<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:blogger='http://schemas.google.com/blogger/2008' xmlns:georss='http://www.georss.org/georss' xmlns:gd="http://schemas.google.com/g/2005" xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-3307136016266736838</id><updated>2024-09-08T15:31:38.087+01:00</updated><category term="2º CCSS"/><category term="Álgebra matricial"/><category term="sistemas"/><category term="autoevaluacion"/><category term="Derivadas"/><category term="funcioens"/><category term="límites"/><category term="Álgebra"/><category term="Calculadora"/><category term="Progr_lineal"/><category term="funciones"/><category term="General"/><category term="PAU"/><category term="Probabilidad"/><category term="derivabilidad"/><category term="gráficas"/><category term="integrales"/><title type='text'>MisMates: 2º de bachillerato</title><subtitle type='html'></subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default?redirect=false'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>25</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-3390819952091858656</id><published>2014-05-06T12:34:00.000+01:00</published><updated>2014-05-06T12:34:32.470+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="autoevaluacion"/><category scheme="http://www.blogger.com/atom/ns#" term="PAU"/><title type='text'>Cuestionario PAU</title><content type='html'>El siguiente cuestionario corresponde a la convocatoria de junio del curso 2012/13 (Opción A). Espero sus respuestas.&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe frameborder=&quot;0&quot; height=&quot;500&quot; marginheight=&quot;0&quot; marginwidth=&quot;0&quot; src=&quot;https://docs.google.com/forms/d/1MEAhczjwG-rQIA94SbmO-Fy0kPoB6c4GhkPmO1OWlQc/viewform?embedded=true&quot; width=&quot;550&quot;&gt;Cargando...&lt;/iframe&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/3390819952091858656/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2014/05/cuestionario-pau.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/3390819952091858656'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/3390819952091858656'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2014/05/cuestionario-pau.html' title='Cuestionario PAU'/><author><name>Carmen Morales</name><uri>http://www.blogger.com/profile/07393638529151217508</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='32' src='//blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh60W2-JM7m0rXZpfSo2op5cJpxIsbsQYzmD8Ucsdd90oNkkWGWQzjxQXi6EappiB5ZLy_hhC6wi3wjWc65NN70RKPEtBOR4bmhQXxMpRUuugOGPM7jTySC8oykMHIM/s220/smiles_escuela+%2814%29.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-6219049423905534095</id><published>2014-02-12T20:49:00.000+00:00</published><updated>2014-02-12T20:49:15.978+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="Probabilidad"/><title type='text'>Distribuciones de probabilidad</title><content type='html'>&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;356&quot; marginheight=&quot;0&quot; marginwidth=&quot;0&quot; scrolling=&quot;no&quot; src=&quot;http://www.slideshare.net/slideshow/embed_code/31139237&quot; style=&quot;border-width: 1px 1px 0; border: 1px solid #CCC; margin-bottom: 5px; max-width: 100%;&quot; width=&quot;427&quot;&gt; &lt;/iframe&gt; &lt;br /&gt;
&lt;div style=&quot;margin-bottom: 5px;&quot;&gt;
&lt;strong&gt; &lt;a href=&quot;https://www.slideshare.net/MisMatesCarmen/distribuciones-de-probabilidad-31139237&quot; target=&quot;_blank&quot; title=&quot;Distribuciones de probabilidad&quot;&gt;Distribuciones de probabilidad&lt;/a&gt; &lt;/strong&gt; from &lt;strong&gt;&lt;a href=&quot;http://www.slideshare.net/MisMatesCarmen&quot; target=&quot;_blank&quot;&gt;MisMatesCarmen&lt;/a&gt;&lt;/strong&gt; &lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/6219049423905534095/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2014/02/distribuciones-de-probabilidad.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/6219049423905534095'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/6219049423905534095'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2014/02/distribuciones-de-probabilidad.html' title='Distribuciones de probabilidad'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-4513866204912923745</id><published>2013-11-04T08:00:00.000+00:00</published><updated>2013-11-04T08:00:04.645+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="autoevaluacion"/><category scheme="http://www.blogger.com/atom/ns#" term="funciones"/><category scheme="http://www.blogger.com/atom/ns#" term="límites"/><title type='text'>Autoevaluación del tema Límites, continuidad y asíntotas.</title><content type='html'>Como comentamos en clase publico ya la autoevaluación de este tema, para que vayan trabajando los ejercicios que se proponen aunque en clase todavía no hayamos terminado esta unidad.&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe frameborder=&quot;0&quot; height=&quot;500&quot; marginheight=&quot;0&quot; marginwidth=&quot;0&quot; src=&quot;https://docs.google.com/forms/d/1OCRzQj6veCDCCbAAZxzZkGjT2CcZPLOKs9tayqWczXY/viewform?embedded=true&quot; width=&quot;600&quot;&gt;Cargando...&lt;/iframe&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/4513866204912923745/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/11/autoevaluacion-del-tema-limites.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/4513866204912923745'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/4513866204912923745'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/11/autoevaluacion-del-tema-limites.html' title='Autoevaluación del tema Límites, continuidad y asíntotas.'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-6669553771981726942</id><published>2013-10-28T08:00:00.000+00:00</published><updated>2013-10-28T08:00:02.303+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="funciones"/><category scheme="http://www.blogger.com/atom/ns#" term="límites"/><title type='text'>Concepto intuitivo de límite</title><content type='html'>Recordemos el concepto de límite mediante la siguiente presentación sobre el tema:&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;356&quot; marginheight=&quot;0&quot; marginwidth=&quot;0&quot; scrolling=&quot;no&quot; src=&quot;http://www.slideshare.net/slideshow/embed_code/1527370&quot; style=&quot;border-width: 1px 1px 0; border: 1px solid #CCC; margin-bottom: 5px;&quot; width=&quot;427&quot;&gt; &lt;/iframe&gt; &lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
En el siguiente vídeo vemos cómo calcular límites a partir de la gráfica de la función:&lt;/div&gt;
&lt;br /&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;//www.youtube.com/embed/EYcwxYab0Qk&quot; width=&quot;420&quot;&gt;&lt;/iframe&gt;

&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
Por último, en la siguiente página practicaremos el cálculo de límites:&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;a href=&quot;http://www.lamanzanadenewton.com/materiales/matematicas/lmn_mat_fch12.html&quot; target=&quot;_blank&quot;&gt;LA MANZANA DE NEWTON: LÍMITE DE FUNCIONES&lt;/a&gt;&lt;/div&gt;
&lt;div style=&quot;margin-bottom: 5px;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;br /&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/6669553771981726942/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/10/concepto-intuitivo-de-limite.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/6669553771981726942'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/6669553771981726942'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/10/concepto-intuitivo-de-limite.html' title='Concepto intuitivo de límite'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-6222997694573042381</id><published>2013-10-15T08:00:00.000+01:00</published><updated>2013-10-15T08:00:11.830+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="autoevaluacion"/><category scheme="http://www.blogger.com/atom/ns#" term="Progr_lineal"/><title type='text'>Autoevaluación</title><content type='html'>Les propongo la autoevaluación sobre el tema de programación lineal:&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe frameborder=&quot;0&quot; height=&quot;500&quot; marginheight=&quot;0&quot; marginwidth=&quot;0&quot; src=&quot;https://docs.google.com/forms/d/18vnZYhadU4o9DL3zpLMppAFlCoc6VDgMC8ZRukdkuZc/viewform?embedded=true&quot; width=&quot;600&quot;&gt;Cargando...&lt;/iframe&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/6222997694573042381/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/10/autoevaluacion.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/6222997694573042381'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/6222997694573042381'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/10/autoevaluacion.html' title='Autoevaluación'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-6633783887724930379</id><published>2013-10-07T08:00:00.000+01:00</published><updated>2013-10-07T08:00:00.062+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="Progr_lineal"/><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra"/><title type='text'>Repasamos las inecuaciones</title><content type='html'>Antes de meternos de pleno en el tema de programación lineal es conveniente que repasemos cómo se resuelven las inecuaciones, tanto en lo que se refiere a sistemas lineales de una incógnita como de dos incógnitas. Les propongo el siguiente vídeo para aclarar las posibles dudas que hayan quedado del curso pasado:&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;//www.youtube.com/embed/42ZjyjG7HG0&quot; width=&quot;560&quot;&gt;&lt;/iframe&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/6633783887724930379/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/10/repasamos-las-inecuaciones.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/6633783887724930379'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/6633783887724930379'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/10/repasamos-las-inecuaciones.html' title='Repasamos las inecuaciones'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-5519593456603188244</id><published>2013-10-03T18:07:00.000+01:00</published><updated>2013-10-03T18:07:53.430+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="autoevaluacion"/><category scheme="http://www.blogger.com/atom/ns#" term="sistemas"/><title type='text'>Terminado este tema</title><content type='html'>Ahora te toca hacer la &lt;b&gt;&lt;u&gt;autoevaluación&lt;/u&gt;&lt;/b&gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;iframe frameborder=&quot;0&quot; height=&quot;500&quot; marginheight=&quot;0&quot; marginwidth=&quot;0&quot; src=&quot;https://docs.google.com/forms/d/1oWAbeWkWuUVkphZtcNjcaZzdJjbLbMwhnkY-36x-Pg8/viewform?embedded=true&quot; width=&quot;600&quot;&gt;Cargando...&lt;/iframe&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/5519593456603188244/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/10/terminado-este-tema.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/5519593456603188244'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/5519593456603188244'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/10/terminado-este-tema.html' title='Terminado este tema'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-5787156545025164286</id><published>2013-10-03T17:56:00.000+01:00</published><updated>2013-10-03T17:56:56.220+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="sistemas"/><title type='text'>Segunda entrega</title><content type='html'>... de las soluciones a los ejercicios del tema.&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;embed allowfullscreen=&quot;true&quot; allowscriptaccess=&quot;always&quot; height=&quot;400&quot; src=&quot;https://app.box.com/embed/3qcscqd4tdgvwcb.swf&quot; type=&quot;application/x-shockwave-flash&quot; width=&quot;466&quot; wmode=&quot;opaque&quot;&gt;&lt;/embed&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/5787156545025164286/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/10/segunda-entrega.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/5787156545025164286'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/5787156545025164286'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/10/segunda-entrega.html' title='Segunda entrega'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-7731133001006128224</id><published>2013-09-30T08:00:00.000+01:00</published><updated>2013-09-30T08:00:04.369+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="Calculadora"/><category scheme="http://www.blogger.com/atom/ns#" term="sistemas"/><title type='text'>Trabajando sistemas de ecuaciones lineales</title><content type='html'>Aquí les dejo las soluciones a los primeros ejercicios de la fotocopia. Están resueltos mediante la calculadora Wiris (recuerden que el curso pasado estuvimos trabajando con ella). Les recomiendo que la utilicen para comprobar las soluciones de los ejercicios que ustedes practiquen.&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;embed allowfullscreen=&quot;true&quot; allowscriptaccess=&quot;always&quot; height=&quot;400&quot; src=&quot;https://app.box.com/embed/iayh0yrtc5fxoqe.swf&quot; type=&quot;application/x-shockwave-flash&quot; width=&quot;466&quot; wmode=&quot;opaque&quot;&gt;&lt;/embed&gt;

&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
En la siguiente dirección puedes ir a la calculadora Wiris on-line de la editorial Bruño: &lt;a href=&quot;http://www.wiris.net/editorial-bruno/wiris/es/index.html&quot; target=&quot;_blank&quot;&gt;WIRIS&lt;/a&gt;&amp;nbsp;&lt;/div&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/7731133001006128224/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/09/trabajando-sistemas-de-ecuaciones.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/7731133001006128224'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/7731133001006128224'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/09/trabajando-sistemas-de-ecuaciones.html' title='Trabajando sistemas de ecuaciones lineales'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-6813985290792440916</id><published>2013-09-17T11:59:00.000+01:00</published><updated>2013-09-17T12:00:14.559+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra"/><title type='text'>Método de Gauss</title><content type='html'>Gauss nos propone resolver sistemas de tres ecuaciones convirtiéndolos en un sistema escalonado. Hoy en clase empezamos a transformar algunas ecuaciones para poder conseguir este tipo de sistemas. El siguiente video nos lo vuelve a explicar paso a paso.&lt;br /&gt;
También he habilitado una nueva pestaña (&lt;a href=&quot;http://mismates2bach.blogspot.com.es/p/sistemas-lineales.html&quot; target=&quot;_blank&quot;&gt;Sist. ec. lineales&lt;/a&gt;) en donde pueden encontrar los recursos del tema que estamos dando que me parecen más interesantes (aplicaciones interactivas, videos, apuntes, páginas web). Recuerden echarle un vistazo cuando necesiten ampliar lo practicado en clase.&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;//www.youtube.com/embed/kKK1iLzbFDw?rel=0&quot; width=&quot;560&quot;&gt;&lt;/iframe&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/6813985290792440916/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/09/metodo-de-gauss.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/6813985290792440916'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/6813985290792440916'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/09/metodo-de-gauss.html' title='Método de Gauss'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-8273633602683874893</id><published>2013-09-16T12:55:00.000+01:00</published><updated>2013-09-16T12:55:32.393+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="2º CCSS"/><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra"/><title type='text'>Desengrasando neuronas</title><content type='html'>&lt;a href=&quot;http://www.ub.edu/stat/GrupsInnovacio/Statmedia/demo/Temas/Capitulo8/Images/normal39.jpg&quot; imageanchor=&quot;1&quot; style=&quot;clear: left; float: left; margin-bottom: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;286&quot; src=&quot;http://www.ub.edu/stat/GrupsInnovacio/Statmedia/demo/Temas/Capitulo8/Images/normal39.jpg&quot; width=&quot;320&quot; /&gt;&lt;/a&gt;Empezamos a publicar cosas en el blog de 2º bachillerato. Durante este curso estará dedicado a las matemáticas aplicadas ya que es el nivel que este año imparto.&lt;br /&gt;
Empezamos a trabajar con el bloque de Álgebra y necesitamos revisar los conocimientos previos adquiridos en cursos anteriores acerca de la resolución de sistemas lineales (método de reducción).&lt;br /&gt;
Quien no lo recuerde suficientemente, o sencillamente necesite refrescar &quot;neuronas&quot;, les propongo que visualicen el siguiente vídeo (cojan lápiz y papel y vayan haciendo las operaciones que hace el profesor ¡es un consejo!)&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;//www.youtube.com/embed/hIYhtq8e8jA?rel=0&quot; width=&quot;560&quot;&gt;&lt;/iframe&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/8273633602683874893/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/09/desengrasando-neuronas.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/8273633602683874893'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/8273633602683874893'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/09/desengrasando-neuronas.html' title='Desengrasando neuronas'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-3383562294340768857</id><published>2013-04-04T18:34:00.002+01:00</published><updated>2013-04-04T18:34:48.789+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra matricial"/><title type='text'>Discusión de sistemas con parámetros y wiris</title><content type='html'>&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;356&quot; marginheight=&quot;0&quot; marginwidth=&quot;0&quot; mozallowfullscreen=&quot;&quot; scrolling=&quot;no&quot; src=&quot;http://www.slideshare.net/slideshow/embed_code/18186910&quot; style=&quot;border-width: 1px 1px 0; border: 1px solid #CCC; margin-bottom: 5px;&quot; webkitallowfullscreen=&quot;&quot; width=&quot;427&quot;&gt; &lt;/iframe&gt; &lt;br /&gt;
&lt;div style=&quot;margin-bottom: 5px;&quot;&gt;
&lt;strong&gt; &lt;a href=&quot;http://www.slideshare.net/MisMatesCarmen/wiris-sistemas&quot; target=&quot;_blank&quot; title=&quot;Wiris sistemas&quot;&gt;Wiris sistemas&lt;/a&gt; &lt;/strong&gt; from &lt;strong&gt;&lt;a href=&quot;http://www.slideshare.net/MisMatesCarmen&quot; target=&quot;_blank&quot;&gt;MisMatesCarmen&lt;/a&gt;&lt;/strong&gt; &lt;/div&gt;
&lt;br /&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/3383562294340768857/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/04/discusion-de-sistemas-con-parametros-y.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/3383562294340768857'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/3383562294340768857'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/04/discusion-de-sistemas-con-parametros-y.html' title='Discusión de sistemas con parámetros y wiris'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-5707758164260618940</id><published>2013-04-02T13:09:00.000+01:00</published><updated>2013-04-02T13:09:37.132+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="sistemas"/><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra matricial"/><title type='text'>Discusión de sistemas con parámetros</title><content type='html'>El siguiente documento son los ejercicios propuestos hoy en clase, resueltos con la calculadora Wiris. En una próxima entrada publicaré el tutorial de cómo resolver estos ejercicios mediante esta aplicación.&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;embed allowfullscreen=&quot;true&quot; allowscriptaccess=&quot;always&quot; height=&quot;400&quot; src=&quot;https://www.box.com/embed/dhbzt848zirzits.swf&quot; type=&quot;application/x-shockwave-flash&quot; width=&quot;466&quot; wmode=&quot;opaque&quot;&gt;&lt;/embed&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/5707758164260618940/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/04/discusion-de-sistemas-con-parametros.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/5707758164260618940'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/5707758164260618940'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/04/discusion-de-sistemas-con-parametros.html' title='Discusión de sistemas con parámetros'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-1364752666786179328</id><published>2013-03-16T13:40:00.000+00:00</published><updated>2013-03-16T13:40:35.054+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="sistemas"/><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra matricial"/><title type='text'>Discusión de sistemas</title><content type='html'>En el siguiente documento hacemos un estudio de rangos e interpretación geométrica de los sistemas lineales para los casos n = 2 y n = 3.&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;embed allowfullscreen=&quot;true&quot; allowscriptaccess=&quot;always&quot; height=&quot;400&quot; src=&quot;https://www.box.com/embed/hi8wh8j2xsfvbyw.swf&quot; type=&quot;application/x-shockwave-flash&quot; width=&quot;466&quot; wmode=&quot;opaque&quot;&gt;&lt;/embed&gt;

&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
En el siguiente enlace puedes practicar la relación entre los rangos de la matriz del sistema, la matriz ampliada y la posición relativa de los planos del sistema:&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;a href=&quot;http://antoniovilahp.galeon.com/3planos.htm&quot; target=&quot;_blank&quot;&gt;POSICIÓN RELATIVA DE TRES PLANOS&lt;/a&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
Esta es la solución del ejercicio PAU propuesto en la anterior entrada:&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;embed allowfullscreen=&quot;true&quot; allowscriptaccess=&quot;always&quot; height=&quot;400&quot; src=&quot;https://www.box.com/embed/igevtv7oev30otz.swf&quot; type=&quot;application/x-shockwave-flash&quot; width=&quot;466&quot; wmode=&quot;opaque&quot;&gt;&lt;/embed&gt;

&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
Y terminamos por hoy con una nueva propuesta de ejercicio PAU de análisis:&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgY3OI2cXxXOJG3MXb_IOfqNUsWyBKqPXbYfUchnHviSMPD8ybuhrvPghi-2cvng8toHQ4he6xvWYpF40a3eHQ_RWnJCaEJWCZ5xqvIdqMX3NgCxrSzhZjiWWA1OXWrJ15__BTAxzev5gMq/s1600/Dibujo.jpg&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;220&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgY3OI2cXxXOJG3MXb_IOfqNUsWyBKqPXbYfUchnHviSMPD8ybuhrvPghi-2cvng8toHQ4he6xvWYpF40a3eHQ_RWnJCaEJWCZ5xqvIdqMX3NgCxrSzhZjiWWA1OXWrJ15__BTAxzev5gMq/s400/Dibujo.jpg&quot; width=&quot;400&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/1364752666786179328/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/03/discusion-de-sistemas.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/1364752666786179328'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/1364752666786179328'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/03/discusion-de-sistemas.html' title='Discusión de sistemas'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgY3OI2cXxXOJG3MXb_IOfqNUsWyBKqPXbYfUchnHviSMPD8ybuhrvPghi-2cvng8toHQ4he6xvWYpF40a3eHQ_RWnJCaEJWCZ5xqvIdqMX3NgCxrSzhZjiWWA1OXWrJ15__BTAxzev5gMq/s72-c/Dibujo.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-7499986097738629507</id><published>2013-02-28T18:29:00.002+00:00</published><updated>2013-02-28T18:31:08.113+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra matricial"/><title type='text'>Matriz inversa</title><content type='html'>Una nueva entrega de videos para el tema de Matrices. En esta ocasión es una explicación de los pasos a seguir para obtener la matriz inversa.&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;http://www.youtube.com/embed/DOvTkttnzZA?rel=0&quot; width=&quot;560&quot;&gt;&lt;/iframe&gt;&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
También les dejo la solución del problema PAU de la clase de hoy ¡espero sus soluciones del próximo problema!:&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;embed allowfullscreen=&quot;true&quot; allowscriptaccess=&quot;always&quot; height=&quot;400&quot; src=&quot;https://www.box.com/embed/kv3kkk2rtujgof2.swf&quot; type=&quot;application/x-shockwave-flash&quot; width=&quot;466&quot; wmode=&quot;opaque&quot;&gt;&lt;/embed&gt;

&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;br /&gt;
Y este es el nuevo problema propuesto. PAU SEPTIEMBRE DEL CURSO 2010/11.&lt;/div&gt;
&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiKLb4oPNtSx__fM2MKJiXW3qS_BT3DQu3sjZ9ikw5ouV9IGmq43x0g62Y1cfTCPKCXCBk7VCT1g6I1WP-rx1w4UgF2hWa0LesoHQyDsLvp_Pe1BvuL9yLhPAWIuW93UDJJEpUYe99dMxlz/s1600/PAU04.jpg&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;99&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiKLb4oPNtSx__fM2MKJiXW3qS_BT3DQu3sjZ9ikw5ouV9IGmq43x0g62Y1cfTCPKCXCBk7VCT1g6I1WP-rx1w4UgF2hWa0LesoHQyDsLvp_Pe1BvuL9yLhPAWIuW93UDJJEpUYe99dMxlz/s400/PAU04.jpg&quot; width=&quot;400&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/7499986097738629507/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/02/matriz-inversa.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/7499986097738629507'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/7499986097738629507'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/02/matriz-inversa.html' title='Matriz inversa'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://img.youtube.com/vi/DOvTkttnzZA/default.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-1946759352255841856</id><published>2013-02-21T12:43:00.000+00:00</published><updated>2013-02-21T12:43:18.126+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="Calculadora"/><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra matricial"/><title type='text'>Matrices y calculadora</title><content type='html'>Algunas de sus calculadoras permite el cálculo básico con matrices: suma, resta, multiplicación, potencia y algunas cosas más que todavía están pendiente de explicar así que ni se las nombro todavía. En el siguiente vídeo se explica cómo funciona.&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;http://www.youtube.com/embed/DzaqhzDSFdk?rel=0&quot; width=&quot;560&quot;&gt;&lt;/iframe&gt;

&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
Por otro lado, el siguiente documento es la solución al problema de PAU de hoy:&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;embed allowfullscreen=&quot;true&quot; allowscriptaccess=&quot;always&quot; height=&quot;400&quot; src=&quot;https://www.box.com/embed/z04c0by8l6duo4f.swf&quot; type=&quot;application/x-shockwave-flash&quot; width=&quot;466&quot; wmode=&quot;opaque&quot;&gt;&lt;/embed&gt;

&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;Y finalmente este es el nuevo problema propuesto:&lt;/b&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;a) Dada la función&amp;nbsp;&lt;/b&gt;&lt;/span&gt;&lt;/div&gt;
&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;&lt;math xmlns=&quot;http://www.w3.org/1998/Math/MathML&quot;&gt;&lt;mrow&gt;&lt;mi&gt;f&lt;/mi&gt;&lt;mfenced&gt;&lt;mi&gt;x&lt;/mi&gt;&lt;/mfenced&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;msup&gt;&lt;mfenced&gt;&lt;mrow&gt;&lt;mi&gt;cos&lt;/mi&gt;&lt;mfenced&gt;&lt;mrow&gt;&lt;mn&gt;3&lt;/mn&gt;&lt;mi&gt;x&lt;/mi&gt;&lt;/mrow&gt;&lt;/mfenced&gt;&lt;/mrow&gt;&lt;/mfenced&gt;&lt;mn&gt;2&lt;/mn&gt;&lt;mn&gt;&lt;br /&gt;&lt;/mn&gt;&lt;/msup&gt;&lt;/mrow&gt;&lt;/math&gt;

&lt;/b&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;hallar las ecuaciones de las rectas tangente y normal a su gráfica en el punto de abscisa x = PI/12.&lt;/b&gt;&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;b) Hallar los extremos relativos y los puntos de inflexión de la función:&lt;/b&gt;&lt;/span&gt;&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;math xmlns=&quot;http://www.w3.org/1998/Math/MathML&quot;&gt;&lt;mrow&gt;&lt;/mrow&gt;&lt;/math&gt;&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;&lt;mi&gt;g&lt;/mi&gt;&lt;mo&gt;(&lt;/mo&gt;&lt;mi&gt;x&lt;/mi&gt;&lt;mo&gt;)&lt;/mo&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;mn&gt;2&lt;/mn&gt;&lt;msup&gt;&lt;mi&gt;x&lt;/mi&gt;&lt;mn&gt;3&lt;/mn&gt;&lt;/msup&gt;&lt;mo&gt;-&lt;/mo&gt;&lt;mn&gt;3&lt;/mn&gt;&lt;msup&gt;&lt;mi&gt;x&lt;/mi&gt;&lt;mn&gt;2&lt;/mn&gt;&lt;/msup&gt;&lt;mo&gt;-&lt;/mo&gt;&lt;mn&gt;12&lt;/mn&gt;&lt;mi&gt;x&lt;/mi&gt;&lt;mo&gt;+&lt;/mo&gt;&lt;mn&gt;5&lt;/mn&gt;&lt;/b&gt;&lt;/span&gt;
&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/1946759352255841856/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/02/matrices-y-calculadora.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/1946759352255841856'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/1946759352255841856'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/02/matrices-y-calculadora.html' title='Matrices y calculadora'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://img.youtube.com/vi/DzaqhzDSFdk/default.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-2579734531587109663</id><published>2013-02-19T17:27:00.000+00:00</published><updated>2013-02-19T17:31:47.881+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra matricial"/><title type='text'>Matrices III</title><content type='html'>El siguiente documento es el problema de PAU resuelto hoy en clase y realizado mediante el uso de la calculadora WIRIS:&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;embed allowfullscreen=&quot;true&quot; allowscriptaccess=&quot;always&quot; height=&quot;400&quot; src=&quot;https://www.box.com/embed/tlddpv96kezesm8.swf&quot; type=&quot;application/x-shockwave-flash&quot; width=&quot;466&quot; wmode=&quot;opaque&quot;&gt;&lt;/embed&gt;

&lt;br /&gt;
&lt;div style=&quot;text-align: justify;&quot;&gt;
&lt;br /&gt;
La representación de la función f, que viene confirmada por los cálculos, es la siguiente:&lt;br /&gt;
&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;
&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhpkB_HwGAu1gvqEnPYy_OrCHGKUKp8zcavxARG9J6kp43WMcVJouQVcwsNTMpBtYEmY_vPLQB_BwUk1x_2xscsl3Qk01AwR_DgWG_rcNUVC_iB7E1gfOFWd8FoqoUP1Fnnmgyf7umES3J9/s1600/PAU01.jpeg&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; height=&quot;219&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhpkB_HwGAu1gvqEnPYy_OrCHGKUKp8zcavxARG9J6kp43WMcVJouQVcwsNTMpBtYEmY_vPLQB_BwUk1x_2xscsl3Qk01AwR_DgWG_rcNUVC_iB7E1gfOFWd8FoqoUP1Fnnmgyf7umES3J9/s320/PAU01.jpeg&quot; width=&quot;320&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;br /&gt;
Además, ya está propuesto el siguiente problema:&lt;/div&gt;
&lt;div style=&quot;text-align: justify;&quot;&gt;
&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;La temperatura T, en grados centígrado, que adquiere una pieza sometida a un cierto proceso de 6 horas de duración, viene dada en función del tiempo t transcurrido en ese proceso por la expresión&lt;/b&gt;&lt;/span&gt;&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/span&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;&lt;math xmlns=&quot;http://www.w3.org/1998/Math/MathML&quot;&gt;&lt;mrow&gt;&lt;mi&gt;T&lt;/mi&gt;&lt;mfenced&gt;&lt;mi&gt;t&lt;/mi&gt;&lt;/mfenced&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;mn&gt;20&lt;/mn&gt;&lt;mo&gt;+&lt;/mo&gt;&lt;mfrac&gt;&lt;mrow&gt;&lt;mn&gt;5&lt;/mn&gt;&lt;mi&gt;t&lt;/mi&gt;&lt;mo&gt;-&lt;/mo&gt;&lt;mn&gt;15&lt;/mn&gt;&lt;/mrow&gt;&lt;mrow&gt;&lt;msup&gt;&lt;mi&gt;t&lt;/mi&gt;&lt;mn&gt;2&lt;/mn&gt;&lt;/msup&gt;&lt;mo&gt;-&lt;/mo&gt;&lt;mn&gt;6&lt;/mn&gt;&lt;mi&gt;t&lt;/mi&gt;&lt;mo&gt;+&lt;/mo&gt;&lt;mn&gt;10&lt;/mn&gt;&lt;/mrow&gt;&lt;/mfrac&gt;&lt;/mrow&gt;&lt;/math&gt;&amp;nbsp; &amp;nbsp; (con 0 &lt;u&gt;&amp;lt;&lt;/u&gt; t &lt;u&gt;&amp;lt;&lt;/u&gt; 6)&lt;/b&gt;&lt;/span&gt;&lt;math xmlns=&quot;http://www.w3.org/1998/Math/MathML&quot;&gt;&lt;mrow&gt;&lt;mi&gt;&lt;br /&gt;&lt;/mi&gt;&lt;/mrow&gt;&lt;/math&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: justify;&quot;&gt;
&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;Determinar en qué momento del proceso la pieza alcanza su temperatura máxima y en qué momento alcanza su temperatura mínima. Justificar las respuestas.&lt;/b&gt;&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;color: blue; font-family: Arial, Helvetica, sans-serif;&quot;&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/span&gt;
&lt;span style=&quot;font-family: inherit;&quot;&gt;Siguiendo con el tema de matrices ahí va el siguiente vídeo de la serie:&lt;/span&gt;&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;http://www.youtube.com/embed/NuzbgFiHCuE?rel=0&quot; width=&quot;560&quot;&gt;&lt;/iframe&gt;
&lt;span style=&quot;font-family: inherit;&quot;&gt;&lt;br /&gt;&lt;/span&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/2579734531587109663/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/02/matrices-iii.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/2579734531587109663'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/2579734531587109663'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/02/matrices-iii.html' title='Matrices III'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhpkB_HwGAu1gvqEnPYy_OrCHGKUKp8zcavxARG9J6kp43WMcVJouQVcwsNTMpBtYEmY_vPLQB_BwUk1x_2xscsl3Qk01AwR_DgWG_rcNUVC_iB7E1gfOFWd8FoqoUP1Fnnmgyf7umES3J9/s72-c/PAU01.jpeg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-2835513951601836146</id><published>2013-02-18T19:31:00.001+00:00</published><updated>2013-02-18T19:31:36.998+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra matricial"/><title type='text'>Matrices II</title><content type='html'>Unos videos más sobre lo aprendido &amp;nbsp;y practicado hoy en clase: Tipos de matrices y matriz traspuesta.&lt;br /&gt;
&lt;div&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;http://www.youtube.com/embed/d-FMZIXC3Dc?rel=0&quot; width=&quot;560&quot;&gt;&lt;/iframe&gt;

&lt;br /&gt;
&lt;br /&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;http://www.youtube.com/embed/sMj13fW-EzY?rel=0&quot; width=&quot;560&quot;&gt;&lt;/iframe&gt;&lt;br /&gt;
&lt;br /&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;http://www.youtube.com/embed/yKZwUCsS8XU?rel=0&quot; width=&quot;560&quot;&gt;&lt;/iframe&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/2835513951601836146/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/02/matrices-ii.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/2835513951601836146'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/2835513951601836146'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/02/matrices-ii.html' title='Matrices II'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://img.youtube.com/vi/d-FMZIXC3Dc/default.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-7453422295280661968</id><published>2013-02-14T09:07:00.000+00:00</published><updated>2013-02-14T09:07:26.513+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="Álgebra matricial"/><title type='text'>Matrices</title><content type='html'>Terminado el bloque de Análisis, nos adentramos en el mundo del Álgebra introduciendo un nuevo elemento de trabajo que son las matrices. El siguiente vídeo es una introducción al concepto de matrices y los elementos que la definen (filas, columnas, dimensión,...). Muy clara la explicación: SE LAS RECOMIENDO.&lt;br /&gt;
También comentamos en clase que iríamos resolviendo ejercicios de PAU del bloque de Análisis que les sirva de repaso tanto a los alumnos que ya han superado este bloque como a aquellos de ustedes que todavía tienen que recuperarlo. Después del video les propongo el primer ejercicio que vamos a trabajar.&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;&quot; frameborder=&quot;0&quot; height=&quot;315&quot; src=&quot;http://www.youtube.com/embed/A3K5wr3ArGE?rel=0&quot; width=&quot;560&quot;&gt;&lt;/iframe&gt;

&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;br /&gt;
&lt;span style=&quot;color: blue;&quot;&gt;&lt;b&gt;EJERCICIO PAU. CURSO 2011/12. SEPTIEMBRE.&lt;/b&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;span style=&quot;color: blue;&quot;&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/span&gt;
&lt;span style=&quot;color: blue;&quot;&gt;&lt;b&gt;Dada la función&amp;nbsp;&lt;/b&gt;&lt;/span&gt;&lt;/div&gt;
&lt;span style=&quot;color: blue;&quot;&gt;&lt;b&gt;&lt;math xmlns=&quot;http://www.w3.org/1998/Math/MathML&quot;&gt;&lt;mrow&gt;&lt;mi&gt;f&lt;/mi&gt;&lt;mfenced&gt;&lt;mi&gt;x&lt;/mi&gt;&lt;/mfenced&gt;&lt;mo&gt;=&lt;/mo&gt;&lt;mfrac&gt;&lt;mrow&gt;&lt;mn&gt;2&lt;/mn&gt;&lt;msup&gt;&lt;mi&gt;x&lt;/mi&gt;&lt;mn&gt;2&lt;/mn&gt;&lt;/msup&gt;&lt;mo&gt;+&lt;/mo&gt;&lt;mn&gt;3&lt;/mn&gt;&lt;/mrow&gt;&lt;mrow&gt;&lt;msup&gt;&lt;mi&gt;x&lt;/mi&gt;&lt;mn&gt;2&lt;/mn&gt;&lt;/msup&gt;&lt;mo&gt;-&lt;/mo&gt;&lt;mn&gt;4&lt;/mn&gt;&lt;mn&gt;&lt;br /&gt;&lt;/mn&gt;&lt;mn&gt;&lt;br /&gt;&lt;/mn&gt;&lt;mn&gt;&lt;br /&gt;&lt;/mn&gt;&lt;mn&gt;&lt;br /&gt;&lt;/mn&gt;&lt;mn&gt;&lt;br /&gt;&lt;/mn&gt;&lt;/mrow&gt;&lt;/mfrac&gt;&lt;/mrow&gt;&lt;/math&gt;
&lt;/b&gt;&lt;/span&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
&lt;span style=&quot;color: blue;&quot;&gt;&lt;b&gt;a) Obtener su dominio y los cortes de su gráfica con los ejes de coordenadas (explicar).&lt;/b&gt;&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;color: blue;&quot;&gt;&lt;b&gt;b) Hallar las asíntotas horizontales y verticales de su gráfica, justificándolas.&lt;/b&gt;&lt;/span&gt;&lt;br /&gt;
&lt;span style=&quot;color: blue;&quot;&gt;&lt;b&gt;c) Determinar intervalos de crecimiento, intervalos de decrecimiento y extremos relativos de esta función. Justificar los resultados obtenidos.&lt;/b&gt;&lt;/span&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/7453422295280661968/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2013/02/matrices.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/7453422295280661968'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/7453422295280661968'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2013/02/matrices.html' title='Matrices'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://img.youtube.com/vi/A3K5wr3ArGE/default.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-1217020981659745110</id><published>2012-12-20T09:36:00.000+00:00</published><updated>2012-12-20T09:36:10.870+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="funcioens"/><category scheme="http://www.blogger.com/atom/ns#" term="integrales"/><title type='text'>Empezando con las integrales</title><content type='html'>Les recomiendo la siguiente página en donde pueden encontrar actividades referentes a todo el temario de 2º de bachillerato:&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;a href=&quot;http://www.vadenumeros.es/segundo/indice-segundo-de-ciencias.htm&quot; target=&quot;_blank&quot;&gt;VADENUMEROS.ES&lt;/a&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
Ahora estamos trabajando las integrales así que dentro de esta página vamos a la tabla de integrales inmediatas y, en ella, podemos enlazar con algunos ejemplos resueltos de cada uno de los tipos que aparece en esta tabla:&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;a href=&quot;http://www.vadenumeros.es/segundo/tabla-de-integrales-inmediatas.htm&quot; target=&quot;_blank&quot;&gt;TABLA DE INTEGRALES INMEDIATAS&lt;/a&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
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&lt;br /&gt;&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/1217020981659745110/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2012/12/empezando-con-las-integrales.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/1217020981659745110'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/1217020981659745110'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2012/12/empezando-con-las-integrales.html' title='Empezando con las integrales'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEheqhIlNZuMS_XLNm3oALggXWnAOCstfmCTyQdLoO3zT30-QhUQ3YtZOf2OpdVdaEHPZ2VkzUOZKL3Q9eYAhrckn0SOuB_PoATYCC4rm9VJWg21inSxBM1qoJ7LldnhkNCotVy5SFWMQwBs/s72-c/reyes_magos.gif" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-3549457657644253339</id><published>2012-11-14T15:29:00.000+00:00</published><updated>2012-11-14T15:29:38.682+00:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="funcioens"/><category scheme="http://www.blogger.com/atom/ns#" term="límites"/><title type='text'>Regla de L&#39;Hôpital y funciones arcos</title><content type='html'>En este ejercicio vemos una aplicación de la regla de L&#39;Hôpital a un límite en el que aparecen varias funciones &quot;arco&quot;:&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowtransparency=&quot;true&quot; frameborder=&quot;0&quot; src=&quot;http://www.selectividad.tv/API.php?tipo=swf&amp;amp;codigo=M_2_3_2&amp;amp;ancho=578&amp;amp;alto=334&quot; style=&quot;border: none; height: 334px; overflow: hidden; width: 578px;&quot;&gt; &lt;/iframe&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/3549457657644253339/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2012/11/regla-de-lhopital-y-funciones-arcos.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/3549457657644253339'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/3549457657644253339'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2012/11/regla-de-lhopital-y-funciones-arcos.html' title='Regla de L&#39;Hôpital y funciones arcos'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-1405893047910961616</id><published>2012-10-18T17:49:00.001+01:00</published><updated>2012-10-18T17:50:24.430+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="Derivadas"/><category scheme="http://www.blogger.com/atom/ns#" term="funcioens"/><category scheme="http://www.blogger.com/atom/ns#" term="gráficas"/><title type='text'>Funciones racionales</title><content type='html'>Estamos estudiando algunas aplicaciones de las derivadas, unas fáciles de intuir y otras un poco más complicadas. Hemos trabajado ya las construcciones gráficas de una función polinómica y también de funciones definidas a trozos.&lt;br /&gt;
Estudiamos ahora otro tipo de funciones: las racionales. Les propongo que estudien esta imagen: no deja de ser un primer ejemplo. Vamos a ver si le sacamos partido a esta aplicación y ustedes son capaces de completarla.&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
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&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe frameborder=&quot;0&quot; height=&quot;610&quot; marginheight=&quot;0&quot; marginwidth=&quot;0&quot; scrolling=&quot;no&quot; src=&quot;http://www.speakingimage.org/imageapi/bd040d3a5ffa95e6bc370c3ad5200fa7?w=685&amp;amp;h=610&quot; width=&quot;685&quot;&gt;&lt;/iframe&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/1405893047910961616/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2012/10/funciones-racionales.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/1405893047910961616'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/1405893047910961616'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2012/10/funciones-racionales.html' title='Funciones racionales'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-172200093984629766</id><published>2012-10-15T08:00:00.000+01:00</published><updated>2012-10-15T08:00:18.539+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="derivabilidad"/><category scheme="http://www.blogger.com/atom/ns#" term="Derivadas"/><title type='text'>Continuidad y derivabilidad</title><content type='html'>Les propongo en esta entrada un ejercicio resuelto, paso a paso, acerca de la continuidad y derivabilidad de una función definida a trozos:&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowtransparency=&quot;true&quot; frameborder=&quot;0&quot; src=&quot;http://www.selectividad.tv/API.php?tipo=swf&amp;amp;codigo=M_2_1_2&amp;amp;ancho=514&amp;amp;alto=350&quot; style=&quot;border: none; height: 350px; overflow: hidden; width: 514px;&quot;&gt; &lt;/iframe&gt;

&lt;br /&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
Además muy interesante la página de referencia &lt;a href=&quot;http://www.selectividad.tv/index.php&quot;&gt;selectividad.tv&lt;/a&gt;&amp;nbsp;donde podrás encontrar una muy completa colección de exámenes de selectividad resueltos paso a paso (no sólo de matemáticas).&lt;/div&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/172200093984629766/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2012/10/continuidad-y-derivabilidad.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/172200093984629766'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/172200093984629766'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2012/10/continuidad-y-derivabilidad.html' title='Continuidad y derivabilidad'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-1199899924437805291</id><published>2012-09-18T19:52:00.001+01:00</published><updated>2012-09-19T17:39:19.762+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="Derivadas"/><title type='text'>Empezando el curso</title><content type='html'>Empezamos este curso donde lo dejamos el curso pasado: es decir (para los que no se acuerden ya) pues habíamos trabajado con muchas funciones, con casi todas sus características y empezamos a trabajar el concepto de derivada (incluso aprendimos a derivar algunas funciones, que no todas).&lt;br /&gt;
Este curso partiremos del repaso al concepto de derivada y una de sus primeras aplicaciones, el cálculo de la ecuación de la recta tangente en un punto.&lt;br /&gt;
Por lo pronto un vídeo musical al respecto. ¡La narración ya la pondremos mañana en la clase!&lt;br /&gt;
&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;iframe allowfullscreen=&quot;allowfullscreen&quot; frameborder=&quot;0&quot; height=&quot;360&quot; src=&quot;http://www.youtube.com/embed/rjmWmouaHjw?rel=0&quot; width=&quot;480&quot;&gt;&lt;/iframe&gt;
&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: left;&quot;&gt;
Las fotocopias que hoy les entregué en clase para trabajar estos días las pueden descargar desde la caja de box en la barra lateral. El documento se llama Derivadas_I:&lt;br /&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;br /&gt;&lt;/div&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;
&lt;embed allowfullscreen=&quot;true&quot; allowscriptaccess=&quot;always&quot; height=&quot;400&quot; src=&quot;https://www.box.com/embed/klwj4q3ed5c9mn5.swf&quot; type=&quot;application/x-shockwave-flash&quot; width=&quot;466&quot; wmode=&quot;opaque&quot;&gt;&lt;/embed&gt;
&lt;/div&gt;
&lt;/div&gt;
</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/1199899924437805291/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2012/09/empezando-el-curso.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/1199899924437805291'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/1199899924437805291'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2012/09/empezando-el-curso.html' title='Empezando el curso'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://img.youtube.com/vi/rjmWmouaHjw/default.jpg" height="72" width="72"/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3307136016266736838.post-5053976730871134045</id><published>2011-07-29T11:30:00.001+01:00</published><updated>2011-07-29T11:30:37.778+01:00</updated><category scheme="http://www.blogger.com/atom/ns#" term="General"/><title type='text'>Cuaderno de aula</title><content type='html'>Este es el cuaderno de aula para los alumnos de 2º de bachillerato.</content><link rel='replies' type='application/atom+xml' href='http://mismates2bach.blogspot.com/feeds/5053976730871134045/comments/default' title='Enviar comentarios'/><link rel='replies' type='text/html' href='http://mismates2bach.blogspot.com/2011/07/cuaderno-de-aula.html#comment-form' title='0 comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/5053976730871134045'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3307136016266736838/posts/default/5053976730871134045'/><link rel='alternate' type='text/html' href='http://mismates2bach.blogspot.com/2011/07/cuaderno-de-aula.html' title='Cuaderno de aula'/><author><name>Camortru</name><uri>http://www.blogger.com/profile/07482640087769357308</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='https://img1.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry></feed>