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>> J. M. Wagner , you are talking right. I already detected & accepted defects in my analysis. In my opinion it is not at all cosmic as it is not accurate value. Somewhere there is very minute error In R.S. Reddy’s analysis of Pi. For that the expert mathematician have to verify every step & assumption involved in RS Reddy’s method.

Here is whole conversion that occurred on this topic from my side:

**** Start of conversations *********

One more analysis that will really confuse & exactly contrary to previous, Respected Sir, I had not proven value of pi = 3.146446 is correct. Just shown as As n -> infinity, n * (delta x) will be in indeterminate form doesn’t mean computing area by dividing into infinite pieces gives wrong result. for x -> 0 , tan(x) / x is in indeterminate form but its limit exist & it is slightly greater than 1. Similarly, For x ->0, sin(x) / x = 1 (slightly less than 1) In this case, sin(x) can be represented as the function of x. sin (x) = (x) – (x^3 / 3!) + (x^5 / 5!) – (x^7 / 7!) +…. Clearly sin(x) is multiple of x ; sin (x) / x = 1 – x^2 / 3! + (x^4 / 5! ) Now, Area of n sided regular polygon inscribed in circle n * (1/2) r^2 sin(2?/n) = n* (1/2) * r^2 * (2?/n) as n -> infinity clearly it tends to ? * (r^2) that means error becomes insignificant as n-> infinity which is quite “contrary” result to previous. Now question is which one is correct ? *** <> Sorry for misinterpretation, But this result is not contrary to my previous analysis but it is consistent. In previous analysis, I showed that Error = n* (delta x) will be in indeterminate form as n -> infinity & delta -> zero. It doesn’t mean limit doesn’t exist. Also concluding n* (delta x) is significant or insignificant at this stage is “illogical”. Whether error become significant or insignificant can be seen by recent analysis i.e. Area of n sided regular polygon inscribed in circle n * (1/2) r^2 sin(2?/n) = n* (1/2) * r^2 * (2?/n) as n -> infinity clearly it tends to ? * (r^2) Yes, error become insignificant as n -> infinity. Also by Inscribing regular polygon in the circle, increasing n to infinity even if we won’t get accurate value of pi up to all decimal place, that doesn’t mean it won’t gives accurate values at least up to five decimal places. ****** End of conversion *********** <<

Professors of the world

Sir,

Till now we have been accepting Exhaustion method of Archimedes as perfect and error – free in computing pi is less than 22/7. Hence pi is 3.14159265358.. But it is proved his method is wrong .

I would think this news would be discussed in the departmental seminar .

Regards

author

———- Forwarded message ———-

From: Mathematician Vitthal Jadhav

Date: Sun, Aug 6, 2017 at 9:31 PM

Subject: Re: 117 Method on Cosmic Pi

To: Sarva Jagannadha Reddy

Cc: bikasbikashchakraborty.math@yahoo.com

Mistakes in the #Archimedes #pi value computed by using Method of exhaustion.

(Issues with Traditional Pi (#?) )

—————————————————————————-

Assume circle, now draw the square inscribed in given circle,

the perimeter of square is clearly less than circumference,

Now if we increase side, draw regular hexagon with the given circle then difference between perimeter of hexagon & circumference will be reduced. Archimedes by using basic instrument like compass bisected each side of hexagon & obtained 12 point equally spaced on curved path of circle, join them & constructed regular dodecagon, in this way he continued this process. He calculated perimeter of regular polygon with 96 side & came to conclusion that the value of pi lies between

3 + 10/71 < ? < 3 + 10/70,

i.e. 3.140845 < ? infinity)

then delta tends to 0,

Now perimeter = n * (side of polygon i.e. AB)

Circumference = n * (Arc AB)

Error = n * ((Arc AB ) – (Side AB))

= n * delta

we clearly see, as n -> infinity , delta -> zero

but error doesn’t tend to zero as

it is “n * delta” becomes indeterminate

Archimedes method assumes error become insignificant.

This gives the reason – why cosmic pi = 3.146 given by Indian Professor R S Reddy (Sarva Jagannadha Reddy – We can call him as “PI Man” ) differ from traditional ? = 3.1459 approximately by 0.004

]]>Where can i find more like this?

Thanks

Mike

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