/2026/07/square-area-3-distances-problem-blog-letters.png 600w, https://mindyourdecisions.com/blog/wp-content/uploads/2026/07/square-area-3-distances-problem-blog-letters-238x300.png 238w" sizes="(max-width: 600px) 100vw, 600px" /><br />
As usual, watch the video for a solution.</p>
<p><b><a href="https://youtu.be/zUbCNnLFJk4"></a></b></p>
<p><iframe src="https://www.youtube-nocookie.com/embed/zUbCNnLFJk4" width="560" height="315" frameborder="0" allowfullscreen="allowfullscreen"></iframe></p>
<p>Or keep reading.<br />
<span id="more-38853"></span><br />
.<br />
.<br />
.<br />
.<br />
M<br />
I<br />
N<br />
D<br />
.<br />
Y<br />
O<br />
U<br />
R<br />
.<br />
D<br />
E<br />
C<br />
I<br />
S<br />
I<br />
O<br />
N<br />
S<br />
.<br />
P<br />
U<br />
Z<br />
Z<br />
L<br />
E<br />
.<br />
.<br />
.<br />
.<br />
<b>Answer To Area Of Square From An External Point</b></p>
<p>(Pretty much all posts are transcribed quickly after I make the videos for them&#8211;please <a href="mailto:presh@mindyourdecisions.com">let me know</a> if there are any typos/errors and I will correct them, thanks).</p>
<p>Suppose the square has a side length equal to <i>x</i>.</p>
<p>Suppose the horizontal distance from <i>B</i> to <i>E</i> is <i>a</i> and the vertical distance is <i>b</i>. We can then construct 3 triangles from point <i>E</i> whose hypotenuses are the three lengths 6, 3, and 5.</p>
<p><img decoding="async" src="https://mindyourdecisions.com/blog/wp-content/uploads/2026/07/square-area-3-distances-solution.png" alt="" width="600" height="392" class="alignnone size-full wp-image-38856" srcset="https://mindyourdecisions.com/blog/wp-content/uploads/2026/07/square-area-3-distances-solution.png 600w, https://mindyourdecisions.com/blog/wp-content/uploads/2026/07/square-area-3-distances-solution-300x196.png 300w" sizes="(max-width: 600px) 100vw, 600px" /></p>
<p>By the Gougu Theorem, we have the following three equations:</p>
<p>(I)<br />
<i>a</i><sup>2</sup> + <i>b</i><sup>2</sup> = 3<sup>2</sup> = 9</p>
<p>(II)<br />
(<i>a</i> + <i>x</i>)<sup>2</sup> + <i>b</i><sup>2</sup> = 5<sup>2</sup> = 25</p>
<p>(III)<br />
<i>a</i><sup>2</sup> + (<i>b</i> + <i>x</i>)<sup>2</sup> = 6<sup>2</sup> = 36</p>
<p>In equation (II) we will solve for <i>a</i>. We will use <i>a</i><sup>2</sup> + <i>b</i><sup>2</sup> = 4 from (I) in the second step.</p>
<p>(<i>a</i> + <i>x</i>)<sup>2</sup> + <i>b</i><sup>2</sup> = 25<br />
<i>x</i><sup>2</sup> + 2<i>ax</i> + <i>a</i><sup>2</sup> + <i>b</i><sup>2</sup> = 25<br />
<i>x</i><sup>2</sup> + 2<i>ax</i> + 9 = 25<br />
<i>a</i> = (16 &#8211; <i>x</i><sup>2</sup>)/(2<i>x</i>)</p>
<p>We will similarly solve for <i>b</i> in (III):</p>
<p><i>a</i><sup>2</sup> + (<i>b</i> + <i>x</i>)<sup>2</sup> = 36<br />
<i>a</i><sup>2</sup> + <i>b</i><sup>2</sup> + 2<i>bx</i> + <i>x</i><sup>2</sup> = 36<br />
9 + 2<i>bx</i> + <i>x</i><sup>2</sup> = 36<br />
<i>b</i> = (27 &#8211; <i>x</i><sup>2</sup>)/(2<i>x</i>)</p>
<p>We can now substitute for <i>a</i> and <i>b</i> in (I):</p>
<p><i>a</i><sup>2</sup> + <i>b</i><sup>2</sup> = 9<br />
((16 &#8211; <i>x</i><sup>2</sup>)/(2<i>x</i>))<sup>2</sup> + ((27 &#8211; <i>x</i><sup>2</sup>)/(2<i>x</i>))<sup>2</sup> = 9<br />
(16 &#8211; <i>x</i><sup>2</sup>)<sup>2</sup> + (27 &#8211; <i>x</i><sup>2</sup>)<sup>2</sup> = 36<i>x</i><sup>2</sup><br />
256 &#8211; 32<i>x</i><sup>2</sup> + (<i>x</i><sup>2</sup>)<sup>2</sup> + 729 &#8211; 54<i>x</i><sup>2</sup> + (<i>x</i><sup>2</sup>)<sup>2</sup> = 36<i>x</i><sup>2</sup><br />
2(<i>x</i><sup>2</sup>)<sup>2</sup> &#8211; 122<i>x</i><sup>2</sup> + 985 = 0</p>
<p>The area of the square is <i>x</i><sup>2</sup>. The last equation is quadratic in <i>x</i><sup>2</sup>, so we can solve for its value using Brahmagupta&#8217;s quadratic formula, giving:</p>
<p><i>x</i><sup>2</sup> = [-(-122) &pm; &radic;((-122)<sup>2</sup> &#8211; 4(2)(985))]/(2(2))<br />
<i>x</i><sup>2</sup> = 61/2 &pm; (&radic;1751)/2</p>
<p>Usually in geometry problems we want the positive radical to get a positive length. But in this problem we have two positive values:</p>
<p><i>x</i><sup>2</sup> = 61/2 + (&radic;1751)/2 &approx; 51.4<br />
<i>x</i><sup>2</sup> = 61/2 &#8211; (&radic;1751)/2 &approx; 9.6</p>
<p>The key in this problem is we want <i>E</i> to be exterior to the square, so we want <i>a</i> and <i>b</i> to be non-negative values. Recall that:</p>
<p><i>a</i> = (16 &#8211; <i>x</i><sup>2</sup>)/(2<i>x</i>)</p>
<p>For <i>a</i> to be non-negative, we need <i>x</i><sup>2</sup> &le; 16.</p>
<p>Thus we must exclude the area &approx; 51.4 case. The correct answer is thus:</p>
<p>Area = <i>x</i><sup>2</sup> = 61/2 &#8211; (&radic;1751)/2 &approx; 9.6 units squared.</p>
]]></content:encoded>
					
		
		
			</item>
		<item>
		<title>Right Triangle Area Puzzle</title>
		<link>https://mindyourdecisions.com/blog/2026/08/19/right-triangle-area-puzzle/</link>
		
		<dc:creator><![CDATA[Presh Talwalkar]]></dc:creator>
		<pubDate>Wed, 19 Aug 2026 20:26:22 +0000</pubDate>
				<category><![CDATA[Math]]></category>
		<category><![CDATA[Puzzle]]></category>
		<category><![CDATA[Video]]></category>
		<guid isPermaLink="false">https://mindyourdecisions.com/blog/?p=38808</guid>

					<description><![CDATA[A right triangle has a perimeter of 150 cm and a hypotenuse of 64 cm. What is its area? This problem was on Reddit AskMath and the picture has a credit to Logic Booster. The poster thought there was insufficient information. But people replied that it was possible to solve. Can you figure it out? &#8230; <a href="https://mindyourdecisions.com/blog/2026/08/19/right-triangle-area-puzzle/" class="more-link">Continue reading <span class="screen-reader-text">Right Triangle Area Puzzle</span></a>]]></description>
										<content:encoded><![CDATA[<p>A right triangle has a perimeter of 150 cm and a hypotenuse of 64 cm. What is its area?</p>
<p><img decoding="async" src="https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-problem.png" alt="" width="600" height="473" class="alignnone size-full wp-image-38815" srcset="https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-problem.png 600w, https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-problem-300x237.png 300w" sizes="(max-width: 600px) 100vw, 600px" /></p>
<p>This problem was on <a href="https://www.reddit.com/r/askmath/comments/1tu6zwa/found_on_facebook_not_enough_info/">Reddit AskMath</a> and the picture has a credit to Logic Booster. The poster thought there was insufficient information. But people replied that it was possible to solve. Can you figure it out?</p>
<p>As usual, watch the video for a solution.</p>
<p><b><a href="https://youtu.be/BMQntrJXJfw">Right Triangle Area Puzzle</a></b></p>
<p><iframe src="https://www.youtube-nocookie.com/embed/BMQntrJXJfw" width="560" height="315" frameborder="0" allowfullscreen="allowfullscreen"></iframe></p>
<p>Or keep reading.<br />
<span id="more-38808"></span><br />
.<br />
.<br />
.<br />
.<br />
M<br />
I<br />
N<br />
D<br />
.<br />
Y<br />
O<br />
U<br />
R<br />
.<br />
D<br />
E<br />
C<br />
I<br />
S<br />
I<br />
O<br />
N<br />
S<br />
.<br />
P<br />
U<br />
Z<br />
Z<br />
L<br />
E<br />
.<br />
.<br />
.<br />
.<br />
<b>Answer To Right Triangle Area Puzzle</b></p>
<p>(Pretty much all posts are transcribed quickly after I make the videos for them&#8211;please <a href="mailto:presh@mindyourdecisions.com">let me know</a> if there are any typos/errors and I will correct them, thanks).</p>
<p><b>Method 1</b>: Algebra</p>
<p><img decoding="async" src="https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-problem.png" alt="" width="600" height="473" class="alignnone size-full wp-image-38815" srcset="https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-problem.png 600w, https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-problem-300x237.png 300w" sizes="(max-width: 600px) 100vw, 600px" /></p>
<p>Let the legs be <i>a</i> and <i>b</i> and the hypotenuse <i>c</i> = 64 cm. Because the perimeter is 150 cm we have:</p>
<p><i>a</i> + <i>b</i> + <i>c</i> = 150<br />
<i>a</i> + <i>b</i> + 64 = 150<br />
<i>a</i> + <i>b</i> = 86<br />
(<i>a</i> + <i>b</i>)<sup>2</sup> = 86<sup>2</sup><br />
<i>a</i><sup>2</sup> + <i>b</i><sup>2</sup> + 2<i>ab</i> = 86<sup>2</sup></p>
<p>But since we have a right triangle we have:</p>
<p><i>a</i><sup>2</sup> + <i>b</i><sup>2</sup> = <i>c</i><sup>2</sup> = 64<sup>2</sup></p>
<p>Substituting we have:</p>
<p>64<sup>2</sup> + 2<i>ab</i> = 86<sup>2</sup><br />
2<i>ab</i> = 86<sup>2</sup> &#8211; 64<sup>2</sup><br />
<i>ab</i>/2 = (86<sup>2</sup> &#8211; 64<sup>2</sup>)/4<br />
<i>ab</i>/2 = (86 + 64)(86 &#8211; 64)/4<br />
<i>ab</i>/2 = 825</p>
<p>So the area is 825 cm<sup>2</sup>, and we didn&#8217;t have to solve for the sides of the triangle!</p>
<p><b>Method 2</b>: Inradius</p>
<p>An alternate method is to construct the incircle with a radius <i>r</i>. In any triangle the area is:</p>
<p><i>rp</i>/2</p>
<p><img decoding="async" src="https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-incircle.png" alt="" width="600" height="384" class="alignnone size-full wp-image-38811" srcset="https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-incircle.png 600w, https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-incircle-300x192.png 300w" sizes="(max-width: 600px) 100vw, 600px" /></p>
<p>Furthermore, in a right triangle the hypotenuse is equal to:</p>
<p><i>c</i> = <i>a</i> &#8211; <i>r</i> + <i>b</i> &#8211; <i>r</i></p>
<p>So we can add <i>c</i> to both sides and get:</p>
<p>2<i>c</i> = <i>a</i> + <i>b</i> + <i>c</i> &#8211; 2<i>r</i><br />
2<i>c</i> = <i>p</i> &#8211; 2<i>r</i><br />
<i>r</i> = (<i>p</i> &#8211; 2<i>c</i>)/2</p>
<p><img decoding="async" src="https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-incircle-right.png" alt="" width="600" height="361" class="alignnone size-full wp-image-38810" srcset="https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-incircle-right.png 600w, https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-incircle-right-300x181.png 300w" sizes="(max-width: 600px) 100vw, 600px" /></p>
<p>So now let&#8217;s solve the original problem.</p>
<p><img decoding="async" src="https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-incircle-solution.png" alt="" width="600" height="420" class="alignnone size-full wp-image-38809" srcset="https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-incircle-solution.png 600w, https://mindyourdecisions.com/blog/wp-content/uploads/2026/06/right-triangle-area-perimeter-hypotenuse-incircle-solution-300x210.png 300w" sizes="(max-width: 600px) 100vw, 600px" /></p>
<p>We can solve for the inradius using the given information:</p>
<p><i>r</i> = (<i>p</i> &#8211; 2<i>c</i>)/2<br />
<i>r</i> = (150 &#8211; 2(64))/2<br />
<i>r</i> = 11</p>
<p>Then we have the area of the triangle is:</p>
<p><i>rp</i>/2<br />
= 11(150)/2<br />
= 825</p>
<p>So we again get the answer of 825 cm<sup>2</sup>.</p>
<p><b>Extra credit</b></p>
<p>Solve for the lengths of the legs.</p>
<p><b>Reference</b></p>
<p>Reddit AskMath<br />
<a href="https://www.reddit.com/r/askmath/comments/1tu6zwa/found_on_facebook_not_enough_info/">https://www.reddit.com/r/askmath/comments/1tu6zwa/found_on_facebook_not_enough_info/</a></p>
]]></content:encoded>
					
		
		
			</item>
		<item>
		<title>Who Really Discovered The Pythagorean Theorem?</title>
		<link>https://mindyourdecisions.com/blog/2026/08/09/who-really-discovered-the-pythagorean-theorem/</link>
		
		<dc:creator><![CDATA[Presh Talwalkar]]></dc:creator>
		<pubDate>Sun, 09 Aug 2026 18:25:21 +0000</pubDate>
				<category><![CDATA[Math]]></category>
		<category><![CDATA[Video]]></category>
		<guid isPermaLink="false">https://mindyourdecisions.com/blog/?p=38863</guid>

					<description><![CDATA[Everyone learns the famous right triangle formula in school: a2 + b2 = c2 But who actually discovered this formula, and how did they figure it out? The following video presents the earliest proofs from China, India, and Greece (Euclid), as well as a few tangents to modern proofs including President Garfield&#8217;s proof and Albert &#8230; <a href="https://mindyourdecisions.com/blog/2026/08/09/who-really-discovered-the-pythagorean-theorem/" class="more-link">Continue reading <span class="screen-reader-text">Who Really Discovered The Pythagorean Theorem?</span></a>]]></description>
										<content:encoded><![CDATA[<p>Everyone learns the famous right triangle formula in school:</p>
<p><i>a</i><sup>2</sup> + <i>b</i><sup>2</sup> = <i>c</i><sup>2</sup></p>
<p>But who actually discovered this formula, and how did they figure it out?</p>
<p>The following video presents the earliest proofs from China, India, and Greece (Euclid), as well as a few tangents to modern proofs including President Garfield&#8217;s proof and Albert Einstein&#8217;s proof.</p>
<p><b><a href="https://youtu.be/u7OR9pjOr-o">Who Really Discovered The Pythagorean Theorem?</a></b></p>
<p><iframe src="https://www.youtube-nocookie.com/embed/u7OR9pjOr-o" width="560" height="315" frameborder="0" allowfullscreen="allowfullscreen"></iframe></p>
<p><span id="more-38863"></span></p>
<p>I spent a long time on the visuals and animations for the video, so I have not prepared a text version with static graphics as I normally do. I hope you can watch the video when you have time. Here are some time stamps that you might find useful:</p>
<p>0:00 Intro<br />
1:50 China<br />
5:00 India<br />
7:35 Garfield<br />
8:45 Pythagoras<br />
9:24 Greece<br />
15:18 Einstein</p>
<p><b>References</b></p>
<p>Community post<br />
<a href="https://www.youtube.com/post/UgkxGSwX5dtLg6zWkm-rNohQdcgDduhp5Gi2">https://www.youtube.com/post/UgkxGSwX5dtLg6zWkm-rNohQdcgDduhp5Gi2</a></p>
<p>Babylon, Egypt<br />
<a href="https://en.wikipedia.org/wiki/File:Plimpton_322.jpg">https://en.wikipedia.org/wiki/File:Plimpton_322.jpg</a><br />
<a href="https://en.wikipedia.org/wiki/File:Papyrus_Berlin_6619.jpg">https://en.wikipedia.org/wiki/File:Papyrus_Berlin_6619.jpg</a><br />
<a href="https://commons.wikimedia.org/wiki/File:All_Gizah_Pyramids.jpg">https://commons.wikimedia.org/wiki/File:All_Gizah_Pyramids.jpg</a><br />
<a href="https://commons.wikimedia.org/wiki/File:Corda-a-12-nodi.svg">https://commons.wikimedia.org/wiki/File:Corda-a-12-nodi.svg</a><br />
Ricardo Liberato, CC BY-SA 2.0 <https://creativecommons.org/licenses/by-sa/2.0>, via Wikimedia Commons</p>
<p>China (Gougu)<br />
<a href="https://en.wikipedia.org/wiki/Xuan_tu">https://en.wikipedia.org/wiki/Xuan_tu</a><br />
<a href="https://en.wikipedia.org/wiki/Zhoubi_Suanjing">https://en.wikipedia.org/wiki/Zhoubi_Suanjing</a><br />
<a href="https://en.wikipedia.org/wiki/File:Duke_of_Zhou.png">https://en.wikipedia.org/wiki/File:Duke_of_Zhou.png</a><br />
<a href="https://www.rediff.com/news/special/did-india-discover-pythogoras-theorem-a-top-mathematician-answers/20150109.htm">https://www.rediff.com/news/special/did-india-discover-pythogoras-theorem-a-top-mathematician-answers/20150109.htm</a></p>
<p>India (Baudhayan)<br />
<a href="https://en.wikipedia.org/wiki/Baudhayana#/media/File:Bas-relief_of_Baudhayana_(cropped).jpg">https://en.wikipedia.org/wiki/Baudhayana#/media/File:Bas-relief_of_Baudhayana_(cropped).jpg</a><br />
<a href="https://archive.org/details/baudhyanasrautas01bauduoft/page/n5/mode/2up">https://archive.org/details/baudhyanasrautas01bauduoft/page/n5/mode/2up</a><br />
<a href="https://en.wikipedia.org/wiki/Yajna">https://en.wikipedia.org/wiki/Yajna</a><br />
Arayilpdas at Malayalam Wikipedia CC BY-SA 3.0 via Wikimedia Commons<br />
<a href="https://w.wiki/S$M5">https://w.wiki/S$M5</a><br />
<a href="https://x.com/ncert/status/2006602652638130291">https://x.com/ncert/status/2006602652638130291</a><br />
<a href="https://ncert.nic.in/textbook/pdf/hegp202.pdf">https://ncert.nic.in/textbook/pdf/hegp202.pdf</a><br />
<a href="https://bhaskarkamble.substack.com/p/the-sulbasutras-and-the-pythagoras">https://bhaskarkamble.substack.com/p/the-sulbasutras-and-the-pythagoras</a></p>
<p>Greece (Pythagoras)<br />
<a href="https://commons.wikimedia.org/wiki/File:Pythagoras_knapp.jpg">https://commons.wikimedia.org/wiki/File:Pythagoras_knapp.jpg</a><br />
<a href="https://archive.org/details/cu31924008704219/page/n165/mode/2up">https://archive.org/details/cu31924008704219/page/n165/mode/2up</a></p>
<p>Greece (Euclid)<br />
<a href="https://mathcs.holycross.edu/~little/Mont201516/EuclidPythagoras1.html">https://mathcs.holycross.edu/~little/Mont201516/EuclidPythagoras1.html</a><br />
<a href="https://commons.wikimedia.org/wiki/File:Tysoe_Windmill_-_geograph.org.uk_-_7335000.jpg">https://commons.wikimedia.org/wiki/File:Tysoe_Windmill_-_geograph.org.uk_-_7335000.jpg</a><br />
Tysoe Windmill by Derek Harper, CC BY-SA 2.0 <https://creativecommons.org/licenses/by-sa/2.0>, via Wikimedia Common<br />
<a href="https://www.cut-the-knot.org/pythagoras/euclid.shtml">https://www.cut-the-knot.org/pythagoras/euclid.shtml</a><br />
<a href="https://webspace.ship.edu/mrcohe/inside-out/vu1/d_joyce/elements/bookVI/propVI31.html">https://webspace.ship.edu/mrcohe/inside-out/vu1/d_joyce/elements/bookVI/propVI31.html</a><br />
<a href="http://aleph0.clarku.edu/~djoyce/elements/bookVI/propVI31.html">http://aleph0.clarku.edu/~djoyce/elements/bookVI/propVI31.html</a><br />
<a href="https://en.wikipedia.org/wiki/File:Visual_proof_of_the_Pythagorean_theorem_by_area-preserving_shearing.gif">https://en.wikipedia.org/wiki/File:Visual_proof_of_the_Pythagorean_theorem_by_area-preserving_shearing.gif</a><br />
<a href="https://www.desmos.com/calculator/zlf3dweki4">https://www.desmos.com/calculator/zlf3dweki4</a><br />
<a href="https://www.youtube.com/watch?v=eWNBw5GpqeY&#038;t=611s">https://www.youtube.com/watch?v=eWNBw5GpqeY&#038;t=611s</a></p>
<p>Einstein<br />
<a href="https://archive.org/details/fractalschaospow0000unse/page/2/mode/2up">https://archive.org/details/fractalschaospow0000unse/page/2/mode/2up</a><br />
<a href="https://www.cut-the-knot.org/pythagoras/PythagorasBySimilarity.shtml">https://www.cut-the-knot.org/pythagoras/PythagorasBySimilarity.shtml</a><br />
<a href="https://terrytao.wordpress.com/2007/09/14/pythagoras-theorem/">https://terrytao.wordpress.com/2007/09/14/pythagoras-theorem/</a><br />
<a href="https://www.newyorker.com/tech/annals-of-technology/einsteins-first-proof-pythagorean-theorem">https://www.newyorker.com/tech/annals-of-technology/einsteins-first-proof-pythagorean-theorem</a></p>
<p>Impossible proof<br />
<a href="https://www.tandfonline.com/doi/epdf/10.1080/00029890.2024.2370240?needAccess=true">https://www.tandfonline.com/doi/epdf/10.1080/00029890.2024.2370240?needAccess=true</a><br />
<a href="https://maa.org/news/groundbreaking-pythagorean-research-featured-in-the-american-mathematical-monthly/">https://maa.org/news/groundbreaking-pythagorean-research-featured-in-the-american-mathematical-monthly/</a><br />
<a href="https://www.youtube.com/watch?v=juFdo2bijic">https://www.youtube.com/watch?v=juFdo2bijic</a></p>
]]></content:encoded>
					
		
		
			</item>
	</channel>
</rss>
