Yeah. The more beer, the better the mathematics

Humans are generally tended to not like those different from themselves, or at least different from what they perceive themselves to be.

This probably isn’t a very popular post, but I was thinking what the heck, I’ll still write this post anyway

Will be correcting my post accordingly at a later time..

On a side note, I’m quite surprised you actually bothered to take the time to write all that!

How about the following:

c=Total permutation = 6^35

a1=Permutations with only 0 dice with r = 35C0*5^(35-0) = 5^35
a1=Permutations with only 1 dice with r = 35C1*5^(35-1) = 5^34
a2=Permutations with only 2 dice with r = 35C2*5^(35-2) = 5^33
a3=Permutations with only 3 dice with r = 35C3*5^(35-3) = 5^32
a4=Permutations with only 4 dice with r = 35C4*5^(35-4) = 5^31
a5=Permutations with only 5 dice with r = 35C5*5^(35-5) = 5^30
a6=Permutations with only 6 dice with r = 35C6*5^(35-6) = 5^29

b=Probability of only 6 or less dice with r = (a0=a1+a2+a3+a4+a5+a6)/c

Probability of at least 7 dice with r = 1-b = 218/599 = 0.36393992184419

If 35 dice is complicated, try just 2 dice.
Total permutations = 6^2 = 36
Permutations for zero dice with r = 2C0 * 5^2 (ie choosing zero from two dice, and the remaining two dice will be of any of the 5 numbers beside r) = 1*25 = 25
Permuations for one dice with r = 2C1 * 5^1 (ie choosing one from two dice, and the other dice will be of any of the 5 numbers beside r) = 2*5 = 10
Permuations for two dice with r = 2C2 * 5^0 (ie choosing two from two dice, and the remaining zero dice will be of any of the 5 numbers beside r) = 1*1 = 1
If you add up the permutations for zero, one and two dice with r, the total permutations will be 36, the same as 6^2.
This means the probability for each of the permutations will add up to 1:
probability of zero dice with r = 25/36
probability of only one dice with r = 10/36
probability of two dice with r = 1/36
25/36 + 10/36 + 1/36 = 36/36 = 1

By extension, probability of at least one dice with r = probability of one dice with r + probability of two dice with r
which is also = 1 – (probability of zero dice with r)

i personally have worked with many foreigners, from malaysia, PRC, philippines and india, and most of my experience with them have been great. especially during my days as HR exec in a manufacturing company.. a lot of these blue collar workers jus wanna earn a living, they don’t mean harm to anyone here, n they are, in fact, very kind people too. so i just can’t tolerate it whn people pass generalizing, discriminating remarks (nothing to do with the fact that i’m not local either) haha.. actually i just don’t like discrimination of any sort.